PHP - Differences In Method Writing
Can someone explain the difference between the following?
function a(array $var) { } function a($var = array()) { } function a(Array $var) { } I have seen these recently in a script I am modifying, but not 100% sure as to what each one does. Well I know what the middle one does, but am a little confused on the 1st and 3rd one. Thanks! Dennis Similar Tutorials
My script has 3 classes (that are relevant to this discussion): DB, User and Validate. They are all in independent files and loaded automatically, when required, by an autoloader.
The error messages I am getting a Any pointers as to what I am doing wrong, or what I should be doing, would be most welcome. After being forced to have the server upgraded I am having problems with my 'reset password' pages. What I wondered is, has there been any changes to PHP or MySQL between these versions ? The PHP version was 5.2.9 and is now 5.2.14 The MySQL version was Client API version 5.0.45 and is now Client API version 5.0.90 Some one clicks a link like this. www.site.com/resetpw.php?pwr=a1b2c3d4e5f6 the code would be a 32 char hash that is checked against the database, but my code now (which was never changed before or after the server change) seems to find the database line and update it but show the message that it was invalid ? instead of showing the the message, your password will be sent to you after changing the DB does anyone have any ideas ? Code: [Select] <?php include('includes/connection.php'); include('includes/functions.php'); date_default_timezone_set('Europe/London'); if(isset($_POST['reset']) && trim($_POST['reset']) == 'Reset') { $email = mysql_real_escape_string($_POST['email']); $checkVerify = mysql_query("SELECT account_id FROM customers WHERE email='$email' AND verified='No' LIMIT 1"); $checkBanned = mysql_query("SELECT account_id FROM customers WHERE email='$email' AND suspended='Yes' LIMIT 1"); if(!$email) { $thisError = 'Please enter your e-mail address.'; } else if(!$password) { $thisError = 'Please enter your password.'; } else if(mysql_num_rows($checkVerify)) { $thisError = 'Your account has not been approved by an Admin.'; } else if(mysql_num_rows($checkBanned)) { $thisError = 'Your account has been suspended by an Admin.'; } else { $password = md5($password); $checkAccount = mysql_query("SELECT account_id FROM customers WHERE email='$email' AND password='$password' LIMIT 1"); if(mysql_num_rows($checkAccount)) { $_SESSION['FM_user'] = $email; header('Location: members.php'); exit; } else { $thisError = 'Your e-mail address and/or password is incorrect.'; } } } include('includes/header.php'); ?> <body> <div class="headerBar"> <?php include('includes/navigation.php');?> </div> <?php headerText(); ?> <div class="content"> <div class="widthLimiter contentStyle"> <div class="formWrapper"> <?php if(isset($thisError)) { echo '<div class="errorDiv">',$thisError,'</div>'; } ?> <?php if(isset($thisSuccess)) { echo '<div class="successDiv">',$thisSuccess,'</div>'; } ?> <span class="subHeader">Initiate Password Reset</span> <?php // include("sendmail2010.php"); $securitycode = ($_GET['pwr']); //echo("53:security:".$securitycode.":<br>"); if ($securitycode != "") { $sql = "SELECT * FROM `customers` WHERE `changeofpasswordcode` = '".mysql_real_escape_string($securitycode)."' LIMIT 1"; //echo("54:sql:".$sql.":<br>"); $res = mysql_query($sql) or die(mysql_error()); //echo("57:<br>"); if (mysql_num_rows($res) != 0) { //echo("59:sql:".$sql.":<br>"); $customerName = mysql_result($res, 0 ,'fullname'); $email = mysql_result($res, 0 ,'email'); $yourpasswordtologin = CreateNewPassword(); $format = 'Y-m-d H:i:s'; $date = date( $format ); $sql = "UPDATE `customers` SET `password` = '" . md5($yourpasswordtologin) . "', `password2` = '" . mysql_real_escape_string($yourpasswordtologin) . "', `changeofpasswordcode` = '', `newpasswordrequestedon` = '" . $date . "' WHERE `changeofpasswordcode` = '" . mysql_real_escape_string($securitycode) . "' LIMIT 1"; //echo("65:sql:".$sql.":<br>"); $res = mysql_query($sql) or die(mysql_error()); $_SESSION['customerName'] = $customerName; $_SESSION['customerEmail'] = $email; $_SESSION['generatePass'] = $yourpasswordtologin; //echo("send email"); $sendemailnow = createEmailSend('newPassword', 'Your new password', 'customer'); //echo("email sent ".$sendemailnow); ?><div style="margin: 30px;">Thank you for completing your password reset process.<br><br>An email with a randomly generated password has been sent to your email address, please check your email account for this email as you will need this password to access your <?=$_SESSION['siteName'];?> account.<br><br><strong><em>Please check your 'spam folder' in case our emails are showing up there.</em></strong><br><br>You may now <a href="<?=$_SESSION['webAddress'];?>">sign in</a> to your account.</div><?php //echo("72:end of IF send email<br>"); } else { //echo("74 bad link<br>"); ?><div style="margin: 20px;">Sorry the link you clicked is and old password reset link or is not valid, please delete the email.<br><br>If you were trying to reset your password, please click the<br>'Member Login' link on our site and then click the 'Reset Password' link.</div><?php //echo("end of IF bad<br>"); } //echo("78:end of first IF<br>"); } ?> </div> </div> </div> <?php include('includes/footer.php');?> </body> </html> With a prior version of Php, this code was acceptable.
$query = sqlsrv_query($conn, $sql);if ($query === false){ exit("<pre>".print_r(sqlsrv_errors(), true));}while ($row = sqlsrv_fetch_array($query)){ $sumUsageKWH += $row[totalUsage];}sqlsrv_free_stmt($query);?>Now, with php 5.6.3, I have to add a couple of things. $query = sqlsrv_query($conn, $sql);if ($query === false){ exit("<pre>".print_r(sqlsrv_errors(), true));}while ($row = sqlsrv_fetch_array($query)){ $sumUsageKWH += $row['totalUsage'];}sqlsrv_free_stmt($query);?>due to an error prompt. Once I make the corrections, I have a new errors all over the place. Is there a difference in defining a variable with 5.6.3? Edited by Butterbean, 10 January 2015 - 01:49 PM. I am making a php/ajax chat, when a post is sent to the chat, a timestamp using mktime() is stored in the database to show when that post was sent. My concern is that I am from England and my timestamp is GMT +0. Will people from different locations around the world see the wrong times that other users post into the chat? If so what do I need to do to make this work ideally? Thanks Hi All, I created a website which runs perfectly on one server but now I transferred the website to another server I get all kinds of errors like, Undefined variables and so on. How is this possible. I thought it was all in the code. Marco Hi, I have 2 db fields with timestamp datatype (ClockingInDate and ClockingOutDate) and i am trying to get the difference between them then update the new db called duration with float datatype field. PHP: if (isset($_POST["clockout"])){ $result3=mysqli_query($con, "select * from attendance_records where OracleID='$session_id'")or die('Error In Session'); $row3=mysqli_fetch_array($result3); $end_date = $row3['ClockingOutDate']; $startdate = $row3['ClockingInDate']; $diff = strtotime($end_date) - strtotime($startdate); $fullDays = floor($diff/(60*60*24)); $fullHours = floor(($diff-($fullDays*60*60*24))/(60*60)); $fullMinutes = floor(($diff-($fullDays*60*60*24)-($fullHours*60*60))/60); $duration = $fullMinutes; $query3=mysqli_query($con, "update attendance_records set Duration = '$duration' where OracleID='$session_id' and isdone='$isdone'")or die('Error In Session'); header('location:index.php'); }
* come to think of that again, i always get zero, is it because it never reaches days in my program! I am using this for attendance system so only hours and minutes are used. Please help. Edited March 13, 2020 by ramiwahdanthoughts I don't know if this is the correct type of question to ask here - I built a sandbox about 3 months ago with the latest XAMPP. I know that it came with PHP 5.x [5.2 I think]. I am not at home right now to check it. I just found out that the host server is running 4.4.9. I have no control over the host, or host selection. I am going to attempt to get a database online using basic [I hope] PHP scripts to query the otherwise static database. Are there major differences in the versions that I need to watch out for? I realize that I will now have to get 4.4.9 installed on my sandbox. I plan on using Dreamweaver CS5 to get my pages built. The main site is built and managed by another person using Expression Web 2. I am also unaware if the master.dwt built in Expression can be somehow brought into my PHP for site consistency. I am open to all comments and suggestions. Hello, I am working on a caching class and all I have left to figure out now is the string compression. I am storing files locally on the server and may eventually expand the option for storing it in the database. But I want to reduce file size while not sacrificing speed as much as possible. The first function I used was the bzip2 bzcompress function. It did a great job with a 92% compression rate, but I noticed a half-second to full-second delay in the decompression. So what I would like to know is does anyone know which compression functions offer the most speed and what their compression ratios look like? This is for a simple string (well XML that I have reduced with some string replacements), so there is no pre-compression to it. The compression libraries available to me on my server are these: zlib, zip, and bz2 Thoughts? Thanks, Patrick I have Win 7 home premium, Apache 2.2 (installed using the .msi) and PHP 5.2.14 (downloaded as "php-5.2.14-Win32-VC6-x86.zip", installed manually, it works) on both machines. The other is 32-bit and the other is 64-bit, both Windows 7 Home Premium. When I run the exactly same script on one machine, it does what it is supposed to (32-bit), but on the 64-bit it does not. Basically this appears in two situations (so far): I have a script that reads a (xml) file into a simplexml object, and if this is not successful, it prints an error message. On the 32-bit machine I can import (read) another xml file at once once the first one is processed (into a sqlite database), but on the 64-bit machine it gives me an error originating from the fact that the script did not manage to create the simplexml object. The other situation is when I want to open a specific PDF - file in a browser window (Firefox, the newest one, on the 32-bit machine, IE something newish on the 64-bit). The file exists, the path to the folder is in the Path environment variable, I can open it normally etc on the 64-bit machine, but when I click on a link that is supposed to open the file in a browser window I only get an error message saying that the file does not start with "%PDF.... Needless to say, the precisely same script works just fine on the 32 bit machine. $path_to_image="D:\\path_to_folder\\"; $file_name=$_GET['file_name']; header("Content-disposition: inline; filename=".$path_to_image.$file_name); header("Content-type: application/pdf"); readfile($path_to_image.$file_name); The above code is from the part that receives the file name from a form (other file). Anyone noticed anything like this? Any suggestions? Have been trying to figure this out for days, now... Oh, forgot: In both cases the thing is accessed as/from "localhost". im trying to make a program that changes some files from 0 to 1,but im having some trouble... heres my code, Code: [Select] $id = $_GET["id"]; $file1 = "http://mysite.co.cc/users/".$id."/file1.txt"; $fh = fopen($file1, 'w'); fwrite($fh, "1"); fclose($fh); I followed this tut: http://www.tizag.com/phpT/filewrite.php I cant find anything wrong with the code,but it will not make the file have 1 in it. Greetings, I am trying to write XML using SimpleXML for a web service call. I was having success until the XML got a little more complicated. Here is the XML format where I am running into problems: Code: [Select] <Agent> <Person Last='Smith' First='John'> <Addresses /> <PhoneNumbers> <Phone Type='1' Number='888-555-1212'> </PhoneNumbers> </Person> </Agent> Here is my php: Code: [Select] $xmlOutput = new SimpleXMLElement('<?xml version="1.0"?><ReportRequest> </ReportRequest>'); $xmlOutput->addAttribute('CID','9200'); $xmlOutput->addAttribute('Diagram','1'); $xmlOutput->addAttribute('DueDate','2011-11-15'); $xmlOutput->addAttribute('NumPhotos','6'); $xmlOutput->addAttribute('InspectAfter',''); $xmlOutput->addAttribute('PolicyNumber','JTC0004425'); $reportType = $xmlOutput->addChild('ReportType'); $reportType->addAttribute('CPType','Commercial'); $reportType->addAttribute('SectionIDs',''); $reportType->addAttribute('Description',''); $reportType->addAttribute('ReportTypeID','123'); $locations = $xmlOutput->addChild('Locations')->addChild('Addresses')->addChild('Address'); $locations->addAttribute('Zip','91216'); $locations->addAttribute('City','Chatsworth'); $locations->addAttribute('Line1','123 Main St'); $locations->addAttribute('Line2','Suite 201'); $locations->addAttribute('State','CA'); $locations->addAttribute('Latitude',''); $locations->addAttribute('Longitude',''); $agent = $xmlOutput->addChild('Agent')->addChild('Person')->addChild('Addresses')->addChild('PhoneNumbers')->addChild('Phone'); $agent->addAttribute('Last','Smith'); $agent->addAttribute('Email',''); $agent->addAttribute('First','John'); $agent->addAttribute('Title',''); $agent->addAttribute('Type','1'); $agent->addAttribute('Number','888-555-1212'); $agent->addAttribute('TypeName','Office'); $agent->addAttribute('Extension',''); Header('Content-type: text/xml'); echo $xmlOutput->asXML(); Everything outputs as it should until the line that starts with $agent. I want the output to match the section above. I have tried several variations but I cannot seem to figure it out. I know the current PHP sample doesn't work. Help?? Thanks in advance, John I don't think the start of my code is right?! Code: [Select] echo '<button onclick=\"gohere(viewpub.php?PubID='.$row['PubID'].')" id="button" type="button" class="ui-button ui-widget ui-state-default ui-corner-all ui-button-text-only" role="button" aria-disabled="false"><span class="ui-button-text">View Pub</span></button>'; Please help?! I have a web app hosted on Just Host that I have nearly finished writing but still needs to have coded the ability to write a text file to user's computer. the user should be able to specify where on their computer they would like the file to be stored. Is this possible ? And can you tell me how it's done, or point me to a souce that can tell me I rarely ever ask for help regarding programming, but this has flumoxed me. If it is not possible to do this, then would I have to generate this file on the Host's server (Just Host in my case), then download it ? If this can be done then can you please tell me how, as any info I have found related to file downloads seems a bit obscure thanks in advance Hi everyone. Still new to PHP and to Object-Oriented Programming. My goal for today is to write a few dummy Classes in PHP that do enough so that I can see something on my webpage. I am wondering if there is someone here who would be willing to help in either the forums or one-on-one. It may sound like a silly request, but this is all new to me as a Procedural Programmer who has actively programmed in about 10 years!! Thanks, TomTees I have a code for writing a log file... The code is working fine but it inserts the new details at the bottom of the file but i want to insert in the top... So what function should i use... Here is the file my_log.php Code: [Select] <?php $usname = $_SESSION['usname']; date_default_timezone_set('Asia/Calcutta'); $date = date("l dS \of F Y h:i:s A"); $file = "log.php"; $open = fopen($file, "a+"); fseek($open,289); fwrite($open "<b><br/>USER NAME:</b> ".$usname . "<br/>"); fwrite($open, "<b>Date & Time:</b> ".$date. "<br/>"); fwrite($open, "<b>What have they done :</b> ".$reason . "<br/><br/>"); fclose($open); ?> and here is my log.php file : Code: [Select] <?php session_start(); if($_SESSION['stage']!=1 || $_SESSION['stage2']!=2) {header('location:index.php'); die(" "); } ?> <?php if($_GET['valu']=="view_log") { $reason=" ".$_SESSION['usname']." Viewed the LOG"; include('my_log.php'); header('location:log.php'); die(""); } // bytes till here are 289 //LINE 1 : Log details have to insert here I want to insert every detail from the top of the page but just below the php code.. What should i do... ANy helo would be appreciated Pranshu Agrawal pranshu.a.11@gmail.com Ok, I know how to write to a file, but what I'm looking for is to check if a line of code exists, and if it is, don't recreate it. It would also be nice to not recreate the file either. Code: [Select] $file = fopen("index.html", "w"); fwrite($file,"This is a line of text"); fclose($file); I'm trying to write to a file with the following code. $fh = fopen("../inc/config.php", "a") or die("\r\nCan't open file."); $write = "\$config['database_host'] = {$mysqlh}; \$config['database_user'] = {$mysqlu}; \$config['datbase_pass'] = {$mysqlp}; \$config['datbase_name'] = {$dbn}; \$config['table_prefix'] = {$tp};"; fwrite($fh, $write); fclose($fh); It is printing out "Can't open file", which I guess means it can't find the file or I've given the wrong path. The file that is executing this code is /install and the file I'm trying to write to is /inc/config.php. I thought .. put you up a directory so if I do .. I will be at the root and then do /inc I will be in inc. Can someone please guide me on what I'm doing wrong? Thanks. I'm writing a script that takes user input from a html form and updates the database with the new data. In this example the user is updating the data about the university they attend. The problem with this is, the script to update the database with the new information appears to be not working - the new data is not being added to the database. The SQL queries used in the script work in phpMyadmin, and the variables - $uni and $username - contain the data the correct data. This has me stumped, could someone look over this for me please and tell me what is going wrong here. Code: [Select] <?php include 'connect.php'; session_start(); $_SESSION['username']; if(!(isset($_SESSION['login']) && $_SESSION['login']!= " ")){ header("Location: login.php"); } $username = $_SESSION['username']; $tablename = 'usr_test'; $uni = $_POST['uni']; $uni = stripslashes($uni); $uni = mysql_real_escape_string($uni); $uni = trim($uni); if(isset($uni)) { $username = $_SESSION['username']; $loc = mysql_query("SELECT * FROM usr_test WHERE usr = '$username'"); if (mysql_num_rows($loc) == 0) header("Location:notlogged.php"); else { extract(mysql_fetch_array($loc)); mysql_query("UPDATE usr_test SET uni = ('$uni') WHERE usr = '$username'") or die (mysql_error()); header("Location:profile.php"); } } ?> I am using a script I adapted from a tutorial to print the contents of a text box to a txt file. Basically, it's a really simple way of seeing who has logged in. I only have a handful of users. The problem is, although the text file is being created in the proper folder, it isn't being written to and just remains blank. <div align="center"> <table width="300" border="2" bordercolor="#FFFFFF" style="-moz-border-radius: 18px; -webkit-border-radius: 18px;" height="120" cellpadding="0" cellspacing="0"> <tr> <form name="form1" method="post" action="checklogin.php"> <td> <table width="100%" border="0" cellpadding="3" cellspacing="1" background="images/loginbg.jpg" style="-moz-border-radius: 15px; -webkit-border-radius: 15px;"> <tr align="center"> <td colspan="3"><font color="#FFFFFF"><strong>Family Login </strong></font></td> </tr> <tr> <td width="78"><font color="#000000">Username</font></td> <td width="6">:</td> <td width="294"><input name="myusername" type="text" id="myusername"> <?php $myusername = $_POST['myusername']; $data = "$myusername\n"; //open the file and choose the mode $fh = fopen("logs/login.txt", "a"); fwrite($fh, $data); fclose($fh); ?></td> </tr> <tr> <td><font color="#000000">Password</font></td> <td>:</td> <td><input name="mypassword" type="password" id="mypassword"></td> </tr> <tr> <td> </td> <td> </td> <td><input type="submit" name="Submit" value="Login"> </td> </tr> </table> </td> </form> </tr> </table> </div> I'm not sure what's going wrong but I'm guessing it's the placing of the php, or at least some of it. I'd quite like to add the time they logged in as well. Any idea's anyone? Greetings,
I am new to these forums, I am working on this assignment, and these are the current issues I am running into.
Notice: Undefined variable: year in G:\EasyPHP-5.3.2i\www\PHP_Projects\ChineseZodiacs\zodiac_year_switch.php on line 77
ie. $year = validateInput($year,"Birth Year");
Notice: Undefined variable: year_count in G:\EasyPHP-5.3.2i\www\PHP_Projects\ChineseZodiacs\zodiac_year_switch.php on line 138
ie. echo "<p>You are person " . $year_count . "to enter " . $year . "</p>\n";
Honestly, I believe they are linked, because what should be happening, as the user enters the year, and hits submit, it should create a file called counts/$year.txt - $year should equal the entered data in the textbox, any help would be appreciated.
Thank you for your help.
<!DOCTYPE html> <head> <title>Write to and From a File</title> <meta http-equiv="content-type" content="text/html; charset=iso-8859-1" /> <?php $dir = "counts"; if ( !file_exists($dir)) { mkdir ($dir, 0777); } function validateInput($year, $fieldname) { global $errorCount; if (empty($year)) { echo "\"$fieldname\" is a required field.<br />\n"; ++$errorCount; $retval = ""; } else { // if the field on the form has been filled in if(is_numeric($year)) { if($year >=1900 && $year <=2014) { $retval = $year; } else { ++$errorCount; echo "<p>You must enter a year between 1900 and 2014.</p>\n"; } } else { ++$errorCount; echo "<p>The year must be a number.</p>\n"; } } //ends the else for empty return($retval); } //ends the function function displayForm() { ?> <form action = "<?php echo $_SERVER['SCRIPT_NAME']; ?>" method = "post"> <p>Year of Birth: <input type="text" name="year" /></p> <p><input type="reset" value="Clear Form" /> <input type="submit" name="submit" value="Show Me My Sign" /></p> </form> <?php } function StatisticsForYear($year) { global $year_count; $counter_file = "counts/$year.txt"; if (file_exists($counter_file)) { $year_count = file_get_contents($counter_file); file_put_contents($counter_file, ++$year_count); } else { $year_count = 1; file_put_contents($counter_file, $year_count); } return ($year_count); }?> </head> <body> <?php $showForm = true; $errorCount = 0; //$year=$_POST['year']; $zodiac=""; $start_year =1900; if (isset($_POST['submit'])) $year = $_POST['year']; $year = validateInput($year,"Birth Year"); if ($errorCount==0) $showForm = false; else $showForm = true; if ($showForm == true) { //call the displayForm() function displayForm(); } else { //begins the else statement //determine the zodiac $zodiacArray = array("rat", "ox", "tiger", "rabbit", "dragon", "snake", "horse", "goat", "monkey", "rooster", "dog", "pig"); switch (($_POST['year'] - $start_year) % 6) { case 0: $zodiac = $zodiacArray[0]; break; case 1: $zodiac = $zodiacArray[1]; break; case 2: $zodiac = $zodiacArray[2]; break; case 3: $zodiac = $zodiacArray[3]; break; case 4: $zodiac = $zodiacArray[4]; break; case 5: $zodiac = $zodiacArray[5]; break; case 6: $zodiac = $zodiacArray[6]; break; case 7: $zodiac = $zodiacArray[7]; break; case 8: $zodiac = $zodiacArray[8]; break; case 9: $zodiac = $zodiacArray[9]; break; case 10: $zodiac = $zodiacArray[10]; break; case 11: $zodiac = $zodiacArray[11]; break; default: echo "<p>The Zodiac for this year has not been determined.</p>\n"; break; } //ends the switch statement echo "<p>You were born under the sign of the " . $zodiac . ".</p>\n"; echo "<p>You are person " . $year_count . "to enter " . $year . "</p>\n"; } //ends the else statement ?> </body> </html> Edited by mstevens, 16 October 2014 - 06:36 PM. |