PHP - If Mysql Record Is Admin, Then Run A Code
Hello, is there something like this?
If mysql record is admin, then a block of code How do I do something like that Similar TutorialsAll I am trying to do is add a record on a page without the page refreshing. For that ajax is used. Here is the code.
It does not add the record to mysql table. Can anyone tell me what I am doing wrong?
record.php
<!DOCTYPE HTML> <html lang="en"> <head> <script type="text/javascript" src="js/jquery-1.11.0.min.js"></script> <script type="text/javascript" > $(function() { $(".submit_button").click(function() { var textcontent = $("#content").val(); var name = $("#name").val(); var dataString = 'content='+ textcontent + '&name='+name; if(textcontent=='') { alert("Enter some text.."); $("#content").focus(); } else { $("#flash").show(); $("#flash").fadeIn(400).html('<span class="load">Loading..</span>'); $.ajax({ type: "POST", url: "action.php", data: dataString, cache: true, success: function(html){ $("#show").after(html); document.getElementById('content').value=''; $("#flash").hide(); $("#content").focus(); } }); } return false; }); }); </script> </head> <body> <?php $record_id = $_GET['id']; // getting ID of current page record ?> <form action="" method="post" enctype="multipart/form-data"> <div class="field"> <label for="title">Name *</label> <input type="text" name="name" id="name" value="" maxlength="20" placeholder="Your name"> </div> <div class="field"> <label for="content">content *</label> <textarea id="content" name="content" maxlength="500" placeholder="Details..."></textarea> </div> <input type="submit" name="submit" value="submit" class="submit_button"> </form> <div id="flash"></div> <div id="show"></div> </body> </html>action.php if(isset($_POST['submit'])) { if(empty($_POST['name']) || empty($_POST['content'])) { $error = 'Please fill in the required fields!'; } else { try { $name = trim($_POST['name']); $content = trim($_POST['content']); $stmt = $db->prepare("INSERT INTO records(record_id, name, content) VALUES(:recordid, :name, :content"); $stmt->execute(array( 'recordid' => $record_id, 'name' => $name, 'content' => $content )); if(!$stmt){ $error = 'Please fill in the required fields.'; } else { $success = 'Your post has been submitted.'; } } catch(Exception $e) { die($e->getMessage()); } } } I have a search form. $req is a keyword or an ID number input by user. As you can see, query checks only for rows where userID matches the current login userID. My question is, how to transform (not independent query for admins) the query to search all rows if user $access is admin (no matter the administrator's own userID). Code: [Select] <?php $userID="something"; (from session) $access="something" (from session / user or admin) $query="SELECT esName, esID, esAddress FROM estates WHERE (esName LIKE '$req' OR esID LIKE '$req') AND userID='$userID'"; mysql_query($query); ?> Thanks in advance <?php session_start( ); include_once( dirname( __FILE__ )."/../inc/func/get_sth.php" ); include_once( _ABSPATH_."/inc/func/header.php" ); if ( $_GET["f"] == "login" ) { $adminuser = strtolower( strip_tags( trim( $_POST["adminuser"] ) ) ); $r_0 = strtolower( strip_tags( trim( $_SESSION["r"] ) ) ); $r_1 = strtolower( strip_tags( trim( $_POST["r"] ) ) ); if ( $r_0 == $r_1 ) { $result = mysql_query( "SELECT password FROM admin where adminuser='".$adminuser."'" ); $val = mysql_fetch_array( $result ); if ( !$val["password"] ) { $loginfail = 1; } else { if ( $val[password] === md5( $_POST["password"] ) ) { $_SESSION['admin'] = $adminuser; header( "Location: ./" ); exit( ); } $loginfail = 1; } } else { $loginfail = 2; } } $page_title = l( "Administration Login" )." | ".get_sitename( ); $smarty->assign( "page_title", $page_title ); $smarty->assign( "loginfail", $loginfail ); $smarty->display( "mgt/login.tpl" ); ?> Code: [Select] $sql = "SELECT poster_id from phpbb_posts WHERE topic_id = ".$topic_id." "; $result = $db->sql_query($sql); //same as mysql_query $row = $db->sql_fetchrow($result); // same as mysql_fetch array. var_dump($row); With this code (i commented the query function for you) im getting Code: [Select] array 'poster_id' => string '59' (length=2) When I run this into SQL in phpmyadmin I'm getting Code: [Select] 59 56 //this is what I want I need to get all of the records, not just the first one. I have even tried using replacing the function with mysql_query and mysql_fetch_array any ideas? It's a bit late, so I may just be making a simple mistake. Thanks! Hello i am unable to find why the record is not adding into the mysql database. My connection are right. I am attaching the files. Please help me in this. [attachment deleted by admin] Thanks for reading my post. How can I update the ten rows from MYSQL Thanks in advance hi - i'm trying to update mysql databse but not working... any ideas??? Code: [Select] [php] <?php ob_start(); require_once('../xconfig.php'); if(isset ($_GET['quote'])&& $_GET['quote']!=""){ $quote_id=$_GET['quote']; mysql_select_db($database, $makeconnection); $sql_find_quote = "SELECT * FROM tbl_quote WHERE quote_id = $quote_id"; $find_quote = mysql_query($sql_find_quote, $makeconnection) or die(mysql_error()); $row = mysql_fetch_assoc($find_quote); $totalRows = mysql_num_rows($find_quote); $quote_author = $_POST['quote_author']; $quote_desc = $_POST['quote_desc']; if (isset($_POST['submitted'])&&($_POST['submitted'] == "yes")) { $register_query = "SELECT quote_desc FROM tbl_quote WHERE quote_desc='$quote_desc'"; mysql_select_db($database, $makeconnection); $register_check=mysql_query($register_query, $makeconnection); $register_found_quote = mysql_num_rows($register_check); if($register_found_quote>1){ header ("Location: quote_modify.php?error=quoteexists"e=$quote_id"); }else{ $sql_modify = "UPDATE tbl_quote SET quote_desc = '$quote_desc' quote_author = '$quote_author' WHERE quote_id = '$quote_id'"; } mysql_select_db($database, $makeconnection); $Result1 = mysql_query($sql_modify, $makeconnection) or die(mysql_error()); header ("Location: quote.php"); } } ob_flush(); ?> [/php] here's my HTML form Code: [Select] <form action="" method="post" enctype="multipart/form-data" name="form1" id="form1"> <p> <input name="quote_author" type="text" class="active-field" id="quote_author" value="<? echo $row['quote_author'];?>"/> <br /> <input name="quote_desc" type="text" class="active-field" id="quote_desc" value="<? echo $row['quote_desc'];?>" /> <br /> <input name="submitted" type="hidden" id="submitted" value="yes" /> <input name="submit" type="submit" id="submit" class="submit-button" value="modiy"/> <br /> </p> </form> [/code] Hi //open the connection $conn = mysql_connect("localhost", "techhom1_test", "pro176"); //pick the database to use mysql_select_db("testDB", $conn); //create the sql statement $sql = "INSERT INTO master_name values ('', '$firstname')"; //execute if (mysql_query($sql,$conn)){ echo "Record Added!"; } else{ echo "Somethin went wrong"; } the code above is insert code and working with out any errors but when i am submitting text into data using method below it is sending echo back Somethin went wrong.I think i am confused with the write name of the user table database is ***_test my tables are duty_number master_name in this _test user i am trying to add first name in master_name field so here is the submit code Code: [Select] <FORM ACTION=insert.php METHOD=POST> <P>text to add:<br> <input type=text name=master_name size=30> <p><input type=submit name=submit value=Insert Record></p> </FORM> My table below in Data base [code]Field Type Null Default Comments name_id smallint(5) Yes NULL name_dateaddedn datetime Yes NULL name_datemodified datetime Yes NULL firstname varchar(75) Yes NULL lastname varchar(75) Yes NULL can someone please look at the code and find the error for me Thanks Hey. So basically I am working on a simple project, I am no PHP expert, I only know a bit of the basics. This project is simply a "performance monitor" script. I have the parts to add records etc. I am now starting to tackle the next phase of the project that is to modify the records to give "infractions" or "bonus". I want to keep this simple and have the following fields on the edit form: PLAYER NAME: Dropdown List of the PLAYER_NAME column on my table called players I grabbed this code from a different thread (and edited it in an attempt to match my table). echo "Select a name: <select name='$name'>"; $query="select PLAYER_NAME from PLAYERS"; $result=mysql_query($query); while($row=mysql_fetch_array($result)){ $name=$row['PLAYER_NAME']; echo "<option value='$name'>$name</option>"; } echo "</select>"; I tried to understand it as I modified it, but aparently I misunderstood it becuase it's not working right, this gives me nothing but an empty dropdown box. Here is a screenshot of my current "players" table, so you can see the structure and what not: INFRACTION/BONUS A box to add or subtract "points". I am thinking along the lines of a number text entry with a radio button for options for either BONUS(add) or INFRACTION (subtract) NOTES Just a simple text box for comments. TIMESTAMP I will do this easily with a field on the SQL table What is wrong with the above PHP code I have for the dropdown box? Also how would I go about making this a usable form? I simply want to create new records with all of the above data on a new table I will create called "infractions". I then want to use the data from the "INFRACTION/BONUS" Field to edit the "ND_POINTS" value on the players table. I know the post is a little long, but I would appreciate any help and guidance you can offer in this project. Thanks. I have three records in this table, yet the script below only displays two records, skipping the first item. I have tried it in other fields also, and it is always skipping the first record? Code: [Select] $result = mysql_query("SELECT * FROM `content_type_ads`"); $row = mysql_fetch_array( $result ); while($row = mysql_fetch_array($result)){ echo $row['nid']. " - ". $row['field_item_id_value']; echo "<br />"; } Hi All, Please can someone help me with this bit of code. I have a mysql database with a table called 'events'. I have six fields namely 'ID, mxitID, type, message, ts, publish'. I am trying to update the field 'publish' from Yes --> No or if it is already No then back to Yes again. I have two files then main one beacon.php and publish.php Here is the code: beacon.php Code: [Select] <?php // connect to the database include('connect-db.php'); // display data in table // echo "<p><b>View All</b> | <a href='view-paginated.php?page=1'>View by Page</a></p>"; // echo "Select your Carousel: "; // get results from database $result = mysql_query("SELECT * FROM events WHERE type='beacon'") or die(mysql_error()); echo "<table border='1' cellpadding='10'>"; echo "<a href='index.php'>b Back</a><br><br>"; echo "<tr> <th>ID</th> <th>mxitID</th> <th>Type</th> <th>Message</th> <th>Timestamp</th> <th>Published</th> <th>Modify</th></tr>"; // loop through results of database query, displaying them in the table while($row = mysql_fetch_array( $result )) { // echo out the contents of each row into a table echo "<tr>"; echo '<td>' . $row['ID'] . '</td>'; echo '<td>' . $row['mxitID'] . '</td>'; echo '<td>' . $row['type'] . '</td>'; echo '<td>' . $row['message'] . '</td>'; echo '<td>' . $row['ts'] . '</td>'; echo '<td>' . $row['publish'] . '</td>'; echo '<td><a href="publish.php?id=' . $row['ID'] . '"><input name="update" type="submit" id="update" value="Update"></a></td>'; echo "</tr>"; } // close table> echo "</table>"; ?> publish.php <?php // connect to the database include('connect-db.php'); // get id value $id = $_GET['id']; echo "$id"; $sql="SELECT * FROM events WHERE type='beacon'"; $result=mysql_query($sql); $active=($result['publish']=='')?'Yes':'No'; echo "$active"; if ($active='Yes') { $active='No'; } else { $active='Yes'; } $sql = "UPDATE events SET publish='$active' WHERE ID='$id'"; $result = mysql_query($sql); // header("Location: beacon.php"); ?> I cant seem to change the value...any help would be much appreciated. Thank you in advance. MOD EDIT: code tags added. Greetings everyone! I have a form that stores data to a database. Separate from that page I would like to have another where at any given time a user can download a .csv of the most recent addition or two? If not a .csv, can they easily view the record without having to know mySQL / phpAdmin and such? Thanks! Jerry I have a form that submits a record and saves it to the database, I've got that working already, I'm trying to figure out if there is a cleaner way to delete a record with a button that gets a value from the unique key, in this case 'id' here is how the delete button looks like: // get info from table $query = "SELECT id, Title, Message FROM table_name"; $result = mysql_query($query); //displaying all data while($row = mysql_fetch_assoc($result)) { echo" <div class='status'><h3>{$row['Title']} <br></h3>" . " <h5>{$row['Message']} <br><br></h5>"; $id = $row['id']; //trying to get unique key from database //delete button echo "</div> <form action='delete.php' method='post' /> <input type='hidden' name='delete' value='yes' /> <input type='hidden' name='id' value='$id' /> <input type='submit' value='remove' /></form>"; } As you can see, i'm trying to give $id a unique value but for some reason i'm not getting it. The delete.php code looks like this: if (isset($_POST['delete']))// check if delete was clicked { $query = "DELETE FROM table_name WHERE id='$id'"; echo "$id Deleted successfully"; } elseif(!mysql_query($query, $db_server)) { echo "DELETE failed: $query<br />" . myql_error() . "<br /><br />"; } mysql_close(); I'm new to php and still learning so, if you think there are other ways to do this, please let me know, the button won't do anything to the data. Thanks in advance Hey Everyone, I want to start out by saying thanks in advance for reading this. Since I started working with the XAMPP package this community has been a great resource, though this is my first post. most of my work has been modifying existing stuff in our network, this is my first project from scratch. I am working on an access control project where I am storing site names and RFID tags in a table, and using PHP to check for existing records. Basically, I want to submit 2 credentials from a host (site and RFID), check if they exist together in the table, if so return TRUE or 1, if not return FALSE or 0. I am new to both PHP and MySQL (although I took a course years ago) so I am looking here for help. On this server I have XAMPP installed and everything I need running. I have a table and created a few records for testing. My current trouble is getting PHP to return the proper values for the SQL query. The SQL query works fine, I think - it returns the number of rows that match and that record. I'm not sure this is the result I need to be able to deal with the way I want. Using other resources my current PHP statement looks like this: Code: [Select] if(mysql_num_rows(mysql_query("SELECT * FROM `users` WHERE 'site_name' LIKE 'berland' AND 'card_id' LIKE '290093C84E' LIMIT 0 , 30"))>0){echo '1';} else {echo '0';} So, my table has the entry as noted in this query above. Final one will be dynamic where the host will be sending those values - I will likely need help with that as well, but small steps first.;-) Anyway, I was playing around with the end statement >0{echo '1';} but wasn't able to make it do what I want. Any help is appreciated. Thank you. Aaron Dear all, I would like to find the total number of individual record in MySQL with php. For example: I have different department name stored in a column in MySQL. I would like to find out the total number of each department. But I do not know the names of the department How can I do it?? Counting the total of each department without knowing their names Thanks! I have a MySQL database with each record of a person who has registered for an event, I am displaying the information on a web page for a user, but he wants to be able to print out all the records in alphabetical order by last name, first name later on so he will have a hard copy of each person who has registered at the table when they arrive. How can I write each record to a Txt file that he can print out later that will be formated with the record contents along with each fields definition (Ex. Last Name - Smith, First Name - John, etc)? Here is what I am trying to accomplish: I have a students table with a studentID I also have a notes table and a sched table with studentID The sched table is working as planned where if the student is scheduled for more than one time he is displayed twice. However if there are multiple notes per student the student is display for each individual note where I would like only the most current note to be displayed Here is what the output is: 1- 10:30:00 - 10:50:00 student3 Three FST Teacher One Special1 One Writing Ratios 09/10 2- 10:30:00 - 10:50:00 student3 Three FST Teacher One Special1 One Needs to work on fractions and decimals 09/10 3- 13:00:00 - 14:00:00 student3 Three FST Teacher One Special1 One Writing Ratios 09/10 4- 13:00:00 - 14:00:00 student3 Three FST Teacher One Special1 One Needs to work on fractions and decimals 09/10 As you can see I have two notes and two schedule times for this student. what I want it to display is only line 1 & 3. which is the newest note in the system. Below is my code that I am using. Any help would be greatly appreciated. Code: [Select] <?php $result = mysql_query("SELECT * FROM students LEFT JOIN teachers ON students.teacherId = teachers.teacherId LEFT JOIN course ON students.courseId = course.courseId LEFT JOIN specialEd ON students.specialId = specialEd.specialId LEFT JOIN sched ON students.studentId = sched.studentId ORDER BY start "); echo "<table>"; while ($row = mysql_fetch_array($result)){ $id = "?id=" . $row['studentId']; echo "<tr>"; echo "<td>" . $row['start'] . " - " . $row['stop'] . "</td>"; echo "<td>" . "<a href='student.php$id'>" . $row['fName'] . " " . $row['lName'] . "</td>"; echo "<td>" . $row['courseName'] . "</td>"; echo "<td>" . $row['teachers_fName'] . " " . $row['teachers_lName'] . "</td>"; echo "<td>" . $row['special_fName'] . " " . $row['special_lName'] . "</td>"; echo "<td>" . $row['note'] . "</td>"; echo "<td>" . date("m/d", strtotime($row['started'])) . "</td>"; echo "</tr>"; } echo "</table>"; ?> I am trying to set up a item entry page form.png: Upon submission it shows unsuccessful even though I have checked the fields on mysql table and seem to be good am I missing something? Code: [Select] <form action="" method="post" enctype="multipart/form-data" name="Product_Entry"> <TABLE> <TR> <TD>Product ID</TD><TD><input name="SKU_ProductID" value="<?php if (isset($_post['SKU_ProductID'])) echo $_POST['SKU_ProductID']; ?>" type="text" size="11" maxlength="11" /></TD> </TR> <TR> <TD>Merchant SKU ID</TD><TD><input name="SKU_MerchSKUID" value="<?php if (isset($_post['SKU_MerchSKUID'])) echo $_POST['SKU_MerchSKUID']; ?>" type="text" size="18" maxlength="30" /></TD> </TR> <TR> <TD>Game Title</TD><TD><input name="Game_Title" value="<?php if (isset($_post['Game_Title'])) echo $_POST['Game_Title']; ?>" type="text" size="40" maxlength="40" /></TD> </TR> <TR> <TD>Platform</TD><TD><input name="Platform" value="<?php if (isset($_post['Platform'])) echo $_POST['Platform']; ?>" type="text" size="20" maxlength="20" /></TD> </TR> <TR> <TD>Genre</TD><TD><input name="Genre" value="<?php if (isset($_post['Genre'])) echo $_POST['Genre']; ?>" type="text" size="11" maxlength="11" /></TD> </TR> <TR> <TD>Weight</TD><TD><input name="Weight" value="<?php if (isset($_post['Weight'])) echo $_POST['Weight']; ?>" type="text" size="7" maxlength="7" /></TD> </TR> <TR> <TD>Supplier</TD><TD><input name="Supplier" Value="<?php if (isset($_post['Supplier'])) echo $_POST['Supplier']; ?>" type="text" size="25" maxlength="25" /></TD> </TR> <TR> <TD>Suppliers Price</TD><TD><input name="Supplier_Price" value="<?php if (isset($_post['Supplier_Price'])) echo $_POST['Supplier_Price']; ?>" type="text" size="10" maxlength="12" /></TD> </TR> <TR> <TD>Cashback</TD><TD><input name="Cashback" value="<?php if (isset($_post['Cashback'])) echo $_POST['Cashback']; ?>" type="text" size="6" maxlength="8" /></TD> </TR> <TR> <TD>Cashback Amount</TD><TD><input name="Cashback_Amount" value="<?php if (isset($_post['Cashback_Amount'])) echo $_POST['Cashback_Amount']; ?>" type="text" size="7" maxlength="11" /></TD> </TR> <TR> <TD><input type="hidden" name="submitted" value="true"/></TD><TD><input name="Submit" type="submit" value="Add_Product" /></TD> </TR></form></TABLE> <?php # Product Entry $page_title = 'Product Entry'; if (isset($_POST['Submit'])) { $errors = array(); if (empty($_POST['SKU_ProductID'])) { $errors[] = 'Please enter Product ID.'; } else { $sid = trim($_POST['SKU_ProductID']); } if (empty($_POST['SKU_MerchSKUID'])) { $errors[] = 'Please enter Merchant SKU.'; } else { $mid = trim($_POST['SKU_MerchSKUID']); } if (empty($_POST['Game_Title'])) { $errors[] = 'Please enter Game Title.'; } else { $gt = trim($_POST['Game_Title']); } if (empty($_POST['Platform'])) { $errors[] = 'Please enter Platform.'; } else { $pl = trim($_POST['Platform']); } if (empty($_POST['Genre'])) { $errors[] = 'Please enter Genre.'; } else { $ge = trim($_POST['Genre']); } if (empty($_POST['Weight'])) { $errors[] = 'Please enter Weight.'; } else { $we = trim($_POST['Weight']); } if (empty($_POST['Supplier'])) { $errors[] = 'Please enter Supplier.'; } else { $sup = trim($_POST['Supplier']); } if (empty($_POST['Supplier_Price'])) { $errors[] = 'Please enter Supplier Price.'; } else { $sp = trim($_POST['Supplier_Price']); } if (empty($_POST['Cashback'])) { $errors[] = 'Please enter Cashback %.'; } else { $cb = trim($_POST['Cashback']); } if (empty($_POST['Cashback_Amount'])) { $errors[] = 'Please enter Cashback Amount.'; } else { $cba = trim($_POST['Cashback_Amount']); } if (empty($errors)) { require_once ('connect.php'); [b]$q = "INSERT INTO `Products` (`SKU_ProductID`, `SKU_MerchSKUID`, `Game_Title`, `Platform`, `Genre`, `Weight`, `Supplier`, `Supplier_Price`, `Cashback`, `Cashback_Amount`) VALUES ('$sid', '$mid', '$gt', '$pl', '$ge', '$we', '$sup', '$sp', '$cb', '$cba')"; $r = @mysql_query ($dbc, $q); if ($r) { // If it ran OK. // Print a message: echo '<h1>Thank you!</h1> <p>Product Inserted!</p><p><br /></p>'; } else { // If it did not run OK. // Public message: echo '<h1>System Error</h1> <p class="error">You could not be registered due to a system error. We apologize for any inconvenience.</p>'; // Debugging message: echo '<p>' . mysqli_error($dbc) . '<br /><br />Query: ' . $q . '</p>'; } // End of if ($r) IF. mysqli_close($dbc); // Close the database connection.[/b] // Include the footer and quit the script: include ('includes/footer.html'); exit(); } else { echo '<H1>Error!</H1> <p class="error">The Following error(s) occurred:<br />'; foreach ($errors as $msg) { echo " - $msg<br />\n"; } echo '</p><p>Please try again.</p><p><br /></p>'; } } ?> If there is anything else needed let me know I have 2 files; Newfault.php and thankyou.php 1) Data is entered into a form in Newfault.php 2) The data from this form is retieved in thankyou.php and is then inserted into a table called "Calls" Problem: My entered record is being added to my database OK, but it is also adding a blank record for some reason and I can't work out why. Can anyone help? This is for my uni assignment. Thanks, Ladykudos |