PHP - Accessing An Object On Different Page

i have created an object in one page. it has a submit button which upon clicking opens a new page. is it possible to access that created object and its data members in that second page?

here is the code for creating the object in the first page.


$viewcart = new Cart();
$viewcart->GetProductCart($user);

Hey all,

I want to have an object that has a property which is an object containing instances of other objects. I try this:
Code: [Select]
class Blog extends Posts {
public $has_posts;

public function __construct($a,$b,$c){
$has_posts = (object) array_merge((array) $a, (array) $b, (array) $c);
}
}

class Posts {
public $b;

public function __construct($b){
$this->b = $b;
}
}

$post1 = new Posts(1);
$post2 = new Posts(2);
$post3 = new Posts(3);

$blog = new Blog($post1,$post2,$post3);
var_dump($blog->has_posts); //null
foreach($blog->has_posts as $post){ //Invalid argument supplied for foreach()
echo $post->b;
}

But as you see, has_posts is null, not an object containing other objects.

Thanks for response.

I have a Soup object in a Bowl object in a Microwave object.

The Microwave object has the methods:

receiveItem(Bowl $b)
cookItem(???)

I want the Microwave to be able to set the Soup->temperature but I'm not how to do that?

Make sense?



TomTees

Hi guys,

I have xml that looks like:

<item>
<title></title>
<link></link>
<description></description>
<dc:date>2011-02-27T16:42:31-05:00</dc:date>
</item>


I can access title, link, and description just fine.  But how do I access a tag that has a colon?

I tried this:

Code: [Select]
$x = new SimpleXmlElement($content);
$entry = $x->item;

$entry->children('dc', true)->date;

Thanks for looking.

LR

If $result contains the result of mysql_query, a select count distinct query, how do I access the count?  I've tried $result[0] to no avail and $result only returns the resource #.

HEy Guys
Here is a snippet of an array:

SimpleXMLElement Object
(
    [report1] => SimpleXMLElement Object
        (
            [ReportHost] => Array
                (
                    => SimpleXMLElement Object
                        (
                            [HostName] => 192.168.2.34
                            [startTime] => Thu Dec 17 13:58:49 2009
                            [stopTime] => Thu Dec 17 15:13:13 2009
                            [netbios_name] => (unknown)
                            [mac_addr] => (unknown)
                            [dns_name] => (unknown)
                            [os_name] => (unknown)
                            [num_ports] => 2
                            [num_lo] => 0
                            [num_med] => 0
                            [num_hi] => 0
                            [ReportItem] => Array
which is printed using print_r($a)
now how can i access [HostName] => 192.168.2.34 in the $a array??
Thanks in advance

Hi all,

I've tried to access the admin.php of the xcart installation he http://www.cleaningshopuk.com but it doesn't allow me to access it, saying that it's a 404 page not found error.

That page does in fact exist, but I think the issue might be something to do with a redirection. The site owner apparently clicked on something in the admin section (possibly https or something similar) but what can I do to avoid this issue without having to re install everything?

Thanks,

Neil

Is it possible to have a class access another class it its parent directory without using a fully qualified name?  While the following script is not valid, it is how I would have thought it would be done should it be possible.  If it is not possible, I expect there is a good reason why one would not want to do so, and would appreciate your thoughts why that is so.  Thanks

// src/PrimaryTopic/SubTopic/SubSubTopic/ParentClass.php
namespace PrimaryTopic\SubTopic\SubSubTopic;
class ParentClass {}

// src/PrimaryTopic/SubTopic/SubSubTopic/Child/ChildClass1.php
namespace PrimaryTopic\SubTopic\SubSubTopic\Child;
class ChildClass1 extends ..\ParentClass {}

// src/PrimaryTopic/SubTopic/SubSubTopic/Child/ChildClass2.php
namespace PrimaryTopic\SubTopic\SubSubTopic\Child;
class ChildClass2 extends ..\ParentClass {}

 

So basically I'm using PHP to solve a math problem for me. The user puts in a few parameters and the program runs those numbers through the algorithm and spits out a bunch of xy coordinates. I'm using the PHP SELF method to retrieve the user input. This all works fine, but it's afterwords that I run into problems. I create a drop down menu of all the x values and I want the user to be able to choose any x value they wish and to have the corresponding y value be displayed. The problem is that I have to use another POST command for this and when I do, it wipes out all the computed data.  Of course the y-value is never displayed, and there lies the problem.

I'm sure there are many ways to get around this, but I could not find one out myself. Anyone have any ideas?

I use a CURL script API with the header "$headers[] = 'Content-Type: application/json';"

The script ends with "$result = curl_exec($ch);"

If I simply echo the $result to  my browser, I get an array that looks like this:

stdClass Object
(
    [fromAddress] => stdClass Object
        (
            [name] => Fred Sender
            [phone] => 203-111-0000
        )

    [toAddress] => stdClass Object
        (
            [name] => Susan Recipient
            [phone] => 919-555-1212
            
What is the absolute minimum I need to do to access the phone number in the "toAddress" (919-555-1212).

Do I really need to "json_decode" this array?

I've spent 2 1/2 days trying every which way, with every permutation to access that one value:

echo $result["fromAddress"]["phone"];
echo $result->fromAddress->phone;
echo $result[0]->fromAddress->phone
echo $arr[0]->fromAddress->phone; // $arr = json_decode($result);
echo $arr->fromAddress->phone;
echo $arr[0]->fromAddress->phone;
echo $arr[0]->fromAddress["phone"];

Unfortunately I must have fallen asleep during the array lesson in PHP class  ?

Thank you.

Hi all,

I am still trying to figure what went wrong. It doesn't work over here.

The error shown was the {else} command
else {
      echo '<p class="error">There was a problem accessing your profile.</p>';
   }

I have attached my 4 sql tables for reference. Appreciate any advices....

Code: [Select]
<?php
$query3 = "SELECT ols.subject_level_id, sl.level_id, sl.subject_id, tl.level_name AS level_name, ts.subject_name AS subject_name " .
        "FROM tutor_overall_level_subject AS ols " .
"INNER JOIN tutor_subject_level AS sl USING (subject_level_id) " .
        "INNER JOIN tutor_level AS tl USING (level_id) " .
        "INNER JOIN tutor_subject AS ts USING (subject_id) " .
"WHERE ols.tutor_id = '" . $_GET['tutor_id'] . "'";


  $data3 = mysqli_query($dbc, $query3)
  or die(mysqli_error($dbc));

  if (mysqli_num_rows($data3) == 1) {

echo '<div id="panel4">';

echo'<table><tr>'; // Start your table outside the loop... and your first row
$count = 0; // Start your counter
while($row3 = mysqli_fetch_array($data3)) {
/*  Check to see whether or not this is a *new* row
If it is, then end the previous and start the next and restart the counter.
*/
if ($count % 5 == 0) { 
echo "</tr><tr>"; $count = 0;
}
echo '<td class="label">' . $row3['level_name'] . '</td><td>' . $row3['subject_name'] . '</td>';
$count++; //Increment the count
} 
echo '</tr></table><br/>'; //Close your last row and your table, outside the loop

echo '</div>'; //End of panel 4

} //End of if (mysqli_num_rows($data3) == 1)

else {
echo '<p class="error">There was a problem accessing your profile.</p>';
}
?>

Hey everyone,
I'm creating a website which requires users to login. I didn't want to have to do my own crypto, so I basically created it with Wordpress. I'm at the point where I don't want to use Wordpress for the whole site--just the login system. So I was wondering how I can piggyback off the user management system of Wordpress while using my own script for the rest of the site. I know that Wordpress ends up storing passwords in the database as HMACs, for what that's worth.
Thank you,
Ryan

Can somebody help me what i'm  doing wrong? The value from database is not visible when using:
<?php
$artikel = new Artikel();
$content= $artikel->printArtikel();
echo $content;
?>


<?php
class Artikel {
                // db connection
protected $mydb; 

                // database value
protected $land;

public function __construct($artikelnummer = false)
{  // databaseconnection:
$this->mydb = new MyDB();

if($artikelnummer)
{
$this->load($artikelnummer); 
}
else // load everything from database.
{
$sql = "SELECT * FROM artikel";
$this->mydb->doQuery($sql);
$this->mydb->close();
}
}

public function load($artikelnummer)
{
$sql = "SELECT * FROM artikel";
$this->mydb->doQuery($sql);

if($artikel = $this->mydb->fetch())
{
    // i got a feeling there is something missing here, like query from database??
                }
$this->mydb->close();
}

public function printArtikel()
{
// return database value as table.
$html = "<table border='1'>";
$html .= "<tr>
<td>".$this->land."</td> 
                </tr>";
$html .= "</table>";
return $html;
}
}
?>


Other class are accessing extern. For example database connection with class MyDB.
please, can somebody correct my script??

    I have the following code in zend:

  Code: [Select]
$arrErrors=array();
     if (!empty($this->post['submit']))
    {
    // Each time theres an error, add an error message to the error array
           // using the field name as the key.
          if (empty($this->post['client_name']))
      $arrErrors['client_name'] = "Please Enter Client's name as it appears in the carrier software";
    }
if i set $this->view->arrErrors=$arrErrors in the controller,
Can I access it as $this->arrErrors['client_name'] in the view?

Hello every1,   I'm trying to create a magazine wesite and I dont want anybody to access my images folder which is located in the root directory.   I want some thing like this...   I want to call the images in my website using <img> tag but I dont want any1 to access the directory directly.   It should also protect from software bots also like (HTTrack or website Copier)   It should show "Access forbidden".   Any help will be greatly appreciated.   Thank you...