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PHP - Populating Drop Down Menu's With Mysql Data
Alright so I created a MySQL database that has 5 tables each named a brand of a dirt bike.
In each table their are 2 fields, one INDEX_ID and MODELS. Under that for rows I have every model bike named. A quick question before I get onto what I want to do: Can data be added underneath the rows? For example, users will be able to submit information about each bike model. If each bike model is a row, can there be a category past that row or do I need to make each field a model name and just have a ton of fields and have the rows be the information users submit. To make it easier to understand I'll post the SQL code for the brand Honda: CREATE TABLE `Honda` ( `INDEX_ID` int(3) NOT NULL auto_increment, `MODELS` varchar(20) collate latin1_general_ci NOT NULL, PRIMARY KEY (`INDEX_ID`) ) ENGINE=MyISAM DEFAULT CHARSET=latin1 COLLATE=latin1_general_ci AUTO_INCREMENT=23 ; -- -- Dumping data for table `Honda` -- INSERT INTO `Honda` VALUES(1, 'CR85'); INSERT INTO `Honda` VALUES(2, 'CR125'); INSERT INTO `Honda` VALUES(3, 'CR250'); INSERT INTO `Honda` VALUES(4, 'CRF100'); INSERT INTO `Honda` VALUES(5, 'CRF150'); INSERT INTO `Honda` VALUES(6, 'CRF230'); INSERT INTO `Honda` VALUES(7, 'CRF250X'); INSERT INTO `Honda` VALUES(8, 'CRF250R'); INSERT INTO `Honda` VALUES(9, 'CRF450X'); INSERT INTO `Honda` VALUES(10, 'CRF450R'); INSERT INTO `Honda` VALUES(11, 'CRF50'); INSERT INTO `Honda` VALUES(12, 'CRF70'); INSERT INTO `Honda` VALUES(13, 'CRF80'); INSERT INTO `Honda` VALUES(14, 'XR650'); INSERT INTO `Honda` VALUES(15, 'CR500'); INSERT INTO `Honda` VALUES(16, 'XR100'); INSERT INTO `Honda` VALUES(17, 'XR200'); INSERT INTO `Honda` VALUES(18, 'XR250'); INSERT INTO `Honda` VALUES(19, 'XR400'); INSERT INTO `Honda` VALUES(20, 'XR50'); INSERT INTO `Honda` VALUES(21, 'XR70'); INSERT INTO `Honda` VALUES(22, 'XR80'); Anyway I still need to figure out how to have this under a form that a user can use to select the bike they want to submit information about. A code like this perhaps?: <? $connection = mysql_connect("localhost","user","pass"); $fields = mysql_list_fields("dbname", "table", $connection); $columns = mysql_num_fields($fields); echo "<form action=page_to_post_to.php method=POST><select name=Field>"; for ($i = 0; $i < $columns; $i++) { echo "<option value=$i>"; echo mysql_field_name($fields, $i); } echo "</select></form>"; ?> Thanks. Similar Tutorialstrying to get a drop-down menu (in a form) to work that needs to get populated from a table table called : CarCategory in this table are 2 columns called CarCategoryID (unique number from 1-18) CarCategoryDesc (actual name of category.. e.g. 'convertible') link : http://98.131.37.90/postPart.php I'm a total novice.. and can't figure out why the first is not working and the second (country) is working code : <!--NOT WORKING ... why not ?? should show drop down menu--> <label> <div align="center"> <select name="carcategory" id="CarCategory" class="validate[required]" style="width: 200px;"> <option value="">Select Car Category from list...</option> <?php while($obj_queryCarCategory = mysql_fetch_object($result_queryCarCategory)) { ?> <option value="<?php echo $obj_queryCarCategory->CarCategoryID;?>" <?php if($obj_queryCarCategory->CarCategoryID == $UserCountry) { echo 'selected="selected"'; } ?> > <?php echo $obj_queryCarCategory->CarCategoryDesc;?></option> <?php } ?> </select> </div> </label> <!-- working ! --> <label> <div align="center"> <select name="country" id="Country" class="validate[required]" style="width: 200px;"> <option value="">Select...</option> <?php while($obj_queryCountry = mysql_fetch_object($result_queryCountry)) { ?> <option value="<?php echo $obj_queryCountry->CountryID;?>" <?php if($obj_queryCountry->CountryID == $UserCountry) { echo 'selected="selected"'; } ?> > <?php echo $obj_queryCountry->CountryName;?></option> <?php } ?> </select> </div> </label> Hi I have coded a drop down menu with php and i am trying to retrieve the data when a user select a option from the menu and the data is retrieved from the database. So far i have tried and nothing is displaying when i tried to process the php form. Sales.php Page <form action="saleprocess.php" method="GET"> <?php echo 'Product Model:'; $query="SELECT * FROM products"; /* You can add order by clause to the sql statement if the names are to be displayed in alphabetical order */ $result = mysql_query ($query); echo "<select name=product_model value=Select>Product Model</option>"; // printing the list box select command while($rows=mysql_fetch_array($result)){//Array or records stored in $nt echo "<option name=product_model value='.$rows[product_id].'>$rows[product_model]</option>"; /* Option values are added by looping through the array */ } echo "</select><br>"; ?> <input type='submit' name='submit' value='Create'></input> <br> </form> ******************************************************************************** Salesprocess.php page <?php include("connect.php"); if(isset($_GET['product_id'])){ $product_id = $_GET['product_id']; $query = mysql_query("SELECT * FROM products WHERE product_id= $product_id"); while($rows = mysql_fetch_assoc($query)) { echo 'Product Model<br>'; echo $rows['product_id']; echo $rows['product_model']; } } ?> Muchly appreciated if someone can help me Hey guys, I have a drop down menu like so <select name="Categories[]"> <Option value="Horror" Name="Horror">Horror</Option> <Option value="Romance" Name="Romance">Romance</Option> ......................................... Like that, just out of interest once the user has selected the option I am unsure on how to extract what the user chose from the drop down menu, how do you grab the value from array of the drop down menu that the user has selected. Any help A.S.A.P would really be appreciated. It also has to be an array. I also thought of using the $_POST['Categories']; to try grab the value if that is the correct way to go about it. Thank you in advance. Hi all, I am currently learning PHP and have the homework to produce a function that can delete a row in a MySQL database table by clicking on an item in a drop-down menu in a web page. The code I have produced up until now is this:
<!DOCTYPE HTML>
<html lang="de">
<head>
<meta charset="utf-8" />
<title>E3_Artikel_Löschen</title>
</head>
<body>
<form method = "GET">
<?php
$anr="";
try {
$pdo = new PDO ('mysql:dbname=bestelldatenbank;host=localhost;charset=utf8', 'root', '');
} catch (PDOException $error){
die ($error->getMessage());
}
?>
<div>
<p>
<label for="artikel">Artikel: </label>
<select id="artikel" name="artikel">
<?php
$sqlSelect = "SELECT anr, name FROM artikel ORDER BY anr ASC";
foreach ($pdo->query($sqlSelect) as $row) {
echo "<option value=$row[0]>$row[0] | $row[1]</option>\n";
$anr = $row[0];
}
?>
</select>
<input type = "submit" value = "Delete row" />
</p>
</div>
<?php
function artLoeschen($anr) {
echo "Function called $anr";
if(isset($_GET[$anr])) {
$anr = $_GET[$anr];
$sqlDelete = $pdo->query("DELETE FROM artikel WHERE anr = :anr");
if ($stmt = $pdo->prepare($sqlDelete)) {
$stmt->bindParam(':anr', $anr);
$stmt->execute();
}
echo "<h2><b>Artikel gelöscht!</b></h2>";
}
}
?>
</form>
</body>
</html>
So, I have observed the following when I run the script in a browser: 1. The HTML works as expected and I get a drop-down list with the article number and description of each item in the affected table. 2. I can click on an item in the list and it populates the top item in the drop-down list. 3. When I click delete row, the selected item is not deleted. 4. There are no error messages returned but the function is not executed (at least not as I would like to expect).
I have obviously missed something or made a mistake in my code. I would be very grateful for any help...this is driving me mad! :) Regards, Kevin your MySQL server version: 5.1.36 Code: [Select] SELECT * FROM game_weapons Table: Picture Attached the EXPLAIN output for your query, if applicable: I wish to connect a drop down menu's selection of weapons with the correlated table information. What do I want to happen: Click on a drop down Menu and have a list of weapons, these weapons are associated with a set number in the database and passed onto the next screen. (The larger number wins, this part I have figured out). <p> <select name="weapon2" style="font-size:20px;font-family:Arial;width:275px"> <option value="power">Power</option> <option value="intelligence">Intelligence</option> <option value="speed">Speed</option> <option value="reserve">Reserve</option> </select> </p> I do have the battle code figured out! (This should be the last step). Hi!! the question look simple at his base because I will receive TONS of answer saying ... " hey men use javascript OR ajax " but I don't want to use these... I want to populate the second dropdown menu dynamicly with PHP code. and sql query. why?? because I have over 43000 possibility and doing a script manually is impossible. the database is changing every hour. this is the code of my working page. the form NOTE: i REMOVE ALL DB CONNECTION FOR SECURITY PURPOSE. THANKS FOR YOUR UNDERTANDING. <!doctype html public "-//w3c//dtd html 3.2//en"> <html> <head> <title>(Type a title for your page here)</title> </head> <body > <img src="http://www.scale24-25.com/images/banners/banner.jpg" alt="banner" width="997" height="213" border="0" usemap="#Map" /> <map name="Map" id="Map"> <area shape="poly" coords="0,100,85,102,92,55,108,50,326,51,323,7,3,3" href="http://www.hobby-shop.qc.ca" alt="hobby-shop" /> <area shape="poly" coords="672,57,891,53,887,4,995,4,985,108,673,102" href="http://www.hobby-shop.qc.ca" alt="hobby-shop" /> <area shape="poly" coords="326,13,330,53,98,54,90,92,670,99,668,54,889,51,886,5" href="http://www.scale-auto-style.com" alt="" /> </map> <?php if (isset($_POST['todo']) && $_POST['todo'] == "search") { $todo=$_POST['todo']; $manufacturer_reel=$_POST['manufacturer_reel']; $query="select * from kit where "; ////////// Including manufacturer_reel field search //// if(strlen($manufacturer_reel) > 0 ){ $query.= " manufacturer_reel='$manufacturer_reel' and "; } //// End of class field search /////////// $query=substr($query,0,(strLen($query)-4)); echo $query; echo "<br><br>"; $nt=mysql_query($query); echo mysql_error(); // End if form submitted }else{ echo "<form method=post action='search-keyword.php?go'><input type=hidden name=todo value=search>"; ?> <table width="960" border="0"> <tr> <td colspan="3"><p align="center"></td> </tr> <tr> <td><div align="right"></div></td> <td> </td> <td> </td> </tr> <tr> <td> </td> <td> </td> <td> </td> </tr> <tr> <td><div align="right">Echelle du modele</div></td> <td align="center"> <?php // strat of drop down /// $q=mysql_query("SELECT DISTINCT scale FROM kit ORDER BY scale"); echo '<select name="scale"><option value="scale">Please Choose an Option</option>'; while($row = mysql_fetch_array($q)) { $thing = $row['scale']; echo '<option>'.$thing.'</option>'; } echo "</select>"; echo " <br> \n"; echo " <br> \n"; ?></td> <td><div align="left">Scale of model</div></td> </tr> <tr> <td> </td> <td> </td> <td><div align="right"></div></td> </tr> <tr> <td><div align="right">Nom du manufacturier automobile</div></td> <td align="center"><?php // strat of drop down /// $q=mysql_query("SELECT DISTINCT manufacturer_reel FROM kit ORDER BY manufacturer_reel"); echo '<select name="manufacturer_reel"><option value="reel manufacturer">Please Choose an Option</option>'; while($row = mysql_fetch_array($q)) { $thing = $row['manufacturer_reel']; echo '<option>'.$thing.'</option>'; } echo "</select>"; // end of drop down /// echo " <br> \n"; echo " <br> \n"; // end of drop down /// ?></td> <td><div align="left">Name Of vehicule manufacturer</div></td> </tr> <tr> <td> </td> <td> </td> <td><div align="right"></div></td> </tr> <tr> <td><div align="right">Nom du manufacturier de modele reduit</div></td> <td align="center"><?php // start of drop down /// $q=mysql_query("SELECT DISTINCT manufacturer_kit FROM kit ORDER BY manufacturer_kit"); echo '<select name="manufacturer_kit"><option value="kit manufacturer">Please Choose an Option</option>'; while($row = mysql_fetch_array($q)) { $thing = $row['manufacturer_kit']; echo '<option>'.$thing.'</option>'; } echo "</select>"; // end of drop down /// echo " <br> \n"; echo " <br> \n"; ?></td> <td><div align="left">Name Of kit manufacturer</div></td> </tr> <tr> <td><div align="right"></div></td> <td> </td> <td> </td> </tr> <tr> <td><div align="right">Annee de fabrication du Vehicule</div></td> <td align="center"><?php // strat of drop down /// $q=mysql_query("SELECT DISTINCT year_prod_reel FROM kit ORDER BY year_prod_reel"); echo '<select name="year_prod_reel"><option value="vehicules year manufactured">Please Choose an Option</option>'; while($row = mysql_fetch_array($q)) { $thing = $row['year_prod_reel']; echo '<option>'.$thing.'</option>'; } echo "</select>"; // end of drop down /// echo " <br> \n"; echo " <br> \n"; ?></td> <td><div align="left">Year of production of the vehicule</div></td> </tr> <tr> <td> </td> <td> </td> <td> </td> </tr> <tr> <td> </td> <td align="center"> </td> <td> </td> </tr> <tr> <td><div align="right"><strong></strong></div></td> <td align="center"> <?php echo " <br><input type=submit value=Search name='name' action='search-keyword.php?go' > </form> "; } ?> <td><div align="left"><strong></strong></div></td> </body> </html> AND THE PAGE RESULT <!doctype html public "-//w3c//dtd html 3.2//en"> <html> <head> <title>(Type a title for your page here)</title> </head> <body > <p align="center"><img src="http://www.scale24-25.com/catalog/images/banners/banner.jpg" alt="banner" width="997" height="213" border="0" usemap="#Map" /> <map name="Map" id="Map"> <area shape="poly" coords="0,100,85,102,92,55,108,50,326,51,323,7,3,3" href="http://www.hobby-shop.qc.ca" alt="hobby-shop" /> <area shape="poly" coords="672,57,891,53,887,4,995,4,985,108,673,102" href="http://www.hobby-shop.qc.ca" alt="hobby-shop" /> <area shape="poly" coords="325,11,329,51,97,52,89,90,669,97,667,52,888,49,885,3" href="http://www.scale-auto-style.com" alt="" /> </map></p> <table width="920" border="0"> <tr> <td width="359"><p class="style5">You will find some TBC. TBC is for "To Be Confirmed". If somebody know the missing information ( TBC ) it will be appreciate to send it to me at this mail: <a href="mailto:info@hobby-shop.qc.ca">info@hobby-shop.qc.ca</a> <br /> <br /> thanks in advance for your help</p> </td> <td width="161"> </td> <td width="386"> <div align="right"> <p>This logo <img src= 'http://www.scale24-25.com/images/PDF_logo.gif' width='50' height='50'/> mean that you can download a PDF file. To read it you need minimum Acrobat reader and you can download it <a href="http://get.adobe.com/reader/">here</a></p> <p>Some link will return a TBC. Sorry for any inconveniant. as soon as we will receive or do the PDF it will be updated.</p> </div></td> </tr> </table> <br> <?php if (isset($_POST['todo']) && $_POST['todo'] == "search") { $todo=$_POST['todo']; $name=$_POST['manufacturer_reel']; $name1=$_POST['manufacturer_kit']; $name2=$_POST['year_prod_reel']; $name3=$_POST['scale']; //-query the database table for the post field $sql="SELECT kit_id, kit_number, kit_name, description, manufacturer_kit, manufacturer_reel, scale, engine_detail, year_prod_kit, year_prod_reel, image_id, image_id1, image_id2 FROM kit "; $sqlOperand="WHERE"; if ($name != "reel manufacturer") { $sql = $sql . $sqlOperand . " manufacturer_reel LIKE '%" . $name ."%' "; $sqlOperand = " AND "; } if ($name1 != "kit manufacturer") { $sql = $sql . $sqlOperand . " manufacturer_kit LIKE '%" . $name1 ."%' "; $sqlOperand = " AND "; } if ($name2 != "vehicules year manufactured") { $sql = $sql . $sqlOperand . " year_prod_reel LIKE '%" . $name2 ."%' "; $sqlOperand = " AND "; } if ($name3 != "scale") { $sql = $sql . $sqlOperand . " scale LIKE '%" . $name3 ."%' "; $sqlOperand = " AND "; } if ($sqlOperand == "WHERE") { echo "<p>Please enter a search query</p>"; } else { // echo '<img src="web-design/sorry.jpg" alt="sorry">'; // echo "Sorry nothing match your selection / Desolle rien ne correspond a votre selection"; // echo "run sql: <BR> $sql <BR> and display results"; } //-run the query against the mysql query function $result=mysql_query($sql); //-make the header of the table echo " <table align=center width=\"1340\" border=\"\">\n"; echo " <tr>\n"; echo" <td nowrap align=center width='95'> kit manufacturer \n"; echo" <td nowrap align=center width='55'> scale \n"; echo" <td nowrap align=center width='90'> kit number \n"; echo" <td nowrap align=center width='290'> kit name \n"; echo" <td nowrap align=center width='400'> description \n"; echo" <td nowrap align=center width='125'> vehicule year \n"; echo" <td nowrap align=center width='80'> complete engine detail\n"; echo" <td nowrap align=center width='80'> Select Picture to get bigger\n"; echo" <td nowrap align=center width='75'> instruction sheet\n"; echo" <td nowrap align=center width='75'> box contain\n"; echo " <tr>\n"; //-create while loop and loop through result set while($row=mysql_fetch_array($result)){ $description =$row['description']; $manufacturer_kit=$row['manufacturer_kit']; $scale=$row['scale']; $manufacturer_reel=$row['manufacturer_reel']; $kit_id=$row['kit_id']; $kit_number=$row['kit_number']; $kit_name=$row['kit_name']; $engine_detail=$row['engine_detail']; $year_prod_reel=$row['year_prod_reel']; $image_id=$row['image_id']; $image_id1=$row['image_id1']; $image_id2=$row['image_id2']; //-create table of item during he while loop echo " <table align=center width=\"1340\" border=\"\">\n"; echo" <td nowrap align=center width='95'> $manufacturer_kit \n"; echo" <td nowrap align=center width='55'> $scale \n"; echo" <td nowrap align=center width='90'> $kit_number \n"; echo" <td nowrap align=center width='290'> $kit_name \n"; echo" <td nowrap width='400'> $description \n"; echo" <td nowrap align=center width='125'> $year_prod_reel \n"; echo" <td nowrap align=center width='80'> $engine_detail \n"; echo" <td nowrap width='80'> <a href=".$image_id."> <img src='".$image_id."' width='75' height='50' border='0'/>"; echo" <td nowrap width='75'> <a href= ".$image_id1."> <img src= 'http://www.scale24-25.com/images/PDF_logo.gif' width='50' height='50' border='0'/>"; echo" <td nowrap width='75'> <a href=".$image_id2."> <img src='http://www.scale24-25.com/images/PDF_logo.gif' width='50' height='50' border='0'/>"; echo " </tr>\n"; echo " </table>\n"; echo " </tr>\n"; echo " </table>\n"; } } else{ echo "<p>Please enter a search query</p>"; } ?> </body> </html> YOU CAN SEE IN THE FORM i HAVE A DROP DOWN MENU CALL Name Of vehicule manufacturer .. IN VACT THIS IS THE REAL CAR MANUFACTURER EX: TOYOTA, gmc ETC.. WHEN THE USER WILL SELECT ONE OF THESE AN OTHER DROPDOWN ( NOT SHOWN ) WILL DISPLAY EVERY MODEL FOUND IN THE DATABASE IN RELATION WITH THE MANUFACTURE. IN FACT IT'S LOCATED IN THE TABLE. SO HOW I CAN GET THIS RELATION?? YOURS SEBASTIEN Basically, I have a database table called 'users' and I would like to populate a drop down box with these values of 'users'. How?? - to call upon the values is this: 'upduser2' Right now, all I am using is a text box, in where you have to type in the users name manually (this is so an admin can change variables and settings according to that current user). This is what I am using so far: <h3>Update User Level</h3> <? echo $form->error("upduser"); ?> <table> <form action="adminprocess.php" method="post"> <tr> <td> Username:<br /> <input type="text" name="upduser" maxlength="30" value="<? echo $form->value("upduser"); ?>" /></td> <td> Level:<br /> <select name="updlevel"> <option value="1">1 </option> //example settings <option value="9">9 </option> </select></td> <td><br /> <input type="hidden" name="subupdlevel" value="1" /> <input type="submit" value="Update Level" /></td> </tr> </form> </table></td> </tr> Much help would be appreciated. As a complete newbie to php and webdesigning i have a following problem.I would like to retrieve the data from database and display it in a drop down menu.Then i should allow the user to select the values from drop down list along with other details,in other words i have to embed the drop down output as the form input for the user and store the form data in another table.I am running a xampp server and i am using php 5.4 version.Please help.My code is as follows.In this case project_name is displayed as the drop down output.but how do i use the same drop down output as a input in the form. <html> <head></head> <body> <?php error_reporting(E_ALL ^ E_DEPRECATED); include 'connect.php' ; $tbl_name="projects"; $sql="SELECT project_name FROM $tbl_name "; $result=mysql_query($sql); if($result === FALSE) { die(mysql_error()); } ?> <form name="resources" action="hourssubmit.php" method="post" > <?php echo "<select name='project_name'>"; while ($row = mysql_fetch_array($result)) { echo "<option value='" . $row['project_name'] ."'>" . $row['project_name'] ."</option>"; } echo "</select>"; ?> </form> </body> </html> Hi all I need to combine these two scripts: Firstly, the following decides which out of the following list is selected based on its value in the mySQL table: <select name="pack_choice"> <option value="Meters / Pack"<?php echo (($result['pack_choice']=="Meters / Pack") ? ' selected="selected"':'') ?>>Meters / Pack (m2)</option> <option value="m3"<?php echo (($result['pack_choice']=="m3") ? ' selected="selected"':'') ?>>Meters / Pack (m3)</option> <option value="Quantity"<?php echo (($result['pack_choice']=="Quantity") ? ' selected="selected"':'') ?>>Quantity</option> </select> Although this works OK, I need it also to show dynamic values like this: select name="category"> <?php $listCategories=mysql_query("SELECT * FROM `product_categories` ORDER BY id ASC"); while($categoryReturned=mysql_fetch_array($listCategories)) { echo "<option value=\"".$categoryReturned['name']."\">".$categoryReturned['name']."</option>"; } ?> </select> I'm not sure if this is possible? Many thanks for your help. Pete I have a mysql table with the structure of Code: [Select] ID Menu_Name Parent_ID 1 Finance NULL 2 Business NULL 3 Investment 1 4 Trading 2 How can I create a html <ul><li> list based on the parent? Any help on this would be greatly appreciated. I am trying to run a mysqldump from my site for my client when they want to back up. They basically will jsut click a button to run the backup. With my script below, the backup file is genrated, but there is no table data in the file. There are the headers in the file with the server IP, linux versin, etc..., but there is no data in the file. Does this look right? Thank you for helping me out. Ryan Code: [Select] ini_set ("display_errors", "1"); error_reporting(E_ALL); $dbhost = 'localhost'; $dbuser = 'databaseuser'; $dbpass = 'password'; $conn = mysql_connect($dbhost, $dbuser, $dbpass) or die ('Error connecting to mysql'); $dbname = 'database'; mysql_select_db($dbname); $tableName = 'lots'; $backupFile1 = '/home/stuff/wwwroot/stuff/appnew/backup/'; $backupFile = $backupFile1.$dbname . date("Y-m-d-H-i-s") . '.gz'; $command = "mysqldump --opt -h$dbhost -u$dbuser -p$dbpass $dbname | gzip > $backupFile"; system($command); $result = mysql_query($command); Hi I making some forms that write to mysql database, Im now in the process of making the update form so the user can update there details on the form, I want it to populate the form with existing data but its not doing it at all. Thanks in advance
Attached Files
delete.php 210bytes
2 downloads
modify.php 4.03KB
4 downloads
index.php 473bytes
3 downloads The below should choose the radio button that is set by the $_SESSION variable or default to 3. However, it's defaulting to 1. Code: [Select] $content.=' <p class="form_item"><label>Product Rating:</label><br /> <div class="rating_radio"><input type="radio" name="review_product_rating" value="1"'; if(isset($review_product_rating) && $review_product_rating=="1"){$content.='checked';} $content.=' /> <br />1</div> <div class="rating_radio"><input type="radio" name="review_product_rating" value="2"'; if(isset($review_product_rating) && $review_product_rating=="2"){$content.='checked';} $content.=' /> <br />2</div> <div class="rating_radio"><input type="radio" name="review_product_rating" value="3"'; if(isset($review_product_rating) && $review_product_rating=="3" || !isset($review_product_rating)){$content.='checked';} $content.=' /> <br />3</div> <div class="rating_radio"><input type="radio" name="review_product_rating" value="4"'; if(isset($review_product_rating) && $review_product_rating=="4"){$content.='checked';} $content.=' /> <br />4</div> <div class="rating_radio"><input type="radio" name="review_product_rating" value="5"'; if(isset($review_product_rating) && $review_product_rating=="5"){$content.='checked';} $content.=' /> <br />5</div> <div class="worst">(Worst)</div><div class="best">(Best)</div> </p> I'm figuring it's because it's multiple if statement (with no elseif) so it's evaluating the first if and being set to true. I tried changing everything else after the first one to elseif, and it's throwing an unexpected T_ELSEIF error. Hi all, I hope someone can help me out here as I think I am close but am not sure where to go from here. The problem is: I have a cms where a user can see a list of photos in the gallery. I provide them the ability to select what photos they want to appear on a particular webpage. The problem I have is that the user wants to be able to put the photos in whatever order they choose. So, I have a form (see attached), the html code is: <table width="566px" cellspacing="0" border="0"> <tr> <td width="33%"> <div class="serviceCell"> <input type='checkbox' checked='checked' name='photos[][0]' value='119' /> Bathroom Sin... <img src="./images/help.gif" title="Enter an integer to signify the order in which this image will appear on the webpage." alt="Enter an integer to signify the order in which this image will appear on the webpage."/> <input type="text" size="2" name="photos[][1]" value="0"/> </div> </td> <td width="33%"> <div class="serviceCell"> <input type='checkbox' checked='checked' name='photos[][0]' value='113' /> Courtyard 1 <img src="./images/help.gif" title="Enter an integer to signify the order in which this image will appear on the webpage." alt="Enter an integer to signify the order in which this image will appear on the webpage."/> <input type="text" size="2" name="photos[][1]" value="0"/> </div> </td> <td width="33%"> <div class="serviceCell"> <input type='checkbox' name='photos[][0]' value='114' /> Courtyard 2 <img src="./images/help.gif" title="Enter an integer to signify the order in which this image will appear on the webpage." alt="Enter an integer to signify the order in which this image will appear on the webpage."/> <input type="text" size="2" name="photos[][1]" value=""/> </div> </td> </tr>... Now, lets assume that the user ticked the box next to 'Courtyard 2' and entered an integer '1' in the input box to signify that this image should be displayed 1st on the chosen webpage. These 2 values go into the multidimensional array (photoid, ranking) and are submitted in the form to php in the photos[][] array. But here is where I have the problem. I am trying to extract the values from the array and then do an insert to a table in mysql. My syntax must be wrong somewhere so I am asking anyone to please offer any advice: if (isset($_REQUEST['submitted'])){ $photos = $_REQUEST['photos']; ... if(!empty($photos)){ foreach($photos as $photoID){ $sql = "INSERT IGNORE INTO menuItemPhotos SET photoid='$photoID[0]', menuItemid='$id', ranking='$photoID[1]'"; $ok = @mysql_query($sql); // execute the query } // End of foreach($photos as $photoID){ } // End of if(!empty($photos)){ Thanks Conor [attachment deleted by admin] I'm building a php program that registers users onto a website. With the help of people from this thread http://www.phpfreaks.com/forums/index.php?topic=332260.15 I was able to accomplish the goal and now the signup works with conditions that check for a valid email, and if the password is strong enough. T he program correctly displays the the problem when a user does NOT enter a valid email, or a strong enough password, but the user has to re-enter the email and password everytime. I want to make it so that the fields remained populated with what the user entered previously, so he or she does not have to re-enter his or her email/password. Here is the code (its really ghetto) Code: [Select] <?php function check_email_address($email) { // First, we check that there's one @ symbol, and that the lengths are right if (!ereg("^[^@]{1,64}@[^@]{1,255}$", $email)) { // Email invalid because wrong number of characters in one section, or wrong number of @ symbols. return false; } // Split it into sections to make life easier $email_array = explode("@", $email); $local_array = explode(".", $email_array[0]); for ($i = 0; $i < sizeof($local_array); $i++) { if (!ereg("^(([A-Za-z0-9!#$%&'*+/=?^_`{|}~-][A-Za-z0-9!#$%&'*+/=?^_`{|}~\.-]{0,63})|(\"[^(\\|\")]{0,62}\"))$", $local_array[$i])) { return false; } } if (!ereg("^\[?[0-9\.]+\]?$", $email_array[1])) { // Check if domain is IP. If not, it should be valid domain name $domain_array = explode(".", $email_array[1]); if (sizeof($domain_array) < 2) { return false; // Not enough parts to domain } for ($i = 0; $i < sizeof($domain_array); $i++) { if (!ereg("^(([A-Za-z0-9][A-Za-z0-9-]{0,61}[A-Za-z0-9])|([A-Za-z0-9]+))$", $domain_array[$i])) { return false; } } } return true; } define('DB_NAME', 'catch'); define('DB_USER', 'username'); define('DB_PASS', 'password'); define('DB_HOST', 'page.sqlserver.com'); // contact to database $connect = mysql_connect(DB_HOST, DB_USER, DB_PASS) or die('Error , check your server connection.'); mysql_select_db(DB_NAME); //Get data in local variable $v_name=$_POST['name']; $v_email=$_POST['email']; $v_msg=$_POST['msg']; if ( check_email_address($_POST['name']) == false) { $query = "INSERT INTO contact(name,email,msg) VALUES ('$v_name','$v_email','$v_msg')"; $result = mysql_query( $query ); if( !$result ) { die( mysql_error() ); } echo <<<EOD <head> <link rel="stylesheet" type="text/css" href="http://hedgezoo.com/signup.css"> </head> <h2>Free Registration</h2> <form action="contact_insert2.php" method="POST" id="insert"> <table> <tr> <td>Email</td> <td ><input type="text" size="40" name="name"></td> </tr> <tr> <td>Password</td> <td><input type="password" size="40" name="msg" ></td> </tr> <tr> <td colspan=2 id="sub"> You must enter a valid email. <br /> <input type="submit" name="submit" value="submit"> </td> </tr> </Table> </form> EOD; } if( $v_name == "" || $v_msg == "" ) // if name is empty or if pass is empty { $query = "INSERT INTO contact(name,email,msg) VALUES ('$v_name','$v_email','$v_msg')"; $result = mysql_query( $query ); if( !$result ) { die( mysql_error() ); } echo <<<EOD <head> <link rel="stylesheet" type="text/css" href="http://hedgezoo.com/signup.css"> </head> <h2>Free Registration</h2> <form action="contact_insert2.php" method="POST" id="insert"> <table> <tr> <td>Email</td> <td ><input type="text" size="40" name="name"></td> </tr> <tr> <td>Password</td> <td><input type="password" size="40" name="msg" ></td> </tr> <tr> <td colspan=2 id="sub"> You must enter an email and password. <br /> <input type="submit" name="submit" value="submit"> </td> </tr> </Table> </form> EOD; } if( strcspn( $_REQUEST['msg'], '0123456789' ) == strlen( $_REQUEST['msg'] ) ) // the above statement says if pass does not contain a number { $query = "INSERT INTO contact(name,email,msg) VALUES ('$v_name','$v_email','$v_msg')"; $result = mysql_query( $query ); if( !$result ) { die( mysql_error() ); } echo <<<EOD <head> <link rel="stylesheet" type="text/css" href="http://hedgezoo.com/signup.css"> </head> <h2>Free Registration</h2> <form action="contact_insert2.php" method="POST" id="insert"> <table> <tr> <td>Email</td> <td ><input type="text" size="40" name="name"></td> </tr> <tr> <td>Password</td> <td><input type="password" size="40" name="msg" ></td> </tr> <tr> <td colspan=2 id="sub"> <div style="color:red;">Your password must contain a number.</div> <br /> <input type="submit" name="submit" value="submit"> </td> </tr> </Table> </form> EOD; } if( strlen($_POST['msg']) < 8 ) // the above statement says if pass is not 8 characters long { $query = "INSERT INTO contact(name,email,msg) VALUES ('$v_name','$v_email','$v_msg')"; $result = mysql_query( $query ); if( !$result ) { die( mysql_error() ); } echo <<<EOD <head> <link rel="stylesheet" type="text/css" href="http://hedgezoo.com/signup.css"> </head> <h2>Free Registration</h2> <form action="contact_insert2.php" method="POST" id="insert"> <table> <tr> <td>Email</td> <td ><input type="text" size="40" name="name"></td> </tr> <tr> <td>Password</td> <td><input type="password" size="40" name="msg" ></td> </tr> <tr> <td colspan=2 id="sub"> <div style="color:red;">Your password must be at least 8 characters long.</div> <br /> <input type="submit" name="submit" value="submit"> </td> </tr> </Table> </form> EOD; } if ( $_POST['msg'] == strtolower($_POST['msg']) ) // the above statement says if pass is all lowercase { $query = "INSERT INTO contact(name,email,msg) VALUES ('$v_name','$v_email','$v_msg')"; $result = mysql_query( $query ); if( !$result ) { die( mysql_error() ); } echo <<<EOD <head> <link rel="stylesheet" type="text/css" href="http://hedgezoo.com/signup.css"> </head> <h2>Free Registration</h2> <form action="contact_insert2.php" method="POST" id="insert"> <table> <tr> <td>Email</td> <td ><input type="text" size="40" name="name"></td> </tr> <tr> <td>Password</td> <td><input type="password" size="40" name="msg" ></td> </tr> <tr> <td colspan=2 id="sub"> <div style="color:red;">Your password must have at least one capital letter.</div> <br /> <input type="submit" name="submit" value="submit"> </td> </tr> </Table> </form> EOD; } if ( preg_replace("/[^a-zA-Z0-9\s]/", "", $_POST['msg']) == $_POST['msg'] ) // the above statement says if pass contains no special characters { $query = "INSERT INTO contact(name,email,msg) VALUES ('$v_name','$v_email','$v_msg')"; $result = mysql_query( $query ); if( !$result ) { die( mysql_error() ); } echo <<<EOD <head> <link rel="stylesheet" type="text/css" href="http://hedgezoo.com/signup.css"> </head> <h2>Free Registration</h2> <form action="contact_insert2.php" method="POST" id="insert"> <table> <tr> <td>Email</td> <td ><input type="text" size="40" name="name"></td> </tr> <tr> <td>Password</td> <td><input type="password" size="40" name="msg" ></td> </tr> <tr> <td colspan=2 id="sub"> <div style="color:red;">Your password must have at least one special character.</div> <br /> <input type="submit" name="submit" value="submit"> </td> </tr> </Table> </form> EOD; } else echo <<<EOD <B>GO FUCK YOURSELF</B> EOD; ?> Dear All, I have attached here with a schema, of MySql DB format i am refering to for the topic i need help on. I want to know what is the best way to achieve this problem / task. I have a profile table, and a category table, and a table to map profiles to category. Which allows me to define/add into the category_profile_mapping table, profile ids against a category id. Each category can have anywhere between 2 to 1,00,000 profiles mapped to it. I have another table called sms_out. hence on the site, when i select a category and submit the form value with message, i want to know what is the best way to populate sms_out with MSISDN from the table "Profile" and the message from the form. The list of MSISDN will be based on the category id selected, hence the profile id's will be available in the category_profile_mapping table. I am bad at explaining the problem, however incase you folks need more info do let me know. i shall be glad to provide the same to .. all of you guys who are willing to help me PS: I am asking this question, cuz i want to knw the best solution to achieve this, when there is entries in millions to be done at one form submit. [attachment deleted by admin] hello. i have an issue where the data stored with an image is not saving to a mysql table. the image data is ok, just not the selections from the dropdown lists. here is the code <?php include ('connect.php'); // Insert any new image into database if(isset($_POST['xsubmit']) && $_FILES['imagefile']['name'] != "") { $fileName = $_FILES['imagefile']['name']; $fileSize = $_FILES['imagefile']['size']; $fileType = $_FILES['imagefile']['type']; $content = addslashes (file_get_contents($_FILES['imagefile']['tmp_name'])); $jeweltype = $_POST['jeweltype']; $jewelsize = $_POST['jewelsize_in']; $jewelcolour = $_POST['jewelcolour_in']; $jewelmaterial = $_POST['jewelmaterial_in']; $jewelgender = $_POST['jewelgender_in']; if(!get_magic_quotes_gpc()) { $fileName = addslashes($fileName); } // Checking file size if ($fileSize < 150000) { mysql_query ("INSERT into jewel_images (name,size,type,content,jeweltype,jewelsize,jewelcolour,jewelmaterial,jewelgender) " . "values ('$fileName','$fileSize','$fileType','$content','$jeweltype','$jewelsize','$jewelcolour','$jewelmaterial','$jewelgender')"); } else { $err = "The Image file to too large!"; } } // Find out about latest image $gotten = mysql_query("select * from jewel_images order by row_id desc"); $row = mysql_fetch_assoc($gotten); $bytes = $row['content']; // If this is the image request, send out the image if ($_REQUEST['pic'] == 1) { header("Content-type: $row[type];"); print $bytes; } ?> <html> <head> <title>Upload an image to a database</title> </head> <body> <font color="#FF3333"><?php echo $err ?></font> <table> <form name="Upload" enctype="multipart/form-data" method="post"> <tr> <td>Upload <input type="file" name="imagefile"><br /> Jewelery Type: <select> <?php $sql="SELECT jeweltype FROM jeweltypes"; $result =mysql_query($sql); while ($data=mysql_fetch_assoc($result)){ ?> <option value ="jeweltype" ><?php echo $data['jeweltype'] ?></option> <?php } ?> </select> <br /> Jewelery Size: <select> <?php $sql="SELECT jewelsize FROM jewelsizes"; $result =mysql_query($sql); while ($data=mysql_fetch_assoc($result)){ ?> <option value ="jewelsize" ><?php echo $data['jewelsize'] ?></option> <?php } ?> </select> <br /> Jewelery Colour: <select> <?php $sql="SELECT jewelcolour FROM jewelcolours"; $result =mysql_query($sql); while ($data=mysql_fetch_assoc($result)){ ?> <option value ="jewelcolour_in" ><?php echo $data['jewelcolour'] ?></option> <?php } ?> </select> <br /> Jewelery Material: <select> <?php $sql="SELECT jewelmaterial FROM jewelmaterials"; $result =mysql_query($sql); while ($data=mysql_fetch_assoc($result)){ ?> <option value ="jewelmaterial_in" ><?php echo $data['jewelmaterial'] ?></option> <?php } ?> </select> <br /> Jewelery Gender: <select> <?php $sql="SELECT jewelgender FROM jewelgenders"; $result =mysql_query($sql); while ($data=mysql_fetch_assoc($result)){ ?> <option value ="jewelgender_in" ><?php echo $data['jewelgender'] ?></option> <?php } ?> </select> <br /> <input type="submit" name="xsubmit" value="Upload"> </td> </tr> <tr> <td>Latest Image</td> </tr> <tr> <td><img src="?pic=1"></td> </tr> </form> </table> </body> </html> ============================================== here is the query =============================================== <html> <head><title>Your Page Title</title></head> <body> <?php $database="josh_jewel"; mysql_connect ("localhost", "xxxxxxxxx", "yyyyyyyyyyyy"); @mysql_select_db($database) or die( "Unable to select database"); $result = mysql_query( "SELECT jewelcolour FROM jewel_images" ) or die("SELECT Error: ".mysql_error()); $num_rows = mysql_num_rows($result); print "There are $num_rows records.<P>"; print "<table width=400 border=1>\n"; while ($get_info = mysql_fetch_row($result)){ print "<tr>\n"; foreach ($get_info as $field) print "\t<td><font face=arial size=1/>$field</font></td>\n"; print "</tr>\n"; } print "</table>\n"; ?> </body> </html> Ok, so I've spent quite a bit of time piecing together this solution from a variety of sources. As such, I may have something in my code below that doesn't make sense or isn't neccessary. Please let me know if that is the case. I'm creating an administrative form that users will you to add/remove items from a MySQL table that lists open positions for a facility. The foreach loop generates all of the possible job specialties from a table called 'specialty_list'. This table is joined to a second table ('open_positions') that lists any positions that have been selected previously. Where I'm stuck is getting the checkbox to be checked if the facility_ID from the open_positions table matches the $id passed in the URL via ?facility_id=''. Here's where I am so far: $query = "SELECT specialty_list.specialty_displayname , specialty_shortname , open_positions.position , facility_ID FROM specialty_list LEFT OUTER JOIN open_positions ON open_positions.position = specialty_list.specialty_shortname ORDER BY specialty_list.specialty_shortname"; $results = mysql_query($query) or die(mysql_error()); while($row = mysql_fetch_assoc($results)) { $positions[$row['specialty_shortname']] = $row['specialty_displayname']; } echo "<form method='POST' action='checkbox.php'>"; foreach($positions as $specialty_shortname => $specialty_displayname) { $facility_ID = $row['facility_ID']; $checked = $facility_ID == $row['facility_ID'] ? ' checked' : ''; echo "<input type='checkbox' name='position[]' value=\"{$specialty_shortname}\"{$checked}> {$specialty_displayname}</input><br/>"; } echo "<input type='hidden' name='facility_ID' value='$id'>"; echo "<input type='submit' value='Submit Checkboxes!'>"; echo "</form>"; Any ideas how to get this working? I feel like I'm very close, but I just can't get it. I also tried starting from scratch with a WHILE statement instead of a FOREACH, but haven't tweaked it enough to prevent duplicate checkboxes. With that in mind, here it is, just in case that's a better direction: $query = "SELECT specialty_list.specialty_displayname , specialty_shortname , open_positions.position , facility_ID FROM specialty_list LEFT OUTER JOIN open_positions ON open_positions.position = specialty_list.specialty_shortname ORDER BY specialty_list.specialty_shortname"; $results = mysql_query($query) or die(mysql_error()); echo "<form method='POST' action='checkbox.php'>"; while($row=mysql_fetch_assoc($results)) { $facility_ID = $row['facility_ID']; $specialty_shortname = $row['specialty_shortname']; $specialty_displayname = $row['specialty_displayname']; if ($facililty_ID==$id) { $checked=' checked'; } echo "<input type='checkbox' name='position[]' value=\"$specialty_shortname\"$checked> $specialty_displayname</input><br/>"; } echo "<input type='hidden' name='facility_ID' value='$id'>"; echo "<input type='submit' value='Submit Checkboxes!'>"; echo "</form>"; Hi,
I need help in populating data from DB in the 2nd listbox depending on 1st listbox data (where the data of 1st listbox is also fetched from DB), in the same form.
Thanks,
Jessentha
Hello to all, I have problem figuring out how to properly display data fetched from MySQL database in a HTML table. In the below example I am using two while loops, where the second one is nested inside first one, that check two different expressions fetching data from tables found in a MySQL database. The second expression compares the two tables IDs and after their match it displays the email of the account holder in each column in the HTML table. The main problem is that the 'email' row is displayed properly while its while expression is not nested and alone(meaning the other data is omitted or commented out), but either nested or neighbored to the first while loop, it is displayed horizontally and the other data ('validity', 'valid_from', 'valid_to') is not displayed.'
Can someone help me on this, I guess the problem lies in the while loop? <thead> <tr> <th data-column-id="id" data-type="numeric">ID</th> <th data-column-id="email">Subscriber's Email</th> <th data-column-id="validity">Validity</th> <th data-column-id="valid_from">Valid From</th> <th data-column-id="valid_to">Valid To</th> </tr> </thead> Here is part of the PHP code:
<?php
while($row = $stmt->fetch(PDO::FETCH_ASSOC))
{
echo '
<tr>
<td>'.$row["id"].'</td>
';
while ($row1 = $stmt1->fetch(PDO::FETCH_ASSOC)) {
echo '
<td>'.$row1["email"].'</td>
';
}
if($row["validity"] == 1) {
echo '<td>'.$row["validity"].' month</td>';
}else{
echo '<td>'.$row["validity"].' months</td>';
}
echo ' <td>'.$row["valid_from"].'</td>
<td>'.$row["valid_to"].'</td>
</tr>';
}
?>
Thank you. |
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