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PHP - Echoing Ajax
i'm not sure whether this should be in this section or the ajax section.
i'm trying to echo out an ajax script so that a page loads in a div tag after a link is clicked in the menu. Without the "echo", it works fine, but as soon as i include it within the "echo", it stops working. Any help would be great else echo" <div id='fcontrol'> <table border='1' class ='tstyle'> <tr height ='700'><td valign='top' class='ssbg' width='120'><div id='menu'> <a href='javascript:ajaxpage(''new_section.php'', ''contentarea'');'>Add new section</a><br/><br/> <a href='javascript:ajaxpage('new_sub_section.php', 'contentarea');'>Add new section to forum</a><br/><br/><a href='index.php'>Back to forum</a><br/><br/></div></td><td class='tcontrol' width='700' valign='top'> <center><div id='contentarea'>Control Panel</div></center></td></tr> </table></div> </div> "; ?> Similar TutorialsRight now I redirect to index page after I delete a record. However I am looking to make it so that I can delete a record without redirecting the page. I know this can be accomplised using Ajax. I have spent countless hours before trying to make it work, but it did not work.
So here is a basic setup I created. Can you please update it with ajax code so that I can see how it's done properly?
<!DOCTYPE HTML> <html lang="en"> <head> <meta charset="UTF-8"> <title>Home Page</title> </head> <body> <div class="record" > <a href="record.php?id=<?php echo $record_id ?>"><?php echo $record_name; ?></a> <div class="delete-record"> <a href="delete.php">Delete Record</a> </div> </div> </body> </html> Edited by man5, 18 August 2014 - 08:55 PM. Now I'm having this strange issue with my website I'm currently working on a tester system and I've encountered a problem that I'm unable to find the issue, tho I'm thinking my ajax php part of the script to be the thing causing it even tho it seems strange that it would cause it. The first part which is connected to where the problem occurs is the echo"<form>"; and from there, It should take you to index.php?page=tester&select=answer, now that is where it in the browser goes there tho it still shows the page stuff from the last page which is index.php?page=tester&select=applications, so it's like showing both &select=answer and &select=applications on the same page. <?php $q=$_GET["q"]; include'../config/connection.php'; $result = mysql_query("SELECT * FROM applications WHERE id = '$q'"); echo "<center><table border='1'> <tr> <th>Account Name</th> <th>Character Name</th> <th>Gender</th> <th>Skin Color</th> </tr>"; $row = mysql_fetch_array($result); echo "<tr>"; echo "<td>" . $row['name'] . "</td>"; echo "<td>" . $row['charactername'] . "</td>"; echo "<td>" . $row['gender'] . "</td>"; echo "<td>" . $row['race'] . "</td>"; echo "</tr></table></center>"; echo"<br/>"; echo"<table><tr> <th>Description</th> <th>Metagaming</th> <th>Powergaming</th></tr>"; echo"<tr>"; echo "<td><textarea readonly='readonly' style='width:22em; height:20em;'>".$row['description']."</textarea></td>"; echo "<td><textarea readonly='readonly' style='width:22em; height:20em;'>".$row['mg']."</textarea></td>"; echo "<td><textarea readonly='readonly' style='width:22em; height:20em;'>".$row['pg']."</textarea></td>"; echo"</tr></table><table><br/><center><h1>Answer</h1><br/><form action='index.php?page=tester&select=answer' method='post'>"; echo"<textarea name='why' style='height:10em; width:60em;'></textarea><br/>"; echo"<input type='submit' name='answer' value='Accept' /><a/>"; echo"<input type='submit' name='answer' value='Decline' /></center>"; echo"<input type='hidden' name='id' value='$q'/>"; echo"</form></table>"; ?> Now on &select=answer it included a page which the script of that include consist of the stuff below, it outputs that the query was successfully, and all that. <? if(!empty($_POST['why'])) { $why = mysql_real_escape_string($_POST['why']); $answer = trim($_POST['answer']); $id = $_POST['id']; if($answer == "Accept") { $query1 = mysql_query("UPDATE characters SET accepted = '1' WHERE id = '".$id."'"); echo"Successfully accepted"; $answer = 1; } elseif($answer == "Decline") { echo"Successfully declined"; $answer = 0; } $query = mysql_query("UPDATE applications SET answer = '$why' AND tester = '".$_COOKIE['Username']."' AND accepted = '$answer' AND answered = '1' WHERE cid = '".$id."'") or die('Could not connect: ' . mysql_error()); if($query) { echo"<br/>Query went through without problems"; header("Refresh: 5;url=index.php?page=tester"); } } ?> This is the ajax part javascript of it which gets the information for index.php?page=tester&select=applications Code: [Select] <script type="text/javascript"> function showApplication(str) { if (str==""||str==0) { document.getElementById("txtHint").innerHTML=""; return; } if (window.XMLHttpRequest) {// code for IE7+, Firefox, Chrome, Opera, Safari xmlhttp=new XMLHttpRequest(); } xmlhttp.onreadystatechange=function() { if (xmlhttp.readyState==4 && xmlhttp.status==200) { document.getElementById("txtHint").innerHTML=xmlhttp.responseText; } } xmlhttp.open("GET","tester/applications.php?q="+str,true); xmlhttp.send(); } </script>If you need any more information feel free to ask for it. Thanks in advance. Hello, I've been trying this for hours now, looking at different examples and trying to change them to work for me, but with no luck... This is what I am trying to do: I have a simple form with: - 1 input field, where I can enter a number - 1 Submit Button When I enter a number into the field and click submit, I want that number to be send to the php file that is in the ajax call, then the script will take that number and run a bunch of queries and then return a new number. I want that new number to be used to call the php script via ajax again, until no number is returned, or something else is returned like the word "done" or something like that, at which point is simply makes an alert or populated a div with a message... The point is, that depending on the number entered it could take up to an hour to complete ALL the queries, so I want the script that is called to only run a fixed amount of queries at a time and then return the number it is currently at (+1), so that it can continue with the next number when it is called again. I would like to use jquery, but could also be any other way, as long as I get this to work. I already have the php script completed that needs to be called by the ajax, it returns a single number when being called. Thank you, vb Hello guys, I want to get the values of 3rd level of my referral but it did not echo any value but if i put the ref id directly on the code, it will echo the values. why is it so? or am i doing it the wrong way? in my database i have a table test_referral id acct_name ref_id refer_id 1 john J1234 0 2 bull B3456 J1234 3 doe D5567 J1234 4 frank F7788 J1234 5 jimmy J9990 J1234 6 tommy T6784 F7788 7 tom T9988 F7788 8 girly G8866 D5567 9 fred F0099 J9990 10 ronaldo R7722 B3456 thanks
$stmt= $pdo->query("SELECT * FROM test_referral WHERE acct_name='Chidi Okafor'");
$parent = $stmt->fetch(PDO::FETCH_LAZY);
echo "<ul><li>";
echo $parent['acct_name'];
$ref_id = $parent['ref_id'];
echo "</li><ul>";
$stmt= $pdo->query("SELECT * FROM test_referral WHERE refer_id='$ref_id'");
$child_count = $stmt->rowCount();
while($child = $stmt->fetch(PDO::FETCH_LAZY)){
echo "<li>";
echo $child['acct_name'];
$ref_ids = $child['ref_id'];
echo "</li>";
}
//$reff = "F7788";
//$stmt= $pdo->query("SELECT * FROM test_referral WHERE refer_id='$F7788'");
$stmt= $pdo->query("SELECT * FROM test_referral WHERE refer_id='$ref_ids'");
$child_count2 = $stmt->rowCount();
while($children = $stmt->fetch(PDO::FETCH_LAZY)){
echo "<ul><li>";
echo $children['acct_name'];
echo "</li></ul>";
}
Edited by Mr-Chidi, 25 December 2014 - 05:34 AM. Hello, I have a PHP page (below) that is suppose to update a field in my database. For some reason it does not update. I am trying to echo that sql with this script. Any help would be greatly appreciated. Thanks JR Code: [Select] $p = (100-$_POST[$c])/100; $sql = "delete from products_groups where customers_group_id = ".$sppc['customers_group_id']; echo $sql; tep_db_query($sql); $sql = "insert into products_groups select '". $sppc['customers_group_id'] ."' as customers_group_id, ( " . $p . " * p.products_price) as customers_group_price, p.products_id from products p"; echo $sql; tep_db_query($sql); Below is the complete code, Code: [Select] <?php require('includes/application_top.php'); ?> <!DOCTYPE html public "-//W3C//DTD HTML 4.01 Transitional//EN"> <html <?php echo HTML_PARAMS; ?>> <head> <meta http-equiv="Content-Type" content="text/html; charset=<?php echo CHARSET; ?>"> <title><?php echo TITLE; ?></title> <link rel="stylesheet" type="text/css" href="includes/stylesheet.css"> <script language="javascript" src="includes/general.js"></script> </head> <body marginwidth="0" marginheight="0" topmargin="0" bottommargin="0" leftmargin="0" rightmargin="0" bgcolor="#FFFFFF" onload="SetFocus();"> <div id="popupcalendar" class="text"></div> <!-- header //--> <?php require(DIR_WS_INCLUDES . 'template_top.php'); ?> <!-- header_eof //--> <?php if (isset($_POST['Update'])) { $sppc_query_raw = "select * from " . TABLE_CUSTOMERS_GROUPS . " order by customers_group_id"; $sppc_query = tep_db_query($sppc_query_raw); while( $sppc = tep_db_fetch_array( $sppc_query ) ) { if ($sppc["customers_group_name"] != "Retail"){ //$sppc['customers_group_id'] $c = "CG_".$sppc['customers_group_id']; $tmp = $_POST[$c]; if ($tmp != 0) { $p = (100-$_POST[$c])/100; tep_db_query("delete from products_groups where customers_group_id = ".$sppc['customers_group_id']); tep_db_query ("insert into products_groups select '". $sppc['customers_group_id'] ."' as customers_group_id, ( " . $p . " * p.products_price) as customers_group_price, p.products_id from products p"); } //if not 0 } //if not Retail } } ?> <!-- body //--> <table border="0" width="100%" cellspacing="2" cellpadding="2"> <tr> <td width="<?php echo BOX_WIDTH; ?>" valign="top"><table border="0" width="<?php echo BOX_WIDTH; ?>" cellspacing="1" cellpadding="1" class="columnLeft"> </table></td> <!-- body_text //--> <td width="100%" valign="top"><table border="0" width="100%" cellspacing="0" cellpadding="2"> <tr> <td width="100%"><table border="0" width="100%" cellspacing="0" cellpadding="0"> <tr> <td class="pageHeading"><?php echo "Special Pricing Discount Setup"; ?></td> <td class="specialPrice" align="right"> </td> </tr> </table></td> </tr> <tr> <td><table border="0" width="100%" cellspacing="0" cellpadding="0"> <tr> <td valign="top"><table border="0" width="100%" cellspacing="2" cellpadding="2"> <tr class="dataTableHeadingRow"> <td class="dataTableHeadingContent" align="left"> <?php if (isset($_POST['Update'])) { echo "<center>Updated!</center>"; } ?> </td> </tr> <?php $sppc_query_raw = "select * from " . TABLE_CUSTOMERS_GROUPS . " order by customers_group_id"; $sppc_query = tep_db_query($sppc_query_raw); while( $sppc = tep_db_fetch_array( $sppc_query ) ) { ?> <tr class="dataTableRow" onmouseover="rowOverEffect(this)" onmouseout="rowOutEffect(this)"> <td class="dataTableContent" align="left"> <?php if ($sppc["customers_group_name"] != "Retail"){ echo $sppc["customers_group_name"]; } if (isset($_POST['Update'])) { if ($sppc["customers_group_name"] != "Retail"){ $c = "CG_".$sppc['customers_group_id']; $tmp = $_POST[$c]; echo " Current Discount is $tmp%" ; } } ?> </td> </tr> <?php } ?> </table></td> </tr> <tr> <td valign="top"> <form action="" method="post"> <table border="0" width="40%" cellspacing="0" cellpadding="2"> <tr> <td class="smallText" align="left"> </td> <td> </td> </tr> <?php $sppc_query_raw = "select * from " . TABLE_CUSTOMERS_GROUPS . " order by customers_group_id"; $sppc_query = tep_db_query($sppc_query_raw); while( $sppc = tep_db_fetch_array( $sppc_query ) ) { if ($sppc["customers_group_name"] != "Retail"){ ?> <tr> <td class="smallText" align="left">Set New Percentage (%) Discount for <?=$sppc["customers_group_name"]?> :</td> <td><input name="CG_<?=$sppc['customers_group_id']?>" type="text" size="5" value="0"></td> </tr> <?php } } ?> <tr> <td colspan="2" align="center"><input type="submit" name="Update" value="Update"></td> </tr> </table> </form> </td> </tr> </table></td> <!-- body_text_eof //--> </tr> </table> <!-- body_eof //--> <!-- footer //--> <?php require(DIR_WS_INCLUDES . 'footer.php'); ?> <!-- footer_eof //--> </body> </html> <?php require(DIR_WS_INCLUDES . 'application_bottom.php'); ?> This problem is existing on a few pages so I'll be in the clear if I can figure out to solve it on one page. Problem is on form submission its still echoing back that sortorder variable which makes it hard for it to compare on the success function to display the right message because the message should be good, bad1, bad2, ... . So is there anyway around that or do I need to do something on the client side of the form page. <?php // Include the database page require ('../inc/dbconfig.php'); if ( isset( $_POST['menuid'] ) ) { $menuid = (int)$_POST['menuid']; $query = "SELECT COUNT(sortorder) AS numOrder FROM `menuitems` WHERE `menu_id` = '".$menuid."'"; $result = mysqli_query ($dbc, $query); $row = mysqli_fetch_array( $result, MYSQL_ASSOC ); $sortorder = $row[ 'numOrder' ] + 1; echo $sortorder; } if (isset($_POST['submitmenuitem'])) { $menuid = mysqli_real_escape_string($dbc, $_POST['menuid']); $itemname = mysqli_real_escape_string($dbc, $_POST['itemname']); $itemurl = mysqli_real_escape_string($dbc, $_POST['itemurl']); $sortorder = mysqli_real_escape_string($dbc, $_POST['sortorder']); $contentpage = mysqli_real_escape_string($dbc, $_POST['contentpage']); $newscategory = mysqli_real_escape_string($dbc, $_POST['newscategory']); $application = mysqli_real_escape_string($dbc, $_POST['application']); $query = "SELECT * FROM `menuitems` WHERE (`itemname` = '".$itemname."') OR (`itemurl` = '".$itemurl."') OR (`contentpage_id` = '".$contentpage."') OR (`application_id` = '".$application."') OR (`newscategory_id` = '".$newscategory."') AND `menu_id` = '".$menuid."'"; $result = mysqli_query ( $dbc, $query ); // Run The Query $rows = mysqli_num_rows($result); if ($rows == 0) { $query = "INSERT INTO `menuitems` (menu_id, itemname, itemurl, sortorder, contentpage_id, newscategory_id, application_id, creator_id, datecreated, enabled) VALUES ('".$menuid."','".$itemname."','".$itemurl."','".$sortorder."','".$contentpage."', '".$newscategory."', '".$application."', 1, NOW(), 0)"; mysqli_query($dbc, $query); echo "good"; } else { $row = mysqli_fetch_array($result); if (($row['itemname'] == $itemname) && ($row['newscategory_id'] == $newscategory)) echo 'bad9'; elseif (($row['itemname'] == $itemname) && ($row['application_id'] == $application)) echo 'bad8'; elseif (($row['itemname'] == $itemname) && ($row['contentpage_id'] == $contentpage)) echo 'bad7'; elseif (($row['itemname'] == $itemname) && ($row['itemurl'] == $itemurl)) echo 'bad6'; elseif ($row['newscategory_id'] == $newscategory) echo 'bad5'; elseif ($row['application_id'] == $application) echo 'bad4'; elseif ($row['contentpage_id'] == $contentpage) echo 'bad3'; elseif ($row['itemurl'] == $itemurl) echo 'bad2'; elseif ($row['itemname'] == $itemname) echo 'bad1'; } } if (isset($_POST['deletemenuitem'])){ $menuitemID = (int)$_POST['menuitemID']; $query = "UPDATE `menuitems` SET `enabled` = '1' WHERE `id` = '".$menuitemID."' LIMIT 1"; mysqli_query($dbc,$query); } ?> $lastfm = file_get_contents('http://www.last.fm/group/Rishloo/members'); $users = explode('" id="r4_', $lastfm); $users = explode('">', $users[1]); var_dump($users[0]); that is only echoing one ID http://www.last.fm/group/Rishloo/members 1 id for each member it should be echoing.. any idea why it isnt? $lastfm = file_get_contents('http://www.last.fm/group/Rishloo/members'); $grab_id=explode('" id="r4_', $lastfm); for($b=1; $b<count($grab_id); $b++){ $getid=explode('">', $grab_id[$b]); echo count($getid[0]); } that echos all 1's.. any help is appreciated.. thanks thanks hi all, I have a piece of code which I coded where it selects all there cars out of the database and shows them, well it is meant to: $getall = mysql_query("SELECT car, id FROM garage WHERE owner='$username'"); $gotall = mysql_fetch_object($getall); echo "$gotall->car - $gotall->id<br />"; Its meant to echo out all the cars which the user own, but for some reason its only echoing one car. Can anyone see why its only showing one car with the id not all the cars they own? Thanks. how do i echo "checked=checked" for a checkbox? here is what i have: Code: [Select] <input type='checkbox' name='ip_automatic_login' id='ip_automatic_login' value='1' if($IPCheck == true) {/"checked=checked/" } /> this code will be echoed! I am having issue creating a checkbox that uses a onClick() js method. I believe this might be due to the fact that I am echoing the html but if any one could help id appreciate it. echo "<tr><td>WrkComp</td><td><input type='checkbox'" ?> <script>onClick="show()" </script> <? "name='WrkComp[]' value='DEP' '.$checked.' '.$Disabled.'/></td>"; I want to echo the contents of column 4 for my username only, and it doesn't show anything. I can do if ($memberQuery->fetchColumn(4) < 2)() though. Code: [Select] $host = 'localhost'; $database = ''; $db_username = ''; $db_password = ''; if (($db = new PDO("mysql:host=$host;dbname=$database", $db_username, $db_password)) == NULL) { echo $db->getMessage(); } $memberQuery = $db->prepare("SELECT * FROM members WHERE username=:username"); $memberQuery->execute(array(':username' => $_SESSION['username'])); $result = $memberQuery->fetchColumn(4); echo "$result"; Hi all, ive got a script witch im wanting to echo all the selected users in a table.. It selects and echos the users but just dosent add on to the table. <?php $themembers = mysql_query("SELECT * FROM users WHERE crew = '$user->crew'"); $ammoutmembers = mysql_num_rows($themembers); ?> <html> <head> <title>Crew Members || SD</title> </head> <body> <?php if ($crewstuff->boss == $username || $crewstuff->coowner == $username || $crewstuff->underboss == $username){ ?> <table width='80%' align='center' class='table' cellpadding='0' cellspacing='0' border='1'> <tr> <td class='header' colspan='3' align='center'>Current Crew Members</td> </tr> <tr> <td class='omg' align='center' width='40%'>Username</td><td class='omg' align='center' width='30%'>Rep</td><td class='omg' width='30%' align='center'>Kick</td> </tr> <?php if ($ammoutmembers != "0"){ while ($member11 = mysql_fetch_object($themembers)){ ?> <tr> <td width='40%'><?php echo("<a href='profile.php?viewuser=$member11->username' target='mainFrame'>$member11->username</a>"); ?></td><td width='30%'><?php echo ("".number_format($member11->rep).""); ?></td><td width='30%'><?php echo("<a href='?action=members&kick=$member11->username'>Kick</a>"); ?></td> </tr> <tr> <td colspan='3' class='omg' align='center'>Any member kicked is logged.</td> </tr> </table> <?php } // $member11 }// $ammoutmembers }elseif ($crewstuff->member == $username){ echo ("Your not being here , without being staff."); } ?> Is there way I can make it so it will be something like this layout: Username | Rep | Kick ---------------------------------- username | 0 | Kick username | 0 | kick For each user thats echoed? Thanks for help given Hi, this is how I echo some results from my DB: Code: [Select] <?php if(mysql_num_rows($execute)>0){ do{ echo " " .$result['id_cliente']. " " .$result['company_name']. " " .$result['cliente_tel']. " " ; }while($result = mysql_fetch_assoc($execute)); }else{ echo " No customer found. " ; } ?> and this echoes the results in one paragraph. I need to print the results in rows...and I need help with that. :shy:Thanks Hey i'm just woundering how i would echo numbers from a database like 1000000 lets say 1 million how would i go about on echoing it like this 1,000,000 ZhsHero Hi all, On my website I have a Functions file which holds information about the user for the game, but earier on today I added ranks which are for the users money. So for the ammout of money they have gives them a different money rank. Heres what ive got: function wealthrank(){ if (($info->money >= "0") && ($info->money < "10000")){ $wealth = "Poor (£0 - £10,000)"; $done="1"; } elseif (($info->money >= "10000") && ($info->money < "500000")){ $wealth = "Won The Lottery (£10,000- £500,000)"; $done="1"; } elseif (($info->money >= "500000") && ($info->money < "5000000")){ $wealth = "Too Much (£500,000 - £5,000,000)"; $done="1"; } elseif (($info->money >= "5000000") && ($info->money < "20000000")){ $wealth = "Millionare (£5,000,000 - £20,000,000)"; $done="1"; } elseif (($info->money >= "20000000") && ($info->money < "75000000")){ $wealth = "Owns The Streets (£20,000,000 - £75,000,000)"; $done="1"; } elseif (($info->money >= "75000000") && ($info->money < "100000000")){ $wealth = "Won The Euro Millions (£75,000,000 - £100,000,000)"; $done="1"; } elseif (($info->money >= "100000000") && ($info->money < "300000000")){ $wealth = "Multi millionare (£100,000,000 - £300,000,000)"; $done="1"; } elseif (($info->money >= "300000000") && ($info->money < "700000000")){ $wealth = "Owns A Bank (£300,000,000 - £700,000,000)"; $done="1"; } elseif (($info->money >= "700000000") && ($info->money < "1500000000")){ $wealth = "Rather Rich (£700,000,000 - £1,500,000,000)"; $done="1"; } elseif (($info->money >= "1500000000") && ($info->money < "5000000000")){ $wealth = "Billionare (£1,500,000,000 - £5,000,000,000)"; $done="1"; } elseif (($info->money >= "5000000000") && ($info->money < "70000000000")){ $wealth = "Owner Of The Land (£5,000,000,000 +)"; $done="1"; } elseif ($info->money >= "100000000000"){ $wealth = "Nearly As Rich As NoName (Hidden!)"; $done="1"; } if (!$done){ $done="0"; } if ($done == "1"){ mysql_query("UPDATE users SET wealthrank='$wealth' WHERE username='$username'"); }} wealthrank(); For some reason its not echoing the correct wealth rank, even at that its only echoing the defult wealth rank. Here is what I done to test it. <?php session_start(); include ("includes/functions.php"); include ("includes/config.php"); logincheck(); $username = $_SESSION['username']; $get = mysql_query ("SELECT * FROM users WHERE username='$username'"); $fetch = mysql_fetch_object($get); ?> Testing something: <?php echo ($username); ?><br /> Wealth Rank: <?php echo ($fetch->wealthrank); ?><br /> Is there something wrong with the way im fetching it from the Database or something wrong with the code? Thanks for any help given. I have a login form at http://cloydprojects.com you can login with username: test password test If you login the script works correctly, but if you type in the wrong info my session is not showing here is that I have. my login script Code: [Select] <?php session_start(); ?> <link href="signUp.css" rel="stylesheet" type="text/css" /> <?php include("db.php"); include("classes/class.account.php"); $Acc = new account; $u = $Acc->clean($_REQUEST['usernameLogin']); $password = $Acc->clean($_REQUEST['passwordLogin']); $p = md5($password); $get = mysql_query("SELECT * FROM users WHERE username = '".$u."' and password = '".$p."'"); $find = mysql_num_rows($get); if ($find == 1) { $info = mysql_fetch_assoc($get); $_SESSION['LoggedIn'] = $info['uID'].'.'.$info['username'].'.'.$info['email']; } else { $_SESSION['LoggedFailed'] = '<div id="ErrorBox">Incorrect username/password!</div>'; } //there is more just not showing it here is my index script where the error should be showing! Code: [Select] <div class="stylized"> <?php if(isset($_SESSION['LoggedIn'])) { echo '<h1> Welcome! </h1>'; echo '<a href="logout.php">logout!</a>'; } else { echo $_SESSION['LoggedFailed']; session_destroy(); ?> <form id="instantform" name="form" action="loginUser.php" method="post"> <h1>Login</h1> <label>Username <span class="small">The username you created!</span></label> <input type="text" name="usernameLogin" id="usernameLogin" /> <label>Password <span class="small">Case sensitive!</span></label> <input type="password" name="passwordLogin" id="passwordLogin" /> <button type="submit">Login</button></div> <div class="spacer"></div> </form> <?php } ?> </div> Hi, I am trying to insert a variable in the body of an email lik so: Code: [Select] $message = "Dear Administrator,\n\nthe following distributor\n\n'.$row_admin_login_RS['distributor_company_name'].'\n\nHas modified his Distributor information record.\n\"; I know it must be a syntax error...but I can't figure it out. Thanks Hi, I have this variable that checks which page we're on: Code: [Select] <?php $checkit = $_SERVER['PHP_SELF']; ?> and I need to echo some text depending which page we're on. I am using this code to do so: Code: [Select] <?php if ($checkit=="index.php") { echo "this is the home page"; } if ($checkit=="index2.php") { echo "this is the other page"; }?>...but nothing is printed. what am i doing wrong? Thanks This code is suppose to echo out ALL the custom pages that are in the database, but it's only show ONE. Why is this? $query_get = mysql_query("SELECT COUNT(id),id,position,content,title FROM custom_pages ORDER BY id"); while($row = mysql_fetch_assoc($query_get)) { echo '<table border="0"> <tr><th><p>Title</p><td>'. $row['title'] .'</td></tr> <tr><th><p>Position</p><td>'. $row['position'] .'</td></tr> <tr><th><p>Action</p><td><a href="index.php?pages=1&delete='. $row['id'] .'">Delete</a> or <a href="index.php?pages=1&edit='. $row['id'] .'">Edit</a></td></tr> </table> '; } |
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