PHP - Trying To Require A File In A Laterally Located Directory Using Relative Paths

I have a form that lets a user upload an image, aswell as another file. I want the image to go into the images directory, and the pdf file to go into the PDF directory once uploaded. The names of the files will then be uploaded to the database.

At the moment I can get the image to upload to the database and directory, but the PDF is only uploading the name to the database, it is not going into the PDF directory aswell. I'm not sure if there is a way you can do this, I am trying to use "move_uploaded_file()" to physically move the files but not sure if you can use it twice.

here is my code, if you can point anything out or where im going wrong that would be great.
<?php

include "include/conn.php";

include "include/session.php";
?>

<?php


// Check to see if the type of file uploaded is a valid image type
function is_valid_type($file)
{
       
        $valid_types = array("image/jpg", "image/jpeg", "image/bmp", "image/gif");

        if (in_array($file['type'], $valid_types))
                return 1;
        return 0;
}




function showContents($array)
{
        echo "<pre>";
        print_r($array);
        echo "</pre>";
}

//Target path for image
$TARGET_PATH = dirname(__FILE__) . "/images/";

//Target path for PDF files
$PDF_TARGET_PATH = dirname(_FILE_) . "/PDF/";

// Get POST variables

$image = $_FILES['image'];

$pdf = $_FILES['pdf'];

$date= date("Y-m-d ");
$time = date("H:i:s");

$title = $_POST['title'];
$title_escape = mysql_escape_string($title);
$title_slashes = stripslashes($title_escape);

$content = $_POST['content'];

$image['name'] = mysql_real_escape_string($image['name']);

$pdf['name'] = mysql_real_escape_string($pdf['name']);


//image path
$TARGET_PATH .= $image['name'];

//PDF path
$PDF_TARGET_PATH .= $pdf['file_name'];

// Make sure all the fields from the form have inputs
if ($image['name'] == "" )
{
        $_SESSION['error'] = "All fields are required";
        header("Location: add_media.php");
        exit;
}

// Verify file is an image
if (!is_valid_type($image))
{
        $_SESSION['error'] = "You must upload a jpeg, gif, or bmp";
        header("Location: add_media.php");
        exit;
}



// move file into the directory and the path name into the database / along with the rest of the form fields
if (move_uploaded_file($image['tmp_name'], $TARGET_PATH))
{
        if(move_uploaded_file($pdf['tmp_name'], $PDF_TARGET_PATH))
{
$sql = "INSERT INTO media_table(title, text, time, date, image, PDF) VALUES ('" . $title_slashes . "','" . $content . "', '" . $time . "', '" . $date . "', '" . $image['name'] . "', '" . $pdf['name'] . "')";
        $result = mysql_query($sql) or die (mysql_error());
        header("Location: add_media.php");
        exit;
}
else
{
print "did not upload";
}
}
else
{
        
        $_SESSION['error'] = "Could not upload file.  Check read/write persmissions on the directory";
     
        exit;
}
?>

Hello.

The title is a little confusing, but:

What I am trying to do is build a simple CMS where all requests are routed through the root index.php file.

This file will be where all constants are defined and importantly where the database connection is estabilished.

There will be a folder where template files will reside and, based on the URI, a template file will be included into the root index.php file.

Here's some code:

Code: [Select]
<?php

//Sets the database connection and defines some constants
require ( "includes/config.php" );

//Where I will place the core functions of the CMS, one being the navigation builder
require ( "includes/functions.php" );

//Home page template file
require ( "views/cms/index.php" );

?>

So as you can see, I want to be able to call the navigation builder function, called "getMenuItems();", from the home page template.

However, I get the following error:

Code: [Select]
Fatal error: Call to undefined function getMenuItems() in C:\wamp\www\cms\views\cms\index.php on line 3
How can I access functions that have been defined in the "includes/functions.php" file, from the required template file "views/cms/index.php"?

If you need anything else explaining then please ask. If this has already been posted, I apologise in advance! I have searched Google and the forums but nothing turned up.

Chris

my directory on my mamp server looks like this;

root/website/index.php

I also have some files in a folder like this

root/website/pages/files.php

My include code is this
include("functions.php");

When I try to include a file from the 'website' folder from a page in the 'pages' folder. It gives me errors that look like this.

Warning: include(functions.php) [function.include]: failed to open stream: No such file or directory in /website/pages/contact.php on line 2

Warning: include() [function.include]: Failed opening 'functions.php' for inclusion (include_path='.:/Applications/MAMP/bin/php5.3/lib/php') in /Applications/MAMP/htdocs/website/pages/contact.php on line 2



That's what it looks like.. I can't get it working.

trying to use a require but not working properly

Fatal error: require() [function.require]: Failed opening required 'get_extra.php?id=1' (include_path='.')

first thing set on page is.. page is profile.php?id=1
$userid = $_GET['id'];

code is:require "get_extra.php?id=$userid";

what can i do to fix this?

thanks

I havent included the whole title as it wouldnt let me but I was wondering if someone could help me on this?

I know this is possible as torrentflux caters for this but unsure of where to start.

I dont want to allow file or directory uploads or creation in my /etc/php.ini file (this is turned off).

Yet then torrentflux allows me to link a torrent from an external source (using legal downloads of course  ) but then it uploads it on my server and creates folders on a per user basis.

How is this possible can someone give me some pointers please?

I look forward to any replies,
Jeremy.

Given a directory - folder1/subfolder1, I would like to loop through all subdirectories under the given directory and return the file path relative to the given directory.

Example:
Code: [Select]
Given Directory
    FolderA
    FolderB
        SubFolderA
        SubFolderB
             SubSubFolderA
                  File1
    FolderC

the file path for File1 should be FolderB/SubFolderB/SubSubFolderA/

Any ideas?

Why does this code:
Code: [Select]
require_once "../../media/php/classes/Mysql.inc.php";
Work when I go to:
http://mysite.com/API/v1/index.php

But when I go to:
http://mysite.com/index.php

it doesn't work.

The require is being called from another class, which I call from the two pages above. The class loads, but in the second link, I get failed to open stream: No such file or directory but the first one works fine. What would cause this?

could this be an htaccess thing?

htaccess:
Code: [Select]
Options +FollowSymlinks
RewriteEngine On
RewriteBase /
RewriteCond %{REQUEST_FILENAME} !-f
RewriteCond %{REQUEST_FILENAME} !-d
RewriteCond %{REQUEST_FILENAME}.php -f
RewriteRule ^(.+)$ /$1.php [L,QSA]

In my script, I'm trying to create a file with the name of a variable in a different directory.
My code is:
Code: [Select]
$handle = fopen("cheese/" . $page . ".html", "w");Output: Warning: fopen(cheese/test.html) [function.fopen]: failed to open stream: No such file or directory in /home/a5938041/public_html/newfile/newpage.php on line 6
What's happening here? (sorry I'm a total noob.)

I'm in the middle of making my own CMS system, where a user can create a page online via a text editor, I know how to create and save the file, but to make the process easier I would like to a function where a user can click a button find a list of files and folders, pick the folder location to save a new file to.

Instead of having to type something like this /commonPages/aboutUs/

with the file name being test.php

What would be the easiest way to do this?

I have just been looking at opendir() and my first thought was to use <input type="file" />, but then I remember that was only for inputting a particular file name, which would be useful for renaming a file at a later date.

For example, if we wanted to change test.php to something more meaningful ie history.php

Hi,   I have this code

<?php
 // Must include this
include("geoiploc.php");

function getYJLINKS($default_font_family,$yj_copyrightear,$yj_templatename,$show_tools,$show_fres,$show_rtlc,$validators_off,$totop_off){
	
	$allLinks = array();

	if((function_exists('toolbox_urls') && $show_tools == 1) || $validators_off == 1 || $totop_off == 1){
		echo '<div class="validators">';
		if($validators_off == 1){
			$allLinks[] ='<a href="http://jigsaw.w3.org/css-validator/check/referer?profile=css3" target="_blank" title="CSS Validity">CSS Valid</a>';
			$allLinks[] ='<a href="http://validator.w3.org/check/referer" target="_blank" title="XHTML Validity">XHTML Valid</a>';
		}
		if($totop_off == 1){
			$allLinks[] ='<a class="yjscroll" href="#stylef'.$default_font_family.'">Top</a>';
		}
		if (function_exists('toolbox_urls') && $show_tools == 1):
		global $font_size;
		global $font_direction;
			if ($show_fres == 1):
				$allLinks[] = '<a id="fontSizePlus" class="fs" href="javascript:;" rel="nofollow">+</a>';
				$allLinks[] = '<a id="fontSizeMinus"  class="fs" href="javascript:;" rel="nofollow">-</a>';
				$allLinks[] = '<a id="fontSizeReset"  class="fs" href="javascript:;" rel="nofollow">reset</a>';
			endif;
			if ($show_rtlc == 1):
				$allLinks[] = '<a class="tdir" href="'.$font_direction[1].'" rel="nofollow">RTL</a>';
				$allLinks[] = '<a class="tdir" href="'.$font_direction[2].'" rel="nofollow">LTR</a>';
			endif;
		endif;
		echo implode(' | ',$allLinks);
		echo '</div>';
   }
// loading this from a database
    $ip = $_SERVER["REMOTE_ADDR"];

// listing Country Flags Images
    $dir = 'images/flags';
    $file_display = array('png');
         if (file_exists ($dir) == false) {
    echo 'Directory \'', $dir, '\' not found!';
    }
    else{
         $dir_contents = scandir($dir);
         foreach($dir_contents as $file) {
         $file_type = strtolower(end(explode('.', $file)));
    If($file !== '.' && $file !== '..' && in_array($file_type, $file_display) == true)
    if($file == '..' || $file == '.') {
    continue;
    }
         $code = strtolower(getCountryFromIP($ip, "code"));
    echo '<div class="yjsgcp">Palana.it &reg; 1994 - '.$yj_copyrightear.' :: Tutti i diritti riservati :: Realizzazione Palana.it &boxv;&boxv; Utente rilevato: IP: '. $ip . ', '.getCountryFromIP($ip, " NamE ").' ('.getCountryFromIP($ip, "code").'-'.getCountryFromIP($ip, "AbBr").') ';
    echo '<img src="', $dir, '/', $code, '.png" /> </div>';
        }
    }
}
?>

The problem, as we see (http://www.palana.it), is that code printed the Italian flag but many times there are images in the directory, that is over 204. See bottom of the page. How can I fix the code to get ONE display?

hey guys im tyring to read my directory (whole of the web server)...i want to be able to put the file name and root into an array...im just wanting to know whats the best function i need to do this please?...thank you

Hey, I dont know whats wrong but i was hoping someone could take a look at the code and provide some errors that maybe causing this script not to work. I want it to display all the .jpg pictures in thumbnails, it currently does not even get the pictures.

code:

<?php
$pic_listing = mysql_query("SELECT * FROM toplist WHERE id='". $id ."'") or die(mysql_error()); 
    while($serverpic = mysql_fetch_array($pic_listing)) 

{

$servername = $serverpic["servername"];

}
$directory = "images/serverpic/" . $servername . "";
$images = glob("" . $directory . "*.jpg");
if(empty($images)) { 
?>
<div class="highslide-gallery">
<?php
foreach($images as $image) 
{
?>
<a href="images/serverpic/<?php echo $servername . "/" . $image; ?>" class="highslide" onclick="return hs.expand(this)">

<img src="images/serverpic/<?php echo $servername . "/" . $image; ?>" alt="Highslide JS" width="100" height="100" title="Click to enlarge" />
</a>
<div class="highslide-caption">
<?php } ?>
</div>

</div> 
<?php } ?>

                                         $file="../myclients/clients/".$company_name."/Download/".$file_name;
                $size = filesize($path); // not working

i try with  function  also

       function formatbytes($file, $type) 
    { 
        switch($type){ 
            case "KB": 
                $filesize = filesize($file) * .0009765625; // bytes to KB 
            break; 
            case "MB": 
                $filesize = (filesize($file) * .0009765625) * .0009765625; // bytes to MB 
            break; 
            case "GB": 
                $filesize = ((filesize($file) * .0009765625) * .0009765625) * .0009765625; // bytes to GB 
            break; 
        } 
        if($filesize <= 0){ 
            return $filesize = 'unknown file size';} 
        else{return round($filesize, 2).' '.$type;} 
    } 

echo formatbytes($file, "KB");



uploaded file size is 488 kb   

but it showing   "unknown file size"

please help me.

file_get_contents() has suddenly stopped working for me. I keep getting this error:
Code: [Select]
Warning: file_get_contents(/Users/ttocskcaj/MineCMS/public/js/jquery.js ) [<a href='function.file-get-contents'>function.file-get-contents</a>]: failed to open stream: No such file or directory in /Users/ttocskcaj/MineCMS/controllers/m.controller.php on line 44
The file(s) definitely exist, I can use nano to open them, and permissions are 777 on all the files. The lampp error log has nothing. Not even a No such file or directory error as you'd expect.

Any ideas what's going on?

After a user on my site deletes their account I want their profile picture to be deleted from my images folder.   I was testing the unlink function on my index.php file and it is failing.

Here is the error: Warning: unlink(/assets/img/avatars/users/jasongordon.png): No such file or directory in /home/www-data/big.com/index.php on line 86

My code was just: unlink('/assets/img/avatars/users/jasongordon.png');

I'm not sure why this fails because my file does exist.