PHP - Help With Replacing Only The First P Tags With A Header Tag

Say I have the following text stored in a MySQL database...

Code: [Select]
<b>Classic Quote from movie</b>
and I retrieve it into a variable called $text, how do I properly echo that so that it keeps the bold tags and actually display the text "Classic quote from movie" in BOLD?

I'm doing something wrong somewhere along the line (simply doing "echo $text;") because it displays on the page as...

Code: [Select]
<b>Classic Quote from movie</b>

Instead of...

Classic Quote from movie

Any info on properly storing and echoing back HTML would be very appreciated.

This topic has been moved to PHP Applications.

http://www.phpfreaks.com/forums/index.php?topic=350027.0

Hello everyone, I'm just starting out with PHP as I need to create an online bookstore for a school project. I'm working by a magazine which should teach you exactly how to do this using PHP, but I've had a bunch of problems with the code they use and I don't really know what's going on. Anyway, this looks really simple and basically  what it does is allows you to post a comment on a book, then returns you to the book's page. Problem is, I'm getting the Header may not contain more than a single header, new line detected. error and I can't figure out why. I've tried researching into the matter but all the cases I found had to do with returning to an url, which is not my case.

Anyway, here's the snippet of code:

The form:

Code: [Select]
<div style="width:400px; border:1px solid #ffffff; background-color:#F9F1E7; padding:5px">
<b>Adauga opinia ta:</b>
<hr size="1">
<form action="adauga_comentariu.php" method="POST">
Nume: <input type="text" name="nume_utilizator"><br><br>
Email: <input type="text" name="adresa_email"><br><br>
Comentariu: <br> <textarea name="comentariu" cols="45"></textarea><br><br>
<input type="hidden" name="id_carte" value="<?=id_carte?>">
<center><input type="submit" value="Adauga"</center>
</form>
</div>
The script adaugare_comentariu.php:


Code: [Select]
<?php
ob_start();
include("conectare.php");
$numeFaraTags=strip_tags($_POST['nume_utilizator']);
$emailFaraTags=strip_tags($_POST['adresa_email']);
$comentariuFaraTags=strip_tags($_POST['comentariu']);
$sql="insert into comentarii (id_carte, nume_utilizator, adresa_email, comentariu) values(".$_POST['id_carte'].", '".$numeFaraTags."','".$emailFaraTags."','".$comentariuFaraTags."')";
mysql_query($sql);
$inapoi="carte.php?id_carte=".$_POST['id_carte'];
header("location:urldecode($inapoi)");
ob_end_flush();
?>
conectare.php connects to the mysql database. $inapoi is the variable which returns the user to carte.php (the book he posted a comment on), where id_carte is the book's unique id. I'm getting Header may not contain more than a single header, new line detected on line ten, which is the header line.

Can anyone help me? I've been stumped on this for a few days now and I've just let it pass and started working on other bits, but it's bugging me too much and I'd like to fix it. 

Please help.  I am trying to replace parenthesises () in a string with <>.  I tried preg_replace and str_replace, but was not success.

Here is what I have for str_replace:
$word = "(test)";

$word = str_replace('(', '<', $word);

$word = str_replace(array('(', ')'), array('<','>'), $word);

 

Hello,

Is str_replace the best way to go about this?

In MYSQL, a html template is stored, such that:

Quote

<table width="{$width}">lots of other ........</table>


This is extract from the database, and stored in a string. I would use eval(), but, any user can update this template, so I need to be able to set which variables will be replaced with what the variable is.

Thanks!

Hey all, i need a function or  a way to replace each letter in a string to a star (*)

Thanks

Hey guys, I have a quick question.

Im going to be making a script that will output the name of a news article along with the poster's name beside it.

There is only a certain amount of space where that stuff can go so I want to know how I can make it so that say after 20 characters, it ends and puts "..." beside it.

Is this possible with php? How would I do it?

How come this is not replacing correctly?

$rp = strtr($rp,"[TIMES]","<span style='font-family: Times New Roman, Times, serif'>")

Hi

I wonder if anyone will be kind enough to help.

I am getting into forking with pcntl_fork()

I intend to create a script that runs 24/7 running 100 forks/children/'threads' simultaneously.

Once a child has finished it's task and exited how can I start a new child to replace it?

I need some kind of infinite loop that can continually check for exited children and set up new ones.  I'm finding it hard to get my head round since I'm new to forking.  Can anyone suggest a way to do this?

Thanks in advance.

Hi Guys,

I use this function to generate seo friendly names for my products once pulled from the database:


function generate_seo_friendly_links($pNM, $pID)
{
    $replacedNM = str_replace(" ", "-", $pNM);  
    $replacedNM = rtrim($replacedNM);  
    $brandNewSEOFriendlyURL = "<a href='$replacedNM-$pID.html'>$pNM</a>";    
    return $brandNewSEOFriendlyURL;
}


This works great, the only thing is say a product is stored in the database like:

product name it would then be converted to: product-name.html

if for example theres 2 spaces:

product  name it would then be converted to: product--name.html

with the 2 "--" so for every space it finds we replace with a "-" etc

is there a way i could ignore more than 1 space and always have it like product-name-here.html so the names are more uniformed, i can't think of a way to do it.

any help would be appreciated

thanks guys

Graham

I have phrases in a string with the structure of "Note: some description" I want to replace "Note with (, but how can I replace the second " with )?

Hi first post here and very new to php. I built a form so that a data entry perosn can "build" new pages for our companies website. I pretty much have the basics of the form and the action page coded correctly, however my issue is that I need this final page where the form inputs are posted too to be an html document.

I read some about the str_replace() function, but I'm not understanding how I could use that to replace the file extension of a page.

Maybe I'm going about this all wrong. I also read that one can edit the htaccess folder to allow an html file to run php script. Not sure which way would be the best. One thing to mention though, is this application would be run locally to our back up files which is then scheduled to be uploaded to the remote server very night.

Any help or suggestions would be greatly appreciated.

Ok mixing javascript with php.... im having bugs .

I basically want to replace any broken image links with a picture "noimage.gif" in the images folder.

I tried this code but am getting the error:
Parse error: syntax error, unexpected T_STRING, expecting ',' or ';' in /home/wormste1/public_html/tilburywebdesign/shop/FTPServers/barryottley/showroom.php on line 78

This is the javascript header - all seems fine:
<script language="JavaScript" type="text/javascript">

function ImgError(source){ 
    source.src = "/images/noimage.gif"; 
    source.onerror = ""; 
    return true; 
} 


</script>

this is the code thats erroring... is it the way ive written in the code into the IMG tag?

while($row = mysql_fetch_array($result)){
echo "<TABLE CELLPADDING=0 CELLSPACING=0 WIDTH=100% BORDER=0>";
echo "<TR />";
echo "<TD WIDTH=30% VALIGN=TOP />";
echo " <A HREF='images/".$row['photo']."' target=_blank><IMG SRC='images/".$row['photo']."' width=186 height=155 border=0 onerror="ImgError(this);" /></A> ";
echo "<br />";
echo "</TD>";
echo "<TD WIDTH=10 VALIGN=TOP />";

Hi,
I have 2 arrays, named $old_teams1 and $old_teams2.
The arrays have from 6 values upwards. If $old_teams1 looks like this:
Code: [Select]
Array (
[0] => 3
[1] => 4
[2] => 3
[3] => 4

[4] => 1
[5] => 2
)
and $old_teams2 is the has the same mixture of values from 1-4.....
.. How do I create a loop that will change all values of $old_teams1 and $old_teams2 to new values such as, 1->3, 2->4, 3->1, 4->2.... (The new values have been randomly generated).