PHP - Duplicate Database Entries

Hi all,   Its been a long time since last help request from real professional from here but I'm again in trouble with a much more spectacular plan I'm working on.

For those who are interested in the plan then here it is:
My Idea was to make a new build starting from scratch and make it as dynamical as possible. So my goal is not to make almost anything fixed in the code. I have made a decision to make a one supper large table for multiple different entries so no more joining and no more views for me.! In this help request I'm having trouble with Posting values to a page processing page lets call it record_changer.php The sole purpose of this file is to get form posts and decide what to do. Either update, delete, or insert.

record_changer.php
 

<?php

include '../../config/config.inc.php';

if(is_ajax()){
# Checks if action value exists
  if(isset($_POST["action"]) && !empty($_POST["action"])){
    $action = $_POST["action"];
# Switch case for value of action
    switch($action){
			case "insert": datatable_insert_function();
			break;
			case "update": datatable_update_function();
			break;
			case "delete": datatable_delete_function();
			break;
    }
  }
}

# Function to check if the request is an AJAX request
function is_ajax(){ return isset($_SERVER['HTTP_X_REQUESTED_WITH']) && strtolower($_SERVER['HTTP_X_REQUESTED_WITH']) == 'xmlhttprequest'; }

function datatable_insert_function(){
}

function datatable_update_function(){
}

function datatable_delete_function(){
}

?>

The problem.

The problem is that the $insert places two entries to the DB. I cant seem to understand why.?

	# Test _POST values
	$_POST['UserID'] = '2';
	$_POST['WorkID'] = '22';
	$_POST['Status'] = '1';
	$_POST['Code'] = '1';
	$_POST['Title'] = '1';


	$columns = array();
	foreach(array_keys($_POST) as $name){
		# Exclude Action and ID
		if($name == 'Action' || $name == 'ID' || $name == 'submit' ){ continue; }
		$columns[] = $name;
	}

	print_r($columns);

	echo "<br>";

	$data = array_fill_keys($columns, 'NULL');

	print_r($data);

	foreach($data as $key => $value){
		$data[$key] = empty($_POST[$key]) ? 'NULL' : "'".mysql_real_escape_string($_POST[$key])."'";
	}

	echo "<br>";

	print_r($data);

	$insert = mysql_query('INSERT INTO datatable (ID, '.implode(', ',$columns).')VALUES (null, '.implode(',',$data).')') or die(mysql_error());

No errors no nothing. Just two entries of correct data. 
PS. Sorry for a lot of prints in the code it is work and idea in the progress. The posts at the moment are fixed in the code so it is easier to refresh and debug.

Please help if you spot the problem. Im really out of ideas. Some fresh eyes might make a difference.

And Please for those who want to say it is a bad idea and why and why and so on.. Move a long.!!! Im not interested in whinging i have a great use for this and just having trouble with the two entries.

Thanks.
Edited by ztimer, 14 January 2015 - 03:27 PM.

MySQL returns an error in the form of a number, a state, and a message. Without parsing the message you will not be able to determine what column is duplicated.While parsing the error code, I have also notice that, if you have multiple unique fields as duplicates, only the first duplicate encountered will be returned in the message. This is not very helpful to the end user.   Is there any way to parse the returned error code to reflect all duplicate fields, please see sample code below?

$error=array();
$sql = 'INSERT INTO staff(username, email, phone)
VALUES (?, ?, ?)';
$stmt = $conn->stmt_init();
$stmt = $conn->prepare($sql);
// bind parameters and insert the details into the database
$stmt->bind_param('sss', $username, $email, $phone);
$stmt->execute();
if ($stmt->errno == 1062) {
$errors[] = "One of the fields is already in use.";
}

Code: [Select]
$query = mysql_query("SELECT a.*, b.*
         FROM friendlist a
INNER JOIN friendlist b
ON (a.friendemail=b.friendemail)
INNER JOIN users c
ON (b.friendemail = c.EmailAddress)
WHERE a.email = 'asdf@gmail.com'
AND c.Username LIKE '%carol%'
GROUP BY a.id
ORDER BY count(*) DESC");
Code: [Select]
while ($showfriends = mysql_fetch_array($query)) {
     echo $showfriends['Username'];
}
and I would get nothing. It produces the correct number of <div> so i know it's getting through, but it's having trouble displaying the entries?

Hello...
I have a .txt database with ~100 records.  I only want to show the 15 records that are at the top (referring to reading order of the file).
Here is my php code to display the records.
http://www.flcbranson.org/mobile.php?content=mobile-freedownloads.php if you want to see the results of the code, below.
Code: [Select]
<?php
$index_file = 'services/series/Index-Date.txt';
$fd = fopen($index_file, 'r');
if ($fd) {
        while (!feof ($fd)) {
                $seriestitle = trim(fgets($fd, 1024)); // Series Title
                if(feof ($fd))
                break;
                $seriessubtitle = trim(fgets($fd, 1024)); // Series subtitle
                $seriesinfo  = trim(fgets($fd, 1024)); // Series Info (Church name)
                $serieslocation = trim(fgets($fd, 1024)); // City, State
                $seriesindex = trim(fgets($fd, 1024)); // Series index file
                $seriesstatus = trim(fgets($fd, 1024)); //Online Only?
                $divider     = trim(fgets($fd, 1024)); // Divider
                $seriestitle2 = $seriestitle;
                $seriestitle3 = str_replace("'", "%27", $seriestitle); // Kind of makes the alt= below work "God's Will" ends up being "God%27s Will" but without is "God"
                if(strstr($seriestitle,"<")) {
                        $seriestitle2 = strip_tags($seriestitle);
                }
                $seriestitle2 = urlencode($seriestitle2);
                if(file_exists("images/ProductCovers/".substr($seriesindex,0,-4).".jpg")) {
                        echo "<img src='images/ProductCovers/".substr($seriesindex,0,-4).".jpg' width='115' height='150' border='0' alt='".substr($seriestitle3,7)."'><br />";
                }
        }
        fclose ($fd);
}
?>
I'm assuming that "for" would do the trick, but when I tried I got 10 copies of every record.
Hehehe...
I'm guessing that it's a quick fix.
Thanks...
JJ

I have an issue with some code I have.  All the code works correctly apart from when submit is clicked not only does it update a the current club but it creates a blank entry in the database!  I cant see whats wrong.  Here is the code.........



//gets
$validation = $_GET['new_club'];
//Querys
    $qGetClub = "SELECT * FROM clubs WHERE validationID = '$validation'"; 
$rGetClub = mysql_query($qGetClub);
$Club = mysql_fetch_array($rGetClub);
//Query for category by name
$qGetCat = "SELECT * FROM club_category WHERE catID = ".$Club['cat']."";
$rGetCat = mysql_query($qGetCat);
$CatName = mysql_fetch_array($rGetCat);
//query for related sub categorys.
$qGetSub = "SELECT * FROM sub_categorys WHERE catID =".$Club['cat']."";
$rSubCat = mysql_query($qGetSub);
// query for groups created
$Groupq = mysql_query("SELECT * FROM groups WHERE memberID = '".$User['memberID']."'");

//end of querys

if(isset($_POST['insert_clubbtn1'])){ 
//Process data for validation     
$subcat     = trim($_POST['subcat']);  
$NewSubCat = trim($_POST['NewSubCat']); 
//Prepare data for db insertion      
$subcat = mysql_real_escape_string($subcat); 
//find the new category 
//insert
$result = mysql_query("UPDATE clubs  SET 
`sub_category` = '$subcat'
WHERE validationID ='$validation'") or die(mysql_error());



if ($result!=="") {
$otherg = trim($_POST['other_groups']);
$newg = trim($_POST['new_group']);
$newg = mysql_real_escape_string($newg);     
//if an item other than none from the list is selected then update the club with an ID relating to the group it belongs to
if ($otherg !=='None') { $groupsq = mysql_query("UPDATE `clubs` SET groupID ='$otherg' WHERE validationID ='$validation'") or die (mysql_error()); }
// If none is selected then $newg must have a value so create a new group in the groups table and then on the next page I will add the group in the club table 
else {
$groupsq = mysql_query("INSERT INTO `groups` (`memberID`, `group`, `clubID`) VALUES ('".$User['memberID']."', '$newg', '".$Club['clubID']."')")or die (mysql_error());
}   }

if ($NewSubCat !="") { mail("mail","New Sub Category Request","Dear Ring Master,
\n\nThe club in the name of $name with a validation code of $validationID would like a new sub category called $new_cat\n\n  
\nTeam Arena\n\n\n\n"); }

$url = "/members/create/create_clubp3.php?new_club=$validation";  
header("Location: $url");     
}

Hello,

For starters I'm not sure if what I want to do is possible, but if it is I would like your input. I have a script that will show a number of fields to fill out in a second form based on the number the user puts into the first from. the problem is that only the last one saves into the database and not all of them.

Code: [Select]
<form auction="index.php" method="post">
System Name: <input type="text" name="systemname">
Number of E-sites: <input type="text" name="events">
Number of Sigs: <input type="text" name="sigs"><br>
<input type="reset" name="reset" value="Reset">
<input type="submit" name="start" value="Start">
</form>
<form auction="index.php" method="post">
<?php
$events = $_POST['events'];
$system = $POST['systemname'];

if (isset($_POST['start'])) {
$num = $_POST['sigs'];
$i = 0;
While ($i < $num)
{
echo "Sig ID: <input type=text name=sigid>";
echo "Type: <input type=text name=type>";
echo "Name: <input type=text name=name>";
echo "Notes: <input type=text name=notes>";
echo "<br>";
$i++;
}
}
?>
<input type="submit" name="enter" value="Enter">
</form>
<?php
$sigid = $_POST['sigid'];
$type = $_POST['type'];
$name = $_POST['name'];
$notes = $_POST['notes'];
mysql_connect('xt', 'x', 'x');
mysql_select_db('wormhole');
if (isset($_POST['enter'])) {

$query = "INSERT INTO sites VALUES ('$system','$events','$sigid','$type','$name','$notes')";
mysql_query($query);

}
?>
How do I get it so all the data saves, lets say that $num = 5, I want all 5 to save not just the last one.

Is there any other way of getting PHP form data into C# any other way besides calling  

www.downloadHandler.text

I am having issues  bringing all the entries into C# and breaking them all up.  I can do one row fine but multiple rows isn't working.  I keep getting an out range error.

This is my PHP echo

echo $row['userName']. '|' .$row['level']. '|' .$row['points']. '|' .$row['killRate']. '/';

And this is my C# code

                string nothing = "Not Placed";
                string Data_string = www.downloadHandler.text;
                string[] DataArray;
                DataArray = Data_string.Split('/');

                int numberOfEntries = DataArray.Length;
                Debug.Log(numberOfEntries);

                if (DataArray[0] == null || numberOfEntries == 1)
                {
                    DataArray[0] = nothing;
                    Debug.Log("Data Array [0] isn't there");
                    High_Points_1.text = DataArray[0];

                }
                else
                {
                    High_Points_1.text = DataArray[0];
                    //Debug.Log(DataArray.Length);
                }
                if (DataArray[1] == null || numberOfEntries == 2)
                {
                    DataArray[1] = nothing;
                    Debug.Log("Data Array [1] isn't there");
                    High_Points_2.text = DataArray[1];
                }
                else
                {
                    High_Points_2.text = DataArray[1];
                    //Debug.Log(DataArray.Length);
                }
                if (DataArray[2] == null || numberOfEntries == 3)
                {
                    DataArray[2] = nothing;
                    Debug.Log("Data Array [2] isn't there");
                    High_Points_3.text = DataArray[2];
                }
                else
                {
                    High_Points_3.text = DataArray[2];
                }
                if (DataArray[3] == null || numberOfEntries == 4)
                {
                    DataArray[3] = nothing;
                    Debug.Log("Data Array [3] isn't there");
                    High_Points_4.text = DataArray[3];
                }
                else
                {
                    High_Points_4.text = DataArray[3];
                }
                if (DataArray[4] == null || numberOfEntries == 5)
                {
                    DataArray[4] = nothing;
                    Debug.Log("Data Array [4] isn't there");
                    High_Points_5.text = DataArray[4];
                }
                else
                {
                    High_Points_5.text = DataArray[4];
                }

I have two entries in the database.  But when I debugged the number int he array I get 3 strings.

I want to show the top five entries in the database.

Hi,
I want to be able to generate visitor statistics for a blog I'm creating. I'm going to be collecting numerous pieces of data when a post is viewed, including a time stamp of the visit.

I need to be able to select timestamps that were within the current day, the previous day, the day before that ect.. So that I can generate the statistics.
Show it for the current week (current day and 6 previous days).

So it would be the entries where the timestamp was made on the days: 11/1, 10/1, 9/1, 8/1, 7/1, 6/1, 5/1. For example.

Not quite sure how I could do this.

Thanks.

For some reason my for loop only seems to be storing some data in my fields, most of the time the data is not true but simply duplicating one of the entries. So instead of having a string of 1,2,3,4 for instance it would store all of them as 4. The entires are selected using fields in a multiple select box, in theory of someone choses 10 unique entries from the "Systems" category all 10 should be made into rows in the MySQL table.

Any idea why this is happening?

The form,

if ($type == "games") {

echo "<tr><td>".$name."</td><td><select name='".$name."_".$i."'[] multiple='multiple'><option value='' selected>--------</option>";

$sqla = mysql_query("SELECT * FROM ".$pre."games ORDER BY `name` ASC") or die(mysql_error());

while($row2a = mysql_fetch_array($sqla)) {
$system = mysql_fetch_array(mysql_query("SELECT * FROM ".$pre."systems WHERE id = '".$row2a[system]."'"));
echo "<option value='".$row2a[id]."'>".$row2a[name]." - ".$system[name]."</option>";
}
echo "</select></td></tr>";
}

if ($type == "system") {
echo "<tr><td>".$name."</td><td><select name='".$name."_".$i."'[] multiple='multiple'><option value='' selected>--------</option>";

$sqlb = mysql_query("SELECT * FROM ".$pre."systems ORDER BY `name` ASC") or die(mysql_error());
while($row2b = mysql_fetch_array($sqlb)) {
echo "<option value='".$row2b[id]."'>".$row2b[name]."</option>";
}
echo "</select></td></tr>";
}

The PHP code,

while($row = mysql_fetch_array($query)) {
$name = "$row[name]";

for ($i = 0; $i < count($_POST["systems_$i"]); $i++) {
   mysql_query("INSERT INTO ".$pre."fielddata VALUES (null, 'systems', '".$_POST["systems_$i"]."', '".$fetch[0]."', 'content')");
}

for ($i = 0; $i < count($_POST["games_$i"]); $i++) {
   mysql_query("INSERT INTO ".$pre."fielddata VALUES (null, 'games', '".$_POST["games_$i"]."', '".$fetch[0]."', 'content')");
}

Hello,

I am using the following code to display images managed by a MySQL database.  Basically another program manages a bunch of images, but this script displays certain ones (ones with INCLUDE = 1 in the database) on my main page.  My question is, is there an easy way to limit the number of images it displays, say to 5?  I'm not too concerned which images actually display (ascending or descending)... or better yet, random!  Most importantly, I only want five to display.  Each image will be linked to the full page, which displays all the images.

Any ideas?

Thanks!


Code: [Select]
<?php
$username="XXXXXXX";
$password="XXXXXXX";
$database="XXXXXXX";

mysql_connect(localhost,$username,$password);
@mysql_select_db($database) or die( "Unable to select database");
$query="SELECT * FROM ft_form_12 WHERE col_24='1'";
// $query="SELECT * FROM ft_form_12";
// SELECT * FROM ft_form_12 WHERE col_24='1'
$result=mysql_query($query);

$num=mysql_numrows($result);

mysql_close();
?>

<?php
$i=0;
while ($i < $num) {

$f20=mysql_result($result,$i,"col_23"); //Photo file name
$f21=mysql_result($result,$i,"col_24"); //INCLUDE
?>

<a href="http://www.domain.com/display_whole_page.shtml"><img src="http://www.domain.com/the_file/pictures/<?php echo $f20; ?>" height="50" border="0"></a>&nbsp;&nbsp;&nbsp;
               
<?php
$i++;
}
?>

I coded the following but some parts are not working (the "curveball" mentioned at the end).
How would YOU do this?

I have a page (A) displaying a form with a textarea field using a WYSIWYG interface.
The user will enter a list of unordered items and upon submit the string will look something like this:

This is my list of food items:
 <ul>
  <li> Lettuce </li>
  <li> Tomatoes </li>
  <li> Eggs </li>
 <ul>




Upon submit, I need to give each list item an unique id and store this id along with the text next to it in a separate table:

List_item_id   List_item_text  List_item_state
food_1             Lettuce
food_2             Tomatoes
food_3             Eggs





The user will then land in another page with a form displaying the list. The text is now in the page itself and not in a textarea.
Instead of the bullets a dropdown list appears, and the user can select "buy" or "sell" for each list item. 
This page (B) looks something like this:

<form>
This is my list of food items:
  <br><select name="food_1">
   <option value="buy">Buy</option>
   <option value="sell">Sell</option>
  </select>
  Lettuce

  <br><select name="food_2">
   <option value="buy">Buy</option>
   <option value="sell">Sell</option>
  </select>
  Tomatoes

  <br><select name="food_2">
   <option value="buy">Buy</option>
   <option value="sell">Sell</option>
  </select>
  Eggs

<input type=submit value="submit">
</form>




When the user hits "submit" the table with the list items will be updated with the values selected in the dropdown list:

List_item_id   List_item_text  List_item_state
food_1             Lettuce        Buy
food_2             Tomatoes       Buy
food_3             Eggs           Sell



The next time the user goes to Page B the list will remember the states.


Here's the curveball: At any point the user may click on "EDIT LIST" on Page B so they may add more items (at the begining, middle or end of the string). On edit mode the list items should appear as bullets again inside the WYSIWYG interface.

Keep in mind that some of the text in the string may not be a list item (ie, "this is my list of food...")

Hello. Many thanks for your help.

I am writing a PHP/MySQL dating-site and have hit a programming impass.

I have a database full of members and a search form consisting of checkboxes.

So to search, a member ticks say...gender: female; age: 21,22,23,24,25,26; height: 5'4",5'5",5'6",5'7"; county: cornwall,devon,somerset

How can a run a check on the database selecting all entries that fall into the selected criteria. For example a 23 year old female of 5'5" living in Cornwall and a 26 year old female of 5'4" living in Somerset?

The key index of my database is 'id' and the fields a age,height,county
The names of the form checkboxes a
Gender: male, female; Age: 21,22,23,24 etc; Height: 5_4,5_5,5_6 etc; county: cornwall,devon etc

Im trying to create a website where users login, and then when they add a new entry to the database there name is put as the author. This is how my tables are set up. One table is named job and has the columns id, jobtext, jobdate, and authorid. Another table is called author. This table contains the columns id, username, password, and name. Authorid from the job table matches with id from the author table. When a user logins in this code is used to register the name...session_start();
$_SESSION['myusername'] = $_POST['myusername'];
$_SESSION['mypassword'] = $_POST['mypassword'];
header("location: index.php");
}
else {
echo "Wrong Username or Password";
}

This is the form users use to add a new entry...
if (isset($_GET['add']))
{
$pagetitle = 'New Job';
$action = 'addform';
$text = '';
$authorid = '';
$id = '';
$button = 'Add job';

include $_SERVER['DOCUMENT_ROOT'] . '/jobs/includes/db.inc.php';

// Build the list of authors
$sql = "SELECT id, name FROM author";
$result = mysqli_query($link, $sql);
if (!$result)
{
$error = 'Error fetching list of authors.';
include 'error.html.php';
exit();
}

while ($row = mysqli_fetch_array($result))
{
$authors[] = array('id' => $row['id'], 'name' => $row['name']);
}

// Build the list of categories
$sql = "SELECT id, name FROM category";
$result = mysqli_query($link, $sql);
if (!$result)
{
$error = 'Error fetching list of categories.';
include 'error.html.php';
exit();
}

while ($row = mysqli_fetch_array($result))
{
$categories[] = array(
'id' => $row['id'],
'name' => $row['name'],
'selected' => FALSE);
}

include 'form.html.php';
exit();
}

if (isset($_GET['addform']))
{
include $_SERVER['DOCUMENT_ROOT'] . '/includes/db.inc.php';

$text = mysqli_real_escape_string($link, $_POST['text']);
$author = mysqli_real_escape_string($link, $_POST['author']);

if ($author == '')
{
$error = 'You must choose an author for this job.
Click &lsquo;back&rsquo; and try again.';
include 'error.html.php';
exit();
}

$sql = "INSERT INTO job SET
jobtext='$text',
jobdate=CURDATE(),
authorid='$author'";
if (!mysqli_query($link, $sql))
{
$error = 'Error adding submitted job.';
include 'error.html.php';
exit();
}

$jobid = mysqli_insert_id($link);

if (isset($_POST['categories']))
{
foreach ($_POST['categories'] as $category)
{
$categoryid = mysqli_real_escape_string($link, $category);
$sql = "INSERT INTO jobcategory SET
jobid='$jobid',
categoryid='$categoryid'";
if (!mysqli_query($link, $sql))
{
$error = 'Error inserting job into selected category.';
include 'error.html.php';
exit();
}
}
}

header('Location: .');
exit();
}


Form.html.php =
<?php include_once $_SERVER['DOCUMENT_ROOT'] .
'/includes/helpers.inc.php'; ?>
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Strict//EN"
"http://www.w3.org/TR/xhtml1/DTD/xhtml1-strict.dtd">
<html xmlns="http://www.w3.org/1999/xhtml" xml:lang="en" lang="en">
<head>
<title><?php htmlout($pagetitle); ?></title>
<meta http-equiv="content-type"
content="text/html; charset=utf-8"/>
<style type="text/css">
textarea {
display: block;
width: 100%;
}
</style>
</head>
<body>
<?php session_start(); ?>

<h1><?php htmlout($pagetitle); ?></h1>
<form action="?<?php htmlout($action); ?>" method="post">
<div>
<label for="text">Type your job he </label>
<textarea id="text" name="text" rows="3" cols="40"><?php
htmlout($text); ?></textarea>
</div>
<div>
<label for="author">Author:</label>
<select name="author" id="author">
<option value="">Select one</option>
<?php foreach ($authors as $author):?>
<option value="<?php htmlout($author['id']); ?>"<?php
if ($author['id'] == $authorid)
echo ' selected="selected"';
?>><?php htmlout($author['name']); ?></option>
<?php endforeach; ?>
</select>
</div>
<fieldset>
<legend>Categories:</legend>
<?php foreach ($categories as $category): ?>
<div><label for="category<?php htmlout($category['id']);
?>"><input type="checkbox" name="categories[]"
id="category<?php htmlout($category['id']); ?>"
value="<?php htmlout($category['id']); ?>"<?php
if ($category['selected'])
{
echo ' checked="checked"';
}
?>/><?php htmlout($category['name']); ?></label></div>
<?php endforeach; ?>
</fieldset>
<div>
<input type="hidden" name="id" value="<?php
htmlout($id); ?>"/>
<input type="submit" value="<?php htmlout($button); ?>"/>
</div>
</form>
</body>
</html>


Right now, under authors, it displays all the authors in the database. I want it to just show/submit the authorid of the logged in user.

Maybe some of the great coders here can help this noob out.
So here is what I have so far:

Code: [Select]
//set age criteria for deletion
$age = 60;

//get current date
$datenow  = date("Y-m-d");

//set the range we want to delete
$delete_range = $datenow - $age;

//get old user_id from users table
$oldusers_users = mysql_query ("SELECT user_id FROM users WHERE lastvisit < $delete_range ");

//get user_id from images table that correspond to users table
$oldusers_images = mysql_query ("SELECT user_id FROM images WHERE $oldusers_users=user_id.images ");

//find folders that correspond to the usernames and delete
$oldusers_files = mysql_query ("SELECT username FROM users WHERE lastvisit < $delete_range ");
//print out username
//$result = mysql_($oldusers_files);
$foldername = mysql_result($oldusers_files, 0);

$sigspath = "sigs/";
unlink($sigspath . $foldername . ".gif/index.php");
rmdir($sigspath . $foldername . ".gif");
//now delete user_id's from database
mysql_query("DELETE * FROM users WHERE user_id=$oldusers_users");
mysql_query("DELETE * FROM images WHERE user_id=$oldusers_images");
unset($oldusers_users, $oldusers_images, $oldusers_files, $foldername, $sigspath );
mysql_close($link);
Right now it is only returning the first entry, not the entire list that meets the criteria.  It does delete that one file though but does not remover the rows from the database.

I am sure the database stuff is jacked up I am really new to that part.  What am I doing wrong here or is there a better way to do this perhaps

Hi everyone, I need a little bit of help finishing off my code. Ive managed to get this far.

Code: [Select]
<?php
mysql_connect("") or die ("Not Connected to MYSQL");
echo "</br>";
mysql_select_db("") or die ("Not Connected to DB");
// Database Connection stuff

$partialNumber = $_POST['partialNumber']; // Post the Partial number
$partialNumber = strtoupper($partialNumber);
$numberSearch = mysql_query("SELECT * FROM product_option_value_description WHERE name LIKE '%$partialNumber%'") or die (mysql_error()); // Query to select the key number

//Query to get product ID //

$productId = "SELECT product_id FROM product_option_value_description";

//Query to get product ID //

while ($keyNumber = mysql_fetch_array($numberSearch)) {
$id = $keyNumber['product_id'];
// Query for the images // 
$query = "SELECT image FROM product WHERE product_id = '$id'";
$result = mysql_query($query);
$row = mysql_fetch_array($result) or die(mysql_error());

$query2 = "SELECT product_option_id FROM product_option_value WHERE product_id = '$id'";
$result2 = mysql_query($query2);
$row2 = mysql_fetch_array($result2) or die(mysql_error());

$query3 = "SELECT product_option_value_id FROM product_option_value WHERE product_id = '$id'";
$result3 = mysql_query($query3);
$row3 = mysql_fetch_array($result3) or die(mysql_error());
?>
    <div>
   
    <br /><br />
    Key Number: <? echo $keyNumber['name']; ?></a>
   
    <form action="http://www.co.uk/teststore/index.php?route=checkout/cart" method="post" enctype="multipart/form-data" id="product">
<br />
<table style="width: 100%;">
<tr>
<td>
Colour:
<select name="option[<? echo $row2['product_option_id']; ?>]">
<option value="<? echo $row3['product_option_value_id']; ?>"></option>
</select></td>
</tr>
</table>
<div class="content"> Qty: <input type="text" name="quantity" size="3" value="1" />
    <input type="hidden" name="product_id" value="<? echo $id; ?>" />
    <input name="submit" type="submit" value="Add to Cart" />

</div>
</form>
<? echo $row3['product_option_value_id']; ?>
</div>
<br />
<img height="150" width="150" src='http://www.co.uk/teststore/image/<? echo $row['0']; ?>'/>
<? }
 ?>

And here is my SQL Table code.

Code: [Select]
product_option_value_id product_option_id product_id
599                302                49
598                302                49
589                297                42
588                297                42

So as you can probably tell, it is a search program that looks for products on a shopping cart. The products will have different option values, and the php script will grab the option values and echo them in a form to post back to the cart to add the product to the basket.

The problem is that the "product_option_value_id" can have lots of different values, but my code echos only the first one it finds. So when I click the add to cart button, it will only add the first option value for the product it finds.

For some reason I am having a hard time explaining this, so I hope someone can help me.

Thanks for looking.