PHP - Preg_replace Help Needed!

Hi there!

I need to echo some text from a database table, this text should be linked to a url stored in the same database. I am trying to do this with preg_replace but I am terrible at it! I keep getting this error:

Warning: Wrong parameter count for preg_replace()

while($row = mysql_fetch_array( $result ))
 {

$reg_exUrl = "/(http|https|ftp|ftps)\:\/\/[a-zA-Z0-9\-\.]+\.[a-zA-Z]{2,3}(\/\S*)?/";

echo preg_replace ($reg_exUrl, $row['title');


Any suggestion?

Thanks

I currently have some custom tags, similar to BBCode, to be used for comments on my site. I'm trying to create a [nobr] tag (note: I know the no break tag will work in many major browsers, but it's deprecated, so I'm trying to be compliant).

The idea is that if I encounter the [nobr] tag, I need to remove all line breaks. Here's the best I can do, but it's not working as I had hoped.

Here's what I currently use to replace line breaks with a break tag.
Code: [Select]
$str=str_replace("\r\n","<br>",$str);

Here's my attempt at introducing this new tag.
Code: [Select]
function BbToHtml($str) {

 $before=preg_replace("/(.+)\[nobr\](.+)\[\/nobr\](.+)/Usi","\\1",$str);
 $during=preg_replace("/(.+)\[nobr\](.+)\[\/nobr\](.+)/Usi","\\2",$str);
 $after=preg_replace("/(.+)\[nobr\](.+)\[\/nobr\](.+)/Usi","\\3",$str);

 $during=str_replace("\r\n","",$during);

 if($during != "") { // If the [nobr] tag was found, go with the new string.
  $str = $before.$during.$after;
 }
 else { // If the [nobr] tag was not found, go ahead like normal.
  $str=str_replace("\r\n","<br>",$str);
 }

 return $str;

I can't get that working. Any ideas on how to fix that, or a completely alternate method of doing it? Thank you!

I'm trying to search a string for all occurences of a pattern, then append text after that pattern.  The example is:   SUM("foo") as "bar"   and have it display as:   SUM("foo") over() as "bar"   The "SUM" could be any SQL aggregate and be case insensitive.  So For bonus points, let's say the valid aggregates are  array('SUM', 'MAX', 'MIN', 'AVG').  My plan right now is to figure it out for SUM, then loop it replacing the aggregate.   This is what I have so far... and it is not working.   $l= 'SUM("foo") as "bar"'; $l=preg_replace('/([^"]+")/','\0 over()',$l);   Thanks,   Ryan

Hello ppl,
I have this website link http://www.somesite.com/anotherpage/yetotherpage.html what i want to make is using preg_replace that the final result will be www.somesite.com

Hi everyone,

how do i add and ampersand symbol into preg_replace

preg_replace("/[^a-zA-Z0-9\s\-\'\,\.\_]/"

where do i place the symbol? &

im trying to do a complex(i think) prg replace but i keep getting the error:

Code: [Select]
Failed evaluating code: $lang->showing-1,1
the code i am trying to replace is:

Code: [Select]
<asf: lang[showing-<asf: var[num_report_alerts]>,<asf: var[num_report_alerts]>]>
and the preg_replace is:

Code: [Select]
$content = preg_replace('|\<asf: lang\[(.*?)-(.*?)\]\>|e', '$lang->replace_vars($lang->//1, array(\\2))', $content);
its supposed to take everything inside <asf: lang[]> and echo \\1 which would be "showing" and then add \\2 into an array which would be "array(1,1)".

So the output would be showing 1 of 1.

Anyone know where im going wrong?

I have no idea what the problem is with preg_replace and strings smaller than 3 characters. I'm writing to do a pattern search of abreviations(array) and replacements (array)... tried word boundries, which seems not to work at all. (it is VITAL that im able to match the whole word)
here is a quick example which I cannot understand maybe someone could explain to me:
1. why repitions of certain abrevs do not get replaced.
2. why '/\bs.\b/' wont get matched (where there is a space before  the b. - hense the word boundry)

here is a snippet of code could someone please explain why this happens:

Code: [Select]
<?php
  $string='de d. s. pres. div. de de d. s.';
 
//DEFINE PATTERN
$patterns = array();
$patterns[0] = '/ s. /';
$patterns[1] = '/ b. /';
$patterns[2] = '/ pres./';
$patterns[3] = '/ Ind./';
$patterns[4] = '/ Mar./';
$patterns[5] = '/ Agt./';  
$patterns[6] = '/ Agy./';  
$patterns[7] = '/ Indpls./';                            
$patterns[8] = '/ Chgo./';
$patterns[9] = '/ Corp./';
$patterns[10] = '/ U./';    
$patterns[11] = '/ Fin./';          
$patterns[12] = '/ ls./';   
$patterns[13] = '/ Pres. /';    
$patterns[14] = '/ Internat. /';   
$patterns[15] = '/ m. /';
$patterns[16] = '/ N.Y.C./';   
$patterns[17] = '/ div. /';   
$patterns[18] = '/ de /';  
$patterns[19] = '/ d. /';    


//DEFINE PATTERN REPLACE
$replacements = array();
$replacements[0] = ' son of ';
$replacements[1] = ' born in ';
$replacements[2] = ' president';
$replacements[3] = ' Indiana ';
$replacements[4] = ' March ';
$replacements[5] = ' Agent ';  
$replacements[6] = ' Agency ';  
$replacements[7] = ' Indianapolis ';                            
$replacements[8] = ' Chicago';
$replacements[9] = ' Corporation ';
$replacements[10] = ' U '; 
$replacements[11] = ' Financial ';       
$replacements[12] = ' Island';   
$replacements[13] = ' President '; 
$replacements[14] = ' International ';  
$replacements[15] = ' married to ';
$replacements[16] = ' New York City ';   
$replacements[17] = ' divorced';    
$replacements[18] = ' de '; 
$replacements[19] = ' daughter of ';    

 echo '------ Original ---------<br>'.$string.'<br>';
$data = preg_replace($patterns, $replacements, $string);
 echo '<br>------ Abbreviation Replace ---------<br>'.$data.'<br>';  
?>

OUTPUT: ------ Original ---------
de d. s. pres. div. de de d. s.

------ Abbreviation Replace ---------
de daughter of son of president divorcedde daughter of d. s.

any help is appriciated thanks.

i want to remove any links which get pulled  out in my general information query.

Code: [Select]
$general_info = $row['general_info'];
$general= preg_replace('/<a href="([^<]*)">([^<]*)<\/a>/', '', $general_info);

echo '<h2>General Information : <img src="images/mag.png"></h2>';
echo '<div id="featurecontent">';
echo '<p>'. ucfirst($general).'</p>';
echo '</div>';
But the above code doesnt seem to be stripping out links.

Can anyone see what i am doing wrong.

Kind Regards

Dean

how is it possible to allow someone to do paragraphs when using preg_replace? would someone show a few good examples of hows its done?

I'm working with the youtube API and the function Code: [Select]
$relatedVideo->watchURL returns a video url

However when I use Code: [Select]
preg_replace("youtube","test",$relatedVideo->watchURL); it gives me the following error
Code: [Select]
preg_replace() [<a href='function.preg-replace'>function.preg-replace</a>]: Delimiter must not be alphanumeric or backslash in <b>C:\wamp\www\site\test.php</b> on line <b>317
Help please?

i'm having trouble in combining the 2 preg_replace into 1.
basically i have a string witch strange chars, first i remove all except alphanumeric chars and the remaining string has 1 or 2 spaces and i replace them with dash.
Code: [Select]
strtolower(preg_replace('/\s+/', '-', preg_replace("/[^0-9a-zA-Z]/i", ' ',$a['item'])));

This topic has been moved to PHP Regex.

http://www.phpfreaks.com/forums/index.php?topic=350441.0

Okay, i know there are lots of these questions out there and tons of ways to do this. I do have it working to replace URLs with <a href="URLs">URLs</a> but now i need some help detecting <a href=""></a> so the preg_replace will not double up the code and mess up the link.

here is my code so far.
Code: [Select]
<?php
echo 'COMMENTS<br /><br />';
  while($rows = mysql_fetch_array($comres)){
  list($comid, $menu_title, $post_id, $comdate, $comname, $comment) = $rows;
  $comment = nl2br($comment);
  $comment = preg_replace('/(http|https|ftp|ftps)\:\/\/[a-zA-Z0-9\-\.]+\.[a-zA-Z]{2,3}(\/\S*)?/', '<a href="$0" target="_new">$0</a>', $comment);
  $comment = str_replace("&acute;", "'", $comment);
  $comdate = date("g:ia - M j, Y",strtotime("$comdate"));
  echo 'User: '.$comname.'<font color="#B20303"> - '.$comdate.'</font><br />';
  echo '&nbsp;&nbsp; - '.$comment.'<br /><br />';
  }
?>

so with this code, if someone commented a link like this

http://example.com

it will turn it this

<a href="http://example.com" target="_new">http://example.com</a>

but now if someone knew some basic HTML coding, and they used this

<a href="http://example.com">Example.com</a>

it will look like this...

<a href=<a href="http://example.com" target="_new">http://example.com</a>>Example.com</a>

$titleurl = preg_replace('/[^a-zA-Z0-9_ -%]/', '-', $d);
$titleurl = preg_replace('/[ ]/', '-', $titleurl);


How do you add to this to replace

---- with -
--- with -
-- with -

and remove quotes?

How do you remove a - if it's at the very end of $titleurl. For example, replace My-iPhone- with My-iPhone

im not sure how to do this: my code used the deprecated ereg_replace like this:
$name = ereg_replace(" ", "", $name);

i replaced it with this:
$name = preg_replace(" ", "", $name);   //this is line 65

but know get a warning:
Warning: preg_replace(): Empty regular expression on line 65

what am i doing wrong please?
thank you