PHP - Open Pdf Within A Section Of A Page.

Hi!

I'd like to echo a text section from pageB.php to pageA.php

Is it possible to mark it up somehow and tell the browser to echo the variable?
I'm thinking something like this should work after some alteration:


pageA:
<?php echo pageb.php/variable; ?>


pageB:

<?php
$variable =


***the content section I want to be displayed on pageA***

";
?>



I'd be very grateful if someone could help me out. (:

hope someone can help me out here, stuck on this page...
This page shows the details of the listing they had just clicked on on the previous page. this part works
If the person logged in is the person who is looking at the page, the email section does not show. this part works
However, the part I cannot get to work, is when the logged in user types their email message and clicks send email. at this point the details of listing stop showing
please SOMEONE HELP ME
thanks in advance, i hope
Code: [Select]
<?php
  // Start the session
  require_once('startsession.php');

  // Insert the page header
  $page_title = 'Listing Details';
  require_once('header.php');

  require_once('connectvars.php');

  // Show the navigation menu
  require_once('navmenu.php');
 

if(isset($_POST['submit'])){
 $dbc = mysqli_connect(DB_HOST, DB_USER, DB_PASSWORD, DB_NAME); 

  // Retrieve the user data from MySQL
  $query1 = 'SELECT email FROM ob_user WHERE username="' . $user_name . '"';
  $data1 = mysqli_query($dbc, $query1);
  $row1 = mysqli_fetch_array($data1);
  
  $email = $row1['email'];
  
 $to = $email;
 $subject = 'OurBazzar response to' . $subject . '';
 $body = $_POST['email'];
 $headers = 'From: caleb.jordan.flax@gmail.com';
 if (mail($to, $subject, $body, $headers)) {
   echo("<p>Message sent!</p>");
  } else {
   echo("<p>Message delivery failed...</p>");
  }
  end();
}



  if (isset($_GET['listing_id']) && isset($_GET['subject']) && isset($_GET['description']) && isset($_GET['price']) && isset($_GET['date']) && isset($_GET['city']) && isset($_GET['state']) && isset($_GET['user_id']) && isset($_GET['category_id'])) {
  
    // Grab the score data from the GET
    $listing_id = $_GET['listing_id'];
    $title = $_GET['subject'];
    $description = $_GET['description'];
    $price = $_GET['price'];
    $date = $_GET['date'];
$city = $_GET['city'];
    $state = $_GET['state'];
    $userid = $_GET['user_id'];
    $categoryid = $_GET['category_id'];

  }

// Connect to the database 
  $dbc = mysqli_connect(DB_HOST, DB_USER, DB_PASSWORD, DB_NAME); 

  // Retrieve the user data from MySQL
  $query = 'SELECT username FROM ob_user WHERE user_id="' . $userid . '"';
  $data = mysqli_query($dbc, $query);
  $row = mysqli_fetch_array($data);

  $query1 = 'SELECT name FROM ob_category WHERE category_id="' . $categoryid . '"';
  $data1 = mysqli_query($dbc, $query1);
  $row1 = mysqli_fetch_array($data1); 
  
$user_name = $row['username'];
$category_name = $row1['name']; 

echo '<table>';
echo '<tr><td colspan="2"><strong>' . $title . '</strong></td></tr>';
echo '<tr><td>Created by: </td><td>' . $user_name . '</td></tr>';
echo '<tr><td>Date created: </td><td>' . $date . '</td></tr>';
echo '<tr><td>Location: </td><td>' . $city . ', ' . $state . '</td></tr>';
echo '<tr><td>Category: </td><td>' . $category_name . '</td></tr>';
echo '<tr><td>Description: </td><td>' . $description . '</td></tr>';
echo '</table>'; 

if ((isset($_SESSION['username'])) && ($_SESSION['username'] != $user_name)) {

?>

<br />
<form method="post" action="<?php echo $_SERVER['PHP_SELF']; ?>">
<fieldset>
<legend>Send Email to <?php echo $user_name; ?></legend>
<label for="email">Message: </label>
<input type="text" name="email" /><br />
<input type="submit" value="Send Email" name="submit">
</fieldset>

<?php

}
require_once('footer.php');
?>

This topic has been moved to mod_rewrite.

http://www.phpfreaks.com/forums/index.php?topic=318858.0

Hi there again all
I am making a site that has a popout music player. My question is since the player is opened by javascript is there a way to let the original page know that the popout is open?

this is my code which is using to check login from database calledchklogin.php

Code: [Select]
<?php
session_start();
include('connect.php');

$tbl_name="members"; 

mysql_select_db($Db, $link); 


// username and password sent from form
$myusername=$_POST['myusername'];
$mypassword=$_POST['mypassword'];

// To protect MySQL injection (more detail about MySQL injection)
$myusername = stripslashes($myusername);
$mypassword = stripslashes($mypassword);
$myusername = mysql_real_escape_string($myusername);
$mypassword = mysql_real_escape_string($mypassword);
$mypassword = md5($mypassword);

$sql="SELECT * FROM $tbl_name WHERE uname='$myusername' and upass='$mypassword'";
$result=mysql_query($sql,$link);
$row=mysql_fetch_array($result);
                                
// Mysql_num_row is counting table row
$count=mysql_num_rows($result);
// If result matched $myusername and $mypassword, table row must be 1 row

if($count==1){
// Register $myusername, $mypassword and redirect to file "login_success.php"
session_register("username"); //Create the session
session_register("myusername");
session_register("mypassword");
$_SESSION['uname'] = "$myusername";
$_SESSION['utype'] = $row['utype'];

header("location:loginsuccess.php"); 
}
else {
//include ('index.php');
echo ("<script type='text/javascript'> window.alert('Wrong username or password!')</script>");
exit();
}

?>
& this code is from another file called loginsuccess.php

Code: [Select]
<?
session_start();
if(!session_is_registered(myusername)){
header("location:index.php");
exit();
}
require_once("login-index.php");           
?>


so when everything is right in chklogin.php then it open loginsuccess.php after that when all is true then it open
login-index.php after that this page open it show double page one is index.php where the login form & another is this login-index.php at one time