PHP - Question On Preg

so I use file_get_contents to get the contents of a webpage, one of the lines has


Code: [Select]
<meta property="og:url" content="http://www.google.com/blahblahblah?s=5cd04d4a7632296b9cdb463d04e82c05" />
I want it to echo only http://www.google.com/blahblahblah so anything between <meta property="og:url" content=" and ?s=5cd04d4a7632296b9cdb463d04e82c05" /> I want to extract and put into a variable

this works just fine but I was thinking preg match would be better


$thread = explode('<meta property="og:url" content="', $psuc);
$thread = explode('?s=', $thread[1]);
echo $thread[0];


Thanks

This topic has been moved to PHP Regex.

http://www.phpfreaks.com/forums/index.php?topic=310802.0

Hello,
I am trying to crawl a website and get all the domain names listed on the site to output into my php script. 
I am using the following code.... 
The main area is the preg match area, since I know nothing about it, nor do I understand it a little bit!

$ch = curl_init();
curl_setopt($ch, CURLOPT_URL,"http://link I am getting data from.com);
curl_setopt($ch, CURLOPT_TIMEOUT, 30); //timeout after 30 seconds
curl_setopt($ch, CURLOPT_RETURNTRANSFER,1);
$result=curl_exec ($ch);
curl_close ($ch);
// Search The Results From The Starting Site
if( $result )
{
// LOOKING FOR ANYTHING.COM  all .com's
preg_match_all( "(.*)\.com", $result, $output, PREG_SET_ORDER );
 
foreach( $output as $item )

{
// ALL LINKS DISPLAY HERE 
print_r($item);



}

}


Any help would be greatly appreciated!

im having trouble using this function. im trying to change the strings within a post.

eg:

Code: [Select]
This is an example post
[attachment=file.png]

what im trying to do is change [attachment=file.png] to file.png.

Here is the code i have but it doesnt change anything.


$p_content = str_replace('<br>', '', $post_info[$key]['p_content']);
        $attach = preg_split('|\[attachment=|', $p_content);
        
        for($i=0; $i<count($attach); $i++)
        {
            $attach[$i] = str_replace(']', '', $attach[$i]);
            if(file_exists($config['asf_root'].'attachments/'.$attach[$i]))
            {
                $p_content = preg_replace('|\[attachment=([0-9a-zA-Z\.-_])\]|#i', $attach[$i], $p_content);
            }
        }
        echo $p_content;


it first gets all the attachment tags within the post then applies the preg replace to all of them. But the preg replace isnt replacing, so i must have gone wrong somewhere.
Any tips/ideas?

Thanks

I've never really made my own bbcode parser function before, but I'm going off of different tutorials to help me create my own style of parsing.  I've actually never really used preg_replace much, either.  My code is returning an odd error and I have no idea how to fix it.  I'm using codeigniter and the error it returns is below:

Quote

preg_replace() [function.preg-replace]: Compilation failed: nothing to repeat at offset 6


This is the code for my function:
Code: [Select]
function bbParse($string){

$codes = array(
'/\[b\](*?)\[\/b\]/' => '<b>\\1</b>', //bold tags
'/\[h2\](*?)\[/h2\]/' => '<h2>\\1</h2>', //h2 tags
'/\[h3\](*?)[\/h3\]/' => '<h3>\\1</h3>', //h3 tags
'/\[quote\](*?)\[\/quote\]/' => '<blockquote>\\1</blockquote>', //quote tags using the template's blockquote tag
'/\[img\](*?)\[/img\]/' => '<img src=\'\\1\' alt=\'Image Not Available\'>', //image tags
'/\[url\=(*?)\](*?)\[/url\]/' => '<a href=\'\\1\' title=\'\\2\'>\\2</a>', //anchor tags
'/\[p\](*?)\[/p\]/' => '<p>\\1</p>' //paragraph tags
);



$string = preg_replace(array_keys($codes), array_values($codes), $string);

return $string;


}

Code: [Select]
$text = preg_replace('{-(\d+)}e', '-convertNumber("$1")', $text);
i have strings im trying to replace like this:

name-2 > name-two
name-p2 > name-p2

im trying to match and replace the first one and basically ignore the second one. ive included the hyphen in the code. so why isnt this working?

I am very confused....
In my database I have lots of comments, but when displayed on the page, a few catch my eye...

Here is one, it displays wrong
Quote

1. addslashes() is not sufficient enough to prevent SQL injection. Use mysql_real_escape_string().

2. You are not enclosing your values in quotes, this just means they need to have a space in their submission to inject SQL.

3. You should not ever echo out mysql_error() to an end user. Log it for your own purposes, but show the user a generic error message.

Your query would be better off like this:

<?php   
   $sql = mysql_query("SELECT * FROM users_table
   WHERE username='".mysql_real_escape_string($_POST['username'])."' AND
   password='".mysql_real_escape_string($_POST['password'])."' LIMIT 1")or die('Sorry, there has been a database error. The webmaster has been notified of the error. Please try again later.');
?>


but this one displays correctly:
Quote

(That was me, the latest Anonymous poster)

One *last* thing. You're saving the passwords as plain text. BAD idea, especially with the SQL injection problems you have. Someone with the right knowledge can easily steal all your user's passwords.

I'd recommend using md5() to has the passwords (at very least md5, though sha1 would be nicer).

Try this:
<?php
$sql = mysql_query("SELECT * FROM users_table
WHERE username='".mysql_real_escape_string($_POST['username'])."' AND
password=md5('".mysql_real_escape_string($_POST['password'])."') LIMIT 1")or die('Sorry, there has been a database error. The webmaster has been notified of the error. Please try again later.');
?>


And make sure you md5() the passwords when you insert them into the database initially.


Do you see where the php tags are? when my script see it, it formats the php but some format not only the php, but the text as well, and I am not sure why.
if you take a look at this page http://beta.phpsnips.com/snippet.php?id=4 and scroll down to the date: 08/20/2008

The first comment displays nice
The second displays okay, "Would be better off as: " is formated as php and shouldn't be
The third one formats the entire post as php

Here is my php to check each comment (it is in a while loop):
$comment = preg_split("/^(<\?php.*?[^\'\"]\?>[^\'\"])/ms", $cow['comment'], -1, PREG_SPLIT_DELIM_CAPTURE | PREG_SPLIT_NO_EMPTY);
foreach($comment as $line){
preg_match('/<\?php.*?\?>/s', $line, $matches);
if($matches[0]){
echo '<div class="phpComment">';
highlight_string($line);
echo '</div>';
}else{
echo nl2br(htmlentities(str_replace('<br />','',$line)));
}
}

Anyone see what is wrong, and why it is formating funky?

This topic has been moved to PHP Regex.

http://www.phpfreaks.com/forums/index.php?topic=354568.0

Hi all

I am trying to do an email validation check. Here's my code:

if (!preg_match($email) == "^[a-z0-9]+([-_\.]?[a-z0-9])+@[a-z0-9]+([-_\.]?[a-z0-9])+\.[a-z]")
{
include("checkout-email-error.php");
exit;
}


It doesn't seem to allow any email addresses through? All help greatly appreciated!

Thanks
Pete

Hi, I am having a pretty difficult time getting files to upload to my server that have a Single Quote in the file name.
Example:

myfile's.pdf

I need to strip the file name of the quote before it uploads to the server.
I currently am using SWFUpload and this is the bit of code that was included with it.

I need to modify it to remove the single quotes as well. Been hammering my head over this all day.


$file_name = preg_replace('/[^'.$valid_chars_regex.']|\.+$/i', "", basename($_FILES[$upload_name]['name']));
if (strlen($file_name) == 0 || strlen($file_name) > $MAX_FILENAME_LENGTH) {
HandleError("Invalid file name");
exit(0);
}


thanks

This topic has been moved to PHP Regex.

http://www.phpfreaks.com/forums/index.php?topic=351288.0

i keep getting this at top of page
Warning: preg_replace() [function.preg-replace]: No ending delimiter '`' found in C:\xampp\htdocs\socialtscripts\activation.php on line 16
here is the code that it is reffering to
Code: [Select]
preg_replace("`", "", $id);

Code: [Select]
line 129- function filterBadWords($str)
 {
    $result = mysql_query("SELECT badwords FROM clean") or die(mysql_error());
    $replacements = "*";
   
    while($row = mysql_fetch_assoc($result))
    {     
          $bad_words= $row['badwords'];
          $spaced_bad_words = preg_replace("/(.)/i", "\${1} ", $bad_words);
          $spaced_bad_words = trim($spaced_bad_words);
          $str = preg_replace("/$bad_words | $spaced_bad_words/i", str_repeat('*', strlen($bad_words)), $str);
    }
   
    return $str;
Line 143 - }
I go this error "Warning: preg_replace() [function.preg-replace]: Compilation failed: unmatched parentheses at offset 1 in C:\xampp\htdocs\login\chatlog3.php on line 139"

Hello, I am trying to replace a url and add a sub-id to it, however I'm not quite there. Any help is always appreciated here. In the end, I would like the value of gotoUrl to have the cpId 123abc45 attached to it. I.E.

http://example.com/?Aff=56732&SID=123abc45
http://example.com/?Aff=56732&uv=123abc45&product=1834234
http://example.com/?Aff=56732&cid=123abc45&ace=2gs244s3

$gotoUrl = "http://example.com/?Aff=56732&SID=";
// OR could be listed as such:
// $gotoUrl = "http://example.com/?Aff=56732&uv=default&product=1834234";
// $gotoUrl = "http://example.com/?Aff=56732&cid=&ace=2gs244s3";

// Will attach this to replace value
$cpId = "123abc45";
// Possible sid replacements, depending on the url
$sidList = array("sid","SID","cid","uv");

	if ($gotoUrl){
		foreach($sidList as $sidVar){
			if (preg_match("/$sidVar/i", $gotoUrl)){
			$gotoUrl = preg_replace("#{$sidVar}(?=.*\d)(?=.*[a-z])(?=.*[A-Z])$#", "{$sidVar}={$cpId}", $gotoUrl);
			}
		}
        echo $gotoUrl;
        }

Edited by iwpg, 13 August 2014 - 10:36 PM.