PHP - Remove Session Even If Browser Is Closed?
Hey All,
I have a sessions table that is used to see if a user is online. It only gets deleted when they click the Logout button. What I need to do is have it so it gets deleted even if they close the browser. Should I add a column in the sessions table with a time stamp and check on each page for every user to make sure its great than 30 min? Is there a better way to do this, without so many queries? Thanks Similar TutorialsHello, How do I get a user's session destroyed when he closes his browser? Thanks in advance Hi Everyone, I wonder if somebody could help me. I have been at this for hours and am really struggling. I have a timer which I have set up for a quiz. The quiz opens in a javascript shadow box. When the quiz is opened a session variable for the timer is set up to keep track of the time. What I need is for this session variable to end when the shadow box is closed. I have a onClose hook to peform actions when the shadow box is closed which is in javascript. Obviously I cannot end the session variable in the javascript function due to js being client side and php being server side. Has anyone any suggestions how I can resolve this issue. I need to end this session variable as if the user exits the quiz and then selects another quiz to do the timer uses the current time session rather than assigning the new time value for that particular quiz. Thanks in advance. Edd OK, I'm nearing the end of a very long chat project and I have one last hurdle to jump, I've saved this task to the near end because I thought it would be a problem as I have no idea what to do or where to start. The problem is exactly what is said in the subject title. I have looked into JavaScript options such as "onbeforeunload" but that is just BAD. The login is controlled by sessions, so when the user closes the browser, the session is ended, but data in the database says different, cookies are not an option I'm afraid. I've had an idea that if I create a special account (or a few) and always leave these accounts logged in, they can check if a user has been inactive for a certain period of time, and then run queries to change things, I know this sound odd but maybe I will not have to create these accounts but general accounts that people make will be able to do this for me, without them even knowing. Please help, any ideas, suggestions, logic or methods that you think will help will be great. Thanks. I made a bug which caused endless loop and endless printing. When I noticed that, I closed the browsers tab, fixed the bug, open a new tab and re-run. I was assuming the server would start from the beginning, but instead I noticed that some variables were active and the program continued from where it stopped. How can I make the program to stop when the client tab is terminated? This topic has been moved to JavaScript Help. http://www.phpfreaks.com/forums/index.php?topic=352282.0 Hello, I am puzzled as to how to get this code actually working, I am using some example code, I want the code to remove the data of the logged in users, at the moment it will remove all users registered in the mysql db. <?php # Access session. session_start() ; if ( !isset( $_SESSION[ 'user_id' ] ) ) { require ( 'login_tools.php' ) ; load() ; } # Connect to the database. require ('connect_db.php'); // Attempt delete query execution $sql = "DELETE FROM users WHERE user_id=user_id"; if(mysqli_query($dbc, $sql, $q)){ echo "Records were deleted successfully."; } else{ echo "ERROR: Could not able to execute $sql. " . mysqli_error($dbc); } # Close database connection. mysqli_close( $dbc ) ; ?> $_session id knows that the user is logged into the control page, but for the code to remove the particular user logged in from the db, what exactly does this need? Thank you. When I remove 1 session item using this it works fine when I select more than 1 item to be removed I get unexpected results, I have checked the outputted html to see what positions get echoed into the remove check box and they are correct, so I guess the problem lies in my remove code here is the part of the form that sends the remove check box <?php for ($basket_counter=0;$basket_counter<$_SESSION['ses_basket_items'];$basket_counter++) { $price=sprintf("%01.2f",$ses_basket_price[$basket_counter]); $quantity=$ses_basket_amount[$basket_counter]; $code=$ses_basket_stockcode[$basket_counter]; $itemID=$ses_basket_id[$basket_counter]; $name=$ses_basket_name[$basket_counter]; $image=$ses_basket_image[$basket_counter]; $size=$ses_basket_size[$basket_counter]; $sizechoice=$ses_basket_sizechoice[$basket_counter]; // create array from sizes and make the option box selections if ($sizechoice!="" && (!in_array($sizechoice, array('One Size', 'one size', 'free size', 'Free Size', 'Adjustable', 'adjustable')))) { // add size trigger $sizelist="add"; //create the array $sizepick=explode(",", $sizechoice); } else { $sizepick=$sizechoice; } // adjust gst for AU customers if ($country=='AU') { $price=sprintf("%01.2f",($price*1.1)); $unit=sprintf("%01.2f",($price/$quantity)); } else { $unit=sprintf("%01.2f",($price/$quantity)); } ?> <tr> <td align='center' class='rescon' style="border-bottom:solid #330000 1px;"><input type="checkbox" name="remove[<?php echo $basket_counter; ?>]" value="<?php echo $basket_counter; ?>" /></td> and here is the part of the code that processes the removal of the items $remove = $_POST['remove']; if (isset($remove) && ($remove!='')) { foreach($remove AS $key => $remove_position){ array_splice ($ses_basket_name, $remove_position, 1); array_splice ($ses_basket_amount, $remove_position, 1); array_splice ($ses_basket_price, $remove_position, 1); array_splice ($ses_basket_stockcode, $remove_position, 1); array_splice ($ses_basket_image, $remove_position, 1); array_splice ($ses_basket_size, $remove_position, 1); array_splice ($ses_basket_sizechoice, $remove_position, 1); array_splice ($ses_basket_id, $remove_position, 1); $_SESSION['ses_basket_items']--; } } I am using a form with checkboxes named remove[$remove_position] and the positions in the form are correct for each item in the array, but when I select more than 1 item to delete they are not always the correct items only the first 1 selected. What am I doing wrong here?? I've added a CSS class to the main menu of a Wordpress site and wish to remove the class if the browser width drops below a certain number. I've tried a number of different approaches but none has worked.
Some examples:
$(document).ready(function() { hey guys, I am trying to setup a session for a filter , I have a button that the user can click on or off, the button starts off but when the user clicks on it a new session starts and it stays on until the user clicks it again to turn it off or when the browser sessions ends... Any help is welcome, thanks guys, you are the best Hi, i m playing arround with php sessions and just started afew testing on it (i never actually used them so i m discovering something new) and i would like to know how can you terminate an PHP Session without closing your browser. For testing i did this small code, just to see the behavior: Code: [Select] <?php session_start(); $id = session_id(); echo $id; session_unset(); session_destroy(); ?> The code above seens only to kill the $_SESSION's variables but what i would like is to Kill the PHPSESSID cookie/session cookie. is there anyway you can achive that? thanks in advance Hello dear friends, let say we have (function) and that function has one variable which is (id) the (id) could be number any number 1 or 4 or even 49999 whatever. how to make closed loop which i mean run this function in unlimited way each time with new id <--- i can do it by set random() but the problem i've is how to make it repeat itself excuted excuted excuted | | | ect let say for example , i will insert random number in at database table Code: [Select] $id = rand(); mysql_query("INSERT INTO comments(id) VALUES ('$id')"); that is it, how then i can repeat it many many times without 1) refresh 2) rewrite it many times thanks in advance I have a class I use to handle my various DB objects. I want to close any connections, if needed, in my destructor. I want to do this even though I already know the connection has been closed previously. What I am looking for is a way to test the $connection variable I have to see if it's in need of closing. I can't figure out how to do this. if (isset($this->connection)) { echo "is set"; } if ($this->connection) { echo "here"; } The above would output "is set" and "here", because in both tests say the already closed connection is still there. Can anyone offer any help? i have a script that wrote which updates fields in a mysql database with millions of rows. it just uses a while loop for each row. now the problem is that i forgot to add something to the script, but i already visited the .php file in my browser. i closed the browser and when i refresh the database it still seems to be running even though i closed the browser the script was running on.... is this because the script is still cached in the memory or what? how can i stop it? Hello. I want to display all photos from the database. The problem is that it displays nothing. I added a foreach loop in html but further it not display. I'am beginner, I hope someone help me where I make mistake. I care about separation logic from view.
class photo_display { private $database; private $userData; public function __construct($database) { $this->database = $database; } public function display() { $query = $this->database->connect()->prepare("SELECT photo FROM photo"); $query->execute(); if ($query->rowcount()) { $row = $query->fetchAll(); } $this->userData = $row; } public function display_Photos(string $colName) { return (isset($this->userData[$colName])) ? $this->userData[$colName] : []; } } <div class='container-fluid bg-dark' id='profil'> <div class='row'> <div class=" col-12 col-sm-12 col-md-4 col-lg-4 col-xl-4 order-5 order-12 order-6 order-md-4"> <div class="row" id="margin"> <div class="col-xl-12 d-flex justify-content-center" id="test"> <?php foreach ($photo_display->display_Photos('photo') as $value) { ?> <img src ="<?php echo var_dump($value) ?>" />; <?php } ?> </div> </div> </div>
Ok this is some noob question here I have a page that has few separate pieces of php code embeded within html code. Each piece is separated with Code: [Select] <?php ... ?> tags, everything works fine. I need to assign a variable in first (from the top) piece of php code. Then I want to be able to use that variable in all others php pieces across this same page.... I searched and searched and first tried to do it like : First piece: Code: [Select] <?php function id() { $id="blah"; } ?> Second piece : Code: [Select] <?php id(); ... echo $id; ?> didn't work, then I tried First place: Code: [Select] <?php $id="blah"; function id() { global $id; } ?> Second piece : Code: [Select] <?php echo $id; ?> After struggling and reading for few days all about global, static, and regular variables i finally decided to ask professionals to help.... please let me know if you need me to make the question description more clear or smn I GET QuoteFatal error: TPL: [in line 0]: syntax error: file 'm/pg/_categories' does not exist in C:\WebServ\httpd\libs\tpl\class.template.php on line 943 unset($_templatelite_tpl_vars); else: $_templatelite_tpl_vars = $this->_vars; echo $this->_fetch_compile_include($this->_vars['TPLx'].'m/pg/_categories'.$this->_vars['HTML'], array()); $this->_vars = $_templatelite_tpl_vars; WITH FILES http://testynarkotykowe.j13x.pl/index.txt && http://testynarkotykowe.j13x.pl/indexpg.txt HOW TO FIX IT I am trying to create an index page which contains registration and login field the problem that i get is on successful login a warning is displayed session_start() [function.session-start]: Cannot send session cookie - headers already sent by (output started at C:\xampp\htdocs\Eventz.com\index.php:116) in C:\xampp\htdocs\Eventz.com\index.php on line 235 This is the login part of my index.php this tag is inside an html table below the login form I also have a registration form and its php code above the login form Code: [Select] <?php if (isset($_REQUEST['pass'])) { $id=$_POST['id']; $pass=$_POST['pass']; $conn =mysql_connect("localhost","root",""); if (!$conn) { die('Could not connect: ' . mysql_error()); } /* checking connection....success! */ $e=mysql_select_db('test', $conn); if(!$e) { die(''.mysql_error()); } else { echo 'database selected successfully'; } if (isset($_REQUEST['id']) || (isset($_REQUEST['pass']))) { if($_REQUEST['id'] == "" || $_REQUEST['pass']=="") { echo "login fields cannot be empty"; } else { $sql=mysql_query("Select email,password from login where email='$id' AND password='$pass'"); $count=mysql_num_rows($sql); if($count==1) /* $count checks if username and password are in same row */ { session_start(); $_SESSION['id']=$id; echo "</br>Login Successful</br>"; } else { echo "</br>invalid</br>"; echo "please try to login again</br>"; } } } } ?> Any help or suggestion would be appreciated in this page http://maximaart.com/newscp/ i have this problem Code: [Select] Warning: session_start() [function.session-start]: Cannot send session cache limiter - headers already sent (output started at /home/maximasy/public_html/newscp/index.php:1) in /home/maximasy/public_html/newscp/index.php on line 2 my source code is <?php session_start(); include_once("config.php"); include_once("functions.php"); $errorMessage = ''; if (isset($_POST['txtUserId']) && isset($_POST['txtPassword'])) { if ($_POST['txtUserId'] === "$user" && $_POST['txtPassword'] === "$pass") { // the user id and password match, $_SESSION['basic_is_logged_in'] = true; require("main.php"); exit;?> I am having trouble resolving an error. Warning: session_start() [function.session-start]: Cannot send session cache limiter - headers already sent (output started at /home/s519970/public_html/header.php:27) in /home/s519970/public_html/admin/login.php on line 2 What I can gather is I can't use "header (Location: 'admin.php')" after i've used session_start(). I have tried to replace the header (Location: 'admin.php') with this: echo "<script>document.location.href='admin.php'</script>"; echo "<script>'Content-type: application/octet-stream'</script>"; I've been trying to read up on solutions but haven't been able to get it sorted. If anyone can offer some advice that would be greatly appreciated as im new to php. Code: [Select] <?php session_start(); if(isset($_SESSION['user'])) echo "<script>document.location.href='admin.php'</script>"; echo "<script>'Content-type: application/octet-stream'</script>"; ?> <div id="loginform"> <form action="dologin.php" method="post"> <table> <tr> <td><span>Username:</span></td> <td><input type="text" name="username" /></td> </tr> <tr> <td><span>Password:</span></td> <td><input type="password" name="password" /></td> </tr> <tr> <td colspan="2" align="right"><input type="submit" name="login" value="Login" /></td> </tr> </table> </form> </div> I have tried using require_once('yourpage.php'); before my <head></head> tags in the header document where I've specified the html information but this doesn't seem to work. I've been advised to use ob_start("ob_gzhandler"); but I am not sure how to implement this. Any advice is greatly appreciated! hi everyone. i'm wondering what the best way is to create a session variable and pass it to an iframe. i need to do something along these lines, but it doesn't seem to pass the ID. Any hints on how i should accomplish this? Code: [Select] session_start(); $_SESSION['ID']=$_GET['ID']; // id from previous page $ID=session_id(); <iframe src="iframepage.php?ID=<?php echo $ID; ?>" style="width:680px; height:200px;" noresize="noresize" frameborder="0" border="0" scrolling="Yes" allowtransparency="true" /> </iframe> |