PHP - I Wish To Know How I Can Convert This Date 24-09-2010 To This Format 2010-09-24

Hello All, 
  Need an advise in finishing this task please. 
 

function convertTimeFormat($time12Hour) {
// Initialized required variable to an empty string.
		$time24Hour = ""; 

// Used explode() function to break the string into an array and stored its value in $Split variable. 
		$Split = explode(":",$time12Hour); // print_r(explode (":", $time12Hour)); => Array ( [0] => 09 [1] => 50 [2] => 08AM )

// Retrieved only "hour" from the array and stored in $Hour variable. 
		$Hour = $Split[0];   

    $Split[2] = substr($Split[2],0,2);

// Used stripos() function to find the position of the first occurrence of a string inside another string.	
		if($Hour == '12' && strpos($time12Hour,"AM")!== FALSE) {
			// Code here 
		} elseif(strpos($time12Hour,"PM")!== FALSE && $Hour != "12") {
			// code here
		}
		return  $time24Hour;
	}
	$time12Hour = "09:50:08AM";
	$result = convertTimeFormat($time12Hour);
	print_r($result); 

/*
Input : "09:50:08AM";
Output : "21:50:08PM";
*/

 

Hi all,

I am currently making a website that has e-custom functions and a back end for the client.

I want them to be able to upload images - but they need to be transparent. I do not want to leave this in the hands of the client, so I am looking at ways of using the GD library to make the change

I got no issue with the png/gif type for upload/resize function since this type already transparent background but my major problems is how to deal with jpeg/jpg image type which is their background was not a transparent...so is it possible I can change/ convert to png/gif type upon successful of uploading image...so the new final image will be png/gif type with transparent background...is it doable...I am not even sure it is possible...?

Thanks for any help..

I have multiple datetimes. The format is dd-mm-yy, hh:mm. I want to insert it into a table using mysql. However mysql format is yy-mm-dd, hh:mm:ss. How can i do it and what type should i use (datetime?timestamp?).
Thanks for your help!!

Can anyone please tell me how I convert DD-MM-YYY (text) to TIME (unix)

thought I'd say that I have this line at the top of all my pages, just in case it means a different code.

Code: [Select]
date_default_timezone_set('Europe/London'); //### Set the default timezone

Hi I was going to start a new project which need to convert files from one fomrat to other like, you can check a site here  online-convert.com , there they give user to convert in various fomats. please check

my question is i have idea how to do these conversion with ffmpeg and php.
Code: [Select]
Audio converter
Video converter
Image converter
Hash generator
can someone please tell me how to do these conversion.
Code: [Select]
Document converter
Ebook converter

Thanks for any help

Hi,

I am trying to convert a String date into numeric date using PHP function's, but haven't found such function.
Had a look at date(), strtotime(), getdate();

e.g. Apr 1 2011  ->    04-01-2011

Could someone please shed some light on this?

Regards,
Abhishek

Does anyone know how I can convert linux epoch number such as 1292878800 to the UTC format?

Ricky

Hi,

I need to post to a form with cURL. I'am sending strings in Headers format...

There are some documentation or some function that translates from the human readable format to the Headers format?

For example:

Human readable format:
Quote

Vendo bicicleta. Como nova.


Headers format:
Quote

Vendo%20bicicleta.%20Como%20nova.


The problem is not the spaces but more the accents. I write in Portuguese.

Can you give me some clue?


Best Regards,

Hi there,

I have a string '12/04/1990', that's in the format dd/mm/yyyy.

I'm attempting to convert that string to a Date, and then insert that date into a MySQL DATE field.

The problem is, every time I try to do so, I keep getting values like this in the database: 1970-01-01.


Any ideas?


Much appreciated.

Hi, I have a connection set up to an API using a PHP script - the API sends back data in JSON format, and if I capture it and echo it, it displays in extremely unfriendly format on the screen.

I've tried to find a way to convert this data into readable format, ideally in a HTML table, but although there are articles on converting manually inputted JSON data into a HTML table using Javascript, I can't find a way to do it from a PHP variable.

This is what I have so far:

if ($_POST['getcompany']) {
$companyname = $_POST['_Name'];
	
$ch = curl_init();

$data_array2 =  array(
      'token' => $token
);
$make_call2 = json_encode($data_array2);
	//echo 'Token is '.$token;
	$token2 = substr($token, 14);
	$token3 = substr($token2, 0, -3);
	
	//echo 'Token 2 is '.$token3;
	//echo 'Company Name is '.$companyname;

//curl_setopt($ch, CURLOPT_GET, 1);
//curl_setopt($ch, CURLOPT_POSTFIELDS, $make_call2);
curl_setopt($ch, CURLOPT_HTTPHEADER, array('Content-Type: application/json','Authorization: '.$token3.'')); 
curl_setopt($ch, CURLOPT_RETURNTRANSFER, true);
curl_setopt($ch, CURLOPT_URL, 'https://connectionurl?countries=GB&name='.$companyname);

//Execute the request
$result = curl_exec($ch);

echo 'Companies: '.$result; //This displays the data provided by the search, but is in JSON format

 

So I need a way to get the data held in $result, into a HTML table. Any idea how I can do this?

Hi

In sql we have dates like this 134238

In php it shows -  19:10:11  . we can make it by using date('d.m.y', $date); where $date=134238 ;

my question is how can we turn 19:10:11 in to 134238 using PHP

Is it possible to convert time(); to date();?

Hi all,

I'm having a bit of trouble a script running on a site where it converts a date of birth in a database shown like this '30/04/1993' to an actual age, for instance 18 in this case. Only the script I'm using below shows this age as 17, not 18 as it should be.

Code: [Select]
<?php
   $birthday = $row_getdets['dob']; 
    function birthday ($birthday){
    list($day,$month,$year) = explode("/",$birthday);
    $day_diff   = date("d") - $day;
    $month_diff = date("m") - $month;
    $year_diff  = date("Y") - $year;
    if ($day_diff < 0 || $month_diff < 0)
      $year_diff--;
    return $year_diff;
  }
?>

So i've tried to remedy this myself with the following:

Code: [Select]
<?php
$birthday = $row_getdets['dob'];
function birthday ($birthday){
    list($year,$month,$day) = explode("/",$birthday);
     $year_diff  = date("Y") - $year;
     $month_diff = date("m") - $month;
     $day_diff   = date("d") - $day;
     if ($month_diff < 0) $year_diff--;
else if (($month_diff==0) && ($day_diff < 0)) $year_diff--;
return $year_diff;
  }
?>
..but I'm having a syntax error (unexpected T_LINE), most probably down to my novice ability, I bet I've missed something simple. I'm still learning guys and I'd really appreciate any help at all.

I am trying to get the full date from form field using the date function and post method.

$fromdate = $_POST[‘sdate’];
$todate = $_POST[‘edate’];
$fromday = date(‘F j, Y, g:i a’,’$fromdate’);
$today1 = date(‘F j, Y, g:i a’,’$todate’);

When trying to print i get the right format but i get extra information not sure from where? I am getting the date from the form fields of type date.

Code Output:

March 19, 2020, 4:16 pm,$31202019pm31Asia/Dubai

why i am getting the second part!

I'm trying to format a date to use in a mysql query and was wondering about the best way to do it.

the form returns: mm/dd/yyyy and I need to format it to yyyy-mm-dd, any help would be greatly appretitaed, thanks in advance!