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PHP - Help With User List/profile
Hello all, i require some assistance in a bit of PHP/MySql code.
I have a website setup with register/login scripts already wrote, i also have a basic members page for now, that has there user ID assigned to it for example members.php?id=$id, which is there ID from the database. I have a members list which shows all members with links to there profiles, now i when i mouse over the link, it will says members.php?id=1 and so on, which is correct but when clicking on any of the members to go to there profile it is my own details that is shown on there profile instead of theres. members.php <?php session_start(); mysql_connect("localhost","root") or die(mysql_error()); mysql_select_db("hireacoder") or die(mysql_error()); $user = $SESSION['username']; $sql = mysql_query("SELECT * FROM users WHERE username='$user'"); $row = mysql_fetch_assoc($sql); echo $row['username']; echo'<br>'; echo $row['fname']; echo'<br>'; echo $row['lname']; echo'<a href="users.php">Users</a>'; ?> users.php <?php session_start(); mysql_connect("localhost","root") or die(mysql_error()); mysql_select_db("hireacoder") or die(mysql_error()); echo "<table border='0'> <tr> <th>UserName</th> </tr>"; $sql = mysql_query("SELECT * FROM users ORDER BY ID"); while($row = mysql_fetch_assoc($sql)) { $id = $row['id']; $username = $row['username']; echo" <tr> <td> <a href='members.php?id=$id'>".$username."</a> </td> </tr>"; } echo "</table>"; ?> Now i know what the problem is, the query is getting the details from the DB with the username = the session user which is me and that is why my details show up on all profiles, but i dont know any other way to do it, any help with be very apprciated thanks you. Similar TutorialsHi guys, I am trying to put together a little system that allows users to log onto my website and access there own personal page. I am creating each page myself and uploading content specific to them which cannot be viewed by anyone else. I have got the system to work up as far as: 1/ The user logs in 2/ Once logged in they are re-directed to their own page using 'theirusername.php' Thats all good and working how I need it too. The problem I have is this. If I log onto the website using USER A details - I get taken to USER A's page like I should but - If I then go to my browser and type in USERBdetails.php I can then access USER B's page. This cannot happen!! I need for USER A not to be able to access USER B profile - there is obviously no point in the login otherwise! If you are not logged in you obviously cannot access any secure page. That much is working! Please find below the code I am using: LOGIN <?php session_start(); function dbconnect() { $link = mysql_connect("localhost", "username", "password") or die ("Error: ".mysql_error()); } ?> <?php if(isset($_SESSION['loggedin'])) { header("Location:" . strtolower($username) . ".php"); if(isset($_POST['submit'])) { $username = mysql_real_escape_string($_POST['username']); $password = mysql_real_escape_string($_POST['password']); $mysql = mysql_query("SELECT * FROM clients WHERE username = '{$username}' AND password = '{$password}'"); if(mysql_num_rows($mysql) < 1) { die("Password or Username incorrect! Please <a href='login.php'>click here</a> to try again"); } $_SESSION['loggedin'] = "YES"; $_SESSION['username'] = $username; $_SESSION['name'] header("Location:" . strtolower($username) . ".php"); } ?> HEADER ON EACH PHP PAGE <?php session_start(); if(!isset($_SESSION['loggedin'])) { die(Access to this page is restricted without a valid username and password); ?> --------------------------------------------------- Am I right in thinking it is something to do with the "loggedin" part? The system I have here is adapted from a normal login system I have been using for years. The original just checks the details and then does a 'session start'. This one obviously has to re-direct to a user specific page. To do this I used the <<header("Location:" . strtolower($username) . ".php");>> line to redirect to a page such as "usera.php" or "userb.php" Any help would be greatly appreciated! Ta Hi, I recently implemented a code to display user profile information. Well, it displays the username and password fine, but the edit function doesn't seem to be working. I edit the information, click submit, get a success message but the username and password didn't change. myprofile.php Code: [Select] <?php session_start(); include('config.php'); $sql = mysql_query( "SELECT * FROM users WHERE id='".$_SESSION['id']."'" ); echo "<h2>Profile</h2> <form method='post' action='editprofile.php'> <table>"; $row = mysql_fetch_array($sql); echo "<tr><th>Name: </th><td>".$row['username']."</td></tr> <tr><th>Password: </th><td><input type='password' value='".$row['password']."' disabled='true' /></td></tr>"; echo "</table><br /> <input type='submit' value='edit profile' /> </form>"; ?> editprofile.php Code: [Select] <?php include('config.php'); if(isset($_POST['btnedit'])){ $username = $_POST['username']; $password = $_POST['password']; $sql = mysql_query( "UPDATE users SET username='".$username."', password='".$password."' WHERE id='".$_SESSION['id']."'" ); if($sql){ echo "<script>alert('profile updated');window.location='myprofile.php'</script>"; }else{ echo "<script>alert('updating profile failed!');</script>"; } } $sql = mysql_query( "SELECT * FROM users WHERE id='".$_SESSION['id']."'" ); $row = mysql_fetch_array($sql); echo "<h2>Edit profile</h2> <form method='post'> <table> <tr><th>registered:</th><td><input type='text' name='username' value='".$row['username']."'/></td></tr> <tr><th>password:</th><td><input type='password' name='password' value='".$row['password']."'/></td></tr> </table><br /> <input type='submit' name='btnedit' value='update' /> </form>"; ?> Hi, I have to ask about profile page for each user like facebook and netlog. As u can see in netlog it is like this http://en.netlog.com/ElegantLeo and i have a site http://cyprussaver.com/merchant.php?id=64 and here each merchant profile can be viewed like this but i need to show them like this http://cyprussaver.com/rocksman please guide me what i have to do in order to achieve this result. Thanks, Hanan ALi Good Day PHP world,
I am encountering a problem in php code meant to allow the user to update their profile picture.
I am using jquery.min and jquery.js. The code below runs with no errors reported. The file has been successfully uploaded to upload path using this form.
upload.php
<form id="imageform" method="post" enctype="multipart/form-data" action='ajaximage.php'> <input type="file" name="photoimg" id="photoimg" class="stylesmall"/> </form>ajaximage.php
$path = "uploads/";
$valid_formats = array("jpg", "png", "gif", "bmp","jpeg");
if(isset($_POST) and $_SERVER['REQUEST_METHOD'] == "POST")
{
$name = $_FILES['photoimg']['name'];
$size = $_FILES['photoimg']['size'];
if(strlen($name))
{
list($txt, $ext) = explode(".", $name);
if(in_array($ext,$valid_formats))
{
if($size<(1024*1024)) // Image size max 1 MB
{
$actual_image_name = $name.".".$ext;
$tmp = $_FILES['photoimg']['tmp_name'];
if(move_uploaded_file($tmp, $path.$actual_image_name))
{
$query = "UPDATE users SET profile_image='$actual_image_name' WHERE student_id='{$_SESSION['user_id']}'";
$result = mysqli_query($link_id, $query);
echo "<img src='uploads/".$actual_image_name."' class='preview'>";
}
The problem is the image being uploaded does not display on the
Student_home.php
<div id="about-img">
<img class="profile-photo" align="middle" src='uploads/".$actual_image_name."' />
</div>
But the image uploaded will display when i write directly its filename example
<div id="about-img">
<img class="profile-photo" align="middle" src="uploads/107.jpg" />
</div>
My problem is i wanted to display the uploaded picture of the specific student on Student_Home.php
Hi All, I am currently struggling with the my user info function which is supposed to display an image on my profile page along with the following parts of information taken from my database. The error is a mysql error stating that the $info = mysql_fetch_assoc($result); is not a valid arguement. Code: [Select] function fetch_user_info($uid) { $uid=(int)$uid; $sql = "SELECT `user_id AS `id` `user_username` AS `username`, `user_firstname` AS `firstname`, `user_lastname` AS `lastname`, `user_email` AS `email`, `user_location` AS `location`, `user_about` AS `about`, `user_gender` AS `gender` FROM `users` WHERE `user_id` = {$uid}"; $result = mysql_query($sql); $info = mysql_fetch_assoc($result); $info['avatar'] = "core/user_avatars/{$info['id']}.jpg"; return $info; } I have looked through the code a few times, but I can tell what is wrong. I have included below the profile page code in case it may be an issue there. Code: [Select] <?php include('core/init.inc.php'); $userinfo = fetch_user_info($_GET['uid']); ?> <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> <title><?php echo $userinfo ['username']; ?>'s Profile</title> </head> <body> <div> <?php if($userinfo == false) { echo 'Sorry, the user does not exist.'; } else { ?> <h1><?php echo $userinfo ['firstname']; ?> <?php echo $userinfo ['lastname']; ?></h1> <img src="<?php echo $userinfo['avatar'];?>" alt="avatar"/> <p>Username: <?php echo $userinfo ['username']; ?></p> <p>First Name: <?php echo $userinfo ['firstname']; ?></p> <p>Last Name: <?php echo $userinfo ['lastname']; ?></p> <p>Gender: <?php echo ($userinfo ['gender'] == 1) ? 'Male' : 'Female'; ?></p> <p>Email: <?php echo $userinfo ['email']; ?></p> <p>Location: <?php echo $userinfo ['location']; ?></p> <p>About: <?php echo $userinfo ['about']; ?></p> </div> <?php } ?> </body> </html> Thanks Jamie Right ive got a user profile that i want a add friend button but i coded a little something what i fort wud work but no luck <?php session_start(); include "includes/db_connect.php"; include "includes/functions.php"; include"includes/smile.php"; logincheck(); $username=$_SESSION['username']; $viewuser=$_GET['viewuser']; $fetch=mysql_fetch_object(mysql_query("SELECT * FROM users WHERE username='$viewuser'")); if (!$fetch){ echo "No such user"; $totalf = mysql_num_rows(mysql_query("SELECT * FROM friends WHERE username = '$viewuser' AND active='1'")); $invite_text="<div>$username Has Sent You A Friend Request<br> <input name=Yes_Accept type=submit id=yes value=Accept Invite class=abutton> <input name=No_accept type=submit value=Decline Invite class=abutton></div><input type=hidden name=invite_id value=$bar2>"; if (($_GET['fri'])){ $exicst=mysql_query("SELECT * FROM users WHERE username='$viewuser'"); $nums=mysql_num_rows($exicst); $adding=mysql_fetch_object($exicst); $already=mysql_num_rows(mysql_query("SELECT * FROM friends WHERE type='Friend' AND person='$viewuser' AND username='$username'")); if ($already != "0"){ echo "<center><font color=orange><b><br>This user is already your friend.<br><br></font>"; }elseif ($already == "0"){ mysql_query("INSERT INTO `friends` ( `id` , `username` , `person` , `type` , `active`) VALUES ( '', '$username', '$viewuser', 'Friend' , '0' )"); mysql_query("INSERT INTO `friends` ( `id` , `username` , `person` , `type` , `active`) VALUES ( '', '$viewuser', '$username', 'Friend' , '0' )"); mysql_query("INSERT INTO `inbox` ( `id` , `to` , `from` , `message` , `subject` , `date` , `read`) VALUES ( '', '$viewuser', '$username', '$invite_text' , 'Friend Request' , '$date' , '0' )"); $bar2=mysql_insert_id(); echo "<center><font color=orange><br>Your Friend Invitation Was Sent To $viewuser<br><br></font>"; exit(); } }} ?> <a href=?fri=Yes>Add Friend +</a> It just adds a blank person and comes back with No Such User and Your Friend Invitation Was Sent To I think ive put some things in the wrong place to be honest but as im not a pro i easily miss things Hi, I am making a dating site where I have made the user profile edit page visible to the user when they log in, and I think I can get away with not showing the user their "public" profile view. But I definitely need to show other users on the site the "public" non editing profile page view. But I don't know how to do this. I have yet to create the search, search results, thumbnails with optional descriptions of the possible dating results. But I first want to just get 2 versions of the user profile page view. One that the user sees that I have already done. (The editable one). And the other I need to make which is the page the other users will see, (The public profile) Please if anyone has any idea how to do this I would greatly appreciate it, especially if you have any pseudocode ideas. thank you. I am trying to upload files to a user profile system. here is the profile page Code: [Select] <?php include('core/init.inc.php'); if (isset($_POST['email'], $_POST['location'], $_POST['about'])) { $errors = array(); if(filter_var($_POST['email'], FILTER_VALIDATE_EMAIL) === false) { $errors[] = "The email address you entered is not valid"; } if(preg_match('#^[a-z0-9 ]+$#i',$_POST['location'])===0) { $errors[] = 'Your location must only contain A-Z 0-9 and spaces.'; } if (empty($_FILES['avatar']['tmp_name']) === false) { $file_ext = end(explode('.', $_FILES['avatar']['name'])); if(in_array(strtolower($file_ext), array('jpg', 'jpeg', 'gif', 'png')) === false) { $errors[] = 'Your avatar must be an image.'; } } if(empty($errors)) { print_r($_FILES); set_profile_info($_POST['email'],$_POST['location'],$_POST['about'], (empty($_FILES['avatar']['tmp_name'])) ? false : $_FILES['avatar']['tmp_name']); } $userinfo = array( 'email' => htmlentities($_POST['email']), 'location' => htmlentities($_POST['location']), 'about' => htmlentities($_POST['about']) ); } else { $userinfo = fetch_user_info($_SESSION['uid']); } ?> <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> <title>Edit your Profile</title> </head> <body> <div> <?php if(isset($errors) == false) { echo 'Click update to edit your profile.'; } else if(empty($errors)) { echo 'Your profile has been updated.'; } else { echo '<ul><li>', implode('</li><li>', $errors), '</li></ul>'; } ?> </div> <form action="" method="post" enctype="multipart/form-data"> <div> <label for="email">Email: </label> <input type="text" name="email" id="email" value="<?php echo $userinfo['email']; ?>" /> </div> <div> <label for="location">Location: </label> <input type="text" name="location" id="location" value="<?php echo $userinfo['location']; ?>" /> </div> <div> <label for="about">About Me: </label> <textarea name="about" id="about" rows="14" cols="50"><?php echo strip_tags($userinfo['about']); ?></textarea> </div> <div> <label for="avatar">Avatar: </label> <input type="file" name="avatar" id="avatar"/> </div> <div> <input type="submit" value="Update" /> </div> </form> </body> </html> here is the function taken from an external file Code: [Select] function set_profile_info($email, $location,$about,$avatar) { $email = mysql_escape_string(htmlentities($email)); $about = mysql_escape_string(nl2br(htmlentities($about))); $location = mysql_escape_string($location); if (file_exists($avatar)) { $src_size = getimagesize($avatar); if ($src_size['mime'] === 'image/jpeg') { $src_img = imagecreatefromjpeg($avatar); } else if ($src_size['mime'] === 'image/png') { $src_img = imagecreatefrompng($avatar); } else if ($src_size['mime'] === 'image/gif') { $src_img = imagecreatefromgif($avatar); } else { $src_img = false; } if ($src_img !== false) { $thumb_width= 200; if($src_size[0] <= $thumb_width) { $thumb = $src_img; } else { $new_size[0] = $thumb_width; $new_size[1] = ($src_size[1] / $src_size[0]) * $thumb_width; $thumb = imagecreatetruecolor($new_size[0], $new_size[1]); imagecopyresampled($thumb, $src_img, 0, 0, 0, 0, $new_size[0], $new_size[1], $src_size[0], $src_size[1]); } imagejpeg($thumb, "{$GLOBALS['path']}/user_avatars/{$_SESSION['uid']}.jpg"); } } $sql = "UPDATE `users` SET `user_email` = '{$email}', `user_about` = '{$about}', `user_location` = '{$location}' WHERE `user_id` = {$_SESSION['uid']}"; mysql_query($sql); } Below I have returned the array of files to check if its been uploaded correctly. Array ( [avatar] => Array ( [name] => Sonic.jpg [type] => image/jpeg [tmp_name] => /var/tmp/php.waq8n [error] => 0 [size] => 48477 ) ) But I get this error message. Warning: imagecreatefromjpeg() [function.imagecreatefromjpeg]: '/var/tmp/php.waq8n' is not a valid JPEG file in /web/stud/u0963643/userprofilesection/finaluserprofile/core/inc/user.inc.php on line 71 If someone could point out where in this code I have made an error I would be very grateful Thanks Jamie Hello users: I am exploring the delightful world of PHP for web applications. I am in the stage where I need to use SESSIONS and COOKIES and MYSQL for a user/membership/profile structure. I understand most of the grammar behind PHP and am excited to apply this in application. I am searching for recommendations and comments about using: 1. COOKIES 2. SESSIONS 3. MYSQL/SQL Almost every website has an authentication mechanism, profile, and use information. My website required this similar structure, but I have been having some problems completing all of the technical steps for production. If anyone has code samples or places where I can review code on this topic, that would be wonderful. I am specifically searching for more advanced topics in these area for general robustness. Please kindly send me a message or respond to this post. Regards, Diamond Edited by Diamond, 30 December 2014 - 04:27 PM. I would appreciate your assistance, there are tons of login scripts and they work just fine. However I need my operators to login and then list their activities for the other operators who are logged in to see and if desired send their clients on the desired activity. I have the login working like a charm and the activities are listed just beautifully. How do I combine the two tables in the MySQL with PHP so the operator Logged in can only make changes to his listing but see the others. FIRST THE ONE script the member logges in here to the one table in MSQL: <?php session_start(); require_once('config.php'); $errmsg_arr = array(); $errflag = false; $link = mysql_connect(DB_HOST, DB_USER, DB_PASSWORD); if(!$link) { die('Failed to connect to server: ' . mysql_error()); } $db = mysql_select_db(DB_DATABASE); if(!$db) { die("Unable to select database"); } function clean($str) { $str = @trim($str); if(get_magic_quotes_gpc()) { $str = stripslashes($str); } return mysql_real_escape_string($str); } $login = clean($_POST['login']); $password = clean($_POST['password']); if($login == '') { $errmsg_arr[] = 'Login ID missing'; $errflag = true; } if($password == '') { $errmsg_arr[] = 'Password missing'; $errflag = true; } if($errflag) { $_SESSION['ERRMSG_ARR'] = $errmsg_arr; session_write_close(); header("location: login-form.php"); exit(); } $qry="SELECT * FROM members WHERE login='$login' AND passwd='".md5($_POST['password'])."'"; $result=mysql_query($qry); if($result) { if(mysql_num_rows($result) == 1) { session_regenerate_id(); $member = mysql_fetch_assoc($result); $_SESSION['SESS_MEMBER_ID'] = $member['member_id']; $_SESSION['SESS_FIRST_NAME'] = $member['firstname']; $_SESSION['SESS_LAST_NAME'] = $member['lastname']; session_write_close(); header("location: member-index.php"); exit(); }else { header("location: login-failed.php"); exit(); } }else { die("Query failed"); } ?> ................................................. ................................ Now I need the person who logged in to the table above to be able to make multiple entries to the table below <? $ID=$_POST['ID']; $title=$_POST['title']; $cost=$_POST['cost']; $activity=$_POST['activity']; $ayear=$_POST['aday']; $aday=$_POST['ayear']; $seats=$_POST['special']; $special=$_POST['seats']; mysql_connect("xxxxxx", "xxx350234427", "========") or die(mysql_error()); mysql_select_db("xxxx") or die(mysql_error()); mysql_query("INSERT INTO `activity` VALUES ('ID','$title', '$cost','$activity', '$aday', '$ayear', '$special', '$seats')"); Print "Your information has been successfully added to the database!" ?> Click <a href="member-profile.php">HERE</a> to return to the main menu <?php ?> Hi all, I am currently facing a problem, if you look at 'viewprofile.jpg' attachment, you can see that there is an uploaded profile picture. However when I click to edit the profile, the picture is missing (editprofile.jpg), I am just wondering what went wrong? Can someone guide me in troubleshooting this problem? Code: [Select] <?php if (isset($_POST['submit'])) { // Validate and move the uploaded picture file, if necessary if (!empty($new_picture)) { if ((($new_picture_type == 'image/gif') || ($new_picture_type == 'image/jpeg') || ($new_picture_type == 'image/pjpeg') || ($new_picture_type == 'image/png')) && ($new_picture_size > 0) && ($new_picture_size <= CT_MAXFILESIZE)) { //0 indicates a success, other values indicate failure if ($_FILES['file']['error'] == 0) { // Move the file to the target upload folder $target = CT_UPLOADPATH . basename($new_picture); if (move_uploaded_file($_FILES['new_picture']['tmp_name'], $target)) { // The new picture file move was successful, now make sure any old picture is deleted if (!empty($old_picture) && ($old_picture != $new_picture)) { @unlink(CT_UPLOADPATH . $old_picture); } } else { // The new picture file move failed, so delete the temporary file and set the error flag @unlink($_FILES['new_picture']['tmp_name']); $error = true; echo '<p class="error">Sorry, there was a problem uploading your picture.</p>'; } } } else { // The new picture file is not valid, so delete the temporary file and set the error flag @unlink($_FILES['new_picture']['tmp_name']); $error = true; echo '<p class="error">Your picture must be a GIF, JPEG, or PNG image file no greater than ' . (CT_MAXFILESIZE / 1024). '</p>'; } } // Grab the profile data from the POST $name = mysqli_real_escape_string($dbc, trim($_POST['name'])); $nric = mysqli_real_escape_string($dbc, trim($_POST['nric'])); $gender = mysqli_real_escape_string($dbc, trim($_POST['gender'])); $old_picture = mysqli_real_escape_string($dbc, trim($_POST['old_picture'])); $new_picture = mysqli_real_escape_string($dbc, trim($_FILES['new_picture']['name'])); $new_picture_type = $_FILES['new_picture']['type']; $new_picture_size = $_FILES['new_picture']['size']; list($new_picture_width, $new_picture_height) = getimagesize($_FILES['new_picture']['tmp_name']); $error = false; // Update the profile data in the database if (!$error) { if (!empty($name) && !empty($nric) && !empty($gender)) { $query = "UPDATE tutor_profile SET name = '$name', nric = '$nric', gender = '$gender' WHERE tutor_id = '" . $_GET['tutor_id'] . "'"; mysqli_query($dbc, $query) or die(mysqli_error($dbc)); // Confirm success with the user echo '<p>Your profile has been successfully updated. Would you like to <a href="viewprofile.php?tutor_id=' . $_GET['tutor_id'] . '">view your profile</a>?</p>'; mysqli_close($dbc); exit(); } else { echo '<p class="error">You must enter all of the profile data (the picture is optional).</p>'; } } } // End of check for form submission else { // Grab the profile data from the database $query = "SELECT name, nric, gender FROM tutor_profile WHERE tutor_id = '" . $_GET['tutor_id'] . "'"; $data = mysqli_query($dbc, $query) or die(mysqli_error($dbc)); // The user row was found so display the user data if (mysqli_num_rows($data) == 1) { $row = mysqli_fetch_array($data); if ($row != NULL) { $name = $row['name']; $nric = $row['nric']; $gender = $row['gender']; } else { echo '<p class="error">There was a problem accessing your profile.</p>'; } } } mysqli_close($dbc); ?> <form enctype="multipart/form-data" method="post" action="<?php echo $_SERVER['PHP_SELF']; ?>"> <input type="hidden" name="MAX_FILE_SIZE" value="<?php echo CT_MAXFILESIZE; ?>" /> <ul id="tabSet_ep"> <li><a href="#panel1">Personal Profile</a></li> <li><a href="#panel2">Qualifications</a></li> <li><a href="#panel3">Tutor\'s Comments/Commitment</a></li> <li><a href="#panel4">Tutoring Levels/Subjects</a></li> </ul> <!--Personal Profile--> <div id="panel1"> <label for="new_picture">Pictu </label> <input type="file" id="new_picture" name="new_picture" /> <?php if (!empty($old_picture)) { echo '<img class="profile" src="' . CT_UPLOADPATH . $old_picture . '" alt="Profile Picture" />'; } ?><br /> <label for="firstname">First name:</label> <input type="text" id="firstname" name="firstname" value="<?php if (!empty($name)) echo $name; ?>" /><br /> <label for="lastname">Last name:</label> <input type="text" id="lastname" name="lastname" value="<?php if (!empty($nric)) echo $nric; ?>" /><br /> <label for="gender">Gender:</label> <select id="gender" name="gender"> <option value="M" <?php if (!empty($gender) && $gender == 'M') echo 'selected = "selected"'; ?>>Male</option> <option value="F" <?php if (!empty($gender) && $gender == 'F') echo 'selected = "selected"'; ?>>Female</option> </select><br /> </div> <input type="submit" value="Save Profile" name="submit" /> </form> I have a server script with which i have allowed the user to mark any item as favorite, but i also want another script through which the user can unfavorite the same item if they want and that item should be deleted from their favorite list. I have kept the same table for both favorite and unfavorite code, therefore i have used update query to update the details. For this purpose i have a code, but its not working, as i am new in the programming field would appreciate if someone could provide the correct codes
<?php
require_once('config.php');
$favorite = $_REQUEST['favorite'];
$unfavorite = $_REQUEST['unfavorite'];
$id=$_REQUEST['id'];
$unfavoritedeal=mysql_query("SELECT * FROM favoritedeals where id='".$id."'"); //favoritedeals is the name of the table
if($row=mysql_fetch_array($unfavoritedeal))
{
$favorite=$row['favorite'];
$unfavorite=$row['unfavorite'];
}
$myfavorite=(isset($_REQUEST['favorite'])?$_REQUEST['favorite']:$favorite);
$myunfavorite=(isset($_REQUEST['unfavorite'])?$_REQUEST['unfavorite']:$unfavorite);
$update = mysql_query("update favoritedeals set favorite = '".$myfavorite."', unfavorite = 1 where id = '".$id."'");
if(unfavorite="1" where id='".$id."')
{
"delete from favoritedeals WHERE id= '".$id."'";
}
$posts[0]['message'] = 'favorite list updated';
$selectt = mysql_query("select * from favoritedeals where id = '".$id."'");
$results = mysql_fetch_assoc($selectt);
$posts[0]['detail'] = $results;
header('Content-type: application/json');
echo json_encode($posts);
?>
Quote Warning: mysql_fetch_array(): supplied argument is not a valid MySQL result resource in /home/largemus/public_html/assets/inc/upcoming.php on line 15 i have hidden connection details for this example Code: [Select] <?php $host=""; // Host name $username=""; // Mysql username $password=""; // Mysql password $db_name=""; // Database name $tbl_name=""; // Table name // Connect to server and select database. mysql_connect("$host", "$username", "$password")or die("cannot connect server "); mysql_select_db("$db_name")or die("cannot select DB"); $sql="SELECT * FROM $tbl_name WHERE user = $session->clientid ORDER BY date ASC LIMIT 3;"; $result=mysql_query($sql); while($rows=mysql_fetch_array($result)){ ?> <div style="width:385px;"> <table style="width: 385px; text-align:center;"> <tr> <td style="width: 121px"><h3>Client</h3></td> <td style="width: 100px"><h3>Occasion</h3></td> <td style="width: 80px"><h3>Location</h3></td> <td><h3>Date</h3></td> </tr> </table> <table style="width: 385px"> <tr> <td style="width: 121px"> <p><? echo $rows['clientid']; ?></p> </td> <td style="width: 100px"> <p><? echo $rows['occasion']; ?></p> </td> <td style="width: 80px"> <p><? echo $rows['location']; ?></p> </td> <td> <p><? echo $rows['date']; ?></p> </td> </tr> </table> </div> <? } mysql_close(); //close database ?> show list of files uploaded by current session user to the database. I want to show different users when they log in to the website...they can see a list of old files that they have uploaded. can anyone tell me the code/script to this.....please, ty Hey guys, I can't wrap my head around how to make this work right... I have three tables: Code: [Select] CREATE TABLE `games` ( `g_id` int(11) NOT NULL AUTO_INCREMENT, `name` varchar(150) DEFAULT NULL, PRIMARY KEY (`g_id`)); CREATE TABLE IF NOT EXISTS `game_player` ( `r_id` int(11) NOT NULL AUTO_INCREMENT, `p_id` int(11) DEFAULT NULL, `g_id` int(11) DEFAULT NULL, `bool` int(1) NOT NULL DEFAULT '0', PRIMARY KEY (`r_id`)); CREATE TABLE IF NOT EXISTS `players` ( `p_id` int(11) NOT NULL AUTO_INCREMENT, `playerid` varchar(150) NOT NULL, PRIMARY KEY (`p_id`), UNIQUE KEY `playerid` (`playerid`)); The players table is my list of users, and they're tied to the list of games via the game_player table. So here's my issue... I'm trying to show the full list of games, and then check mark each record where the player does play it. This is what I have so far - it shows all the games, but it's not checking the boxes. Code: [Select] $result = mysql_query("SELECT * FROM games") or die(mysql_error()); while($row = mysql_fetch_array($result)) { $newquery = "SELECT * FROM game_player, players WHERE game_player.p_id = players.p_id AND game_player.g_id = ".$row['g_id']. " AND players.playerid = {$userid}"; $query = mysql_query($newquery) or die(mysql_error()); if($query['bool'] == 1) { $set_checked = " CHECKED"; } else{ $set_checked = ""; } echo "<input type=\"checkbox\" name=\"box1\" value=\"".$query['g_id']."\"" . $set_checked . "/>".$row['name']."<br />\n"; } I need help with this script...... i get the error... 'Undefined index: username in C:\wampnew\www\login and register\profile.php on line 28!' <?php require("include/connect.php"); if(!isset($_GET['id'])) { echo("Please enter a members profile to view."); die(); } elseif($_GET['id'] == "") { echo("Please enter a members profile to view."); die(); } $pid = mysql_real_escape_string(preg_replace("@[^a-z0-9]@i","",$_GET['id'])); $check = mysql_num_rows(mysql_query("SELECT id FROM tut_users WHERE id='{$pid}'")); if($check !="1") { echo("Member does not exist."); require("footer.php"); die(); } $sql = mysql_query("SELECT * FROM tut_users WHERE id='{$pid}'") or die(mysql_error()); $fetch = mysql_fetch_assoc($sql) or die(mysql_error()); $username = mysql_real_escape_string(preg_replace("@[^a-z0-9]@i","",$fetch['username'])); echo("Member Profile Of: {$username} <br /> " ); ?> Could someone please help me thanks... Hi everyone, i have currently have a registration and login page working, i have now included a profile/edit profile page once the user is logged in. However im having a problem, once the user logs in the account page welcomes them by there username using the following code <h2>Welcome, <?php echo $_SESSION['username']; ?></h2> Which is fine, however when users edit there profile there details arent stored into there userid within the mysql database. for example this is my edit profile page and this is what it does within the mysql database: It doesn't save that info to the current user and im not sure how to get it to do it, heres my code: <?PHP //Database Information $dbhost = "localhost"; $dbname = "blank"; $dbuser = "blank"; $dbpass = "password"; //Connect to database mysql_connect ( $dbhost, $dbuser, $dbpass)or die("Could not connect: ".mysql_error()); mysql_select_db($dbname) or die(mysql_error()); $real_name = $_POST['real_name']; $location = $_POST['location']; $mobile_number = $_POST['mobile_number']; $instant_messaging = $_POST['instant_messaging']; $query = "REPLACE INTO users (real_name, location, mobile_number, instant_messaging) VALUES('$real_name', '$location', '$mobile_number', '$instant_messaging')"; mysql_query($query) or die(mysql_error()); mysql_close(); ?> I can see why it doesn't work as it just inserts it into the users database but I'm not sure how to associate it with the current logged in user. Any help would be great, Lee Here's a function I use for displaying a member's profile using $_GET Code: [Select] <?php function view_profile ($username) { include_once "connect.php"; $query = "SELECT * FROM fans WHERE username = '$username'"; $result = mysql_query($query); $row = mysql_fetch_array($result); $count = mysql_num_rows($result); while ($row = mysql_fetch_array($result)) { $username = $row["username"]; $name = $row["name"]; $email = $row["email"]; $region = $row["region"]; $country = $row["country"]; $gender = $row["gender"]; $status = $row["status"]; $subscription = $row["subscription"]; $time_registered = $row["time_registered"]; $date_registered = $row["date_registered"]; $birthdate = $row["birthdate"]; $age = $row["age"]; $last_time = $row["last_time"]; $last_date = $row["last_date"]; $default_photo = $row["default_photo"]; $about_me = $row["about_me"]; echo $name; echo $email; echo $status; echo $username; } } ?> The only problem is, its not echoing the member's information when the function gets called. I used a variable called "$count" and echoed that to see if it was getting any results, and it is, it's just the while loop isn't working and i don't know why as I used an identical function like this for another script. Any suggestions? Hi I am trying to develop an editprofile.php page to allow users to change their details. So far i have written Code: [Select] <?php $result = mysql_query("SELECT username FROM users WHERE username = {$_SESSION['MM_Username']}"); $num_rows = mysql_num_rows($result); if($num_rows > 0) { while ($row = mysql_fetch_array($result)) { $username = $row['username']; } } ?> and then tried to test it by using Code: [Select] <div><?php echo $username ?></div> but nothing is being echo'ed out. What am i doing wrong? |
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