PHP - Running Php Inside Js Dialog Box.
I am trying to display a js dialog box when someone wants to delete something. Currently I have it all with buttons and PHP in the background. When they click the delete icon, I want a dialog box to appear with OK or Cancel. On cancel, return back to the same page, If OK, I want it to run the PHP/mysql code that deletes the record from the DB. Once deletes, I want the box to appear again saying it was deleted successfully.
I found this but now sure how to make it work. function show_confirm() { var r=confirm("Press a button"); if (r==true) { alert("You pressed OK!"); } else { alert("You pressed Cancel!"); } } Similar TutorialsThis topic has been moved to JavaScript Help. http://www.phpfreaks.com/forums/index.php?topic=316454.0 Hi, I have this curl string required by an email verification vendor I use. Inside my php file I wish to run it. Apparently there is a problem with the syntax as I’m getting the following error in the browser: ”Parse error: syntax error, unexpected '--' (T_DEC) in /var/www/html/wp-content/plugins/dw_functionality_plugin/dw_functionality_plugin.phpon line 398 Here is the code string:
< > any help much appreciated! Edited March 23 by dwest100How can i handle what the user clicked in the Save File Dialog Box? if(user clicked "save") { i will send them an email; } else if (user clicked "cancel") { i will not send them an email; } is this possible? Please help me out guys. Thankyou I'm currently creating a web based application for the company I'm working on. It was just a simple application that I can surely done but there is one thing that become a hindrance... That thing is the situation wherein dialog box that keeps on popping whenever I clicked the submit button wherein supposed to be it should change page. Hope everyone could help. Thank you in advance. The Script:
$desired_width = 110; if (isset($_POST['submit'])) { $j = 0; //Variable for indexing uploaded image for ($i = 0; $i < count($_FILES['file']['name']); $i++) {//loop to get individual element from the array $target_path = $_SERVER['DOCUMENT_ROOT'] . "/gallerysite/multiple_image_upload/uploads/"; //Declaring Path for uploaded images $validextensions = array("jpeg", "jpg", "png"); //Extensions which are allowed $ext = explode('.', basename($_FILES['file']['name'][$i]));//explode file name from dot(.) $file_extension = end($ext); //store extensions in the variable $new_image_name = md5(uniqid()) . "." . $ext[count($ext) - 1]; $target_path = $target_path . $new_image_name;//set the target path with a new name of image $j = $j + 1;//increment the number of uploaded images according to the files in array if (($_FILES["file"]["size"][$i] < 100000) //Approx. 100kb files can be uploaded. && in_array($file_extension, $validextensions)) { if (move_uploaded_file($_FILES['file']['tmp_name'][$i], $target_path)) {//if file moved to uploads folder echo $j. ').<span id="noerror">Image uploaded successfully!.</span><br/><br/>'; $tqs = "INSERT INTO images (`original_image_name`, `image_file`, `date_created`) VALUES ('" . $_FILES['file']['name'][$i] . "', '" . $new_image_name . "', now())"; $tqr = mysqli_query($dbc, $tqs); // Select the ID numbers of the last inserted images and store them inside an array. // Use the implode() function on the array to have a string of the ID numbers separated by commas. // Store the ID numbers in the "image_file_id" column of the "thread" table. $tqs = "SELECT `id` FROM `images` WHERE `image_file` IN ('$new_image_name')"; $tqr = mysqli_query($dbc, $tqs) or die(mysqli_error($dbc)); $fetch_array = array(); $row = mysqli_fetch_array($tqr); $fetch_array[] = $row['id']; /* * This prints e.g.: Array ( [0] => 542 ) Array ( [0] => 543 ) Array ( [0] => 544 ) */ print_r($fetch_array); // Goes over to create the thumbnail images. $src = $target_path; $dest = $_SERVER['DOCUMENT_ROOT'] . "/gallerysite/multiple_image_upload/thumbs/" . $new_image_name; make_thumb($src, $dest, $desired_width); } else {//if file was not moved. echo $j. ').<span id="error">please try again!.</span><br/><br/>'; } } else {//if file size and file type was incorrect. echo $j. ').<span id="error">***Invalid file Size or Type***</span><br/><br/>'; } } }Hey, sorry that I am posting this darn image upload script again, I have this almost finished and I am not looking to ask more questions when it comes to this script specifically. With the script above I have that part where the script should store the ID numbers (the auto_increment column of the table) of the image files inside of one array and then the "implode()" function would get used on the array and then the ID numbers would get inserted into the "image_file_id" column of the "thread" table. As you can see at the above part the script prints the following: Array ( [0] => 542 ) Array ( [0] => 543 ) Array ( [0] => 544 )And I am looking to insert into the column of the table the following: 542, 543, 544I thought of re-writing the whole image upload script since this happens inside the for loop, though I thought maybe I could be having this done with the script as it is right now. Any suggestions on how to do this? I'm trying to pull results from a database (using php) to populate a javascript "top news rotation" script I found. The problem is that I'm getting the "java is disabled" message that is in the code...instead of the results I'm expecting. Here's the code: Code: [Select] <!-- create a element in your HTML like the following --> <div id="quotetext" > Text will go here. Be sure to add initial text here for users with JavaScript disabled. </div> <!-- The easiest way is to place the below JavaScript code after the above HTML. The better way would be to add in the <head> section of the document and call the rotatequote() function through the window.onload event. However this can cause problems if you have other scripts that use the window onLoad settings --> <script type="text/javascript" > var myquotes = new Array( <?php $link = mysql_pconnect($host, $username, $password); mysql_select_db('briansch_brn',$link); $sql = "SELECT * FROM story WHERE ORDER BY date DESC LIMIT 4"; $rs = mysql_query($sql,$link); $matches = 0; while ($row = mysql_fetch_assoc($rs)) { $matches++; echo "'<strong>$row[headline]</strong><br />(posted $row[date]) - $row[short_story]<br /><a href='/pages/$row[keyword]'>READ MORE</a>'"; if($matches < 4) { echo ','; } if($matches == 4) { echo ''; } } if (! $matches) { echo (""); } echo ""; ?> ); function rotatequote() { thequote = myquotes.shift(); //Pull the top one myquotes.push(thequote); //And add it back to the end document.getElementById('quotetext').innerHTML = thequote; // This rotates the quote every 10 seconds. // Replace 10000 with (the number of seconds you want) * 1000 t=setTimeout("rotatequote()",10000); } // Start the first rotation. rotatequote(); </script> I know that javascript inside php is hard to make work...and I know that php inside javascript is hard to make work. Any ideas? Thanks! ok. this may make now sense at all, I will try to explain as best as I can. anyways, what I need is for a mysql query to run that will pull all data from table payment between certain days. Then all the rows will show, but I want only one row with each cart_id(there will be multiple) to show. After it does that, in a new column on a table, all the payment types with the amount will show with a slash between each one. I want all of this in a table generated from a php loop. maybe a visual represenation will be better. I hope the picture I attached makes a bit more sense. Hey Guys, I have a DB with two tables, one is field names, the other is the data. So for example, I log in and I am user ID 1..... I need to query the DB to show all fields where user_id = 1 Field1 - Data1 Field2 - Data2 etc etc... This is what I have so far, but I dont get any output... $sql = "SELECT * FROM ".WPSC_TABLE_DATA." WHERE `user_id` == .$cu. ORDER BY id DESC"; $user= $wpdb->get_row($sql); while($user) { echo $user->name .' : '. $user->value .'<br />'; } Can you help please? Hi, I have a PHP script which I want to run from a different IP on my server. Example of what I want to do: My main ip: 4.5.6.7 Have several IP's on server. I want my PHP script (running from CLI) to use cURL with another IP, ay 4.5.6.9 Is this possible to do? Help would be greatly appreciated! Hi, Im trying to create a really simple password protected page that is fairly secure but when the user doesnt enter a password the wrong error is displayed. Can anyone see a problem? Also could someone please check that im properly compairing the hash password of 2135fa0dd7fb99d167b420b7ff34ec98 with what the user entered when its hashed? login.php <?php session_start(); ?> <?php $submit = $_POST['submit']; $password = md5($_POST['password']); if ($submit) { if ($password) { if ($password == '2135fa0dd7fb99d167b420b7ff34ec98') { $_SESSION['user'] = logged; header('Location: page.php'); } else { header('Location: index.php?id=1'); } } else { header('Location: index.php?id=2'); } } else { header('Location: index.php?id=1'); } ?> index.php <?php $id=$_REQUEST['id']; ?> <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Strict//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-strict.dtd"> <html lang="EN" dir="ltr" xmlns="http://www.w3.org/1999/xhtml"> <head> <meta http-equiv="content-type" content="text/xml; charset=utf-8" /> <title>Keys</title> <link rel = "stylesheet" type = "text/css" href = "css/layout.css" /> </head> <body> <div id="header"> <h1>Keys</h1> </div> <div id="secondheader"> </div> <div id="main"> <form method="POST" action="login.php"> Password: <input type="password" name="password" onfocus="selected(this)" onblur="notselected(this)"> <input type="submit" name="submit" value="Login"> </form> <br/> <?php if ($id==1) { echo "Invalid password. Please try again"; } elseif ($id==2) { echo "Please enter a password"; } ?> </div> <div id="footer"> </div> <div id="left"> </div> </body> </html> Thanks in advance. I am using MAMP on my MacBook and don't understand why MAMP and my code in NetBeans will not run if I am offline? If I am trying to execute PHP files locally on my laptop, why should MAMP or Apache of NetBEans care if I do not have an Internet connection?! I wanted to show someone something at work where there is no Internet access, but that won't work as it currently stands. TomTees Hi, actually the problem is i have been modifying a website, which has been already built and working. so i have all the code and everything, i need to keep it running to make changes. But i m facing problems like above Warning: require_once(../../global-inc.php) [function.require-once]: failed to open stream: No such file or directory in C:\\Apache2.2\htdocs\login.php on line 2 Fatal error: require_once() [function.require]: Failed opening required '../../global-inc.php' (include_path='.;C:\php5\pear') in C:\\Apache2.2\htdocs\login.php on line 2 please let me know what to do ... and the other thing is i need to execute the entire file of code at a time .....can u please tell me the process of doing it .......... thanks in advance shiva shiva I want to run a php file which contains a long process and takes time. If I simply run the file on browsers, the process will be interrupted by any perturbation in the internet connection or closing the browser. How I can force the php process to continue running without connection to my local PC (server side controlling)? I am looking for something like what cron job does (but only one time, not periodically). So I've coded this to run the while loop once for every server within the the table, there is currently two rows within the table and the while loop wont stop running it just keeps on running until I restart Apache, its producing the same effect as what "while(1)" would do, could anybody tell me what the problem could be?, thanks for your time in advance. class bot_restart { function __construct( ) { while($CurrentServers = mysql_fetch_array(mysql_query("SELECT * FROM xhost_boxs"))) { echo $CurrentServers['box_id']; } } } I am coding a browser game in php/mysql. the economy code needs to run at a regular interval. How can I get my code to run say, every 6/12/24 minutes? I heard of something called a cron job, but im not sure if it is going to be what I need. Okay I want to run some code every 24 hours, what would be the best way to do this? Also I don't have root to the server or anything. Hi i was wondering what im doing wrong, im trying to insert a query for submit button, it works if i run it straight in mysql, but not working when linked through php. Im just doing it for testing purpose right now only, so when i see that it works i will use another query. here it is Code: [Select] <?php include('config.php'); if($_SESSION['username']){ if(isset($_POST['ASubmit'])){ $query3=("update country set Status='test1' where Uname='Mclovin'");} echo '<td><form name="test" method="post" form id="form1"><label for="test">Status</label> <select name="Status"> <option value="">-----</option> <option value="In process" '.(($row['Status']=='In process')?'selected="selected"':'').'>In process</option> <option value="Approved" '.(($row['Status']=='Approved')?'selected="selected"':'').'>Approved</option> <option value="Denied" '.(($row['Status']=='Denied')?'selected="selected"':'').'>Denied</option> </select><input name="ASubmit" type="submit" value="Update">'; echo $row{'Status'}.'</td></form>'; } ?> Hey everyone, I have an SQL file called "Cype.sql" and I was wanting to have it run when the install feature is going on. However I can't seem to figure out why exactly the code is not working. is it possible to have it run without getting too in depth the PHP coding? I'm not OOP Literate yet. //Connection is opened //While in installation file $sqlFile = "Cype.sql"; if(!file_exists($sqlFile)){ echo "File not found"; } else{ $openFile = fopen($sqlFile, "r"); $tryQuery = mysql_query($openFile); } Now obviously, I'm not the best coder. I've been out of the works of PHP for quite some time now as well. However, I have researched it and found no answers to my issue. Any help would be greatly appreciate. Thank you. Hi, i need some help with my script to take data from mysql database to be used for a login. Created table, with registration, checked passwords and such but the login button when clicked does nothing? please help <?php $username = $_POST['username']; $password = $_POST['upassword']; $self = $_SERVER['PHP_SELF']; $referer = $_SERVER['HTTP_REFERER']; #if either form field is empty return to the log-in page if( (!$username ) or (!$password ) ) { header( "Location:$referer" ); exit(); } #connect to mysql $conn = @mysql_connect( "server", "username", "password ) or die( "Could not connect" ); #select database $rs = @mysql_select_db( "removalspacelogin", $conn ) or die ( "Could not select db" ); #create query $sql="select * from users where username=\"$username\" and password = password( \$password\" )"; #execute query $rs = mysql_query( $sql, $conn ) or die( "Could not execute query" ); #get number of rows that match username and password $num = mysql_numrows( $rs ); #if there is a match the log-in in done if( $num != 0 ) { $msg = "Welcome $username - your log-in was successfull!"; } else #or return to: login.php { header( "Location:www.removalspace.com/wrong.html" ); exit(); } ?> <html> <head><title>Check-login</title></head> <body> <?php echo( $msg ); ?> </body> </html> |