PHP - Easy Question

So I am extending the DateTime class and would like to completely disable the modify() function that is built in so i have this:
Code: [Select]
<?php
class NewDateTime extends DateTime
{

public function modify()
{
throw new Exception('modify() has been disabled.');
}
}

thats not the entire class description, just the pertinent part of course

now any time I create a new object from NewDateTime I get this message at the top of the screen:

Quote

Strict Standards: Declaration of NewDateTime::modify() should be compatible with that of DateTime::modify() in C:\xampp\htdocs\.....my file path here.....\NewDateTime.php on line 62


what gives? how do I get rid of this and still disable modify()? I'm betting its a setting that i have wonky but I am really rusty in php so dont know where to look in php.ini

Hello Everybody   I usually work with C#, but I'm doing a website right now and have a question: I want a picture in my header and when I change the window size the image may not move.   My code so far:

#a1 { 
position: relative;
top:-175px; left:0px; width:50px; height:50px;
background-image:url(http://domain.png);
      background-repeat:no-repeat;}
</style>

Hope someone can answer this question easy

I'm trying to search the 'ad' column where 'ad' = 1 or 3

I'm having problems doing this.

Here is what I currently have, but it is not bringing back 'ad' where ='1' (for obvious reasons)
Quote

    $query = "SELECT * FROM users WHERE ad='3' AND state='$state1'";



Here is what I thought would work, but it displays every listing in my database when I do it this way.

Quote

    $query = "SELECT * FROM users WHERE ad='3' OR ad='1' AND state='$state1'";




Thank you in advance for your answers, google is not being so kind to me right now.

How can I use an include file that has a list of links in any directory at my website without breaking those links?

You can see it in action here...

The links in this directory work...

https://www.billelgin.com/primary-directory/

The links in this directory (being created from the same include file) do not work...

https://www.billelgin.com/primary-directory/subsection-one/

Obviously the problem is the include file is being called from different directories, so it's breaking the relative path links in the include file, but what can I do to fix it?

You can download the example directory structure here...

https://www.billelgin.com/EXAMPLE.zip

Wow, am I glad I found this forum!  I spent the past few hours trying to modify a PHP/mySQL script in order to test it. What this script does is basically look up a mySQL database (based on ip2nation) to find out what country and currency the IP address belongs to. This is the code sample:

Code: [Select]
$sql = 'SELECT  c.country, c.curr_code FROM  ip2nationcountries c, ip2nation i WHERE  i.ip < INET_ATON("24.24.24.24") AND c.code = i.country ORDER BY  i.ip DESC LIMIT 0,1';

        $countryName = $db->get_sql_row($sql);

I tested the code in PHPmyAdmin and it returns 2 rows:

country ------- curr_code (row names)
United States ------- USD (actual values)

So basically 2 variables, United States and USD. Now comes the problem, in order to test the script for several countries, I need to be able to "override" the result in the PHP script

I tried to do that by commenting out the part that returns the result from the mySQL query and modifying it with the following style, but I think I'm doing something wrong:

Code: [Select]
### $countryName = $db->get_sql_row($sql); ###

$countryName = "United States USD";

Is there any way that I can temporarily override the result returned by mySQL and "fake it" so to say? I understand the mySQL query returns 2 rows, so how would I go about overriding 2 rows?

I hope this makes sense ...you're all my last hope.

 

I am very new to php and am trying to create a simple application that uploads a PDF file to a database. I have one field for the Volume Number and on file field for the PDF to be uploaded. My issue is i can't get the PDF to upload or insert the name of the pdf (eg volume1.pdf) into the data base.

I would also like to point out that I know i have a low post count, but i only seek help when i truly need it and have exhausted all other resources...

Here is what i have, please go easy on me this is my first round at php:
Code: [Select]
<?php
if(isset($_POST['submit'])){
$vol_num = $_POST['vol_num'];
$pdf = $_FILES['pdf']['name'];
$path = '../pdf/'.$_FILES['pdf']['name'];
move_uploaded_file($_FILES["pdf"]["tmp_name"], $path);
        mysql_query("INSERT INTO volumes set vol_num='$vol_num', vol_link='$pdf'") or die (mysql_error());
echo "<script>location.href='add_volume.php'</script>";
}
?>
what am i doing wrong here?

Thanks in advance

Alright, so I just started picking up PHP again and I have a pretty simple question. I have a html form that takes a string then writes it on another page. My problem is when I use quotations I'll get slashes in them on the page it writes the string on.

Is there a way to clean that stuff up?

ob_start();
include('file.php');
$content = ob_get_clean(); 

ok so this is the code i found for adding a file to a variable..

now how would i use it in term of this:
<?php
$id = NULL;
if(isset($_GET['id']) && $_GET['id'] == "1"){
  $id = 'Marc';
}
else if(isset($_GET['id']) && $_GET['id'] == "2"){
  $id = 'Glenn';
}
else if(isset($_GET['id']) && $_GET['id'] == "3"){
  $id = 'Nathan';
}
else if(isset($_GET['id']) && $_GET['id'] == "4"){
  $id = 'Scott';
}
?>


ok so the get variable checks to see whose id youve requested.

then when for example id = 4 i want to display an include file somewhere else on the page so i would use..
<?php echo $id; ?>

now insted of it being "nathan" i want it to be a file

i didnt really understand the first code i found

Ok so this is what I am looking for and I cannot seem to find any documentation on it!

I have some html files which I want to call up by using the following:

engine.php?id=?

with the questionmark being 1,2,3,4,5,6, etc... where each number is a different HTML page, I just want it to look a little cleaner then if I just have it redirect to each page itself I mean come on what looks better:

http://localhost/engine.php?id=1 <------
http://localhost/home.html

Any guidance is welcome.

Thanks,
Drew

Easy One - What is the symbol for or?

Example: && = and, right?
What is 'or'?

Is there a simple way of sorting data like this?

$string = "
50|1|0|15|1|1~
13|2|0|15|1|1~
50|3|0|15|1|0~
19|1|2|10|0|0~
19|2|2|10|0|0~
22|4|2|10|0|0~
22|3|2|10|0|0~
19|5|2|10|0|0~
1|6|2|10|1|0~
19|6|1|10|1|1
";

I treat this data as a string, and create an array out of it as follows:

$individuals = explode("~", $string);

Then I can divide up each individual as follows:

foreach ($individuals as $individual)
  {
  $individual = explode("|", $individual);
  }

How can I write something that sorts this data by $individual[0], $individual[1], and $individual[2], respectively and in that order??  After sorting I should get the following:


$string = "
1|2|10|0|0~
13|2|0|15|1|1~
19|2|1|10|0|0~
19|5|2|10|0|0~
19|6|1|10|1|0~|
19|6|2|10|1|1~
22|3|2|10|0|0~
22|4|2|10|0|0~
50|1|0|15|1|1~
50|3|0|15|1|0
";

Help?  I have no idea how to write such a function.  Thank you guys.

I'm just learning php and I've created a test shopping website. Everything is working well, but I need help with the following:

This is my products table in the database:

"CREATE TABLE products (
id int(11) NOT NULL auto_increment,
product_name varchar(255) NOT NULL,
price varchar(16) NOT NULL,
details text NOT NULL,
category varchar(16) NOT NULL,
subcategory varchar(16) NOT NULL,
date_added date NOT NULL,
PRIMARY KEY (id),
UNIQUE KEY product_name (product_name)
) ";

I have 3 subcategories: Hats, Pants and Shirts.

On my index page I have links to these three items.

This is my products.php code.  When run it shows all the items in the 3 subcategories.  How do I change the code so that this page display only the Hats when someone clicks on the Hats link?

<?php
// Connect to the MySQL database 
include "storescripts/connect_to_mysql.php";
$dynamicList = "";
$sql = mysql_query("SELECT * FROM products ORDER BY subcategory DESC");
$productCount = mysql_num_rows($sql); // count the output amount
if ($productCount > 0) {
   while($row = mysql_fetch_array($sql)){
             $id = $row["id"];
   $product_name = $row["product_name"];
   $price = $row["price"];
   $date_added = strftime("%b %d, %Y", strtotime($row["date_added"]));
   $dynamicList .= '<table width="100%" border="0" cellspacing="0" cellpadding="6">
        <tr>
          <td width="17%" valign="top"><a href="product.php?id=' . $id . '"><img style="border:#666 1px solid;" src="inventory_images/' . $id . '.jpg" alt="' . $product_name . '" width="77" height="102" border="1" /></a></td>
          <td width="83%" valign="top">' . $product_name . '<br />
            $' . $price . '<br />
            <a href="product.php?id=' . $id . '">View Product Details</a></td>
        </tr>
      </table>';
    }
} else {
   $dynamicList = "We have no products listed in our store yet";
}
mysql_close();
?>
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
<title>Store Home Page</title>
<link rel="stylesheet" href="style/style.css" type="text/css" media="screen" />
</head>
<body>
<div align="center" id="mainWrapper">
  <?php include_once("template_header.php");?>
  <div id="pageContent">
  <table width="100%" border="0" cellspacing="0" cellpadding="10">
  <tr>
    <td width="32%" valign="top"><h3>xxx</h3>
      <p>xxx</p></td>
    <td width="35%" valign="top"><h3>Latest Designer Fashions</h3>
      <p><?php echo $dynamicList; ?><br />
        </p>
      <p><br />
      </p></td>
    <td width="33%" valign="top"><h3>xxx</h3>
      <p>xxx</p></td>
  </tr>
</table>

  </div>
  <?php include_once("template_footer.php");?>
</div>
</body>
</html>

If someone can help me I'd be so grateful! 

I am trying to send an html file (with .js formatting) to the browser from within a PHP script.  The .js formatting is not being interpreted and so the result in the browser is less than impressive.  Why can't I make a call, in PHP, to a url and have the results from that call directed to the browser?

Hello!

I am trying to make a Guestbook with help from the internet. I have created all sites what i need, but i have some problems with the Input.

For example here is the Name inputfrom the "sign.php"

<form id="form1" name="form1" method="post" action="addguestbook.php">
<td>
<table width="400" border="0" cellpadding="3" cellspacing="1" bgcolor="#FFFFFF">
<tr>
<td width="117">Name</td>
<td width="14">:</td>
<td width="357"><input name="name" type="text" id="name" size="40" /></td>
</tr>


And here is the "insert sequence" from the "guestbook.php":

$sql="INSERT INTO $tbl_name(name, email, comment, datetime)
VALUES('$name', '$email', '$comment', '$datetime')";
$result=mysql_query($sql);

If i open the guestbook.php i just can see the datetime. What went wrong?

Thanks, Mark
p.S.: sorry for my english.

OK below is my code. the values for $row['state'] are in this format "AL - Alabama" its got the space in it.

Code: [Select]

while($row = mysql_fetch_array($result))
{
echo "<option value=" . $row['state'] . '">' . $row['state'];
}
?>

When i run the script it outputs HTML as this Code: [Select]
<option value="AL" -="" alabama"="">AL - Alabama</option>

As you can see at the space it terminates and puts the " in. Im assuming this is a rookie programming mistake.

Please help,
Justin