Learn VBA & Macros in 1 Week!

PHP - Object Method Returns By Reference

Full Excel VBA Course - Beginner to Expert

Object Method Returns By Reference	View Content

Hi all,

Why when i set my method to returns by reference its giving me a notice that only variables should return by reference while where is not set to return by reference it don't.

Fro example:

interface i
{
function &m();
}

class a implements i
{
public function &m()
{
return $v;
}
}

$v = new a();
$v->m();

So i just return empty $v. Is this a good practice or should i just ignore the notice

Full Excel VBA Course - Beginner to Expert

Method Returns Unexpected Result

Similar Tutorials

View Content

Why does this return null rather than 'john must write the book'?
Code: [Select]
<?
abstract class User {
protected $name;
protected $role;

function __construct($name,$role){
$this->name = $name;
$this->role = $role;
}

abstract function run_errand();
}

class Author extends User {
public function run_errand(){
echo $this->name . "must write the book";
}
}

class Editor extends User {
public function run_errand(){
echo $this->name . "must edit the book";
}
}

class Boss {
private $users = array();

public function review(User $user){
$this->user[] = $user;
}

public function delegate(){
if(count($this->users)){
foreach($this->users as $user){
if($user->role == "author"){
echo $user->run_errand();
}
}
}
}
}

//client code
$boss = new Boss();
$boss->review(new Author('John','author'));
var_dump($boss->delegate()); //returns null
?>

Method Doesn't Return An Array, It Returns Nothing.

Similar Tutorials

View Content

I've done pretty much everything I can come up with.
The method itself works fine, if I print_r(); just before returning it, it successfully returns the array.
But once returned, it's empty.
Heres my code:

Code: [Select]
<?php
include_once $_SERVER['DOCUMENT_ROOT'] . "/includes/class_database.php";
include_once $_SERVER['DOCUMENT_ROOT'] . "/includes/values.php";

?>

<?php

class User {

    private $database;

    public    function __construct(MySqlDatabase $database) { //Type Hinting
    $this->database = $database;
}

    public function hash_password($password) {
        $result = hash(sha512, $password . SUOLA);
        return $result;
}

    public function find_all() {
    $result = $this->database->db_query("SELECT * FROM users");
    $final = mysqli_fetch_array($result);
    return $final;
}

    public function find_by_id($id=1) {
    $result = $this->database->db_query("SELECT * FROM users WHERE id={$id}");
    $final = mysqli_fetch_array($result);
    return $final;
}

    public function check_required($array) { // this method gets called first
    if (empty($array['username']) || empty($array['first_name'])
        || empty($array['last_name']) || empty($array['password'])
        || empty($array['email']) || empty($array['secret_question'])
        || empty($array['password2']) || empty($array['secret_answer'])
        || !($array['email'] === $array['email2'])
        || !($array['password'] === $array['password2'])) {
        die("Fill required fields!" . "<br />"
            . "<a href='javascript:history.go(-1)'>Go back</a>");

        } else {
            $this->database->array_query_prep($array); // it then continues to the next method automatically
        }

    }

    public function create_user($array) {
    $date = date('d-m-Y H:i:s');

    $sql = "INSERT INTO users (username, first_name, ";
    $sql .= "last_name, password, email, secret_question, ";
    $sql .= "secret_answer, create_time) VALUES ";
    $sql .= "('{$array['username']}', '{$array['first_name']}', '{$array['last_name']}', ";
    $sql .= "'{$array['password']}', '{$array['email']}', '{$array['secret_question']}', '{$array['secret_answer']}', ";
    $sql .= "'{$date}');";

    $this->database->db_query($sql);
    }
}
?> Code: [Select]
<?php
include_once $_SERVER['DOCUMENT_ROOT'] . "/includes/values.php";
include_once $_SERVER['DOCUMENT_ROOT'] . "/includes/class_user.php";
?>

<?php
class MySqlDatabase extends MySQLi {

    function __construct() {
        //Check if constants are missing
        if (!defined("DB_USERNAME") || !defined("DB_SERVER") ||
            !defined("DB_PASSWORD") || !defined("DB_NAME")) {
            die("One or more of the database constants are missing!");
            }

        //Establish connection if constants are present using the parent class
        parent::__construct(DB_SERVER, DB_USERNAME, DB_PASSWORD, DB_NAME);

        //Echo error message if connection has failed
        if ($this->connect_errno) {
            die("Database connection has failed: " . $this->connect_errno);
            }
    }

    public function db_query($sql) {
    $result = $this->query($sql);
        if (!$result) {
            die("Database query failed: " . $this->errno);
        }
}

    public function array_query_prep($array) { // continues to this method
    $result = array_map(array($this, 'real_escape_string'), $array);
        if (!$result) {
            die("Preparing query failed: " . $this->errno);
        }
// if i print_r here, it returns the array as it should
    return $result;
}
}
?> Code: [Select]
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<link rel="stylesheet" type="text/css" href="../stylesheets/main.css"/>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
<title>Untitled Document</title>
</head>
<body class="main_body">
<div id="container">
<div id="header">
<div id="top">
<div id="login">
<form action="" method="post" target="/login/">
<label for="username">Username:</label><br />
<input name="username" type="text" class="text" maxlength="20" /><br />
<label for="password">Password:</label><br />
<input name="password" type="password" class="text" maxlength="30" /><br />
<input name="submit" type="submit" class="loginbtn" value="Login" /></form>
</div>
</div>
<div>
<h1>Welcome to _________ website!</h1>
</div>

<?php
include_once $_SERVER['DOCUMENT_ROOT'] . "/includes/values.php";
include_once $_SERVER['DOCUMENT_ROOT'] . "/includes/functions.php";
include_once $_SERVER['DOCUMENT_ROOT'] . "/includes/class_database.php";
include_once $_SERVER['DOCUMENT_ROOT'] . "/includes/class_user.php";
?>
<?php

$database = new MySqlDatabase();
$user = new User($database);

if (isset($_POST['submit'])) {
    $result = $user->check_required($_POST); //this is where I get nothing back
    $user->create_user($result);
    die("Registration was successful!");
    } else {
    $username = "";
    $first_name = "";
    $last_name = "";
    $password = "";
    $email = "";
    $email2 = "";
    $secret_question = "";
    $secret_answer = "";
    unset($_POST);
    }


?>
<form action="" method="post" target="_self">
Username: <input type="text" name="username" class="text" maxlength="20" value="<?php echo htmlentities($username); ?>" /><br />
First Name: <input type="text" name="first_name" class="text" maxlength="20" value="<?php echo htmlentities($first_name); ?>" /><br />
Last Name: <input type="text" name="last_name" class="text" maxlength="20" value="<?php echo htmlentities($last_name); ?>" /><br />
Password: <input type="password" name="password" class="text" maxlength="30" value="<?php echo htmlentities($password); ?>" /><br />
Enter again: Password: <input type="password" name="password2" class="text" maxlength="30" value="<?php echo htmlentities($password2); ?>" /><br />
Email: <input type="text" name="email" class="text" maxlength="30" value="<?php echo htmlentities($email); ?>" /><br />
Enter again: Email: <input type="text" name="email2" class="text" maxlength="30" value="<?php echo htmlentities($email2); ?>" /><br />
Secret Question: <input type="text" name="secret_question" class="text" maxlength="35" value="<?php echo htmlentities($secret_question); ?>" /><br />
Secret Answer: <input type="text" name="secret_answer" class="text" maxlength="35" value="<?php echo htmlentities($secret_answer); ?>" /><br />
<input type="submit" name="submit" class="submitbtn" value="Submit" />
<?php

?>
</div>
</div>
</body>
</html>
[/quote]

Any ideas?

Database Resource Reference To Class __construct Method

Similar Tutorials

View Content

Can I not pass references into class properities from outside the object?

class db_manipulation {

private $connection = NULL;

function __construct(&$database_connection) {
$this->connection = $database_connection;
if (!$this->connection) die('couldnt connection to database');
}

function __destruct() {
mysqli_close($this->connection);
}
}

Results in: Warning: mysqli_close() [function.mysqli-close]: Couldn't fetch mysqli in

What's Faster Static Functions Calls Or Passing Object Reference

Similar Tutorials

View Content

I everyone, I'm developing a small MVC framework for my personal work, now, in order to have access from all the classes to certain variables I've created a registry class, for this to work I have 2 options:
1.- passing every time the registry object to the constructor class(controllers, models, etc)
or
2.- create in the registry static set and get so I can reach the variables by Registry::set(name, value) and Registry::get(name)

My question is, which one of this two options takes less resources(is faster)?

I hope anyone can help me with this, thanks in advance

Onload - Object Method Vs Function

Similar Tutorials

View Content

Hi Guys I wonder if someone can explain something that is probably quite basic. When I try to add an event listener and target a normal function this works fine - e.g. 'window.addEventListener('load',test)'. However, if I try to target a function that is a property of an object this fails - e.g. 'window.addEventListener('load',initialiser.init)'. Further in this latter case I also get a console log saying it's undefined. The code for this example is below. So my question is why does it fail onload when I use a function in an object as opposed to a straight function? Presumably it's something to do with the way the document and the code are loaded or initialised but what is it that makes them behave differently. Thanks, Drongo

<script>
       
       //this function call works fine
       //window.addEventListener('load',test);

       //this functiton call fails and is undefined in console
	window.addEventListener('load',initialiser.init);
	
	//example object holding a method
	var initialiser = {
		
		init:function(){
			alert('Init called!');
		}
	};

	//some random function
	function test(){
	
		alert('test called!');
	}
</script>

Edited by Drongo_III, 18 May 2014 - 10:59 AM.

Pear::iserror Returns Non-static Method Pear::iserror() Should Not Be Called Sta

Similar Tutorials

View Content

In my code I call PEAR::isError to see if there was an error in the SQL Query so I can log it but its always returning this error. Does anyone know a fix? I have tried to search google it and found http://pear.php.net/bugs/bug.php?id=9950 but it does not say how to fix it. Does anyone have any ideas?

Error
Non-static method PEAR::isError() should not be called statically

$query = "SELECT
Column
            FROM
             TableName";
$res = $db['database']->query($query);
if (PEAR::isError($res)) {
  $logger->err("Error pulling results from DB. Query:" . $query);
}

How To Access Method Object In Base Class From Derived Class? Error In My Solut

Similar Tutorials

View Content

I have mysqli object in Database class base:

[color=]database class:[/color]

class Database {
  private $dbLink = null;

  public function __construct() {
    if (is_null($this->dbLink)) {
      // load db information  to connect
      $init_array = parse_ini_file("../init.ini.inc", true);
      $this->dbLink = new mysqli($init_array['database']['host'],
                           $init_array['database']['usr'],
                           $init_array['database']['pwd'],
                           $init_array['database']['db']);

      if (mysqli_connect_errno()) {
        $this->dbLink = null;
      }
    }
  }

  public function __destruct() {
    $this->dbLink->close();
  }
}

Class derived is Articles where I use object dBLink in base (or parent) class and I can't access to mysqli methods (dbLink member of base class):

Articles class:

require_once ('./includes/db.inc');

class Articles extends Database{
  private $id,
              ....
              ....
             $visible = null;

  public function __construct() {
    // Set date as 2009-07-08 07:35:00
    $this->lastUpdDate = date('Y-m-d H:i:s');
    $this->creationDate = date('Y-m-d H:i:s');
  }

  // Setter
  ....
  ....

  // Getter
  ....
  ....

  public function getArticlesByPosition($numArticles) {
    if ($result = $this->dbLink->query('SELECT * FROM articles ORDER BY position LIMIT '.$numArticles)) {
      $i = 0;
      while ($ret = $result->fetch_array(MYSQLI_ASSOC)) {
        $arts[$i] = $ret;
      }
      $result->close();
      return $arts;
    }
  }
}

In my front page php I use article class:

include_once('./includes/articles.inc');
$articlesObj = new articles();
$articles = $articlesObj->getArticlesByPosition(1);
var_dump($articles);

[color=]Error that go out is follow[/color]

Notice: Undefined property: Articles::$dbLink in articles.inc on line 89

Fatal error: Call to a member function query() on a non-object in articles.inc on line 89

If I remove constructor on derived class Articles result don't change
Please help me

Problem With Calling A Method From Within A Method In Another Class

Similar Tutorials

View Content

My script has 3 classes (that are relevant to this discussion): DB, User and Validate. They are all in independent files and loaded automatically, when required, by an autoloader.
Both the User class and the Validate class have a private variable $_db which is instantiated by their class constructor: $this->_db = DB::getInstance();
At the top of the script I declare new instances: $user = new User(); and $validate = new Validate();
I then call a method in $user: $found = $user->findInUsers ( .... )
From within the findInUsers method I then want to call the query method in the DB class. My problem is that I can't find a way to do this that works.
I have tried $this->_db->query( ... ), $_db->query( ... ), but neither works.

The error messages I am getting a
An error occurred in script '/srv/http/classes/User.php' on line 42: Undefined variable $_db
Uncaught Error: Call to a member function query() on null in /srv/http/classes/User.php:42

Any pointers as to what I am doing wrong, or what I should be doing, would be most welcome.

Assigning An Object Of Multiple Instances To Another Object's Property

Similar Tutorials

View Content

Hey all,

I want to have an object that has a property which is an object containing instances of other objects. I try this:
Code: [Select]
class Blog extends Posts {
public $has_posts;

public function __construct($a,$b,$c){
$has_posts = (object) array_merge((array) $a, (array) $b, (array) $c);
}
}

class Posts {
public $b;

public function __construct($b){
$this->b = $b;
}
}

$post1 = new Posts(1);
$post2 = new Posts(2);
$post3 = new Posts(3);

$blog = new Blog($post1,$post2,$post3);
var_dump($blog->has_posts); //null
foreach($blog->has_posts as $post){ //Invalid argument supplied for foreach()
echo $post->b;
}

But as you see, has_posts is null, not an object containing other objects.

Thanks for response.

Reference Error

Similar Tutorials

View Content

Hello, I've just started learning PHP, JavaScript and I've got a big problem on my website. I'm getting this ReferenceError. I know what's the problem, but I don't know how to solve it, and I know people can do it for money but I don't have money, I'm searching for someone who's willing to help newbie. As I said I'm begginer, and I know something. The main problem is because I want to use GKPlugin and Player(jwplayer). Plugin need to use object, example:

<object id="flashplayer" classid="clsid:D27CDB6E-AE6D-11cf-96B8-444553540000" width="600" height="400">
<param name="movie" value="player.swf" />
<param name="allowFullScreen" value="true" />
<param name="allowScriptAccess" value="always" />
<param name="FlashVars" value="plugins=plugins/proxy.swf&proxy.link=http://www.vidbull.com/53qx9uo10k5d" />
<embed name="flashplayer" src="player.swf" FlashVars="plugins=plugins/proxy.swf&proxy.link=http://www.vidbull.com/53qx9uo10k5d" type="application/x-shockwave-flash" allowfullscreen="true" allowScriptAccess="always" width="600" height="400" />
</object>

Script is generetad just to embed with iframe, and the problem is when I replace it with object, then I'm getting this error. I know that JS can't "call" that iframe to show because I've replaced it with object. You guys probably know about what I'm talking. I'm just searching for some instructions, guidelines from you.

    ReferenceError: embeds is not defined
    

    if (embeds[embedid].indexOf("rapidplayer")== iframe_ad){

Here's the rest of code, I think it's used to show iframe.

    elseif (substr_count($link,"gorillavid")){
    $video_id = explode("/",$link);
    if (isset($video_id[count($video_id)-1])){
    $video_id = $video_id[count($video_id)-1];
    $embed = '<object id="flashplayer" classid="clsid:D27CDB6E-AE6D-11cf-96B8-444553540000"                                                                      width="600" height="400">
    <param name="movie" value="http://www.kiinc.com/videott/player.swf" />
    <param name="allowFullScreen" value="true" />
    <param name="allowScriptAccess" value="always" />
    <param name="FlashVars" value="plugins=http://www.kiinc.com/videott/plugins/proxy.swf&proxy.link=http://gorillavid.in/'.$video_id.'" />
    <embed name="flashplayer" src="player.swf" FlashVars="plugins=http://www.kiinc.com/videott/plugins/proxy.swf&proxy.link=http://gorillavid.in/'.$video_id.'" type="application/x-shockwave-flash" allowfullscreen="true" allowScriptAccess="always" width="600" height="400" />
    </object>';

This is the original code. Don't look at providers(source as gorillavid) because I used gorillavid in previous an posted another example from another source (zalaa)

    elseif (substr_count($link,"zalaa")){
    $video_id = explode("/",$link);
    if (isset($video_id[count($video_id)-1])){
    $video_id = $video_id[count($video_id)-1];
    $embed = '<IFRAME SRC="http://www.zalaa.com/embed-'.$video_id.'.html" FRAMEBORDER=0 MARGINWIDTH=0 MARGINHEIGHT=0 SCROLLING=NO WIDTH='.$width.' HEIGHT='.$height.'></IFRAME>';

Function which embed links and should embed GKPlugin/Player:

// general image link

    if (!$embed){
    $embed = "<div style='background-color:#000000; width: ".$width."px; height: ".$height."px;text-align:center;cursor:pointer;' onclick='window.open(\"$link\");'>";
    $embed.= "<p style='text-align:center; padding-top: 70px;'>";
    $embed.= "<a href='$link' target='_blank' style='font-size:24px; color: #ffffff !important'>Click here to play this video</a>";
    $embed.= "</p>";
    $embed.= "</div>";
    }
    return $embed;
    }

JavaScript code:

  function getEmbed(embedid){
        if (embeds[embedid].indexOf("rapidplayer")== iframe_ad){
            var html_content =     "<div class='fake_embed' id='fake_embed"+embedid+"' onclick='closeFakeEmbed("+embedid+");'>" +
                                    "<br /><br />" +
                                    "<div class='fake_embed_ad_close'><a href='javascript:void(0);' onclick='closeFakeEmbed("+embedid+");'>Close Ad</a></div>" +
                                    "<div class='fake_embed_ad' id='fake_embed_ad" + embedid +"'>" +
                                        "<iframe src='"+baseurl+"/iframe_ad.php' width='300' height='300' frameborder='NO' border='0'></iframe>" +
                                    "</div>" +
                                    "<div class='fake_embed_bar'><span class='fake_embed_bar_right'></span></div>" +
                                "</div>" +
                                "<div id='real_embed"+embedid+"' style='display:none'>"+embeds[embedid]+"</div>";
            
            
            jQuery('#videoBox'+embedid).html(html_content);
            jQuery('#videoBox'+embedid).show();
        } else {
            jQuery('#videoBox'+embedid).html(embeds[embedid]);
            jQuery('#videoBox'+embedid).show();
        }    
        
    }
    
    function countDown(embedid){
        showCounter = showCounter-1;
        jQuery('span#counter').html(showCounter);
        if (showCounter>0){
            showTimer = setTimeout('countDown('+embedid+');',1000);
        } else {
            showTimer = null;
            showCounter = 20;
            getEmbed(embedid);
        }
    }
    
    function changeEmbed(embedid, counter){
        if (counter == 0){
            jQuery('.embedcontainer').html('');
            jQuery('.embedcontainer').hide();
            getEmbed(embedid);
        } else {
            if (showTimer){
                clearTimeout(showTimer);
            }
            showTimer = null;
            showCounter = counter;
            
            jQuery('.embedcontainer').html('');
            jQuery('.embedcontainer').hide();
            jQuery('#videoBox'+embedid).html(js_lang.ticker);
            jQuery('#videoBox'+embedid+' span#counter').html(showCounter);
            jQuery('#videoBox'+embedid).slideDown("slow");
            
            showTimer = setTimeout('countDown('+embedid+');',1000);
        }
        /*
        jQuery('li.selected').removeClass('selected');
        jQuery('#selector'+embedid).addClass('selected');
        */
    }

How Do I Reference A Parent Id ?

Similar Tutorials

View Content

hello.

say i have list and i want the correct children under each parent

so i have
$id
$parent_id
$type
$name

in the db i have
4 parents each with 2 children

id=1 - type=parent - parent_id=0 - name=p1
id=2 - type=parent - parent_id=0 - name=p2
id=3 - type=parent - parent_id=0 - name=p3
id=4 - type=parent - parent_id=0 - name=p4
id=5 - type=child - parent_id=1 - name=c1
id=6 - type=child - parent_id=1 - name=c2
id=7 - type=child - parent_id=2 - name=c3
id=8 - type=child - parent_id=2 - name=c4
id=9 - type=child - parent_id=3 - name=c5
id=10 - type=child - parent_id=3 - name=c6
id=11 - type=child - parent_id=4 - name=c7
id=12 - type=child - parent_id=4 - name=c8

so how would i do the code?

i thought i could do it like this but its not working.

Code: [Select]
<?php

$family = Family::find_all();
foreach($family as $familys){

$id = $familys->id;
$type = $familys->type;
$parent_id = $familys->parent_id;
$name = $familys->name;

echo'
<ul>';
if($type == "parent"){
echo $name;
}
echo' </ul>

<li>';
if($type == "child" && $parent_id == $id){
echo $name;
}
echo'
</li>';
}
?>

all i get back is

p1

p2

p3

p4

no children

??

if i remove Quote

$parent_id == $id

from Quote

if($type == "child" && $parent_id == $id){

i get this

p1

p2

p3

p4

c1

c2

c3

c4

c5

c6

c7

c8

but they are not listed under the correct parent

i also tried moving the </ul> to the bottom but i get the same
Code: [Select]
<?php

$family = Family::find_all();
foreach($family as $familys){

$id = $familys->id;
$type = $familys->type;
$parent_id = $familys->parent_id;
$name = $familys->name;

echo'
<ul>';
if($type == "parent"){
echo $name;
}
echo'

<li>';
if($type == "child"){
echo $name;
}
echo'
</li>
</ul>';
}
?>

any thoughts?

thanks

rick

Unique Reference

Similar Tutorials

View Content

Hi,

I just need someone to check that a couple of lines I've written do what I believe them to do... i.e. check my logic!

I'm developing a booking form for booking on events. Each booking needs a unique reference, which needs to be meaningless to the customer, so I am BASE36 encloding it.

As the booking is be saved to a MySql database, my approach is to use the auto-incremented ID for the record to make the reference unique. The increment starts at 10000, and I add a random number before coding to make the encoded reference longer. I then BASE36 encode it to make it appear random.

Am I right in thinking the reference produced WILL be unique ... provided the auto-inc ID is unique?

$ref = rand(100,999) . $auto_incremented_id; //e.g. 354 & 10012 = 35410001
$ref_encoded = strtoupper(base_convert($rand, 10, 36)); // e.g.UD4J8P
Thanks

Foreach By Reference

Similar Tutorials

View Content

Can someone explain this strange behavior:

$aArray = array(
1 => null,
2 => null,
3 => null,
);
foreach($aArray as $key => &$val)
{
$val = "Some Value";
foreach($aArray as $Xkey => $Xval){} // Second foreach
}
var_dump($aArray);

Rsult is:
array(3) {
[1]=>
string(10) "Some Value"
[2]=>
NULL
[3]=>
NULL
}

It looks like second foreach breaks reference, why?

Php Variables By Reference

Similar Tutorials

View Content

Hi all,

I have been coding in PHP for a fair while now and I have come across variables by reference, but I don't really know:
a) how they work;
b) when to use them;
c) why they are used;

Can anyone here please clarify these issues please.

Thanks in advance!

Only Returns End Value Of $row

Similar Tutorials

View Content

Hello, i have a query that returns the rows of certain parts of a databse.

i made a button on the end of each echo, to make sure that, the button being printed with each echo, correlates to that echo. However, the SESSIONS only return the same varaibles each time. The last in the list.

$sql = "SELECT p.Title, p.PerfDate, p.PerfTime FROM performance AS p INNER JOIN production AS r ON p.Title = r.Title";

$result = $conn->query($sql);

if ($result->num_rows > 0) {
    // output data of each row
    while($row = $result->fetch_assoc()) {
       echo '<tr>
<td>'.$row['Title'].'</td>
<td>'.$row['PerfDate'].'</td>
<td>'.$row['PerfTime'].'</td>
<td><button name="availability" value="'.$row['Title'].'">Availability</button></td> 
</tr>';

$_SESSION["Title"] = $row['Title'];
$_SESSION["PerfDate"] = $row['PerfDate'];
$_SESSION["PerfTime"] = $row['PerfTime'];



    }
} else {
    echo "0 results";
}

$_SESSION["name"] = $_GET["name"];

?>

How am i able to make it so each button correlates to each row?

There's a screenshot of how it looks for reference

Edited December 8, 2019 by AdamSteele

Function By Reference Not Executing

Similar Tutorials

View Content

OK, so I have the following file that has database functions:

<?php

function dbDelete($param){
$conDelete = mysql_connect($url,'username','password',true);
mysql_select_db('my_db',$conDelete);
mysql_query($param,$conDelete);
mysql_close();
   if(isset($conDelete)){
   mysql_close($conDelete);
   }
}
?>

I include the above file in a session handling file. But for some reason the new file can't call the above function as follows:
<?php
include_once 'the above stated file';
function timeOut(){
dbDelete("DELETE FROM acctussessi WHERE acctussessi_usid = '$sessius[0]'");
   $_SESSION = array();
   setcookie(session_name(),'',time()-4200);
   session_destroy();
}
//CHECK FOR TIMEOUT REQUEST
switch($_GET['xyz']){
   case 'timeout':
   timeOut();
   header("Location: /?xyz=timedout");
   break;
   case 'logout':
   timeOut();
   header("Location: /?xyz=loggedout");
   break;
   case 'refresh':
   dbUpdate("UPDATE acctussessi SET acctussessi_time = ".time()." WHERE acctussessi_unid ='".$token."'");
   break;
}
?>

dbDelete isn't being called inside of the TimeOut() function. The only way it works is by doing the following:

<?php
function timeOut(){
   $_SESSION = array();
   setcookie(session_name(),'',time()-4200);
   session_destroy();
}
//CHECK FOR TIMEOUT REQUEST
switch($_GET['xyz']){
   case 'timeout':
      dbDelete("DELETE FROM acctussessi WHERE acctussessi_usid = '$sessius[0]'");
   timeOut();
   header("Location: /?xyz=timedout");
   break;
   case 'logout':
      dbDelete("DELETE FROM acctussessi WHERE acctussessi_usid = '$sessius[0]'");
   timeOut();
   header("Location: /?xyz=loggedout");
   break;
   case 'refresh':
      dbUpdate("UPDATE acctussessi SET acctussessi_time = ".time()." WHERE acctussessi_unid ='".$token."'");
   break;
}
?>
But this is annoying and repetitive. What is going on?

Thanks in advance.

How To Reference To A File In Different Location

Similar Tutorials

View Content

Hi everyone,

This is driving me crazy. I need to reference different files located in different folder structure. For example, I have the following file structure.

/my_project/
/my_project/database/database_script.php
/my_project/index.php

1. If I want to reference /my_project/index.php from /my_project/database/database_script.php, how can I reference it ?
2. From /my_project/index.php to /my_project/database/database_script.php , it's obvious all I gotta do it include("/database/database_script.php").

I use $_SERVER('DOCUMENT_ROOT"), to solve the 1. problem. It works on my XAMPP local machine but when I uplode it onto the server, there's a problem. The path becomes '/my_project/my_project/database/database_script.php". Is there a universal way (more like a standard way) to reference files in php so that I won't need to change every file path once I upload those onto the server ?

Regards,

Reference Stored Image

Similar Tutorials

View Content

I am writting a php function that uses mysql to get user data - pretty common, right

Well, my issue is that I need to run a check in my file system. Users profile pictures are stored in my image directory as .png's. I need to have my function check that directory and if an image matches their id, then return their information. I only want the user data if they have an image uploaded.

Here is my current function:

Code: [Select]
function fetch_users_login($limit)
{
$limit = $limit(int);

$sql = "SELECT
`users`.`id`,
`users`.`firstname`,
`users`.`lastname`,
`users`.`username`,
`user_privacy`.`avatar`
FROM `users`
LEFT JOIN `user_privacy`
ON `users`.`id` = `user_privacy`.`uid`
WHERE `users`.`status` > 2
AND `user_privacy`.`avatar` = 1
ORDER BY `users`.`id` DESC
LIMIT 0, {$limit}";

$result = mysql_query($sql) or die(mysql_error());

$users = array();

$i = 0;

while(($row = mysql_fetch_assoc($result)) !== false)
{
$users[$i] = array(
'id' => $row['id'],
'firstname' => $row['firstname'],
'lastname' => $row['lastname'],
);

$users[$i]['avatar'] = getUserAvatar($row['username']);

$i++;
}

return $users;
}

Obtain Such A Reference In The Script

Similar Tutorials

View Content

Is it possible to get something as a reference in the script if it is such a http://site.com/home#p1

tried in different ways but #p1 my script does not see

Pass By Reference Deprecated?

Similar Tutorials

View Content

Hi Guys

Probably a simple answer to this.

Writing a script where I have a foreach to escape data in a multi dimensionsal array - destined for the database.

I want to preserve the the escaped values in the array so I've passed in the value by referece. See code below:

Code: [Select]
foreach($myarray as $key=>$value){

foreach($value as $k=>$v){

$v = $mysqli->real_escape_string(&$v);
echo $v ."<br/>";

}

}

I've switched on error_reporting(E_STRICT), because i read it was good practice to build your scripts with this on.

Anyway - when i pass by reference I get a message as follows:

Quote

Deprecated: Call-time pass-by-reference has been deprecated in C:\wamp\www\wh\C.php on line 105

So if pass by reference is deprecated, what's the alternative?

I realise i could pass the new values to a new array. But does this mean i shouldn't pass by reference anymore?

Many thanks and sorry for going round the planet to ask such a simple question.

Drongo