PHP - How To Remove All White Spaces In Front Of A Form Entry ?

I'm familiar with 'trim' and even tried the following:

$datanew = str_replace(array("\n", "\r", "\t", " ", "\o", "\xOB"), '', $data);

but for the life of me I can't remove any white space within the source code which is messing everything else up.

This is what I need:
What people see....
Code: [Select]
word1 word2 word3

The source...
Code: [Select]
word1
word2
word3

This is the current situation
What people see...
Code: [Select]
word1 word2 word3

The source...
Code: [Select]
word1


                                               word2
                                                                       


                                                                                    word3

For whatever reason, if I can strip the whitespace from the source code then I can use the content accordingly. How would do you strip the white space? Does this even make sense? 

Hi, I was just trying to post form data to MySQL and trying to also post value of logged in user? but that code below doesnt work..Do you see a typo? or is it done some other way?

 

$uid =$_SESSION[ "uid" ]; 

$sql = "INSERT INTO Date (uid) VALUES (:uid)"; 
$query= $conn->prepare( $sql ); 
$query->execute( array( ':uid'=>$uid) );

 

	$value0 = $_POST['date1'];
    $value1 = $_POST['date2'];
    $value2 = $_POST['date3'];

$sql = "INSERT INTO Datetable (startdate,enddate, total)
VALUES ('$value0','$value1', '$value2')" ;

$result = mysqli_query($sql);

Hi,

I was wondering is it possible to not insert values in MySQL if form entry is left blank? Right now if I dont enter any values in form for my dates than MySQL entry shows 0000-00-00 but I need it not to show anything.

 

Alright,  wasn't quite sure how to summarize this in the title,  but I want to:

Check if a user status is "active" or not based on the UserName input.

I have a table witch holds:

Code: [Select]
VarChar Username      Var CharPassWord     int Active
 Ted                        TedsPW                1
something like the above(assuming it formatted correctly.

In my php script I will want to input a variable for Username to check for:

inputUN in this example would be "Ted".

$UserNameToCheck = $_GET['inputUN'];

Then I want to check for that UserName in the database,  if it exists,  I want pull the value for the "Active" field for just that UserName and echo it.

Thanks for any help.
 

I'm looking at creating a web interface for cusotmers to enter credit card information.

What is the best approach for this? Keeping in mind security of data... Maybe this last point is more a question for web server administrators, but thought I'd ask anyway.

I spent several hours trying to figure this thing out.  Thought I had it nailed, but still getting duplicate record entries into the MySQL DB when I do NOT want them.   Here's the plot:   People filling out the possible attendance form for a Ham Radio event *sometimes* bring a 2nd person (either a spouse or a friend).  The 2nd person may, or may not, also has a Callsign which I need to put INSERT the same MySQL Callsign column.  In any event, to also identify the 2nd person as coming 'with' the 1st person.   MOST of the attendees are individuals with NO 2nd person.   My entry form has these primary fields:   callsign fullname   AND...   callsign2 fullname2   What I came up with was to process the MySQL INSERT for the primary callsign & fullname into their respective MySQL DB Columns (which works fine), and then........... immediately following the main Query INSERT, to do a substitution type thing depending on whether or not a form entry  was made in the callsign2 field, AND/OR, the fullname2 field.   This partially works, but if there is ONLY a primary callsign and fullname in the form, I'm still getting a duplicate record entry which includes the callsign in the `with` column (which should ONLY take place IF there is a 2nd person indicated).   Confusing?   Here is what I have  been wrestling with to try and accomplish the objective, and now my eyes are glazed over ;-(

// TRICKY PART HERE

// If a 2nd Callsign AND a Fullname

if ($callsign2 != ' ' && $fullname2 != ' ') {

// Still make reference to the primary Callsign in the MySQL DB `with` column

$with = $callsign;

// Assignment to allow 2nd Callsign to be entered in the MySQL `callsign` column

$callsign=$callsign2;
$fullname=$fullname2;

$sql="INSERT INTO `mytable` (`callsign`, `fullname`, `with`)
VALUES ('$callsign', '$fullname', '$with')";

// If NO 2nd Callsign BUT a Fullname

} elseif ($callsign2 = ' ' && $fullname2 != ' ') {

// Make reference to the primary Callsign in the MySQL DB `with` column

$with = $callsign;

$callsign=$callsign2;
$fullname=$fullname2;

$sql="INSERT INTO `mytable` (`callsign`, `fullname`, `with`)
VALUES ('$callsign', '$fullname', '$with')";

} else {

// The only thing I could thing of to (hopefully) NOT make a 2nd entry 
// record in the MySQL DB IF there is NO 2nd person referenced

$with = $callsign;

}

if (!mysqli_query($con,$sql)) {
  die('Error: ' . mysqli_error($con));
}

This mostly works EXCEPT if only a single (primary) person entry.   The recap the objetives:   1. If ONLY a primary/single person entry on the form:   * callsign & fullname get INSERTed into the `callsign` and `fullname` columns in the DB as ONLY one record entry   2. If BOTH a primary and 2nd person on the form:   A. IF the 2nd person has a Callsign, then the 2nd record entry would be:   *   callsign2 & fullname2 get INSERTed into the `callsign` & `fullname` columns in the 2nd DB as a separate record entry *   callsign of the primary person also gets INSERTED into the `with` column in the same 2nd DB record entry   B. IF the 2nd person does NOT have a callsign, then the 2nd record entry would be:   *  fullname2 gets INSERTed into the `fullname` column in the DB as a separate 2nd DB record entry *  callsign of the primary person also gets INSERTED into the `with` column in the same 2nd DB record entry   I obvioiusly have overlooked something, but just can't seem to figure it out at this point {SIGH}.   Thanks for any enlightenment.   -FreakingOUT      

When there is a duplicate entry in my database, I would like it to go to the another page that indicates the error, rather than the "Error: Duplicate entry 'username' for key 1". It happens if someone is going to join and there is a duplicate entry. I would rather it show one of my customized php pages rather than a black page stating the error.

I've tried to catch the entry with some php code but it bypasses it and continues with the duplicate error.

I would appreciate any direction with this. Thanks!

I am using php to upload a file to my server, and at the same time inserting the files name and url into my mysql database.

$sql = "UPDATE uploads SET name = '$name', url='$target_path'";
    $statement = $dbh->prepare($sql); 
    $statement->execute();

This is working, however, when I upload a new file, rather than making a new entry in my database, it just overwrites the first one.

I'm quite new at mysql so was wondering how I would make it add new entrys instead of overwriting the current one?

I have a table called "colors".  It has 2 columns, id and color.

All I'm trying to do is pull the data into the form, then edit the colors (for example - misspelled, etc.)
Then submit it back to the table.

Here is the code that pulls the data into a form so I can edit it:
Code: [Select]
<form action="adminupdatecolors.php" method="post">

<table width="500" border="1" cellpadding="10">

<tr>
  <td>Color Options:</td>
    <td>
    <?
$result = mysql_query("SELECT * FROM colors");
while ($row = mysql_fetch_assoc($result)) {

echo '<input type="text" name="color[]" value="' . $row['color'] . '"/>' . $row['id'] . '<br />';
}

?>
   </td>
</tr>

   <tr>
  <td>&nbsp;</td>
  <td><input type="Submit" value="Update Colors"></td>
  </tr>
</form>
</table>

Here is my update script:
Code: [Select]
<?php

include("config.php");
include("db.php");

$id=$_POST['id'];
$color=$_POST['color'];

$result = mysql_query("SELECT id FROM colors ORDER BY id DESC LIMIT 0,1");

if ($row = mysql_fetch_assoc($result)) {
$id = $row['id']; 
}
$sql = "DELETE FROM colors WHERE id='$id'";
mysql_query($sql) or die("Error: ".mysql_error());

foreach ($color as $colorvalue) {
$sql2 = "INSERT INTO colors (id,color) VALUES ($id,'$color')";
mysql_query($sql2) or die("Error: ".mysql_error());

}

header("Location: " . $config_basedir . "adminhome.php");

?>

I am trying to set up a item entry page form.png:

Upon submission it shows unsuccessful even though I have checked the fields on mysql table and seem to be good am I missing something?

Code: [Select]
<form action="" method="post" enctype="multipart/form-data" name="Product_Entry">
<TABLE>
<TR>
<TD>Product ID</TD><TD><input name="SKU_ProductID" value="<?php if (isset($_post['SKU_ProductID'])) echo $_POST['SKU_ProductID']; ?>" type="text" size="11" maxlength="11" /></TD>
</TR>
<TR>
<TD>Merchant SKU ID</TD><TD><input name="SKU_MerchSKUID" value="<?php if (isset($_post['SKU_MerchSKUID'])) echo $_POST['SKU_MerchSKUID']; ?>" type="text" size="18" maxlength="30" /></TD>
</TR>
<TR>
<TD>Game Title</TD><TD><input name="Game_Title" value="<?php if (isset($_post['Game_Title'])) echo $_POST['Game_Title']; ?>" type="text" size="40" maxlength="40" /></TD>
</TR>
<TR>
<TD>Platform</TD><TD><input name="Platform" value="<?php if (isset($_post['Platform'])) echo $_POST['Platform']; ?>" type="text" size="20" maxlength="20" /></TD>
</TR>
<TR>
<TD>Genre</TD><TD><input name="Genre" value="<?php if (isset($_post['Genre'])) echo $_POST['Genre']; ?>" type="text" size="11" maxlength="11" /></TD>
</TR>
<TR>
<TD>Weight</TD><TD><input name="Weight" value="<?php if (isset($_post['Weight'])) echo $_POST['Weight']; ?>" type="text" size="7" maxlength="7" /></TD>
</TR>
<TR>
<TD>Supplier</TD><TD><input name="Supplier" Value="<?php if (isset($_post['Supplier'])) echo $_POST['Supplier']; ?>" type="text" size="25" maxlength="25" /></TD>
</TR>
<TR>
<TD>Suppliers Price</TD><TD><input name="Supplier_Price" value="<?php if (isset($_post['Supplier_Price'])) echo $_POST['Supplier_Price']; ?>" type="text" size="10" maxlength="12" /></TD>
</TR>
<TR>
<TD>Cashback</TD><TD><input name="Cashback" value="<?php if (isset($_post['Cashback'])) echo $_POST['Cashback']; ?>" type="text" size="6" maxlength="8" /></TD>
</TR>
<TR>
<TD>Cashback Amount</TD><TD><input name="Cashback_Amount" value="<?php if (isset($_post['Cashback_Amount'])) echo $_POST['Cashback_Amount']; ?>" type="text" size="7" maxlength="11" /></TD>
</TR>
<TR>
<TD><input type="hidden" name="submitted" value="true"/></TD><TD><input name="Submit" type="submit" value="Add_Product" /></TD>
</TR></form></TABLE>

<?php # Product Entry

$page_title = 'Product Entry';

if (isset($_POST['Submit'])) {

$errors = array();

if (empty($_POST['SKU_ProductID'])) {
$errors[] = 'Please enter Product ID.';
} else {
$sid = trim($_POST['SKU_ProductID']);
}

if (empty($_POST['SKU_MerchSKUID'])) {
$errors[] = 'Please enter Merchant SKU.';
} else {
$mid = trim($_POST['SKU_MerchSKUID']);
}

if (empty($_POST['Game_Title'])) {
$errors[] = 'Please enter Game Title.';
} else {
$gt = trim($_POST['Game_Title']);
}

if (empty($_POST['Platform'])) {
$errors[] = 'Please enter Platform.';
} else {
$pl = trim($_POST['Platform']);
}

if (empty($_POST['Genre'])) {
$errors[] = 'Please enter Genre.';
} else {
$ge = trim($_POST['Genre']);
}

if (empty($_POST['Weight'])) {
$errors[] = 'Please enter Weight.';
} else {
$we = trim($_POST['Weight']);
}

if (empty($_POST['Supplier'])) {
$errors[] = 'Please enter Supplier.';
} else {
$sup = trim($_POST['Supplier']);
}

if (empty($_POST['Supplier_Price'])) {
$errors[] = 'Please enter Supplier Price.';
} else {
$sp = trim($_POST['Supplier_Price']);
}

if (empty($_POST['Cashback'])) {
$errors[] = 'Please enter Cashback %.';
} else {
$cb = trim($_POST['Cashback']);
}

if (empty($_POST['Cashback_Amount'])) {
$errors[] = 'Please enter Cashback Amount.';
} else {
$cba = trim($_POST['Cashback_Amount']);
}

if (empty($errors)) {

require_once ('connect.php');

[b]$q = "INSERT INTO `Products` (`SKU_ProductID`, `SKU_MerchSKUID`, `Game_Title`, `Platform`, `Genre`, `Weight`, `Supplier`, `Supplier_Price`, `Cashback`, `Cashback_Amount`) VALUES ('$sid', '$mid', '$gt', '$pl', '$ge', '$we', '$sup', '$sp', '$cb', '$cba')";
$r = @mysql_query ($dbc, $q);

if ($r) { // If it ran OK.

// Print a message:
echo '<h1>Thank you!</h1>
<p>Product Inserted!</p><p><br /></p>';

} else { // If it did not run OK.

// Public message:
echo '<h1>System Error</h1>
<p class="error">You could not be registered due to a system error. We apologize for any inconvenience.</p>'; 

// Debugging message:
echo '<p>' . mysqli_error($dbc) . '<br /><br />Query: ' . $q . '</p>';

} // End of if ($r) IF.

mysqli_close($dbc); // Close the database connection.[/b]
// Include the footer and quit the script:
include ('includes/footer.html'); 
exit();

} else {

echo '<H1>Error!</H1>
<p class="error">The Following error(s) occurred:<br />';

foreach ($errors as $msg) {

echo " - $msg<br />\n";
}

echo '</p><p>Please try again.</p><p><br /></p>';

}

}

?>
If there is anything else needed let me know

Say I have an "Entries" table. I want to submit same multiple entries using a form submission. And If I have other queries submitted in the same form, I want those quarries to be submitted only once.  Is that possible to do? 

Here's my code.

if(isset($_POST['submit'])) {

  $entries = 10;

  $id   = 55;
  $name = 'Smith';

  $insert = $db->prepare("INSERT INTO entries(id, name) VALUES(:id, :name)");
  $insert->bindParam(':id', $id);
  $insert->bindParam(':name', $name);
  $result_insert = $insert->execute();
  if($result_insert == false) {
    echo 'Fail';
  } else {
    echo 'Success';
  }

}
?>
<form action="" method="post">
  <input type="submit" name="submit" value="SUBMIT" />
</form>

 

Edited January 13, 2019 by imgrooot

This for loop:


 for ($m = 01; $m <= 12; $m++)


Will output:
1
2
3
4
etc.

And NOT:
01
02
03
04


My question is: how can I make the number be 2 digits and have it output together with the ZERO?

And when it's reaching the number 10 it should continue outputting:

10
11
12

And not

010
011
etc.

This is driving me nuts and I'm hoping someone can help me figure it out.  I have a site with PHP/MySQL.  I have a form where people can submit a comment.  This comment then goes into a MySQL database and gets displayed back on another page of the website.

NOTE:  I put this question in the PHP Forum because I think the problem is happening somewhere BEFORE the info gets entered into MySQL.  But of course, I could be wrong.

The problem is that some of the comments are coming in with a "\" in front of apostropes, but NOT ALL OF THEM (which is really confusing me).

For example, someone entered this comment which shows in the MySQL database exactly like this...

I predict Lena's gonna win a lifetime Grammy.  It's long overdue.

Someone else entered a comment which shows in the MySQL database exactly like this...

can\\\'t wait to see first pics of the next addition.  Congrats!

They both have apostrophes in them, but only that second one added those slashes (and 3 of them for some reason). 

There are more instances of this where some comments have the slashes before the apostrophe and some don't.  Anyone know what might be causing this seemingly random insertion of slashes?