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PHP - Expiry Date
I'm trying to get an expiry date to work on my project.... but at the moment... it doesnt seem to be working.
Heres the code for the main news submission form: Code: [Select] <form action='newsubmit.php' method='POST'> Title: <input type='text' name='title' /><br /> Story: <input type='text' name='story' /><br /> Upload Image: <a href="#" onclick="window.open('fileuploadprocess.php','mywindow','width=450,height=300,toolbar=no,location=no,directories=no,s tatus=no,menubar=no,scrollbars=yes,copyhistory=yes,resizable=yes')"> Click here</a> <?php require_once('../../../2740/recaptcha/recaptchalib.php'); $publickey = "6Ldbd8ASAAAAAL96lIWHSDRmoaVJhgQJuKQwXNbd"; echo recaptcha_get_html($publickey); ?> <input type='submit' name='submit' value='Submit' /> <input name='reset' type='reset' value='Reset' /> </form> Heres the code for the submission page: Code: [Select] <?php include_once("functions.php"); session_start(); $submit = clean_string($_POST['submit']); $title = clean_string($_POST['title']); $story = clean_string($_POST['story']); $datetoday = date('Y-m-d', $expires); $daystoexpire = '7'; $expires = time() + (86400 * $daystoexpire); $userid = $_SESSION['userID']; $newsimage = $_SESSION['imagelocation']; $message = ''; require_once('../../../2740/recaptcha/recaptchalib.php'); $privatekey = "6Ldbd8ASAAAAAFz8VT29H5w4WLNjsbI-mFY2QkaC"; $resp = recaptcha_check_answer($privatekey, $_SERVER["REMOTE_ADDR"], $_POST["recaptcha_challenge_field"], $_POST["recaptcha_response_field"]); $message = ""; if ($submit == 'Submit') { if (!$resp->is_valid) { // What happens when the CAPTCHA was entered incorrectly $errMessage = $resp->error; $message = "<strong>The reCAPTCHA wasn't entered correctly. Please try again.</strong><br />" . "(reCAPTCHA said: $errMessage)<br />"; } else { // Process valid submission data here if ($title && $story) { //process details here if (strlen($title) > 80) { $message = "The title you have provided is too long. Please <a href='news_entry.php'>try again</a>"; } else { if (strlen($story) > 300) { $message = "The news story you have provided is too long. Please <a href='news_entry.php'>try again</a>"; } else { require_once("db_connect.php"); if ($db_server) { mysql_select_db("a200458721"); //Insert news story into news table $query = "INSERT INTO news (usersID, title, story, image, datetoday, expires) VALUES ('$userid', '$title', '$story', '$image', '$datetoday', '$expires')"; mysql_query($query) or die("User insert failed. " . mysql_error() . "<br />" . $query); $message = "News Story Successfully Submitted! Return to <a href='index.php'>homepage</a>"; } } } } else { $message = "Failed to connect to database"; } if ($expires < time()) { // Expired! } require_once("db_close.php"); } } else { $message = "please fill in all the required fields"; } echo $message; mysql_close($db_server); ?> At the moment, this is the error its throwing up: I'm not sure why its saying about the 1970 date either... User insert failed. Incorrect datetime value: '1303391514' for column 'expires' at row 1 INSERT INTO news (usersID, title, story, image, datetoday, expires) VALUES ('13', 'NEWS TITLE GOES HERE', 'NEWS STORY', '', '1970-01-01', '1303391514') Any ideas on why its throwing me up the error? Similar TutorialsWe are working on a new student application system. Due to privacy laws, everything will be done behind https. However, this is one of many systems looked after by the system administrators. I would like to safeguard against the situation several years down the road when the certificate expires. There are several administration pages that will be checked frequently by the graduate admin assistant. While this person has no technical background, a warning several months before the certificate expires would allow her to remind the technical staff to renew the certificate. I know I can use curl to connect to my own server, but that seems like a long way to do it (and an extra https connection). Is there any way to get the certificate information for the current https connection from the server or from the php runtime? I've simply set some sessions.... $_SESSION['LoggedIn'] = 1; $_SESSION['UserID'] = $row["UserID"]; They don't seem to last very long, usually when I close my browser and go back on later, they'll expire. I want them to last permanently unless the user logs out. How do I do this? Thanks in advance. Hello guys, I am new to PHP. I need some help. I am trying to build a web app, in which I have login functionality. I want to keep the logged in user session active for around 3-4 months. But in my case as soon as I close the browser, session data is lost and I need to login again. Can anyone help me with this. Hey, I'm using a script which allows you to click on a calendar to select the date to submit to the database. The date is submitted like this: 2014-02-08 Is there a really simple way to prevent rows showing if the date is in the past? Something like this: if($currentdate < 2014-02-08 || $currentdate == 2014-02-08) { } Thanks very much, Jack Hello. I'm new to pHp and I would like to know how to get my $date_posted to read as March 12, 2012, instead of 2012-12-03. Here is the code: Code: [Select] <?php $sql = " SELECT id, title, date_posted, summary FROM blog_posts ORDER BY date_posted ASC LIMIT 10 "; $result = mysql_query($sql); while($row = mysql_fetch_assoc($result)) { $id = $row['id']; $title = $row['title']; $date_posted = $row['date_posted']; $summary = $row['summary']; echo "<h3>$title</h3>\n"; echo "<p>$date_posted</p>\n"; echo "<p>$summary</p>\n"; echo "<p><a href=\"post.php?id=$id\" title=\"Read More\">Read More...</a></p>\n"; } ?> I have tried the date() function but it always updates with the current time & date so I'm a little confused on how I get this to work. Alright, I have a Datetime field in my database which I'm trying to store information in. Here is my code to get my Datetime, however it's returning to me the wrong date. It's returning: 1969-12-31 19:00:00 $mysqldate = date( 'Y-m-d H:i:s', $phpdate ); $phpdate = strtotime( $mysqldate ); echo $mysqldate; Is there something wrong with it? I have tried a large number of "solutions" to this but everytime I use them I see 0000-00-00 in my date field instead of the date even though I echoed and can see that the date looks correct. Here's where I'm at: I have a drop down for the month (1-12) and date fields (1-31) as well as a text input field for the year. Using the POST array, I have combined them into the xxxx-xx-xx format that I am using in my field as a date field in mysql. <code> $date_value =$_POST['year'].'-'.$_POST['month'].'-'.$_POST['day']; echo $date_value; </code> This outputs 2012-5-7 in my test echo but 0000-00-00 in the database. I have tried unsuccessfully to use in a numberof suggested versions of: strtotime() mktime Any help would be extremely appreciated. I am aware that I need to validate this data and insure that it is a valid date. That I'm okay with. I would like some help on getting it into the database. (continuing from topic title) So if I set a date of July 7 2011 into my script, hard coded in, I would like the current date to be checked against the hard coded date, and return true if the current date is within a week leading up to the hard coded date. How could I go about doing this easily? I've been researching dates in php but I can't seem to work out the best way to achieve what I'm after. Cheers Denno Hi, I have a job listing website which displays the closing date of applications using: $expired_date (This displays a date such as 31st December 2019) I am trying to show a countdown/number of days left until the closing date. I have put this together, but I can't get it to show the number of days.
<?php
$expired_date = get_post_meta( $post->ID, '_job_expires', true );
$hide_expiration = get_post_meta( $post->ID, '_hide_expiration', true );
if(empty($hide_expiration )) {
if(!empty($expired_date)) { ?>
<span><?php echo date_i18n( get_option( 'date_format' ), strtotime( get_post_meta( $post->ID, '_job_expires', true ) ) ) ?></span>
<?php
$datetime1 = new DateTime($expired_date);
$datetime2 = date('d');
$interval = $datetime1->diff($datetime2);
echo $interval->d;
?>
<?php }
}
?>
Can anyone help me with what I have wrong? Many thanks I'm getting this Time Zone error. Perhaps it's a compatibility issue with PHP 5.3. Looked all over for an answer without finding one. Here is the error message Warning: date() [function.date]: It is not safe to rely on the system's timezone settings. You are *required* to use the date.timezone setting or the date_default_timezone_set() function. In case you used any of those methods and you are still getting this warning, you most likely misspelled the timezone identifier. We selected 'America/New_York' for 'EST/-5.0/no DST' instead in /blocked.php on line 41 12/02/12 Here is the code. Line 41 is near the bottom, the one with the d,m,y. Perhaps the echo date (d/m/y") needs to be changed. Appreciate any help! Code: [Select] <table border="3" width="16%" align="center" cellspacing="0" bgcolor="#FF6600" bordercolor="red" bordercolordark="red" bordercolorlight="red"> <tr> <td width="176"> <p align="center"><?php // shows IP Number on Page echo $ip; ?> </p> </td> </tr> </table> <p align="center"><?php // Show the user agent echo 'Your user agent is: <b>'.$_SERVER['HTTP_USER_AGENT'].'</b><br />';?></p> [b]<h1 align="center"><?php echo date("d/m/y");?></h1>[/b] </td> </tr> </table [,code] i have a table that shows payments made but want to the payments only showing from a set date(06/12/14) and before this date i dont want to show
this is my sql that doesnt seem to work and is showing dates before the specified date.
.
"SELECT * FROM payments2014, signup2014, editprop2014 WHERE signup2014.userid = payments2014.payment_userid AND editprop2014.prop_id = signup2014.prop_id AND signup2014.userid !='page1' AND signup2014.userid !='page6' AND signup2014.userid !='page4' AND payments2014.payment_transaction_status !='none' AND payments2014.payment_transaction_status !='CANCELLEDa' AND payments2014.payment_type !='deposit' AND payments2014.payment_paid_timestamp NOT LIKE '%2012%' AND payments2014.payment_paid_timestamp NOT LIKE '%2011%' AND payments2014.payment_paid_timestamp >= '06/12/14' ORDER BY payments2014.payment_id DESC"i have some other parts in the statment but this one that should be filtering is host_payments2014.payment_paid_timestamp >= '06/12/14'thanks in advance Hi, I am trying to convert a String date into numeric date using PHP function's, but haven't found such function. Had a look at date(), strtotime(), getdate(); e.g. Apr 1 2011 -> 04-01-2011 Could someone please shed some light on this? Regards, Abhishek Hi guys, I'm putting together a small event system where I want the user to add his own date and time into a textfield (I'll probably make this a series of drop-downs/a date picker later). This is then stored as a timestamp - "0000-00-00 00:00:00" which displays fine until I try to echo it out as a UK date in this format - jS F Y, which just gives today's date but not the inputted date. Here's the code I have right now: Code: [Select] $result = mysql_query("SELECT * FROM stuff.events ORDER BY eventdate ASC"); echo "<br />"; echo mysql_result($result, $i, 'eventvenue'); echo ", "; $dt = new DateTime($eventdate); echo $dt->format("jS F Y"); In my mysql table eventdate is set up as follows: field - eventdate type - timestamp length/values - blank default - current_timestamp collation - blank attributes - on update CURRENT_TIMESTAMP null - blank auto_increment - blank Any help as to why this could be happening would be much appreciated, thanks. Hi there, I have a string '12/04/1990', that's in the format dd/mm/yyyy. I'm attempting to convert that string to a Date, and then insert that date into a MySQL DATE field. The problem is, every time I try to do so, I keep getting values like this in the database: 1970-01-01. Any ideas? Much appreciated. Hi, Currently I am making a module for joomla. every article has an publish date, if the article was published in 7 days ago, it will displayed as "article in last week", My idea is to use today's date - publish date, if the result is greater than 7 and smaller than 14, the article will be displayed as "article in last week. Any one know how to write this code? Here is what I have got, but not working. <?php $todays_date = date("Y-m-d"); $result = mysql_query("select * from jos_content where $test between $todays_date-14 and $todays_date-7"); while($row = mysql_fetch_array($result)) { echo "$todays_date - $row[title]"; } ?> Hi Guys.. How can I change a date on the fly ? Everything is UTC on my server. How can I change a date to something else on the fly? Ie: $timezone = "cet"; $datetime = "2011-09-04 19:53:00"; echo $datetime($timezone); So I can give it a datetime and have it echo the datetime as if it were in the other timezone? Thanks Graham Hi Guys, Need some help I have two dates: Now= 2011-02-08 Expires= 2011-06-15 How can I check if we are getting close to the expire date. For example. Lets say we were 5 days away from 2011-06-15 ( todays date was 2011-06-10 ) for example.. How can i tell this? / return 1 Ie: if date is 5 days or less away do ( this ) Its s essentially so i can email people when something is due to expire. Many thanks L Hi... Good day! I have table that has a field from_date and to_date. Now I just want to know if how can I display as table format the dates between from_date to_date. Like this from_date: 2011-12-16 to_date: 2011-12-31 I want to display it: 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 // table format. Thank you I want to see if a date is more than 10 days overdue. if ($row['duedate'] < "todays date plus 10 days"){ How do I do that? I put in quote sup there in "english" what I want... |
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