PHP - Navigation Bar That Shows Submenus When Linked Is Clicked

Hi, I want to be able to allow user to enter in <input type="text" >... the total XML files to upload on the first page so:

my first page has form that asks user how many uploads form they want so (firstpage.html):
<form method='post' action='outputTotalUploads.php' >...

Then in second form (outputTotalUploads.php) is where it outputs the desired number of upload forms based on the first page:
for loop to post each <form method='post' action='addToDb.php' >...

Finally in third page (addToDb.php):
for each uploaded file, do: //BUT HOW DO I GET THIS TOTAL??
  add to database

*My problem is HOW do I refer to the total number of uploads the user chose way back in the first page b/c I know you cannot have multiple action attribute in the form tag.

Any help much appreciated!

...in a different folder?

For instance, I have a stylesheet in my  C:\xampp\htdocs\rcm folder, and I want to link it to files in the C:\xampp\htdocs\ folder. Is there a way of doing this?

Thanks in advance

I have no idea where to start or which board would be the proper place to put this but what I"m attempting to do is integrate this idea with my custom cms I'm making now is that once inside I can take down my site in case I (administrator) wanted to perform some maintenance on my site and have it instead display a custom 404 page. Any ideas on where to start. I tried using my best friend google but he gave me nothing. Maybe a few tutorials of this might help.

Simplified for everyone's sanity and re-posted.   Got a Wordpress Conference theme, lets you enter speakers into a database and assign each one a category/role.

In the settings for the theme, there's a dropdown from which you can select one of the roles you create. Doing so will display all the speakers assigned that role in the footer of the homepage and also populate a stand-alone Speakers page with the same role.

I want to make it so that the footer on the homepage displays one role and the stand-alone speaker page displays another.

Here's the PHP for the Speakers page (identical to the footer PHP)

<?php

/**

 * Template Name: Speakers page

 * Description: Speakers page

 *

 * @package WordPress

 * @subpackage wpconference

 * @since wpconference 0.1

 */


get_header(); ?>


    <div id="primary">

        <div id="content" role="main">

        

        <h1 class='entry-title'><?php the_title(); ?></h1>


            <?php

                global $conf_sched;

                

                $speakers_category = $conf_sched->get_option('speakers-category',-1);

                if($speakers_category !=-1){

                    $speaker = get_term($speakers_category, 'participant-roles');

                    $conf_sched->shortcode_participants(array('role'=>$speaker->slug));    

                }else

                {

                    _e("To be annouced...",'wpconference');

                }

                                        

            ?>

    </div> <!-- #content -->

    </div> <!--  #primary -->

    

    <?php get_footer(); ?>

Here's the HTML for the "dropdown" portion of the settings, where you can see the role categories available. "Speaker" is the default created by the Theme, "whyattend" is the one I made.

<!-- Speakers Category -->

            <tr valign="top"><th scope="row">Speakers Category</th>

                <td>

                    <select name='conf_sched[speakers-category]' id='cat_speakers' class='postform' >

    <option value='-1'>&#38;#8212;</option>

    <option class="level-0" value="2">Speaker</option>

    <option class="level-0" value="17" selected="selected">whyattend</option>

</select>

 <br />

                    <span class="description">Please choose which category is your speakers category. If none is available please go to Participants menu and add a new role speakers</span>

                </td>

            </tr>

I want "whyattend" to show on the Footer and "Speaker" to populate the Speakers page.

Can this be done?

HI,
I have a ms-access file which has linked table. The linked table is connected to a ODBC source (e.g MS-SQL or 3rd Party ODBC Driver).
WebPage(php) Apache, connecting to a ODBC DSN of MS-Access, MS-Access is having linked tables. Linked tables as from another ODBC source.
On the PHP Page, When I am trying to connect the ms-access odbc dsn , I am able to connect.
But when I query any of the linked tables, PHP is not able to query and is failing.

Does php has capabilities to read/write to linked tables in ms-access file.
Or it is issue with MS-Access
Or is it I am missing something.

Microsoft says, its an issue of PHP
https://social.msdn....forum=accessdev

Requesting you to please share your feedback

Regards
Rajendra Dewani

This topic has been moved to mod_rewrite.

http://www.phpfreaks.com/forums/index.php?topic=347820.0

Hi all,

I wonder if anyone could give me some idea: I have a form and one of the filed is an email (must field) if empty an error message will show up: - Now I want to add a CHECKBOX where when the CHECKBPX is clicked the "must field" email will become" not must field one" (Not required field).

I have this code as my snippets:

Code: [Select]
<form action="<?php echo $PHP_SELF;?>" method="post" name="reg1">
..
<tr>
<td><input name="noemail" type="checkbox" value="noemail">
 Do not want to get the E-mail address</td>
</tr>
<tr>
<td nowrap>Enter email
<input name="email1" type="text" <?php if ($_POST['action'] == "register") { echo 'value="'.$_POST['email1'].'"'; } ?>>
   </td>
</tr>
..
</form>


..
..
$error = 0; 
$errormsg = "";
..
..
if ($_POST['action'] == "register") {

if (($_POST['email1'] == "") OR (!check_text($_POST['email1']))) {
$error = 1;
$errormsg .= "Please enter your requested email address<br>";
$errornum[3] = 1;
    }
}
..


Can anyone assist me what shall I add so I can achieve this please?

Thanks in advance.
Siabanie

Hello and ty all for helping
I have located the problem its in login.php file but dont know where thats why am turning to experts of coding.
My file is located here ftp.sofo.si username and password are same "guest" pls feel free to download and inspect

Thank you again for any help
cheers

I have a database where I have 2 departments, and I want it to not show if they are both taken, but I'm not sure how to do this? Currently I have
Code: [Select]
$type_sql2 = mssql_query("SELECT * FROM Database2 Where SaleID ='$salesid'");
                       while($RS2 = mssql_fetch_assoc($type_sql2)) {
                       $used_dist = $RS2['DistID'];
$type_sql = mssql_query("SELECT * FROM Database Where Disable = 0 AND DeptID!= '$used_dist'");
                       while($RS = mssql_fetch_assoc($type_sql)) {
                        $DeptID_ID = $RS['DeptID'];
                        $DeptID_Name = $RS['DeptDescription'];
                  echo "<option value=\"$DeptID_ID\">$DeptID_Name</option>\n";
                       }
}And my DeptID is SE and CM, now in another database where these are used, I want this to not show them if they are both used and only show the one not being used any other time, but I can't just do it one at a time, because I may have more departments later on, but right now, with the above, if one is used, then it works, because only one shows up, but if both are used, it shows both still because it then sees SE and puts in CM, then loops thru again and sees CM and puts in SE then the second time. I hope this makes sence. But how do I not show either if both are used, and if one is used then only show the other?
Thanks

Hi

I have deleted quite lot data from mysql database however,  php still shows that page but blank ie page.php?id=186  - this id and all assosiated fields with this id has been removed from mysql but id still showing on the net and google cached all of them ( 600 pages) . page.php is still in use but I was wondering if there is any way not to show these blank pages/ids from mysql db and more importantly how can I remove these blank pages from google?

Thanks for your help.

I try to adjust my date and time to ("M-d-Y h:i:s A"), but when I do, I get 0's for the both the date and time.

Code: [Select]
<table width="400" border="0" align="center" cellpadding="3" cellspacing="0">
<tr>
<td><strong>Test Sign Guestbook </strong></td>
</tr>
</table>
<table width="400" border="0" align="center" cellpadding="0" cellspacing="1" bgcolor="#CCCCCC">
<tr>
<form id="form1" name="form1" method="post" action="addguestbook.php">
<td>
<table width="400" border="0" cellpadding="3" cellspacing="1" bgcolor="#FFFFFF">
<tr>
<td width="117">Name</td>
<td width="14">:</td>
<td width="357"><input name="name" type="text" id="name" size="40" /></td>
</tr>
<tr>
<td>Email</td>
<td>:</td>
<td><input name="email" type="text" id="email" size="40" /></td>
</tr>
<tr>
<td valign="top">Comment</td>
<td valign="top">:</td>
<td><textarea name="comment" cols="40" rows="3" id="comment"></textarea></td>
</tr>
<tr>
<td>&nbsp;</td>
<td>&nbsp;</td>
<td><input type="submit" name="Submit" value="Submit" /> <input type="reset" name="Submit2" value="Reset" /></td>
</tr>
</table>
</td>
</form>
</tr>
</table>
<table width="400" border="0" align="center" cellpadding="3" cellspacing="0">
<tr>
<td><strong><a href="viewguestbook.php">View Guestbook</a> </strong></td>
</tr>
</table>

Code: [Select]

<?php
$mysql_host = "myhost";
$mysql_database = "guest";
$mysql_user = "myusername";
$mysql_password = "mypassword"; 

//$db_name="guest"; This is not needed, as db_name is $mysql_database above, so please delete this line.
$tbl_name="guestbook"; // Table name

// Connect to server and select database.
mysql_connect("$mysql_host", "$mysql_user", "$mysql_password") or die("cannot connect server ");
mysql_select_db("$mysql_database") or die("cannot select DB");

$name = $_POST['name'];
$email = $_POST['email'];
$comment = $_POST['comment'];
$datetime=date("y-m-d h:i:s"); //date time

$sql="INSERT INTO $tbl_name (name, email, comment, datetime) VALUES ('$name', '$email', '$comment', '$datetime')";
$result=mysql_query($sql);

//check if query successful
if($result){
echo "Successful";
echo "<BR>";
echo "<a href='viewguestbook.php'>View guestbook</a>"; // link to view guestbook page
}

else {
echo "ERROR";
}

mysql_close();
?>


Code: [Select]
<table width="400" border="0" align="center" cellpadding="3" cellspacing="0">
<tr>
<td><strong>View Guestbook | <a href="guestbook.php">Sign Guestbook</a> </strong></td>
</tr>
</table>
<br>

<?php
$mysql_host = "myhost";
$mysql_database = "guest";
$mysql_user = "myusername";
$mysql_password = "mypassword"; 
$tbl_name="guestbook"; // Table name

// Connect to server and select database.
mysql_connect("$mysql_host", "$mysql_user", "$mysql_password") or die("cannot connect server ");
mysql_select_db("$mysql_database") or die("cannot select DB");

$sql="SELECT * FROM $tbl_name";
$result=mysql_query($sql);

while($rows=mysql_fetch_array($result)){
?>
<table width="400" border="0" align="center" cellpadding="0" cellspacing="1" bgcolor="#CCCCCC">
<tr>
<td><table width="400" border="0" cellpadding="3" cellspacing="1" bgcolor="#FFFFFF">
<tr>
<td>ID</td>
<td>:</td>
<td><? echo $rows['id']; ?></td>
</tr>
<tr>
<td width="117">Name</td>
<td width="14">:</td>
<td width="357"><? echo $rows['name']; ?></td>
</tr>
<tr>
<td>Email</td>
<td>:</td>
<td><? echo $rows['email']; ?></td>
</tr>
<tr>
<td valign="top">Comment</td>
<td valign="top">:</td>
<td><? echo nl2br($rows['comment']); ?></td>
</tr>
<tr>
<td valign="top">Date/Time </td>
<td valign="top">:</td>
<td><? echo $rows['datetime']; ?></td>
</tr>
</table></td>
</tr>
</table>
<BR>
<?
}
mysql_close(); //close database
?>

I'm a bit stumped here and as usual I'm sure it's something simple.

I have an object that checks if a user is an admin. It works fine. But it the HTML below it is not getting displayed.

Take a look.

welcome.php
session_start();

$user = new users();

if (!isset($_SESSION['username'], $_SESSION['imadmin']) || $user->is_admin($_SESSION['username'])==0)
{
header('Location: index.php');
}

welcome.php is getting displayed without getting redirected to the index. But there's no HTML, just the URL to welcome.php in the bar.

Anyone?

Cheers!

Hey all.  I have a simple code for verifying some data.  I have two echos from if statements.  The first is if the text input is empty echo: HELLO.  The second is if text input data is not found in database echo: NOPE.

Now in the following code the second one works fine.  But the problem is if I leave the field empty BOTH echos show.  So if I leave the input empty instead of saying "HELLO"  it says, "HELLONOPE".

Yet the second one works fine and display only "NOPE"

The other thing is if I switch the two echos to die instead, they work fine.

Code: [Select]
if (isset($_POST['submit'])) {

// if form has been submitted
// makes sure they filled it in
  if(!$_POST['id']) {

echo "HELLO";

  }
  // checks it against the database
 

  $check = mysql_query("SELECT * FROM emp WHERE id = '".$_POST['id']."'")or die(mysql_error());

 
 //Gives error if user dosen't exist
 $check2 = mysql_num_rows($check);
 if ($check2 == 0) {
 
 echo "NOPE";
  }
 
 else
 {

//if login good then redirect them to the members area
$id = $_POST['id'];
header("Location: somepage.php?id=$id"); }
}

 else {

// they are not logged in


 
 }
 
 <form action="<?php echo $_SERVER['PHP_SELF']?>" method="post"> 
 <input type="text" name="id" maxlength="40">  <input type="submit" name="submit" value="Login"> </form>

What am I doing wrong?

I set up the following code to successfully individual items based on the id number. ?id=1 etc.  However, I thought it would be simple to change to show another row so I changed all the terms to 'description'.  However, if I enter ?description=abcde it shows nothing.  But if I type in ?description=description is bizarrely shows everything.

The only thing I can only put it down to is numbers.  Does $_GET react differently react differently to numbers or does it require commas surrounding the string?




<?php
if( isset($_GET['description']))
$_GET['description'];
$query = "SELECT * FROM productfeed WHERE description = $description LIMIT 0, 10";
$fetchdata = mysql_query($query) or die("query: $query<br>This has an error: " . mysql_error() . '<br>');
while($row = mysql_fetch_array($fetchdata)) {
$id = $row['id'];
$image = $row['awImage'];
$link = $row['link'];
$description = $row['description'];
$fulldescription = $row['fulldescription'];
$price = $row['price'];





echo "<div class='productdisplayshell'>
<div class='productdisplayoutline'>
<div class='productborder'><center>
<a href='$link' target='_blank'><img src='$image'/></a>
</center> </div></div>
<div class='productdescriptionoutline'>
<div class='productdescriptionbox'>
<a href='$link' target='_blank' >$description</a>
</div>
<div class='productfulldescriptionbox'>$fulldescription</div>
</div>
<div class='productpriceoutline'>
<div class='productpricebox'>
<center>&#38;#163; $price</center>
</div>
<div class='productbuybutton'>
<center><a href='$link' target='_blank' ><img src=/images/buybutton.png /></a></center>
</div>
</div>
</div>";
} 
?>