PHP - Creating Output When Number Of Rows Gets To Each 10

Hi I wanted to know how once I have selected and echoed the rows from mysql table how can I get it to number those rows that echo?
etc

1.   echo $variable
2.   echo $variable
3.   echo $variable
4.   echo $variable
5.   echo $variable

Any help is appreciated

I was just wondering when you run a mysql query what the easiest way to find out the number of rows returned.  Just so I can do a number of results found on a search.  Thanks. 

Hi,

I have a problem regarding counting rows in a mysql table. Here is the code:

Code: [Select]
<?php
require_once('includes/connection.inc.php');
$conn = dbConnect('read');
$check = 'SELECT COUNT(*) FROM images';
$checkRes = $conn->query($check) or die(mysqli_error());
if($checkRes <= 0) { header('Location: empty_blog.php'); // redirect to another page
} else { // do something else... }
?>

The error I'm getting: "Notice: Object of class mysqli_result could not be converted to int in C:\xampp\htdocs\photoblog\index.php on line 6"

Any help is greatly appreciated!

I have a cart script, and I need to display the products the user has added.  This is a school assignment and I'm very stuck on this seemingly 'little' error.

Right now, I have two tables:

For time's sake, I am showing duplicate products with different prod_id's:
Table: products
prod_id category sub_category thumb_href image_href title desc summary manufacturer price 17 sofa leather red_leather_sofa_small.jpg red_leather_sofa_main.jpg Red Leather Sofa [BLOB - 134B] [BLOB - 59B] Balenty 999.99 18 sofa leather red_leather_sofa_small.jpg red_leather_sofa_main.jpg Red Leather Sofa [BLOB - 134B] [BLOB - 59B] Balenty 999.99 19 sofa leather red_leather_sofa_small.jpg red_leather_sofa_main.jpg Red Leather Sofa [BLOB - 134B] [BLOB - 59B] Balenty 999.99
And this is the cart table that holds temporary cart items (storing the product ID to pull later):
Table: cart
temp_cart_item cart_id (assigned by session_id() ) prod_id user_id 22 jier11u0e7cl2ghosjodpaark2 17 asdfasdf 23 jier11u0e7cl2ghosjodpaark2 17 asdfasdf 24 jier11u0e7cl2ghosjodpaark2 35 asdfasdf 25 jier11u0e7cl2ghosjodpaark2 5 asdfasdf 26 jier11u0e7cl2ghosjodpaark2 19 asdfasdf
SO, user 'asdfasdf' is logged in and has selected 5 items for his cart - two of which are the same (prod_id 17).  Basically,

I need to compare the prod_id's of each table and output all products (and quantities) matching the temporary cart prod_id.

What I have now to loop through and display the cart items are (bear with me):


echo "<h1>Cart</h1>";
}
// Display welcome and navigation links
displayWelcome();
displayNav();

// Getting the prod_id's from the table cart to compare with the product table
$cart_id = session_id();
$user_id = ($_SESSION['login_username']);
$query = "SELECT prod_id FROM cart WHERE cart_id='$cart_id' AND user_id='$user_id'";
$result = mysqli_query($cxn,$query) or die("<h2 class=\"warning\">Whoa! Problem with the cart script here!</h2>");
$nrows = mysqli_num_rows($result);
if($nrows < 1)
{
echo "<h2>Your cart is empty</h2><p><a href=\"catalog.php\">Go back to the catalog</a></p>";
}
else {  // Continue to gather products for all the product IDs in the products DB table...
echo "<h4>$nrows items in your cart</h4>";
while($row = mysqli_fetch_array( $result )) {
$user_id = ($_SESSION['login_username']);
$product = $row['prod_id'];

// Is the query my problem?
$query = "SELECT * FROM products WHERE prod_id='$product'";
$result = mysqli_query($cxn,$query) or die("<h2 class=\"warning\">Whoa! Problem with the cart script here!</h2>");
$nrows = mysqli_num_rows($result);
if($nrows < 1) { // If the item doesn't exist, display an error
echo "<h2>That is not a valid product, or any of the items you had in your cart are missing or have been deleted.</h2><p><a href=\"catalog.php\">Go back to the catalog</a></p>";
// Protect from continually displaying an error by deleting the invalid cart record
$deletequery = "DELETE FROM cart WHERE prod_id='$product'";
$deleteresult = mysqli_query($cxn,$deletequery) or die("<h2 class=\"warning\">Whoa! Problem with the cart script here!</h2>");
exit();
}
while($row = mysqli_fetch_array( $result )) {  //  Then disply them in a table
echo "<h2>Items in Your Cart:</h2>";
echo "
<table id=\"products\">
<thead>
<tr>
<th class=\"col1 headercol\" scope=\"col\">Thumbnail</th>
<th class=\"col2 headercol\" scope=\"col\">Summary</th>
<th class=\"col3 headercol\" scope=\"col\">Manufacturer</th>
<th class=\"col4 headercol\" scope=\"col\">Price</th>
</tr>
</thead>

<tbody>\n";
$query = "SELECT SUM(price) FROM products WHERE prod_id='$product' GROUP BY price";
$priceResult = mysqli_query($cxn,$query) or die("<h2 class=\"warning\">Whoa! Problem with the cart script here!</h2>");
// keeps getting the next row until there are no more to get
// Print out the contents of each row into a table
echo "<tr>
<td class=\"col1\">"; 
echo "<a class=\"imgHref\" href=\"detail.php?prod_id=".$row['prod_id']."\" title=\"".$row['title']."\"><img src=\"../images/".$row['thumb_href']."\" alt=\"".$row['title']."\" /></a>";
echo "</td>\n"; 
echo " <td class=\"col2\">"; 
echo "<h3 class=\"title\"><a href=\"detail.php?prod_id=".$row['prod_id']."\" title=\"".$row['title']."\">".$row['title']."</a> <span class=\"inlineh3\">by <a href=\"categories.php?manufacturer=".$row['manufacturer']."\" title=\"View all products by ".$row['manufacturer']."\">".$row['manufacturer']."</a></span></h3>";
echo "<p class=\"summary\">".$row['summary']."</p>
<p class=\"descHeading\">&#38;#9758; <em>Full Description:</em></p>
<p class=\"desc\">".$row['desc']."</p>";
echo "</td>\n"; 
echo " <td class=\"col3\">"; 
echo "<p class=\"manufacturer\"><a href=\"categories.php?manufacturer=".$row['manufacturer']."\" title=\"View all products by ".$row['manufacturer']."\">".$row['manufacturer']."</a></p>";
echo "</td>\n"; 
echo " <td class=\"col4\">"; 
echo "<p class=\"price\">$".$row['price']."</p>";
echo "</td>
</tr>\n"; 
}
while($priceRow = mysqli_fetch_array( $priceResult )) {
echo "<tr class=\"short\"><td class=\"col1\"><h3><a href=\"clear_cart.php\">Empty Cart</a></h3></td><td class=\"col2\"></td><td class=\"col3 nobackground\">Total:</td><td class=\"col4\">$".$priceRow[0]."</td></tr>";
}
echo "</tbody>
</table>";
echo "<p class=\"submitOrder\"><form action='submit_order.php' method='post' id='form'>
  <input type='submit' name='pButton' value='Submit Order'>
  <input name='order_total' type='hidden' id='order_total' value='".$priceRow[0]."' />
</form>
</p>";
}
}



And so the cart.php looks something like this (this example asdfasdf has 6 items in his cart):



So you can see that it only displays ONE item, even though asdfasdf DOES have 6 items in his cart (proven by checking database).  And the price is not accurate, either.

Can anyone help me in where my problem might be?  Is it my query?  Or my while clause?

Folks,

Having trouble here. Forgot how you use the COUNT. Not interested in the num_rows due to it being slow compared to COUNT.

I have users table like this:

id|username|sponsor_username

0|barand|requinix

1|phpsane|alison

2|mickey_mouse|requinix

Now, I want to check if a sponsor username exists or not. Such as does the entry "requinix" exists or not in one of the rows in the "sponsor_username" column.

In our example it does twice and so the variable $sponsor_username_count should hold the value "2". Else hold "0".

I get error:

Fatal error: Uncaught mysqli_sql_exception: You have an error in your SQL syntax; check the manual that corresponds to your MariaDB server version for the right syntax to use near '?' at line 1 

 

My code:

	$stmt_1 = mysqli_prepare($conn,"SELECT COUNT(sponsor_username) from users = ?"); 
            mysqli_stmt_bind_param($stmt_1,'s',$sponsor_username_count); 
            mysqli_stmt_execute($stmt_1); 
            
            //Show error if 'users' tbl was not successfully queried". 
            if (!$stmt_1) 
            { 
                echo "ERROR 1: Sorry! Our system is currently experiencing a problem loading this page!"; 
                exit(); 
            } 
            else 
            { 
                mysqli_stmt_bind_result($stmt_1,$sponsor_username_count);     
                mysqli_stmt_fetch($stmt_1); 
                mysqli_stmt_close($stmt_1); 
                
                //Check if Sponsor Username in Url ($_GET) is already registered or not. If not then show "Invalid Url" or Link message. 
                if ($sponsor_username_count < 1) 
                { 
                    echo "<b>Invalid Url or Link!<br> Invalid Sponsor: \"$sponsor_username\"!</b><?php "; 
                    exit(); 
                } 
            }