PHP - Finding Last Entry
My query is not finding the last recieptnum entry, it is finding the number 9 everytime for some odd reason. Im trying to incrementally increase this each time a reciept is created.
$getreceiptnum = mysql_query("SELECT receiptnum FROM accounting WHERE agency = '$agency' ORDER BY receiptnum DESC LIMIT 1") or die(mysql_error()); $recieptarray = mysql_fetch_array($getreceiptnum); $recieptnum = $recieptarray['receiptnum']; echo $recieptnum; Similar TutorialsHi I'm very much a newbie to PHP and am struggling with a registration and login problem. The registration part is fine - the password is emailed out fine, I check the database and the entry is there, the password is encrypted. but when the user tries to log in.... if (mysql_num_rows($result) == 0) .... it returns 0? and the access denied page is shown. I'm thinking it is something to do with the sql database encryption? I'm completely lost here and would appreciate some guidance Thanks in advance Jan Alright, wasn't quite sure how to summarize this in the title, but I want to: Check if a user status is "active" or not based on the UserName input. I have a table witch holds: Code: [Select] VarChar Username Var CharPassWord int Active Ted TedsPW 1 something like the above(assuming it formatted correctly. In my php script I will want to input a variable for Username to check for: inputUN in this example would be "Ted". $UserNameToCheck = $_GET['inputUN']; Then I want to check for that UserName in the database, if it exists, I want pull the value for the "Active" field for just that UserName and echo it. Thanks for any help. I am using php to upload a file to my server, and at the same time inserting the files name and url into my mysql database.
$sql = "UPDATE uploads SET name = '$name', url='$target_path'"; $statement = $dbh->prepare($sql); $statement->execute();This is working, however, when I upload a new file, rather than making a new entry in my database, it just overwrites the first one. I'm quite new at mysql so was wondering how I would make it add new entrys instead of overwriting the current one? Hi I have a file, that is copied from other files. All other files work perfectly. But, for some reason this one is throwing back an error. I've been over it so many time, but can't see whats wrong. Error: Fatal error: Call to undefined method stdClass::save() in /home/p/o/powtest/web/public_html/admin/lib/ajax_php/add_interests.php on line 28 add_interests.php Code: [Select] <?PHP require_once("../../../includes/initialize.php"); $flag = 0; $ID = $_POST['ID']; $type = $_POST['type']; $category = $_POST['category']; $interest = $_POST['interest']; $expInt = explode("\n", $interest); $DMOD = date('Y-m-d'); $TMOD = date('H:i:s'); $check_entry = Admin_interest::if_exists(clean_input_value($category)); if($check_entry == 0){ $new_category = Admin_interest::make($ID, clean_input_value($category), clean_input_value($type), $DMOD, $TMOD); if($new_category && $new_category->save()){ $CID = $new_category->id; $flag = 1; } } foreach($expInt as $expInts){ $check_entry = Admin_interests_sub::if_exists($CID, clean_input_value($expInts)); if($check_entry == 0){ $new_interest = Admin_interests_sub::make($ID, $CID, clean_input_value($expInts), $DMOD, $TMOD); if($new_interest && $new_interest->save()){ $message = 'Thank You: Your list Has Been Saved'; }else{ $message = "Sorry, There was an error"; } } } echo $message; ?> Class: Code: [Select] <?PHP require_once(LIB_PATH.DS.'database.php'); class Admin_interests_sub { protected static $table_name="admin_interests_sub"; protected static $db_fields = array('id', 'category_id', 'interest_sub', 'dateMod', 'timeMod'); public $id; public $category_id; public $interest_sub; public $dateMod; public $timeMod; public static function make($ID, $category_id, $interest_sub, $DMOD, $TMOD){ if(!empty($interest_sub)){ $interest = new Admin_interests_sub(); $interest->id = (int)$ID; $interest->category_id = (int)$category_id; $interest->interest_sub = $interest_sub; $kw->dateMod = $DMOD; $kw->timeMod = $TMOD; return $kw; }else{ return false; } } protected function attributes(){ $attributes = array(); foreach(self::$db_fields as $field){ if(property_exists($this, $field)){ $attributes[$field] = $this->$field; } } return $attributes; } protected function sanitized_attributes(){ global $database; $clean_attributes = array(); foreach($this->attributes() as $key => $value){ $clean_attributes[$key] = $database->escape_value($value); } return $clean_attributes; } public function save(){ return !empty($this->id) ? $this->update() : $this->create(); } public function create(){ global $database; $attributes = $this->sanitized_attributes(); $sql = "INSERT INTO ".self::$table_name." ("; $sql .= join(", ", array_keys($attributes)); $sql .= ") VALUES ('"; $sql .= join("', '", array_values($attributes)); $sql .= "')"; if($database->query($sql)){ $this->id = $database->insert_id(); return true; }else{ return false; } } public function update(){ global $database; $attributes = $this->sanitized_attributes(); $attribute_pairs = array(); foreach($attributes as $key => $value){ $attribute_pairs[] = "{$key}='{$value}'"; } $sql = "UPDATE ".self::$table_name." SET "; $sql .= join(", ", $attribute_pairs); $sql .= " WHERE id=".$database->escape_value($this->id); $database->query($sql); return ($database->affected_rows() == 1) ? true : false; } public function delete(){ global $database; $sql = "DELETE FROM ".self::$table_name." "; $sql .= "WHERE id=".$database->escape_value($this->id); $sql .= " LIMIT 1"; $database->query($sql); return ($database->affected_rows() == 1) ? true : false; } } ?> Any help finding this bug will be a big help. Thanks Okay I'm done with searching for answers, working on this preg_match for about 3 hours now.
I'm looking for "($0.01/$0.02 USD)" in a string. The needle might be slighty different. Possible strings that I might look for is: (€xx.xx/€xx.xx EUR) where the EUR can be changed into USD, including its signs. //calculate age $birthdate = "1978-04-26"; //birth date... actually being obtained from a database $today = date("Y-m-d H:i:s"); // The exact date $age = date_diff($str_birthday, $today); echo $age; I'd like a simple code to echo the age of someone with the mysql database information that's in their record. This doesn't work. I have no idea why. Nothing seems to work that I've found on the net. Please help. Thanks. Hello. I think I have a little unique and difficult to solve problem that I really need to post here. I, as a counter-strike portal administrator, am running some CS servers. With automatical script, the server uploads demos (videos of gameplay) on FTP in this format: 101229154428.dem and so on. The number is a date in this format: year, month, day, hours, minutes, seconds => for the example it's 29th December 2010, 15h, 44m and 28s. Then I have a "report" page. The important part on it is that, there is a date in unix timestamp in each row like 1336837680 (29th december 2010, 15h, 47m, 00s). And now what I need: Find a demo that corresponds to the unix timestamp. If there is a timestamp 1336837680, it should find 101229154428.dem. You know what I mean, there is not one demofile, there are plenty. Just find the demo, that contains a record of the time used in timestamp. Pretty difficult, isn't it? I would love to see if anybody came up with anything. Best regards! hi there all i need the code that adds the url to a page like in the new forums cheers.
you get a image of that website and the url of the page
can anyone help please
thank you
like if i type www,google.com <<< you get a image and link automaticly..
Edited by php-real-degree, 15 September 2014 - 05:07 PM. Hi , I'm new on this forum so don't judge too hard.. But I have a few questions. I am recently new to PHP as this is my first computer language I've learnt besides HTML. My first question is, what's the difference between !== and !=, and is it more secure to use !== when comparing two fields such as passwords? I've different things and this has confused me.. And my second question is, I have this piece of code Code: [Select] /* option error checking */ $field = "option"; // Use field name for option /* Check if the option picked is from the list of options to choose from*/ if($suboption !== "option1" || $suboption !== "option2" || $suboption !== "option3" || $suboption !== "option4" || $suboption !== "option5" || $suboption !== "option6" || $suboption !== "option7"){ $form->setError($field, "* Unexpected error with option"); } I'm guessing in the long run, this will slow down my script.. is there an easier way of checking without using || $suboption !== and is it okay if I've used !==? Like I said I'm new to this so please don't flame.. I've done some research but I can't seem to find some accurate answer. Thank you, ZT Howdy Colleagues,
I was wondering whether you know ways/websites/channels/magic owls to how to help find a job in USA as a programmer as in for relocating there while the company pays for the Visa and the travel expenses?
My land-lord's son found a job as a programmer in Texas and the company was generous and kind enough to pay his travelling expenses, as well for his wife and kid.
I have an account in Monster & Indeed and I send CVs very often, but no luck so far.
And I want to go there to work and live, not like some people to rely on welfare, I have worked my whole life.
Thank you!
BR,
Stefany
What I want to be able to do is this: If I have a list of values in my database: 1 13 26 15 12 4 I do a query of this database and sort it asc so it looks like this: 1 4 12 13 15 26 I want to know how I can use php and/or sql query to find these values based off of "position" in the list. If I wanted the 3rd value in the list, that value would be 12. If i wanted the 2nd value in the list it would be 4. How would I go about doing this? Thank you in advance. I am trying to find the URL to a directory TWO levels above the script level (if you know what I mean). For example.. the script sits at Code: [Select] http://www.domain.com/TestArea2/members/index.php BUT I need to find the path to Code: [Select] http://www.domain.com/TestArea2/ the nearest I get is... $domain = $_SERVER['HTTP_HOST']; $domain .= $_SERVER['REQUEST_URI']; echo $domain; // outputs www.domain.com/TestArea2/members/index.php Is there a simple method to do this or have I got to split the string and work backwards? Many thanks User submits 1 or more refrerences via a form. On the action page I want to check if any id's on the page match any values submitted in $_POST. Code: [Select] $Ref = $_POST['Ref']; $source = file_get_contents( 'E:/wamp/www/Project/File.php' ); $document = new DOMDocument; $document->validateOnParse = true; $document->LoadHTML($source); for($i=0; $i<count($Ref); $i++) { $ID = $document->getElementById('$Ref[$i]'); } I have a table on the source page with the same id as a reference contained in $Ref, but getElementById is not seeing/recognsing it. No idea why not. Im trying to find the time between the last database entry and the current time and then echo it so it says something like '2 minutes ago'. I tried doing: $last_post_gap = strtotime('NOW') - strtotime($topic_info->topic_last_post_time); $last_post_gap = date('i', strtotime($last_post_gap)); $last_post = date('F j, Y', strtotime($topic_info->topic_last_post_time)); if ($last_post <= '- 1 DAY') { $last_post = 'Yesterday at '.date("g:i a", strtotime($topic_info->topic_last_post_time)); } if ($last_post <= '- 1 MINUTE') { $last_post = 'Less Than 1 Minute Ago'; } else { $last_post = $last_post_gap.' Minutes Ago'; } but that just displays 0 minutes ago regardless of the time. Is there anything im missing? Hi i have two arrays, activity and feed.. contains 100 arrays, $activity = array(0,1,2....,100); contains 5 arrays $feed = array(100,50,25,12,75); I have 7 ranges, (0 -15),(15-30),(30-45),...(90-105) now i need to compare feed array with activity array to find in which range it was... Example, $feed[0] = 100, then it is in (90-105) range $feed[3] = 12, then it is in (0-15) range.. ... how to find this range?? please help me.. I want to iterate through each element on an html page and echo each element's name. I thought this should work: Okay, I'm wanting to do a search, but until return the info if it has a specific indicator in the chosen field. Let me show you: $query = doquery("SELECT * FROM `orgs` IF `type`='c' ORDER BY name", "orgs"); How do I do that "IF" bit? Obviously this doesn't work. Thanks! I am trying to find a character in the follwing string $string = ' Mumbai Mast Kallander - 02 - Mumbai Mast Kallander'; the character i want to find is '-' and the find how many times does it occur in the string.. can anyone help? Hey Guys Im following PHPACADEMY tutorial for integrating login. Im on the second video The problem im getting is when i enter in my login and password from my table in my database [(alex, abc) I tried copying them directly also] "I get the error that user doesn't exist" index.php Code: [Select] <html> <form action='login.php' method='POST'> Username: <input type='text' name='username'><br> Password: <input type='password' name='password'><br> <input type='submit' value='Log In'> </form> </html> Login.php Code: [Select] <?php $username = $_POST['username']; $password = $_POST['password']; if ($username&&$password) { $connect = mysql_connect("localhost","root","") or die ("couldnt connect"); mysql_select_db("phplogin") or die ("could not connect to db"); $query = mysql_query("SELECT * FROM users WHERE username='$username'"); $numrow = mysql_num_rows($query); if ($numrows!=0) { //code to login } else die("that user doesn't exist"); } else die("Please Enter username and password"); ?> I run MAMP and would like to know where I can find and view the data stored in my Sessions? Any ideas? Thanks, Debbie |