PHP - Hrefs Not Finding Path For Mysql File Uploaded
Hi:
I'm a newby regarding uploading files to MySQL, turning report output into an HREF, and getting MySQL data via a hyperlink. I have successfully uploaded, files to MySQL, I have also been able to display filename information as a hyperlink in report output, but when I click on the hyperlink, I get the following message format on a 404 page: The requested URL /current_dir_of_requesting_page/filename.filetype was not found on this server. My reporting page has teh following line of code in a report table to create the hyperlink: <td style="width:225px"><? echo "<a href=".$row['name'].">".$row['name']."</a>";?></td> Can anyone assist me with this? Similar TutorialsGiven a directory - folder1/subfolder1, I would like to loop through all subdirectories under the given directory and return the file path relative to the given directory. Example: Code: [Select] Given Directory FolderA FolderB SubFolderA SubFolderB SubSubFolderA File1 FolderC the file path for File1 should be FolderB/SubFolderB/SubSubFolderA/ Any ideas? Hey everyone, I posted something similar to this before and thought I had received an answer, but for whatever reason, the script I wrote had inconsistent functionality. It would work sometimes, but not others. At any rate I had to completely revamp the script. Now I'm having the same initial problem with this new script. Basically, what I'm trying to do is get my PHP script to upload a file, insert form info into the MySQL Database Table, and insert the name of the uploaded file into the MySQL Database table as well. I've been able to get everything to work except inserting the name of the uploaded file into the MySQL Database table. I'll show you what I have currently (a stripped down version anyway) then any suggestions you could give would be much appreciated! Please help! I've been working on this for the past month and keep running into issues: Code: [Select] <?php $target_path = "Images/"; $target_path = $target_path . basename($name = $_FILES['pic']['name']); $first_name=$_POST['first_name']; $last_name=$_POST['last_name']; $middle_init=$_POST['middle_init']; mysql_connect("localhost", "My_Username", "My_Password") or die(mysql_error()) ; mysql_select_db("My_Database") or die(mysql_error()) ; if (!$_POST['first_name'] | !$_POST['last_name'] | !$_POST['middle_init']) { header('Location:http://www.mysite.com/error.html'); die(); } $insert = "INSERT INTO image (first_name, last_name, middle_init, name) VALUES ('".$_POST['first_name']."', '".$_POST['last_name']."', '".$_POST['middle_init']."', '".$_POST['name']."')"; $add_member = mysql_query($insert); move_uploaded_file($_FILES['pic']['tmp_name'], $target_path) ?> <HTML> <HEAD> <TITLE>My Site</TITLE> HTML "Confirmation Script" continues on from there. Like I said before, everything works except the name of the uploaded file doesn't get inserted into the MySQL table. Oh...that specific field in the MySQL table is titled "name". Anyway, again, any help you could give would be awesome! Thanks! Hello, I'm having some frustrations right now. I have built an application form where an applicant inputs their info and then uploads their resume. Even though the resume gets uploaded to a directory on the server i would also like the file name of the resume to get inserted into the mysql database so that I can easily see which resume matches which applicant...if that makes sense. At any rate I'm able to get everything else to work, the applicant's info gets inserted into the database, the resume gets uploaded to the directory, i just can't seem to get the resume file name to also insert into the database. Most of the info i have found on this subject through googleing and the like has been a little over my head and/or a little more complex than what i'm looking for. Here is an extremely simplified version of what I have right now. I have excluded the 'connect to database' code since it's working fine and really doesn't have anything to do with this issue: Code: [Select] <?php $target_path = "docs/"; $target_path = $target_path . basename( $_FILES['resume']['name']); $first_name=$_POST['first_name']; $last_name=$_POST['last_name']; $middle_init=$_POST['middle_init']; $resume=$_POST['resume']; mysql_query("INSERT INTO `intern` VALUES ('$first_name', '$last_name', '$middle_init', '$resume')") ; if (move_uploaded_file($_FILES['resume']['tmp_name'], $target_path)); ?> HTML begins after that. At any rate, any info, help, etc. you could provide would be GREATLY appreciated! Thanks! I am trying to find the URL to a directory TWO levels above the script level (if you know what I mean). For example.. the script sits at Code: [Select] http://www.domain.com/TestArea2/members/index.php BUT I need to find the path to Code: [Select] http://www.domain.com/TestArea2/ the nearest I get is... $domain = $_SERVER['HTTP_HOST']; $domain .= $_SERVER['REQUEST_URI']; echo $domain; // outputs www.domain.com/TestArea2/members/index.php Is there a simple method to do this or have I got to split the string and work backwards? Many thanks I need help making the uploaded image file name, that's chosen to be uploaded, be displayed on the html page with the path /upload/ added to the beginning of the displayed file name like so: ../upload/test.png Any help/improvements will be appreciated. <html> <head> <title>PHP Test</title> </head> <body> <?php if ($form_submitted == 'yes') { $allowedExts = array("gif", "jpeg", "jpg", "png"); $temp = explode(".", $_FILES["file"]["name"]); $extension = strtolower( end($temp) ); if ( $_FILES["file"]["size"] < 200000 && in_array($extension, $allowedExts) ) { if ($_FILES["file"]["error"]!= 0) { echo "Return Code: " . $_FILES["file"]["error"] . "<br>"; } else { $length = 20; move_uploaded_file($_FILES["file"]["tmp_name"], "upload/" . $newfilename ); $file_location = '<a href="http://../upload/' . $newfilename . '">' . $newfilename . '</a>'; } } else { echo "Invalid upload file"; } ?> <label for="file">Filename:</label> <input type="file" name="file" id="file"> </body> </html> Hi! So I'm working for someone, and they want me to fix this error in a PHP file.. Here is the code: <?php include_once('config.php'); $online = mysql_query("SELECT * FROM bots WHERE status LIKE 'Online'"); $offline = mysql_query("SELECT * FROM bots WHERE status LIKE 'Offline'"); $dead = mysql_query("SELECT * FROM bots WHERE status LIKE 'Dead'"); $admintrue = mysql_query("SELECT * FROM bots WHERE admin LIKE 'True'"); $adminfalse = mysql_query("SELECT * FROM bots WHERE admin LIKE 'False'"); $windows8 = mysql_query("SELECT * FROM bots WHERE so LIKE '%8%'"); $windows7 = mysql_query("SELECT * FROM bots WHERE so LIKE '%7%'"); $windowsvista = mysql_query("SELECT * FROM bots WHERE so LIKE '%vista%'"); $windowsxp = mysql_query("SELECT * FROM bots WHERE so LIKE '%xp%'"); $unknown = mysql_query("SELECT * FROM bots WHERE so LIKE 'Unknown'"); $totalbots = mysql_num_rows(mysql_query("SELECT * FROM bots")); $onlinecount = 0; $offlinecount = 0; $deadcount = 0; $admintruecount = 0; $adminfalsecount = 0; $windows8count = 0; $windows7count = 0; $windowsvistacount = 0; $windowsxpcount = 0; $unknowncount = 0; while($row = mysql_fetch_array($online)){ $onlinecount++; } while($row = mysql_fetch_array($offline)){ $offlinecount++; } while($row = mysql_fetch_array($dead)){ $deadcount++; } while($row = mysql_fetch_array($admintrue)){ $admintruecount++; } while($row = mysql_fetch_array($adminfalse)){ $adminfalsecount++; } while($row = mysql_fetch_array($windows8)){ $windows8count++; } while($row = mysql_fetch_array($windows7)){ $windows7count++; } while($row = mysql_fetch_array($windowsvista)){ $windowsvistacount++; } while($row = mysql_fetch_array($windowsxp)){ $windowsxpcount++; } while($row = mysql_fetch_array($unknown)){ $unknowncount++; } $statustotal = $onlinecount + $offlinecount + $deadcount; $admintotal = $admintruecount + $adminfalsecount; $sototal = $windows7count + $windowsvistacount + $windowsxpcount + $unknowncount; ?> Can anyone tell me the error here, can how to fix it? I don't know, it seemed simple but it turns out I don't know what to do.
I was told that storing a photo as a blob was much harder than simply storing a photo's url or directory location...
So... when a file has been selected through the browse-file manager triggered by
<input type="file"...>and the file selected is shown, when a person pusehs "upload" what is supposed to happen? Do I need some kind of FTP client to access the server and place the photo in there? It seems so easy in a way like the built in filemanager in cPanel... What am I missing? Thanks for any help. <td><label for='images'> <b>File to upload:</b> </label></td> <td><input type='file' name = 'drama_image' '<?php echo $row['drama_image']; ?>'/></ </tr> <?php $target_path = "images/"; $target_path = $target_path . basename( $_FILES['images']['name']); if(move_uploaded_file($_FILES['images']['tmp_name'], $target_path)) { echo "The file ". basename( $_FILES['images']['name']). " has been uploaded"; } else{ echo $row['drama_image']; } ?> ['drama_image'] is the name of the file I wanna echo it out in the box of file upload so when I save , the default picture will still be there instead of being overwritten as the box does not have any value in it. Hey guys, total newb when it comes to php. any help here would be much apreciated, what i am trying to achieve is to allow a person to upload a jpg image that he wants displayed on a dynamic flash site, but seeing as the flash is looking for xx.jpg, is it possible that any jpg file he uploads , say its called golf.jpg, is automatically uploaded/renamed to xx.jpg ? so i dont have to get him to rename the files before uploading. i attempted to understand a short tutorial on doing this but failed, here is what code i used. ( i added that rename line, looking at it now sorta seems like a really lame attempt lol ) Code: [Select] <?php $target = "upload/"; $target = $target . basename( $_FILES['uploaded']['name']) ; $ok=1; rename ("*.jpg", "xx.jpg"); //This is our size condition if ($uploaded_size > 350000) { echo "Your file is too large.<br>"; $ok=0; } //This is our limit file type condition if ($uploaded_type =="text/php") { echo "No PHP files<br>"; $ok=0; } //Here we check that $ok was not set to 0 by an error if ($ok==0) { Echo "Sorry your file was not uploaded"; } //If everything is ok we try to upload it else { if(move_uploaded_file($_FILES['uploaded']['tmp_name'], $target)) { echo "The file ". basename( $_FILES['uploadedfile']['name']). " has been uploaded"; } else { echo "Sorry, there was a problem uploading your file."; } } ?> <body> <form enctype="multipart/form-data" action="upload.php" method="POST"> Please choose a file: <input name="uploaded" type="file" /><br /> <input type="submit" value="Upload" /> </form> cheers I have a made a section on my site where I can upload files to a specific directory, rename them and delete them. So I don't have to go through a FTP program. When renaming and deleting a file I connect using FTP commands with PHP, except when uploading. When uploading it gets the file that has been uploaded from the form on the page before which has its own code using <input type="file"> to search for a local file, then when submit is clicked it uploads it. Then on my PHP script it moves that file from the temp upload folder to the actual site. Bottom line is, is there any way I can make a button that opens a file browser on the users PC and returns the filepath chosen? So I can use FTP to upload the file rather than the form? anyone can show example how i could remane the uploaded file name with users id along with some number? Code: [Select] //////////////////////////////////////uploader else if($action=="uploader") { echo "Upload your picture and copy the link <br/>after uploading to user it at gallery.<br/><br/>"; echo "<form method=\"post\" enctype=\"multipart/form-data\" action=\"index.php?action=uploaded&sid=$sid\">"; echo "Choose Pictu <br />"; echo "<input name=\"uploaded\" type=\"file\" /><br /><br />"; echo "<input type=\"submit\" value=\"Upload\" />"; echo "</form><br/>"; echo "<p align=\"center\">"; echo "<a href=\"index.php?action=main&sid=$sid\">Home</a>"; echo "</p>"; } //////////////////////////////////////uploader else if($action=="uploaded") { $blacklist = array(".php", ".php.jpg", ".php.jpeg", ".php.gif", ".php.png", ".phtml", ".php3", ".php4"); foreach ($blacklist as $item) { if(preg_match("/$item\$/i", $_FILES['uploaded']['name'])) { echo "<p align=\"center\">"; echo "Oops sorry we do not allow those files.<br/>"; echo "<a href=\"index.php?action=main&sid=$sid\">Home</a>"; echo "</p>"; exit; } } $target = "../images/"; $target = $target . basename( $_FILES['uploaded']['name']) ; $ok=1; if (file_exists("../images/" . $_FILES["uploaded"]["name"])) { echo "<p align=\"center\">"; echo $_FILES["file"]["name"] . "Oops file name already exists<br/> kindly rename your picture and upload again. <br/>"; echo "<a href=\"index.php?action=main&sid=$sid\">Home</a>"; echo "</p>"; }else{ //This is our size condition if ($uploaded_size > 25600){ echo "Your file is too large. We have a 25kb limit.<br/>"; $ok=0; } $types = array('image/jpeg', 'image/gif', 'image/png'); if (in_array($_FILES['uploaded']['type'], $types)) { // file is okay continue } else { $ok=0; } //Here we check that $ok was not set to 0 by an error if ($ok==0){ echo "<p align=\"center\">"; Echo "Sorry your file was not uploaded.<br/> It may be the wrong filetype. <br/>We only allow JPG, GIF, and PNG filetypes.<br/>"; echo "<a href=\"index.php?action=main&sid=$sid\">Home</a>"; echo "</p>"; } //If everything is ok we try to upload it else{ if(move_uploaded_file($_FILES['uploaded']['tmp_name'], $target)){ echo "<p align=\"center\">"; echo "The file ". basename( $_FILES['uploadedfile']['name']). " Picture uploaded successfully.<br/><br/><b>$target <br/>"; echo "<a href=\"index.php?action=main&sid=$sid\">Home</a>"; echo "</p>"; } else{ echo "<p align=\"center\">"; echo "Sorry, there was a problem uploading your file.<br/>"; echo "<br/><a href=\"http://index.php?action=main&sid=$sid\">Wml Home</a><br />"; echo "<a href=\"index.php?action=main&sid=$sid\">Home</a>"; echo "</p>"; } } } } [code] Why does the following code not detect the following file? After I select a file and I click upload, it goes back to the upload form. <?php include_once("includes/config.php"); //grab their type if(!$_COOKIE['user']) { //they are a guest $info = "Guest"; } else { //they are a user $info = $_COOKIE['user']; } if(!$_FILE['file']) { $content = '<form action="submit.php" method="post" enctype="multipart/form-data"> <label for="file">SELECT SKIN:</label> <input type="file" name="file" id="file" /> <input type="submit" name="submit" value="Submit" /> </form>'; } else { if($_FILES['file']['error'] > 0) { $content = "There was an error trying to upload the skin ".$_FILES['file']['name'].".".$_FILES['file']['error']; } } ?> <html> <head> <title><?php $title; ?></title> <link rel="stylesheet" type="text/css" href="theme/style.css" /> </head> <body> <div id="header"> MCSkins </div> <?php echo "Submitting as: ".$info."<br/><br/>".$content; ?> </body> </html> What's the maximum file size I can upload through a regular form ? If it's server dependant, how do I find out my max ? I tried to handle a 550MB file (on localhost) - I only wanted to show the filename, but it hung up for about 10secs, then returned nothing. My 1st try practice uploading file to the server and it was successful. Now I wonder how can I set a default file name to the file that will be uploaded and overwrite the existing one. I have tried experimenting on the code but I can't get it to work. Here's my simple code.. edit_logo.php Code: [Select] <?php <form enctype="multipart/form-data" method="post" action="uploaded_logo.php"> <input type="hidden" name="MAX_FILE_SIZE" value="100000" /> <tr> <td>Choose a Logo to Upload: </td> <td><input name="uploaded_file" type="file" /></td> </tr> <tr> <td> </td> <td><input type="submit" value="Upload File" name="submit>"</td> </tr> </form> ?> uploaded_logo.php Code: [Select] <?php if($_FILES['uploaded_file']["type"] == "image/gif") { $target_path = "logo/"; $target_path = $target_path. basename($_FILES['uploaded_file']['name']); if(move_uploaded_file($_FILES['uploaded_file']['tmp_name'], $target_path)) { echo "<span class=\"error_validation\">The Logo has been successfully changed!<br></span>"; echo "<span class=\"error_validation\">Upload Logo Again? <a href=\"edit_logo.php\">Click Here</a><br></span>"; } else { echo "<span class=\"error_validation\">There was an error uploading the logo. Pls. try again.<br></span>"; echo "<span class=\"error_validation\">Upload Logo Again? <a href=\"edit_logo.php\">Click Here</a><br></span>"; } } else { echo "<span class=\"error_validation\">Invalid file format. We are only accepting image file. Pls. try again.<br></span>"; echo "<span class=\"error_validation\">Upload Logo Again? <a href=\"edit_logo.php\">Click Here</a><br></span>"; } ?> So what the code suppose to do is.. If I upload an image file as the new logo it should have the default logo name "my_logo.gif", then it will overwrite the existing one... Anyone? Hi guys, I need some PHP/jquery code that constantly checks a folder for when files are added to it, then grabs the file/s and processes them through a php function. Any ideas how I can automate this, I am happy for a browser window to have to be open to do it (that would be the only way I think) but now I just need the web based code to go with it. Any help/suggestions are much appreciated. Cheers in advance. Hi I need to change the name of a file being uploaded by a user. The reason i need this is because there is a strong possibility that duplicate filenames would be logged. This is the code i have currently: Code: [Select] $upload_path = 'cv/'; // The place the files will be uploaded to (currently a 'files' directory). $filename = $_FILES['userfile']['name']; // Get the name of the file (including file extension). $ext = substr($filename, strpos($filename,'.'), strlen($filename)-1); // Get the extension from the filename. // Check if we can upload to the specified path, if not DIE and inform the user. if(!is_writable($upload_path)) die('You cannot upload to the specified directory, please CHMOD it to 777.'); // Upload the file to your specified path. if(move_uploaded_file($_FILES['userfile']['tmp_name'],$upload_path . $filename)); This code works fine to upload the file in the current name. I assume i need to seperate the filename from the file extension, and i can then assign a new variable to the filename. Easier said than done though as Ive tried many combinations of things. Is there a simple way using this script? or will i need to start from scratch? Cheers Hi Guys, I have this script below which inserts the file name and path into my datebase and uploads the file into the customers folders (which is creates dynamically). The is no error checking as I want it to be as flexible as possible but mostly(99.999%) the files I upload are JPEG and PDF's. I would like my script to be able to resize the files above automatically to be smaller. Please is this possible thanks! Here is script: <?php //Will create a directory once a customer is clicked and will not if page is refreshed an so forth if (file_exists('customerUploads/' . $check_id . ', ' . $c_name . '')) { } else { mkdir('customerUploads/' . $check_id . ', ' . $c_name . ''); } ?> <?php //This php block of code will takecare of inserting the upload variables into the db if(isset($_POST['submitbutton'])) { $target_path = 'customerUploads/' . $check_id . ', ' . $c_name . '/'; $target_path = str_replace("'","",$target_path); $target_path = $target_path . basename( $_FILES['upload']['name']); $manager= mysql_real_escape_string($_POST['username']); $upload = $_FILES['upload']['name']; $upload = str_replace("'","",$upload); $check_id = mysql_real_escape_string($_POST['id']); $submitbutton= mysql_real_escape_string($_POST['submitbutton']); if($submitbutton) { if($manager&&$upload) { if (file_exists($target_path)) { echo $_FILES["upload"]["name"] . " already exists. "; } else { move_uploaded_file($_FILES["upload"]["tmp_name"],$target_path); echo "Stored in: " . 'customerUploads/' . $check_id . ', ' . $c_name . '/' . $_FILES["upload"]["name"]; $insert=mysql_query("INSERT INTO img_up (username,upload,id,target_path,img_date) VALUES ('$manager','$upload','$check_id','$target_path', now()) "); // Where the file is going to be placed $target_path = 'customerUploads/' . $check_id . ', ' . $c_name . '/'; /* Add the original filename to our target path. Result is "uploads/filename.extension" */ $target_path = $target_path . basename( $_FILES['upload']['name']); $target_path = 'customerUploads/' . $check_id . ', ' . $c_name . '/'; $target_path = $target_path . basename( $_FILES['upload']['name']); if (file_exists($target_path)) { echo $_FILES["upload"]["name"] . " already exists. "; } else { move_uploaded_file($_FILES["upload"]["tmp_name"],$target_path); echo "Stored in: " . 'customerUploads/' . $check_id . ', ' . $c_name . '/' . $_FILES["upload"]["name"]; } } } else { echo "There was an error uploading the file, please try again!"; } } header("location: mainupload_complete.php?id=$check_id"); } ?> Hi, I want to be able to let user upload XML form, and then in the action page it needs to extract that so that I can add it to the database. Here is the upload form: Code: [Select] <html> <head></head> <body> <form method='post' action="uploadFileToDB.php" enctype="multipart/form-data"> <p> <label> Upload image<input type='file' name='imageFileType' id='imageFileType' /> </label> </p> <p> <input type='submit' value='Upload this image' name='upload' id='upload' /> </p> </form> </body> </html> Here is the uploadFileToDB.php: Code: [Select] <?php require("PHP_xml_parsing_via_DOM.php"); //NB: this script does the actual shreddering (XML to SQL) //IF User uploaded dir or XML file successful, then: if(isset($_POST['upload'])) { //SHRED NOW //NB: how to retrieve the uploaded xml file $_filePath=?? $node=basename($_filePath); $dom=new DOMDocument(); $dom->load($node); $labelPath=array(); mysql_connect("localhost","root"); mysql_select_db("dummydpev7"); $isXdocExist=mysql_query("SELECT file_Path,file_Name FROM xdocument WHERE file_Path='$_filePath' AND file_Name='$node'"); $docId=0; if(mysql_num_rows($isXdocExist)==1) { print "Entry already exists!"; $docId=mysql_next_id("xdocument")-1; } else { mysql_query("INSERT INTO xdocument (file_Path,file_Name) VALUES ('$_filePath','$node')"); $docId=mysql_next_id("xdocument")-1; } print "<br />".$docId; writeXMLtoDBViaDOM($dom->documentElement,$labelPath,$docId,$_filePath); } //ELSE else //Please upload Valid XML print "Problem with XML file being uploaded."; ?> The question in point is how do I extract the file I uploaded to set to $_filePath?? in the script so that I pass it to my function writeXMLtoDBviaDOM?? Please any help much appreciated! Hi everyone, im a newbie and have written this script, has taken me a day to get here. The form inserts data into the database, uploads a file and sends an email. All this works fine, what i am trying to do is rename the file to the id of the record and check to make sure it is a pdf. I would really appreciate any help. I've tried and tried and just cant get it to work. <?php switch ($_REQUEST['action']) { case 'recruit': foreach($_POST as $key=>$value){ $$key = $value; } if ((!$name) || (!$email) || (!$phone)) { $error_msg = 'Fields marked<span class="gold"> * </span>are required to submit the form'; }elseif (!eregi("^[_a-z0-9-]+(\.[_a-z0-9-]+)*@[a-z0-9-]+(\.[a-z0-9-]+)*(\.[a-z]{2,3})$", $email)) { $error_msg = 'Invalid email address'; } echo "$error_msg","<br><br>"; if ($error_msg == ''){ $date=date("d/m/y", time()); $add="recruitment/".$_FILES[userfile][name]; $cleaned = stripit($add); $add2 = $cleaned; if(move_uploaded_file ($_FILES[userfile][tmp_name], $add2)); $Q = mysql_query("INSERT INTO recruitment (`name`,`phone`,`email`, `qual`,`exper`,`file`) VALUES ('$name','$phone','$email','$qual','$exper','$cleaned')"); foreach($_POST as $key=>$value){ $$key = htmlentities(stripslashes($value)); } $companyname = 'Mead Business college'; $companyemail = 'ross@emediastudios.com.au'; $headers = "MIME-Version: 1.0\r\n"; $headers .= "Content-type: text/html; charset=iso-8859-1\r\n"; $headers .= "From: ".$name." <".$email.">\r\n"; $headers .= "Reply-To: ".$name." <".$email.">\r\n"; $to = "".$companyname."<".$companyemail.">"; $subject = "Mead Business College Recruitment Form Submission"; $message = '<style type="text/css>"; <!-- .style { font-family: Verdana, Arial, Helvetica, sans-serif; font-size: 10px; } --> </style> <table width="100%" border="0" cellspacing="0" cellpadding="0"> <tr> <td class="style"> <b>Details:</b><br /><br /> <b>Name:</b> '.$name.'<br /> <b>Email:</b> '.$email.'<br /> <b>Mobile No:</b> '.$phone.'<br /> <b>Qualifications:</b><br> '.$qual.'<br /> <b>Experience:</b><br /><br />'.$exper.'<br /><br /> <b>Uploaded resume:</b> http://www.mydomain.com.au/'.$cleaned.' </td> </tr> </table>'; mail($to, $subject, $message, $headers); echo '<table width="99%" border="0" cellpadding="0" cellspacing="0"> <tr> <td class="mybody">Hi '.$name.',<p />Thank you for your enquiry. An MBC Consultant will contact you shortly.<br /> <br /> </td> </tr> </table>'; }else{ foreach($_POST as $key=>$value){ $$key = htmlentities(stripslashes($value)); } echo ' <FORM ENCTYPE="multipart/form-data" id="form" name="Contact Form" method="post" action="'.$_SERVER['PHP_SELF'].'?action=recruit"> <table width="489" border="0" cellspacing="5" cellpadding="0" class="formsw"> <tr> <td width="227">Name:</td> <td width="358"><input type="text" name="name" id="name" value="'.$name.'" /></td> </tr> <tr> <td>Contact Mobile:</td> <td><input type="text" name="phone" id="phone" value="'.$phone.'" /></td> </tr> <tr> <td>Email:</td> <td><input type="text" name="email" id="email" value="'.$email.'" /></td> </tr> <tr> <td>Relevent Qualifications:</td> <td><textarea name="qual" id="qual" cols="45" rows="5" value="'.$qual.'"></textarea></td> </tr> <tr> <td>Recent Experience:</td> <td><textarea name="exper" id="exper" cols="45" rows="5" value="'.$exper.'"></textarea></td> </tr> <tr> <td>Upload Resume:</td> <td><input type="file" name="userfile" id="userfile" /></td> </tr> <tr> <td><input type="submit" name="submit" id="submit" value="Submit" /></td> <td> </td> </tr> </table> </form>'; } break; } ?> |