PHP - Alias Field Names
Hi all. I've got a little function to generate a simple form depending on the input. What I'd like to do is alias the field names that get output to make them a little more human readable. However, I'm not entirely sure how to do that with the output that I get.
The function.... function build_form($table_name){ $result=mysql_query("SELECT * FROM $table_name"); $num=mysql_num_rows($result); $i=1; echo "<table>"; while ($i < mysql_num_fields($result)) { $fields=mysql_fetch_field($result,$i); echo "<tr><td>" . $fields->name . "</td><td><input type=\"text\" size=\"30\" name=\"" . $fields->name . "\" /></td></tr>"; $i++; }; echo "</table>"; }; Q: Where would I have to modify the output from mysql_fetch_field? My modified function... function build_form($table_name){ $result=mysql_query("SELECT * FROM $table_name"); $num=mysql_num_rows($result); $i=1; echo "<table>"; while ($i < mysql_num_fields($result)) { $fields=mysql_fetch_field($result,$i); $field_name=str_replace("_"," ",$fields->name); echo "<tr><td>" . $field_name . "</td><td><input type=\"text\" size=\"30\" name=\"" . $field_name . "\" /></td></tr>"; $i++; }; echo "</table>"; }; Not sure if that will work, but am I heading in the right direction? Any help is much appreciated! Similar TutorialsI have the following mysql query: Code: [Select] $lead_query=$this->db->query(" SELECT `first_name`, `last_name` , `state` FROM leads WHERE `lead_id`='$lead_id' "); $this->view->lead_query=$lead_query->fetchALL(); Now when I retrieve the above details I need to return the first_name last_name together(separated as space) and the name of the key as client_name in the array. I need it that way because when i return a json_encode($lead_query), I want to return the first_name.last_name as client_name. I need to update a particular table and there be a whole lot of field names. I'd like to do it without having to use them the same way you can access then like $row[12] after a "select" query. The standard for updating (at least how I write it) goes like this ... Code: [Select] $query = "UPDATE linguistics SET welcome1='$var3', welcome2='$var4' WHERE language = '$lengua'"; Well, I'd like to do it where I don't have to name welcome1 and welcome2, but instead refer to their numerical position within the database. On a "select" query we can do this. Can this be done on an update? Something perhaps like ... Code: [Select] $query = "UPDATE linguistics SET 3='$var3', 4='$var4' WHERE language = '$lengua'"; ... where 3 and 4 represent the 4th and 5th fields respectively. I know that this particular phrasing doesn't work because I've tried it, but surely there has to be something. This will save me LOTS of time. Thanks!! I would like to echo field names in my table on webpage one by one. I know mySQL has "describe" function which will list the complete table, I am looking for a way to display each field name one by one with other stuff in between them like input field or description. Hi. The idea: I want to pull a client record and simply place all the row columns into editable form field text boxes. Once the user reviews and edits a submit button will update the record. What I have: Code: [Select] $Query01 = "SELECT * FROM `CustomerSignups` WHERE `Id` = '$_GET[Id]'"; $Result01 = mysql_query($Query01) or die("Error 01: " . mysql_error()); while ($get_info = mysql_fetch_row($Result01)) { foreach ($get_info as $field) echo "<p>$field</p>"; It displays as expected, a line for each field. How can I get this to pull the field names also and then I can use those as text box input fields...? I currently have php code that outputs information from my database, but how do i make it also display the name of the fields beside each entry of the database? heres my PHP code: Code: [Select] <?php $server = ""; // Enter your MYSQL server name/address between quotes $username = ""; // Your MYSQL username between quotes $password = ""; // Your MYSQL password between quotes $database = ""; // Your MYSQL database between quotes $con = mysql_connect($server, $username, $password); // Connect to the database if(!$con) { die('Could not connect: ' . mysql_error()); } // If connection failed, stop and display error mysql_select_db($database, $con); // Select database to use // Query database $result = mysql_query("SELECT * FROM Properties"); if (!$result) { echo "Error running query:<br>"; trigger_error(mysql_error()); } elseif(!mysql_num_rows($result)) { // no records found by query. echo "No records found"; } else { $i = 0; echo '<div style="font-family:helvetica; font-size:15px; padding-left:15px; padding-top:20px;">'; while($row = mysql_fetch_array($result)) { // Loop through results $i++; echo '<img class="image1" src="'. $row['images'] .'" />'; //image echo "Displaying record $i<br>\n"; echo "<b>" . $row['id'] . "</b><br>\n"; // Where 'id' is the column/field title in the database echo $row['Location'] . "<br>\n"; // Where 'location' is the column/field title in the database echo $row['Property_type'] . "<br>\n"; // as above echo $row['Number_of_bedrooms'] . "<br>\n"; // .. echo $row['Purchase_type'] . "<br>\n"; // .. echo $row['Price_range'] . "<br>\n"; // .. } echo '</div>'; } mysql_close($con); // Close the connection to the database after results, not before. ?> thanks in advance Okay, so I'm trying to run a query to pull the information from a specific item that they click on in order to edit it. When I run an echo $query, though, it shows the field names rather than the information from the table. How can I make it so that it pulls the information rather than the field names? Here's what I have... <?php include("lib.php"); define("PAGENAME", "Edit Equipment"); if ($player->access < 100) $msg1 = "<font color=\"red\">"; //name error? $error = 0; $query = $db->execute("SELECT * FROM items WHERE id=?", array($_POST['id'])); echo "$id"; $result = mysql_query($query); echo "$query"; $data = mysql_fetch_assoc($result); $msg1 .= "</font>"; //name error? ?> Thanks!! Hi all. The title pretty much says it all. I really have no idea if this is even possible or where to start. A recent dilemma caused me to have to change a field name with some spaces in it. I have a database with ~65 tables, a majority of which were converted from Access. So I'm curious as to how many others have bad field names. Is there a way to use PHP to go through all the field names in a database and remove spaces? This topic has been moved to MySQL Help. http://www.phpfreaks.com/forums/index.php?topic=318312.0 Hi all, I have the following MySQL insert query: Code: [Select] $insert= mysql_query ("INSERT INTO tablename (column1,`".$EXPfields."`) VALUES ('$something','".$EXPvalues."')"); where $EXPfields is an array of table-field-names and $EXPvalues is an array of table-field-values. Now I want to write an equivalent query, but using UPDATE instead of INSERT INTO, but I don't want to write out all the field names/values separately, but again want to use $EXPfields and $EXPvalues. So something like this: Code: [Select] $update = mysql_query ("UPDATE tablename SET (column1,`".$EXPfields."`) = ('$something','".$EXPvalues."') WHERE .... "); Is this possible? If so, what is the proper syntax? Thanks! This topic has been moved to MySQL Help. http://www.phpfreaks.com/forums/index.php?topic=320409.0 This might be better for the Apache forum, but I'll explain anyways. I'm switching up my local dev environment so I can use SVN. I have a directory for all my SVN stuff on my local machine now in /var/svn. When I call $_SERVER['DOCUMENT_ROOT'] its listing the document root as /var/www. For this alias I've setup in apache I want the document root to be /var/svn/myproject. Alot of my includes are failing because of this now. My Php Buddies, I have mysql tbl columns these:
id: Now, I want to display their row data by excluded a few columns. Want to exclude these columns: date_&_time account_activation_code account_activation_status id_verification_video_file_url password
So, the User's (eg. your's) homepage inside his account should display labels like these where labels match the column names but the underscores are removed and each words' first chars CAPITALISED:
Id: 1
For your convenience only PART 1 works. Need help on Part 2 My attempted code:
PART 1 <?php // Check connection if ($conn->connect_error) { die("Connection failed: " . $conn->connect_error); } // Query to get columns from table $query = $conn->query("SELECT COLUMN_NAME FROM INFORMATION_SCHEMA.COLUMNS WHERE TABLE_SCHEMA = 'members' AND TABLE_NAME = 'users'"); while($row = $query->fetch_assoc()){ $result[] = $row; } // Array of all column names $columnArr = array_column($result, 'COLUMN_NAME'); foreach ($columnArr as $value) { echo "<b>$value</b>: ";?><br><?php } ?> PART 2 <?php //Display User Account Details echo "<h3>User: <a href=\"user.php?user=$user\">$user</a> Details</h3>";?><br> <?php $excluded_columns = array("date_&_time","account_activation_code","account_activation_status","id_verification_video_file_url","password"); foreach ($excluded_columns as $value2) { echo "Excluded Column: <b>$value2</b><br>"; } foreach ($columnArr as $value) { if($value != "$value2") { $label = str_replace("_"," ","$value"); $label = ucwords("$label"); //echo "<b>$label</b>: "; echo "$_SESSION[$value]";?><br><?php echo "<b>$label</b>: "; echo "${$value}";?><br><?php } } ?> PROBLEM: Columns from the excluded list still get displayed. Edited November 19, 2018 by phpsaneThis is my first real jump into PHP, I created a small script a few years ago but have not touched it since (or any other programming for that matter), so I'm not sure how to start this. I need a script that I can run once a day through cron and take the date from one table/filed and insert it into a different table/field, converting the human readable date to a Unix date. Table Name: Ads Field: endtime_value (human readable date) to Table Name: Node Field: auto_expire (Converted to Unix time) Both use a field named "nid" as the key field, so the fields should match each nid field from one table to the next. Following a tutorial I have been able to insert into a field certain data, but I don't know how to do it so the nid's match and how to convert the human readable date to Unix time. Thanks in advance!. Hi: I'm going crazy trying to do the following: I'm making a job registration process where the user registers on one php page to the website, must acknowlege and email receipt using an activate php page, then is directed to upload their C.V. (resume) based on the email address they enter in the active page output. I then run an upload page to store the resume in teh MySQL db based on the users email address in the same record. If I isolate the process of the user registering to the db, it works perfectly. If I isolate the file upload process into the db, it works perfect. I simply cannot upload teh file to the existing record based on teh email form field matching the user_email field in the db. With the processes together, teh user is activated, but teh file is not uploaded. Maybe I've simply been at this too long today, but am compeled to get through it by end day. If anyone can help sugest a better way or help me fix this, I will soo greatly appreciate it. My code is as follows for the 2 pages. ---------activate.php------- <?php session_start(); include ('reg_dbc.php'); if (!isset($_GET['usr']) && !isset($_GET['code']) ) { $msg = "ERROR: The code does not match.."; exit(); } $rsCode = mysql_query("SELECT activation_code from subscribers where user_email='$_GET[usr]'") or die(mysql_error()); list($acode) = mysql_fetch_array($rsCode); if ($_GET['code'] == $acode) { mysql_query("update subscribers set user_activated=1 where user_email='$_GET[usr]'") or die(mysql_error()); echo "<h3><center>Thank You! This is step 2 of 3. </h3>Your email is confirmed. Please upload your C.V. now to complete step 3.</center>"; } else { echo "ERROR: Incorrect activation code... not valid"; } ?> <!DOCTYPE html PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN" "http://www.w3.org/TR/html4/loose.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta content="text/html; charset=utf-8" http-equiv="Content-Type" /> <title>Job application activation</title> </head> <body> <center> <br/><br/><br/> <p align="center"> <form name="form1" method="post" action="upload.php" style="padding:5px;"> <p>Re-enter you Email : <input name="email" type="text" id="email"/></p></form> <form enctype="multipart/form-data" action="upload.php" method="POST"> <input type="hidden" name="MAX_FILE_SIZE" value="4000000"> Upload your C.V.: <input name="userfile" type="file" id="userfile"> <input name="upload" type="submit" id="upload" value="Upload your C.V."/></form> </p> </center> </body> </html> --------upload.php---------- <?php session_start(); if (!isset($_GET['usr']) && !isset($_GET['code']) ) { $msg = "ERROR: The code does not match.."; exit(); } if(isset($_POST['upload']) && $_FILES['userfile']['size'] > 0) { $fileName = $_FILES['userfile']['name']; $tmpName = $_FILES['userfile']['tmp_name']; $fileSize = $_FILES['userfile']['size']; $fileType = $_FILES['userfile']['type']; $email = $_POST['email']['user_email']; $fp = fopen($tmpName, 'r'); $content = fread($fp, filesize($tmpName)); $content = addslashes($content); fclose($fp); if(!get_magic_quotes_gpc()) { $fileName = addslashes($fileName); } include 'reg_dbc.php'; $query = "UPDATE subscribers WHERE $email = user_email (name, size, type, content ) ". "VALUES ('$fileName', '$fileSize', '$fileType', '$content')"; mysql_query($query) or die('Error, query failed'); mysql_close($dbname); } ?> <center> <br/> <br/> <br/> <br/> Thank you for uploading your <?php echo "$fileName"; ?> file, completing your registration, and providing us your C.V. for this position. <br/> <br/> <br/> We will contact you if your canditature qualifies. </center> Code: [Select] $new_array2=array_diff($my_array,$itemIds); $updatedb = mysql_query("UPDATE content_type_ads SET field_expire_value = '666' WHERE $new_array2 = field_item_id_value"); "$new_array2" has only 12 digit numbers for each item in the array, and I want to match them to the "field_item_id_value" field in the table, updating the "field_expire_value" field for the record where they match. I know I am close because the UPDATE code works before I add the WHERE statement (it of course adds '666' to EVERY field, but for a noobie it's a start!). (Another quite newbie...) I have already an online booking form. The Form works fine now and I would like to add on one more issue, but the code ignores what I want to check. I have 4 fields: arrival, departure, no. of persons and comments to check. Scenario 1: All field mentioned above are emtpty: Workes fine and message appears: "You have not provided any booking details". Scenario 2: If arrival (date_start) and departure (date_end) is entered, there should be at least an entry either in the field "comment", or in the field "pax". If not, there should be a message: "You have not provided sufficient booking details". INSTEAD: The booking request is sent, which should not be the case. The code is currently: # all fields empty : arrival, departure, pax and comments - error if(empty($data_start) && empty($data_end) && empty($pax)&& empty($comment)){ exit("You have not specified any booking details to submit to us. <br>Please use your browser to go back to the form. <br>If you experience problems with this Form, please e-mail us"); exit; } #If arrival and departure date is entered, there should be at least an entry either in the field "comment", or in the field "pax". if(!isset($data_start) && !isset($data_end) && empty($pax) && empty($comment)){ exit("You have not provided sufficient booking details. <br>Please use your browser to go back to the form. <br>If you experience problems with this Form, please e-mail us"); exit; } The form can be tested at http://www.phuket-beachvillas.com/contact-own/contact-it.php Can someone please check and tell me what's wrong with the code ? Thanks to anyone for any hint. Hi, I'm developing an app using flash AS2 as the front end via PHP and a mySQL database at the backend on my server. what i'm looking to do is update/insert into a table called 'cards' and at the same time update/insert into another table called 'jingle'. There is a field called 'cardID' in jingle that should be the same as the ID number created in 'cards' thus creating a link between entries in the different tables that can be called up as i choose. hope i've been clear i just wouldn't know where to start any help would be appreciated. MySQL client version: 5.0.91 PHPmyAdmin Version information: 3.2.4 thanks in advance Hey , I'm looking for functions names from the GD directory. 1.function that open image. 2.function that getting pixel color. 3.function that changing pixel color. thanks. |