PHP - Links, Current Page
Why this code dont work :S
<?php echo ' <ul> <li'; if ($_SERVER['PHP_SELF'] == "kategorije.php") { echo ' id="current"'; } echo '><a href="kategorije.php"><span>Kategorije</span></a></li> </ul>'; ?> Checking if PHP_SELF is "kategorije.php" do not work, why, and what is solution ? Similar TutorialsQuesion: Show each movie in the database on its own page, and give the user links in a "page 1, Page 2, Page 3" - type navigation system. Hint: Use LIMIT to control which movie is on which page. I have provided 3 files: 1st: configure DB, 2nd: insert data, 3rd: my code for the question. I would appreciate the help. I am a noob by the way. First set up everything for DB: <?php //connect to MySQL $db = mysql_connect('localhost', 'root', '000') or die ('Unable to connect. Check your connection parameters.'); //create the main database if it doesn't already exist $query = 'CREATE DATABASE IF NOT EXISTS moviesite'; mysql_query($query, $db) or die(mysql_error($db)); //make sure our recently created database is the active one mysql_select_db('moviesite', $db) or die(mysql_error($db)); //create the movie table $query = 'CREATE TABLE movie ( movie_id INTEGER UNSIGNED NOT NULL AUTO_INCREMENT, movie_name VARCHAR(255) NOT NULL, movie_type TINYINT NOT NULL DEFAULT 0, movie_year SMALLINT UNSIGNED NOT NULL DEFAULT 0, movie_leadactor INTEGER UNSIGNED NOT NULL DEFAULT 0, movie_director INTEGER UNSIGNED NOT NULL DEFAULT 0, PRIMARY KEY (movie_id), KEY movie_type (movie_type, movie_year) ) ENGINE=MyISAM'; mysql_query($query, $db) or die (mysql_error($db)); //create the movietype table $query = 'CREATE TABLE movietype ( movietype_id TINYINT UNSIGNED NOT NULL AUTO_INCREMENT, movietype_label VARCHAR(100) NOT NULL, PRIMARY KEY (movietype_id) ) ENGINE=MyISAM'; mysql_query($query, $db) or die(mysql_error($db)); //create the people table $query = 'CREATE TABLE people ( people_id INTEGER UNSIGNED NOT NULL AUTO_INCREMENT, people_fullname VARCHAR(255) NOT NULL, people_isactor TINYINT(1) UNSIGNED NOT NULL DEFAULT 0, people_isdirector TINYINT(1) UNSIGNED NOT NULL DEFAULT 0, PRIMARY KEY (people_id) ) ENGINE=MyISAM'; mysql_query($query, $db) or die(mysql_error($db)); echo 'Movie database successfully created!'; ?> ******************************************************************** *********************************************************************** second file to load info into DB: <?php // connect to MySQL $db = mysql_connect('localhost', 'root', '000') or die ('Unable to connect. Check your connection parameters.'); //make sure you're using the correct database mysql_select_db('moviesite', $db) or die(mysql_error($db)); // insert data into the movie table $query = 'INSERT INTO movie (movie_id, movie_name, movie_type, movie_year, movie_leadactor, movie_director) VALUES (1, "Bruce Almighty", 5, 2003, 1, 2), (2, "Office Space", 5, 1999, 5, 6), (3, "Grand Canyon", 2, 1991, 4, 3)'; mysql_query($query, $db) or die(mysql_error($db)); // insert data into the movietype table $query = 'INSERT INTO movietype (movietype_id, movietype_label) VALUES (1,"Sci Fi"), (2, "Drama"), (3, "Adventure"), (4, "War"), (5, "Comedy"), (6, "Horror"), (7, "Action"), (8, "Kids")'; mysql_query($query, $db) or die(mysql_error($db)); // insert data into the people table $query = 'INSERT INTO people (people_id, people_fullname, people_isactor, people_isdirector) VALUES (1, "Jim Carrey", 1, 0), (2, "Tom Shadyac", 0, 1), (3, "Lawrence Kasdan", 0, 1), (4, "Kevin Kline", 1, 0), (5, "Ron Livingston", 1, 0), (6, "Mike Judge", 0, 1)'; mysql_query($query, $db) or die(mysql_error($db)); echo 'Data inserted successfully!'; ?> ************************************************************** **************************************************************** MY CODE FOR THE QUESTION: <?php $db = mysql_connect('localhost', 'root', '000') or die ('Unable to connect. Check your connection parameters.'); mysql_select_db('moviesite', $db) or die(mysql_error($db)); //get our starting point for the query from the URL if (isset($_GET['offset'])) { $offset = $_GET['offset']; } else { $offset = 0; } //get the movie $query = 'SELECT movie_name, movie_year FROM movie ORDER BY movie_name LIMIT ' . $offset . ' , 1'; $result = mysql_query($query, $db) or die(mysql_error($db)); $row = mysql_fetch_assoc($result); ?> <html> <head> <title><?php echo $row['movie_name']; ?></title> </head> <body> <table border = "1"> <tr> <th>Movie Name</th> <th>Year</th> </tr><tr> <td><?php echo $row['movie_name']; ?></td> <td><?php echo $row['movie_year']; ?></td> </tr> </table> <p> <a href="page.php?offset=0">Page 1</a>, <a href="page.php?offset=1">Page 2</a>, <a href="page.php?offset=2">Page 3</a> </p> </body> </html> is this possibe with php? Hi, This may be something for JavaScript but I would like to know if and how it's possible to show who is currently active/viewing the page. Users are logged into the system with their own account. The purpose of this is for a CRM where more than one person may be editing the same record, so undesired overwrites might occur which is what I'd like to avoid with this "other user editing this record" notification. Hi guys, I'll try to explain this. I'm doing a quoting system for a building contractor and I have a dynamic purchase order created for every quote that's confirmed and it spits out all the materials they will need for each supplier. The layout of the page is exactly what I need emailed to the supplier so they can ship out the materials listed, it's your basic purchase order. I'm going to put a button on the page that sends the email to the supplier but I need to attach the purchase order displayed on the page. Preferably in PDF but it just needs to be an attached file. I know I can have the user use PRINT.... to save it as PDF and then use Outlook to email it but I'd like to automate it. Thanks. I am trying to create a script that alters the navigation div depending on the page the user is on. How do I get the current page using PHP? Hi all, I want to get the current page name as displayed in the URL, not neccesarily the name of the PHP script that is running. E.g. I have a PHP file 'home.php' that contains iframes that contain other PHP files such as 'frame1.php'. What I want is a script that can be run from frame1.php but that will return 'home.php' as the current page (as displayed in the URL in the browser). How do I do this? Thanks! I have an html table that is being populated with links from a specific directory.. I would like the user to be able to click the link and if its a file they will download the file. If its a directory, I woudl like to reload the current page but this time show the contents of the directory. My main issue is that I have a session variable called 'workingdirectory' that I need to update before I reload the page. I have tried setting it and then calling Location('page.php') but I get the 'cannot change header information' error. I realized I was getting this because I had begun to call HTML code before the PHP was finished. Is there a way to just simply update the session variable, and then make the page reload when the user clicks on a link? I have a few PHP files. Currently, if the URL contains page=var, index includes var.php, otherwise it includes home.php. Apparently, this method makes the site easy to hack through Remote File Inclusion. Also, using PHP5 breaks this method entirely, as no matter what you set page to in the URL, it includes home.php. What's the best way to do this without using the URL? Give example code if possible. I've used PHP for a while but haven't really gotten past the beginner level. I'd really appreciate any help. Thanks. Hello, I'm having trouble figured out how to do this... Basically I want update.php to run after the user hits the 'update' button, and after update.php runs (which will take about 60 seconds) I want the index.php to reload. How can this be done? thanks! <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Strict//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-strict.dtd"> <html xmlns="http://www.w3.org/1999/xhtml" xml:lang="en" lang="en"> <head> <title>Server List</title> </head> <body> <?php $mlink = @mysql_connect("localhost","user","pass"); mysql_select_db("dbname", $mlink); $result = mysql_query("SELECT * FROM ServerList"); while($row = mysql_fetch_array($result)){ echo $row['HostName']. " - ". $row['UsedSlots']. " / ". $row['MaxSlots']; echo "<br />"; } ?> <br/> <br/> <form action="update.php" method="post"> <button type="submit">update</button> </form> </center> </body> </html> I'm doing a cURL post to a server and it returns "true No_Error Data was accepted 10356546 3770 false 0 " Form --> Method=Post --> submit.php (this is the page that's doing the cURL post and the server returns data that appears on this page). How do I take this and put it into a string? Hello, I got this basic code from a website and it is supposed to highlight the current page on the menu, which it does very well. The problem is that I cannot stylize the font, color or size of the type in the current page menu display. No matter what I do, it always stays as the default font. The other buttons on the menu can be stylized but not the current page. Is there a way to do this? Code: [Select] ## SNIPPET 1 - THE PHP ## // To be saved in the 'includes' directory as "nav_include.php" <?php $menu=file_get_contents("includes/menu.html"); // get the navigation list of pages $base=basename($_SERVER['PHP_SELF']); // get the current page $menu=preg_replace("|<li><a href=\"".$base."\">(.*)</a></li>|U", "<li id=\"current\">$1</li>", $menu); // add an id of 'active' to the link and id of class to the list item for the current page echo $menu; // echo the HTML list with the current page highlighted ?> ## SNIPPET 2 - THE HTML LIST ## To be saved as menu.html <ul id="navlist"> <li><a href="index.php">Home</a></li> <li><a href="products.php">Products</a></li> <li><a href="services.php">Services</a></li> <li><a href="about.php">About Us</a></li> <li><a href="contact.php">Contact Us</a></li> </ul> ## CSS ## for the *.css file #navlist { margin: 0; padding: 30px 0 20px 10px; float: right; width: 60%; } #navlist ul, #navlist li { margin: 0; padding: 0; display: inline; list-style-type: none; } #navlist a:link, #navlist a:visited { float: left; line-height: 14px; font-weight: bold; margin: 0 10px 4px; text-decoration: none; color: #4F4F4F; width: auto; } /* link and visited link styles - the visited state can be styled separately if you wish */ #navlist a:link#current, #navlist a:visited#current, #navlist a:hover { border-bottom: 4px solid #66733f; padding-bottom: 2px; background: transparent; color: #4F4F4F; } /* this line's the style for the current page link */ #navlist a:hover { border-bottom: 4px solid #4F4F4F; color: #4F4F4F; } /* hover state for all the links */ ## TO DISPLAY ON THE PAGE ## <?php include("includes/nav_include.php"); ?> I'm feeling a little overwhelmed/burned-out/confused... I have a page "article_index.php" that contains a summary of each article plus a link to it, e.g. Code: [Select] <a href="<?php echo WEB_ROOT; ?>articles/postage-meters-save-you-money"> When you click on a link, it goes to "article.php" and uses a mod_rewrite to transform the "pretty URL" to regular URL that "article.php" can use to query the correct article from my database. ----- Here is what I need help with... When a user is on a given article page, I want to sto - ReturnToPath - ArticleID in the SESSION. I am drawing a blank on how to get the "ArticleID" when a user is on a give page?! Hope you guys follow me?! Debbie Hi Everyone, I have this small bit of PHP that when you are on a certain page it will add a class called selected Code: [Select] <?php $currentPage = basename($_SERVER['SCRIPT_NAME']); ?> <ul id="subnav"> <li><a href="gallery.php?category=Wedding" id="wedding" <?php if ($currentPage == 'gallery.php?category=Wedding') {echo 'class="selected"';} ?>>Wedding Hair</a></li> <li><a href="gallery.php?category=Men" id="mens-styles" <?php if ($currentPage == 'gallery.php?category=Men') {echo 'class="selected"';} ?>>Mens Styles</a></li> <li><a href="gallery.php?category=Women" id="womens-styles" <?php if ($currentPage == 'gallery.php?category=Women') {echo 'class="selected"';} ?>>Women's Styles</a></li> <li><a href="gallery.php?category=Salon" id="salon" <?php if ($currentPage == 'gallery.php?category=Salon') {echo 'class="selected"';} ?>>Salon</a></li> </ul> This is not working I think it's because of the file extenstion 'gallery.php?category=Wedding' is there any way I can get this to work with these extensions Any help would be greatly appreciated Thanks Barry Is there a function to check the name of the current page? Such as login.php or something like that? If not, does anyone have a custom function already created? I've looked at loads of other scripts that highlight the page but none of them work on mine . Here's part of my code: $i =1; for ($x=0;$x<$foundnum;$x=$x+$e) { echo " <a href='search.php?search=$search&s=$x'>$i</a> "; $i++; Hi everyone, I have this script that identify's the current page in the navigation Code: [Select] <?php $currentPage = basename($_SERVER['SCRIPT_NAME']); ?> <ul id="nav"><!-- Open Nav --> <li><a href="index2.php" <?php if ($currentPage == 'index2.php') {echo 'class="selected"';} ?>>Home</a></li> <li><a href="salon-information.php" <?php if ($currentPage == 'salon-information.php') {echo 'class="selected"';} ?>>Salon Information</a></li> <li><a href="about-us.php" <?php if ($currentPage == 'about-us.php') {echo 'class="selected"';} ?>>About us</a></li> <li><a href="hair-care-advice.php" <?php if ($currentPage == 'hair-care-advice.php') {echo 'class="selected"';} ?>>Hair Care Advice</a></li> </ul><!-- Close Nav --> My problem is that hair-care-advice.php has a number of sub pages. How do I get it so the selected class remains selected for all the sub pages as well as the main page. Any help would be greatly appreciated Thank you Barry i get this error Warning: current() [function.current]: Passed variable is not an array or object.. for this Code: [Select] $lastblock = current( ${"s".$row} ); print_r($lastblock); when i change to this it works.. Code: [Select] $lastblock = current( $s0 ); print_r($lastblock); The problem is i won't know the $row seeing as it is in a while loop. Solution? hi, i actually got some code working to add an ID dynamically to a website i'm working on (it was a momentous occasion ). here's the code: in the functions.php file: $url = 'tanzaniatravel.za.com'; $page = $_SERVER['PHP_SELF']; $page = str_replace("/","",$page); $page = str_replace(".php","",$page); $page = str_replace("$url", "", "$page"); i call the functions.php file into the index.php file, and add this as the opening body tag: Code: [Select] <body id="<?php echo $page; ?>"> this dynamically adds an ID named after whatever the actual page is named. now, i make use of the following top navigation structu Code: [Select] <ul class="nav-top"> <li <?php echo ($page == '' ? 'class="nav-top-current"' : ''); ?>><a class="nav-top-lineheight" href="index.php" title="Tanzania Travel home">Home</a></li> <li <?php echo ($page == '' ? 'class="nav-top-current"' : ''); ?>><a class="nav-top-lineheight" href="about.php" title="Why use TanzaniaTravel.Za.Com">Why us</a></li> <li <?php echo ($page == '' ? 'class="nav-top-current"' : ''); ?>><a href="" title="">Overview and area map</a></li> <li <?php echo ($page == '' ? 'class="nav-top-current"' : ''); ?>><a href="" title="">Tanzania National Park</a></li> <li <?php echo ($page == '' ? 'class="nav-top-current"' : ''); ?>><a href="" title="">Tanzania Safari Lodges</a></li> <li <?php echo ($page == '' ? 'class="nav-top-current"' : ''); ?>><a href="" title="">Tanzania Tour Itineraries</a></li> <li <?php echo ($page == '' ? 'class="nav-top-current"' : ''); ?>><a href="" title="">Safari Dates & Prices</a></li> <li <?php echo ($page == '' ? 'class="nav-top-current"' : ''); ?>><a href="" title="">Zanzibar Kilimanjaro</a></li> <li class="<?php echo ($page == '' ? 'nav-top-current' : ''); ?> nav-top-last-li"><a class="nav-top-lineheight" href="" title="">Contact Us</a></li> </ul> you'll see that i've left the $page variable empty. i want that variable to call in the current page's ID, so that only the current page's <li> is active. this, of course, will greatly assist with developing the CSS for the navigation. i appreciate your help very much. thank you. Hi, I'm wanting to find rows whose date is within the next week of the current month of the current year. The format of the date is, for example: 2010-10-28 Any ideas guys? Thanks lots! Hello - I've come to an issue with something I'm working on and have searched around with no luck. When editing user accounts I want it to not be able to change the e-mail address into existing ones on other rows, but when submitting the form it takes into account that this particular rows email address is the same as the one which was sent via $_POST and throws up the error. The desired behaviour I want is for it to ignore the ID of the row which was posted, but take into account every other row. Here's the code as it stands at the moment: $email = $_POST['email']; $checkemail = mysql_query("SELECT email FROM users WHERE email='$email'"); } if (mysql_num_rows($checkemail) > 0) { return $this->error("The e-mail address you provided is already associated with an account."); } |