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PHP - Display Existing Results In Form
EDIT: sorry - new to posting guidelines - using XAMPP with mysql 5.1.44 (I think this is correct!!)
Newbie question he I have successfully created a form that that displays students (based on a selected lesson/group/date) with the ability to enter scores. I'm now trying to set the form up so that if data already exists then it is displayed in the form. Eg: if a member of staff choses group 7AS, lesson 1, 24/09/2010 and another member of staff has entered a score already for one student it shows up in the <select> drop down by using Code: [Select] <option>" . $scorevalue . "</option> I had this working at one point but have made a change somewhere and cannot get it working again! can anyone spot an obvious mistake I am making? The code I am using is as follows: Code: [Select] <input type="hidden" name="tutor" value="<?php echo $_GET["tutor"]; ?>" /> <input type="hidden" name="date" value="<?php echo $_GET["date"]; ?>" /> <input type="hidden" name="lesson" value="<?php echo $_GET["lesson"]; ?>" /> <?php error_reporting(-1); $con = mysql_connect("localhost","root",""); if (!$con) { die('Could not connect: ' . mysql_error()); } mysql_select_db("lakeside", $con); $result = mysql_query("SELECT students.admin, students.fname, students.surname, students.tutor FROM students WHERE tutor='$_GET[tutor]' ORDER BY students.tutor, students.surname"); echo "<table class='scores'> <tr> <th>Admin</th> <th>Firstname</th> <th>Surname</th> <th>Tutor</th> <th>Score</th> <th>Code</th> <th>Comment</th> </tr>"; while($row = mysql_fetch_array($result)) { $sqlstatement = "SELECT * FROM scores where admin = '" . $row['admin'] . "' and lesson = '" . $_GET[lesson] . "' and date = '" . $_GET[date] . "' "; $scorevalue = mysql_query($sqlstatement); echo " . $score . "; while($rowvalue = mysql_fetch_array($scorevalue)) { $score = $rowvalue['score']; $comment = $rowvalue['comment']; $code = $rowvalue['code']; } echo "<tr>"; echo "<td>" . $row['admin'] . "</td>"; echo "<td>" . $row['fname'] . "</td>"; echo "<td>" . $row['surname'] . "</td>"; echo "<td>" . $row['tutor'] . "</td>"; echo "<td><select name='score" . $row['admin'] . "' value='{$row['score']}' /> <option>" . $scorevalue . "</option> <option>0</option> <option>1</option> <option>2</option> <option>2.5</option> <option >3</option> <option>3.5</option> <option>4</option> </select> </td>"; Similar Tutorials In the code below, I am trying to produce a google-like page where the user can type keywords and pages of search results are displayed. The main difficulty I am encountering is that when the browser changes pages, it forgets everything about current data. Perhaps I should include the display of pages inside the HTML form ? How can I fix this code ? Here is the contents of my searchpage.php file :
<?php
$keywords='';
$display_search_results='';
if(isset($_POST['search_submitted'])) {
$keywords=$_POST['keywords'];
$search_results=array();
$totalNbrOfItems=20;
for($k=1;$k<=$totalNbrOfItems;$k++) {
$search_results[$k]='Your keywords '$keyowrds.' have been found in item number '.$k;
}
$nbrOfItemsParPage = 5;
$nbrOfPages = ceil($totalNbrOfItems / $nbrOfItemsParPage);
// Compute current page
$current_page = (isset($_GET['page']))?intval($_GET['page']):1;
$display_pages=($nbrOfPages<2)?'<p>Page : ':'<p>Pages : ';
for ($i = 1 ; $i <= $nbrOfPages ; $i++)
{
if ($i == $current_page) //No link to the current page
{
$display_pages=$display_pages.$i.' ';
}
else
{
$display_pages=$display_pages.'<a href="searchpage.php?'.
'page='.$i.'">'.
$i . '</a> ';
}
}
$display_pages=$display_pages.'</p>';
$display_items='';
$start=$nbrOfItemsPerPage*($current_page-1);
for($k=1;$k<=$nbrOfItemsParPage;$k++) {
$display_items=$display_items.($search_results[$start+$k]).'<br>';
}
$display_search_results=$display_pages.$display_items;
}
echo '<form method="post" action="searchpage.php">'.
' Type your keywords here : <br><br>'.
'<textarea cols="65" rows="1" '.
'id="keywords_id" name="keywords">'.$keywords.'</textarea>'.
'<input type="submit" name="search_submitted" id="search_submitted_id" value="Search" /> '.
'</fieldset>'.
'</form>';
echo $display_search_results;
?>
hi again, after I clicked a particular data to edit, it will bring me to a html which i created, UpdateRecordForm.html In there, how do i retrieve the data from database so it will show the data in the textbox that i can edit it. Code: [Select] <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> <title>adding a new data record</title> </head> <body> <form id="form1" name="form1" method="post" action="processUpdateRecord.php"> <p> <label>Student Number: <input name="StudentNumber" type="text" id="StudentNumber" size="10" /> </label> </p> <p> <label>First Name: <input name="FirstName" type="text" id="FirstName" size="20" /> </label> </p> <p> <label>Last Name: <input name="LastName" type="text" id="LastName" size="20" /> </label> </p> <p> <label>Email Address: <input name="EmailAddr" type="text" id="EmailAddr" size="50" /> </label> </p> <p> <label>Telephone: <input name="PhoneNumber" type="text" id="PhoneNumber" size="20" /> </label> </p> <p> <input type="submit" name="submit" id="submit" value="Update Record" /> </p> </form> </body> </html> Hi, I have a basic form that lets people enter details Code: [Select] <form action="welcome.php" method="post"> Name: <input type="text" name="fname" /> Second name: <input type="text" name="sname" /> <input type="submit" /> </form> And the standard insert in sql command. Im now looking to add a image uplad field the the same form. I have tried several methods off the internet but i cant get any to work. I would like the form to upload the image into the directory '../images' and then save the path to the file in the database, e.g. 'images/picture.jpg'. Can anyone point me in the right direction please. Im guessing i will have to use the file input type but i cant get any of it to work. Thanks Hi guys, I've spent quite a bit of time searching the site and have a good start - hoping for some help. I run a hockey league and have a database that keeps our stats. Regular stats page is here - http://okchockey.com/stats/stats.php I need a web form that can update existing records in the database. Maybe I am going thru this the wrong way - please let me know. I know there's a better way than my current version. Basically I have a table that has fields of Week, Jersey, Name, Goals, Assists, Points, and Penatly_Min. Again - excuse the newbie-ness - what I did is have a record for each player for each week. I already pre-created a record for each player for each week. I just need a web form that will update these existing records. I already created one that can add new records but I am having a tough time creating one to update existing ones. I'd like to be able to select the week (week 1-10) then select a player and update his stats for that particular week. Hopefully this makes sense. If anyone has some sample code I can look at I'd sure appreciate it. Really struggling trying to teach myself PHP Hi guys, I'm having problems integrating Recaptcha into an existing form. I want it all to process on the same page. I took a look on Google and found a pre-existing script which does what I want but I'm still having trouble integrating it with what I already have, form fields and the recaptcha validate seperately. Here's my script so far: before the <html> tag: Code: [Select] <?php session_start(); ?> <?php // DEMO to use reCAPTCHA library on a form // // courtesy Spectrum Nashville // http://www.spectrum-nashville.com // // provide the Public Key and Private Key for your account he define( API_PUBLIC_KEY, '6LeNt84SAAAAAAH0Et-eJpNeuYO-kRXgrpcXML36' ); define( API_PRIVATE_KEY, '6LeNt84SAAAAAMlGWZUEHqFHncRyvaYbI5YdE8BY' ); // // once the keys have been provided above, this demo should work without any further changes to the code below // // include the recaptcha library file here // require_once('recaptchalib.php'); // // the $validated variable will switch to true in the code below if a valid CAPTCHA is submitted (see code below). // do not change this. // $validated = false; ?> <?php //If the form is submitted if(isset($_POST['submit'])) { //Check to make sure that the name field is not empty if(trim($_POST['name']) == '') { $hasError = true; } else { $name = trim($_POST['name']); } //Check to make sure sure that a valid email address is submitted if(trim($_POST['email']) == '') { $hasError = true; } else if (!eregi("^[A-Z0-9._%-]+@[A-Z0-9._%-]+\.[A-Z]{2,4}$", trim($_POST['email']))) { $hasError = true; } else { $email = trim($_POST['email']); } //Check to make sure comments were entered if(trim($_POST['comment']) == '') { $hasError = true; } else { if(function_exists('stripslashes')) { $comment = stripslashes(trim($_POST['comment'])); } else { $comment = trim($_POST['comment']); } } //If there is no error, send the email if(!isset($hasError)) { $emailTo = 'eevansrange@gmail.com'; //Put your own email address here $subject = "Feedback from TEST FORM"; $body = "Name: $name \n\nEmail: $email \n\nSubject: $subject \n\nComments:\n $comment"; // $body = "Enquiry type: $enquiry \n\nName: $name \n\nEmail: $email \n\nSubject: $subject \n\nComments:\n $comments"; $headers = 'From: My Site <'.$emailTo.'>' . "\r\n" . 'Reply-To: ' . $email; mail($emailTo, $subject, $body, $headers); $emailSent = true; } } ?> Within body tag: Code: [Select] <!-- RECAPTCHA START --> <script> // example of using JavaScript variable to provide "theme" control // of the reCAPTCHA element. This entire <script> block is optional. var RecaptchaOptions = { theme : 'blackglass', tabindex : 2 }; </script> <!-- RECAPTCHA END --> <section id="form"> <h2 class="blue">CONTACT ME</h2> <div id="form-holder"> <p class="form-instructions">Need some work doing? Have a comment? Post them below and I'll get back to you asap!</p> <?php if(isset($hasError)) { //If errors are found ?> <p class="errors">Please check you've filled out the fields correctly.</p> <?php } ?> <?php if(isset($emailSent) && $emailSent == true) { //If email is sent ?> <p class="success">Thank you <strong><?php echo $name;?></strong>, your email has been sent.</p> <?php } ?> <?php // see the form below and look for the hidden input named 'validate' to see how this works. This is a nice flag to // indicate to us that the validation should be attempted. The first time a user browses to this page, there will be // no 'validate' variable in the $_POST[] array, so no validation is attempted and no error message will be generated. // // do not change any of this code. // if( $_POST['validate'] === 'yes' ) { $response = recaptcha_check_answer( API_PRIVATE_KEY, $_SERVER['REMOTE_ADDR'], $_POST['recaptcha_challenge_field'], $_POST['recaptcha_response_field'] ); if( ! $response->is_valid ) { // // captcha failed -- display the error message // // change this to whatever message you want to display. you could even perform other form validations // and display messages about other required fields, etc., here if you want. // use the CSS in the <head> section above to determine how your error message "box" will appear. // echo '<div id="recaptcha_error_box">The reCAPTCHA failed with this message: '.$response->error.'<br />Please try again.</div>'; // by default now, let the flow-of-control fall back into the <form> below so the user can try again } else { // set $validated to true so we know later in our document not to show the form again // don't change this. $validated = true; // // YOUR CODE HERE.... // // at this point, th form was submitted with valid reCAPTCHA, so go do whatever you wanted to do. // for the demo, we'll just echo back the values from the form. // // you could also send an email message, add or update database records, etc. // ?> <?php } /* end if( ! is_valid ) */ } /* end if($_POST['validate']==='yes') */ ?> <?php if( ! $validated ) { ?> <form class="cmxform" id="commentForm" method="post" border="0" action="<?php echo $_SERVER['PHP_SELF']; ?>#form"><!-- added #form so on submit the page anchors to the form div rather than taking you back to the top of the page --> <?php require_once('recaptchalib.php'); $publickey = "6LeNt84SAAAAAAH0Et-eJpNeuYO-kRXgrpcXML36"; // you got this from the signup page echo recaptcha_get_html($publickey); ?> <!--<input type="submit" />--> <br /> <label class="required" for="name" title="Enter your name"><span>Name</span><input type="text" id="name" name="name" size="50" class="required" value="<?php echo stripslashes(htmlentities($_POST['your_name'])); ?>" /></label> <label class="required" for="email" title="Enter your email"><span>Email</span><input type="text" id="email" name="email" size="50" class="required" value="<?php echo stripslashes(htmlentities($_POST['your_email'])); ?>" /></label> <label class="required" for="comment" title="Enter your comments" size="50" value="<?php echo stripslashes(htmlentities($_POST['comment'])); ?>"> <span>Comments</span><textarea name="comment" rows="5" cols="50" class="required"></textarea> </label> <!-- CAPTCHA START --> <?php echo recaptcha_get_html(API_PUBLIC_KEY); ?> <!-- CAPTCHA END --> <input type="hidden" name="validate" value="yes" /> <!--<input type="submit" value="Try It" />--> <label for="submit" class="nocontent"><input class="submit" type="submit" name="submit" value="Try It" title="Send form" />Items marked <img src="images/required-2.png" width="12" height="12" alt="required field" /> are required fields</label> <!-- need to include the name tag =submit above for the form to process and send the email --> <!-- class="nocontent" - commmented out of above label --> </form> <?php } /* end if( ! $validated ) */ ?> </div> </section> <!-- client-side validation --> <script type="text/javascript"> jQuery(function(){ // Grab each form element jQuery("label[title]").each(function(){ jQuery(this).append("<div class=\"infopop\">"); titletext = jQuery(this).attr("title"); jQuery(this).removeAttr("title"); jQuery(".infopop",this).css({opacity:0}).html(titletext); jQuery("input",this).focus(function(){ // Mouseover doFocus(this); }).blur(function(){ // MouseOut doBlur(this); }); /* ADDED TO show errors for textarea */ jQuery("textarea",this).focus(function(){ // Mouseover doFocus(this); }).blur(function(){ // MouseOut doBlur(this); }); }); }); function doFocus(obj) { jQuery(obj).addClass("active").parents("label").addClass("active").find(".infopop").animate({opacity:1,left:492},500); } function doBlur(obj) { if (validate(obj)) { isGood(obj); } } function reportErr(obj, message) { jQuery(obj).addClass("error").parents("label").removeClass("isgood").addClass("required").addClass("error").find(".infopop").html(message).addClass("errorpop").animate({opacity:1,left:492},500); } function isGood(obj) { jQuery(obj).removeClass("error").removeClass("active").parents("label").addClass("isgood").removeClass("error").removeClass("active").find(".infopop").removeClass("errorpop").animate({opacity:0,left:513},500); } function validate(obj) { mask = jQuery.extend({textfieldmask: /^[a-z\.\s-]{5,}$/i,emailmask: /^([a-z0-9\+_\-]+)(\.[a-z0-9\+_\-]+)*@([a-z0-9\-]+\.)+[a-z]{2,6}$/i,commentsboxmask: /^[a-z\.\s-]{5,}$/i}); errmsg = jQuery.extend({textfielderr:"5 or more letters",emailerr:"Invalid address",matcherr: "Must match",commenterr: "5 or more letters"}); var masktouse = null; var mustmatch = null; switch(obj.name) { case "name": masktouse="textfieldmask"; errtouse="textfielderr"; break; case "email": masktouse="emailmask"; errtouse="emailerr"; break; case "comment": masktouse="commentsboxmask"; errtouse="commenterr"; break; } // Check that the element is a required field before validating against it. if(jQuery(obj).parents("label").hasClass("required") && masktouse) { // Set up a quick way of accessing the object we're validating pointer = jQuery(obj); // Test the value of the field against the Regular Expression if (mask[masktouse].test(pointer.val())) { // The field validated successfully! // Check to see if the field needs to match another field in the form if (mustmatch) { // It does need to match, so grab the object it needs to match matchobj = jQuery("#"+mustmatch); if (matchobj.val()!='' && matchobj.val()!=pointer.val()) { // The fields don't match, so report an error on both of them reportErr(obj,errmsg["matcherr"]); reportErr(matchobj,errmsg["matcherr"]); } else { // Either the fields match, or the other field hasn't been completed yet // If the other field has been completed, call the isGood function to clear any error message showing if (matchobj.val()!='') { isGood(matchobj);} return true; } } else { // No match is required, so return true - validation passed! return true; } } else { // The field failed to validate against the Regular Expression reportErr(obj,errmsg[errtouse]); return false; } } else { // This isn't a required field, so we won't validate it against anything return true; } } </script> Any help would be much appreciated MK Hi, I'm trying to make a form that will submit a customers order into my database. The form it self is no problem and posting it to the database that part I can do, but I want this form to find existing posts in my database as the user inputs information. As an example if I add an ordrer for a customer ordering item numberr "1234" the form will search for item numberr "1234" and print it back to the form before the user submit the form, like "auto finish" the form. So in other words it will search the database "on the fly" for this item and fill it in. Could someone point me in the right direction? Somewhere in the PHP manual or maybe a good tutorial on this topic. I have made a form that asks a user for email, first name, last name, and password. I am using Spry validation tools in Dreamweaver. When I used those only, I did not have a problem. The problem began once I tried to actually check to see if the email was already registered. I have tried changing so many things like what $_POST variable to look for at the beginning, to different db connection arrangements. I am stumped. The only other thing I can think of is that I have the order wrong somehow in the logic. Thanks for the help. First, here is the form: Code: [Select] Enter Email<?php if($error_email_taken) echo ": $error_email_taken."; ?> <form name="form1" method="post" action="<?php echo $_SERVER['PHP_SELF']; ?>"> <input name="email" type="text" id="email" value="<?php if($_POST["email"]) echo $_POST["email"]; ?>"> <input name="first" type="text" id="first" value="<?php if($_POST["first"]) echo $_POST["first"]; ?>"> <input name="last" type="text" id="last" value="<?php if($_POST["last"]) echo $_POST["last"]; ?>"> <input name="pass" type="password" class="formText1" id="pass" value="<?php if($_POST["pass"]) echo $_POST["pass"]; ?>"> <input type="submit" name="Submit" value="Submit"></td> </form> And the email verification and insert, which is placed before the opening html tag. Code: [Select] <?php if($_POST['Submit']) { //Check to see if email is registered. $email = $_POST['email']; $dbc=mysqli_connect(DB_HOST, DB_USER, DB_PASSWORD, DB_NAME); $q_1 = "SELECT users_email FROM table WHERE users_email = $email"; $r_1 = mysqli_query($dbc, $q_1); $rows_1 = mysqli_num_rows($r_1); if ($rows_1 == 0) { //If 0, email is not already registered. $new_email = $_POST['email']; } else { $error_email_taken = "This email is already registered."; } //If everything is good, insert the information. if(isset($new_email)) { $first_name = $_POST['first']; $last_name = $_POST['last']; $password = $_POST['pass']; //Insert User information. $q_2 = "INSERT INTO table (users_email, users_first, users_last, users_pass) VALUES ('$new_email', '$first_name', '$last_name', '$password')"; $r_2 = mysqli_query($dbc, $q_2); //Go to new page if form was submitted and information properly inserted. header('Location: new_page.php'); }//End: if($new_email) } //End: if $_POST['submit'] ?> I've simplified it as much as I could. I totally eliminated stuff like a password hash, etc. because I wanted to get it down to the most simple form, so once this gets working, I'll add that other stuff later. Thanks so much again. I have an existing GET form that I use and want to write to a MYSQL table everytime a user uses that form. Code: [Select] <FORM ACTION="https://someurl.com" METHOD=GET> Would the easiest to be a javascript function that uses the onclick event? What would be the best way to continue to pass the user along while capturing data and writing that to a MYSQL table. Thanks! hi friends. to fetch results from the database i made a function and how i call the function on a page like $results = GetResults($someID); when i print_r the $results i get all the results, but now im confused on how do i print the rows individually? say i got Title row how will i only get the Title row from the $results VAR? Hello all, I have made the multi level marketing downline tree, but the problem with it now, it gives only the downline of one result, as the query gives 2 results what I want now is to make it give the downline of both results not just one, and it's always 2 results, not more here is my code Code: [Select] <?php $id = $_GET['id']; $result = mysql_query("SELECT id FROM users WHERE id = '".$id."' ORDER BY id"); $row = mysql_fetch_assoc($result); if ($row['id'] == 0) { echo" <table> <div id=\".piccenter\""; echo "<tr>"; echo "<img src=\"icon.gif\" border=0 align=\"center\">"; echo ""; } else { echo "<img src=\"images.png\" border=0>"; echo "<br />"; echo "'".$row['id']."'"; echo ""; echo "</div>"; } } $result2 = mysql_query("SELECT id FROM users WHERE recruiteris = '".$row['id']."'"); $rows2 = mysql_fetch_assoc($result2); foreach ($rows2 as $row2) { if ($row2['id'] == 0) { echo" <div id=\".picleft\"> <img src=\"icon.gif\" border=0 align=\"center\">"; } else { echo "<img src=\"images.png\" border=0 >"; echo "<br />"; echo "'".$row2['id']."'"; echo "</div>"; echo " <td>"; echo "</td> "; } } $result3 = mysql_query("SELECT id FROM users WHERE recruiteris = '".$rows2['id']."'"); $row3 = mysql_fetch_assoc($result3); if ($row3['id'] == 0) { echo"<div id=\".picright\"> <img src=\"icon.gif\" border=0 align=\"center\">"; } else { echo "<img src=\"images.png\" border=0>"; echo "<br />"; echo "'".$row3['id']."'"; echo ""; echo " <tr> <td>"; echo "</td> </tr> "; } $result4 = mysql_query("SELECT id FROM users WHERE recruiteris = '".$row3['id']."'"); $rows4 = mysql_fetch_assoc($result4); if ($rows4['id'] == 0) { echo"<img src=\"icon.gif\" border=0 align=\"center\">"; } else { echo "<img src=\"images.png\" border=0>"; echo "<br />"; echo "'".$rows4['id']."'"; echo ""; echo " <tr> <td>"; echo "</td> </tr> "; } $result5 = mysql_query("SELECT id FROM users WHERE recruiteris = '".$rows4['id']."'"); $rows5 = mysql_fetch_assoc($result5); if ($rows5['id'] == 0) { echo"<img src=\"icon.gif\" border=0 align=\"center\">"; } else { echo "<img src=\"images.png\" border=0>"; echo "<br />"; echo "'".$rows5['id']."'"; echo ""; echo " <tr> <td>"; echo "</td> </tr> "; } $result6 = mysql_query("SELECT id FROM users WHERE recruiteris = '".$rows5['id']."'"); $rows6 = mysql_fetch_assoc($result6); if ($rows6['id'] == 0) { echo"<img src=\"icon.gif\" border=0 align=\"center\">"; } else { echo "<img src=\"images.png\" border=0>"; echo "<br />"; echo "'".$rows6['id']."'"; echo ""; echo " <tr> <td>"; echo "</td> </tr> "; } $result7 = mysql_query("SELECT id FROM users WHERE recruiteris = '".$rows6['id']."'"); $rows7 = mysql_fetch_assoc($result7); if ($rows7['id'] == 0) { echo"<img src=\"icon.gif\" border=0 align=\"center\">"; } else { echo "<img src=\"images.png\" border=0>"; echo "<br />"; echo "'".$rows7['id']."'"; echo ""; echo " <tr> <td>"; echo "</td> </tr> "; } $result8 = mysql_query("SELECT id FROM users WHERE recruiteris = '".$rows7['id']."'"); $rows8 = mysql_fetch_assoc($result8); if ($rows8['id'] == 0) { echo"<img src=\"icon.gif\" border=0 align=\"center\">"; } else { echo "<img src=\"images.png\" border=0>"; echo "<br />"; echo "'".$rows8['id']."'"; echo ""; echo " <tr> <td>"; echo "</td> </tr> "; } $result9 = mysql_query("SELECT id FROM users WHERE recruiteris = '".$rows8['id']."'"); $rows9 = mysql_fetch_assoc($result9); if ($rows9['id'] == 0) { echo"<img src=\"icon.gif\" border=0 align=\"center\">"; } else { echo "<img src=\"images.png\" border=0>"; echo "<br />"; echo "'".$rows9['id']."'"; echo ""; echo " <tr> <td>"; echo "</td> </tr> </tbody> </table> "; } ?> Hi I have the following code: Code: [Select] $result = mysql_query("SELECT * FROM xbox_games order by gameid"); $row = mysql_fetch_assoc($result); $id = $row["gameid"]; $title = $row["gametitle"]; $cover = $row["cover"]; <?php echo $title;?> Which displays only the first result from my database. How can i change this to display all the results either as a list, or in a table? Thanks I'm new to php and been trying to follow along with different tutorials to try and build my own site, i followed a tutorial on making a search feature for the site and have it working perfectly, but i want to change the way how to search displays the results. I want to make it display them how there displayed on the index page. here is the index page how there displayed <div id="table"> <table> <tr class="top"> <th>Account</th> <th>Country</th> <th>Info</th> <th>Login</th> <th>Pass</th> <th>Price</th> <th>Buy</th> </tr> <?php $class = 'grey'; ?> <?php $items = getItems(); ?> <?php if(empty ($items)): ?> <h3>No Items Found</h3> <?php else: ?> <?php foreach($items as $item): ?> <?php $class = ($class == 'grey') ? 'grey2' : 'grey'; ?> <tr class="<?php echo $class; ?>"> <td><?php echo $item['item_account']; ?></td> <td><?php echo $item['item_country']; ?></td> <td><?php echo $item['item_info']; ?></td> <td><?php echo maskUser($item['item_login']); ?></td> <td><?php echo maskPass($item['item_pass']); ?></td> <td><?php echo $item['item_price']; ?> </td> <td><form method="post" action="https://sci.libertyreserve.com/"><input type="submit" name="buy" value="Buy" class="button" /></form></td> </tr> <?php endforeach; ?> <?php endif; ?> how the search is display if (strlen($search) <= 2) { echo 'Search keyword is too short.'; } else { echo "You searched for <b>$search</b><hr size='1'>"; $search_exploded = explode(" ", $search); foreach($search_exploded as $search_each) { $x++; if ($x == 1) $construct .= "item_account LIKE '%$search_each%'"; else $construct .= " OR item_account LIKE '%$search_each%'"; } $construct = "SELECT * FROM items WHERE $construct"; $run = mysql_query($construct); $foundnum = mysql_num_rows($run); if ($foundnum == 0) { echo 'No results found.'; } else { echo "$foundnum results found!</p>"; while ($numrows = mysql_fetch_assoc($run)) { $item_id = $numrows['item_id']; $itemAccount = $numrows['item_account']; $itemI = $numrows['item_info']; $itemLogin = $numrows['item_login']; $itemPass = $numrows['item_pass']; $itemPrice = $numrows['item_price']; echo " <b>$itemAccount</b><br /> $itemI <br /> " . maskUser($itemLogin) . '<br />' . maskPass($itemPass, 0) . '<br />'; } } } my question is im not sure how to edit the search code to display the results in the same format as the index page thanks Folks,
I managed to get this piece of code working. But I need you to check if it is buggy or in error or not. I will add VALIDATION later. Just let me know is this how you query db with mysqli_stmt_bind_result (prepared statement using procedural style) and display results on screen ? Don't worry about pagination. i will add that later. Just let me know if I got the basics correct or not to display results from db or not. That is all. Note my comments in CAPITALS. They are questions to which I need answers. conn.php
<?php
$db_server = 'localhost';
$db_user = 'root';
$db_password = '';
$db_database = 'test';
$conn = mysqli_connect("$db_server","$db_user","","$db_database");
//SHOULD I KEEP FOLLOWING 1 LINE INTACT HERE OR DUMP IT TO main file search.php ?
$conn->set_charset('utf8mb4');//Always use Charset.
//HOW TO CONVERT ABOVE LINE TPO PROCEDURAL ?
if (!$conn)
{
//HOW TO WRITE CODE SO FOLLOWING TECHNICAL ERROR IS WRITTEN TO ERROR FILE AND NOT SHOWN TO USER ?
//Error Message to show user in technical/development mode to see errors.
die("Database Error : " . mysqli_error($conn));
//Error Message to show User in Layman's mode to see errors.
die("Database error.");
exit();
}
?>
Q1. Do not forget to answer my question you see in CAPITALS in above code (conn.php). Check the search.php before replying.
error_reporting.php
<?php
ini_set('error_reporting','E_ALL');
ini_set('display_errors','1');
ini_set('display_startup_errors','1');
error_reporting(E_ALL);
//SHOULD I KEEP FOLLOWING 1 LINE INTACT HERE OR DUMP IT TO main file search.php ?
mysqli_report(MYSQLI_REPORT_ERROR|MYSQLI_REPORT_STRICT);
?>
Q2. Do not forget to answer my question you see in CAPITALS in above code (error_reporting.php). Check the search.php before replying.
search.php
<?php
//include('error_reporting.php');
error_reporting(E_ALL);
ini_set('error_reporting',E_ALL);
ini_set('display_errors','1');
ini_set('display_startup_errors','1');
?>
<form name = "search" method = "POST" action="">
<label for="keywords">Keywords:*</label>
<input type="text" name="keywords" id="keywords" placeholder="Input Keywords" required>
<br>
<button type="submit">Submit</button><br>
<button type="submit" value="submit">Submit</button><br>
<input type="submit" value="submit"><br>
<button name=submit value=" ">Search</button><br>
<button type="submit" name="submit" value="submit">Search</button>
<br>
<input type="reset">
<br>
</form>
<?php
if($_SERVER['REQUEST_METHOD'] === 'POST')
{
if(ISSET($_POST['submit']))
{
if(ISSET($_POST['keywords']))
{
$keywords = $_POST['keywords'];
}
//SHOULD I KEEP FOLLOWING 1 LINE INTACT HERE OR DUMP IT TO error_reporting.php ?
mysqli_report(MYSQLI_REPORT_ERROR|MYSQLI_REPORT_STRICT);
//SHOULD I KEEP FOLLOWING 5 LINES INTACT HERE OR DUMP IT TO conn.php ?
$conn = mysqli_connect("localhost","root","","test");
$conn->set_charset("utf8mb4");
if(mysqli_connect_error())
{
echo "Could not connect!" . mysqli_connect_error();
}
$query = "SELECT page_url,link_anchor_text,page_description,keyphrases,keywords FROM links WHERE keywords = ?";
$stmt = mysqli_stmt_init($conn);
//FIRST ATTEMPT TO DISPLAY TBL RESULTS USING mysqli_stmt_bind_result() FUNCTION. TEST RESULT: ATTEMPT A FAILURE!
if(mysqli_stmt_prepare($stmt,$query))
{
mysqli_stmt_bind_param($stmt,'s',$keywords);
$stmt_execution = mysqli_stmt_execute($stmt);
if($stmt_execution === FALSE)
{
printf("Error: %s.\n", mysqli_stmt_error($stmt));
printf("Error: %d.\n", mysqli_stmt_errno($stmt));
die;
}
$bind_result = mysqli_stmt_bind_result($stmt,$page_url,$link_anchor_text,$page_description,$keyphrase,$keywords);
if($bind_result === FALSE)
{
printf("Error: %s.\n", mysqli_stmt_error($stmt));
printf("Error: %d.\n", mysqli_stmt_errno($stmt));
die;
}
$stmt_fetch = mysqli_stmt_fetch($stmt);
if($stmt_fetch === FALSE)
{
printf("Error: %s.\n", mysqli_stmt_error($stmt));
printf("Error: %d.\n", mysqli_stmt_errno($stmt));
die;
}
while(mysqli_stmt_fetch($stmt))
{
echo "$page_url"; echo "<br>";
echo "$link_anchor_text"; echo "<br>";
echo "$page_description"; echo "<br>";
echo "$keyphrase"; echo "<br>";
echo "$keywords"; echo "<br>";
echo "|";
echo "<br>";
}
mysqli_stmt_close($stmt);
mysqli_close($conn);
}
else
{
die("QUERY failed!)";
}
Q3. Anything I should know ? Edited July 17, 2020 by 2020Hey guys so my code below is not working, it will get the app information for the user but its only display 3 results like every time a new user "installs" an new app like it stops showing the last result and starts displaying the new result. Like for example right now it should be showing 7 results but only displaying 3 is there something wrong with my query. (PS: this is just developement testing purposes so thats why my code is sorta sloppy) Thanks!
$default_apps = mysql_query("SELECT * FROM apps WHERE `default`='1'") or die(mysql_error());
$user_apps = mysql_query("SELECT * FROM user_apps WHERE `user_id`='$user_id'") or die(mysql_error());
while($row = mysql_fetch_array($default_apps))
{
$url = $row['download_url'];
$name = $row['name'];
echo $row['name'];
echo "<a href='$url'>$name</a><br />";
}
while($raw = mysql_fetch_array($user_apps)){
$app_id = $raw['app_id'];
}
$select_user_apps = mysql_query("SELECT * FROM apps WHERE `app_id`='$app_id' ");
while($rop = mysql_fetch_array($select_user_apps))
{
$name = $rop['name'];
$url = $rop['download_url'];
echo $name;
echo $url;
}
I have a program which have written with c+ +. This program is a generic server stats program for all Silkroad versions. ( Silkroad = MMORPG game like WoW ). " So if you have a website, you can upload the file via FTP to your own directory and write a simple PHP script or ASP script to parse the file and display the results. Or, you can post the data via PHP via a web URL. " I need to make this what i write that write the results. This write the following data: Code: [Select] Server Id Server Name Current Players Max Players State (1 = open, 0 = check) For example: 2 220 Zeus 354 2500 1 221 Venus 539 2500 1 And save this data to any.txt file. Here is the site: http://www.error-soft.net/forum/prvsro.php u need to se the server stats : Server Name Players State Status Total Capacity 2059 / 6000 [34%] ZSZC(Fire) 0 / 2000 Empty Offline ZSZC (Water) 2059 / 2000 Full Online ZSZC (Retro) 0 / 2000 Empty Offline i have the program what check the server and write this information to text file, but i do not know how can i parse this information like this website. Good Evening, What I am trying to do in here is to display data based on my selected option in the drop down list. I don't have submit button, I just want it to automatically display results based on my selection. Here's my code: <link href="add_client.css" rel="stylesheet" type="text/css"> <?PHP include("dbconnection.php"); //Include database connection to file $query = "SELECT * FROM records"; if(isset($_POST["territory"])) { $query .= " WHERE territory LIKE '%".$_POST["territory"]."%' ORDER BY territory ASC LIMIT 0,15" ; $result = mysql_query($query, $connection) or die(mysql_error()); } ?> <!-- Start of table --> <table width="760" border="0" align="center" cellpadding="0" cellspacing="0"> <td> <table width="760" border="0" cellpadding="0" cellspacing="0"> <!-- Table data containing the Asia Logo --> <td width="199" align="center" valign="top"> <a href="login.html"> <img src="asia.gif" alt="" width="152" height="58" border="0" /> </a> </td> <!-- Table data containing Home button --> <td width="176" align="right" valign="bottom"> <a href="main.php"> <img src="Home.jpg" width="104" height="20" border="0"/> </a> </td> <!-- Table data containing View Client button --> <td width="130" align="right" valign="bottom"> <img src="View.jpg" width="104" height="20" border="0"/> </td> <!-- Table data containing the Add Client button --> <td width="146" align="right" valign="bottom"> <a href="add_client.php"> <img src="Add.jpg" width="104" height="20" border="0"/> </a> </td> <!-- Blank table data --> <td width="109" align="right" valign="bottom"> </td> </table> <!-- Table design division and body--> <table width="760" border="0" cellpadding="0" cellspacing="0"> <td width="200" height="3" bgcolor="#1B1C78"> <img src="images/topspacerblue.gif" alt="" width="1" height="3" /></td> <td width="560" bgcolor="#0076CC"> <img src="images/topspacerlblue.gif" alt="" width="1" height="3" /></td> <tr> <td height="500" colspan="2" align="center" valign="top" bgcolor="#F3FAFE"> <!-- Page contents --> <!-- Search Query --> <br> <form name="form" action="trustlist.php" method="post"> <table width="293" border="0"> <tr> <td width="140" align="left" valign="middle"> SEARCH RECORD: </td> <td width="143" align="center" valign="middle"><select name="territory" id="territory" style="width: 143px" width="230"> <option selected="selected" disabled="disabled">Select Territory</option> <option>Territory 01</option> <option>Territory 02</option> <option>Territory 03</option> <option>Territory 04</option> <option>Territory 05</option> <option>Territory 06</option> <option>Territory 07</option> <option>Territory 08</option> <option>Territory 09</option> <option>Territory 10</option> </select></td> </tr> </table> <br> <!-- End of search query--> <!-- Start of Search Results--> <table border="0" cellpadding="3" cellspacing="1" bordercolor="38619E" > <tr> <th width="148" align="center" bgcolor="#E0E8F3">Acute Trusts</th> <th width="262" align="center" bgcolor="#E0E8F3">Employer</th> <th width="160" align="center" bgcolor="#E0E8F3">Name</th> <th width="80" align="center" valign="middle" bgcolor="#E0E8F3"> </th> </tr> <?php if($result) { for($i=0; $i<mysql_num_rows($result); $i++) { $id = trim(mysql_result($result, $i, "id")); $territory = trim(mysql_result($result, $i, "territory")); $employer = trim(mysql_result($result, $i, "employer")); $first_name = trim(mysql_result($result, $i, "first_name")); $last_name = trim(mysql_result($result, $i, "last_name")); echo "<tr>"; echo "<td>".$territory."</td>"; echo "<td>".$employer."</td>"; echo "<td>".$last_name.", ".$first_name."</td>"; echo "<td><a href='edit_client.php?id=".$id."'>edit</a> | <a href='delete_client.php?id=".$id."'>delete</a></td>"; echo "</tr>"; } } ?> </table> </form> <!-- End of page --> </td> </tr> </table> </td> <tr> <td height="38"> <table width="760" border="0" cellpadding="0" cellspacing="0"> <td width="200" height="35" align="center" bgcolor="#1B1C78" class=white> <a href="disclaimer.html"> <font color="#FFFFFF">Legal Disclaimer</font> </a> </td> <td width="560" align="center" bgcolor="#0076CC"> Copyright © 2006 - 2010 AsiaLimited. All rights reserved. </td> </table></td> </tr> </table> Hey all. I have a query that selects data from a datbase based on a criteria. Easy enough. But now I am growing and the amount displaying is too much. How can you, via php, have a queries result be displayed only so many at a time and auto create links that show the rest? Like if query returns 82 results, I want it to display 25 immediately and create 3 links at the bottom. The next link would show 26-50. The next 51-75. And the final 76-82. etc Example: Code: [Select] $result = mysql_query("SELECT * FROM pay"); $num_rows = mysql_num_rows($result); while($row = mysql_fetch_array($result)) { echo $row['first_name']; echo $row['last_name']; echo $row['item_name']; echo $row['option_selection1']; echo $row['payment_date']; echo $row['stat']; } This is simple. But what happens when the results are 125? I want to limit it to displaying 25 at a time. Is the only way to manually create seperate pages and have each one show 1-25, then 26-50, etc? Or is there a way to have the script do it, itself? Any tutorials out there on this specifically? Hopefully I am making sense. Thanks! Hello, I know this should be pretty simple to figure out, but everything I try is giving me absolutely no results. I have a mysql query selecting columns from my database and returning results. I have the results printing out right now, so I can see that this part is working. All I want to do is take the results and put them into a table to display on my page. Basically, take what's in the database table and copy it to a table I can put on the web. FYI I am using sourcerer so the "connect" code is taken care of for me in the "JFactory" bit of code. Here is the first part of my code, selecting the information from the database. {source} <?php $db = JFactory::getDbo(); $query = $db -> getQuery(true); $query -> SELECT($db -> quoteName(array('first_dept_name', 'last_name', 'dept', 'position', 'phone_num'))); $query -> FROM ($db -> quoteName('#__custom_contacts')); $query -> ORDER ('first_dept_name DESC'); $query -> WHERE ($db -> quoteName('contact_category')."=".$db -> quote('YTown Employees')); $db -> setQuery($query); $results = $db -> loadObjectList(); print_r($results); Here is where I am trying to print the results into a table. I got this code directly from a PHP book, but I am getting nothing at all returned back to me. I get table headers, but no data. <?php echo "<table><tr><th>Name</th><th>Department</th></tr>"; while ($row = mysqli_fetch_array ($result)){ echo "<tr>"; echo "<td>".$row['last_name']."</td>"; echo "<td>".$row['dept']."</td>"; echo "</tr>"; } echo "</table>"; ?> {/source} I am pulling some info from a mysql table, checking some logic, and displaying in on a page. The way this is written now it shows all of the items in a one column table, I simply want to break it up into multiple columns (ideally by specifying say 20 items per column). I know I need a counter and a loop but I'm just not sure how it all fits in with my existing program. Any help would be greatly appreciated. Here is my code Code: [Select] $result2 = mysql_query("SELECT * FROM propertyids ORDER BY propertyname ASC"); while($row2 = mysql_fetch_array($result2)){ ${'resp'.$row2['id']} = curl_multi_getcontent(${'ch'.$row2['id']}); ${'status'.$row2['id']} = strpos(${'resp'.$row2['id']},$httpvar); if(${'status'.$row2['id']} === false) { echo "<tr><td>"; echo "<img src='images/down.png'> <a href='" . $row2['primaryurl'] . "' target='_blank'>" . $row2['propertyname'] . "</a>"; echo "</td></tr>"; } else { echo "<tr><td>"; echo "<img src='images/up.png'> <a href='" . $row2['primaryurl'] . "' target='_blank'>" . $row2['propertyname'] . "</a>"; echo "</td></tr>"; } } echo "</td></table>"; Hello all. I'm using this code to go through the database and output certain user-defined numbers Code: [Select] <?php mysql_connect ("pdb1.awardspace.com", "anastasov_db","moscow1945") or die (mysql_error()); mysql_select_db ("anastasov_db"); $term = $_POST['term']; $sql = mysql_query("select * FROM countries WHERE cocode = '$term'"); while ($row = mysql_fetch_array($sql)){ echo '<br/> Code: '.$row['cocode']; echo '<br/> Country: '.$row['coname']; echo '<br/><br/>'; } ?> Now how would I go about making a page that appears if the script can't find any results in the database? Thank you in advance |
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