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PHP - In Need Of An External Link Counter Script! Please Help
in need of an external link counter script! please help
cheers matt Similar Tutorialshi hope you all are fine. i have been working on a Email Form (like user fills up the form which send the information to our email) but i was having problem with (URL field i created) link of form is (http://services.shadowaura.com/allquotations/static.php) field which is not working is "Inspirational Website:" when i submit the form it says (Forbidden You don't have permission to access /allquotations/staticworking.php on this server. Additionally, a 404 Not Found error was encountered while trying to use an ErrorDocument to handle the request.) Can some one help me out ????????????? code behind this form is: Code: [Select] <?php /* Email Variables */ $emailSubject = 'Shadow Aura Contact Info!'; $webMaster = '*****@shadowaura.com'; /* Data Variables */ $Name = $_POST['Name']; $email = $_POST['email']; $Cell = $_POST['Cell']; $Phone = $_POST['Phone']; $CompanyName = $_POST['CompanyName']; $TypeOfBusiness = $_POST['TypeOfBusiness']; $Address = $_POST['Address']; $YourBudget = $_POST['YourBudget']; $HaveDomain = $_POST['HaveDomain']; $RunningWeb = $_POST['RunningWeb']; $WebLink = $_POST['WebLink']; $Inspiration1 = $_POST['Inspiration1']; $Inspiration2 = $_POST['Inspiration2']; $NumberPages = $_POST['NumberPages']; $UseFlash = $_POST['UseFlash']; $TimeFrame = $_POST['TimeFrame']; $Provided = $_POST['Provided']; $Comments = $_POST['Comments']; $body = <<<EOD <h1> Static Website Quotation </h1> <br> <b>Name of Client:</b>$Name<br> <b>Your Email:</b>$email<br> <b>Cell Number:</b>$Cell<br> <b>Line Phone Number:</b>$Phone<br> <b>Company Name:</b>$CompanyName<br> <b>Type of Business:</b>$TypeOfBusiness<br> <b>Address:</b>$Address<br> <b>Your Budget:</b>$YourBudget <br> <b>Do you have Domain:</b>$HaveDomain<br> <b>Your Site is Running:</b>$RunningWeb <br> <b>Website Link:</b><a href="$WebLink">$WebLink</a><br> <b>Inspiration:</b>$Inspiration1<br> <b>2nd Inspiration:</b>$Inspiration2<br> <b>Number of Pages:</b>$NumberPages<br> <b>Use Flash:</b>$UseFlash <br> <b>Time Frame:</b>$TimeFrame<br> <b>You will provide:</b>$Provided<br> <b>Comments:</b>$Comments<br> EOD; $headers = "From: $email\r\n"; $headers .= "Content-type: text/html\r\n"; $success = mail($webMaster, $emailSubject, $body, $headers); /* Results rendered as HTML */ $theResults = <<<EOD <html> <head> <title>sent message</title> <meta http-equiv="refresh" content="3;URL=http://services.shadowaura.com/"> <style type="text/css"> <!-- body { background-color: #8CC640; font-family: Verdana, Arial, Helvetica, sans-serif; font-size: 20px; font-style: normal; line-height: normal; font-weight: normal; color: #fec001; text-decoration: none; padding-top: 200px; margin-left: 150px; width: 800px; } --> </style> </head> <div align="center">Your email will be answered soon as possible! You will return to <b>Shadow Aura Services</b> in a few seconds !</div> </div> </body> </html> EOD; echo "$theResults"; ?> I know basically nothing about PHP but i have a few websites i manage that are built with PHP. I plan to learn PHP but for the time being learning Javascript has a wider range of usability for me. That being said, Im trying to link to an XML sitemap using php. in html i would use Code: [Select] <link href="sitemap.xml" /> how can i do this in PHP? I have searched google and such for how to do this but was unable to find an explanation that i could understand as relating to my need. Hello, I am trying to make the buy product button on all single product pages to open in a popup iframe or simular! I am new to java, php and such and I am looking for how to achieve this?
I have been researching this for over a month and nothing seems to work. I am affiliated with Amazon so I need my woocommerce buy product buttons to open a new smaller popup window in front of my site!
I have already had it set to open as _blank, But I really need all my external product button links to open as a popup! Is this possible? I have tried editing cart.php and I know nothing about java. Please help!!
Thank you in advance,
Dee
Folks, When someone click on a link on my webpage and if that Link takes the visitor off my site, then i want to make an entry in my database. But if that link goes back to some other link in my Site then i do not want to Count that link. So, is there any code that lets me detect any outgoing link Click? Cheers Hey, I am currently trying to get a variable created inside a require_once script to be echoed inside the main page that called the require. The script below is a basic idea of what i want to do. I just want to be able to create a basic variable none of this session stuff as its makes life harder at the moment. Thank guys, hope the snippet below gives you a better idea. Main Code: Code: [Select] <body> <?php require_once("makesVariable.php"); <div> // Variable I want to be echo "NOT WORKING" echo $var; </div> ?> </body> External PHP Code: Code: [Select] <?php //Function gets called by previous code to create the needed variable function createTheVariable(){ $var = "I am the variable to be called"; return $var; } ?> Hi, I am very new to PHP (and web developing generally, as well). I have been passing through two different ways of verifying user input in a PHP webpage: 1- By calling a different script file, where the verification logic code is listed and then recall the referer $_SERVER['HTTP_REFERER'] page and pass the result using $_SESSION. (I understood this is basically done to avoid repeating the action in the code with every refreshment of the browser window). 2- By enclosing the verification logic code withing the same PHP page, so the page is a big mix of HTML & PHP. (I understood this is basically done, in order to keep the user input without using $_SESSION and it should save one trip of data transfer.) For me, I see both are working; still I want to learn the best coding practices. So your advice is appreciated, and please feel free to correct my, if I missed something about both methods. I would like it to list a bunch of music in a folder but the user dosent have accesses to except me. So the page he can view will list all the files in the other folder and has a downloadable link to it so he can download the files Thanks Dan Hello, I had a web page which had sharing (share issue on facebook, twitter....) and I want to record what each user had shared. So, they will click on alink to share it. I want to call a php function when the user click on a link, whats the best method to do this? Thanks in advance Seems to be a basic question, but I couldn't find an answer nor figure it out on my own. Basically I have a script that takes out specific data out of the database, the script works on its own, now I just need a way to make the user execute it with a link or a button. Example: Category: [Smileys] - [Category2] - [Category3] - etc. As soon as the user clicks on [Smileys] all data in the database which contains the word smileys in the category field gets selected and outputted as a list. Again the script works, I just need to be able to execute it with a button. If I understood it correctly I have to run the script by adding a if (isset($_POST['Smileys'])) { in front of the script. But how do I build the connection with the text link? Hello there Really new by in PHP, I find out your forums and look really professional, so I'm dropping in some questions. Maybe can have some help. I'm setting an old plugin of WP and got some issues. The plugin is really nice and dedicated to create a directory inside a website in WP but regretfully no one take care of that code, so no one to ask for. There are some errors. Example, lets go with the first one. When I (or someone) add a new website in the directory the script does not manage correctly a duplicate submissions. I can submit more times the same url. It is supposed to manage that problem, here is the code that take care of all the errors. Code: [Select] if($title == "" || $url == " " || $url == "http://" || $description == "" || $description == " " || $keyword == "" || $contact_name == "" || $contact_email == "" || !$cat_id) { if($title == "") $error_msg .= "- " . 'Please insert the title of the website!' . " - <br />"; if($url == " " || $url == "http://" ) $error_msg .= "- " . 'Please insert the URL of the website!' . " - <br />"; if(!$cat_id) $error_msg .= "- " . 'Please select a category for the website!' . " - <br />"; if($description == " ") $error_msg .= "- " . 'Please write the description of the website!' . " - <br />"; if($description == "") $error_msg .= "- " . 'Please write the description of the website!' . " - <br />"; if($keyword == "") $error_msg .= "- " . 'Please write the keywords of the website!' . " - <br />"; if($contact_name == "") $error_msg .= "- " . 'Please insert your name!' . " - <br />"; if($contact_email == "") $error_msg .= "- " . 'Please insert your email address!' . " - <br />"; } else { $link_id = $class_link->GetLinkId($cat_id, $url, $title); if ($link_id != "") { $error_msg .= "- " . 'This link currently exist!' . " - <br /> "; } } It is working fine for all the errors but NOT for the last one... is not working, no message ""This link currently exist"" and no error come out after the submission that go in smoothly. So here is the problem.... but can't solve it. Code: [Select] } else { $link_id = $class_link->GetLinkId($cat_id, $url, $title); if ($link_id != "") { $error_msg .= "- " . 'This link currently exist!' . " - <br /> "; } } Any idea? This is my script I want to display but it does not show in the page just blank. <td><object width="220" height="148"><param name="movie" value="http://www.youtube.com/user/THEWORLDOFTRAVEL#p/search/2/uX9nd3xM_MY=1&h1=enUS&color1=0x234900&color3=34900&"></param><param name="allowFullScreen" value="true"></param><param name="allowscriptaccess" value="always"></param><embed src="http://www.youtube.com/user/THEWORLDOFTRAVEL#p/search/2/uX9nd3xM_MY=1&h1=enUS&color1=0x234900&color3=34900&" type="application/x-shockwave-flash" allowscriptaccess="always" allowfullscreen="true" width="220" height="148"></embed></object></td> Hi All, The Problem: I'm trying to learn how to take records from the NAME row of one table (i.e. Tom, Jim, Chris, Mike) and put them into a SELECT (drop down menu) box, then select a name and save it to a DIFFERENT table where the row is also called NAME, and THEN have that selection I just saved show in the SELECT box as SELECTED when the page refreshes. I have found a hundred websites showing how to bind a SELECT box to a table and put them into a SELECT box via $key => $val and even how to save it to ANOTHER textbox on the page, which is a lot easier, but never a step further as described in the first paragraph above. Seems unbelievable to me since it's so common. Maybe I'm just not using the proper search terms/keywords. Here's an example: Let's say you wanted to notify 3 people of your birthday. So, on the notification page, you would enter three names of people you would want notified all in separate input textboxes with [keys]. So, you enter John, Chris, and Tom into three text boxes and save the page. Done. Now, on another page, I have -- say .... five select boxes. For arguments sake, let's just say I click on all of them one at a time. In each of them, I would only see three names (John, Chris, and Tom). Now, in the first SELECT box I click on John. In the second select box I click on Chris, and on the third I click on Tom. Then save the form. I would like to see John, Chris, and Tom in the first three boxes after refreshing and I would like to see SELECT A NAME on the last two Select boxes that we never did anything with. Remember, there are NO default names in the first table with row called NAMES. They are populated by the user and saved to the row. I'm attaching an image of what the page looks like that I want to see the names and be able to select them. Does anyone have a link to a site that shows how to do this... or maybe have something very basic that would show me the process? Or, if not too difficult, maybe you could show me? Thanks in advance for any help! Attached Files Untitled.jpg 24.97KB 0 downloads Hi all, I'm not great with PHP and I have this one problem that I hope you can help with. I have a script that generates an URL. The output string is $shorturl and displays properly when I echo it using Code: [Select] <?php echo '$shorturl' ?>. However, when I try the following script for a Facebook share button Code: [Select] <fb:share-button> <a name="fb_share" type="button" share_url="<?php echo '$shorturl' ?>" href="http://www.facebook.com/sharer.php" layout="button_count">Share</a><script src="http://static.ak.fbcdn.net/connect.php/js/FB.Share" type="text/javascript"></script> </fb:share-button> The resulting URL it produces is: http://</?php+echo+%27http%3A%2F%2Fshelb... Any idea's? Thank you! Goal: To have a gallery that downloads images from the folder I previously uploaded to in a previous script. Bug: When I load the page the thumbnail comes up as broken and when I click on the thumbnail to get the bigger picture it comes up with the following error message: "Firefox doesn't know how to open this address, because the protocol (c) isn't associated with any program." <?php include 'db.inc.php'; //connect to MySQL $db = mysql_connect(MYSQL_HOST, MYSQL_USER, MYSQL_PASSWORD) or die ('Unable to connect. Check your connection parameters.'); mysql_select_db(MYSQL_DB, $db) or die(mysql_error($db)); //change this path to match your images directory $dir ='C:/x/xampp/htdocs/images'; //change this path to match your thumbnail directory $thumbdir = $dir . '/thumbs'; ?> <html> <head> <title>Welcome to our Photo Gallery</title> <style type="text/css"> th { background-color: #999;} .odd_row { background-color: #EEE; } .even_row { background-color: #FFF; } </style> </head> <body> <p>Click on any image to see it full sized.</p> <table style="width:100%;"> <tr> <th>Image</th> <th>Caption</th> <th>Uploaded By</th> <th>Date Uploaded</th> </tr> <?php //get the thumbs $result = mysql_query('SELECT * FROM images') or die(mysql_error()); $odd = true; while ($rows = mysql_fetch_array($result)) { echo ($odd == true) ? '<tr class="odd_row">' : '<tr class="even_row">'; $odd = !$odd; extract($rows); echo '<td><a href="' . $dir . '/' . $image_id . '.jpg">'; echo '<img src="' . $thumbdir . '/' . $image_id . '.jpg">'; echo '</a></td>'; echo '<td>' . $image_caption . '</td>'; echo '<td>' . $image_username . '</td>'; echo '<td>' . $image_date . '</td>'; echo '</tr>'; } ?> </table> </body> </html> Any help appreciated. Hi, After looking at some Javascript, I think it can only be done in PHP. I'm trying to get my script to add a "1" to an external file. It's made in Javascript, but I hope I can put some PHP in it, even if it's at the end. I'm working on a Safari Extension, and would like to know how many people use it. It's all made in a .HTML file, so I should be able to add a PHP script at the end. I hope this is clear, and I hope it can be done in PHP, or something at least. Thanks, Joseph Duffy How can I say, if more than one of these if's happens do this.... Code: [Select] if ((!isset($_POST['state'])) && (($_POST['country'] != $r['country']) || ($_POST['city'] != $r['city']))) { $details = $_POST['city'].', '.$_POST['country']; update_user_actions(1, $details); } else if ((isset($_POST['state'], $_POST['city'])) && (($_POST['state'] != $r['state']) || ($_POST['city'] != $r['city']))) { $details = $_POST['city'].', '.$_POST['state']; update_user_actions(1, $details); } if ((isset($_POST['credentials'])) && ($_POST['credentials'] != $r['credentials'])) { $details = ''; update_user_actions(2, $details); } if ((isset($_POST['specialties'])) && ($_POST['specialties'] != $r['specialties'])) { $details = ''; update_user_actions(3, $details); } if ((isset($_POST['personalweb'])) && ($_POST['personalweb'] != $r['personalweb'])) { $details = $_POST['personalweb']; update_user_actions(4, $details); } how do I make $counter add one evertime it runs through the loop: Code: [Select] <?php // Query member data from the database and ready it for display $sql4 = mysql_query("SELECT * FROM labels where item_id='".$pid."'"); $num_rows = mysql_num_rows($sql4); echo $num_rows; while($row = mysql_fetch_array($sql4)){ $label =$row["label"]; $lid=$row['id']; $counter = 0; $counter = $counter + 1; print $counter . "<BR>"; ?> <select name="name<?php echo $counter; ?>"> <?php echo $label; ?>currently, it says counter is 1 everytime Hey all. Have a question, im still learning but what i am trying to do is make the number 1 add 1 to itself and repeat in the loop so, 1 2, 3, 4, 5, 6 ect...What am i doing wrong. $result = mysql_query("SELECT * FROM comments WHERE quoteid = ".$_REQUEST['quoteid'].""); while($row=mysql_fetch_array($result)){ $date = $row[date]; $name = $row[name]; $email = $row[email]; $quoteid = $row[quoteid]; $comment = stripslashes($row[comment]); $commentid = $row[commentid]; $counter = 1; $counted = $counter++; $resultb = mysql_query("SELECT * FROM quotes WHERE quoteid= '$quoteid'") or die(mysql_error()); while($link=mysql_fetch_array($resultb)){ $artist = $link[artist]; $song = $link[song]; } echo'<table border="0" cellpadding="0" cellspacing="0"><tr> <td rowspan="3" align="center"><span class="commentNumber">'.$counted.'</span></td> I have a counter that updates the database automatically with out refreshing the page. However i was wondering if someone can give me some pointers on how i can keep it updating the database even after someone exits the page. Currently it updates the database every 2 seconds by increasing the number by 1..however i want to be able to do this even if the page i not loaded is there any way i can do this? Hello, My hit counter doesnt work, at all. It is ment to update hits.txt(add 1 to the number in there.), and desplay how many hits it has using gd2. Here is my code: <?php /** * @author Jragon * @copyright 2010 */ getHits() function getHits() { $file = "hits.txt"; $fh = fopen($file, "r"); $hits = fread($fh, filesize("$file")); fclose($fh); ++$hits; $fh = fopen($file, "w+"); fwrite($fh, "$hits"); fclose($fh); getImage("$hits"); } function getImage($string) { //Make $string to to a string $string = "$string"; //Define fontsize $font = 5; //use imagefontwidth to find out the widht of each charicter, //then times it by how many charicters theere are, //and add some padding. $width = imagefontwidth($font) * strlen($string) + 10; //height of a charicter, and add some padding. $height = imagefontheight($font) + 10; //random color thingy. $r = rand(25, 250); $g = rand(25, 250); $b = rand(25, 250); //create a blank image using the dimsions set above. $image = imagecreate($width, $height); //set the background color $background_color = imagecolorallocate($image, 0, 0, 0); //set the text color using the random integers made above. $text_color = imagecolorallocate($image, $r, $g, $b); //Put the text into the image. imagestring($image, $font, 6, 6, $string, $text_color); //Change the type of webpage so you see the image header("Content-type: image/png"); //put everything together and make the image imagepng($image); //free up some space on the temp drive imagedestroy($image); } ?> I have created hits.txt with the value of 0 inside of it. Thanks Jragon |
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