PHP - Simple Count Code
Looke on the PHP manual for the "count" function and it has confused me.
it seems to count arrays more than anything. i have a small site and i wanted to display how many items are contained within a Database table. for example i want it to count the amount of users are in the user table. and i then need to echo that amount + 100. Can someone help me with the code. i have already included a database connect script within the header of the page with includes etc. Help would be appreciated. but i would like to know how the code works else i will never learn. Similar TutorialsI'm trying to work out a count of how many of what assets are in a certain location: there should be 13 different categories (asset types) in a location and i want the individual count of each category. here's what i have - which seems to give me a total count of all assets and locations together plus one asset description and one location..... almost right. Code: [Select] $con = mysql_connect('localhost','root',''); if(! $con) die(mysql_error()); mysql_select_db("test",$con); $result = mysql_query("SELECT DISTINCT COUNT(`Asset Description`) AS TOTALAD, LOCATION, `Asset Description` AS AD FROM master WHERE LOCATION like 'NC%'"); while($row = mysql_fetch_array($result)) { echo $row["LOCATION"]; echo "<br />"; echo $row["TOTALAD"]; echo "<br />"; echo $row["AD"]; echo "<br />"; } mysql_close($con); SELECT COUNT(*) obviously counts all records matching the WHERE clause, however... Field1 / Field2 1 / A / A 1 / B 1 / A I want to count all records where Field2 is "A", but if Field1 is set to "1" then that record counts as half. So above would return a result of 2 (one and two halfs = 2) I'm sure SQL can do this without the need to perfrom PHP calculations. Hope this makes sense. Thanks in advance. I have a field in my MySQL DB that holds numbers separated by a comma (example: 1, 3, 45, 137, 87). I simply want to get a count of how many numbers are in there. (Using my example the result would be 5). I'm sure this is a simple question but I don't know how. I'm able to extract the numbers but I can't get the count to read anything other than 1. Can anyone help? Hey everyone, So here is my problem. I have some code to display the amount of views that page has got. In this case it is the thread in my forums section. I have used the same code to show how many people have views a certain persons profile page and that works fine but when I use it on my forum thread page I get this error. Quote You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'WHERE id='20' LIMIT 1' at line 1 Here is the section of code: Code: [Select] <?php $thread_id = preg_replace('#[^0-9]#i', '', $_GET['id']); $getThreadViews = mysql_query("SELECT view_count FROM forum_posts WHERE id='$thread_id' LIMIT 1") or die (mysql_error()); $row = mysql_fetch_assoc($getThreadViews); $counter = $row['view_count']; if($counter == 0){ $counter = 1; $startCounter = mysql_query("INSERT INTO forum_posts (view_count) VALUES ('$counter') WHERE id='$thread_id' LIMIT 1") or die (mysql_error()); } $threadViews = $counter+1; $appendCounter = mysql_query("UPDATE forum_posts SET view_count='$view_count' WHERE id='$thread_id'") or die (mysql_error()); ?> I have checked that there are no spelling errors so just wanted to show it to a fresh pair of eyes because its really starting to annoy me. Thanks in advance for any help. The following works, but I don't want to have to write 50 query statements for 50 states. How can I just write one query (using a variable I presume) and then echo the variable count each time for each state? I'm just trying to list the total number of rows for each state, that exist in the db. <? $result = mysql_query("SELECT * FROM mytable WHERE source = 'alabama'") or die(mysql_error()); $num_rows = mysql_num_rows($result); ?> href="/state/alabama/">alabama</a> (<?php echo("$num_rows");?>) <br> <? $result = mysql_query("SELECT * FROM mytable WHERE source = 'alaska'") or die(mysql_error()); $num_rows = mysql_num_rows($result); ?> href="/state/alaska/">alaska</a> (<?php echo("$num_rows");?>) <br> The above would give output such as: alabama (122) alaska (212) Hi Everyone, I have an ecommerce store that I have done some coding for, and each category has some coding to create pages to display items in that category. For some reason, I am getting a couple of "ghost" pages on the end of a couple categories. For example, look at this page: http://www.autismcommunitystore.com/view.php?category=4 Pages 5 & 6 are blank - page 4 has the last of the items in the category. I have a table called prods_to_cats which connects the products and the categories (a many to many relationship). I'm posting the code here - could someone just let me know if they spot something that looks like trouble? Thank you in advance for your time! Code: [Select] <? $category=$_REQUEST['category']; $showcategory=$category; include 'connect.php'; $thiscategory = mysql_query("SELECT * FROM category WHERE category_id=$showcategory", $dbh); $thisrow = mysql_fetch_array($thiscategory); $this_des=$thisrow["category_description"]; $this_text=$thisrow["category_text"]; $titlekey="Products listed in $this_des at Autism Community Store 877-422-5932"; // If current page number, use it // if not, set one! if(!isset($_GET['page'])){ $page = 1; } else { $page = $_GET['page']; } // Define the number of results per page $max_results = 40; // Figure out the limit for the query based // on the current page number. $from = (($page * $max_results) - $max_results); echo '<div id="product">'; $result = mysql_query("SELECT DISTINCT product.id, product.* FROM prods_to_cats INNER JOIN product ON prods_to_cats.id=product.id WHERE prods_to_cats.category_id=$showcategory ORDER BY product.title ASC LIMIT $from, $max_results", $dbh); $numresult = mysql_num_rows($result); if($numresult==0) { echo "<p style='padding-left: 50px'>There are no products listed in this category.</p>\n"; } else { $thiscategory = mysql_query("SELECT * FROM category WHERE category_id=$showcategory", $dbh); $thisrow = mysql_fetch_array($thiscategory); $this_des=$thisrow["category_description"]; echo "<table width='100%'><tr>"; echo "<div style='position:relative; left:150px;'><font size='2'>Return To: <strong><a href='http://www.autismcommunitystore.com'>Home </a></strong></font></div><br/>"; echo "<div style='position:relative ; width:100%' align='center'>"; echo "<br />"; echo "<img src='http://www.watchesandthings.com/autism/images/suppliesHeader.gif'>"; echo "</div>"; echo "<h2>"; echo "<div style='padding-right:20px ; position:relative ; width;100%; text-align:right;'>"; echo "<div style='position:relative ; width;80%; text-align:center; left:20%;'>"; echo $this_des; echo "</div>"; echo "</div>"; echo "</h2>"; echo "<div style='position:relative ; padding-left:30px ; padding-right:30px ; '>"; echo "<p>"; echo "$this_text </p>"; echo "</div>"; echo "</tr>"; $count = 1; $column = 1; //initialize column 1 or 2 //-----------------------code for drop down menu---------------------------------------- include 'browserChecker.php'; /* echo $browser; echo "<br/>"; echo $browser_version; echo "<br/>"; $main_version=$browser_version[0]; echo $main_version; */ if ($browser=='IE' && $browser_version<7){ echo '<br />'; //make version 6 compatible select box if ($category==1 || $category==24){ }else{ ?> <center> <div id="hiddendiv" style="display:;"> <form method="get" enctype="multipart/form-data" action="http://www.autismcommunitystore.com/viewsubcategory.php"> <select id="myselectbox" name="subcategory" > <? $sql="SELECT * FROM subcategory ORDER BY sub_description ASC"; $result=mysql_query($sql, $dbh); while($myrow=mysql_fetch_array($result)) { if ($myrow['category_id']==$category){ $myrow['sub_description'] ?> <option name="subcategory" value="<? echo $myrow['sub_id'] ?>" ><? echo $myrow['sub_description'] ?> </option> <? }//close if for category check }//close drop down while loop ?> </select> </center> <div id="go_subcat"> <input type="submit" value=" GO " style="background-color: #E4DFF3; color: #6F5079; border: 2px solid #6F5079"> </div> </form> </div> <? }//end check category }else{ //make normal select box if ($category==1 || $category==24){ }else{ ?><div style="z-index:2"><br /><form method="get" enctype="multipart/form-data" action="http://www.autismcommunitystore.com/viewsubcategory.php"> <div align="center" style='z-index:5'> <select name="subcategory" size="1" style="background-color: #ffffff; color: #6F5079; border: 2px solid #6F5079"> <? $sql="SELECT * FROM subcategory ORDER BY sub_description ASC"; $result=mysql_query($sql, $dbh); while($myrow=mysql_fetch_array($result)) { if ($myrow['category_id']==$category){ ?> <option name="subcategory" value="<? echo $myrow['sub_id'] ?>" ><? echo $myrow['sub_description'] ?> </option> <? }//close if for category check }//close drop down while loop ?> </select> <input type="submit" value=" GO " style="background-color: #E4DFF3; color: #6F5079; border: 2px solid #6F5079"> </div> </form> </div> <? } }//end browser checker if //-----------------------end code for drop down menu---------------------------------------- //reste variables $result = mysql_query("SELECT DISTINCT product.id, product.* FROM prods_to_cats INNER JOIN product ON prods_to_cats.id=product.id WHERE prods_to_cats.category_id=$showcategory ORDER BY product.title ASC LIMIT $from, $max_results", $dbh); echo "<TABLE cellspacing='20'>"; while($myrow = mysql_fetch_array($result)) { extract($myrow); $location=$image; $price=$sale_price; $item=$myrow["id"]; $stockstatus=$stat; if($stat=='IN STOCK') { $stockstatus=""; } else { $stockstatus="--Item Coming Soon--"; } if($price>0) { $printout="<table border=0 height=70 width=250><tr><td width='100px' align='center' ><a href=http://www.autismcommunitystore.com/item/$item/><img src=http://www.watchesandthings.com/autism/files/thumbnails/$location border=0 alt=$product_id></a></td><td><a href=http://www.autismcommunitystore.com/item/$item/>$title</a><br><span class=prod-dollar>$$price</span><br>$stockstatus</td></tr></table>"; } else { $printout="<table border=0 height=70 width=250><tr><td width='100px' align='center' ><a href=http://www.autismcommunitystore.com/item/$item/><img src=http://www.watchesandthings.com/autism/files/thumbnails/$location border=0 alt=$product_id></a></td><td><a href=http://www.autismcommunitystore.com/item/$item/>$title<br /><span class=prod-dollar>Click for Pricing</span></a><br>$stockstatus</td></tr></table>"; } if ($column=="1") { echo "<tr><td>$printout</td>"; // first column } else { echo "<td>$printout</td></tr>"; // 2nd column } // end of columns $count += 1; // this is a modulus operator it gets the remainder of the equation $column = $count % 2; } // end of while loop echo "</table>"; ; // Figure out the total number of results in DB: $total_results = mysql_result(mysql_query("SELECT COUNT(*) as Num FROM prods_to_cats WHERE category_id=$showcategory"),0); //$total_results = mysql_result(mysql_query("SELECT COUNT(*) as Num FROM product"),0); // Figure out the total number of pages. Always round up using ceil() $total_pages = ceil($total_results / $max_results); echo "<p><center>Pages<br />"; // Build Previous Link if($page > 1){ $prev = ($page - 1); echo "<a href='http://www.watchesandthings.com/autism/view.php?category=$showcategory&page=$prev'><<Previous</a> "; } for($i = 1; $i <= $total_pages; $i++){ if(($page) == $i){ echo "$i "; } else { echo "<a href='http://www.watchesandthings.com/autism/view.php?category=$showcategory&page=$i'>$i</a> "; } } // Build Next Link if($page < $total_pages){ $next = ($page + 1); echo "<a href='http://www.watchesandthings.com/autism/view.php?category=$showcategory&page=$next'>Next>></a>"; } echo "</center>"; }//end of else> echo "</table>"; echo "</div>"; ?> Can you see any problems with the code below? It doesn't work. What I am trying to do is quite straightforward. The links on my site look like this: go.php?id=1&url=usa go.php?id=1&url=uk go.php?id=2&url=usa go.php?id=2&url=uk When a visitor clicks on one of these links, I want to grab the values of the id and url parameters, count the click, and redirect the visitor. Here's the error that I get when I try the code: Quote Warning: mysql_fetch_row() expects parameter 1 to be resource, boolean given in C:\xampp\htdocs\sites\go.php on line 18 Warning: Cannot modify header information - headers already sent by (output started at C:\xampp\htdocs\sites\go.php:18) in C:\xampp\htdocs\sites\go.php on line 19 <?php $conn = mysql_connect('localhost','username', 'password') or trigger_error("SQL", E_USER_ERROR); mysql_select_db('database', $conn) or trigger_error("SQL", E_USER_ERROR); $id = intval($_GET['id']); $url = intval($_GET['url']); mysql_query("UPDATE urls SET click_counter = click_counter+1 WHERE id=$id"); if ($url=="usa") $href = "SELECT usa FROM urls WHERE id=$id"; elseif ($url=="uk") $href = "SELECT uk FROM urls WHERE id=$id"; elseif ($url=="aus") $href = "SELECT aus FROM urls WHERE id=$id"; elseif ($url=="can") $href = "SELECT can FROM urls WHERE id=$id"; else $href = "SELECT int FROM urls WHERE id=$id"; $qry = mysql_query($href); list($href)=mysql_fetch_row($qry); header("Location:$href"); mysql_close($conn); ?> Hi guys, I need your help. I am trying to insert the rows in the mysql database as I input the values in the url bar which it would be like this: Code: [Select] www.mysite.com/testupdate.php?user=tester&pass=test&user1=tester&email=me@shitmail.com&ip=myisp However i have got a error which i don't know how to fix it. Error: Column count doesn't match value count at row 1 <?php session_start(); define('DB_HOST', 'localhost'); define('DB_USER', 'mydbusername'); define('DB_PASSWORD', 'mydbpassword'); define('DB_DATABASE', 'mydbname'); $errmsg_arr = array(); $errflag = false; $link = mysql_connect(DB_HOST, DB_USER, DB_PASSWORD); if(!$link) { die('Failed to connect to server: ' . mysql_error()); } $db = mysql_select_db(DB_DATABASE); if(!$db) { die("Unable to select database"); } function clean($var){ return mysql_real_escape_string(strip_tags($var)); } $username = clean($_GET['user']); $password = clean($_GET['pass']); $adduser = clean($_GET['user1']); $email = clean($_GET['email']); $IP = clean($_GET['ip']); if($username == '') { $errmsg_arr[] = 'username is missing'; $errflag = true; } if($password == '') { $errmsg_arr[] = 'PASSWORD is missing'; $errflag = true; } if($errflag) { $_SESSION['ERRMSG_ARR'] = $errmsg_arr; echo implode('<br />',$errmsg_arr); } else { $sql = "INSERT INTO `members` (`username`,`email`,`IP`) VALUES ('$adduser','$email','$IP')"; if (!mysql_query($sql,$link)) { die('Error: ' . mysql_error()); } echo "The information have been updated."; } ?> Here's the name of the columns i have got in my database: Code: [Select] username IP I have input the correct columns names, so I can't correct the problem I am getting. Please can you help? This topic has been moved to MySQL Help. http://www.phpfreaks.com/forums/index.php?topic=331562.0 This topic has been moved to MySQL Help. http://www.phpfreaks.com/forums/index.php?topic=330192.0 Why am I getting this error when there are 3 Fields with 3 values? Column count doesn't match value count at row 1 Code: [Select] $sql5="INSERT INTO participants (participant_name, team_no, sport) VALUES ('".implode("','$_POST[team]'),('",$_POST['participant_name'])."','$_POST[team]','$sport')"; Hi, this is my first time posting here. I am just delving into PHP and I am learning about foreach loops. I have written code in Notepad++ EXACTLY the way I saw it in a tutorial video I watched (I wish I could show the tutorial video to you, but it is on Lynda.com and you have to pay to watch) I attached the file with my code. The example 1 code works just fine. The example 2 code is the one that is not working for some reason. However, it worked for the guy that wrote it in the video, so I am not sure where I am going wrong? *The comments in green are mainly for myself, I explain things to myself so that I don't forget what the code does forloops.php 1.74KB 2 downloads I would appreciate some help. Thank you!!! Anyone can help me? <?php $tbl_name="menu"; $kategorije = mysql_query("SELECT * FROM $tbl_name WHERE Left(menu_name, 1) BETWEEN 'A' AND 'M' ORDER BY menu_name ASC"); if (!$kategorije) { die("Database query failed: " . mysql_error()); } while ($row=mysql_fetch_array( $kategorije )) { echo "<div id=lista-header><h4>{$row["menu_name"]}</h4></div>"; $id_sub=$row['id_menu']; $podkategorije = mysql_query("SELECT * FROM submenu WHERE id_menu=$id_sub ORDER BY sub_name ASC", $connection); if (!$podkategorije) { die("Database query failed: " . mysql_error()); } echo "<ul class=\"pod\">"; while ($pod=mysql_fetch_array( $podkategorije )) { echo "<li><a href=index.php?=podkate?".$pod["id_sub"]." class=black>{$pod["sub_name"]}</a><hr size=1 align=left width=100px color=#cccccc></li>"; } echo "</ul>"; } ?> In this way, I get list with categories and hes subcategories. How to count how many subcategories have each categories, and count how many articles have each categories? Example (I wanna get this kind of look): Categories name (3) subcategoriesname (2) subcategoriesname (4) subcategoriesname (7) Categories name (5) subcategoriesname (1) subcategoriesname (14) subcategoriesname (9) subcategoriesname (2) subcategoriesname ( Categories name (2) subcategoriesname (28) subcategoriesname (17) Where the numbers represent how many categories and sub-items have articles <html> <?php $id = $_GET['id']; $dbusername="web148-matt"; $dbpassword="matt"; $dbdatabase="web148-matt"; mysql_connect(localhost,$dbusername,$dbpassword); @mysql_select_db($dbdatabase) or die( "Unable to select database"); mysql_query("UPDATE count SET clicks=clicks+1 WHERE id='$id'"); $sql = mysql_query("SELECT link FROM count WHERE id='$id'"); $fetch = mysql_fetch_row($sql); $result = mysql_query("SELECT * FROM count"); while($row = mysql_fetch_array($result)) { echo "<a href=" .$row['link']. ">Link</a>"; } ?> <a href='http://www.google.com'>Google</a> <a href='/index.php?id=2'>link2</a> </html> Okay so I have a table that displays grades. If the stupid has 100 for the grade points then I want a A to be displayed under the table... I think it does something like this... if grade_type >=100 $final_grade = A Idk, im new to php and need help doing this... here is my code... Code: [Select] <?php ini_set ("display_errors", "1"); error_reporting(E_ALL); require_once('database.php'); session_start(); if (isset($_POST['add_grade'])) { $query = "INSERT INTO grades (grade_id, student_id, grade_type, grade_name, grade_points) "; $query .= "VALUES (:grade_id, :student_id, :grade_type, :grade_name, :grade_points) "; $statement = $db->prepare($query); $statement->bindValue (':student_id', $_SESSION['student_id']); $statement->bindValue (':grade_id', $_SESSION['grade_id']); $statement->bindValue (':grade_type', $_POST['grade_type']); $statement->bindValue (':grade_name', $_POST['grade_name']); $statement->bindValue (':grade_points', $_POST['grade_points']); $statement->execute(); $statement->closeCursor(); } ?> <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> <title>View Course Grades</title> <link rel="stylesheet" type="text/css" href="main.css" /> </head> <body> <?php $student_name = $_SESSION['student_name']; $student_id = $_SESSION['student_id']; $query = "SELECT * FROM grades WHERE student_id = :student_id "; $statement = $db->prepare($query); $statement->bindValue (':student_id', $student_id); $statement->execute(); $grades = $statement->fetchAll(); $statement->closeCursor(); echo "<h1>Show Grades for $student_name </h1>"; foreach ($grades as $grade) { echo $grade['grade_type'] . " " . $grade['grade_name']. " " . $grade['grade_points'] . "<br />"; } ?> <div id="content"> <!-- display a table of products --> <table> <tr> <th>Grade Type</th> <th>Grade Name</th> <th>Grade Points</th> <th>Remove</th> </tr> <?php foreach ($grades as $grade) : ?> <tr> <td><?php echo $grade['grade_type']; ?></td> <td><?php echo $grade['grade_name']; ?></td> <td><?php echo $grade['grade_points']; ?></td> <td><form action="delete_grade.php" method="post"> <input type="submit" name="remove" value="Delete" /> <input type="submit" name="update" value="Update" /> </form></td> </tr> <?php endforeach; ?> </table> </div> </div> <div id="footer"> </div> <form name="grades" method="post" action="grades.php"> <p>Grade Type<SELECT NAME="grade_type"> <OPTION VALUE="Mid-Term">Mid-Term <OPTION VALUE="Final">Final <OPTION VALUE="Lab">Lab </SELECT> <br> Grade Name:<input type="text" name="grade_name" value=""><br /> Grade Points:<input type="text" name="grade_point" value=""> <input type="submit" name="add_grade" value="Add Grade"> </form> </table> </body> </html> Code: [Select] <html> <head> <title>Delete Grade</title> </head> <body> <form method="post" action="delete_grade.php"> <?php ini_set ("display_errors", "1"); error_reporting(E_ALL); $dbc = mysqli_connect('localhost', 'se266_user', 'pwd', 'se266') or die(mysql_error()); //delete grades if (isset($_POST['remove'])) { foreach($_POST['delete'] as $delete_id) { $query = "DELETE FROM grades WHERE grade_id = $delete_id"; mysqli_query($dbc, $query) or die ('can\'t delete user'); } echo 'grade has been deleted.<br />'; } if (isset($_POST['update'])) { foreach($_POST['update'] as $update_id) { $query = "UPDATE grades SET grade_id = $update_id"; mysqli_query($dbc, $query) or die ('can\'t update user'); } } //Display grade info with checkbox to delete $query = "SELECT * FROM grades"; $result = mysqli_query($dbc, $query); while($row = mysqli_fetch_array($result)) { echo '<input type="checkbox" value="' .$row['grade_id'] . '" name="delete[]" />'; echo ' ' .$row['grade_type'] .' '. $row['grade_name']; echo '<br />'; } mysqli_close($dbc); ?> <p>Grade Type<SELECT NAME="grade_type"> <OPTION VALUE="Mid-Term">Mid-Term <OPTION VALUE="Final">Final <OPTION VALUE="Lab">Lab </SELECT> <br> Grade Name:<input type="text" name="grade_name" value=""><br /> Grade Points:<input type="text" name="grade_point" value=""> <input type="submit" name="remove" value="Remove" /> <input type="submit" name="update" value="Update" /> </form> </body> </html> Hi!
I'm new to php so, please forgive if this is a really simple question or if it doesn't make sense.
I have an www.domain.com web site and then I have an microprocessor at home connected to the internet also hosting and simple page. That page is acessible from the internet.
When I'm browising on my www.domain.com i want to add an botton that sends an request to the microprocessor, right now what i do is when the button is clicked, it opens the microprocessor page like : microprocessor.ddns.net/?update=1.
How can i make the www.domain.com send the "?update=1" to the microprocessor without the user have to see the microprocessor page.
The main purpose is to hide the microprocessor address so it's harder to be hacked..
Thanks for the help!
Hello ..Im so glad to be here with u all I am a novice in the use of this php/sql and I have to complete my project..but Unfortunately, I got this problem and I couldent figure out where the mistake lies.. please any advice here u my code Code: [Select] <html> <body background="3d-background-blue.jpg"> <?php $x1=$_POST['fname']; $x2=$_POST['age']; $x3=$_POST['password']; $x4=$_POST['email']; $x5=$_POST['yourtype']; mysql_connect("localhost","root","")or die("there is a problem "); mysql_select_db("order1")or die("no DB"); // check if the username is taken $check = "select id from users where fname = '$x1'"; $qry = mysql_query($check) or die ("Could not match data because ".mysql_error()); $num_rows = mysql_num_rows($qry); if ($num_rows != 0) { echo "Sorry, there the username $x1 is already taken. "; echo "Try again"; echo "<a href= iinterface.html >home</a>"; echo "<br>"; exit(); } else { // insert the data $query="insert into users (fname,age,password,email,type) values('$x1','$x2','$x3','$x4','$x5')"; $result=mysql_query($query); if($result){ echo "thanks for registering $x1 " ;echo "<br>"; echo "the date of registeration is "; Echo gmdate ("D, d M Y H:i:s"); echo "<br>"; echo "<br>"; echo "<a href=iinterface.html > back to main </a>"; echo "<br>"; } else {echo"insertion error"; } ?> </body> </html> the massege of error is : Quote Parse error: parse error in insert2.php on line 45
Hello I do not know anything about php this is the code <?php echo do_shortcode( “[covid19 country=‘Pakistan’ title=‘Pakistan’]” ); echo do_shortcode( “[covid19 country=‘India’ title=‘India’]” ); echo do_shortcode( “[covid19]” ); ?>
can anyone help me to center the numbers of cases death recovered:
heres the code... <?php mysql_connect("localhost","peter","tizer") or die("Error: ".mysqlerror()); mysql_select_db("matquant"); //replace TestTable with the name of your table //also in a real app you would get the id dynamically $idtochange=$_POST['idtochange']; $sql="select * from `quantites` where id = $idtochange"; $query=mysql_query($sql); while ($row=mysql_fetch_array($query)){ $id = $row['id']; $material = $row['material']; $quantity = $row['quantity']; $unit = $row['unit']; //we will echo these into the proper fields } mysql_free_result($query); ?> <html> <head> <title>Edit material list</title> <link href="css/quant1.css" rel="stylesheet" type="text/css"> </head> <body> <div id="leftcol"> <form "method="post"> <p><br/> <input type="text"value="1" name="idtochange" > <p> <input type="submit"value="submit changes"/> </form> <form action="changequan.php"method="post"> <p>Material Id currently active<br/> <input type="text"value="<?php echo $id;?>" name="id" disabled/> </p> <p> Enter new material name: </p> <input type="text"value="<?php echo $material;?>" name="material"/> <br/> change quantity: <input type="text"value="<?php echo $quantity;?>" name="quantity"/> <br/> unit of mesurement for quantity<br/> <input type="text"value="<?php echo $unit;?>" name="unit"/> <br/> </p> <input type="submit"value="submit changes"/> </form> </div> <div id="rightcol"><?php // make connection mysql_connect ("localhost", "peter", "tizer") or die ('I cannot connect to the database becuase: ' . mysql_error()); mysql_select_db ("matquant"); // build query $query = mysql_query("SELECT * FROM `quantites` ORDER BY `id` ASC"); // display results while ($row = mysql_fetch_array($query)) { echo "<br /> ..... " .$row ['id']. " ....... " .$row ['material']. " ...... " .$row['quantity']. " ...... " .$row['unit']. "<br />";} echo mysql_error(); ?> <a href="index.html">Home </a> <p> <a href="quanform.php">Insert new material and quantity form</a></p></div> </body> </html> I'm struggling with php. Any help anyone can give would be appreciated. |