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PHP - Fget Has White Space
I have tried to look google, but was unable to find anything.
and the search daemon is giving me errors on this site. So, when I am calling lines from a text file, I am getting a problem. to explain, I will use a # to show were this "white space" is I am getting This is the text file Code: [Select] url.com url2.com url3.com when PHP reads the file, and I output it into PHP its reading it like this Code: [Select] url1.com# url2.com# url3.com url1.com and url2.com both are getting this "white space" at the end of them, and the last entry does not. I have tried to use str_replace(" ","",$line) and str_replace("\r","",$line) but nothing. can anyone advise me as to what character this is that is being outputed. my code I'm using $f = fopen ("list.txt", "r"); while ($line= fgets ($f)) { if($url == $line){echo $line;} } fclose ($f); Similar TutorialsI'm familiar with 'trim' and even tried the following: $datanew = str_replace(array("\n", "\r", "\t", " ", "\o", "\xOB"), '', $data); but for the life of me I can't remove any white space within the source code which is messing everything else up. This is what I need: What people see.... Code: [Select] word1 word2 word3 The source... Code: [Select] word1 word2 word3 This is the current situation What people see... Code: [Select] word1 word2 word3 The source... Code: [Select] word1 word2 word3 For whatever reason, if I can strip the whitespace from the source code then I can use the content accordingly. How would do you strip the white space? Does this even make sense? Hello, I have the following code writting IP,session, and date to a text file (it works) but I want to add a white space after the IP address. fwrite($fp, $_SERVER['REMOTE_ADDR']. $_SESSION["sess_name"]. " $dateTime\r\n"); At the moment it prints like this 16.17.51.41SESSION_ID 2011/01/23 12:53:32 thanks in advance. I have a form on my website with a text area input field. I am looking for a php function that can strip the formating from the Text and take out line breaks and paragraphs so that when i retrieve the information from database i can change it from this _____________________________________ FANTASTIC BARGAINS ALL SPRING / SUMMMER 2010 ...... STOCK NOW REDUCED to this FANTASTIC BARGAINS ALL SPRING / SUMMMER 2010...... STOCK NOW REDUCED does anyone know what fucntion i could use for this? i have this so far but it doesnt seem to be working $descr = ''; if(strlen($row['description']) > DESCR_LIMIT) { $descr = (substr($row['description'], 0, DESCR_LIMIT).'...'); } else { $descr = $row['description']; } $descr = preg_replace("/(\r\n)+/", " ", $descr); $descr = preg_replace("/ +/", " ", $descr); $status .= $descr; I have a table with postcodes in it. At some point some of the codes will be entered with spaces (LA12 5TH) and some without (LA17HU) what i need is a function to check if there is a space, if not - count back 3 characters from the end of the string and insert a space. I don't know which string function to use - looked at pad but that seems to be for either end of string and not the middle - any ideas? Hello.
The first page works, but when form actioning to the next i just get a white screen.
This is the white screen page:
<?php session_start(); include 'details.php'; $username = $_POST['username']; $password = $_POST['password']; $pwswdrd = md5($password); if(!empty($_POST['username'])) { $query = mysqli_query($con, "SELECT * FROM users where name = '$username' AND pass = '$pwswdrd'") or die(mysqli_connect_error()); $row = mysqli_fetch_array($query); if(!empty($row['name']) AND !empty($row['pass'])) { $_SESSION['username'] = $row['username']; $_SESSION['id'] = $row['id']; header('Location: index.php'); } } else { echo "You failed to log in."; } ?> - details.php <?php $one=mysqli_connect('.......webhost.com','aee','aaa') or die("Failed to connect to MySQL: " . mysqli_error() ); $db=mysqli_select_db($one,'aee') or die("Failed to connect to MySQL: " . mysqli_error() ); ?> -- What can possibly be wrong?! hello, here is what i have. i feel like im close. Code: [Select] $result4 = mysql_query("SELECT * FROM schedule WHERE eid = '$posteid' AND status = 1 OR 2"); Okay, I can't seem to figure out why the form isn't pulling up. Here's what I'm trying to do. Administrator clicks on Add New Item to Inventory, pulling up the shops that are available to add inventory to. (This part appears to be working, because it does list those shops available). Then, the administrator will click on a shop name, opening up a form that will allow them to type in the name of the item they want to add. Instead, it goes to a blank screen, no errors even with error reporting on. adminpanel.php is the main file that houses all these functions. If you're familiar with EZRPG, it's the same basic setup, just with these additions to the list. Any help would be greatly appreciated! Thank you!! function addinv() { $query = doquery("SELECT id,name FROM shop ORDER BY name", "shop"); $page = "<b><u>Add Inventory</u></b><br />Click to add an item to a shop's inventory.<br /><br /><table width=\"50%\">\n"; $count = 1; while ($row = mysql_fetch_array($query)) { if ($count == 1) { $page .= "<tr><td width=\"8%\" style=\"background-color: #eeeeee;\">".$row["id"]."</td><td style=\"background-color: #eeeeee;\"><a href=\"admin_panel.php?do=addshopinv:".$row["id"]."\">".$row["name"]."</a></td></tr>\n"; $count = 2; } else { $page .= "<tr><td width=\"8%\" style=\"background-color: #ffffff;\">".$row["id"]."</td><td style=\"background-color: #ffffff;\"><a href=\"admin_panel.php?do=addshopinv:".$row["id"]."\">".$row["name"]."</a></td></tr>\n"; $count = 1; } } if (mysql_num_rows($query) == 0) { $page .= "<tr><td width=\"8%\" style=\"background-color: #eeeeee;\">No items found.</td></tr>\n"; } $page .= "</table>"; admindisplay($page, "Add Shop Inventory"); } function addshopinv($name) { if (isset($_POST["submit"])) { extract($_POST); $errors = 0; $errorlist = ""; if ($name == "") { $errors++; $errorlist .= "Name is required.<br />"; } else if ($errors == 0) { $query1 = doquery("SELECT * FROM items WHERE name=$name"); $item_id = mysql_fetch_array($query1); $query = doquery("INSERT INTO `sale` SET shop_id=".$row["id"].", item_id='$item_id',"); admindisplay("Inventory Item Added.","Add New Inventory Item"); } else { admindisplay("<b>Errors:</b><br /><div style=\"color:red;\">$errorlist</div><br />Please go back and try again.", "Add New Item to Shop"); } } $name = $page = <<<END <b><u>Add New Inventory Item</u></b><br /><br /> <form action="admin_panel.php?do=addshopinv:$name" method="post"> <table width="90%"> <tr><td width="20%">Name:</td><td><input type="text" name="name" size="30" maxlength="255" value="" />*255 character max</td></tr> </table> <input type="submit" name="submit" value="Submit" /> <input type="reset" name="reset" value="Reset" /> </form> END; $page = parsetemplate($page, $row); admindisplay($page, "Add New Inventory Item"); } Hi all, can anyone see why my function is not running? im not getting the form output now. Code: [Select] <?php /* NEW.PHP Allows user to create a new entry in the database */ // creates the new record form // since this form is used multiple times in this file, I have made it a function that is easily reusable function renderForm($Name, $Rank, $error) { ?> <!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01//EN" "http://www.w3.org/TR/html4/strict.dtd"> <html> <head> <title>New Record</title> <link rel="stylesheet" href="style.css" type="text/css" /> </head> <body> <div id="wrapper"> <p> <?php // if there are any errors, display them if ($error != '') { echo '<div style="padding:4px; border:1px solid red; color:red;">'.$error.'</div>'; } ?> </p> <p> </p> <form action="" method="post"> <div> <table width="842" border="0" class="styletable" style="border: 1px solid #000000"> <tr> <td width="255"><strong>Name: *</strong></td> <td width="577"><input type="text" name="Name" value="<?php echo $Name; ?>" /></td> </tr> <tr> <td><strong>Rank:</strong></td> <td><input type="text" name="Rank" value="<?php echo $Rank; ?>" /></td> </tr> <tr> <td><strong>Contact Email: *</strong></td> <td><input type="text" name="ContactEmail" value="<?php echo $ContactEmail; ?>" /></td> </tr> <tr> <td><strong>Website: (omitting http://)</strong></td> <td><input type="text" name="Website" value="<?php echo $Website; ?>" /></td> </tr> <tr> <td><strong>Location:</strong></td> <td><select name="Location" id="Location"> <option value="East Midlands">East Midlands</option> <option value="East Of England">East Of England</option> <option value="Greater London">Greater London</option> <option value="North East England">North East England</option> <option value="North West England">North West England</option> <option value="South East England">South East England</option> <option value="South West England">Soth West England</option> <option value="West Midlands">West Midlands</option> <option value="Yorkshire And The Humber">Yorkshire And The Humber</option> </select> </td> </tr> <tr> <td><strong>Bio:</strong></td> <td><textarea name="BIO" id="BIO" cols="60" rows="5"></textarea></td> </tr> <tr> <td> </td> <td> </td> </tr> </table> <p>* required</p> <input type="submit" name="submit" value="Submit"> <a href="view.php">Cancel - View Records</a> </div> </form> </div> </body> </html> <?php } // connect to the database include('../connect-db.php'); // check if the form has been submitted. If it has, start to process the form and save it to the database if (isset($_POST['submit'])) { // get form data, making sure it is valid $Name = mysql_real_escape_string(htmlspecialchars($_POST['Name'])); $Rank = mysql_real_escape_string(htmlspecialchars($_POST['Rank'])); $ContactEmail = mysql_real_escape_string(htmlspecialchars($_POST['ContactEmail'])); $Website = mysql_real_escape_string(htmlspecialchars($_POST['Website'])); $Location = mysql_real_escape_string(htmlspecialchars($_POST['Location'])); $BIO = mysql_real_escape_string(htmlspecialchars($_POST['BIO'])); // check to make sure both fields are entered if ($Name == '' || $ContactEmail == '') { // generate error message $error = 'ERROR: Please fill in all required fields!'; // if either field is blank, display the form again renderForm($Name, $Rank, $error); } else { // save the data to the database mysql_query("INSERT members SET Name='$Name', Rank='$Rank',ContactEmail='$ContactEmail', Website='$Website', Location='$Location', BIO='$BIO'") or die(mysql_error()); // once saved, redirect back to the view page header("Location: view.php"); // if the form hasn't been submitted, display the form } renderForm('','',''); } ?> Hello! Incredibly new to PHP, so if this problem is a clear error i apologise. I am developing a page which will display a product based on what is clicked as a result of a search, my problem is that no matter that happens I cannot display anything from the Products table in my database: Code: [Select] <?php session_start(); include "connect.php"; $prodsql="SELECT product_ID, product_Name, Category, Price, Information from Product ;"; $prodresult = mysqli_query($_SESSION['conn'], $prodsql); while ($prow = mysql_fetch_array($prodresult, MYSQL_NUM)) { echo "<p> $prow['product_Name']"; } else{ } What am i missing? The connect.php works as I can successfully login and register members. Thank you So I'm new to PHP GD, I cant understand why the PNG image will not go transparent, it's just showing a white background.
Could anyone help me out with this?
Spoiler Code: [Select] Address: 351 Hougang Ave 3 (769057) Contact No: 6752 5513 Operating Hours: 8.00am - 9.30pm (Thursday to Tuesday & Public Holidays) Background: Opened to the public on 30 Mar 88 Hi good day, if I paste the above address into one of the mysql field, I found out that I cannot fetch it using php. It give me a blank page. Code: [Select] Address: 351 Hougang Ave 3 (769057) Contact No: 6752 5513 Operating Hours: 8.00am - 9.30pm (Thursday to Tuesday & Public Holidays) Background: Opened to the public on 30 Mar 88 When I sort it together then i can see mysql working, very strange.. Can anyone help? I made my website on my laptop (localserver) and it was working fine. But when I uploaded to my hosting account and tried to view it in my browser, all I get is a blank white screen. No errors, no messages. Just blank screen. I tried different hosts ... same problem ... but the website runs fine on my localhost. what could be the problem ??? I even contacted me hosting company and they told me that PHP server is running fine. Keep going over this and can't find the stupid error. Need some fresh eyes for some help. Thanks Code: [Select] <?php ob_start(); session_start(); include("include/db_connect.php"); // Define $username and $password $username = $_REQUEST['username']; $password = $_REQUEST['password']; // To protect MySQL injection $username = stripslashes($username); $password = stripslashes($password); $username = mysql_real_escape_string($username); $password = mysql_real_escape_string($password); $sql="SELECT * FROM login WHERE username = '$username' AND password = '$password'"; $result=mysql_query($sql) or die(mysql_error()); $row = mysql_fetch_array($result); // Mysql_num_row is counting table row $count=mysql_num_rows($result); // If result matched, table row must be 1 row if($count!=0) { // Register session variables and redirect to file "dashboard.php" $_SESSION['id'] = $row['id']; $_SESSION['franchise_id'] = $row['franchise_id']; $_SESSION['dealer_id'] = $row['dealer_id]'; $_SESSION['first'] = $row['first']; $_SESSION['last'] = $row['last']; header("location:dashboard.php"); } else { header("location:not_logged_in.php"); } ob_end_flush(); ?> Hi all.
i am trying to use php to include a javascript onto different pages, and then "sort of " pass it a var.
The bulk of the code will be in an included footer php file.
The var will be set in the main page.
i have it working as follows: by just using echo 3 times.. the 1st with the first part of the script, the 2nd is the variable, and the 3rd is the rest of the script.
The same endcode.php file needs to also be used for pages that wont have a var set, and wont be using the script - hense the isset.
<!-- mainPage.php -->
<?php $sion_gallery_id = '450'; ?>
<?php include(endcode.php); ?>
<!-- endcode.php -->
<?php if (isset($sion_gallery_id))
{echo "start of javascript.......album/"; echo $sion_gallery_id; echo"/end of script"; }
else { echo "var not on set";} ?>
Guys: What is the way to remove white spaces in front of a form entry ? Should I use regular expression for this ? Thanks. Hi im having trouble with uploading images with spaces in as they dont show up in the browser. Here is the code: Code: [Select] $image = addslashes($_FILES['image']['name']); $target = "images/"; $target = $target . basename( $_FILES['image']['name']); //Writes the photo to the server if(move_uploaded_file($_FILES['image']['tmp_name'], $target)) { Any help would be appreciated. Hello,
I am having some troubles and was hoping someone could guide me through it.
Q: When ever I try call my get_status function all I get is a white page of nothing, no errors to work from etc... Can anyone here see what I am doing wrong?
PATH: index.php
NOTICE //<<-- KILLS PAGE
<?php
spl_autoload_register(function ($class) {
include '/lib/' . $class . '.inc';
});
$servers = new servers;
echo $servers->get_servers();
echo "STATUS: ".$servers->get_status("0.0.0.0",80); //<<-- KILLS PAGE
?>
Page works fine until I want to use the status function, I get no errors or anything just a blank page.
PATH: Lib/Servers.inc
NOTICE //<<-- KILLS PAGE
<?php
ini_set('display_errors',1);
ini_set('display_startup_errors',1);
error_reporting(E_ALL);
error_reporting(-1);
include_once '../../Global-Includes/ServerStatus/db-connect.php';
//namespace xStatus;
class servers {
private $db_Hostname = HOSTNAME;
private $db_Username = USERNAME;
private $db_Password = PASSWORD;
private $db_Database = DATABASE;
private $dbSQL = '';
function __construct() {
} // End Construct
public function get_servers(){
$db = new mysqli($this->db_Hostname,$this->db_Username,$this->db_Password,$this->db_Database);
$message = '';
// list current servers from database
$sql = "SELECT * FROM tbl_servers";
$res = $db->query($sql);
if ($res->num_rows > 0) {
$message = '<h3>Current Servers</h3>';
while ($row = $res->fetch_assoc()) {
$message .= $row['HostGame'] . '<br>';
$message .= $row['HostIP'] . '<br>';
$message .= $row['HostPort'] . '<br>';
$message .= $this->get_status($row['HostIP'],$row['HostPort']) . '<br>'; //<<-- KILLS PAGE!
}
}
$message .= "<br>End of the \"Server List\" ";
return $message;
}
public function get_status(&$ServerIP,&$ServerPort){
if(@stream_socket_client("tcp://".$this.$ServerIP.":".$this.$ServerPort."", $errno, $errstr, 1) !== false) {
return "Online";
} else {
return "Offline";
}
return "Offline";
}
} // End class
?>
Kind regards and thank you.
Ok, this is rather bizarre. First this code... if($postCount > 0) { $i = 0; while($row = $this->db->fetch_assoc($post_pagination->resource())) { // echo $row['post_message']; $content .= ($i % 2 == 0 ? '<tr class="odd">' : '<tr>'); $content .= '<table>'; $content .= '<tr><td>'.$row['username'].'</td></tr>'; $content .= '<tr>'; $content .= '<td><p>'.$row['post_message'].'</p></td>'; $content .= '</tr>'; $content .= '</table>'; $content .= '</tr>'; $i++; } $content .= '<tr><td>| '.$plinks.' |</td></tr>'; } For whatever reason, if I comment out the line with $row['post_message'] everything works as expected. If I leave that in there like it is now, I get a completely blank white page. I've also tried assigning it to a variable within the loop like... $post_message = $row['post_message']; and that works fine, until I try echo'ing it then the same blank white page result. I've double checked the query, both in PHP and in PHPMyAdmin and it is working correctly. Here's the query code: $post_pagination = new pagination($ppg, "SELECT `posts`.`post_id`, `posts`.`post_message`, `cg_accounts`.`id`, `cg_accounts`.`username` FROM `".$this->dbname."`.`threads`, `".$this->dbname."`.`posts` INNER JOIN `crikeyga_central`.`cg_accounts` ON (`cg_accounts`.`id` = `posts`.`userid`) WHERE `posts`.`thread_id`=`threads`.`thread_id` AND `posts`.`thread_id`='".$thread_id."' ORDER BY `posts`.`post_timestamp` ASC"); I've also double checked the pagination class is working as expected, and it's fine in every other page it's used in. Also $ppg is the correct value(simply holds the current page number). $this->dbname is also correct, and as mentioned above the query works in PHPMyAdmin. And $post_pagination->resource() is holding the correct value and I've checked the database class in particular $this->db->fetch_assoc() and that's working fine. Really not having much luck pinning this one down, no errors are coming up(error reporting(E_ALL)). seems strange to me that $row['username'] comes up fine, but $row['post_message'] results in a white page. The values are also what they should be. Any help is appreciated! Thanks, Ace I'm trying to convert a grayscale image to pure black and white in php using the GD library. The purpose would be to detect the cervical cells within the image. I'll leave the php code and a matlab one (i wrote this code in matlab and i'm trying to obtain the same result in php). Basically, im having troubles accessing each individual pixel's color and modifying it. MATLAB:
clear all, clc, close all;
I = imread('celule.jpg');
imshow(I)
title('original');
a=rgb2gray(I);
figure;
imshow(a)
title('grayscale');
s=size(a);
for i=1:s(1)
for j=1:s(2)
if a(i,j)>190
a(i,j)=0;
else a(i,j)=255;
end
end
end
figure;
imshow(a)
title('pure black and white');
PHP:
<?php
$im = imagecreatefromjpeg("celule.jpg");
function imagetograyscale($im)
{
if (imageistruecolor($im)) {
imagetruecolortopalette($im, false, 256);
}
for ($c = 0; $c < imagecolorstotal($im); $c++) {
$col = imagecolorsforindex($im, $c);
$gray = round(0.299 * $col['red'] + 0.587 * $col['green'] + 0.114 * $col['blue']);
imagecolorset($im, $c, $gray, $gray, $gray);
}
}
imagetograyscale($im);
//imagefilter($im, IMG_FILTER_CONTRAST, -255); //i'm not looking for this effect
header('Content-type: image/jpeg');
imagejpeg($im);
$C = imagesx($im); //width
$L = imagesy($im); //height
echo "Dimensiuni imagine: latime $C, inaltime $L <br>";
//scanning through the image
for($x = 0; $x < $L; $x++) { //each line
for($y = 0; $y < $C; $y++) { //each collumn
// pixel color at (x, y)
$color = imagecolorat($im, $y, $x);
$color = imagecolorsforindex($im, $color); //getting rgb values
$RED[$x][$y] = $color["red"]; //each rgb component
$GREEN[$x][$y] = $color["green"];
$BLUE[$x][$y] = $color["blue"];
}
}
?>
image "celule.jpg": https://i.ibb.co/6Ffj6sc/celule.jpg Hello everyone, When I submit my login form to go to my login page it goes to a white page and does not display an error. Code: [Select] <?php include("../secure/database.php"); if(!empty($_POST['loginsubmit'])){ if(!empty($_POST['email'])){ $email = securevar($_POST['email']); if(!empty($_POST['passconf'])){ $pass = securevar($_POST['passconf']); $q = "SELECT * FROM `accountinfo_db` WHERE `email` = '$email' AND `password` = '$pass'"; $res = mysql_query($q) or die(mysql_error()); $login = mysql_fetch_array($res); $id = $login['id']; $active = $login['active']; if($id>=1){ if($active==1){ $_SESSION['logged'] = $login['id']; $q = "UPDATE `accountinfo_db` SET `loggedtimes` = `loggedtimes`+'1' WHERE `id` = '$id'"; $res = mysql_query($q) or die(mysql_error()); $user = $login['username']; header("Location: ../mainframe.php?strmsg=Welcome Back $user"); }else{ header("Location: activate.php"); } }else{ header("Location: ../index.php?strmsg=Login Information Incorrect!"); } }else{ header("Location: ../index.php?strmsg=You did not enter a valid password!"); } }else{ header("Location: ../index.php?strmsg=You did not enter a valid email!"); } }else{ header("Location: ../index.php?strmsg=We are sorry but you are not allowed viewance of that directory!"); } ?> any help would be great. Brian |
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