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PHP - Convert Files To Other Format
Hi I was going to start a new project which need to convert files from one fomrat to other like, you can check a site here online-convert.com , there they give user to convert in various fomats. please check
my question is i have idea how to do these conversion with ffmpeg and php. Code: [Select] Audio converter Video converter Image converter Hash generator can someone please tell me how to do these conversion. Code: [Select] Document converter Ebook converter Thanks for any help Similar Tutorials
Hello All,
function convertTimeFormat($time12Hour) {
// Initialized required variable to an empty string.
$time24Hour = "";
// Used explode() function to break the string into an array and stored its value in $Split variable.
$Split = explode(":",$time12Hour); // print_r(explode (":", $time12Hour)); => Array ( [0] => 09 [1] => 50 [2] => 08AM )
// Retrieved only "hour" from the array and stored in $Hour variable.
$Hour = $Split[0];
$Split[2] = substr($Split[2],0,2);
// Used stripos() function to find the position of the first occurrence of a string inside another string.
if($Hour == '12' && strpos($time12Hour,"AM")!== FALSE) {
// Code here
} elseif(strpos($time12Hour,"PM")!== FALSE && $Hour != "12") {
// code here
}
return $time24Hour;
}
$time12Hour = "09:50:08AM";
$result = convertTimeFormat($time12Hour);
print_r($result);
/*
Input : "09:50:08AM";
Output : "21:50:08PM";
*/
Hi all, I am currently making a website that has e-custom functions and a back end for the client. I want them to be able to upload images - but they need to be transparent. I do not want to leave this in the hands of the client, so I am looking at ways of using the GD library to make the change I got no issue with the png/gif type for upload/resize function since this type already transparent background but my major problems is how to deal with jpeg/jpg image type which is their background was not a transparent...so is it possible I can change/ convert to png/gif type upon successful of uploading image...so the new final image will be png/gif type with transparent background...is it doable...I am not even sure it is possible...? Thanks for any help.. I have multiple datetimes. The format is dd-mm-yy, hh:mm. I want to insert it into a table using mysql. However mysql format is yy-mm-dd, hh:mm:ss. How can i do it and what type should i use (datetime?timestamp?). Thanks for your help!! Can anyone please tell me how I convert DD-MM-YYY (text) to TIME (unix) thought I'd say that I have this line at the top of all my pages, just in case it means a different code. Code: [Select] date_default_timezone_set('Europe/London'); //### Set the default timezone while I'm reading the cell value '20/09/1980' from an excel file using phpexcel class method $student[$i]['d_o_b'] = $objWorksheet->getCell('G' . $intRow)->getValue(); getting the value as '29484' pls help me to convert it into the date format again. Hi, I need to post to a form with cURL. I'am sending strings in Headers format... There are some documentation or some function that translates from the human readable format to the Headers format? For example: Human readable format: Quote Vendo bicicleta. Como nova. Headers format: Quote Vendo%20bicicleta.%20Como%20nova. The problem is not the spaces but more the accents. I write in Portuguese. Can you give me some clue? Best Regards, Does anyone know how I can convert linux epoch number such as 1292878800 to the UTC format? Ricky Hi. I have an input field where a date is entered, format dd-mm-yy. I need to query the database to see if this date exists. How can I convert the date to yyyymmdd before the query? Thanks Hi, I have a connection set up to an API using a PHP script - the API sends back data in JSON format, and if I capture it and echo it, it displays in extremely unfriendly format on the screen. I've tried to find a way to convert this data into readable format, ideally in a HTML table, but although there are articles on converting manually inputted JSON data into a HTML table using Javascript, I can't find a way to do it from a PHP variable. This is what I have so far:
if ($_POST['getcompany']) {
$companyname = $_POST['_Name'];
$ch = curl_init();
$data_array2 = array(
'token' => $token
);
$make_call2 = json_encode($data_array2);
//echo 'Token is '.$token;
$token2 = substr($token, 14);
$token3 = substr($token2, 0, -3);
//echo 'Token 2 is '.$token3;
//echo 'Company Name is '.$companyname;
//curl_setopt($ch, CURLOPT_GET, 1);
//curl_setopt($ch, CURLOPT_POSTFIELDS, $make_call2);
curl_setopt($ch, CURLOPT_HTTPHEADER, array('Content-Type: application/json','Authorization: '.$token3.''));
curl_setopt($ch, CURLOPT_RETURNTRANSFER, true);
curl_setopt($ch, CURLOPT_URL, 'https://connectionurl?countries=GB&name='.$companyname);
//Execute the request
$result = curl_exec($ch);
echo 'Companies: '.$result; //This displays the data provided by the search, but is in JSON format
So I need a way to get the data held in $result, into a HTML table. Any idea how I can do this? Hi, I have songs that I have uploaded. There are tracks in each song. So I want my users to click download and they'll be able to download all of the tracks combined in a zip file. I have seen this hapening on several sites. Can any body tell me how that works using PHP codes / classes Regards, Faisal We have a site that uses archived Realmedia video files, but we would like to have a automated way of converting those uploaded videos into seperate podcats for user download. Is there a way using PHP to do this? I have just started learning PHP and have no idea if this is even possible. I am trying to find out how to convert HTML code to ePub format dynamically, i know it can be done, but i was wondering if anyone had a tutorial i could follow or something, Thanks. I am trying to convert 6 files into a single 1 php file. I have attached the original files. I need help because I don't know where I am going wrong. this what I have done so far : <?php session_start(); if ($_SESSION['ON'] =="FALSE" || $_SESSION['ON']==null) { header( 'Location: index.php?error=invalid-login' ); session_unset(); session_destroy(); exit(); } ?> <html><head><meta http-equiv="content-type" content="text/html; charset=iso-8859-1"> <title>LOGIN WEB SESSION</title> <link rel="stylesheet" type="text/css" href="loginsession.css" /> </head> <body> <?php // If the step is one, show the correct form // if ($step == 0) { echo '<form action="index.php?step=2" method="post"> <table> <tr><td width="100">Username:</td><td width="200"><input type="text" name="username"></td></tr> <tr><td width="100">Password:</td><td width="200"><input type="password" name="password"></td></tr> <tr><td colspan="2" align="center"><input type="submit" value="Login"></td></tr> </table> </form>'; } else if ($step == 1) { // Create the step 2 section of the page // function clean($data) { $data = trim($data); $data = stripslashes($data); $data = htmlspecialchars($data); return $data; } $user = clean($_POST['username']); $pass = clean($_POST['password']); if ($user == "webdeveloper" && $pass == "master") { session_start(); $_SESSION['username'] = $user; $_SESSION['password'] = $pass; $_SESSION['ON']="TRUE"; $lifetime=600; setcookie(session_name(),session_id(),time()+$lifetime); header( 'Location: index.php?step=2' ) ; exit(); } else { header( 'Location: index.php' ); session_destroy(); exit(); } } else if ($step == 2) <div>LOGIN WELCOME</div> <div> HERE IS YOUR USER DATA:<br /> <label class="data">username:'; <?php echo $_SESSION['username'] ?> <br> password: <?php echo $_SESSION['password'] ?> <br></label> HERE IS YOUR SESSION DATA:<br /> <label class="data"> <?php echo (session_name().": ".session_id()) ?><br> <?php echo ("SESSION DATA: ".session_encode() )?> </label> </div>index.php?step=3">Logoff</a></div> } else if ($step == 3) { // Create the step 4 section of the page // header( 'Location: index.php' ); session_start(); session_unset(); session_destroy(); exit(); } ?> </body> </html> I have tried a large number of "solutions" to this but everytime I use them I see 0000-00-00 in my date field instead of the date even though I echoed and can see that the date looks correct. Here's where I'm at: I have a drop down for the month (1-12) and date fields (1-31) as well as a text input field for the year. Using the POST array, I have combined them into the xxxx-xx-xx format that I am using in my field as a date field in mysql. <code> $date_value =$_POST['year'].'-'.$_POST['month'].'-'.$_POST['day']; echo $date_value; </code> This outputs 2012-5-7 in my test echo but 0000-00-00 in the database. I have tried unsuccessfully to use in a numberof suggested versions of: strtotime() mktime Any help would be extremely appreciated. I am aware that I need to validate this data and insure that it is a valid date. That I'm okay with. I would like some help on getting it into the database. I wish to know how i can convert this date 24-09-2010 to this format 2010-09-24 So far I have managed to create an upload process which uploads a picture, updates the database on file location and then tries to upload the db a 2nd time to update the Thumbnails file location (i tried updating the thumbnails location in one go and for some reason this causes failure) But the main problem is that it doesn't upload some files Here is my upload.php
<?php
include 'dbconnect.php';
$statusMsg = '';
$Title = $conn -> real_escape_string($_POST['Title']) ;
$BodyText = $conn -> real_escape_string($_POST['ThreadBody']) ;
// File upload path
$targetDir = "upload/";
$fileName = basename($_FILES["file"]["name"]);
$targetFilePath = $targetDir . $fileName;
$fileType = pathinfo($targetFilePath,PATHINFO_EXTENSION);
$Thumbnail = "upload/Thumbnails/'$fileName'";
if(isset($_POST["submit"]) && !empty($_FILES["file"]["name"])){
// Allow certain file formats
$allowTypes = array('jpg','png','jpeg','gif','pdf', "webm", "mp4");
if(in_array($fileType, $allowTypes)){
// Upload file to server
if(move_uploaded_file($_FILES["file"]["tmp_name"], $targetFilePath)){
// Insert image file name into database
$insert = $conn->query("INSERT into Threads (Title, ThreadBody, filename) VALUES ('$Title', '$BodyText', '$fileName')");
if($insert){
$statusMsg = "The file ".$fileName. " has been uploaded successfully.";
$targetFilePathArg = escapeshellarg($targetFilePath);
$output=null;
$retval=null;
//exec("convert $targetFilePathArg -resize 300x200 ./upload/Thumbnails/'$fileName'", $output, $retval);
exec("convert $targetFilePathArg -resize 200x200 $Thumbnail", $output, $retval);
echo "REturned with status $retval and output:\n" ;
if ($retval == null) {
echo "Retval is null\n" ;
echo "Thumbnail equals $Thumbnail\n" ;
}
}else{
$statusMsg = "File upload failed, please try again.";
}
}else{
$statusMsg = "Sorry, there was an error uploading your file.";
}
}else{
$statusMsg = 'Sorry, only JPG, JPEG, PNG, GIF, mp4, webm & PDF files are allowed to upload.';
}
}else{
$statusMsg = 'Please select a file to upload.';
}
//Update SQL db by setting the thumbnail column to equal $Thumbnail
$update = $conn->query("update Threads set thumbnail = '$Thumbnail' where filename = '$fileName'");
if($update){
$statusMsg = "Updated the thumbnail to sql correctly.";
echo $statusMsg ; }
else
{ echo "\n Failed to update Thumbnail. Thumbnail equals $Thumbnail" ; }
// Display status message
echo $statusMsg;
?>
And this does work on most files however it is not working on a 9.9mb png file which is named "test.png" I tested on another 3.3 mb gif file and that failed too? For some reason it returns the following Updated the thumbnail to sql correctly.Updated the thumbnail to sql correctly. Whereas on the files it works on it returns REturned with status 0 and output: Retval is null Thumbnail equals upload/Thumbnails/'rainbow-trh-stache.gif' Failed to update Thumbnail. Thumbnail equals upload/Thumbnails/'rainbow-trh-stache.gif'The file rainbow-trh-stache.gif has been uploaded successfully. Any idea on why this is? Hello I have a simple question about file handling... Is it possible to list all files in directories / subdirectories, and then read ALL files in those dirs, and put the content of their file into an array? Like this: array: [SomePath/test.php] = "All In this php file is being read by a new smart function!"; [SomePath/Weird/hello.txt = "Hello world. This is me and im just trying to get some help!";and so on, until no further files exists in that rootdir. All my attempts went totally crazy and none of them works... therefore i need to ask you for help. Do you have any ideas how to do this? If so, how can I be able to do it? Thanks in Advance, pros I am using WPSQT plugin in my blog site .I code some files in PHP also.how to add that files in plugin files.
I have the following code in javascript, I would like to rewrite it in PHP, if someone can help thank you very much. my code: http://pastebin.com/Jnt8RiYj |
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