PHP - Get Index Of Foreach Xml
hi very good
I'm trying to get the indices of the gallery that I have a xml file to display it in a <select> xml file is as follows .. I'm trying to use "foreach" but what brings me, is twice galleria, but that's fine, what happens is that it brings are the names, but I want indices, 0 and 1 xml file <?xml version="1.0"?> <content> <gallery Name="Hostal" Folder="Gallery/hostal"> <image Thumb="thumb0.jpg" Large="0.jpg" Caption="Hostal Regina" Colour="181f0a"> <comentarios><![CDATA[<p>Hostal Regina comentarios</p>]]></comentarios> </image> <image Thumb="thumb1.jpg" Large="1.jpg" Caption="Hostal Regina" Colour="181f0a"> <comentarios><![CDATA[<p>Hostal Regina</p>]]></comentarios> </image> </gallery> <gallery Name="Vistas" Folder="Gallery/nerja"> <image Thumb="thumb0.jpg" Large="0.jpg" Caption="Vista Nocturna" Colour="eeeeeee"> <comentarios><![CDATA[<p>Vista Nocturna realizada por Diego Palomo</p>]]></comentarios> </image> <image Caption="eeeeeee"><comentarios>http://php-design-patterns.com</comentarios></image> </gallery> </content> file select form <select name="action"> <option value="">Escoger de la Lista</option> <?php $source = 'content.xml'; // load as string $xmlstr = file_get_contents($source); $sitemap = new SimpleXMLElement($xmlstr); // load as file $sitemap = new SimpleXMLElement($source,null,true); foreach($sitemap->gallery as $index=>$content) { $atributo = $content->attributes(); echo "<option value='".$index."'>".$index. "</option>";///in value no show index } ?> </select> Similar TutorialsHow do I skip to the next index in a foreach loop? I've tried the following: Code: [Select] foreach($c as $val){ if(1==1){ next; } echo "HI" } In the code above it still echos HI How do I fix this? This topic has been moved to Application Frameworks. http://www.phpfreaks.com/forums/index.php?topic=355772.0 I really dont no what the problem is and im new here so i dont no if this is the right place to put this but im trying to make a registration page for my server and when i bring it up it says Undefined index: action in C:\xampp\htdocs\index.php on line 56 and idk what to do >.< this is the line that has the problem if($_POST['action']!="signup") so hopefully u guys could help me :/ Im using xampp btw Hi there, I was wondering if there is a way to display content on only my index.php page? I believe there is a way and I have done it before, but some of my pages use index.php?category etc. Is there a way to show content just on index.php and not on any dynamic pages? Thanks I'm not sure if the title explains it very well, but here is an image of it. I am trying to figure out how to access the option selected (equal, not equal, etc.), along with its input box, for each column (the checkboxes on the right) selected. The purpose of this is to allow a non-programming administrator user to create a custom query to access information. I can find out which checkboxes are selected no problem, but finding the accompanying drop-down option and input box is difficult for me. How do I do this? If you have a suggestion on how to change it, I'm very open. Thank you in advance! Code: [Select] if(!isset($_POST['submit'])) { echo " <form method='post'> <table> <tr> <td valign='top'>SELECT</td> <td valign='top'> <table>"; // LIST ALL COLUMNS IN A TABLE $result = mysql_query("SELECT * FROM table_name") or die(mysql_error()); $rowcount=mysql_num_rows($result); $y=mysql_num_fields($result); for ($x=0; $x<$y; $x++) { echo " <tr> <td> <input type='checkbox' name='fields[]' value='".mysql_field_name($result, $x)."'>".mysql_field_name($result, $x)." </td> </tr>"; } echo " </table> </td> <td valign='top'>FROM allocations</td> <td valign='top'>WHERE</td> <td> <table>"; // LIST ALL COLUMNS IN A TABLE $result = mysql_query("SELECT * FROM table_name") or die(mysql_error()); $rowcount=mysql_num_rows($result); $y=mysql_num_fields($result); for ($x=0; $x<$y; $x++) { echo " <tr> <td> <input type='checkbox' name='column[]' value='".mysql_field_name($result, $x)."'>".mysql_field_name($result, $x)." </td> <td> <select name='operator[]'> <option value='='>equals</option> <option value='<>'>does not equal</option> <option value='>'>greater than</option> <option value='<'>less than</option> <option value='>='>greater than or equal to</option> <option value='<='>less than or equal to</option> <option value='LIKE'>is like</option> </select> </td> <td><input type='text' name='criteria[]'></td> </tr>"; } echo " </table> </td> <td valign='top'><input type='submit' value='Process Query' name='submit' class='submit'></td> </tr> </table> </form>"; } else { echo "<b>Fields to edit:</b> "; foreach ($_POST['fields'] as $fields) { echo $fields,", "; } echo "<br><br>"; echo "<b>Columns to query:</b> "; foreach ($_POST['column'] as $columns) { echo $columns," HERE IS THE SPOT, "; } } In the code I want to proceed to the next step only after stripslashes and strip_tags are completed. How do I put the code below with if? $stripped = array('name', 'location', 'bio'); foreach ( $_POST as $k => $v ) { if ( in_array($k, $stripped) ) { ${$k} = strip_tags($v); } } foreach ( $_POST as $p => $q ) { if ( in_array($p, $stripped) ) { ${$p} = stripslashes($q); } } Thanks, Ruth. Hi! When I echo $m below, it will show all selected options fine. Instead, I want it to show many I selected. So if I selected 3 in dropdown, I want it to say I selected 3 instead of showing their values. $allmaps=$_POST['maps']; foreach ($allmaps as $m) { echo 'm = '.$m.''; } <select name="maps[]" multiple>'.$maps.'</select> I appear to be having a simple simon day! my foreach is only displaying the last result in the table as opposed to each row $num_rows = mysql_num_rows($query); echo "There are $num_rows records.<br>"; while($row = mysql_fetch_row($query)) foreach ($row as $field) { echo '<div class="results">'; echo $field; echo '<br></div>'; } And the source Code: [Select] <link href="../styles/clientbox.css" rel="stylesheet" type="text/css"> <body><br> <h3>My Services</h3> <div class="text"> You currently have the following services with us: </div> There are 2 records.<br><div class="results">test1<br></div> </body> </html> My table has 2 rows which the 1st one has a package of test and the second a package of test1 Can anyone help? Thanks Hi i am trying to pass values from a cart to a database using foreach. This is my code: Code: [Select] $columns = array('order_id', 'order_item_id', 'order_product_name', 'order_product_dimensions', 'order_product_options', 'order_product_quantity', 'order_product_price', 'order_product_subtotal', 'order_product_vat', 'order_product_delivery','order_product_total','order_product_sku','order_product_image_name','order_product_image_type','order_product_image_path','order_product_image_size','order_product_artwork_link','order_product_artwork_name','order_product_artwork_type','order_product_artwork_path','order_product_artwork_size','order_firstname','order_lastname','order_companyname','order_email','order_tel','order_billing_address','order_billing_address2','order_billing_town','order_billing_county','order_billing_postcode','order_shipping_address','order_shipping_address2','order_shipping_town','order_shipping_county','order_shipping_postcode','order_status','order_username'); $data = array_fill_keys($columns, 'NULL'); foreach($data as $key => $value) { $data[$key] = empty($_POST[$key]) ? 'NULL' : "'".mysql_escape_string($_POST[$key])."'"; $query = "INSERT INTO orders (id, order_created_at, ".implode(", ",$columns).") VALUES (null, NOW(), ".implode(",",$data).')'; } Problem is posting 2 or more products into the database. How do i split the values so it enters each product into the database? today i programmed my own weight calculator. one thing i am having a problem is with trying to make it so if a weight is over a certain number, then the shipping price will increase by X. shipping prices are charged in 20000 gram blocks, so if I have something that is 22000 grams then that will be two blocks. what i need to do is something like (this is a big guess) Quote $row3 = 50; $weighttotal = 22000; if ($weighttotal > 20000) { foreach (20000) { $row3 += $row3;} } } } can it be done on php?? Hi can any one help please im still very new but hard trying The problem is that i only get 1 result back from the database i need it to loop any ideas please Code: [Select] $query = mysql_query("SELECT * FROM categorys, sub_categorys WHERE categorys.cat_id = sub_categorys.cat_id"); echo "<ul>"; $row[] = mysql_fetch_array($query); foreach($row as $category){ echo "<li>"; echo $category['category']; foreach($row as $sub_category){ if($category['cat_id'] == $sub_category["cat_id"]){ echo "<ul><li>".$sub_category["sub_category"]."</li></ul>"; } } echo "</li>"; } echo "</ul>"; why does wordpress is using foreach rather than while in listing records? common Code: [Select] while ($products = mysql_fetch_object($rs) { ... } but wordpress is using foreach Code: [Select] foreach ($posts as $post) { ... } which is better? because i'm trying to create my own code for database connection. public function update($data, $table, $where) { foreach ($data as $column => $value) { $sql = "UPDATE $table SET $column = $value WHERE $where"; print "table: ".$table." column: ".$column." whe ".$where; mysql_query($sql) or die(mysql_error()); } return true; } $data: $data = array( "username" => "Jack", "email" => "jack.gmail@gmail.com" ); $db->update($data, "users", 'id=1'); Working on this code that updates a column from a class. Everything is fine except for one issue. As of right now $column is set to "Jack" which outputs an error, instead of what it should be as "username". I'm sure it's something really simple, so any assistance is appreciated. Any ideas? Problem area is listed in red. Noob question. I've learned so much in the last couple of weeks that I've actually found two ways of doing the same thing! I was wondering which was the better method, if there is any difference. They are being used to print somewhere between 10 and 200 lines of text. Either: $categories_count= (count($categories[1])) -1; for ($u=0; $u < $categories_count; $u++) {echo "<li>".$categories[1][$u]."</li>";} Or: foreach ($categories[1] as $line => $cat) {echo "<li>".$cat."</li>";}; I'm trying to figure out why its saying Warning: Invalid argument supplied for foreach() in /home/content/y/a/n/yankeefaninkc/html/defiant/efedmanager/forms/booking.php on line 17. I thought I did the foreach loop right so far. $eventid = $_GET['id']; $query = "SELECT CONCAT_WS(' ', eventnames.eventname, events.label) AS event, DATE_FORMAT(events.bookingdate, '%M %d, %Y') AS bookingdate, events.nummatches AS nummatches FROM events, eventnames WHERE events.event_id = eventnames.id AND events.id = '" . $eventid . "'"; $result = mysqli_query ( $dbc, $query ); // Run The Query foreach ($nummatches as $matchnum) { echo "Match # $matchnum"; echo "<select class=dropdown name=matchtype id=matchtype title=Match Type>"; echo "<option value=0>- Select -</option>"; $query = 'SELECT id, matchtypename FROM matchtypes'; $result = mysqli_query ( $dbc, $query ); // Run The Query while ( $row = mysqli_fetch_array ( $result, MYSQL_ASSOC ) ) { print "<option value=\"".$row['id']."\">".$row['matchtypename']."</option>\r"; } } i have a table that echos 10 entries what i want to do is once it echos 5 records it starts a new table. I dont know how to go about this. Could you guys guide me the right way. Hi guys, Having a bit of trouble getting this to work. I should say before I start that im a rookie at PHP. Basically this is the code I have {counter start=0 print=false name=competcount} {foreach item=compet from=$person.competition} <img src="./bargraph/bar.php?value={$person.lineup[$compet.id].titular}&max={$club.matchsplayed[$compet.id].nummatchs}&info" /> The problem lies with the $club array not being defined Code: [Select] $club.matchsplayed[$competition.id].nummatchs How do I set up multiple arrays with foreach? Am I even in the right ball park with this? I am trying to develop a calendar. I have code to determine the number of days for each month. I want to cycle through each day and spit out code for each day. Something like the following: Code: [Select] <?php $month = "December"; $days = 31; foreach($days){ echo "<div id='day_block'> ".$days." </div>"; } ?> i think i need to use a counter but don't know how, any help would be awesome! Hi All, I essentially am trying to figure out how to print out all of the zip codes that are associated with a search that I am doing, but not list the same zip code more than once. My current foreach statement is as follows and prints out the zip code for each property that is associated with the search: <ul> <?php foreach($properties as $property) { ?> <li><?=$property->$zipcode?></li> <?php } ?> </ul> How would I modify this to print out 1 occurrence of each zip code that is in the search, even if, for example 20 properties have the same zip code? Thanks in advance! P.S. - Tried using an array to work with it but pretty sure my logic was incorrect when putting it together and couldn't get past the errors. Anyways, thanks in advance for the help! i'm running code on what i only want to be the HOME page, but the current site it built using GET variables with index.php needless to say, the home page is accessed either as domain.com/ or domain.com/index.php - i'm hoping someone can show me how to check for this condition, that it is only index.php without anything further I'm only slightly familiar with $_SERVER['uri'], etc... So i don't know just what to ask. thanks for anyone's help. Glenn |