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PHP - Source Of Data
Not wanting to 'hijack' another thread, but curious about the error of my ways.
Why specifically (and very very clearly as I am OLD fart and totally self taught in php/mysql), why will this not suffice to determine form where POSTED data came? page 1 - form start session create and store a hashed session variable 'who_is_it' (ie hash 1Q9zFrEd) display the form submit to page 2 page 2 start session create a hashed variable $is_it-me (ie hash 1Q9zFrEd) compare $is_it_me with the session variable 'who_is_it' if the camparison == each other obtain, validate, cleanse and store data ELSE not from a vaild source Similar TutorialsHi, I'm trying to retrieve/scrape some information from a website using the class name and the tag name.
Below is the example in VB:
Dim htmL_cat As HTMLDocument
Dim objTableL_cat As Object, objDatL_cat As Object, objItemL_cat As Object, objKeyL_cat As Object
Dim intRowL_cat As Long
Set htmL_cat = New HTMLDocument
With CreateObject("MSXML2.XMLHTTP")
.Open "GET", "http://www.lelong.com.my/Auc/List/BrowseAll.asp", False
.send
htmL_cat.body.innerHTML = .responseText
End With
With htmL_cat
Set objTableL_cat = .getElementsByClassName("CatLevel1") 'Find elements with class name first
For Each objDatL_cat In objTableL_cat
Set objKeyL_cat = objDatL_cat.getElementsByTagName("a") 'Next, find elements with tag name
For Each objItemL_cat In objKeyL_cat
Sheets("Analytics").Range("E6").Offset(intRowL_cat, 0) = objItemL_cat.innerText
intRowL_cat = intRowL_cat + 1
Next
Next
End With
Set htmL_cat = Nothing
Set objTableL_cat = Nothing
Set objKeyL_cat = Nothing
How do I do the same using PHP? Thanks.
I need to pass captured data, basically, a list of email addresses that are being read from a CSV file and (1st) saved to an local database, then sent over to an external source via URL string. I have everything working except - script opens the file, read and validates all emails in the specified column, and saves to local db. ISSUE: after validating then INSERTING the data into local mySQL db, I need to then pass each piece of data to an external source via URL string. Example: www.domain.com?email={$new_email} I was initially think to just add the URL in a header function but, I'm not sure if the HEADER() function the right method to pass all of the data - during the loop - via the URL string. For example, if the CSV file contain 500 emails: Q: how can I continue that loop until the last email read, passing each up to the external source via the URL string? I'm not sure if using the HEADER() function at the end of the script - but within the loop - will interate and send each capture email via that URL string. Can anyone advise a possible solution to this? thanks Hi all, I'm new to php (and the forum) and I'm trying to figure out something I feel should be relatively easy but can't figure out. I am wanting to parse the source of multiple web pages to get a list of classes. Here is what I've kind of tried to follow, with the help of the internet: Code: [Select] $buffer = file_get_contents("http://catalog.utk.edu/content.php?catoid=5&navoid=386&cpage=1"); $regex = '/ something something /'; preg_match($regex,$buffer,$match); var_dump($match); echo $match[1]; } I'm trying to extract the course number and name from part of the source that looks like this: Code: [Select] <td width="15">  </td> <td width="100%">•  <a href="preview_course_nopop.php?catoid=1&coid=32666" onClick="showCourse('1', '32666',this, 'a:2:{s:8:~location~;s:8:~template~;s:28:~course_program_display_field~;N;}'); return false;" target="_blank">ACCT 200 - Foundations of Accounting</a> </td> </tr> Now, here's the thing, beside the fact that I can't use regex properly, I want to be able to put this into a loop for multiple courses per page of source. I am pretty fluent in c++, but this is throwing me for a serious loop (pun intended) As a side note, I want to be able to do this for multiple pages as well, the only thing that changes in the page URL is the page=# part, so would it be possible to automate it for all 33 pages? Thanks for any help. jiat Does any one have a better idea to protect PHP files so that you can distribute a 'release' without the customer being able to read the source files. There are tools on the internet which costs money, BUT your are dependant on their software and if its not open source, its not trustworthy. What I've done so far is writing an ISAPI DLL in borland cpp and installed it under iis6. Basically you call this isappi dll and it decrypts the encrypted php files and executes them respectively. It is thread safe (as is php). There are other methods available on the net that you use to encrypt your pages, BUT the decryption algorithm is found in your main php file and duh, if you can read the main file, you can easily decrypt all other files, so that is a bad idea. Any other ideas? Possibly to write a PHP extension perhaps but I have not been able to get that working on borland cpp. i am currently creating a school portal. there is this page which enables user to create their own website for Computer Education lesson. Every user are able to upload their files and view but the problem is, i need a function for the user to be able to edit it in on the page itself. Hey folks,
I'm looking for an open-source php project to contribute to. I'm not looking for a really well-known project (ex: Wordpress, Zencart)
Something small would be greatly appreciated!
So I am completely done with my forum after several posts here and a lot of time. But crap! I just realized that the way my avatar system works it will give away the password! I REALLY don't want to redo that system because truth is it is about 40 percent of the entire sites coding. It works by making pictures in a directory named the usersname.thepassword . Whatever filesystem. Now when I echo the path everyone can see the password and username in the source code! And thy can click it to see the picture! Is there a way to hide the paths or the source codeM thanks! I'd like to play music in the background of a page, but don't want to display the url of the music files in the source code or encrypt it. Is that possible to do using php? Hi Everyone, I am a noob so forgive me I tried looking this up myself But I am still confused. Basically, I am trying to use the above code to display a gallery of images from my images folder on my image site. But this free code I found below Pulls the images from the /root not a named directory where the images are stored. Would someone be kind enough to tell me how I can get the script below to pull the large images from a folder called "images" Vs the script looking for the images the root. Thanks so much in advance Code: [Select] <?php # SETTINGS $max_width = 100; $max_height = 100; function getPictureType($ext) { if ( preg_match('/jpg|jpeg/i', $ext) ) { return 'jpg'; } else if ( preg_match('/png/i', $ext) ) { return 'png'; } else if ( preg_match('/gif/i', $ext) ) { return 'gif'; } else { return ''; } } function getPictures() { global $max_width, $max_height; if ( $handle = opendir(".") ) { $lightbox = rand(); echo '<ul id="pictures">'; while ( ($file = readdir($handle)) !== false ) { if ( !is_dir($file) ) { $split = explode('.', $file); $ext = $split[count($split) - 1]; if ( ($type = getPictureType($ext)) == '' ) { continue; } if ( ! is_dir('thumbs') ) { mkdir('thumbs'); } if ( ! file_exists('thumbs/'.$file) ) { if ( $type == 'jpg' ) { $src = imagecreatefromjpeg($file); } else if ( $type == 'png' ) { $src = imagecreatefrompng($file); } else if ( $type == 'gif' ) { $src = imagecreatefromgif($file); } if ( ($oldW = imagesx($src)) < ($oldH = imagesy($src)) ) { $newW = $oldW * ($max_width / $oldH); $newH = $max_height; } else { $newW = $max_width; $newH = $oldH * ($max_height / $oldW); } $new = imagecreatetruecolor($newW, $newH); imagecopyresampled($new, $src, 0, 0, 0, 0, $newW, $newH, $oldW, $oldH); if ( $type == 'jpg' ) { imagejpeg($new, 'thumbs/'.$file); } else if ( $type == 'png' ) { imagepng($new, 'thumbs/'.$file); } else if ( $type == 'gif' ) { imagegif($new, 'thumbs/'.$file); } imagedestroy($new); imagedestroy($src); } echo '<li><a href="'.$file.'" rel="lightbox['.$lightbox.']">'; echo '<img src="thumbs/'.$file.'" alt="" />'; echo '</a></li>'; } } echo '</ul>'; } } ?> <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Strict//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-strict.dtd"> <html xmlns="http://www.w3.org/1999/xhtml" dir="ltr" lang="en-US"> <head> <meta http-equiv="Content-Type" content="text/html; charset=UFT-8" /> <title>Pictures</title> <link rel="stylesheet" href="css/lightbox.css" type="text/css" media="screen" /> <style type="text/css"> #pictures li { float:left; height:<?php echo ($max_height + 10); ?>px; list-style:none outside; width:<?php echo ($max_width + 10); ?>px; text-align:center; } img { border:0; outline:none; } </style> </head> <body> <?php getPictures(); ?> <script type="text/javascript" src="js/prototype.js"></script> <script type="text/javascript" src="js/scriptaculous.js?load=effects,builder"></script> <script type="text/javascript" src="js/lightbox.js"></script> </body> </html>
How to edit my source code so the output prints correctly ?
looking for a way to view the PHP source code of any PHP page on the web. Looking for a way to obtain PHP source code in order to help me with a certain issue. Advise. Hi I am trying to hide the image filepath and found this tutorial http://www.bounmis.com/en/PHP/How_To_Hide_Image_Source.html which I am currently using. It works but I need an additional security here so this script parses images only if the user is logged in to wordpress here's what i have so far: <?php include('wp-config.php'); $wp->init(); $wp->parse_request(); $wp->query_posts(); $wp->register_globals(); Header('Content-type: image/jpeg'); $exp=GMDate('D, d M Y H:i:s',time()+999); Header('Expires: $exp GMT'); $image_path = 'pathtoimages/'; $file=$image_path . $_GET["img"]; // getting image name and your image path if ( is_user_logged_in() ) { $file=$image_path.'authorized.jpg'; } else { $file=$image_path.'notauthorized.jpg'; }; if (file_exists($file)){ $info=getimagesize($file); $width=$info[0]; $height=$info[1]; if ($info[2]==1){ $img=@imagecreatefromgif($file); } else if ($info[2]==2){ $img=@imagecreatefromjpeg($file); } else if ($info[2]==3){ $img=@imagecreatefrompng($file); } else { $width=800; $height=600; $file = 'notauthorized.jpg'; // if there is not such image, it will show default image $img=@imagecreatefrompng($file); } ImageJpeg($img); imagedestroy($img); } ?> the script doesnt work. I think it's because i set headers Header('Content-type: image/jpeg'); What can I do to make it work? Please help thanks So I am completely done with my forum after several posts here and a lot of time. But crap! I just realized that the way my avatar system works it will give away the password! I REALLY don't want to redo that system because truth is it is about 40 percent of the entire sites coding. It works by making pictures in a directory named the usersname.thepassword . Whatever filesystem. Now when I echo the path everyone can see the password and username in the source code! And thy can click it to see the picture! Is there a way to hide the paths or the source codeM thanks! by any means is there a way to view a email.php form source? not just the html part but the entire script including the php? This is source of a page: http://vn-ace.com/forum/test.txt I want to get contents betweent <blockquote class="postcontent restore">() and </blockquote>() but i dont know how to do ? How can i do ? Please help me. I am newbie. Thanks when i right click to view page source i just saw the javascript calling php as source file , while on page there is table, i need to read that table in database , is there nay way to do that, file_get contents dont work on it its just take javascript not the page table As part of the registration procedure, my PHP application generates the mail below and presents the option to a user to click on the url in the mail to activate his account.
Please click on this link http://www.example.org.ng/activate.php?token=XeZNYf8uDVYxAY5+RBqldOosI1hm/FjB0cLnXB8R to activate your account.The activate.php script returns that their is no record of this token in the database, even though it is there. In troubleshooting, i printed the $token = $_GET["token"] in the activate.php script; and this is what i got XeZNYf8uDVYxAY5 RBqldOosI1hm/FjB0cLnXB8R. Notice that the $token variable is missing one character, (the +), which is the 16th character form the left!! Why this would happen is unclear. Any thoughts. If it helps, the is the script generating my random tokens:
function generateToken($length = 40)
{
if(function_exists('openssl_random_pseudo_bytes'))
{
$token = base64_encode(openssl_random_pseudo_bytes($length, $strong));
if($strong == TRUE)
return substr($token, 0, $length); //base64 is about 33% longer, so we need to truncate the result
}
//fallback to mt_rand if php < 5.3 or no openssl available
$characters = '0123456789';
$characters .= 'ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz^!$';
$charactersLength = strlen($characters)-1;
$token = '';
//select some random characters
for ($i = 0; $i < $length; $i++)
{
$token .= $characters[mt_rand(0, $charactersLength)];
}
return $token;
}
$token=generateToken($length = 40);
Edited by terungwa, 09 June 2014 - 05:17 PM. This topic has been moved to Miscellaneous. http://www.phpfreaks.com/forums/index.php?topic=355719.0 Currently testing a site thats almost built, am going to be including php on a sidebar on all pages so thought it'd be easier to just make all pages .php, however when i upload and try and view, in Firefox it just displays the source code on screen! It does it on other computers, but works fine in IE! ARRGGGHH Anyone have a clue? Kind Regards, Chris Hello all, i have a feeling im doing something wrong, but i have no idea what. being server-side code, php should not show when you 'view page source' in your browser (or rather it should display as html), correct ? why, then am i seeing php code when i view page source? see attached image |
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