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PHP - Menu Depending On Login
Alright, so meanwhile i wait for answer on the other thread i started another project, to fix the menu... but it was a bit confusing so now i ask you again!...
Heres my current menu.php Code: [Select] <?php include "config.php"; if (!$_SESSION["valid_user"]) { echo '<a href="login.php">' . 'Login <br/><br/>' . '</a>'; } if ($_SESSION["valid_user"]) { echo '<a href="logout.php">' . 'Logout <br/><br/>' . '</a>'; echo '<a href="members.php">' . 'Control Panel <br/><br/>' . '</a>'; } echo '<a href="memberlist.php">' . 'Members <br/><br/>' . '</a>'; echo '<a href="ranking.php">' . 'Rankings <br/><br/>' . '</a>'; ?> Now it works perfectly when logged in, but when you logout the session dies, leaving me with this: Notice: Undefined index: valid_user in C:\wamp\www\kawaii\menu.php on line 5 Login Notice: Undefined index: valid_user in C:\wamp\www\kawaii\menu.php on line 10 Members Rankings Now, how can i make a login that depends on if your logged in if this happens when you logout..., i hope someone can find a solution that can work out Similar TutorialsHi, Im not sure whether this is a PHP or MySQL question, but im trying to get a select menu to only display the number of options that are defined in the mysql database.
For example
The code I have that retrieves the $quantity from the database.
Lets say that
$quantity = 3
Now I would like the option menu to only display three options, like this:
<select name="quantity"> <option value="<?php echo $quantity ?>"><?php echo 'Maximum of ' . $quantity . ' available'?></option> <option value="1">1</option> <option value="2">2</option> <option value="3">3</option> </select>but for example, if the $quantity was equal to 10 then I would like the menu to be displayed as such <select name="quantity"> <option value="<?php echo $quantity ?>"><?php echo 'Maximum of ' . $quantity . ' available'?></option> <option value="1">1</option> <option value="2">2</option> <option value="3">3</option> <option value="4">4</option> <option value="5">5</option> <option value="6">6</option> <option value="7">7</option> <option value="8">8</option> <option value="9">9</option> <option value="10">10</option> </select>How is it possible to do this? I am completely at a loss here. Many Thanks aquaman Hello all Ok here is the problem... I want when a user inputs the requested data to the text fields , the script to insert those data in the prope table depending on the choise the user does by choosing one option from the drop down menu. Below is the php code (apparently not working) $editFormAction = $_SERVER['PHP_SELF']; if (isset($_SERVER['QUERY_STRING'])) { $editFormAction .= "?" . htmlentities($_SERVER['QUERY_STRING']); } $site_type = $_REQUEST['category_selection']; if ((isset($_POST["MM_insert"])) && ($_POST["MM_insert"] == "link_submission") && ($site_type = "Web_Sites")) { $insertSQL = sprintf("INSERT INTO partner_sites (url, url_title, anchor_text, `description`, webmaster_name, webmaster_email, category) VALUES (%s, %s, %s, %s, %s, %s, %s)", GetSQLValueString($_POST['url_field'], "text"), GetSQLValueString($_POST['title_field'], "text"), GetSQLValueString($_POST['anchor_field'], "text"), GetSQLValueString($_POST['description_field'], "text"), GetSQLValueString($_POST['webmaster_nane_field'], "text"), GetSQLValueString($_POST['webmaster_email_field'], "text"), GetSQLValueString($_POST['category_selection'], "text")); mysql_select_db($database_content_conn, $content_conn); $Result1 = mysql_query($insertSQL, $content_conn) or die(mysql_error()); } if ((isset($_POST["MM_insert"])) && ($_POST["MM_insert"] == "link_submission") && ($site_type = "Blogs")) { $insertSQL = sprintf("INSERT INTO partner_blogs (url, url_title, anchor_text, `description`, webmaster_name, webmaster_email, category) VALUES (%s, %s, %s, %s, %s, %s, %s)", GetSQLValueString($_POST['url_field'], "text"), GetSQLValueString($_POST['title_field'], "text"), GetSQLValueString($_POST['anchor_field'], "text"), GetSQLValueString($_POST['description_field'], "text"), GetSQLValueString($_POST['webmaster_nane_field'], "text"), GetSQLValueString($_POST['webmaster_email_field'], "text"), GetSQLValueString($_POST['category_selection'], "text")); mysql_select_db($database_content_conn, $content_conn); $Result1 = mysql_query($insertSQL, $content_conn) or die(mysql_error()); } if ((isset($_POST["MM_insert"])) && ($_POST["MM_insert"] == "link_submission") && ($site_type = "Directories")) { $insertSQL = sprintf("INSERT INTO partner_directories (url, url_title, anchor_text, `description`, webmaster_name, webmaster_email, category) VALUES (%s, %s, %s, %s, %s, %s, %s)", GetSQLValueString($_POST['url_field'], "text"), GetSQLValueString($_POST['title_field'], "text"), GetSQLValueString($_POST['anchor_field'], "text"), GetSQLValueString($_POST['description_field'], "text"), GetSQLValueString($_POST['webmaster_nane_field'], "text"), GetSQLValueString($_POST['webmaster_email_field'], "text"), GetSQLValueString($_POST['category_selection'], "text")); mysql_select_db($database_content_conn, $content_conn); $Result1 = mysql_query($insertSQL, $content_conn) or die(mysql_error()); } And the html form <form action="<?php echo $editFormAction; ?>" method="POST" enctype="multipart/form-data" name="link_submission" id="link_submission"> <table width="630" border="0" align="center" cellpadding="5" cellspacing="5"> <tr> <td width="76">URL:*</td> <td width="519"><label for="url_field"></label> <span id="sprytextfield1"> <label for="url_field"></label> <input name="url_field" type="text" id="url_field" size="50" /> <span class="textfieldRequiredMsg">A value is required.</span><span class="textfieldInvalidFormatMsg">Invalid format.</span></span></td> </tr> <tr> <td>Anchor Text:*</td> <td><label for="anchor_field"><span id="sprytextfield2"> <input type="text" name="anchor_field" id="anchor_field" /> <span class="textfieldRequiredMsg">A value is required.</span></span></label></td> </tr> <tr> <td>URL Title:*</td> <td><label for="title_field"><span id="sprytextfield3"> <input type="text" name="title_field" id="title_field" /> <span class="textfieldRequiredMsg">A value is required.</span></span></label></td> </tr> <tr> <td>Description:*</td> <td><span id="sprytextarea1"> <label for="description_field"></label> <textarea name="description_field" id="description_field" cols="45" rows="3"></textarea> <span id="countsprytextarea1"> </span><span class="textareaRequiredMsg">A value is required.</span><span class="textareaMaxCharsMsg">Exceeded maximum number of characters.</span></span></td> </tr> <tr> <td>Webmaster Name:*</td> <td><label for="textfield2"><span id="sprytextfield4"> <input type="text" name="webmaster_nane_field" id="webmaster_nane_field" /> <span class="textfieldRequiredMsg">A value is required.</span></span></label></td> </tr> <tr> <td>Webmaster E-mail:*</td> <td><label for="textfield3"><span id="sprytextfield5"> <input name="webmaster_email_field" type="text" id="webmaster_email_field" size="40" /> <span class="textfieldRequiredMsg">A value is required.</span><span class="textfieldInvalidFormatMsg">Invalid format.</span></span></label></td> </tr> <tr> <td>Category:*</td> <td><span id="spryselect1"> <label for="category_selection"></label> <select name="category_selection" id="category_selection"> <option>Select An Option</option> <option value="Web_Sites">Web Sites</option> <option value="Blogs">Blogs</option> <option value="Directories">Directories</option> </select> <span class="selectRequiredMsg">Please select an item.</span></span></td> </tr> <tr> <td> </td> <td><label for="select"></label> <input type="submit" name="button" id="button" value="Url Submission" /></td> </tr> </table> <input type="hidden" name="MM_insert" value="link_submission" /> </form> Im begging for your help..... I am trying to create a login menu, but I keep getting the same errors. My code does not have any errors. However, when I test it, all it says is "you have entered an incorrect username and password. But I can't even see the username and password text boxes to enter a username or password. hi i need help an idea how can i separate members from admins since i dont know how to create login form i used tutorial ( http://www.youtube.com/watch?v=4oSCuEtxRK8 ) (its session login form only that i made it work other tutorials wre too old or something) how what i want to do is separate members and admins because admin need more rights to do now i have idea but dont know will it work like that what i want to do is create additional row in table named it flag and create 0 (inactive user) 1 (member) 2 (admin) will that work? and how can i create different navigation bars for users and admins? do you recommend that i use different folders to create it or just script based on session and flag? Hello guys, Is there on web any updated tutorial on how can I add Facebook login on my simple php login script? Hi guys, Can anyone assist me. I am trying to create a login for admin and user (if user not a member click register link) below is my code: But whenever I enter the value as: Username: admin Password:123 - I got an error message "That user does not exist!" Any suggestion and help would be appreciated. Thanks. login.php <?php //Assigned varibale $error_msg as empty //$error_msg = ""; session_start(); $error_msg = ""; if (isset($_POST['submit'])) { if ($a_username = "admin" && $a_password = "123") { //Define $_POST from form text feilds $username = $_POST['username']; $password = $_POST['password']; //Add some stripslashes $username = stripslashes($username); $password = stripslashes($password); //Check if usernmae and password is good, if it is it will start session if ($username == $a_username && $password == $a_password) { session_start(); $_SESSION['session_logged'] = 'true'; $_SESSION['session_username'] = $username; //Redirect to admin page header("Location: admin_area.php"); } } $username = (isset($_POST['username'])) ? $_POST['username'] : ''; $password = (isset($_POST['password'])) ? $_POST['password'] : ''; if($username && $password) { $connect = mysql_connect("localhost", "root", "") or die ("Couldn't connect!"); mysql_select_db("friendsdb") or die ("Couldn't find the DB"); $query = mysql_query ("SELECT * FROM `user` WHERE username = '$username'"); $numrows = mysql_num_rows($query); if ($numrows != 0){ while ($row = mysql_fetch_array($query)) { $dbusername = $row['username']; $dbpassword = $row['password']; } //Check to see if they are match! if ($username == $dbusername && md5($password) == $dbpassword) { header ("Location: user_area.php"); $_SESSION['username'] = $username; } else $error_msg = "Incorrect password!"; //code of login }else $error_msg = "That user does not exist!"; //echo $numrows; } else $error_msg = "Please enter a username and password!"; } ?> <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta http-equiv="Content-Type" content="text/html; charset=iso-8859-1" /> <title>Login Page</title> </head> <body> <br /> <?php require "header.php"; ?><br /> <div align="center"> <table width="200" border="1"> <?php // If $error_msg not equal to emtpy then display error message if($error_msg!="") echo "<div id=\"error_message\"style=\"color:red; \">$error_msg</div><br />";?> <form action="<?php echo $_SERVER['PHP_SELF'];?>" method="post"> <!--form action="login_a.php" method="post"--> Username: <input type="text" name="username" /><br /><br /> Password: <input type="password" name="password" /><br /><br /> <input type="submit" name = "submit" value="Log in" /> </form> <p> </p> Register a <a href="register.php">New User</a> </table> </div> </body> </html> Hi guys. What I want to create is really complicated. Well I have a login system that works with post on an external website. I have my own website, but they do not give me access to the database for security reasons, therefore I have to use their login system to verify my users. What their website does is that it has a post, with username and password. The POST website is lets say "https://www.example.com/login". If login is achieved (i.e. username and password are correct), it will redirect me to "https://www.example.com/login/success" else it will redirect me to "https://www.example.com/login/retry". So I want a PHP script that will do that post, and then according to the redirected website address it will return me TRUE for success, FALSE for not successful login. Any idea?? Thanks How to add the ability to login with username or email for login?
<?php
ob_start();
include('../header.php');
include_once("../db_connect.php");
session_start();
if(isset($_SESSION['user_id'])!="") {
header("Location: ../dashboard");
}
if (isset($_POST['login'])) {
$email = mysqli_real_escape_string($conn, $_POST['email']);
$password = mysqli_real_escape_string($conn, $_POST['password']);
$result = mysqli_query($conn, "SELECT * FROM users WHERE email = '" . $email. "' and pass = '" . md5($password). "'");
if ($row = mysqli_fetch_array($result)) {
$_SESSION['user_id'] = $row['uid'];
$_SESSION['user_name'] = $row['user'];
$_SESSION['user_email'] = $row['email'];
header("Location: ../dashboard");
} else {
$error_message = "Incorrect Email or Password!!!";
}
}
?>
Is there a way to query some information depending on if a table field DOES NOT include a specific value? I've got a table that contains over 100 locations. I want to organize the data on the frontend by country (specifically US and International). How would I go about filtering out locations that DO NOT belong in USA? $q = "SELECT * FROM table WHERE COUNTRY='USA'"; i have a small search profile search and need to set $getuname variable to users username if((trim($country) !== ''&&($state) !== ''&&($city) !== '')){ $data = mysql_query("SELECT * FROM users WHERE users.state='$state' AND users.country='$Country' AND users.city='$city' ORDER BY RAND() DESC LIMIT 1 "); Echo "Country city state search"; $getuname = mysql_real_escape_string($_GET['username']); am i meant to use the get or is that only for forms? Hi all, I am trying to produce a script that will send out an email but the user can basically choose how often they get this email... I want to give them the option of daily, weekly and monthly. I have the logic down on paper and in plain English it seems to make sense but I am having a hard time converting this to code: My logic is: 1. find out how often they want to get the email (we will call this frequency, as thats what my database field is called) 2. drag out last updated timestamp (this is called last_updated and is a unix timestamp) 3. some form of compare i.e. if frequency is weekly and $today is 7 days after last reminded alert them as I say this makes sense in plain English but I'm having a hard time converting it... this is what I have come up with so far: Code: [Select] <?php // Connect include("../connect.php"); $query = "SELECT * FROM resumes_bak WHERE jobseekerid = '2610'"; $result = mysql_query($query) or die (mysql_error()); while ($row = mysql_fetch_array($result)) { $current_timestamp = time(); echo "Current Timestamp: ".$current_timestamp; echo "<br /><br />"; $frequency = $row['frequency']; echo "Frequency is: ".$frequency; echo "<br /><br />"; $lastReminded = $row['last_reminded']; echo "Last reminded: ".$lastReminded; echo "<br /><br />"; $daily = strtotime('+1 day', $lastReminded); echo "One day forward: ".$daily; echo "<br />"; $weekly = strtotime('+1 week', $lastReminded); echo "One week forward: ".$weekly; echo "<br />"; $monthly = strtotime('+1 month', $lastReminded); echo "One month forward: ".$monthly; echo "<br /><br />"; if($frequency = 'daily' && /* I THINK I NEED ADDITIONAL CLAUSES IN HERE TO DO THE COMPARISON */ ) { echo "I am daily"; } elseif ($frequency = 'weekly') { echo "I am weekly"; } else { echo "I am monthly"; } } ?> Can anybody help me on my way here, I seem to have hit a wall! Many thanks, Greens85 Hello. I recently posted about getting my top nav to work which it does now (with thanks) but im having trouble getting my side navs to work. i have tried various things but i think its just a case of getting the where clause right. see what you think. any help would be great these are my files. includes/navL1.php - which does the top navigation includes/navL2.php - which does the left navigation main includes/navL3.php - which does the left navigation sub admin/layouts/admin_topnav.php admin/layouts/admin_leftnav.php admin/layouts/index.php ok so. admin topnav.php code looks like this and works Code: [Select] <?PHP require_once("../includes/initialize.php"); global $topNav; global $pageName; ?> <div id="navWrapper"> <?PHP $topNav = navL1::find_all(); ?> <div id="ddtabs3" class="solidblockmenu"> <ul> <?PHP foreach($topNav as $topNavs): ?> <li><a <?PHP echo ($pageName == $topNavs->title ? 'class="selected"' : '')?> href="<?PHP echo $topNavs->title; ?>.php" id="<?PHP echo $topNavs->title; ?>"><?PHP echo $topNavs->title; ?></a></li> <?PHP endforeach; ?> </ul> </div><!-- #ddtabs3--> </div><!-- #navWrapper--> now i need when a top nav is selected i need the correct left nav main and subs to show. this is how my left nav looks at the moment Code: [Select] <?PHP require_once("../includes/initialize.php"); global $topNav; global $pageName; ?> SOME ACCORDION SCRIPT GOES HERE <div class="arrowlistmenu"> <?PHP $nav1 = navL1::find_all(); $nav2 = navL2::find_by_nav(); $nav2 = navL2::find_by_nav(); ?> <?PHP foreach($nav2 as $nav2s): ?><h3 class="menuheader expandable"> // MAIN LEVEL <li><a <?PHP echo ($pageName == $nav2s->title ? 'class="selected"' : '')?> href="<?PHP echo $nav2s->title; ?>.php" id="<?PHP echo $nav2s->title; ?>"><?PHP echo $nav2s->title; ?></a></li></h3> <?PHP endforeach; ?> // SUB LEVEL <ul class="categoryitems"> <?PHP foreach($nav3 as $nav3s): ?> <li><a <?PHP echo ($pageName == $nav3s->title ? 'class="selected"' : '')?> href="<?PHP echo $nav3s->title; ?>.php" id="<?PHP echo $nav3s->title; ?>"><?PHP echo $nav3s->title; ?></a></li> <?PHP endforeach; ?> </ul> </div><!-- #End arrowlistmenu --> <img src="images/wrapper/loading.gif" alt="loading..." id="Pageloading" height="28" width="28" style="visibility:hidden;float:left;" /> this is the code im trying to get to work in my includes files that i can seem to get my head around includes/navL2.php Code: [Select] public static function find_by_nav(){ global $database; global $topNav; $sql = "SELECT * FROM ".self::$table_name." WHERE title="$topNav" LIMIT 1"; $result_array = self::find_by_sql($sql); return !empty($result_array) ? array_shift($result_array) : false; } the find_by_sql($sql) looks like this but i dont think you need it Code: [Select] public static function find_by_sql($sql){ global $database; $results_set = $database->query($sql); $object_array = array(); while($row = $database->fetch_array($results_set)){ $object_array[] = self::instantiate($row); } return $object_array; } im trying to use the same code to pull the sub levels inside includes/navL3.php if any of this makes sense please could you point out whats wrong thanks ricky Hey guys, I'm just trying to add a form button to my site that updates a user's data in the mysql database. However I'm struggling trying to find a way to define which field to edit, can someone tell me if I'm along the correct lines: Page with submit button: Code: [Select] <?php $result = mysql_query("SELECT * FROM members WHERE Username='$_SESSION[Username]'") or die(mysql_error()); while($row = mysql_fetch_array( $result )) { echo '<b>Resources</b><br />'; echo 'Wood: ' . $row['res1'] . ' <br />'; echo 'Iron: ' . $row['res2'] . ' <br />'; echo 'Credits: ' . $row['credits'] . ' <br />'; } echo 'Offence Power: '; echo $offencepower; echo '<br />'; echo 'Defence Power: '; echo $defencepower; echo '<br />'; echo 'Total Power: '; echo $totalpower; ?> <br /><br /> <form action="update.php" method="post"> <input type="hidden" name="Memberid" value="' . $row['Memberid'] . '"> <input type="submit" name="submit" value="submit"> </form> Update.php: Code: [Select] <?php include ('config.php'); ?> <?php $Memberid = mysql_real_escape_string($_POST['Memberid']); if (isset($_POST['Memberid'])) { $query=("UPDATE members SET totalpower = '10' WHERE Memberid='$Memberid'"); mysql_query($query); echo $query; /* header('Location: ' . $_SERVER['HTTP_REFERER']);*/ } ?> When echoing the query I'm getting: Quote UPDATE members SET totalpower = '10' WHERE Memberid='\\\' . $row[\\\'Memberid\\\'] . \\\'' Thanks This will be a little difficult to explain, but keep with me. On the profile.php page. It starts a new session. Code: [Select] // Connect to MySQL... $conn = mysql_connect($hostname, $username, $password) or die("Connecting to MySQL failed"); mysql_select_db($database, $conn) or die("Selecting MySQL database failed"); // Run our query, see if session username exists in session field... $sql="select username,email from user where username='{$_SESSION['user']}' limit 1"; $result=mysql_query($sql,$conn); // Parse our results into $data (as an associative array)... $data=mysql_fetch_assoc($result); // If one row was found in the result set, username exists... if (mysql_num_rows($result)==1) { $_SESSION['sellername'] = $data['username']; So what I am hoping that is doing, is the session named "sellername" is stored with the variable of the logged in user. In this example "testuser". Now the page updates.php will have an id attached to like so: updates.php?id=13. Which will have info only available for testuser's eyes. On the page it does this. Code: [Select] // Connect to MySQL... $conn = mysql_connect($hostname, $username, $password) or die("Connecting to MySQL failed"); mysql_select_db($database, $conn) or die("Selecting MySQL database failed"); // Run our query, see if session username exists in session field... $sql="select username from user where username='{$_SESSION['user']}' limit 1"; $result=mysql_query($sql,$conn); // Parse our results into $data (as an associative array)... $data=mysql_fetch_assoc($result); // If one row was found in the result set, username exists... if (mysql_num_rows($result)==1) { $query='select seller from listings where seller = "'.$data['username'].'"'; $queryresult=mysql_query($query,$conn); while($info = mysql_fetch_assoc($queryresult)){ if ( $_SESSION['sellername'] == $info['seller'] ){ The if statement should process: "If the session variable for 'sellername' equals the database entry 'seller' then display the rest of the page." However, no matter what user is logged, it will display the page. Any ideas? Hey im having troube making this code as i have no idea how to do it... basically what im trying to do is for example if the index.php?id=XXX i want to echo "this" and if it is just index.php i want to echo "that" your help would be nice thanks <?php $id_lang = $_GET['id']; if($id_lang == $id_lang){ $result = mysql_query("SELECT * FROM pages WHERE id='$id_lang' ",$connect); while($row44 = mysql_fetch_assoc($result)) { $js_langdir = $row44['lang_dir']; }} else{ $js_langdir = "LTR"; } ?> just a little confused where ( brackets go in this statement . im just wanting to to display the information differently depending on which message is returned from the database. thanks Code: [Select] if ($info['message'])="<a href=\"freindacept.php?username=$myusername\">Has sent you a friend request </a>";{ Echo "<a href='viewprofile.php?username={$info['username']}'><img src='http://datenight.netne.net/images/".$info['img'] ."' width='30' height='30''></a>".$info['from_user']." ".$info['message']; }elseif ($info['message'])="You have sent a contact request to"; Echo " .$info['message']<a href='viewprofile.php?username={$info['username']}'><img src='http://datenight.netne.net/images/".$info['img'] ."' width='30' height='30''></a>".$info['from_user']."; } } Hi, I'm trying to display a user review system allowing user's to vote. This works fine, but I'm trying to user php to only display the rating system if the user is logged in and display alternate text if they are not. I am getting the following error: Parse error: syntax error, unexpected T_ELSE in XXXXXX on line 182 Here's the code: Code: [Select] <?php if ($_SESSION['username']){ $query = mysql_query("SELECT * FROM locations WHERE name = '$location'"); while($row = mysql_fetch_array($query)) { $rating = (int)$row[rating] ?> <div class="floatleft"> <div id="rating_<?php echo $row[id]; ?>"> <span class="star_1"><img src="fivestars/star_blank.png" alt="" <?php if($rating > 0) { echo"class='hover'"; } ?> /></span> <span class="star_2"><img src="fivestars/star_blank.png" alt="" <?php if($rating > 1.5) { echo"class='hover'"; } ?> /></span> <span class="star_3"><img src="fivestars/star_blank.png" alt="" <?php if($rating > 2.5) { echo"class='hover'"; } ?> /></span> <span class="star_4"><img src="fivestars/star_blank.png" alt="" <?php if($rating > 3.5) { echo"class='hover'"; } ?> /></span> <span class="star_5"><img src="fivestars/star_blank.png" alt="" <?php if($rating > 4.5) { echo"class='hover'"; } ?> /></span> </div> </div> <div class="star_rating"> (Rated <strong><?php echo $rating; ?></strong> Stars) </div> <div class="clearleft"> </div> } } <?php else { echo "Log in to review"; } ?> Thanks in advance for any help. I'm sure it's something trivial but I can't see it! Hi guys! How do I display different code depending on the title/url? This is the code for the form that brings you from "http://www.xxx.uk/index.php" to "http://www.xxx.uk/index.php?name=ro": Code: [Select] <form name="input" action="http://www.xxx.uk/index.php?name=ro" method="post"> Enter student number:<input type="text" name="sid"/> <input type="submit" value="Submit"> Now when you are on "http://www.xxx.uk/index.php?name=ro" I would like another content(but written in the same php file). I tried with _GET, but the problem is that I don't simply want to add a word but a lot of content. With _GET, that whole content would have to be displayed in the title and I don't want that. |
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