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PHP - Setcookie() Expects Paramater To Be Long.
I'm stumped on this one. New to sessions and cookies. When somebody logs out, the browser goes to logout.php. It logs them out, but the page shows this error:
Warning: setcookie() expects parameter 3 to be long, string given in /data/21/2/40/160/2040975/user/2235577/htdocs/logout.php on line 23 you are now logged out. Code: [Select] <?php session_start(); if(!($_SESSION[id])){ $url = 'http://' . $_SERVER['HTTP_HOST'] . dirname($_server['PHP_SELF']); // check for trailing slash if ((subst($url, -1) == '/') OR (substr($url, -1) == '\\') ){ $url = substr($url, 0, -1); } $url .= '/index.php'; header("Location: $url"); exit(); } else { $_SESSION = array(); session_destroy(); setcookie ('PHPSESSID'. '', time()-300, '/', '', 0); } $page_title ='logged out!'; echo ' you are now logged out'; Similar TutorialsStumped on this. I copied the syntax of this from another site I'd done (where it works) Then I changed the query, of course. But I'm getting an error, that I'm not sure I understand: The page prints: 451made it to here Warning: mysql_query() expects parameter 1 to be string, resource given in /home/workshop/public_html/register5b.php on line 20 Resource id #4 Warning: mysql_num_rows() expects parameter 1 to be resource, null given in /home/workshop/public_html/register5b.php on line 23 Query failed: And the code is: Code: [Select] <?php if ((isset($_POST['rid'])) && (is_numeric($_POST['rid']))) { $rid = $_POST['rid']; print_r($rid); echo "made it to here"; // connect to database include("x.php"); $query = mysql_query("SELECT tbl_registration.*, tbl_workshops.* FROM tbl_registration_workshop LEFT JOIN tbl_registration ON tbl_registration_workshop.workshop_id = tbl_registration.reg_id LEFT JOIN tbl_workshops ON tbl_registration_workshop.workshop_id = tbl_workshops.workshop_id WHERE tbl_registration_workshop.registration_id = $rid"); $result = mysql_query($query); echo $query; if (mysql_num_rows($result) == 1){ while ($row = mysql_fetch_array($result)) { $workshop = $row['workshop_id']; ?> <!-- from here on, I just print out fields from the data I pull. --> <?php } } }die("Query failed: " . mysql_error()); ?> I'm an extreme newbie and have this current error on my site. The error states: Warning: mktime() expects parameter 4 to be long, string given in featured_product.php on line 75 <?php for ($i = 0; $i < $num_rows; $i++) { $id = mysql_result($result,$i,"id"); $title = mysql_result($result,$i,"title"); $featured = mysql_result($result,$i,"featured"); $feature_date = mysql_result($result,$i,"feature_date"); $feature_date_arr = explode("-",$feature_date); $feat_date = mktime(0,0,0,$feature_date_arr[0],$feature_date_arr[1],2000+$feature_date_arr[2]); if ( ($feat_date+($featured*24*60*60))<time() ) { $db2->query("UPDATE product_catalog SET featured = 0 WHERE id='$id'"); $featured = 0; } else { $featured = 1; $db2->query("UPDATE product_catalog SET featured = 1 WHERE id='$id'"); } ?> Any ideas on how to correct this? Thanks! Here is the error: Code: [Select] Warning: image_type_to_extension() expects parameter 1 to be long, string given in C:\wamp\www\Login\inc\edit-profile.php on line 23 Here is the code for line 23: Code: [Select] $type = image_type_to_extension($_FILES['pic']['type'], true); Here is the code for the whole page: Code: [Select] <?php if(!$userb) { login('?p=edit-profile'); die(); } if(isset($_POST['submit'])) { $mottof = mysql_real_escape_string(bb($_POST['motto'])); $aboutf = mysql_real_escape_string(bb($_POST['about'])); $interesrsf = mysql_real_escape_string(bb($_POST['interests'])); $booksf = mysql_real_escape_string(bb($_POST['books'])); $authorsf = mysql_real_escape_string(bb($_POST['author'])); $randf = mysql_real_escape_string(bb($_POST['random'])); if($_FILES['pic']['type'] == 'image/gif' || $_FILES['pic']['type'] == 'image/jpeg' || $_FILES['pic']['type'] =-'image/pjpeg' || $_FILES['pic']['type'] == 'image/png') { if($_FILES['pic']['size'] < 8388608) { if($_FILES['pic']['name'] != '') { //mkdir('/images/user_images/' .$user_log); $type = image_type_to_extension($_FILES['pic']['type'], true); move_uploaded_file($_FILES['pic']['tmp_name'], 'images/user_images/' .$user_log .'pp' .$type); $path = 'images/user_images/' .$user_log .'pp' .$type; } else { $path = 'images/user_images/user.jpg';} } $q2 = "UPDATE login_info SET profile_picture = '$path' WHERE user='$user_log' "; mysql_query($q2) or die(mysql_error()); } $query = " UPDATE login_info SET motto = '$mottof', about = '$aboutf', fav_books = '$booksf', fav_authors = '$authorsf', interests = '$interesrsf', random = '$randf' WHERE user='$user_log' "; mysql_query($query); echo '<h3> Profile Updated </h3>'; } $q = "SELECT * FROM login_info WHERE user='$user_log' "; $s = mysql_query($q) or die(mysql_error()); $r = mysql_fetch_assoc($s); $motto = $r['motto']; $about = $r['about']; $books= $r['fav_books']; $authors = $r['fav_authors']; $rand = $r['random']; $interests = $r['Interests']; if(isset($_GET['act'])){$red = '?p=' .$rpage ;} else {$red='?p=edit_profile';} echo" <form action='?p=edit-profile' enctype='multipart/form-data' method='post' > <label>Motto: </label> <input type='text' name='motto' value='$motto' placeholder='Motto' /> <label> About :</label> <textarea name='about' cols='40' rows='10'> $about</textarea> <label> Interests: </label> <textarea name='interests' cols='40' rows='10'> $interests </textarea> <label> Favorite Books: </label> <textarea name='books' cols='40' rows='10'> $books </textarea> <label> Favorite Authors </label> <textarea name='author' cols='40' rows='10'> $authors </textarea> <label> Random: </label> <textarea name='random' cols='40' rows='10'> $rand </textarea> "; ?> <script type='text/javascript'> function if_checked() { if($('#cur').is(':checked')) { $('#pic').attr('disabled', true); } else { $('#pic').removeAttr('disabled'); } } </script> <label> Profile Pictu </label> <input type='checkbox' name= 'current' id='cur' onchange="if_checked();" checked /> <label for='current' style='display:inline;'> Current profile picture </label> <br /> <input type='file' id='pic' name='pic' disabled="disabled" /> <br /> <input type='submit' value ='Submit' name='submit' /> </form> Ive used the function before and I havent encountered this error. Im not sure what it means. hello; I installed xampp today ( v2.5 ) and all of my old php/mysql stuff is haywire. ONE example is this: $lvs_result = str_pad( 1 , 4 , "0" , "STR_PAD_LEFT" ) ; print ( $lvs_result . "\n" ) ; //==> Warning: str_pad() expects parameter 4 to be long, string given in C:\xampp\htdocs\testing\index.php on line 18 I am getting dozens of warnings for all kinds of functions however .. any thoughts? old php was 5.2 ... new php is 5.3. thanks. Hi, I'm getting this error: Warning: mktime() expects parameter 5 to be long, string given in /home/user/public_html/include/functions.php on line 58 The code is: if($Date_Format == 1) #For dd-mm-yyyy { $Date_Output = date("d-m-Y",mktime(0,0,0,$Month,$Day,$Year)); } elseif($Date_Format == 2) #For dd/mm/yyyy { $Date_Output = date("d/m/Y",mktime(0,0,0,$Month,$Day,$Year)); } elseif($Date_Format == 3) #For mm-dd-yyyy { $Date_Output = date("m-d-Y",mktime(0,0,0,$Month,$Day,$Year)); } elseif($Date_Format == 4) #For mm/dd/yyyy { $Date_Output = date("m/d/Y",mktime(0,0,0,$Month,$Day,$Year)); } elseif($Date_Format == 5) #For Mon Day YYYY { $Date_Output = date("M D Y",mktime(0,0,0,$Month,$Day,$Year)); } elseif($Date_Format == 6) #For Month Day YYYY { $Date_Output = date("F D Y",mktime(0,0,0,$Month,$Day,$Year)); } elseif($Date_Format == 7) #For Date"nd" Month YYYY { $Date_Output = date("d\\t\h F Y",mktime(0,0,0,$Month,$Day,$Year)); } elseif($Date_Format == 8) #For Month Day YYYY { $Date_Output = date("F d Y",mktime(0,0,0,$Month,$Day,$Year)); } elseif($Date_Format == 9) #For Month Day YYYY { $Date_Output = date("d/m/Y H:i",mktime($DateDispsplittimehr,$DateDispsplittimemin,0,$Month,$Day,$Year)); // Line 58 } return $Date_Output; } else { return NULL; Line 58 says $Date_Output = date("d/m/Y H:i",mktime($DateDispsplittimehr,$DateDispsplittimemin,0,$Month,$Day,$Year)); I really appreciate any help on this. Hi, I'm working on a mac with MAMP, phpMyadmin. on localhost, also the mysql server is on my localhost. I've tested in either Safari and Firefox. I'm trying to set my cookie, and it doesn't work, and pulling my hair out. I'm trying out following script which should work, but it doesn't and it's driving me mad. I wanna check the cookie for when a person is or isn't logged in, so that i can show additional data on the .php page <html> <body> <?php $value = "my cookie value"; // send a cookie that expires in 24 hours setcookie("TestCookie",$value, time()+3600*24); // Print individual cookies echo $_COOKIE["TestCookie"]; // Print all cookies print_r($_COOKIE); ?> </body> </html> i have never been able to get this to work but i am at it agian in this code the php is not making the cookie can any one tell me why <?php function getRandomString($length = 5) { $validCharacters = "abcdefghijklmnopqrstuxyvwzABCDEFGHIJKLMNOPQRSTUXYVWZ+-*#&@!?1234567890"; $validCharNumber = strlen($validCharacters); $result = ""; for ($i = 0; $i < $length; $i++) { $index = mt_rand(0, $validCharNumber - 1); $result .= $validCharacters[$index]; } return $result; } setcookie("code", "getRandomString()", 3600000); echo getRandomString(); ?> Hey Guys, I am trying to set a cookie so that when I registered user returns it Auto Logins them in. I am able to accomplish this on my Local server but as Soon as I upload to a web server to test it, it doesn't work. Is anyone able to shed some light on this for me. $usass = $mem['userid']; if (isset($_POST['rem'])) { $year = 3600*24*365; setcookie ("id" , "$usass", time()+$year); } if the code for setting the cookie, and the code for checking the cookie is Below if(isset($_COOKIE['id'])) { $_SESSION['userid'] = $_COOKIE['id']; print "<script>"; print " self.location='loggedin.php';"; // Comment this line if you don't want to redirect print "</script>"; } For some reason I can not get this to work. Any thoughts? if( $row['password'] == $pass && $row['name'] == $user ) { $username = $row['name']; $uid = $row['id']; setcookie("id", $uid, 1400); //creates the first session var setcookie("username", $username, 1400); // second session var setcookie("loggedin", "1", 1400); echo "<script type=\"text/javascript\">alert(\"".$row['name']."Logged in as ".$_COOKIE['username'].".\"); window.location=\"index.php?OMG=loggedin\"</script>"; } I get a message box saying: "[username] Logged in as ." I've searched php.ini for corrupt cookie settings, nothing unusual. I know PHP setcookie can set for all subdomains - by setting parameter 5 to something like ".domain.com". However, I have quite a lot of code that just leaves param 5 blank (so sets for the current subdomain of that server). Hopefully there'd be an easy way how to do this (a server setting?). I know you can use ini_set('session.cookie_domain','http://domain.com'); but that only seems to set the session cookie value, not ones set in PHP. I only really want it to ensure if someone accesses the site through both www.domain.com and domain.com that they use the same cookies. when a user logs in the cookie isnt being set. am i doing it wrong? if(empty($error)) { $query = $link->query("SELECT * FROM ".TBL_PREFIX."users WHERE u_username = '$username' AND u_password = '".asf_hash($password)."'") or die(print_link_error()); $row = $query->fetchAll(); $num_rows = $query->rowCount(); if($num_rows == 1) { if($row[0]['u_confirmed'] == 1) { setcookie('uid', $row[0]['u_uid'], time() + $session_length); // this cookie isnt being set echo 1; } else { $error = 'You Need To Activate Your Account'; } } else { if(!$error) { echo $lang->incorrect_login_details; } } } im doing a print_r on all cookies and it doesnt appear in the list. $session_length is set at 99999999 I am aiming to use setcookie to refresh the expiry of a cookie on EVERY page request. Is this slow? I'm sure I can design things so i don't need to reset it on every page request, but if it isn't a big deal then I'll do it. Is setcookie slow? hello i use the fallowing code for my login page but it gives me the fallowing error i was wondering what is the problem? (line 179 is the setcookie) by the way it doesn't set the cookie any help would be appreciated error: Quote Warning: Cannot modify header information - headers already sent by (output started at /home2/sportsh9/public_html/test/login_acc.php:6) in /home2/sportsh9/public_html/test/login_acc.php on line 179 my code: <? include_once('functions.php'); function cleanQuery($string) { if(get_magic_quotes_gpc()) // prevents duplicate backslashes { $string = stripslashes($string); } $badWords = "(delete)|(update)|(union)|(insert)|(drop)|(http)|(--)"; $string = eregi_replace($badWords, "", $string); if (phpversion() >= '4.3.0') { $string = mysql_real_escape_string($string); } else { $string = mysql_escape_string($string); } return $string; } if (isset($_COOKIE['scmuser'])) { echo "<META HTTP-EQUIV=\"Refresh\" CONTENT=\"1; URL=index.php\">"; }else{ if ($_POST['username']) { //did they supply a password and username $username=cleanQuery($_POST['username']); $password=cleanQuery($_POST['password']); if ($password==NULL || $username==NULL) { ?> <p align="center"> <font color="#FF0000">Username or password wasn't supplied!</font><form action="login_acc.php" method="POST"> <table style="border:1px solid #FFFFFF;" width="90%" align="center"> <tr> <td align="center">Username: </td> <td align="center"> <input type="text" size="20" maxlength="25" name="username" /></td> </tr> <tr> <td align="center">Password: </td> <td align="center"> <input type="password" size="20" maxlength="25" name="password" /></td> </tr> <tr> <td align="center" colspan="2"> <input type="submit" value="Login"/> </td> </tr> <tr> <td align="center" colspan="2"> <a href="register.php">Register</a> - <a href="forgetpass.php">Forgot Your Password?</a> </td> </tr> </table> </form> <? }else{ $query = mysql_query("SELECT username,password FROM users WHERE username = '$username'") or die(mysql_error()); $data = mysql_fetch_array($query); if($data['password'] != $password) { ?> <p align="center"> <font color="#FF0000">The supplied login was incorrect</font><form action="login_acc.php" method="POST"> <table style="border:1px solid #FFFFFF;" width="90%" align="center"> <tr> <td align="center">Username: </td> <td align="center"> <input type="text" size="20" maxlength="25" name="username" /></td> </tr> <tr> <td align="center">Password: </td> <td align="center"> <input type="password" size="20" maxlength="25" name="password" /></td> </tr> <tr> <td align="center" colspan="2"> <input type="submit" value="Login"/> </td> </tr> <tr> <td align="center" colspan="2"> <a href="register.php">Register</a> - <a href="forgetpass.php">Forgot Your Password?</a> </td> </tr> </table> </form> <? }else{ $query = mysql_query("SELECT username,password FROM users WHERE username = '$username'") or die(mysql_error()); $row = mysql_fetch_array($query); setcookie("scmuser", "$username", time()+3600); echo "<META HTTP-EQUIV=\"Refresh\" CONTENT=\"1; URL=index.php\">"; } } } } ?> thank you Hello. I currently have a site that registered members can login in to and view the member only pages. Eventually I will be adding paypal code to purchase products. I use Session with an IF statement for all my members pages. Would it be beneficial at all to have cookies created for the users with setcookie? Or is this just a security risk waiting to happen? I am working on a login script and I am using cookies for the first time. I have it something like this: <?php if (correct user/pass entered) - set user/pass cookies ?> <html> <?php if (user/pass cookies are set) {echo 'you are logged in';} else {echo 'you are NOT logged in';} ?> </html> The problem is that if I enter a valid username and password, and the cookies are set, then I get the message 'you are NOT logged in' unless I leave the page then return to it, or if I refresh, in which case I get the message 'you are logged in'. Its almost as though I cannot use the cookies until I navigate away from the page on which they were set. Am I doing something wrong, or is this the way it works? I hate header errors... I can never figure them out, im getting this error; Warning: Cannot modify header information - headers already sent by (output started at /home/damnpeti/public_html/restrict2.php:6) in /home/damnpeti/public_html/restrict2.php on line 62 Code: <?php $testDB = mysql_connect('localhost', $db_user, $db_pwd); mysql_select_db ($db_name); if (!$testDB) { die('Could not connect: ' . mysql_error()); } $surfer_ip = $_SERVER["REMOTE_ADDR"]; $str_sql = "select * from ".$db_table." where ipaddress='".$surfer_ip."'"; $result = mysql_query($str_sql); if ($row = mysql_fetch_assoc($result)) { $blocked_time = strtotime($row['blocked_time']); if($blocked_time != 0) { $current_time = time(); if($current_time - $blocked_time > 3600*24) //24 hours past { $str_sql = "delete from ".$db_table." where ipaddress='".$surfer_ip."'"; mysql_query($str_sql); $str_sql = "insert into ".$db_table." (ipaddress, surf_index) values('".$surfer_ip."', 1)"; mysql_query($str_sql); } else { die ("<center><div class='errors'>You have accessed this page too many times. To regain access, purchase a license or wait 24 hours.</div></center>"); } } else { if($row['surf_index'] < 2) { $str_sql = "update ".$db_table." set surf_index=surf_index+1 where ipaddress='".$surfer_ip."'"; mysql_query($str_sql); } else { $str_sql = "update ".$db_table." set blocked_time='".date ("Y-m-d H:i:s")."' where ipaddress='".$surfer_ip."'"; mysql_query($str_sql); die ("<center><div class='errors'>You have accessed this page too many times. To regain access, purchase a license or wait 24 hours.</div></center>"); } } } else { $str_sql = "insert into ".$db_table." (ipaddress, surf_index) values('".$surfer_ip."', 1)"; mysql_query($str_sql); } if(!isset($_COOKIE['surf_no'])) setCookie('surf_no', '1'); else setCookie('surf_no', $_COOKIE['surf_no']+1); if ($_COOKIE['surf_no'] > 2) die("<center><div class='errors'>You have accessed this page too many times. To regain access, purchase a license or wait 24 hours.</div></center>"); include 'http://damnitpetitions.com/cut/index3.php'; ?> Line 62 is if ($_COOKIE['surf_no'] > 2) I know it has something to do with the cookie... but Idk? I need the include there. If there include isnt where its at, the script is worthless. Hi All, I am trying to call a javascript pop-up window via a link by echoing out the html via php but keep getting parse errors: Parse error: syntax error, unexpected ')', expecting ',' or ';' Here is the code in question: Code: [Select] echo "<td class=\"today\"> <a href=\"javascript:statusWindow('status.php?month=".$month."&day=".$day."&year=$year');\">"$day_num</a> </td>\n"; And here is the javascript function: Code: [Select] <script type="text/javascript"> function statusWindow(url){ status_popupWin = window.open(url, 'status', 'resizable=yes, scrollbars=yes, toolbar=no,width=400,height=400'); status_popupWin.opener = self; } </script> Any help is appreciated. Thanks, kaiman trying to figure this problem out. sucks being a newbie maybe i will gain enough knowledge to be able to help out others in the near future. Code: [Select] <?php session_start(); $DBConnect = @mysqli_connect("localhost", "**********", "**********") Or die("<p>Unable to connect to the database server.</p>" . "<p>Error code " . mysqli_connect_errno() . ": " . mysqli_connect_error()) . "</p>"; $DBName = "skyward_aviation"; @mysqli_select_db($DBConnect, $DBName) Or die("<p>Unable to select the database.</p>" . "<p>Error code " . mysqli_errno($DBConnect) . ": " . mysqli_error($DBConnect)) . "</p>"; $CustomerName = ""; if (isset($_COOKIE['customerName'])) $CustomerName = $_COOKIE['customerName']; $TableName = "mileage"; $Mileage = 0; $SQLstring = "SELECT SUM(mileage) FROM $TableName WHERE flyerID='{$_SESSION['flyerID']}"; $QueryResult = @mysqli_query($DBConnect, $SQLstring); if (mysqli_num_rows($QueryResult) > 0) { $Row = mysqli_fetch_row($QueryResult); $Mileage = number_format($Row[0], 0) ; mysqli_free_result($QueryResult); } mysqli_close($DBConnect); ?> i know its a simple stupid error but cant remember nor figure it out. HERES THE ERROR Warning: mysqli_num_rows() expects parameter 1 to be mysqli_result, boolean given in C:\xampp\htdocs\PHP_Projects\Chapter.10\FrequentFlyerClub.php on line 23 I am trying to create a simple voting form. Everything goes well until I submit and then I get a Warning: mysqli_error() expects exactly 1 parameter, 0 given on line 79 error. I am assuming it is not pulling the ID correctly but as I am new to php and mysqli I cannot exactly say if it the way the code is written or if I am calling the parameter incorrectly in the query. Again I am new to to this so please be gentle. Below is my code. It pulls the drop down list correctly and echo's correctly but I believe my post query to be a little out of wack. Could someone point me in the correct direction? It would be very appreciated.
<form action="businesstype_update.php" method="post">
<?php
if(isset($_POST['voteall'])){
$vote_lg = "update membertest where id={$row_lg['id']} set vote=vote+1";
$run_lg = mysqli_query($con, $vote_lg) or die(mysqli_error());
}
$result_lg = mysqli_query($con, "SELECT id, business FROM membertest WHERE businesstype='large'");
echo "Vote for large business of the year! <SELECT name='business'>\n";
echo "<option>Select a large business</option>";
while($row_lg = $result_lg->fetch_assoc()) {
echo "<option value='{$row_lg['id']}'>{$row_lg['business']}</option>\n";
}
echo "</select></br></br>\n";
echo "<input type='submit' name='voteall' value='voteall'>";
$result_lg->close();
$con->close();
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