PHP - $_get?

Please i will like to know what this variable $_GET['id']is used for and how to use it
Thanks

I cannot seem to get my link to work.. I want to build a php script that has more than one $_GET command.. The link I want to make is: index.php?section=tutorial&viewing=18-classes_or_ids.
Here is my PHP code..

<?php
$section = $_GET['section'];
switch ($section)
{
case "home":
include("home.html");
break;
case "register":
include("register.html");
break;
case "tutorial_home":
include("tutorial.html");
break;
default:
include("home.html");
}
$tutorial = "?section=" .  urlencode('tutorial&viewing') . $_GET['tutorial&viewing'];
switch ($tutorial)
{
case "18-classes_or_ids":
include("classesorids.html");
break;
}
?>

Please help me!!

I am seen people have dynamic pages that loads the information from a database and then displays that information from the url. EG domain.com/somedirectory/something I have a website that does this but uses domain.com/something.php?id=something . This works great but when I go to try and get the statistics for that page from facebook for number of people that have liked that page.

When I go to: http://graph.facebook.com/http://likebook.cz.cc/ It shows me the information:
Code: [Select]
{
   "id": "**************",
   "name": "LikeBook",
   "picture": "http://profile.ak.fbcdn.net/hprofile-ak-snc4/hs178.ash2/41817_130259343675613_3465_s.jpg",
   "link": "http://www.facebook.com/pages/LikeBook/130259343675613",
   "category": "Website",
   "description": "Collect every like at LikeBook.cz.cc",
   "fan_count": 3
}
But when I try and go to: http://graph.facebook.com/http://likebook.cz.cc/like.php?id=31 It shows me:

Code: [Select]
{
   "id": "http://likebook.cz.cc/like.php"
}
So what I need to do is. Make a dynamic page within that sub directory.

So that http://likebook.cz.cc/like/31 does grabs the information from line 31 of my database, like http://likebook.cz.cc/like.php?id=31 would do.

Thank you
~AJ

Hi I am trying to use 2 codes to get a url link.

code1 (test.php):

    <form action="test1.php" method="GET" />
    link: <input type="text" name="link" /><br />
    <input type="submit" value="Submit" />
    </form>



code2 (test1.php)

    <?php
    $link = $_GET['link'];
    echo $link;
    ?>



If I input a link as a text such as "Yahoo" it works. But if I input a link as "http://yahoo.com", it didn't work .

Hi there,

I am new to this forum want to say Hi  to everyone  .
I just learn a little bit of PHP. I couldn't figure this out. Could someone please help me? Many thanks.

1. when I ran the 1st code below, it showed me "thank you" in the browser.
    <?php
    $title=$_GET[title];
    echo $title;
    ?>

2. when I ran the 2nd code below, I got what I wanted.
    <?php
    $sql = "SELECT * FROM mytable WHERE title='thank you' ";
    ...
    ?>

3. when I ran the 3rd code below, it showed me a blank page  .
    <?php
    $title=$_GET[title];
    $sql = "SELECT * FROM mytable WHERE title='<?php echo $title; ?>' ";
    ...
    ?>

How to make the 3rd code work like the 2nd one? It seems a php code under php is NOT working.

I have some javascript for a tabbed interface in index.php. The content of each tab is in content.php which uses $_GET to define which tab is selected. But i want to include queries based on variables from index.php how would i do this?

here is the code for the tabbed interface:

<script language="JavaScript" type="text/javascript" src="<?php echo SITE_ROOT; ?>/js/ahahLib.js"></script> 
<script language="JavaScript" type="text/javascript"> 
function makeactive(tab) { 
document.getElementById("tab1").className = ""; 
document.getElementById("tab2").className = ""; 
document.getElementById("tab3").className = ""; 
document.getElementById("tab"+tab).className = "active"; 
callAHAH('includes/content.php?content= '+tab, 'content', 'Loading...', 'Error'); } 
</script> 

<ul id="tabmenu" > 
<li onclick="makeactive(1)">
<a class="" id="tab1">Account Information</a>
</li> 
<li onclick="makeactive(2)">
<a class="" id="tab2">Second Page</a>
</li> 
<li onclick="makeactive(3)">
<a class="" id="tab3">Third Page</a>
</li> 
</ul> 
<div id="content"></div> 

and the code in content.php

if ($_GET['content'] == 1) { echo 'Content for Page 1'; } 

if ($_GET['content'] == 2) { echo 'Content for Page 2'; }

if ($_GET['content'] == 3) { echo 'Content For Page 3'; } 


ive tried adding the variable $user_id to the content.php url as follows:

callAHAH('includes/content.php?user=$user_id&amp;content= '+tab, 'content', 'Loading...', 'Error'); } 

but that just brought up an error.

How to find the name  value using php or $_GET

here is the url

 header("Location:http://localhost:8666/OnlineBookingsPhp/index.php?name=Next");

Thanks

hi all   new to webforum and php, how can I enter $_get['id] as I know this id...my code snippet is below   $sql = "SELECT x,y,z  from tablename WHERE Id='" . $_GET["id"] . "'";   It works fine as it is getting the variable from a another webpage, but I know an id and want to enter it manually just to check a different webpage , thanks in advance....singhy   Please give example if the known id=xyztest

I never really thought about it before, but recently I visited a site with a url like:

www.example.com/?OR

Which made me wonder how you would go about getting that keyname since it is without a value. Any ideas?

Hello can any one help me with this question iv only just started to use the get function like

<code>

if (isset($_GET['pageID'])){
            echo $row['content'];
       }    
</code>

can any one if me info how to make it safe

I am a new programmer. I am working on a personal project for my portfolio, it is a simple blog.
I am trying to give the user the ability to delete a blog entry. It works fine, the problem is that
when you refresh the page, with out clicking 'delete' the entry is still deleted. $_GET is passing
the $id to my function and it is executing. The code I have posted is my effort to fix the problem.

How can I connect $_GET to the delete button ? I have tried using a hidden value but this is not working.

Any help would be greatly appreciated.
AL


Code: [Select]
// code to display message before deletion
if($_GET['T'])
{
echo("<div style='float:right; width:25%; height:100px; position:absolute; top:150px; right:15%;'>");
echo("<h2>Are you sure you want to delete:<h2>");
echo $_GET['T'];
echo("<form method='get' action='?'>");
echo("<input type='submit' name='button' value='Delete'>");
echo("<input type='hidden' name='submit_check' value='1'>");
echo("</form>");

echo("<form action='http://nuke.industry.com/Blogspiracy/UserPage/index.php'>");
echo("<input type='submit' value='Cancel'/>");
echo("</form>");
echo("</div>");
}

// code to delete a selected blog entry
function delete_blog($id)
{
global $dbh;
$sql = "DELETE FROM tblBlog WHERE tblBlog.id = '$id' LIMIT 1;";
$sth = $dbh->prepare($sql);
$sth-> execute();
return;
}

if (isset($_GET['id']) && ($_GET['submit_check']))  how do I "GET" the hidden value?
{
$remove = delete_blog($_GET['id']);

}

[code]
 

Hi All

Please take a look at the code below.  I am sucessfully accessing a database and pulling the details through into a HTML form with a drop down.  However I then want to use a variable (test) in another page.  However I cannot get the variable userrow['userid'] to send a value to my getquiz.php.  What am I doing wrong?

<!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.0 Transitional//EN">
<HTML>
 <HEAD>
  <TITLE> New Document </TITLE>
  <META NAME="Generator" CONTENT="EditPlus">
  <META NAME="Author" CONTENT="">
  <META NAME="Keywords" CONTENT="">
  <META NAME="Description" CONTENT="">
 </HEAD>
 <?php
include_once "db.inc.php";
?>
<body>
<form action="getquiz.php" method="GET">
  <tr><td class="title">Please Select User</td> 
<td><select name="test">
<?php
$courseid = mysqli_query($link, 'SELECT id FROM mdl_quiz WHERE course = "225"; ');
if (!courseid)
{
$error = ' Error fetching course id: ' . mysqli_error($link);
include 'error.html.php';
exit();
}
else {
while($row = mysqli_fetch_array($courseid))
  {
  $user = mysqli_query($link, 'SELECT userid FROM mdl_quiz_attempts WHERE quiz =' . $row['id']);
  while ($userrow = mysqli_fetch_array($user))
  {
  $names = mysqli_query($link, 'SELECT firstname,lastname FROM mdl_user WHERE id=' . $userrow['userid']);
  while ($usernames = mysqli_fetch_array($names))
  {?>
  <option value="<?php $userrow['userid']?>"> <?php echo $usernames ['firstname'] . " " . $usernames['lastname'] . $userrow['userid']; ?> </option>
  <?php
     }
  }
  }
}
?>
</select>
</td></tr>
<center><input type="submit" value="Submit"></center>
</table>
</form>
</body>
</html>

I run into this every now and again and wonder if someone knows what I could be doing wrong. Using a simple $ClientID = $_GET['ID']; is not working on a certain page, I can see the ID=193 value in the address field but $ClientID remains an empty variable. I even try $_REQUEST instead, still nothing. I'm puzzled.

Hi guys,
I've seen a lot of posts with this question but I still haven't managed to get it working!
I have the following URL:
www.myurl.com?&fltAccessories=Steel File &amp; Oxide Stone

I'm using the following code to read all the $_GET variables
Code: [Select]
while(list($key, $value) = each ($_GET)) {
....
....
}

Problem is, $value contains 'Steel File' in this example.
I've tried urldecode around the $_GET but to no avail.

Anyone any idea how to make this work?

Hi,

I'm using $_GET to pass form data to a URL -

http://localhost/projects/phpget/test.php?Q7=Dave&Q8=Smith&Q9=123+Road&Q10=ls11sl&Q2=dave%40hotmail.com&Q4=71&day=19&month=01&year=1995&Q263=3127&Q262=3126&x=99&y=24

All the form fields are named Qx and all are ok apart from dob.

I've been trying to get the dob to be passed as dd-mm-yyyy with name of Q5, so in above example would be:

http://localhost/projects/phpget/test.php?Q7=Dave&Q8=Smith&Q9=123+Road&Q10=ls11sl&Q2=dave%40hotmail.com&Q4=71&Q5=19-01-1995&Q263=3127&Q262=3126&x=99&y=24

I cannot name all 3 fields (date, month, year) as Q5 si i'm guessing that the 3 values need to be assinged to Q5 before the form is submitted??

Any help on this would be much appreciated as hours of trawling through google has not helped.

Many thanks.