PHP - Multiple Joins

I have this code which should get all the results from forum_forums and list them in their respective parents using forum_forums.parent_id. It does work sort of but it repeats one of them and doesnt include all of them.

Can anyone see where i am going wrong?

$parent_info_query = $db->query("SELECT 
                    parent_id,
                    parent_name
                    FROM ".DB_PREFIX."parents")
                    or die(mysql_error());

while ($parent_info = mysql_fetch_object($parent_info_query)) { 
 
// Add parent_id into variable for later query
 
 $parent_id = $parent_info->parent_id;

echo '<table class="forum_table" onclick="expandCollapseTable(this)">
<tr id="tr1">
<th class="forum_left_corner"></th>
<th class="forum_parent_name">'.$parent_info->parent_name.'</th>
<th class="empty"></th>
<th class="empty"></th>
<th class="forum_last_post_header">'.LAST_POST.'</th>
</tr>';

// Get Forum information from DB to show all forums
// including who the last post was posted by

$forum_info_query = $db->query("SELECT 

                    ".DB_PREFIX."forums.forum_id,
                    ".DB_PREFIX."forums.forum_name,
                    ".DB_PREFIX."forums.forum_description,
                    ".DB_PREFIX."forums.forum_topics,
                    ".DB_PREFIX."forums.forum_posts,
                    ".DB_PREFIX."forums.forum_last_poster,
                    ".DB_PREFIX."forums.forum_last_post_time,
                    ".DB_PREFIX."forums.forum_last_post,
                    
                    ".DB_PREFIX."members.user_id,
                    ".DB_PREFIX."members.user_username,
                    ".DB_PREFIX."members.user_group,
                    
                    ".DB_PREFIX."topics.topic_id,
                    ".DB_PREFIX."topics.topic_name
                    
                    FROM ".DB_PREFIX."forums
                    
                    JOIN ".DB_PREFIX."members
                    
                    ON ".DB_PREFIX."forums.forum_last_poster
                    = ".DB_PREFIX."members.user_id
                    
                    JOIN ".DB_PREFIX."topics
                    
                    ON ".DB_PREFIX."forums.forum_id
                    = ".DB_PREFIX."topics.forum_id
                    
                    WHERE ".DB_PREFIX."forums.parent_id 
                    = $parent_id") 
                    
                    or trigger_error("SQL", E_USER_ERROR);
                    
while ($forum_info = mysql_fetch_object($forum_info_query)) {

Hi,

I'm trying to a query to check whether a record has a reference in two other tables, I have the following:


Explain SELECT COUNT(*) AS new FROM entity_details
  LEFT JOIN entity_turned_prospect
ON entity_details.id = entity_turned_prospect.entityRef
LEFT JOIN entity_turned_customer
ON entity_details.id = entity_turned_customer.entityRef
 WHERE entity_details.ownerRef = 41
    AND entity_details.typeRef = 4
 AND entity_details.dateCreated = MONTH(NOW())
    AND entity_turned_prospect.id = NULL
 AND entity_turned_customer.id = NULL


But I get 0 results returned when I know for a fact there should be some.

If I change the count to just select * I then get an error:

You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'AS new FROM entity_details, LEFT JOIN entity_turned_prospect ON' at line 1

Could someone show me how to fix this?

Check out my code below and you will see what I am trying to do.

I cannot figure out what is going wrong.
Warning: mysql_fetch_array(): supplied argument is not a valid MySQL result resource in /home/mskordus/public_html/index.php on line 25

Code: [Select]
<?php
$result = mysql_query("SELECT * FROM students,teachers,specialEd,course,sched,notes WHERE
   students.studentId=notes.studentId AND
   students.studentId=sched.studentId AND
   students.teacherId=teachers.teacherId AND
   students.specialId=specialEd.specialId AND
   students.courseId=course.courseId AND
   ");
echo "<table>";
while ($row = mysql_fetch_array($result)){
echo "<tr>";
echo "<td>" . $row['students.fName'] . "</td>";
echo "<td>" . $row['teachers.fName'] . "</td>";
echo "</tr>";
}
echo "</table>";
?>

This topic has been moved to MySQL Help.

http://www.phpfreaks.com/forums/index.php?topic=322128.0

I have created a file with this basic structure in the referals table:
refREFER = the referer, person who sent the referal link out
refREFED = the refered person, the one who signed up with the link
refREFERIP = the referer's IP
refREFEDIP = the refered person's IP

I'm trying to create a code that will list any user that has signed up on the same IP with a referal link. Everything works except the Refered column, which I can't seem to figure out how to do. Basically I have made the refREFER = the userid in the users table, so it can be output as a username. However I want to do the same with the refREFED but don't know how. Here's my code so far:


<?php
include "globals.php";
if($ir['user_level'] != 2 && $ir['user_level'] != 3) //User level check
{
    die("You can't access this page");
}

$q=mysql_query("SELECT u.userid, u.username, u.laston, r.* 
FROM users u 
LEFT JOIN referals r ON r.refREFER=u.userid 
WHERE r.refREFERIP=r.refREFEDIP 
ORDER BY userid ASC",$c); //Selecting everything that's needed

print "<center><br /><b><font color=white><h1>Referral Multis</h1></b><br />

<table width=75% border=1>
<tr style='background:black'>
<th><font color=grey>Referer</font></th>
<th><font color=grey>Refered</font></th>
<th><font color=grey>IP</font></th> 
<th><font color=grey>Time</font></th>
</tr>";
while(($r=mysql_fetch_array($q) or die(mysql_error()))) //Making all of the select stuff into $r
{
$reftime = date('F j, Y g:i:s a', $r['refTIME']);
if($r['laston'] >= time()-60*60) { $on="<font color=green><b>Online</b></font>"; } else { $on="<font color=red><b>Offline</b></font>"; }
print "
<tr> 
<td><a href='viewuser.php?u={$r['userid']}'><font color=brown><b>{$r['username']}</b></font></a> [{$r['refREFER']}]</td>
<td> {$r['username']} - {$r['refREFED']}</td>
<td>{$r['refREFERIP']}</td>
<td>$reftime</td>
</tr>";
}
print "</table>";

$h->endpage();

?>


At the moment under the Refered column it shows the wrong username, but the correct ID. Any ideas?

This topic has been moved to MySQL Help.

http://www.phpfreaks.com/forums/index.php?topic=313836.0

This topic has been moved to MySQL Help.

http://www.phpfreaks.com/forums/index.php?topic=315743.0

This topic has been moved to MySQL Help.

http://www.phpfreaks.com/forums/index.php?topic=320409.0

This topic has been moved to MySQL Help.

http://www.phpfreaks.com/forums/index.php?topic=351561.0

Ok I'm trying to insert multiple rows by using a while loop but having problems. At the same time, need to open a new mysql connection while running the insert query, close it then open the previous mysql connection.

I managed to insert multiple queries before using a loop, but for this time, the loop does not work? 
I think it is because I am opening another connection... yh that would make sense actually?

Here is the code:


$users = safe_query("SELECT * FROM ".PREFIX."user");
       while($dp=mysql_fetch_array($users)) { 
          
   $username = $dp['username'];
 $nickname = $dp['nickname'];
 $pwd1 = $dp['password']; 
 $mail = $dp['email'];
 $ip_add = $dp['ip'];
 $wsID = $dp['userID'];
 $registerdate = $dp['registerdate'];
 $birthday = $dp['birthday'];
 $avatar = $dp['avatar'];
 $icq = $dp['icq']; 
 $hp = $dp['homepage'];
 
echo $username." = 1 username only? :(";
      

// ----- Forum Bridge user insert -----

$result = safe_query("SELECT * FROM `".PREFIX."forum`");
$ds=mysql_fetch_array($result);
$forum_prefix = $ds['prefix'];
define(PREFIX_FORUM, $forum_prefix);
define(FORUMREG_DEBUG, 0);

$con = mysql_connect($ds['host'], $ds['user'], $ds['password']) or system_error('ERROR: Can not connect to MySQL-Server');
$condb = mysql_select_db($ds['db'], $con) or system_error('ERROR: Can not connect to database "'.$ds['db'].'"');
                
include('../_phpbb_func.php');
$phpbbpass = phpbb_hash($pwd1);
$phpbbmailhash = phpbb_email_hash($mail);
$phpbbsalt = unique_id();

safe_query("INSERT INTO `".PREFIX_FORUM."users` (`username`, `username_clean`, `user_password`, `user_pass_convert`, `user_email`, `user_email_hash`, `group_id`, `user_type`, `user_regdate`, `user_passchg`, `user_lastvisit`, `user_lastmark`, `user_new`, `user_options`, `user_form_salt`, `user_ip`, `wsID`, `user_birthday`, `user_avatar`, `user_icq`, `user_website`) VALUES ('$username', '$username', '$phpbbpass', '0', '$mail', '$phpbbmailhash', '2', '0', '$registerdate', '$registerdate', '$registerdate', '$registerdate', '1', '230271', '$phpbbsalt', '$ip_add', '$wsID', '$birthday', '$avatar', '$icq', '$hp')");
if (FORUMREG_DEBUG == '1') {
echo "<p><b>-- DEBUG -- : User added: ".mysql_affected_rows($con)."<br />";
       echo "<br />-- DEBUG -- : Query used: ".end($_mysql_querys)."</b></p><br />";
      
       $result = safe_query("SELECT user_id from ".PREFIX_FORUM."users WHERE username = '$username'");
       $phpbbid = mysql_fetch_row($result);
safe_query("INSERT INTO `".PREFIX_FORUM."user_group` (`group_id`, `user_id`, `group_leader`, `user_pending`) VALUES ('2', '$phpbbid[0]', '0', '0')");
safe_query("INSERT INTO `".PREFIX_FORUM."user_group` (`group_id`, `user_id`, `group_leader`, `user_pending`) VALUES ('7', '$phpbbid[0]', '0', '0')");
mysql_close($con);
}

         include('../_mysql.php');        
         mysql_connect($host, $user, $pwd) or system_error('ERROR: Can not connect to MySQL-Server');
mysql_select_db($db) or system_error('ERROR: Can not connect to database "'.$db.'"');
       
       }



So I need to be able to insert these rows using the while loop.. how can I do this?

I really appreciate any help.

First, Happy X-Mas to all!


I want to do a form for entering dog-show results. On first site of form the user is able to enter how many dogs for each class (there are youth and open class for example) he want to insert. So on second site there will be formfields for every dog in every class, created with php. User should be able to take dogname from jquery autocomplete - this works for multiple fields. But i need the according id to the dogname - and actual only one id is given - the first one is changing by choosing from autocomplete in next fields...

Data came from a json array like

0: {dogidindatabase: "9892", value: "Excalibur Khali des Gardiens de la Cour ",…}
dogidindatabase: "9892"
label: "<img src='../main/img/female.png' height='20'>Excalibur Khali des Gardiens de la Cour   "
value: "Excalibur Khali des Gardiens de la Cour   "
1: {dogidindatabase: "15942", value: "Excalibur from Bandit's World Kalli",…}
dogidindatabase: "15942"
label: "<img src='../main/img/male.png' height='20'>Excalibur from Bandit's World   Kalli"
value: "Excalibur from Bandit's World   Kalli"

all i need is inside ...


the script in form is

<script type='text/javascript'>
		//<![CDATA[
		$(function() {
		
				$(".dog").autocomplete({
				source: "xxx.php",
				minLength: 3,
				select: function(event, ui) {
					$('#dogidindatabase').val(ui.item.dogidindatabase);
					}
			});
			
			$["ui"]["autocomplete"].prototype["_renderItem"] = function( ul, item) {
				return $( "<li></li>" ) 
  				.data( "item.autocomplete", item )
  				.append( $( "<a></a>" ).html( item.label ) )
  				.appendTo( ul );
			};
	
		});
		//]]>
</script>

and the form looked like

<input type='text' name='dog' class='dog' value='".strip_tags(${'dogname' .($countbabymale+1)})."' size='35' data-required='true' /><br>
	
<input class='readonly' readonly='readonly' type='text' id='dogidindatabase' name='dogidindatabase' size='5'  />

I changed in script and form id='dogidindatabase' to class, but it doesn´t work.   Testsite is under http://www.wolfdog-d...how.php?lang=de (only german at first) - Insert a number (higher than 1) under baby 3-6 (first box, the others are not working for testing); submit to get to page 2; you see all post-variables (for testing). Try to insert a dogname in first input-field (choose "exc") and insert first one - the id is under dogname. In second dogname inputfield you can choose second dog - the id for the first one changes to id of seond one ....   How can i get both for every dog?

This seems to be a bit of a challenge but I am creating a multiple page form and on one of the pages I have a select field. I would like the user to have the ability to select multiple options but I am using some functions to move the data in hidden fields from page to page. I don't think my functions are jiving with my my foreach loop cause I keep getting an invalid argument error.

Thanks in advance for any help.

Here is my function:

    function setSelected($fieldName, $fieldValue) {
        if(isset($_POST[$fieldName]) && $_POST[$fieldName] == $fieldValue) {
            echo 'selected="selected"';
        }
    }

And here is my loop:

    $selections = "";
   
    if(isset($_POST["selections"])) {
        foreach ($_POST["selections"] as $selection) {
            $selections .= $selection . ", ";
        }
    }

Hello all,

   I am trying to learn OOP in PHP so please forgive my ignorance. I seem to be having difficulty inserting data into my database from checkbox items. My database has a column for each each fruit. I would like for each column to be populated with either a one(1) for checked or a zero(0)  for not checked. Currently, my attempts have failed. I can either get all checkboxes to insert all zeros or I can get the first column to insert a one(1) while the others as zeros. Is there anybody here that can help me figure out what I am doing wrong and help me to re-work my code so I can get this to work? If anybody can help me using OOP methods that would be fantastic. Thank you all in advance.

 

$preffruit->create_preffruit(array(

  'fruit_apple' => escape(Input::get(['fruit_selection'][0]) ? 1 : 0),
  'fruit_orange' => escape(Input::get(['fruit_selection'][1]) ? 1 : 0),
  'fruit_banana' => escape(Input::get(['fruit_selection'][2]) ? 1 : 0),
  'fruit_pear' => escape(Input::get(['fruit_selection'][3]) ? 1 : 0),
  'fruit_kiwi' => escape(Input::get(['fruit_selection'][4]) ? 1 : 0)

  ));

<input type="checkbox" name="fruit_selection[]" value="fruit_apple">
<input type="checkbox" name="fruit_selection[]" value="fruit_orange">
<input type="checkbox" name="fruit_selection[]" value="fruit_banana">
<input type="checkbox" name="fruit_selection[]" value="fruit_pear">
<input type="checkbox" name="fruit_selection[]" value="fruit_kiwi">



public function insert_preffruit($table, $fields = array()) {
			
			$keys = array_keys($fields);
			$values = '';
			$x = 1;			
			
			foreach($fields as $field) {
				$values .= '?';
				if($x < count($fields)) {
					$values .= ', ';
				}
				$x++;
			}		
				
				$sql = "INSERT INTO preffruit (`user_id`, `" . implode('`, `', $keys) . "`) VALUES (LAST_INSERT_ID(), {$values})";		
			
			if(!$this->query($sql, $fields)->error()) {
				return true;
			}			
			
			return false;
		}

 

Edited September 23, 2020 by ke-jo

Ok so i want to grab an id from the checkbox then grab the option drop down associated with that check box and update a mysql row here is my code so far

any help is awesome help taaaanks guys

<?php
mysql_connect("localhost", "root", "root") or die(mysql_error());
mysql_select_db("db1") or die(mysql_error());
$query = "SELECT * FROM tickets ORDER BY id DESC";
$result = mysql_query($query) or die(mysql_error());

while($row = mysql_fetch_array($result))
{

print "<input name='delete[]' value='{$row['id']}' type='checkbox'>";
mysql_connect("localhost", "root", "root") or die(mysql_error());
mysql_select_db("db1") or die(mysql_error());
$query2 = "SELECT * FROM admin";
$result2 = mysql_query($query2) or die(mysql_error());
print "<form name='namestoupdate' method='post' action='update.php'>\n";
print '<select>';
while($row2 = mysql_fetch_array($result2))
{
if ($row2['priv']==prov){print '<option value="'.$row2['user'].'" name="prov['.$i++.']">'.$row2['user'].'</option>';}
}
print '</select>';
print "<input type='submit' value='submit' />";
print "</form>";
}
?>


Visual aid

does anyone have a code todo this? a snippet or soemthing ive tried a few diffrent ones ive seen but nothing that works.. it takes whats submited in search, then takes the words, breaks them up and creates a query string with all the diffrent feilds... here is what phpadmin produces when i search

 SELECT *  FROM `breedclads`.`activeamahorse` WHERE (`id_entered` LIKE '%green%' OR `uuid` LIKE '%green%' OR `ama_hr_coat` LIKE '%green%' OR `breedable` LIKE '%green%' OR `ama_hr_sex` LIKE '%green%' OR `ama_hr_age` LIKE '%green%' OR `date_entered` LIKE '%green%' OR `ama_hr_eyes` LIKE '%green%' OR `ama_hr_eyes_type` LIKE '%green%' OR `ama_hr_mane` LIKE '%green%' OR `ama_hr_tail` LIKE '%green%' OR `ama_hr_luster_coat` LIKE '%green%' OR `ama_hr_luster_hair` LIKE '%green%' OR `ama_hr_gleam_coat` LIKE '%green%' OR `ama_hr_gleam_hair` LIKE '%green%' OR `ama_hr_parents` LIKE '%green%' OR `ama_hr_sale_type` LIKE '%green%' OR `ama_hr_sale_price` LIKE '%green%' OR `ama_hr_location` LIKE '%green%' OR `auction_date` LIKE '%green%' OR `picture_type` LIKE '%green%' OR `picture_name` LIKE '%green%' OR `picture_size` LIKE '%green%' OR `picture_content` LIKE '%green%' OR `ama_hr_coat_type` LIKE '%green%' OR `ama_hr_coat_gloom` LIKE '%green%' OR `ama_hr_hair_gloom` LIKE '%green%' OR `ama_hr_slurl` LIKE '%green%' OR `class_link_key` LIKE '%green%')  AND  (`id_entered` LIKE '%albino%' OR `uuid` LIKE '%albino%' OR `ama_hr_coat` LIKE '%albino%' OR `breedable` LIKE '%albino%' OR `ama_hr_sex` LIKE '%albino%' OR `ama_hr_age` LIKE '%albino%' OR `date_entered` LIKE '%albino%' OR `ama_hr_eyes` LIKE '%albino%' OR `ama_hr_eyes_type` LIKE '%albino%' OR `ama_hr_mane` LIKE '%albino%' OR `ama_hr_tail` LIKE '%albino%' OR `ama_hr_luster_coat` LIKE '%albino%' OR `ama_hr_luster_hair` LIKE '%albino%' OR `ama_hr_gleam_coat` LIKE '%albino%' OR `ama_hr_gleam_hair` LIKE '%albino%' OR `ama_hr_parents` LIKE '%albino%' OR `ama_hr_sale_type` LIKE '%albino%' OR `ama_hr_sale_price` LIKE '%albino%' OR `ama_hr_location` LIKE '%albino%' OR `auction_date` LIKE '%albino%' OR `picture_type` LIKE '%albino%' OR `picture_name` LIKE '%albino%' OR `picture_size` LIKE '%albino%' OR `picture_content` LIKE '%albino%' OR `ama_hr_coat_type` LIKE '%albino%' OR `ama_hr_coat_gloom` LIKE '%albino%' OR `ama_hr_hair_gloom` LIKE '%albino%' OR `ama_hr_slurl` LIKE '%albino%' OR `class_link_key` LIKE '%albino%')  AND  (`id_entered` LIKE '%69%' OR `uuid` LIKE '%69%' OR `ama_hr_coat` LIKE '%69%' OR `breedable` LIKE '%69%' OR `ama_hr_sex` LIKE '%69%' OR `ama_hr_age` LIKE '%69%' OR `date_entered` LIKE '%69%' OR `ama_hr_eyes` LIKE '%69%' OR `ama_hr_eyes_type` LIKE '%69%' OR `ama_hr_mane` LIKE '%69%' OR `ama_hr_tail` LIKE '%69%' OR `ama_hr_luster_coat` LIKE '%69%' OR `ama_hr_luster_hair` LIKE '%69%' OR `ama_hr_gleam_coat` LIKE '%69%' OR `ama_hr_gleam_hair` LIKE '%69%' OR `ama_hr_parents` LIKE '%69%' OR `ama_hr_sale_type` LIKE '%69%' OR `ama_hr_sale_price` LIKE '%69%' OR `ama_hr_location` LIKE '%69%' OR `auction_date` LIKE '%69%' OR `picture_type` LIKE '%69%' OR `picture_name` LIKE '%69%' OR `picture_size` LIKE '%69%' OR `picture_content` LIKE '%69%' OR `ama_hr_coat_type` LIKE '%69%' OR `ama_hr_coat_gloom` LIKE '%69%' OR `ama_hr_hair_gloom` LIKE '%69%' OR `ama_hr_slurl` LIKE '%69%' OR `class_link_key` LIKE '%69%')




i need this to be made when people search with mutliple words  as you can see it searchs each feilds for the green then each feild for albino, so on.. but i wont ever know what there searching for

Please help me, thanks