PHP - Grabbing Html Table And Putting It Into Drop Down Box!emergency!

i'm back again and i am not very good with tables as the <tr> and <td> tags confuse me 
i need to put 2 sets of links into 2 columns in the table and they come out jumbled up.

Code: [Select]
<table>
<tr>
<th>column 1</th>
<th>column 2</th>
</tr>
<?php

$sites = array_map('trim',file('websites.txt')); //read the whole file into an array & trim the newline character from the end of each line
foreach ($sites as $link) {
   echo "<tr><td><a href='$link'>$link</a></td>";
}


$sites = array_map('trim',file('websites2.txt')); //read the whole file into an array & trim the newline character from the end of each line
foreach ($sites as $link) {
   echo "<td><a href='$link'>$link</a></td></tr>";
}

?>

</table>

Hi Everyone,

I'm trying to figure out a way to put my MySql data into a table. I'm close to getting this completed by I'm having some trouble. The data I'm inserting isn't being put into the correct tables. I'm not quite sure what I'm doing wrong. Any help?

http://whatsmyowncarworth.com/practice/table.php

Code: [Select]
<?php
include('init.php');


$result = mysql_query("SELECT * FROM info")
or die(mysql_error());


echo "<table border='1'>";
echo "<tr> <th>Name</th> <th>Last Name</th> <th>Address</th> <th>City</th> </tr>";

// keeps getting the next row until there are no more to get
while($row = mysql_fetch_array( $result )) 

{
// Print out the contents of each row into a table
echo "<tr><td>"; 
echo $row['first_name'];
echo "</td><td>"; 
echo $row['last_name'];
echo "</td></tr>"; 

echo "<tr><td>"; 
echo $row['address'];
echo "</td><td>"; 
echo $row['city'];
echo "</td></tr>"; 
} 

echo "</table>";
?>

I have a dropdown menu

<td width="148" height="35" valign="top"><b>Type: </b> </td>
            <td><select name ="tabledrop">
<option value="goggles">goggles</option>
<option value="headbands">headbands</option>
 <input type='hidden' id='tabledrop' name='tabledrop' value = ''/>
</select>
</td>

those 2 options are actually names of my tables.


I tried this and got some syntax error.


$type = $_POST['tabledrop'];
$item = $_POST['goggles_name'];
$price = $_POST['goggles_price'];
$file = $_FILES['goggles_image']['name'];

$query = "INSERT into $type SET [$type]_name = '$item' , [$type]_price = '$price' , [$type]_image = '$file'";

//First I'm assigning a $variable ($emailzipmatch) to query a database table called(repzipcodes) and having it pull and display 1 to 3 records based on matching up a customer's zip code (RepZipCode = $CustomerZipMatch) with 1 to 3 other people (GROUP BY RepId HAVING COUNT(1) <= 3") that want that customer's information from that particular zip code. <This code works fine>

// CODE WORKS BELOW
Code: [Select]
<?php
    $emailzipmatch = mysql_query("SELECT * FROM repzipcodes WHERE RepZipCode = $CustomerZipMatch GROUP BY RepId HAVING COUNT(1) <= 3") or die(mysql_error());

    $recipients = array();
    while($row = mysql_fetch_array($emailzipmatch)) 
    { 
    $recipients[] = $row['RepEmail'];

    echo "Agent's Email Address: ";
 
    echo 'font color="#FF7600"',$row['RepEmail'], '/font';
 
    echo '<br />'; 

    echo "Rep's ID: "; 
    echo '<br />';
    echo 'font color="#FF7600"',$row['RepId'], '/font';
    echo '<br />';
    echo 'hr align="left" width="50%" size="2" /';
    }


//MY PROBLEM BELOW

// For the NEXT step of the process above I would take $row['RepEmail'] and $row['RepId'] which can have 1 to 3 results and assign the 1 to 3 results a new $variable so it can be inserted into a different db table so I can track the results of the query ($emailzipmatch = ) from the top of the page: ie..

    <New Variable>   <Listed from above>
    $SentRepId 0   = RepId (results from above echo area)
    $SentRepId 1   = RepId (results from above echo area)
    $SentRepId 2   = RepId (results from above echo area)


// Below I'd like to insert the above results into a new database

    $?Variable??? = mysql_query("INSERT INTO sentemail 
   (SentRepId0, SentRepId1, SentRepId2,SentDateTime
   ) VALUES (
   '$_SESSION[RepId]', // ?????
   '$_SESSION[RepId]', // ?????
   '$_SESSION[RepId]', // ?????
    NOW()
     )") or die(mysql_error());

Thank ahead of time for any help you guys can give me. Please respond with ANY question if my coding or request isn't clear or if I've been confusing due to my lack of experience with PHP and MySQL.


MOD EDIT: code tags added.

Hi again all,

Why does the foreach loop im doing, put the array values from collection, into seperate table rows rather than 1 row per whole array?



    <?php
        class registration{                    
            public $fields = array("username", "email", "password");
            public $data = array();
            public $table = "users";
            public $dateTime = "";
            public $datePos = 0;
            public $dateEntryName = "date";
            public $connection;
            
            function timeStamp(){
                return($this->dateTime = date("Y-m-d H:i:s"));
            }
            
            function insertRow($collection){      
                    //HERE
                    foreach($this->fields as $row => $value){
                        mysql_query("INSERT INTO $this->table ($value)
                        VALUES ('$collection[$row]')");
                    }
                    
                    mysql_close($this->connection->connectData);
            }
            
            function validateFields(){            

                $this->connection = new connection();
                $this->connection->connect(); 
                        
                foreach($this->fields as $key => $value){
                    array_push($this->data, $_POST[$this->fields[$key]]);
                }
                $this->dateTime = $this->timeStamp();
                array_unshift($this->data, $this->dateTime);                
                array_unshift($this->fields, $this->dateEntryName);   
                
                foreach($this->data as $value){
                    echo "$value";
                }
                
                $this->insertRow($this->data);
            }
        }
        
        $registration = new registration();
        $registration->validateFields();
    ?>




I end up with 3 rows

row 1: username
row 2: email
row 3 : password

rather than row 1:username email password.

Hi,
 
I have two html made text boxes one that is called "name" and another that is called "regnum". I also have a submit button.
 
They are both used to add data to a database.
 
The name text box should add a name to the database under the "name" heading and the regnum should add a number under the "regnum" heading
 
Here is the code for them:
 

HTML Code:
 <form action="" method="post">
 <p>
 Name: <input type="text" name="name"/>
 </p>
 <p>
 Regnum: <input type="text" name="regnum"/>
 </p>
 <p>
 <input type="submit" value="Add To Database" name = "submit2" />
 </p>
 </form>
 
Here is the PHP code that i am using for adding the user to the database:
 

PHP Code:
 $host="localhost";
$username="root";
$password="";
$database="lab2";

mysql_connect("$host", "$username", "$password") or die(mysql_error());

mysql_select_db("$database") or die(mysql_error());

$name = $_POST['name'];
$regnum = $_POST['regnum'];

if(!$_POST['submit2']){
echo "Enter A Vaue";
}else{
mysql_query("INSERT INTO lab2('name', 'regnum')
VALUES(NULL, '$name', '$regnum')") or die(mysql_error());
echo "User Added To Database";
}

The problem i get with this is "Undefined Index name and regnum".
 
I watched a video on youtube and this is how the guy did it but it worked for him and for some reason it doesn't work for me.
 

Can anyone help??
 

Thanks.

Hello everyone,

Sorry if this has been answered but if it has I can't find it anywhere. So, from the begining then.  Lets say I had a member table and in it I wanted to store what their top 3 interests are.  Their$ row has all the usual things to identify them userID and password etc.. and I had a further 3 columns which were labled top3_1 top3_2 & top3_3 to put each of their interests in from a post form.

If instead I wanted to store this data as a PHP Array instead (using 1 column instead of 3) is there a way to store it as readable data when you open the PHPmyadmin?

At the moment all it says is array and when I call it back to the browser (say on a page where they could review and update their interests) it displays 'a' as top3_01 'r' as top3_02 and 'r' as top3_03 (in each putting what would be 'array' as it appears in the table if there were 5 results. Does anyone know what I mean?

For example -

If we had a form which collected the top 3 interests to put in a table called users,

Code: [Select]
<form action="back_to_same_page_for_processing.php" method="post" enctype="multipart/form-data">
   
    <input name="top3_01" type="text" value="enter interest number 1 here" />
    <input name="top3_02" type="text" value="enter interest number 2 here" />
    <input name="top3_03" type="text" value="enter interest number 3 here" />
    <input type="submit" name="update_button" value=" Save and Update! " />

   
    </form> // If my quick code example for this form is not correct dont worry its not the point im getting at :)
And they put 'bowling' in top3_01, 'running' in top3_02 and 'diving' in top3_03 and we catch that on the same page with some PHP at the top -->

Code: [Select]
        if (isset($_POST)['update_button']) {
   
    $top3_01 = $_POST['top3_01']; // i.e, 'bowling' changing POST vars to local vars
    $top3_02 = $_POST['top3_02']; // i.e, 'running'
    $top3_03 = $_POST['top3_03']; // i.e, 'diving'

With me so far? If I had a table which had 3 columns (1 for each interest) I could put something like -

  Code: [Select]
   include('connect_msql.php');
   
    mysql_query("Select * FROM users WHERE id='$id' AND blah blah blah");
   
    mysql_query("UPDATE users SET top3_01='$top3_01', top3_02='$top3_02', top3_03='$top3_03' WHERE id='$id'");


And hopefully if ive got it right, it will put them each in their own little column. Easy enough huh? But heres the thing, I want to put all these into an array to be stored in the 1 column (say called 'top3') and whats more have them clearly readable in PHPmyadmin and editable from there yet still be able to be called back an rendered on page when requested.

Continuing the example then, assuming ive changed the table for the 'top3' column instead of individual colums,  I could put something like this -


Code: [Select]
            if (isset($_POST)['update_button']) {
       
        $top3_01 = $_POST['top3_01']; // i.e, 'bowling' changing POST vars to local vars
        $top3_02 = $_POST['top3_02']; // i.e, 'running'
        $top3_03 = $_POST['top3_03']; // i.e, 'diving'
   
    $top3_array = array($top3_01,$top3_02,$top3_03);
   
    include('connect_msql.php');
   
    mysql_query("UPDATE members SET top3='$top3_array' WHERE id='$id' AND blah blah blah");
But it will appear in the column as 'Array' and when its called for using a query it will render the literal string. a r r in each field instead.  Now I know you can use the 'serialize()' & 'unserialize()' funtcions but it makes the entry in the database practically unreadable. Is there a way to make it readable and editable without having to create a content management system?

If so please let me know and I'll be your friend forever, lol, ok maybe not but I'd really appreciate the help anyways.  The other thing is, If you can do this or something like it, how am I to add entries to that array to go back into the data base?

I hope ive explained myself enough here, but if not say so and I'll have another go.  Thanks very much people,  L-PLate (P.s if I sort this out on my own ill post it all here)

Code: [Select]
$q = mysqli_query($mysqli, "DROP TABLE IF EXIST 'airline_survey'");
  if($q){echo "deleted the table airline_survey....<br>";}
  else{echo "damm... ".mysqli_error($mysqli);}
$mysqli is my connection and it works I had no trouble creating the table but I decided to add these few lines in front of the code to create the table and I get this error.

damm...You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'EXIST 'airline_survey'' at line 1
I gotta believe this is really simple but it's got me stumped.

Hi,

I'm trying to drop a table form a database using the table name as a variable. This variable is set within a session. I am using a form where you input the table name, then the DROP TABLE procedure is executed in the next page.

I know that the variable gets passed because it prints the table name variable out when I "echo".

The execution is simple (code found in deletetable.php)

$temp = $_POST['temp'];
$query = "DROP TABLE $temp";
if(mysql_query($query)){
echo "<h1 style='color:green;'>Table $temp deleted</h1>";}
else{
echo "<h1 style='color:red;'>Deletion of table '$temp' failed!</h1>";}


Here's my code for the two pages:
delete_table.php

<?php
include("includes/header.html");
session_start();
$hostname = $_SESSION['hostname'];
$user = $_SESSION['user'];
$passwd = $_SESSION['passwd'];
$database = $_SESSION['database'];
$tblname = $_SESSION['table'];

$conn = mysql_connect($hostname, $user, $passwd, $database);
/*if(! $conn )
{
  die('Could not connect: ' . mysql_error());
}*/
?>
<div id="container">
<div id="header">Create DB</div>
<div id="breadcrumbs">
<?php
function check_port($port) {
    $conn = @fsockopen("127.0.0.1", $port, $errno, $errstr, 0.2);
    if ($conn) {
        fclose($conn);
        return true;
    }
}

function server_report() {
    $report = array();
    $svcs = array('3306'=>'MySQL');
    foreach ($svcs as $port=>$service) {
        $report[$service] = check_port($port);
    }
    return $report;
}

$report = server_report();
?>
<div id="server"><p>Server is <?php echo $report['MySQL'] ? "running" : "offline"; ?></p></div>
<?php
if(!$_SESSION['hostname']){

echo "<font color='red'>Not connected to server!</font>";
} else {

echo "<font color='green'>Server: ".$_SESSION['hostname']."</font>";
} 
if(!$_SESSION['database']){

echo "";
}else{

echo "<br><font color='green'>Database: ".$_SESSION['database']."</font>";
}
?>
</div>
<div id="nav">
<p><a href="#" onclick="javascript:window.open('connect_db.php','_self');"><img src="server_conn_ico.png" align="left" />Server Connection</a></p>
<p><a href="databases.php"><img src="databases_ico.png" align="left" />View Database</a></p>
<p><a href="create_db.php"><img src="server_folder_ico.png" align="left" />Create Database</a></p>
<p><a href="drop_db.php"><img src="drop_ico.png" align="left" />Drop Database</a></p>
<p><a href="create_table.php"><img src="status_ico.png" align="left" />Add Table</a></p>
<p><a href="add_fields.php"><img src="server_ico.png" align="left" />Add Fields</a></p>
<p class="active"><a href="delete_table.php"><img src="status_delete_ico.png" align="left" />Delete Table</a></p>
<p><a href="view_tables.php"><img src="user_admin_ico.png" align="left" />View Tables</a></p>
<p><a href="view_data.php"><img src="user_admin_ico.png" align="left" />View Table Data</a></p>
<p><a href="http://localhost/phpmyadmin/" target="_blank"><img src="phpmyadmin_ico.png" align="left" />phpMyAdmin</a></p>
<p><a href="connect_info.php"><img src="health_ico.png" align="left" />System Info</a></p>
<p><a href="error_log.php"><img src="logs_ico.png" align="left" />Server Log</a></p>
<p><a href="bug_report.php"><img src="bugs-icon.png" align="left" />Bug Reports</a></p>
</div>
<div id="controls"><a href="javascript:self.close()"><img src="controls.png" /></a></div>
<div id="main">
<div id="content">
<!--<h1>Delete Database Table</h1>-->
<?php
if(empty($database)) {

echo "<p>You must be connected to a database in order to delete a table.</p>";
}else{
//echo 'Connected successfully to \''.$database.'\'';

// Check tables

$sql = "SHOW TABLES FROM $database";

$result = mysql_query($sql);

if (mysql_num_rows($result) > 0) {

echo "<p style='text-align:left;padding-left:24px;'>Available tables:</p>\n";

echo "<pre style='text-align:left;padding-left:24px;font-size:1.2em;'>\n";

while ($row = mysql_fetch_row($result)) {

echo "{$row[0]}\n";

}

echo "</pre>\n";

}
?>
<form action="deletetable.php" method="post">
Enter table you'd like to delete from '<?php echo $database; ?>' database:
<input name="temp" type="text" /><br/>
<input name="Submit" type="submit" value="  Delete Table  " />&nbsp;&nbsp;&nbsp;<input type='button' value='  Cancel  ' onclick="javascript:window.location='connect_db.php';"></p>
</form>
<?php
}
include("includes/footer.html");
?>


Executing file deletetable.php:

<?php
include("includes/header.html");
session_start();
$hostname = $_SESSION['hostname'];
$user = $_SESSION['user'];
$passwd = $_SESSION['passwd'];
$database = $_SESSION['database'];
//$tblname = $_SESSION['table'];

$conn = mysql_connect($hostname, $user, $passwd, $database);
?>
<div id="container">
<div id="header">Create DB</div>
<div id="breadcrumbs">
<?php
function check_port($port) {
    $conn = @fsockopen("127.0.0.1", $port, $errno, $errstr, 0.2);
    if ($conn) {
        fclose($conn);
        return true;
    }
}

function server_report() {
    $report = array();
    $svcs = array('3306'=>'MySQL');
    foreach ($svcs as $port=>$service) {
        $report[$service] = check_port($port);
    }
    return $report;
}

$report = server_report();
?>
<div id="server"><p>Server is <?php echo $report['MySQL'] ? "running" : "offline"; ?></p></div>
<?php
if(!$_SESSION['hostname']){

echo "<font color='red'>Not connected to server!</font>";
} else {

echo "<font color='green'>Server: ".$_SESSION['hostname']."</font>";
} 
if(!$_SESSION['database']){

echo "";
}else{

echo "<br><font color='green'>Database: ".$_SESSION['database']."</font>";
}
?>
</div>
<div id="nav">
<p><a href="#" onclick="javascript:window.open('connect_db.php','_self');"><img src="server_conn_ico.png" align="left" />Server Connection</a></p>
<p><a href="databases.php"><img src="databases_ico.png" align="left" />View Database</a></p>
<p><a href="create_db.php"><img src="server_folder_ico.png" align="left" />Create Database</a></p>
<p><a href="drop_db.php"><img src="drop_ico.png" align="left" />Drop Database</a></p>
<p><a href="create_table.php"><img src="status_ico.png" align="left" />Add Table</a></p>
<p><a href="add_fields.php"><img src="server_ico.png" align="left" />Add Fields</a></p>
<p class="active"><a href="delete_table.php"><img src="status_delete_ico.png" align="left" />Delete Table</a></p>
<p><a href="view_tables.php"><img src="user_admin_ico.png" align="left" />View Tables</a></p>
<p><a href="view_data.php"><img src="user_admin_ico.png" align="left" />View Table Data</a></p>
<p><a href="http://localhost/phpmyadmin/" target="_blank"><img src="phpmyadmin_ico.png" align="left" />phpMyAdmin</a></p>
<p><a href="connect_info.php"><img src="health_ico.png" align="left" />System Info</a></p>
<p><a href="error_log.php"><img src="logs_ico.png" align="left" />Server Log</a></p>
<p><a href="bug_report.php"><img src="bugs-icon.png" align="left" />Bug Reports</a></p>
</div>
<div id="controls"><a href="javascript:self.close()"><img src="controls.png" /></a></div>
<div id="main">
<div id="content">
<?php
$temp = $_POST['temp'];
$query = "DROP TABLE $temp";
if(mysql_query($query)){
echo "<h1 style='color:green;'>Table $temp deleted</h1>";}
else{
echo "<h1 style='color:red;'>Deletion of table '$temp' failed!</h1>";}

include("includes/footer.html");
?>


Your help is greatly appreciated!!

Hey guys,

I made in php an sql droplist. But I need some help. I want it to work like this.
When I select something from the list and click Add To Cart, that also the product gets send to the cart and not only the quantity.

you can check it out here : http://fhcs.be/cart-demo2/index.php

I also added my index.php as an attachment


Greets

Hello,

I need some help. Say that I have a list in my MySQL database that contains elements "A", "S", "C", "D" etc... Now, I want to generate an html table where these elements should be distributed in a random and unique way while leaving some entries of the table empty, see the picture below. But, I have no clue how to do this... Any hints?



Thanks in advance,
Vero

Hi,

I wonder if I somebody can help me

I have three drop down lists which are populated from data thats stored in my sql database. I also have a table which is echoed from the database all on the same page.


What i want to do is allow users to select values in the drop down lists which will then echo different results below in the table. Is this possible.

So on page load it will show all of the info in the html table. Then when the user changes the drop downs and clicks submit it will change the query to something SELECT dropdown1 value FROM users where Dropdown2 = 1 AND Dropdown3 = 2 etc.

Is this possible to display this information on the same page using the dropdown list or does it need to load a different page as the client side is trying to edit a server side script?

If its possible please can someone give me an example.

Thanks in advance

Edd

Name says it all. I have a form and 2 tables that are going to have to be linked with each other. Although what I'm trying to do now is very basic and I'm struggling haha Though this is my first php project

Basicly I got a form with a drop down menu, which I want to display the contents of my table (course) which the user then selects from and submits to another table (student)

Here is my code for this part
<?php Code: [Select]
<?php
$q = "SELECT cname FROM course ";
$result = mysql_query($q);
$course = mysql_fetch_array($result);

?>
<div id="apdiv3">

<FORM action = "demo.php" method ="post">

<p>Course name:</p>
<select name="cname"> <OPTION> <?php echo $course['cname']; ?> </option> </SELECT>?>

It only displays 1 item from my course table. What am I doing wrong? And also please explain so I can learn from my mistakes

Hi guys...   I was at home and doing some coding and stumbled across and API for a computer game called Battlefield 4 http://api.bf4stats....ApRiL&output=js;   I was checking it out and it is a LOT of data.  I was wondering if its possible to only pull certain data from the API, say for instance you only want to pull your user name, ID, and what game you are playing (those are the top 3 things).  How would you pull only those 3 stats and display that information on say a webpage for you?   thanks guys   JL

Php Whizzes!

 

Need to grab geo ip.

Why these 2 show data differently ?

http://www.geoplugin.net/json.gp?ip=19.117.63.253

http://www.geoplugin.net/php.gp?ip=19.117.63.253

Which one you like ? I like 1st one.

 

Anyway, is this code any good ? Will it misfire ?

	<?php
//https://stackoverflow.com/questions/12553160/getting-visitors-country-from-their-ip
function ip_info($ip = NULL, $purpose = "location", $deep_detect = TRUE) {
    $output = NULL;
    if (filter_var($ip, FILTER_VALIDATE_IP) === FALSE) {
        $ip = $_SERVER["REMOTE_ADDR"];
        if ($deep_detect) {
            if (filter_var(@$_SERVER['HTTP_X_FORWARDED_FOR'], FILTER_VALIDATE_IP))
                $ip = $_SERVER['HTTP_X_FORWARDED_FOR'];
            if (filter_var(@$_SERVER['HTTP_CLIENT_IP'], FILTER_VALIDATE_IP))
                $ip = $_SERVER['HTTP_CLIENT_IP'];
        }
    }
    $purpose    = str_replace(array("name", "\n", "\t", " ", "-", "_"), NULL, strtolower(trim($purpose)));
    $support    = array("country", "countrycode", "state", "region", "city", "location", "address");
    $continents = array(
        "AF" => "Africa",
        "AN" => "Antarctica",
        "AS" => "Asia",
        "EU" => "Europe",
        "OC" => "Australia (Oceania)",
        "NA" => "North America",
        "SA" => "South America"
    );
    if (filter_var($ip, FILTER_VALIDATE_IP) && in_array($purpose, $support)) {
        $ipdat = @json_decode(file_get_contents("http://www.geoplugin.net/json.gp?ip=" . $ip));
        if (@strlen(trim($ipdat->geoplugin_countryCode)) == 2) {
            switch ($purpose) {
                case "location":
                    $output = array(
                        "city"           => @$ipdat->geoplugin_city,
                        "state"          => @$ipdat->geoplugin_regionName,
                        "country"        => @$ipdat->geoplugin_countryName,
                        "country_code"   => @$ipdat->geoplugin_countryCode,
                        "continent"      => @$continents[strtoupper($ipdat->geoplugin_continentCode)],
                        "continent_code" => @$ipdat->geoplugin_continentCode
                    );
                    break;
                case "address":
                    $address = array($ipdat->geoplugin_countryName);
                    if (@strlen($ipdat->geoplugin_regionName) >= 1)
                        $address[] = $ipdat->geoplugin_regionName;
                    if (@strlen($ipdat->geoplugin_city) >= 1)
                        $address[] = $ipdat->geoplugin_city;
                    $output = implode(", ", array_reverse($address));
                    break;
                case "city":
                    $output = @$ipdat->geoplugin_city;
                    break;
                case "state":
                    $output = @$ipdat->geoplugin_regionName;
                    break;
                case "region":
                    $output = @$ipdat->geoplugin_regionName;
                    break;
                case "country":
                    $output = @$ipdat->geoplugin_countryName;
                    break;
                case "countrycode":
                    $output = @$ipdat->geoplugin_countryCode;
                    break;
            }
        }
    }
    return $output;
}
	echo ip_info("119.30.32.215", "Country"); ?><br><?php
echo ip_info("119.30.32.215", "Country Code"); ?><br><?php
echo ip_info("119.30.32.215", "State"); ?><br><?php
echo ip_info("119.30.32.215", "City"); ?><br><?php
echo ip_info("119.30.32.215", "Address"); ?><br><?php
	print_r(ip_info("119.30.32.215", "Location")); // Array ( [city] => Menlo Park [state] => California [country] => United States [country_code] => US [continent] => North America [continent_code] => NA )
	?>
	

 

What you say ?

Lemme see your sample code.

 

Thanks!