PHP - Assigning An Uploaded Image To Recall In A Php Array!! Really Need Help !!!
OK,
When the user fills the info in the form out it goes in the DB fine. I can then array them on the "showroom page" fine. When they upload a picture it goes into the /images/ folder fine. Problem is... On each array on the showroom page I need the image they uploaded to be displayed. Cant work it out. Help would be GREAT!!!!! Similar TutorialsI need to assign unknown array keys and their values to strings. The code I am using is: Code: [Select] $cart = $_SESSION['cart']; $items = explode(',',$cart); $qty = array(); foreach ($items as $item) { $qty[$item] = $qty[$item] + 1; } print_r($qty); The keys change and are not ordered. I do not know what the key or it's value may be. So as an example, I might have: Code: [Select] Array ( [2] => 5 [4] => 8 ) or in a different scenario, I might have: Code: [Select] Array ( [1] => 6 ) What those numbers represent is a product id (the key), and the quantity (the value of the key). Can someone help me to assign these to a string? I have been reading all morning, and not making any progress. Thank you! Hi all, I can't seem to designate an array key by using a variable and I was wondering if this is possible. I'm looking to do something like this: Code: [Select] <?php $key = "apple"; $arr = array($key => "fruit"); ?> Any suggestions would be appreciated! Hey everyone. I have been trying to assign dates to image so I could sort them, and also display the date they were uploaded. But I need some help. I have a script that uploads an image to a file directory, and also stores the file directory and the upload date in a database. And I also have a script that displays the images in the file directory but I cannot find a way to assign the right date to the right image. Here is the script that displays the images: Code: (php) [Select] if (isset($_POST['submit'])) { // fill an array with all items from a directory $dir = "thumbs/"; $handle = opendir($dir); while ($file = readdir($handle)) { $files[] = $file; // This removes the full stops from the array unset($files[0]); unset($files[1]); } foreach($files as $fileimg) { echo "<img src='". $dir . $fileimg ."'/>\n"; echo "$date"; } } and here is the script for calling the date from the database: Code: [Select] $query = mysql_query("SELECT imgaddress, uploaddate FROM thumbs WHERE imgaddress='" . $dir . $file . "'"); if (mysql_num_rows($query) == 1) { $row = mysql_fetch_assoc($query); $date = $row['uploaddate']; If I use the database statement before the foreach, then it does not get the right file directory, but if I call it inside the foreach, then I cannot use krsort() to sort the array. Any help would be greatly appreciated, thanks I have this code where I add records: Code: [Select] <?php ini_set('display_errors',1); error_reporting(-1); require_once ('./includes/config.inc.php'); require_once (MYSQL); $add_cat_errors = array(); if ($_SERVER['REQUEST_METHOD'] == 'POST') { // Check for a name: if (empty($_POST['product'])) { $add_cat_errors['product'] = 'Please enter the name!'; } // Check for a description: if (empty($_POST['prod_descr'])) { $add_cat_errors['prod_descr'] = 'Please enter the description!'; } // Check for a category: if (!isset($_POST['cat']) || !filter_var($_POST['cat'], FILTER_VALIDATE_INT, array('min_range' => 1))) { $add_cat_errors['cat'] = 'Please select a category!'; } // Check for a price: if (empty($_POST['price']) || !filter_var($_POST['price'], FILTER_VALIDATE_FLOAT) || ($_POST['price'] <= 0)) { $add_cat_errors['price'] = 'Please enter a valid price!'; } // Check for a category: if (!isset($_POST['directory']) || !filter_var($_POST['directory'], FILTER_VALIDATE_INT, array('min_range' => 1))) { $add_cat_errors['directory'] = 'Please select a directory!'; } // Check for an image: if (is_uploaded_file ($_FILES['image']['tmp_name']) && ($_FILES['image']['error'] == UPLOAD_ERR_OK)) { $file = $_FILES['image']; $size = ROUND($file['size']/1024); // Validate the file size: if ($size > 512) { $add_cat_errors['image'] = 'The uploaded file was too large.'; } // Validate the file type: $allowed_mime = array ('image/jpeg', 'image/JPG', 'image/jpg'); $allowed_extensions = array ('.jpg', 'jpeg'); $image_info = getimagesize($file['tmp_name']); $ext = substr($file['name'], -4); if ( (!in_array($file['type'], $allowed_mime)) || (!in_array($image_info['mime'], $allowed_mime) ) || (!in_array($ext, $allowed_extensions) ) ) { $add_cat_errors['image'] = 'The uploaded file was not of the proper type.'; } // Move the file over, if no problems: if (!array_key_exists('image', $add_cat_errors)) { // Create a new name for the file: $new_name = (string) sha1($file['name'] . uniqid('',true)); // Add the extension: $new_name .= ((substr($ext, 0, 1) != '.') ? ".{$ext}" : $ext); //$new_name = $dir . '/' . $new_name; $dest = "../db/images/$new_name"; // Move the file to its proper folder but add _tmp, just in case: //$dest = "../db/images/$new_name"; $dirs = array('full_heads', 'human_hair', 'lip_tattoos', 'ponytails', 'synthetic_hair'); if (move_uploaded_file($file['tmp_name'], $dest)) { // Store the data in the session for later use: $_SESSION['image']['new_name'] = $new_name; $_SESSION['image']['file_name'] = $file['name']; // Print a message: echo '<h4>The file has been uploaded!</h4>'; } else { trigger_error('The file could not be moved.'); unlink ($file['tmp_name']); } } // End of array_key_exists() IF. } elseif (!isset($_SESSION['image'])) { // No current or previous uploaded file. switch ($_FILES['image']['error']) { case 1: case 2: $add_cat_errors['image'] = 'The uploaded file was too large.'; break; case 3: $add_cat_errors['image'] = 'The file was only partially uploaded.'; break; case 6: case 7: case 8: $add_cat_errors['image'] = 'The file could not be uploaded due to a system error.'; break; case 4: default: $add_cat_errors['image'] = 'No file was uploaded.'; break; } // End of SWITCH. } // End of $_FILES IF-ELSEIF-ELSE. // Check for a stock: if (empty($_POST['stock']) || !filter_var($_POST['stock'], FILTER_VALIDATE_INT, array('min_range' => 1))) { $add_cat_errors['stock'] = 'Please enter the quantity in stock!'; } if (empty($add_cat_errors)) { $query = "INSERT INTO product (product, prod_descr, catID, price, dirID, image, stock) VALUES (?, ?, ?, ?, ?, ?, ?)"; // Prepare the statement: $stmt = mysqli_prepare($dbc, $query); // For debugging purposes: // if (!$stmt) echo mysqli_stmt_error($stmt); // Bind the variables: mysqli_stmt_bind_param($stmt, 'ssssssi', $name, $desc, $_POST['cat'], $_POST['price'], $_POST['directory'], $_SESSION['image']['new_name'], $_POST['stock']); // Make the extra variable associations: $name = strip_tags($_POST['product']); $desc = strip_tags($_POST['prod_descr']); // Execute the query: mysqli_stmt_execute($stmt); if (mysqli_stmt_affected_rows($stmt) == 1) { // If it ran OK. // Print a message: echo '<h4>The product has been added!</h4>'; // Clear $_POST: $_POST = array(); // Clear $_FILES: $_FILES = array(); // Clear $file and $_SESSION['image']: unset($file, $_SESSION['image']); } else { // If it did not run OK. trigger_error('The product could not be added due to a system error. We apologize for any inconvenience.'); unlink ($dest); } } // End of $errors IF. } else { // Clear out the session on a GET request: unset($_SESSION['image']); } // End of the submission IF. require_once ('./includes/form_functions.inc.php'); ?> <form enctype="multipart/form-data" action="add_product.php" method="post" accept-charset="utf-8"> <input type="hidden" name="MAX_FILE_SIZE" value="524288" /> Product<br /><?php create_form_input('product', 'text', $add_cat_errors); ?> Description<br /><?php create_form_input('prod_descr', 'textarea', $add_cat_errors); ?> Category<br /><select name="cat"<?php if (array_key_exists('cat', $add_cat_errors)); ?>> <option>Select One</option> <?php // Retrieve all the categories and add to the pull-down menu: $q = 'SELECT catID, cat FROM category ORDER BY cat ASC'; $r = mysqli_query ($dbc, $q); while ($row = mysqli_fetch_array ($r, MYSQLI_NUM)) { echo "<option value=\"$row[0]\""; // Check for stickyness: if (isset($_POST['cat']) && ($_POST['cat'] == $row[0]) ) echo ' selected="selected"'; echo ">$row[1]</option>\n"; } ?> </select><?php if (array_key_exists('cat', $add_cat_errors)) echo $add_cat_errors['cat']; ?> Price<br /><?php create_form_input('price', 'text', $add_cat_errors); ?> Directory<br /><select name="directory"<?php if (array_key_exists('directory', $add_cat_errors)); ?>> <option>Select One</option> <?php // Retrieve all the categories and add to the pull-down menu: $q = 'SELECT dirID, directory FROM directory ORDER BY directory ASC'; $r = mysqli_query ($dbc, $q); while ($row = mysqli_fetch_array ($r, MYSQLI_NUM)) { echo "<option value=\"$row[0]\""; // Check for stickyness: if (isset($_POST['directory']) && ($_POST['directory'] == $row[0]) ) echo ' selected="selected"'; echo ">$row[1]</option>\n"; } ?> </select><?php if (array_key_exists('directory', $add_cat_errors)) echo $add_cat_errors['directory']; ?> </select> Image<br /><?php // Check for an error: if (array_key_exists('image', $add_cat_errors)) { echo $add_cat_errors['image'] . '<br /><input type="file" name="image"/>'; } else { // No error. echo '<input type="file" name="image" />'; // If the file exists (from a previous form submission but there were other errors), // store the file info in a session and note its existence: if (isset($_SESSION['image'])) { echo "<br />Currently '{$_SESSION['image']['file_name']}'"; } } // end of errors IF-ELSE. ?> <br /> Stock<br /><?php create_form_input('stock', 'text', $add_cat_errors); ?> <input type="submit" value="Add This Product" class="button" /> </fieldset> </form> What I want to achieve is this; When a record is being inserted, a user will make a selection from the dropdown box with a list of directories. Then, a user will upload an image. When a image is uploaded and a directory is chosen, I want the image to be assigned to a specific directory from the list so when the record is inserted, that image will be placed in the specific directory. How do I achieve this please? Hi. I have a script here that will let users upload an image to my website but I just can't figure out how to save the uploaded image as "upload/logo.png" so that it will replace the already existing "upload/logo.png". Help would be greatly appreciated. Code: [Select] <html> <body> <form action="" method="post" enctype="multipart/form-data"> <label for="file">Filename:</label> <input type="file" name="file" id="file" /> <br /> <input type="submit" name="submit" value="Submit" /> </form> </body> </html> <?php if(isset($_POST['submit']) && !empty($_FILES["file"]["name"])) { $timestamp = time(); $target = "upload/"; $target = $target . basename($_FILES['uploaded']['name']) ; $ok=1; $allowed_types = array("image/gif","image/jpeg","image/pjpeg","image/png","image/bmp"); $allowed_extensions = array("gif","png","jpg","bmp"); if ($_FILES['file']['size'] > 350000) { $max_size = round(350000 / 1024); echo "Your file is too large. Maximum $max_size Kb is allowed. <br>"; $ok=0; } if ($_FILES["file"]["error"] > 0) { echo "Error: " . $_FILES["file"]["error"] . "<br />"; $ok=0; } else { $path_parts = pathinfo(strtolower($_FILES["file"]["name"])); if(in_array($_FILES["file"]["type"],$allowed_types) && in_array($path_parts["extension"],$allowed_extensions)){ $filename = $timestamp."-".$_FILES["file"]["name"]; echo "Name: " . $filename . "<br />"; echo "Type: " . $_FILES["file"]["type"] . "<br />"; $path_parts = pathinfo($_FILES["file"]["name"]); echo "Extension: " . $path_parts["extension"] . "<br />"; echo "Size: " . round($_FILES["file"]["size"] / 1024) . " Kb<br />"; //echo "Stored in: " . $_FILES["file"]["tmp_name"]. " <br />"; } else { echo "Type " . $_FILES["file"]["type"] . " with extension " . $path_parts["extension"] . " not allowed <br />"; $ok=0; } } if($ok == 1){ @move_uploaded_file($_FILES["file"]["tmp_name"], $target . $filename); $file_location = $target . $filename; if(file_exists($file_location)){ echo "Uploaded to <a href='$file_location'>$filename</a> <br />"; } else { echo "There was a problem saving the file. <br />"; } } } else { echo "Select your file to upload."; } ?> Thanks! Hi again all, I wondered if anyone could help again (sorry). I have one single page which I would like to record a cookie when the user hits submit. The next time the user visits the site, I want it to recall the cookie and put the value in the textbox on the page. I think I have it storing the cookie (not sure though), but I am having trouble getting it to recall in the text box. I wondered if someone could look at this code and see where I am going wrong or help with what I need to add. New to PHP so having trouble getting my head around things. Thanks in advance. Code: [Select] <? setcookie('user',$userName,(time()+60*60*24*30) ); ?> <style type="text/css"> <!-- body,td,th { color: #FFFFFF; } body { background-color: #000000; } .style1 {font-family: Verdana, Arial, Helvetica, sans-serif} --> </style><form id="form1" name="form1" method="post" action=""> <label> <div align="center" class="style1"><strong>My Timetable Search</strong><br /> <br /> Enter Network User ID:<br /> <input type="text" name="txtUserID" id="txtUserID" value=""/> </div> <p align="center"> <label> <input type="submit" name="cmdGo" id="cmdGo" value="Show Timetable" onclick="setcookie('user',$userName,(time()+60*60*24*30);"/> </label> <br /> </p> <hr /> </form> <div align="center"> <?php $userName = $_POST["txtUserID"]; $hostname = "xxxxx"; $dbuser = "xxxxx"; $dbpassword = "xxxxxx"; $dbname = "xxxxx"; $LessonCount = 0; $db_link=mysql_connect($hostname, $dbuser, $dbpassword) or die("Unable to connect to the server!"); mysql_select_db($dbname) or die("Unable to connect to the database"); $fields_array=array(); $num_fields=0; $num_row=0; $sql= "SELECT core.UserID, wstt.Period, wstt.Lesson, wstt.Staff, wstt.Room FROM wstt INNER JOIN core ON wstt.Adno = core.Adno WHERE core.UserID='$userName'"; // find position of "FROM" in query $fpos=strpos($sql, 'from'); // get string starting from the first word after "FROM" $strfrom=substr($sql, $fpos+5, 50); // Find position of the first space after the first word in the string $Opos=strpos($strfrom,' '); //Get table name. If query pull data from more then one table only first table name will be read. $table=substr($strfrom, 0,$Opos); // Get result from query $result=mysql_query($sql); $num_row=mysql_numrows($result); print('<html>'); print('<head><title>'); print('Timetable for'.$userName.'</title>'); print('<link rel="stylesheet" href="style.css">'); print("</head>"); print('<body><br>'); print('<h3>Timetable for: '.$userName.'</h3>'); print('<div align="center"'); if($num_row >0) { //Get number of fields in query $num_fields=mysql_num_fields($result); # get column metadata $i = 1; //Set table width 10% for each column $width=10 * $num_fields; // print('<br><table width='.$width.'% align="center" border=1> padding=0<tr>'); print('<br><table width='.$width.'% border="1" cellpadding="0" cellspacing="0" bordercolor="#000066"<tr>'); print('<tr><th colspan='.$num_fields.'>Timetable List</th></tr>'); while ($i < $num_fields) { //Get fields (columns) names $meta = mysql_fetch_field($result); $fields_array[]=$meta->name; //Display column headers in upper case print('<th><b>'.strtoupper($fields_array[$i]).'</b></th>'); $i=$i+1; } print('</tr>'); //Get values for each row and column while($row=mysql_fetch_row($result)) { print('<tr>'); //SET TO 1 TO HIDE USERNAME for($i=1; $i<$num_fields; $i++) { //Display values for each row and column print('<td>'.$row[$i].'</td>'); } //START if ($LessonCount ==4) { print('<tr>'); print('<td colspan="4"><div align="center">-----------------------------------------------------</td></tr>'); $LessonCount=0; }else { ($LessonCount = $LessonCount+1); } //STOP print('</tr>'); } } print('</div>'); ?> </div> Hi everyone, I have a script below, which uplads an image, however, the image name always starts with a capital letter, I want all letters to be small, how to adjust this please, thank you
$target_dir = ""; $target_file = $target_dir . basename($_FILES["fileToUpload"]["name"]); $target_file = "$get_current_user.jpg"; $uploadOk = 1; $imageFileType = strtolower(pathinfo($target_file,PATHINFO_EXTENSION)); // Check if image file is a actual image if(isset($_POST["submit"])) { $check = getimagesize($_FILES["fileToUpload"]["tmp_name"]); if($check !== false) { echo ""; /// was File is an image $uploadOk = 1; } else { echo "File is not an image<br>"; $uploadOk = 0; } } // Check file size if ($_FILES["fileToUpload"]["size"] > 10000000) { echo "Sorry, this image is too large, please resize using Paint<br>"; $uploadOk = 0; } // Allow certain file formats if($imageFileType != "jpg" && $imageFileType != "png" && $imageFileType != "jpeg" && $imageFileType != "gif" ) { echo "Only JPG, JPEG, PNG & GIF files are allowed<br>"; $uploadOk = 0; } // Check if $uploadOk is set to 0 by an error if ($uploadOk == 0) { echo "There was an error<br>"; } else { if (move_uploaded_file($_FILES["fileToUpload"]["tmp_name"], $target_file)) { echo "Uploaded successfully (You may need to clear Cache to see the new image)"; mysql_query("UPDATE user SET user_image = 'https://.../images/users/$get_current_user.jpg' WHERE user_name = '$get_current_user' "); } else { echo ""; /// was Select a suitable image, file not uploaded yet } }
I'm beginning with simple codes to understand how things work and work my way up with what I need. My upload form looks like this: <form name="upload about" action="display.php" enctype="multipart/form-data" method="post"> Header: <input type="text" name="header" /> Body: <input type="text" name="body" /> <input type="hidden" name="MAX_FILE_SIZE" value="30000" /> Image: <input type="file" name="pic" /> <input type="submit" /> </form> And my display page is just as simple. <?php echo $_POST["header"]; ?> <?php echo $_POST["body"]; ?> <?php echo $_FILES['pic']['name']; ?> The problem is, whenever I submit the data, everything is fine, except the image does not display and just posts the filename of the image I uploaded. According to my research setting the enctype to multipart/formdata should display the image, but it does not. Can anyone tell me what's wrong? Not sure if this is the right place to post this. I have PHP form that I use to upload a document, PDF or Word Doc, I would also like the form to create a thumbnail of the document when it is uploaded, is this possible? Hello I have uploaded images from a server onto a website, they run through a mysql database (database holds the image file names). The problem I am having is resizing the images. Can anyone help? Thank you in advance GWG Hello. I'm using an Amazon S3 class to uploaded to S3. I have 2 upload boxes - The first uploads once and the second needs to upload twice - 1 full size, 1 thumb. The issue i'm having is that the 2nd image (the thumb) seems to be failing, although if I don't save the first full sized image I am able to upload the thumb. So I think the issue is with using the temp file twice? This is my code: //retreive post variables $fileName = $randomString . "_" . $_FILES['theFile']['name']; $fileTempName = $_FILES['theFile']['tmp_name']; $fileName2 = $randomString . "_" . $_FILES['theFile2']['name']; $fileTempName2 = $_FILES['theFile2']['tmp_name']; //move the file if ($s3->putObjectFile($fileTempName, "containerhere", $fileName, S3::ACL_PUBLIC_READ)) { echo "<strong>Uploaded Image</strong>"; }else{ echo "<strong>Something went wrong while uploading your file... sorry.</strong>"; } //move the file if ($s3->putObjectFile($fileTempName2, "containerhere", $fileName2, S3::ACL_PUBLIC_READ)) { echo "<strong>Uploaded Image</strong>"; }else{ echo "<strong>Something went wrong while uploading your file... sorry.</strong>"; } include('simpleImage.php'); $image = new SimpleImage(); $image->load($_FILES['theFile2']['tmp_name']); $image->resizeToWidth(100); $image->save($_FILES['theFile2']['tmp_name']); $fileName3 = $randomString . "_" . $_FILES['theFile2']['name']; $fileTempName3 = $_FILES['theFile2']['tmp_name']; //move the file if ($s3->putObjectFile($fileTempName3, "containerhere", "thumbs/" . $fileName3, S3::ACL_PUBLIC_READ)) { echo "<strong>Uploaded Image</strong>"; }else{ echo "<strong>Something went wrong while uploading your file... sorry.</strong>"; } Can anyone offer any advice? Thanks. Hi, I have a script that uploads an image to a directory and then saves the fill path to a field in a table for later use. The only problem is people are uploading huge images and then when I produce a catalogue of my listings it takes forever to load because the images are so big. What I am after is an add in script to create an ADDITIONAL image 100 x 75px, I don't really want to change my upload script. Any ideas? Thanks in advace. Here is what I have: Code: [Select] <?php $idir = "../fleet/"; // Path To Images Directory if (isset ($_FILES['fupload'])){ //upload the image to tmp directory $url = $_FILES['fupload']['name']; // Set $url To Equal The Filename For Later Use if ($_FILES['fupload']['type'] == "image/jpg" || $_FILES['fupload']['type'] == "image/jpeg" || $_FILES['fupload']['type'] == "image/pjpeg") { $file_ext = strrchr($_FILES['fupload']['name'], '$account.'); // Get The File Extention In The Format Of , For Instance, .jpg, .gif or .php $copy = copy($_FILES['fupload']['tmp_name'], "$idir" . $_FILES['fupload']['name']); // Move Image From Temporary Location To Perm } } $fleetimage1 = mysql_real_escape_string("$idir" . $_FILES['fupload']['name']); //then insert sql code below... ?> Hi I have a column in my database showing Banned words. What im trying to do is to recall the list of bad words from my database and if some of them is going to be displayed they should replace it with :-x well I made the `$bwords` to recall the info from the database. Hi Basically I've built a CMS where by my clients can upload a number of images. On the success page I want to display the images they uploaded by file name. The issue is the number of images can vary. They may upload 2 or 10 or 50 etc. So far I've come up with this: Code: [Select] // number of files $UN = 3; //I've set this to 3 for now, but this is passed from the upload page! // server directories and directory names $dir = '../properties'; $images = glob($dir.'/*.{jpg}', GLOB_BRACE); //formats to look for $num_of_files = $UN; //number of images to display from number of uploaded files foreach($images as $image) { $num_of_files--; $newest_mtime = 0; $image = 'BROKEN'; if ($handle = @opendir($dir)) { while (false !== ($file = readdir($handle))) { if (($file != '.') && ($file != '..')) { $mtime = filemtime("$dir/$file"); if ($mtime > $newest_mtime) { $newest_mtime = $mtime; $image = "$file"; } } } } if($num_of_files > -1) //this made me laugh when I wrote it echo $trimmed = ltrim($image, "../properties").'<br />'; //display images else break; } Without this piece of code: Code: [Select] $newest_mtime = 0; $image = 'BROKEN'; if ($handle = @opendir($dir)) { while (false !== ($file = readdir($handle))) { if (($file != '.') && ($file != '..')) { $mtime = filemtime("$dir/$file"); if ($mtime > $newest_mtime) { $newest_mtime = $mtime; $image = "$file"; } } } } It shows the first 3 files alphabetically. I want to view the last number of images added. With the above code it simply shows the last image added 3 times! So I need to get the time each image was added and then order by the newest added and limit to the number of images uploaded. Any suggestions please? Kindest regards Glynn hi to all.Im currently displaying the images from my upload directory but the image does not display.please help thanks Hey guys! I have the following php code that grabs variables (and the browsed image) from Flash. //FLASH VARIABLES $Name = $_POST['Name']; $itemNumber = $_POST['itemNumber']; $filename = $_FILES['Filedata']['name']; $filetmpname = $_FILES['Filedata']['tmp_name']; $fileType = $_FILES["Filedata"]["type"]; $fileSizeMB = ($_FILES["Filedata"]["size"] / 1024 / 1000); list($filename, $extension) = explode('.', basename($_FILES['Filedata']['name'])); $filename = $Name; $target = $filename . $itemNumber . "." . $extension; // Place file on server, into the images folder move_uploaded_file($_FILES['Filedata']['tmp_name'], "images/".$target); This works perfect, but what I want to change is the width and height of the uploaded image. Any ideas/suggestions on how this could be done? Thanks in advance!! Cheers! I need help making the uploaded image file name, that's chosen to be uploaded, be displayed on the html page with the path /upload/ added to the beginning of the displayed file name like so: ../upload/test.png Any help/improvements will be appreciated. <html> <head> <title>PHP Test</title> </head> <body> <?php if ($form_submitted == 'yes') { $allowedExts = array("gif", "jpeg", "jpg", "png"); $temp = explode(".", $_FILES["file"]["name"]); $extension = strtolower( end($temp) ); if ( $_FILES["file"]["size"] < 200000 && in_array($extension, $allowedExts) ) { if ($_FILES["file"]["error"]!= 0) { echo "Return Code: " . $_FILES["file"]["error"] . "<br>"; } else { $length = 20; move_uploaded_file($_FILES["file"]["tmp_name"], "upload/" . $newfilename ); $file_location = '<a href="http://../upload/' . $newfilename . '">' . $newfilename . '</a>'; } } else { echo "Invalid upload file"; } ?> <label for="file">Filename:</label> <input type="file" name="file" id="file"> </body> </html> could someone help in how to resize a uploaded image size, say if someone is uploading a 1mb photo to my server, i wish for it to become 100kb and also resize its width and height? here is my code Code: [Select] //////////////////////////////////////uploader else if($action=="uploader") { echo "Upload your picture and copy the link <br/>after uploading to user it at gallery.<br/><br/>"; echo "<form method=\"post\" enctype=\"multipart/form-data\" action=\"index.php?action=uploaded&sid=$sid\">"; echo "Choose Pictu <br />"; echo "<input name=\"uploaded\" type=\"file\" /><br /><br />"; echo "<input type=\"submit\" value=\"Upload\" />"; echo "</form><br/>"; echo "<p align=\"center\">"; echo "<a href=\"index.php?action=main&sid=$sid\">Home</a>"; echo "</p>"; } //////////////////////////////////////uploader else if($action=="uploaded") { $blacklist = array(".php", ".php.jpg", ".php.jpeg", ".php.gif", ".php.png", ".phtml", ".php3", ".php4"); foreach ($blacklist as $item) { if(preg_match("/$item\$/i", $_FILES['uploaded']['name'])) { echo "<p align=\"center\">"; echo "Oops sorry we do not allow those files.<br/>"; echo "<a href=\"index.php?action=main&sid=$sid\">Home</a>"; echo "</p>"; exit; } } $target = "../images/"; $target = $target . basename( $_FILES['uploaded']['name']) ; $ok=1; if (file_exists("../images/" . $_FILES["uploaded"]["name"])) { echo "<p align=\"center\">"; echo $_FILES["file"]["name"] . "Oops file name already exists<br/> kindly rename your picture and upload again. <br/>"; echo "<a href=\"index.php?action=main&sid=$sid\">Home</a>"; echo "</p>"; }else{ //This is our size condition if ($uploaded_size > 25600){ echo "Your file is too large. We have a 25kb limit.<br/>"; $ok=0; } $types = array('image/jpeg', 'image/gif', 'image/png'); if (in_array($_FILES['uploaded']['type'], $types)) { // file is okay continue } else { $ok=0; } //Here we check that $ok was not set to 0 by an error if ($ok==0){ echo "<p align=\"center\">"; Echo "Sorry your file was not uploaded.<br/> It may be the wrong filetype. <br/>We only allow JPG, GIF, and PNG filetypes.<br/>"; echo "<a href=\"index.php?action=main&sid=$sid\">Home</a>"; echo "</p>"; } //If everything is ok we try to upload it else{ if(move_uploaded_file($_FILES['uploaded']['tmp_name'], $target)){ echo "<p align=\"center\">"; echo "The file ". basename( $_FILES['uploadedfile']['name']). " Picture uploaded successfully.<br/><br/><b>$target <br/>"; echo "<a href=\"index.php?action=main&sid=$sid\">Home</a>"; echo "</p>"; } else{ echo "<p align=\"center\">"; echo "Sorry, there was a problem uploading your file.<br/>"; echo "<a href=\"index.php?action=main&sid=$sid\">Home</a>"; echo "</p>"; } } } } I have learned php coding by doing (looking for patterns and trying things) and I have hit a roadblock trying to modify a template that creates a delimited text file of products from an ecommerce site (Sunshop) for upload to google base. I have tried to search for the answer but I don't know what I don't know so I may not have put the right search terms in. So I apologize if this has been addressed in the past. The script uses case to call up the contents of specific rows of the product table which I understand but in when I want to call up the manufacturer row Sunshop uses a reference number and then a different table called manufacturers with an ID row that matches the manufacturer row numbers (that are associated with each product) and then next to it a name row which contains the actual manuracturer names. Can I put code in the case that will pull up the referenced name as opposed to just the numbers that are in the column? This is what I have now that just calls up the cells from the manufacurer row: Code: [Select] case 'mfg': $item[mfg] = $item[manufacturer]; The mfg refers to this part of the code in an array: Code: [Select] array('header' => 'manufacturer', 'value' => 'mfg'), In case it helps I will attach the full document. Thanks. hi, i am updating records from database using ajax and javascript on php page. The result is displayed inside a div (<div id="show"></div>). Now i want to assign the content of the above div(say y) to php variable for further calculations. How can i assign the value displayed in div tag to a php variable? Thanks. |