PHP - Insert Multiple Entries Into Multiple Tables
I have a form where a user can duplicate part of a form like below:
I've named the fields with the HTML arrays (ie. "fieldName[]") and came up with this: //--> CONTROLLERS $system_controllers_qty = $_POST['system_controllers_qty']; $system_controllers_make = $_POST['system_controllers_make']; $system_controllers_model = $_POST['system_controllers_model']; $system_controllers_serial_no = $_POST['system_controllers_serial_no']; for ($i = 0; $i < count($system_controllers_qty); $i++) { echo "qty " . clean($system_controllers_qty[$i]) . "<br/>"; echo "make " . clean($system_controllers_make[$i]) . "<br/>"; echo "model " . clean($system_controllers_model[$i]) . "<br/>"; echo "serial_no " . clean($system_controllers_serial_no[$i]) . "<br/>"; } //--> CPUS $system_cpus_qty = $_POST['system_cpus_qty']; $system_cpus_model = $_POST['system_cpus_model']; $system_cpus_serial_no = $_POST['system_cpus_serial_no']; $system_cpus_speed = $_POST['system_cpus_speed']; for ($i = 0; $i < count($system_cpus_qty); $i++) { echo "qty " . clean($system_cpus_qty[$i]) . "<br/>"; echo "model " . clean($system_cpus_model[$i]) . "<br/>"; echo "serial_no " . clean($system_cpus_serial_no[$i]) . "<br/>"; echo "speed " . clean($system_cpus_speed[$i]) . "<br/>"; } //--> DISKS $system_disks_qty = $_POST['system_disks_qty']; $system_disks_make = $_POST['system_disks_make']; $system_disks_model_no = $_POST['system_disks_model_no']; $system_disks_size = $_POST['system_disks_size']; $system_disks_serial_no = $_POST['system_disks_serial_no']; for ($i = 0; $i < count($system_disks_qty); $i++) { echo "qty " . clean($system_disks_qty[$i]) . "<br/>"; echo "make " . clean($system_disks_make[$i]) . "<br/>"; echo "model_no " . clean($system_disks_model_no[$i]) . "<br/>"; echo "size " . clean($system_disks_size[$i]) . "<br/>"; echo "serial_no " . clean($system_disks_serial_no[$i]) . "<br/>"; } //--> MEMORY $system_memory_qty = $_POST['system_memory_qty']; $system_memory_serial_no = $_POST['system_memory_serial_no']; $system_memory_manf = $_POST['system_memory_manf']; $system_memory_part_no = $_POST['system_memory_part_no']; $system_memory_size = $_POST['system_memory_size']; for ($i = 0; $i < count($system_memory_qty); $i++) { echo "qty " . clean($system_memory_qty[$i]) . "<br/>"; echo "serial " . clean($system_memory_serial_no[$i]) . "<br/>"; echo "manf " . clean($system_memory_manf[$i]) . "<br/>"; echo "part_no " . clean($system_memory_part_no[$i]) . "<br/>"; echo "size " . clean($system_memory_size[$i]) . "<br/>"; } This just outputs all the fields I post at the moment. Say I have 3 different disk types, it's going to loop 3 times. Is it possible to make this all into 1 giant query or am I better off doing each query separately? Each section is a different table. Similar TutorialsOk I'm trying to insert multiple rows by using a while loop but having problems. At the same time, need to open a new mysql connection while running the insert query, close it then open the previous mysql connection. I managed to insert multiple queries before using a loop, but for this time, the loop does not work? I think it is because I am opening another connection... yh that would make sense actually? Here is the code: $users = safe_query("SELECT * FROM ".PREFIX."user"); while($dp=mysql_fetch_array($users)) { $username = $dp['username']; $nickname = $dp['nickname']; $pwd1 = $dp['password']; $mail = $dp['email']; $ip_add = $dp['ip']; $wsID = $dp['userID']; $registerdate = $dp['registerdate']; $birthday = $dp['birthday']; $avatar = $dp['avatar']; $icq = $dp['icq']; $hp = $dp['homepage']; echo $username." = 1 username only? :("; // ----- Forum Bridge user insert ----- $result = safe_query("SELECT * FROM `".PREFIX."forum`"); $ds=mysql_fetch_array($result); $forum_prefix = $ds['prefix']; define(PREFIX_FORUM, $forum_prefix); define(FORUMREG_DEBUG, 0); $con = mysql_connect($ds['host'], $ds['user'], $ds['password']) or system_error('ERROR: Can not connect to MySQL-Server'); $condb = mysql_select_db($ds['db'], $con) or system_error('ERROR: Can not connect to database "'.$ds['db'].'"'); include('../_phpbb_func.php'); $phpbbpass = phpbb_hash($pwd1); $phpbbmailhash = phpbb_email_hash($mail); $phpbbsalt = unique_id(); safe_query("INSERT INTO `".PREFIX_FORUM."users` (`username`, `username_clean`, `user_password`, `user_pass_convert`, `user_email`, `user_email_hash`, `group_id`, `user_type`, `user_regdate`, `user_passchg`, `user_lastvisit`, `user_lastmark`, `user_new`, `user_options`, `user_form_salt`, `user_ip`, `wsID`, `user_birthday`, `user_avatar`, `user_icq`, `user_website`) VALUES ('$username', '$username', '$phpbbpass', '0', '$mail', '$phpbbmailhash', '2', '0', '$registerdate', '$registerdate', '$registerdate', '$registerdate', '1', '230271', '$phpbbsalt', '$ip_add', '$wsID', '$birthday', '$avatar', '$icq', '$hp')"); if (FORUMREG_DEBUG == '1') { echo "<p><b>-- DEBUG -- : User added: ".mysql_affected_rows($con)."<br />"; echo "<br />-- DEBUG -- : Query used: ".end($_mysql_querys)."</b></p><br />"; $result = safe_query("SELECT user_id from ".PREFIX_FORUM."users WHERE username = '$username'"); $phpbbid = mysql_fetch_row($result); safe_query("INSERT INTO `".PREFIX_FORUM."user_group` (`group_id`, `user_id`, `group_leader`, `user_pending`) VALUES ('2', '$phpbbid[0]', '0', '0')"); safe_query("INSERT INTO `".PREFIX_FORUM."user_group` (`group_id`, `user_id`, `group_leader`, `user_pending`) VALUES ('7', '$phpbbid[0]', '0', '0')"); mysql_close($con); } include('../_mysql.php'); mysql_connect($host, $user, $pwd) or system_error('ERROR: Can not connect to MySQL-Server'); mysql_select_db($db) or system_error('ERROR: Can not connect to database "'.$db.'"'); } So I need to be able to insert these rows using the while loop.. how can I do this? I really appreciate any help. Hello all, I am trying to learn OOP in PHP so please forgive my ignorance. I seem to be having difficulty inserting data into my database from checkbox items. My database has a column for each each fruit. I would like for each column to be populated with either a one(1) for checked or a zero(0) for not checked. Currently, my attempts have failed. I can either get all checkboxes to insert all zeros or I can get the first column to insert a one(1) while the others as zeros. Is there anybody here that can help me figure out what I am doing wrong and help me to re-work my code so I can get this to work? If anybody can help me using OOP methods that would be fantastic. Thank you all in advance.
$preffruit->create_preffruit(array( 'fruit_apple' => escape(Input::get(['fruit_selection'][0]) ? 1 : 0), 'fruit_orange' => escape(Input::get(['fruit_selection'][1]) ? 1 : 0), 'fruit_banana' => escape(Input::get(['fruit_selection'][2]) ? 1 : 0), 'fruit_pear' => escape(Input::get(['fruit_selection'][3]) ? 1 : 0), 'fruit_kiwi' => escape(Input::get(['fruit_selection'][4]) ? 1 : 0) )); <input type="checkbox" name="fruit_selection[]" value="fruit_apple"> <input type="checkbox" name="fruit_selection[]" value="fruit_orange"> <input type="checkbox" name="fruit_selection[]" value="fruit_banana"> <input type="checkbox" name="fruit_selection[]" value="fruit_pear"> <input type="checkbox" name="fruit_selection[]" value="fruit_kiwi"> public function insert_preffruit($table, $fields = array()) { $keys = array_keys($fields); $values = ''; $x = 1; foreach($fields as $field) { $values .= '?'; if($x < count($fields)) { $values .= ', '; } $x++; } $sql = "INSERT INTO preffruit (`user_id`, `" . implode('`, `', $keys) . "`) VALUES (LAST_INSERT_ID(), {$values})"; if(!$this->query($sql, $fields)->error()) { return true; } return false; } Edited September 23, 2020 by ke-jo I am trying to export multiple csv files to download from 2 separate tables in my database. Some background: I have a web app that links to a phpmyadmin database. There are 2 tables in the database (entering and exiting). These tables hold the phone inventory information of employees currently entering or exiting the organization. The fields in my tables a location, firstname, lastname, username, extension, mac, type What I am trying to do is export the data in these 2 tables to CSV (which I have working now) but I need to have multiple CSVs for each. For example, for my exiting table, I need to have one CSV export all the fields in the table and I also need another CSV to export just the location and username field. I have a simple html form with a submit button which is currently working now: <form action="exportexiting.php" method="POST" style="width: 456px; height: 157px"> <div> <fieldset> <legend style="width: 102px; height: 25px"><strong>Entering CSV:</strong></legend> <input name="Export" type="submit" id="Export" value="Export"> </fieldset><br/> </div> </form> This links to my exportexiting.php file: <?php $host = 'localhost'; $user = 'root'; $pass = 'xxxx'; $db = 'PhoneInventory'; $table = 'exiting'; // Connect to the database $link = mysql_connect($host, $user, $pass); mysql_select_db($db); require 'exportcsv.inc.php'; exportMysqlToCsv($table); ?> Then to exportcsv.inc.php: <?php function exportMysqlToCsv($table,$filename = 'export.csv') { $csv_terminated = "\n"; $csv_separator = ","; $csv_enclosed = ''; $csv_escaped = "\\"; $sql_query = "select * from $table"; // Gets the data from the database $result = mysql_query($sql_query); $fields_cnt = mysql_num_fields($result); $schema_insert = ''; for ($i = 0; $i < $fields_cnt; $i++) { $l = $csv_enclosed . str_replace($csv_enclosed, $csv_escaped . $csv_enclosed, stripslashes(mysql_field_name($result, $i))) . $csv_enclosed; $schema_insert .= $l; $schema_insert .= $csv_separator; } // end for $out = trim(substr($schema_insert, 0, -1)); $out .= $csv_terminated; // Format the data while ($row = mysql_fetch_array($result)) { $schema_insert = ''; for ($j = 0; $j < $fields_cnt; $j++) { if ($row[$j] == '0' || $row[$j] != '') { if ($csv_enclosed == '') { $schema_insert .= $row[$j]; } else { $schema_insert .= $csv_enclosed . str_replace($csv_enclosed, $csv_escaped . $csv_enclosed, $row[$j]) . $csv_enclosed; } } else { $schema_insert .= ''; } if ($j < $fields_cnt - 1) { $schema_insert .= $csv_separator; } } // end for $out .= $schema_insert; $out .= $csv_terminated; } // end while header("Cache-Control: must-revalidate, post-check=0, pre-check=0"); header("Content-Length: " . strlen($out)); // Output to browser with appropriate mime type, you choose header("Content-type: text/x-csv"); //header("Content-type: text/csv"); //header("Content-type: application/csv"); header("Content-Disposition: attachment; filename=$filename"); echo $out; exit; } ?> Again, this is working perfectly for only exporting all the data from the exiting table into one CSV file. My question is, how can I make my one submit button export the 2 CSV files that I need? Thanks for the help... I have a search where I want to be able to search a string of words. The search is going to be looking in 2 different table joined by a left outer join. The tables are "quotes" and "categories". $sql="SELECT q.id, q.username, q.quote, q.by, q.voteup, q.votedown, q.servtime, c.quote_id, c.label FROM quotes q LEFT OUTER JOIN categories c ON q.id = c.quote_id WHERE ( q.username LIKE '$srch' OR q.quote LIKE '$srch' OR q.`by` LIKE '$srch' OR c.label LIKE '$srch')"; The above mysql statement works and returns values..BUT if say, I search "john" and "funny", and a quote is posted by the user "john", but has a category of "funny" it will output the same quote twice. I was wondering if there was a way to see if a quote has either 1 term or both terms, if so display that quote but only display it once. Below is what the query is outputting. [100] => Array ( [id] => 100 [username] => John [quote] => new test quote blah blah [by] => John [voteup] => 0 [votedown] => 0 [servtime] => 2010-12-02 @ 16:27:03 [label] => Array ( [0] => Historic [1] => Serious [2] => Funny ) ) Here is the code in full. //// $sword = explode(" ",$search); foreach($sword as $sterm){ $srch="%".$sterm."%"; echo"$srch<br />"; $sql="SELECT q.id, q.username, q.quote, q.by, q.voteup, q.votedown, q.servtime, c.quote_id, c.label FROM quotes q LEFT OUTER JOIN categories c ON q.id = c.quote_id WHERE ( q.username LIKE '$srch' OR q.quote LIKE '$srch' OR q.`by` LIKE '$srch' OR c.label LIKE '$srch')"; $result=mysql_query($sql); while($row=mysql_fetch_object($result)){ $quote[$row->id]['id'] = $row->id; $quote[$row->id]['username'] = $row->username; $quote[$row->id]['quote'] = $row->quote; $quote[$row->id]['by'] = $row->by; $quote[$row->id]['voteup'] = $row->voteup; $quote[$row->id]['votedown'] = $row->votedown; $quote[$row->id]['servtime'] = $row->servtime; $quote[$row->id]['label'][] = $row->label; } echo"<pre>"; print_r($quote); echo"</pre>"; I don't think this is the fastest way of doing this, as it loops for each item in the db, per each keyword that is search. Any help would be great!! -BaSk Hello, For starters I'm not sure if what I want to do is possible, but if it is I would like your input. I have a script that will show a number of fields to fill out in a second form based on the number the user puts into the first from. the problem is that only the last one saves into the database and not all of them. Code: [Select] <form auction="index.php" method="post"> System Name: <input type="text" name="systemname"> Number of E-sites: <input type="text" name="events"> Number of Sigs: <input type="text" name="sigs"><br> <input type="reset" name="reset" value="Reset"> <input type="submit" name="start" value="Start"> </form> <form auction="index.php" method="post"> <?php $events = $_POST['events']; $system = $POST['systemname']; if (isset($_POST['start'])) { $num = $_POST['sigs']; $i = 0; While ($i < $num) { echo "Sig ID: <input type=text name=sigid>"; echo "Type: <input type=text name=type>"; echo "Name: <input type=text name=name>"; echo "Notes: <input type=text name=notes>"; echo "<br>"; $i++; } } ?> <input type="submit" name="enter" value="Enter"> </form> <?php $sigid = $_POST['sigid']; $type = $_POST['type']; $name = $_POST['name']; $notes = $_POST['notes']; mysql_connect('xt', 'x', 'x'); mysql_select_db('wormhole'); if (isset($_POST['enter'])) { $query = "INSERT INTO sites VALUES ('$system','$events','$sigid','$type','$name','$notes')"; mysql_query($query); } ?> How do I get it so all the data saves, lets say that $num = 5, I want all 5 to save not just the last one. Hello, Hopefully I can ger som help here I have been googling this for months and seem to cant find anything that will help me out. I am trying to create a form (which is the easy part) but I want this form to send multiple entries at once from what I gather so far I need to use for each and/or loop which i am not familiar with it with my lack of knowledge........ what I have so far is Table= locations fields are id state county city the form is set up as follows state county city city city city city city city city city city city city The reason for so many cities is so i can update all cities in one county at the same time saving time I am not sure if its % doable in the manner i would like it to be done but i hope so ok i enter the state and county then i enter the cities i want i submit the form i want it to create the state/county and the first city with the next id # then enter the state/county and next city and id#. please some help me if u need to see my file let me know and ill post it im just not sure which one you need i believe it will be the save.php file but i also have the create.php file which is the form itself Thanks anyone for the help i can get Hi guys Im trying to delete multiple images from a page with the code below, I have retirieved the images successfully but i can not delete the with checkbox, wht it does is just refereshing the page and thats it, what im trying to do is to delete the image from the database but it wont. can u help me please? <?php session_start(); include ("../../global.php"); //welcome messaage $username=$_SESSION['username']; echo "$username"; $query=mysql_query("SELECT id FROM users WHERE username='$username'"); while($row = mysql_fetch_assoc($query)) { $user_id = $row['id']; } $ref=$_GET['reference']; $images=mysql_query("SELECT * FROM img WHERE refimage='$ref'"); while($row = mysql_fetch_array($images)) { $image=$row['image']; $thumb=$row['thumb']; ?> <table width="400" border="0" cellspacing="1" cellpadding="0"> <tr> <td><form name="" method="post" action=''> <tr> <td align="center" bgcolor="#FFFFFF"><input name="checkbox[]" type="checkbox" id="checkbox[]" value="<? echo $rows['id']; ?>"></td> <td bgcolor="#FFFFFF"><? echo "<a href='$image' rel='lightbox[roadtrip]'><img src= '$thumb' width='60' height='40' alt='$title'>";?></td> <? } ?> <tr> <td colspan="5" align="center" bgcolor="#FFFFFF"><input name="delete" type="submit" id="delete" value="Delete"></td> </tr> <?php // Check if delete button active, start this $delete = $_REQUEST['delete']; if( $delete != '' ){ $checkbox = $_REQUEST['checkbox']; $count = count($_REQUEST['checkbox']); for($i=0;$i<$count;$i++){ $del_id = $checkbox[$i]; $del = mysql_query("DELETE FROM img WHERE id = '$del_id'"); } } ?> Hi, I want to build into my html table that populates my database table to have a column for checkboxes with a delete button that takes the user to another page to confirm the deletion by outputting a message: Are you sure you want to delete ____, followed by a for loop to see how many checked records to get its ID in order to get its appropriate name. So I have a submit button with name attribute of "delete0" and the values of the input type of checkbox is $row['ID'], for some reason, I get the notice: "Notice: Undefined index: modifyArray in C:\display.php" and modifyArray is the name I give to the checkbox attribute (please see this in my display.php below) Here is my display.php Code: [Select] <table border="border"> <!--NB: checkbox form for multiple delete/update/insert--> <form method="post" action=""> <input type='submit' value='DELETE' name='delete0' /> <?php session_start(); require 'bellSessionDisconnect.inc'; require 'bellConnect.inc.php'; $result=mysql_query("SELECT ID, Image, Name, Manufacturer, Price, Description, SimSupport FROM bellProducts"); //phpinfo(); //NB: print table headings if(mysql_num_rows($result))//if there is at least one entry in bellProducts, make a table { //$counter+=1; print "<table border='border'>"; print "<tr> <th>ID</th> <th>Select entries to modifiy</th> <th>Image</th> <th>Name</th> <th>Manufacturer</th> <th>Price</th> <th>Description</th> <th>SimSupport</th> <th colspan='2' align='center'>Modify</th> </tr>"; //NB: now output each row of records while($row=mysql_fetch_assoc($result)) { //extract($row); "<tr align='center'> <td>$row[ID]</td> <td><input type='checkbox' name='modifyArray[]' value='$row[ID]' /></td> <td>"; if(!empty($row['Image'])) { $curImage=$row['Image']; } else if(empty($row['Image'])) { $curImage='fileUploadIcon.jpg'; //$title="please upload item image"; } print "<img src=$curImage width='70px' height='90px' /> </td> <td> $row[Name] </td> <td> $row[Manufacturer] </td> <td> $$row[Price]</td> <td align='left'>$row[Description]</td> <td>$row[SimSupport]</td> <td><a href='bellUploadForm.php?ID=$row[ID]'>UPLOAD IMAGE</a></td> <td><a href='bellUpdateForm.php?ID=$row[ID]'>UPDATE</a></td> </tr>"; //}//END INNER IF }//END WHILE }//END BIG IF ?> <?php if(array_key_exists('delete0', $_POST)) { $modifyArray=$_POST["modifyArray"]; if(!empty($modifyArray)) { header("Location: http://localhost/bellDeleteForm.php"); exit(); } } ?> </form> </table> I will worry about redirecting to bellDeleteForm.php to confirm the records the user wants to delete after I get this going, please help!!! thanks Here is one of those purely conceptual questions, which involves no code. I'm trying to create a select query which among other things, allows a user of a website to search other members who fall within a particular age range. I have a column in the table where the members' information are stored which records their ages. Which brings us to the problem. On any given day, a member's age may increase by one year compared to what it was the previous day, hence the need to update this column periodically. I can't think of any way to automatically update this column on a daily basis. So my solution is to run an initial update query every time a member tries to search other members based on age, which updates the age column for all other members, before running the select query which eventually retrieves the desired age range. This leads to the second problem. Imagine there are thousands of users using the website. At any given instance, there could be hundreds of members, trying to search others based on age. This means hundreds of users will be updating a single column (the age column) in one table at the same time. Is this feasible? Can it cause the server to crash? Or is there really a more reasonable way to do all of this? Thank you all for taking your time to read this. Appreciate any responses. MySQL returns an error in the form of a number, a state, and a message. Without parsing the message you will not be able to determine what column is duplicated.While parsing the error code, I have also notice that, if you have multiple unique fields as duplicates, only the first duplicate encountered will be returned in the message. This is not very helpful to the end user.
Is there any way to parse the returned error code to reflect all duplicate fields, please see sample code below?
$error=array(); $sql = 'INSERT INTO staff(username, email, phone) VALUES (?, ?, ?)'; $stmt = $conn->stmt_init(); $stmt = $conn->prepare($sql); // bind parameters and insert the details into the database $stmt->bind_param('sss', $username, $email, $phone); $stmt->execute(); if ($stmt->errno == 1062) { $errors[] = "One of the fields is already in use."; } <?php require_once("../includes/session.php");?> <?php require_once("../includes/connection.php");?> <?php require_once("../includes/function.php");?> <?php confirm_logged_in();?> <?php require_once("../includes/validation_functions.php");?> <?php if(isset($_POST['submit'])){ //process the form // often there are form values in $_POST $product_name = mysql_prep($_POST["product_name"]); $product_amount = (int) $_POST["product_amount"]; $visible = (int) $_POST["visible"]; foreach($_FILES['files']['tmp_name'] as $key => $tmp_name ){ $file_tmp =$_FILES['files']['tmp_name'][$key]; $uploaded_dir = "images/"; $filename = $_FILES['files']['name'][$key]; $path = $uploaded_dir . $filename; move_uploaded_file($file_tmp,"images/".$_FILES['files']['name'][$key]); $query ="INSERT INTO products ("; $query .=" name, amount, visible"; $query .=") VALUES ("; $query .=" '{$product_name}',{$product_amount},{$visible}"; $query .=")"; $result = mysqli_query($connection,$query); $last_id = mysqli_insert_id($connection); $sql.= "('$last_id','$path'),"; $sql ="INSERT INTO images ( productID, file_name ) VALUES". trim($sql,','); $results = mysqli_query($connection,$sql); // validations $required_fields = array("product_name", "product_amount"); validate_presences($required_fields); $fields_with_max_lenghts = array("product_name" => 30); validate_max_lenght($fields_with_max_lenghts); if(!empty($errors)){ $_SESSION["errors"] = $errors; redirect_to("new_product.php"); } if($result && $results ){ // Sucess $_SESSION["message"] = "Product inserted."; redirect_to("manage_content.php"); }else{ // Failure $_SESSION["message"] = "Product insertion Failed."; redirect_to("new_product.php"); } } }else{ // THis is probably a GET request redirect_to("new_product.php"); } ?> <?php if(isset($connnection)){ mysqli_close($connection); } ?>Attached Files new_product.php 1.35KB 0 downloads create_product.php 1.99KB 0 downloads The code below kind of works, I don't get any errors. It has 2 problems; it only inserts the second row of data I get nothing for the first row. It also does not insert the 4id correctly I just get 1 instead of the actually user id number. I'd appreciate some help, been trying to hack this out for a couple hours. Code: [Select] <?php // Begin the script for this page $id = $_SESSION['id']; if (!isset($_POST['submit'])) { // if page is not submitted to itself echo the form } else { //Assign each array to a variable $id = $_SESSION['id']; $store = $_POST['store']; $item = $_POST['item']; $itemprice = $_POST['itemprice']; $itemnumber = $_POST['itemnumber']; $couponvalue = $_POST['couponvalue']; $limit = count($id); for($i=0;$i<$limit;$i++){ $id[$i] = $id[$i]; $store[$i] = check_input($store[$i]); $item[$i] = check_input($item[$i]); $itemprice[$i] = check_input($itemprice[$i]); $itemnumber[$i] = check_input($itemnumber[$i]); $couponvalue[$i] = check_input($couponvalue[$i]); } $query = "INSERT INTO `item` (user_id, store, item, itemprice, itemnumber, couponvalue) VALUES ('".$id[$i]."','".$store[$i]."', '".$item[$i]."', '".$itemprice[$i]."', '".$itemnumber[$i]."', '".$couponvalue[$i]."')"; if (!mysql_query($query,$link)){ die('Error: ' . mysql_error()); } else { echo "$row record added"; } } ?> <div class="pageContent"> <div id="main"> <div class="container"> <form action="" method="post"> <table> <tr> <input type="text" name="id[]" id="id[]" value="<?php echo $_SESSION['id'];?>" /> <td><DIV CLASS="p2"><center><b>Store</b></center></div> <input type="text" name="store[]" id="store[]" size="15" maxlength="255"/></td> <td><DIV CLASS="p2"><center><b>Item</b></center></div> <input type="text" name="item[]" id="item[]" size="15" maxlength="255"/></td> <td><DIV CLASS="p2"><center><b>Item Price</b></center></div> <input type="text" name="itemprice[]" id="itemprice[]" size="15" maxlength="255"/></td> <td><DIV CLASS="p2"><center><b>Item Number</b></center></div> <input type="text" name="itemnumber[]" id="itemnumber[]" size="15" maxlength="255"/></td> <td><DIV CLASS="p2"><center><b>Coupon Value</b></center></div> <input type="text" name="couponvalue[]" id="couponvalue[]" size="15" maxlength="255"/></td> </tr> <tr> <input type="text" name="id[]" id="id[]" value="<?php echo $_SESSION['id'];?>" /> <td><input type="text" name="store[]" id="store[]" size="15" maxlength="255"/></td> <td><input type="text" name="item[]" id="item[]" size="15" maxlength="255"/></td> <td><input type="text" name="itemprice[]" id="itemprice[]" size="15" maxlength="255"/></td> <td><input type="text" name="itemnumber[]" id="itemnumber[]" size="15" maxlength="255"/></td> <td><input type="text" name="couponvalue[]" id="couponvalue[]" size="15" maxlength="255"/></td> </tr> </table> <input type="submit" name="submit" value="Submit Item"> </form> </div> </div> </div> It would be GREAT if someone could provide some specific structural info for this: I have one checkbox each for Moe, Larry, and Curly respectively. I have managed to assemble code that allows for each of their names: $sql="INSERT INTO $table (first_name) VALUES... It works great INDIVIDUALLY. But I want to be able to insert any combination into the $table by checking the respective checkboxes and submitting the form. It seems that initiating more than a single INSERT will not get the job done, and separating the values as variables hasn't worked either. What is required? Can you offer an example? I have 3 tables.
1)state(s_id, details);
2)univer(u_id,details,s_id);
3)sub(su-id,daetails,u_id, s_id)
Now there is a problem, for ever selection of state and univer there is multiple choice of sub and they can be common in different selections. And how to store these values in databse and can call in a selection menu. so how can i solve it?
Edited by N0name, 31 May 2014 - 10:38 PM. Hi all I am trying to take the data from a form and add into a mySQL table. I have multiple forms on one page that uses a loop: Code: [Select] <?php $textqty = $showbasket['qty']; for ($i = 1; $i <= $textqty ; $i++) { ?> <form id="texts" name="texts" method="post" action=""> <input name="mainqty" type="hidden" value="<?php echo $textqty; ?>" /> <input name="productid" type="hidden" value="<?php echo $showbasket['productid']; ?>" /> <input name="productqtyid" type="hidden" value="<?php echo $i; ?>" /> <input name="productsize" type="hidden" value="<?php echo $showbasket['size']; ?>" /> Text: <input name="text_<?php echo $i; ?>" type="text" value="<?php echo $showtext['text']; ?>" size="35" maxlength="250" /> Colour: <select name="colour"> <?php $getcolours = mysql_query(" SELECT * FROM text_colours ORDER BY id ASC"); while($showcolours = mysql_fetch_array($getcolours)) { ?> <option value="<?php echo $showcolours['colour']; ?>"><?php echo $showcolours['colour']; ?></option> <?php } ?> </select> No. Characters: <br /> <?php } ?> <input name="update" type="submit" id="update" value="Update" /> </form> This data is then inserted into the mySQL: Code: [Select] <?php if(isset($_POST['update'])) { $mqty = $_POST['mainqty']; for ($i = 1; $i <= $mqty ; $i++) { $productid = $_POST['productid']; $productqtyid = $_POST['productqtyid']; $productsize = $_POST['productsize']; $colour = $_POST['colour']; $producttext = $_POST['text_$i']; mysql_query (" INSERT INTO emb_texts SET sessionid = '".$sessionid."', productid = '".$productid."', qtyid = '".$productqtyid."', size = '".$productsize."', colour = '".$colour."', text = '".$producttext."'") or die(mysql_error()); } } ?> This almost works but it adds the $productqtyid the same very time. I'm not sure if I am going about the the right way? Each form needs to add its own values into the mySQL. Many thanks for your help I have six rows of text boxes for users to enter into. The fields are named like ROW1: invqty, invpart, invdesc, invlist, invprice, parttotal ROW2: invqty02, invpart02, invdesc02, invlist02, invprice02, parttotal02 ROW3: ... ROW4: ... How can I add these to variables so $invoiceqty = invqty, invqty2, invqty3, etc. $invoicepart = invpart, invpart02, invpart03, etc. and then loop through them, inserting all rows into a table until all data is INSERTED Hi coders,
i have a js to add multiple input and its depend to a user how many input should he want to add. and my problem is, it work insert data in a first line of rows but the rest of rows are not save.
any idea, what should i add to make it work.
js
<script> $(document).ready(function(){ $('#add').click(function(){ var inp = $('#box'); var i = $('input').size() + 1; $('<div id="box' + i +'"><input type="text" id="name" class="name" name="code[]' + i +'" placeholder="Input '+i+'"/><img src="remove.png" width="32" height="32" border="0" align="top" class="add" id="remove" /> </div>').appendTo(inp); i++; }); $('body').on('click','#remove',function(){ $(this).parent('div').remove(); }); }); </script>html <div id="box"> <input name = "code[]" type="text" id="name" class="name" placeholder="Input 1"> <img src="add.png" width="32" height="32" border="0" align="top" class="add" id="add" /> </div>php $rf = $_POST['regform']; $b = $_POST['branch']; $d = $_POST['date']; $c = $_POST['code']; $u = $_POST['user']; for($i = 0; $i<count($c); $i++) { $a_query = mysql_query("INSERT INTO code_number(ts_number,branch_id,yy,code,username) VALUES('$rf','$b','$d','$c[$i]','$u')"); } return $a_query; The information is drawn in from a table into a form that the user will click submit and all the rows will be inputted into the table with their username association. With this form, its only inputting the last row and not all of them. You're help is much appreciated! Here is the form in the PHP area: while($row=mysql_fetch_array($get_items_sql)){ $name =$row['item']; $date = ($row['expiration_date']); $exp_date = date('M d Y', strtotime($row['expiration_date'])); $content .= ""; $content .="<table width=\"450\" border=\"0\"><tr><td width=\"200\"><span class=\"anotherfont\"><input name=\"item[]\" type=\"hidden\" value=\"$name\" id=\"item[]\">$name</span></td><td width=\"200\"><span class=\"greenfont\"><input name=\"expiration_date[]\" type=\"hidden\" value=\"$date\" id=\"expiration_date[]\">$exp_date</span><input name=\"username[]\" type=\"hidden\" value=\"$username\" id=\"username[]\"/> </td></tr><br /></table>"; $content .= "\n"; } $content .= "</ul>\n"; Then below is part of the HTML Form with $content referenced: <form action="add_select.php?source_id=<?php echo $coupon_source ?>" method="post" enctype="multipart/form-data" name="add_new" id="add_new"> <?php echo $content ?> <input name="SUBMIT" type="submit" value="submit" /></form><br /> Then here is the section from the "add_select.php" file from the form: include('connect.php'); foreach($_POST['item'] as $row=>$item) { $Item_name=$item; $expiration_date=$_POST['expiration_date'][$row]; $username=$_POST['username'][$row]; } foreach($_POST['item'] as $row=>$item) { $Item_name=mysql_real_escape_string($item); $expiration_date=mysql_real_escape_string($_POST['expiration_date'][$row]); $username=mysql_real_escape_string($_POST['username'][$row]); } $sql2="INSERT INTO place (item, expiration_date, username) VALUES ('$Item_name', '$expiration_date', '$username')"; if (!mysql_query($sql2)) { die('Error: ' . mysql_error()); }else { header("location:insert_complete.php"); } Hi Guys
I have a number of arrays that are posted from a form
They are
$home_rider
$order
$away_rider
$awayorder
for each home rider I want to to action the following query
"INSERT INTO tbl_lg_rider_order (`name`,`card_id`,`homeaway`,`riderorder`) VALUES ('$homerider',$card_id,'h','$homeorder')"
and for each away rider I want to do the following
"INSERT INTO tbl_lg_rider_order (`name`,`card_id`,`homeaway`,`riderorder`) VALUES ('$awayrider',$card_id,'a','$awayorder')"
I am using the following code
$i=0; for($i){ $homerider=$home_rider[$i]; $homeorder=$order[$i]; $homesql="INSERT INTO tbl_lg_rider_order (`name`,`card_id`,`homeaway`,`riderorder`) VALUES ('$homerider',$card_id,'h','$homeorder')"; echo $homesql; $i++; } $i=0; for($i){ $awayrider=$away_rider[$i]; $awayorder=$awayorder[$i]; $homesql="INSERT INTO tbl_lg_rider_order (`name`,`card_id`,`homeaway`,`riderorder`) VALUES ('$awayrider',$card_id,'a','$awayorder')"; echo $awaysql; $i++; }I am getting an error saying Parse error: syntax error, unexpected ')', expecting ';' Where am I going wrong? |