PHP - How To Resize Uploaded Image Size From Original To A Default Size?

I use a simple php code (taken from php.net example) to resize an image

Code: [Select]
list($width, $height) = getimagesize($filename);
$new_height = $height / $width * 400;
$image_p = imagecreatetruecolor(400, $new_height);
$image = imagecreatefromjpeg($filename);
imagecopyresampled($image_p, $image, 0, 0, 0, 0, 400, $new_height, $width, $height);
imagejpeg($image_p, "new.jpg");
Here, we create a blank image and merge it with the resized image. I wonder if it is the simplest way to resize and save an image. Is it really necessary to create a blank background image?

Is there a way I can get the .jpg file in kilobytes from a remote url and check it to make sure it does not exceed 40 kilobytes before it saves the remote url into my database?

Hey

My php function keeps returning an error on a valid image! I get this error:

Quote

could not make seekable

I use this line to get the image size but i get the above error for it:$picturearray = getimagesize($Image); 

Url being tested : Code: [Select]
http://www.fileden.com/files/2010/12/22/3043070/Sidroc.jpg
The url is correct and the image does exist - does any one know what can cause this issue ?

Hi,

I'm developing a code that uploads images. I need to verify if the image have the minimum size of 100*100 pixels before the upload. How can I do this?

Best Regards,

Sorry for my bad english.

Hey there so I'm using the below code to upload images/files to my server via ftp. The issue I've found is that anything bigger than 200KB either stalls out and partially uploads or doesn't upload at all.

I've set my php.ini file to have upload_max_filesize = 1000M and post_max_size = 1000M. And still anything bigger than 200KB won't upload right. Any help would be appreciated. I'm using php version 5.2.14 fyi. Thanks so much.


---CODE---
<?if(!isset($_POST["submit"])){?>

<!-- THE FORM ACTION IS ONTO ITSELF -->
<form action="index.php" method="POST" enctype="multipart/form-data">
<input name="userfile" type="file" size="40">
<input type="submit" name="submit" value="Upload image" />

</form>

<?
}
else
{

set_time_limit(30000);//i noticed that this had to be pretty big otherwise your upload was likely to stall out.

$paths='/yourfilepath/yourfilepath/';

$filep=$_FILES['userfile']['tmp_name'];

$ftp_server='ftp.yourdomain.com';

$ftp_user_name='your_user_name';

$ftp_user_pass='your_password';

$name=$_FILES['userfile']['name'];



$conn_id = ftp_connect($ftp_server);

$login_result = ftp_login($conn_id, $ftp_user_name, $ftp_user_pass);

if ((!$conn_id) || (!$login_result)) {
echo "FTP connection has encountered an error!";
echo "Attempted to connect to $ftp_server for user $ftp_user_name....";
exit;
} else {
echo "";
}

$upload = ftp_put($conn_id, $paths.'/'.$name, $filep, FTP_BINARY);

if (!$upload) {
echo "FTP upload has encountered an error!";
} else {
echo "Uploaded file with name $name Succsessfully ";
}

ftp_close($conn_id);   

}
?>

hello
anyone can help me to reduce image file size(reduce quality of images) using php ?

My 1st try practice uploading file to the server and it was successful.

Now I wonder how can I set a default file name to the file that will be uploaded and overwrite the existing one.

I have tried experimenting on the code but I can't get it to work.


Here's my simple code..

edit_logo.php

Code: [Select]
<?php

<form enctype="multipart/form-data" method="post"  action="uploaded_logo.php">

<input type="hidden" name="MAX_FILE_SIZE" value="100000" />

<tr>
<td>Choose a Logo to Upload: </td>
    <td><input name="uploaded_file" type="file" /></td>
</tr>

<tr>
<td>&nbsp;</td>
    <td><input type="submit" value="Upload File" name="submit>"</td>
</tr>




</form>

?>

uploaded_logo.php
Code: [Select]
<?php

if($_FILES['uploaded_file']["type"] == "image/gif")
{

$target_path = "logo/";

$target_path = $target_path. basename($_FILES['uploaded_file']['name']);



if(move_uploaded_file($_FILES['uploaded_file']['tmp_name'], $target_path))
{
echo "<span class=\"error_validation\">The Logo has been successfully changed!<br></span>";
echo "<span class=\"error_validation\">Upload Logo Again? <a href=\"edit_logo.php\">Click Here</a><br></span>";
}
else
{
echo "<span class=\"error_validation\">There was an error uploading the logo. Pls. try again.<br></span>";
echo "<span class=\"error_validation\">Upload Logo Again? <a href=\"edit_logo.php\">Click Here</a><br></span>";
}

}
else
{
echo "<span class=\"error_validation\">Invalid file format. We are only accepting image file. Pls. try again.<br></span>";
echo "<span class=\"error_validation\">Upload Logo Again? <a href=\"edit_logo.php\">Click Here</a><br></span>";
}


?>

So what the code suppose to do is.. If I upload an image file as the new logo it should have the default logo name "my_logo.gif", then it will overwrite the existing one...

Anyone?

Hi guys, with code below i can upload pictures to database, however i need to limit the file upload. I have this code done with help of php freak forum and i am  a newbie so can u help me please? thanks in advance


if (isset($_POST['register']) && $_POST['register']){
//image1
$nameone=$_FILES['myfileone']['name'];
if ($nameone)

{
$dst_filename = resize_upload_image($_FILES['myfileone'], "images/");
if ($dst_filename !== false) {
extract($dst_filename);
$image1 = mysql_query ("INSERT INTO img SET image='$img_filename', thumb='$thumb_filename', refimage='$reference'");
}
}
}
?>
<form action='' method='POST' enctype='multipart/form-data'>
<p>File:
      <input type='file' name='myfileone'>

I have some code that displays 1 large image and then 5 small ones, you click on a small one and it becomes the large one "trades places"

I then fixed the sizes so they don't distort when changing from large to small and then back.

My problem is when the image is clicked the large image size does not change, the image does

I that my issue lies here
Code: [Select]
<img name='picture' src=uploads/harkly_1.jpg ";echo imageResize($myImg1[0], $myImg1[1], 300); echo " border=0></td> but no clue on how to fix it

this part Quote

$myImg1[0], $myImg1[1

needs to change based on the selected image, can someone help me figure out how to make this happen??

Is there someway to create an if statement for this?
Code: [Select]
If (something){
echo "$myImg1[0], $myImg1[1]";
}
else {
echo "$myImg2[0], $myImg2[1]";
} 

My full code


Code: [Select]
<?php 

// to change the image size within the web page
function imageResize($width, $height, $target) {
//takes the larger size of the width and height and applies the formula accordingly...
//this is so this script will work dynamically with any size image 

if ($width > $height) {
$percentage = ($target / $width); 
} 
else { 
$percentage = ($target / $height); 
} 

//gets the new value and applies the percentage, then rounds the value 

$width = round($width * $percentage); 
$height = round($height * $percentage); 

//returns the new sizes in html image tag format...
//this is so you can plug this function inside an image tag and just get the 

return "width='$width' height='$height'"; 
} 
?>

<HEAD>
<SCRIPT LANGUAGE="JavaScript">
<!-- Original:  Ronnie T. Moore, Editor -->
<!-- Web Site:  The JavaScript Source -->

<!-- Begin
var photo_1 = new Image();
var photo_2 = new Image();
var photo_3 = new Image();

photo_1.src = "uploads/harkly_1.jpg";
photo_2.src = "uploads/harkly_2.jpg";
photo_3.src = "uploads/harkly_3.jpg";

function doButtons(picimage) {
eval("document['picture'].src = " + picimage + ".src");

}
//  End -->
</script>
</HEAD>

<?php //get the image size of the picture and load it into an array 

$photo_1="uploads/harkly_1.jpg";
$photo_2="uploads/harkly_2.jpg";
$photo_3="uploads/harkly_3.jpg";

$myImg1 = getimagesize($photo_1);
$myImg2 = getimagesize($photo_2);
$myImg3 = getimagesize($photo_3);


echo "

<BODY>
<center>
<table border=1>
<tr><td>

<p>
<li><a href = '' onmouseover = \"doButtons('photo_1')\"><img name='photo_1' src='$photo_1' ";echo imageResize($myImg1[0], $myImg1[1], 55); echo " border=0><p>

<li><a href = '' onmouseover = \"doButtons('photo_2')\"><img name='photo_2' src='$photo_2' ";echo imageResize($myImg2[0], $myImg1[1], 55); echo " border=0><p>

<li><a href = '' onmouseover = \"doButtons('photo_3')\"><img name='photo_3' src='$photo_3' ";echo imageResize($myImg3[0], $myImg1[1], 55); echo " border=0><p>

<td width=440 height=300> 
<img name='picture' src=uploads/harkly_1.jpg ";echo imageResize($myImg1[0], $myImg1[1], 300); echo " border=0></td> 

</tr>
</table>
</center>
";
?>

(1) What does this actually do? (compress it?)

$image = imagecreatefromjpeg("image.jpg");
header('Content-Type: image/jpeg');
imagejpeg($image);

By using this rather than displaying by using www.site.com/image.jpg it reduces file size of an image from 2.5mb to 0.5mb !!

(2) ImageMagick can't get these results. Am I doing something wrong? If I change the pixel size of an image in ImageMagick then I can reduce its file size, but (1) above reduces file size regardless of changing pixel size.

Hi

I have an upload script which uploads an image then resizes

The error
Code: [Select]
Fatal error: Allowed memory size of 20971520 bytes exhausted (tried to allocate 7776 bytes) in Dir/UploadScript.php on line 234

The code function


 $strNewFileName = date("YmdHis").rand(0,5000).".".$this->strFileExt;
          
          $this->strNewFileName = $strNewFileName;
          $strDir = $_SERVER['DOCUMENT_ROOT'].$this->strSaveDir.$strNewFileName;
          $strTNDir = $_SERVER['DOCUMENT_ROOT'].$this->strSaveDir."tn_".$strNewFileName;
          
          move_uploaded_file($this->arrUploadFile['tmp_name'], $strDir);
          
          $image_p = imagecreatetruecolor($this->intNewWidth, $this->intNewHeight);
          
          switch($this->strFileExt){
              case "jpg":
                $image = imagecreatefromjpeg($strDir);
                break;
              case "gif":
                $image = imagecreatefromgif($strDir);
                break;
              case "png":
                $image = imagecreatefrompng($strDir);
                break;
          }
          
          imagecopyresampled($image_p, $image, 0, 0, 0, 0, $this->intNewWidth, $this->intNewHeight, $this->intCurWidth, $this->intCurHeight);
          
          
          
          
          $blnSuccessUpload = false;
          
          switch($this->strFileExt){
              case "jpg":
                if(imagejpeg($image_p, $strTNDir)){
                    $blnSuccessUpload = true;
                }
                break;
              case "gif":
                if(imagegif($image_p, $strTNDir)){
                    $blnSuccessUpload = true;
                }
                break;
              case "png":
                if(imagepng($image_p, $strTNDir)){
                    $blnSuccessUpload = true;
                }
          }
          imagedestroy($image_p);
          return $blnSuccessUpload;


the Line causing issues (234) is
Code: [Select]
                $image = imagecreatefromjpeg($strDir);


Now that image is created but the TN is not

//Edit
Just a note.
I have ini_set('memory_limit', 16MB);
if you notice the allocated memory is less than the memory allowed.

This topic has been moved to Miscellaneous.

http://www.phpfreaks.com/forums/index.php?topic=353875.0

Hi Guys,

I have this script below which inserts the file name and path into my datebase and uploads the file into the customers folders (which is creates dynamically).

The is no error checking as I want it to be as flexible as possible but mostly(99.999%) the files I upload are JPEG and PDF's.

I would like my script to be able to resize the files above automatically to be smaller.

Please is this possible thanks!

Here is script:
<?php 
//Will create a directory once a customer is clicked and will not if page is refreshed an so forth 
 if (file_exists('customerUploads/' . $check_id . ', ' . $c_name . '')) {
 
} else {
  mkdir('customerUploads/' . $check_id . ', ' . $c_name . '');
}
?>
<?php 
//This php block of code will takecare of inserting the upload variables into the db

if(isset($_POST['submitbutton'])) {

$target_path = 'customerUploads/' . $check_id . ', ' . $c_name . '/';
$target_path = str_replace("'","",$target_path);
$target_path = $target_path . basename( $_FILES['upload']['name']);
$manager= mysql_real_escape_string($_POST['username']);
$upload =  $_FILES['upload']['name'];
$upload = str_replace("'","",$upload);
$check_id = mysql_real_escape_string($_POST['id']);
$submitbutton= mysql_real_escape_string($_POST['submitbutton']);


if($submitbutton)
{
if($manager&&$upload)
{
if (file_exists($target_path))
{
echo $_FILES["upload"]["name"] . " already exists. ";
}
else
{
move_uploaded_file($_FILES["upload"]["tmp_name"],$target_path);

echo "Stored in: " . 'customerUploads/' . $check_id . ', ' . $c_name . '/' . $_FILES["upload"]["name"];

$insert=mysql_query("INSERT INTO img_up (username,upload,id,target_path,img_date) VALUES ('$manager','$upload','$check_id','$target_path', now()) ");

// Where the file is going to be placed 
$target_path = 'customerUploads/' . $check_id . ', ' . $c_name . '/';

/* Add the original filename to our target path.  
Result is "uploads/filename.extension" */
$target_path = $target_path . basename( $_FILES['upload']['name']); 

$target_path = 'customerUploads/' . $check_id . ', ' . $c_name . '/';

$target_path = $target_path . basename( $_FILES['upload']['name']); 

if (file_exists($target_path))
{
echo $_FILES["upload"]["name"] . " already exists. ";
}
else
{
move_uploaded_file($_FILES["upload"]["tmp_name"],$target_path);
echo "Stored in: " . 'customerUploads/' . $check_id . ', ' . $c_name . '/' . $_FILES["upload"]["name"];
}


}
}
else
{
echo "There was an error uploading the file, please try again!";
}
}
 header("location: mainupload_complete.php?id=$check_id"); 
}
?>

I am working on a PHP project that will allow a user to upload a handful of images, and then submit text to go along with it.

To simplify the uploading process of a file, I restricted the type of file that can be uploaded (jpg) and the size (2.5mb). The problem is, the form is calling to a PHP script, and I have error logging built in to alert the user of why a file didn't upload, but since the PHP script is just being called, no errors are being displayed on the page. I guess unless I do a refresh of a few seconds to view any errors on the page....

What I would like to do is show a pop-up/error message notifying the user that the file type or size is incorrect and needs to be adjusted. Now part of the problem is, the file needs to be uploaded to the server first, and then everything can be checked, so I am really getting confused.

If someone can point me in the right direction on what I could use to accomplish this, it would be greatly appreciated. Thanks

-beemer