PHP - Simple Php Mysql Select Not Working

I'm experimenting out premade codes and trying to make them some how work the way I want to. This is "my" image uploader. For the uploader is suppose to find the image AND the code stored in mysql, but it doesn't seem to find it. any problem?
<?php 
$link = mysql_connect("localhost", "mcd", "whatanicepassword");
mysql_select_db("mcd", $link);


if (!isset($_POST["code"])) 
{
die ("Error: Not all fields complete");
}

$limit_size=5120;
$target = "skin/"; 
$target = $target . basename( $_FILES['uploaded']['name']); 
$ok=1; 
$filelol = $_FILES['uploaded']['name'];
$file_size=$_FILES['uploaded']['size'];
$filecheck = "skin/".$filelol;

//This is our size condition 

 if ($file_size >= $limit_size)
{ 
echo "Your file is too large.<br>"; 
$ok=0; 
} 
 
if (file_exists($filecheck))
{

} else {echo $filelol." does not exist in the database. Please upload at the main site.<br>";
$ok=0;}

// username and password sent from Form
$uploaded=mysql_real_escape_string($_POST['uploaded']); 
$code=mysql_real_escape_string($_POST['code']); 
$checkquery = mysql_query("SELECT * FROM user_list WHERE uploaded = '$uploaded' AND code = '$code'") or die("Error : " . mysql_error());

$num_rows=mysql_num_rows($checkquery);
if ($num_rows < 1 ) { 
          echo 'File not found in MySQL<br><br><br>';
          $ok=0;
}    
else 
{echo 'YES!';}


//This is our limit file type condition 
if (($_FILES["uploaded"]["type"] != "image/png"))
{
echo "You may only upload PNG files.<br>";
$ok=0;
} 

if ($ok==0) 
 { 
 Echo "Sorry your file was not uploaded<br>"; 
 } 
 //If everything is ok we try to upload it 
 else 
 { 
 if(move_uploaded_file($_FILES['uploaded']['tmp_name'], $target)) 
 { 
 echo "The file ".$filelol." has been uploaded"; 
 } 
 else 
 { 
 echo "Sorry, there was a problem uploading your file."; 
 } 
 } 
 ?>

Hi there,

I'm having a problem with updating a record with an UPDATE mysql query and then following that query with a SELECT query to get those values just updated.

This is what I'm trying to do...I'd like a member to be able to complete a recommended task and upon doing so, go to a page in their back office where they can check off that task as "Completed".  This completed task would be recorded in their member record in our database so that when they return to this list, it will remain as "Completed".  I'm providing the member with a submit button that will call the same page and then update depending on which task is clicked as complete.

Here is my code:
Code: [Select]
$memberid = $_SESSION['member'];

// Check if form has been submitted
if(isset($_POST['task_done']) && $_POST['task_submit'] == 'submitted')
{
  $taskvalue = $_POST['task_value'];
  $query = "UPDATE membertable SET $taskvalue = 'done' WHERE id = $memberid";
  $result = mysqli_query($dbc, $query);
}

$query ="SELECT task1, task2, task3 FROM membertable WHERE id = $memberid";
$result = mysqli_query($dbc, $query);
$row = mysqli_fetch_array($result, MYSQLI_ASSOC);

$_SESSION['task1'] = $row['task1'];
$_SESSION['task2'] = $row['task2'];
$_SESSION['task3'] = $row['task3'];
?>
<h4>Task List</h4>
<table>

  <form action="" method="post">
    <tr>
      <td>Task 1</td>
      <td><?php if($_SESSION['task1'] == 'done') {echo '<div>Completed</div>';} else{ echo '<input type="submit" name="task_done" value="Mark As Completed" />';} ?></td>
    </tr>
    <input type="hidden" name="task_value" value="task1" />
    <input type="hidden" name="task_submit" value="submitted" />
  </form>

  <form action="" method="post">
    <tr>
      <td>Task 1</td>
      <td><?php if($_SESSION['task1'] == 'done') {echo '<div>Completed</div>';} else{ echo '<input type="submit" name="task_done" value="Mark As Completed" />';} ?></td>
    </tr>
    <input type="hidden" name="task_value" value="task2" />
    <input type="hidden" name="task_submit" value="submitted" />
  </form>

  <form action="" method="post">
    <tr>
      <td>Task 1</td>
      <td><?php if($_SESSION['task1'] == 'done') {echo '<div>Completed</div>';} else{ echo '<input type="submit" name="task_done" value="Mark As Completed" />';} ?></td>
    </tr>
    <input type="hidden" name="task_value" value="task3" />
    <input type="hidden" name="task_submit" value="submitted" />
  </form>

</table>

The problem that I am having is that the database is not updated with the value "done" but after submission, the screen displays "Completed" instead of "Mark As Completed".  So the value is being picked up as "done", but that is why I have the SELECT after the UPDATES, so that there is always a current value for whether a task is done or not.  Then I refresh and the screen returns the button to Mark As Complete.  Also, when I try marking all three tasks as, sometimes all three are updated, sometimes only one or two and again, I leave the page or refresh and the "Marked As Completed" buttons come back.  Bizarre.  If anyone can tell me where my logic is going wrong, I would appreciate it.

I had this working, but when I try and get fancy and use AJAX the data doesn't display. I think this is a PHP problem though.

My code for the select form including AJAX code

Code: [Select]
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Strict//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-strict.dtd">
<html xmlns="http://www.w3.org/1999/xhtml" xml:lang="en-GB">
<head>
<title>AJAX Example</title>
<link rel="stylesheet" type="text/css" href="Form.css" media="screen" />
<script type="text/javascript" src="http://ajax.googleapis.com/ajax/libs/jquery/1.4.2/jquery.min.js"></script>
<script type="text/javascript">
 $(document).ready(function(){
 $("tr:odd").addClass("odd");
 });
</script>
<script type="text/javascript">
function showPlayers(str)
{
var xmlhttp;
if (str=="")
  {
  document.getElementById("DataDisplay").innerHTML="";
  return;
  }
if (window.XMLHttpRequest)
  {// code for IE7+, Firefox, Chrome, Opera, Safari
  xmlhttp=new XMLHttpRequest();
else
  {// code for IE6, IE5
  }
  xmlhttp=new ActiveXObject("Microsoft.XMLHTTP");
  }
xmlhttp.onreadystatechange=function()
  {
  if (xmlhttp.readyState==4 && xmlhttp.status==200)
    {
    document.getElementById("DataDisplay").innerHTML=xmlhttp.responseText;
    }
  }
xmlhttp.open("GET","Query.php?category_id="+str,true);
xmlhttp.send();
}
</script>
        </head>

<body>

<h1">AJAX Example</h1>

<?php
#connect to MySQL
$conn = @mysql_connect( "localhost","username","pw")
or die( "You did not successfully connect to the DB!" );

#select the specified database
$rs = @mysql_SELECT_DB ("MyDB", $conn )
or die ( "Error connecting to the database test!");
?>
<form name="sports" id="sports">
<legend>Select a Sport</legend>
<select name="category_id" onChange="showPlayers(this.value)">
<option value="">Select a Sport:</option>
<?php
$sql = "SELECT category_id, sport FROM sports ".
"ORDER BY sport";

$rs = mysql_query($sql);

while($row = mysql_fetch_array($rs))
{
  echo "<option value=\"".$row['category_id']."\">".$row['sport']."</option>\n  ";
}
?>
</select>

</form>
<br />
<div id="DataDisplay"></div>

</body>
</html>


             
                       
 
Query.php


<?php
#get the id
$id=$_GET["category_id"];

#connect to MySQL
$conn = @mysql_connect( "localhost","username","pw")
or die( "Error connecting to MySQL" );

#select the specified database
$rs = @mysql_SELECT_DB ("MyDB", $conn )
or die ( "Could not select that particular Database");
#$id="category_id";
#create the query
$sql ="SELECT *
FROM sports
INNER JOIN players ON sports.category_id = players.category_id
WHERE players.category_id = '".$id."'";


echo $sql;

#execute the query
$rs = mysql_query($sql,$conn);
#start the table code
echo "<table><tr><th>Category ID</th><th>Sport</th><th>First Name</th><th>Last Name</th></tr>";
#write the data
while( $row = mysql_fetch_array( $rs) )
{
echo ("<tr><td>");
echo ($row["category_id"] );
echo ("</td>");
echo ("<td>");
echo ($row["sport"]);
echo ("</td>");

echo ("<td>");
echo ($row["first_name"]);
echo ("</td>");

echo ("<td>");
echo ($row["last_name"]);
echo ("</td></tr>");
}
echo "</tr></table>";
mysql_close($conn);
?>


I think the problem is either with this part in the AJAX
Code: [Select]
xmlhttp.open("GET","Query.php?category_id="+str,true);

or most likely in my Query.php code

when I wasn't using AJAX and using POST it worked fine, but adding the AJAX stuff and GET it doesn't work.

When I echo out the SQL the result is

Code: [Select]
SELECT * FROM sports INNER JOIN players ON sports.category_id = players.category_id WHERE players.category_id = ''

so the category_id is not being selected properly and that is the primary key/foreign key in the MySQL table which connects the JOIN.

Hello. i am writing an API for lua... that sends POST requests to a php script. this php script is malfunctioning. below is the code and error.

Hey Again;

trying to have the code select the top 5 players bases on exper field in the DB

'SELECT * from players WHERE exper = '';