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PHP - Php Based Img Swap Always Turning Up Orange Version???
Hi guys, I have written a page that contains a form. When the user chooses a color, it is posted, then the posted value is re-written as a filename, sent through a function, and the image on the page uses the "colorized.gif" created by the function to make an image swap "onclick. Problem is, no matter the choice, it always changes the picture to orange! Here is the code for the form: <?php include('function.php'); ?> <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> <title>PHP GD CONFIGURATOR</title> </head> <body> <form action="<?php echo $_SERVER['PHP_SELF']; ?>" method="post"> Red<input type="radio" name="color" value="red" /> Orange<input type="radio" name="color" value="orange" /> Ivory<input type="radio" name="color" value="ivory" /> Black<input type="radio" name="color" value="black" /> <input type="submit" name="submit" value="submit" /> </form> <?php if($_POST['color'] != NULL){ echo $_POST['color']; $file =('gdimages/' . $_POST['color'] . '.gif'); createImg($file); } ?> <img src="default.jpg" name="lola" alt="lola dining chair" onclick="this.src = 'colorized.gif'" /> </body> </html> And here is the function... function createImg ($imgname1) { $base = imagecreatefromgif("gdimages/base.gif"); $top = imagecreatefromgif($imgname1); if ($top) { imagecopy($base, $top, 0, 0, 0, 0, 250, 250); imagejpeg($base, 'colorized.gif'); imagedestroy($base); } else{ header("Content-Type: text/html"); } } I really can't understand it...this is my first attempt at programming something new by myself...and I really need it to work!!! I also plan for this to work with combining more than 2 images from more than two choice menus...so debugging now is definitely necessary. Any suggestions? Similar TutorialsHi all, But of a PHP newbie so treat me nice but this one is driving me nuts I have the exact same login.php file running on two different servers and they have slightly different versions of PHP installed as follows: 1. PHP Version 5.0.4 - version http://www.trafficpaymaster.com/tpm/phpversion.php 2. PHP Version 5.2.15 - version http://www.dentistsinflorida.org/tpm/phpversion.php The login works fine on the first server from he http://www.trafficpaymaster.com/tpm/login.php Email: test@test.com Pwd: test But try it on the second server he http://www.dentistsinflorida.org/tpm/login.php Using the same email and password (which is correct) it just loops round not letting the user into the main script at index.php Question: Why? What have I got wrong for that later version of PHP? Many thanks guys. having a problem turning this sql into a query and I need it to only update rows where id field is empty. Code: [Select] UPDATE systems SET naqahdah = naqahdah + naqahdah_mines * 2 I tried this out with failure Code: [Select] <?php mysql_query("UPDATE systems SET naqahdah= naqahdah + naqahdah_mines * 2 WHERE id <> ' ' "); ?> so i tried getting rid of WHERE and couldnt even get this to work. I tested the sql out it works fine. Code: [Select] <?php mysql_query("UPDATE systems SET naqahdah= naqahdah + naqahdah_mines * 2 "); ?> I am trying to turn a .txt file into an array, count the items in the array, and display a random quote from it.
<p class = "center">
<?php
$Proverb = file('../proverbs.txt');
$ProverbCount = count($Proverb);
echo rand(0, $ProverbCount-1);
?>
<br>
© 2014
</p>
The issue I am having is that it states the file does not exist:
FULL PATH: G:\EasyPHP-5.3.2i\www\PHP_Projects\ChineseZodiacs\Includes\inc_footer.php
TEXT FILE: G:\EasyPHP-5.3.2i\www\PHP_Projects\ChineseZodiacs\proverbs.txt
Please help, thank you.
Hey i'm having trouble figuring out how to do this. This is the code grabbing the users who are online and listing them one by one. Code: [Select] $qt=mysql_query("SELECT username FROM users WHERE lastvisit > '$tm' and online='ON'"); echo mysql_error(); while($nt=mysql_fetch_array($qt)){ echo "<tr><td> $nt[username] </td></tr>"; } ?> what i want to do is have each username be a hyperlink that links to their profile how would i go about this? cause i'm completely clueless on this. is there some way i can do it in the php or will i need to make a varchar column for each player that holds their profile link and grab that with the query too? I recently had a need to check several arrays, and if an index wasn't set, set a variable to a given value. The code was such that I couldn't perform the isset check all at once. I then thought "wouldn't it be great if I could try the script, and catch the error or warning". Searching a bit, I came across the following script. I am a little nervous, however, that there might be negative consequences of doing so. Thoughts?
set_error_handler(function($errno, $errstr, $errfile, $errline, array $errcontext) {
// error was suppressed with the @-operator
if (0 === error_reporting()) {
return false;
}
throw new ErrorException($errstr, 0, $errno, $errfile, $errline);
});
try {
dns_get_record();
} catch (ErrorException $e) {
// ...
}
right now i have my date system to say "X amount of seconds ago, X hours ago, X days ago, X years ago, How could i turn mktime() (1290874161) into a mm/dd/yyyy format? so it would say like, "Nov 27, 2010 at Hour:Minute" (whatever the hour/minute is) Hi, I'm pretty new to PHP, struggled my way through most of my encounters with PHP so far, but getting the hang of it I'm looking for a simple script that turns a number or word served by a weather station into a graphic. E.g. If the temp is 20 degrees, a graphic I've designed would be shown, or a cloud or the sun or whatever. At the moment the weather station feed is converted from 'webtags' in to php tags (temp is $temp, wind is $wind etc.) and these echo out as numbers and words on the website. I can sort of see how it would work in my head, but need a little help. Can anyone please point me in the right direction? Thanks (for reference site is www.southtyneweather.co.uk) I got a tab menu, where the user choose his category and a list of sub categories appear. Personally I like the old fashion way, where everything listed like in craiglist.com ... How can I turn the following tab menu, into a simple 3 column list? <!--CATEGORIES--> <div id="selCategories"> <div class="slidetabsmenu menu_fix"> <ul> <?php if(isset($groups) and $groups->num_rows()>0) { $i=0; foreach($groups->result() as $group) { ?> <li id="gr<?php echo $i;?>" class="<?php if($i == '0') echo "selected"; ?>"><a href="javascript:;" onclick="getCat('<?php echo $i ?>','<?php echo $groups->num_rows ?>',<?php echo $group->id;?>);"><span><?php echo $group->group_name;?></span></a></li> <?php $i++;} } ?> </ul> </div> <div class="clsInfoBox"> <div class="block"> <div class="grey_t"> <div class="grey_r"> <div class="grey_b"> <div class="grey_l"> <div class="grey_tl"> <div class="grey_tr"> <div class="grey_bl"> <div class="grey_br"> <div class="cls100_p"> <h4><span class="clsCategory"><?php echo $this->lang->line('CATEGORIES');?></span></h4> <div class="clsCategoryList clearfix" id="catInner"> </div> </div> </div> </div> </div> </div> </div> </div> </div> </div> </div> </div> </div> <!--END OF CATEGORIES--> Your tips, directions, and support is highly appreciated. I have got a date field in my mysql database with events, and as you know date in MYSQL uses yyyy/mm/dd but I would first like to turn this around to dd/mm/yyyy but also turn this into for example "Tuesday - May 1990" would anyone like to point me into the right direction? Much appreciated! i run several wordpress on domains - and wthin the wordpress i have a plugin that allows uploads of images -within a certain plugin the interesting thing: image upload is - sometimes possible and sometinmes impossible: see here the circumstances - PHP Version : 5.3.28 PHP Safe Mode : On image upload is impossible - and on the same server - a second vhost PHP Version : 5.3.28 PHP Safe Mode : off image upload is possible why is this so - does it have to do with the safe-mode - Hi all,
is it possible to install php version 5.2.3 on windows server 2012R2 ?
will it work ? are they any security issues ?
Best regards,
Amit menasahe
After being forced to have the server upgraded I am having problems with my 'reset password' pages. What I wondered is, has there been any changes to PHP or MySQL between these versions ? The PHP version was 5.2.9 and is now 5.2.14 The MySQL version was Client API version 5.0.45 and is now Client API version 5.0.90 Some one clicks a link like this. www.site.com/resetpw.php?pwr=a1b2c3d4e5f6 the code would be a 32 char hash that is checked against the database, but my code now (which was never changed before or after the server change) seems to find the database line and update it but show the message that it was invalid ? instead of showing the the message, your password will be sent to you after changing the DB does anyone have any ideas ? Code: [Select] <?php include('includes/connection.php'); include('includes/functions.php'); date_default_timezone_set('Europe/London'); if(isset($_POST['reset']) && trim($_POST['reset']) == 'Reset') { $email = mysql_real_escape_string($_POST['email']); $checkVerify = mysql_query("SELECT account_id FROM customers WHERE email='$email' AND verified='No' LIMIT 1"); $checkBanned = mysql_query("SELECT account_id FROM customers WHERE email='$email' AND suspended='Yes' LIMIT 1"); if(!$email) { $thisError = 'Please enter your e-mail address.'; } else if(!$password) { $thisError = 'Please enter your password.'; } else if(mysql_num_rows($checkVerify)) { $thisError = 'Your account has not been approved by an Admin.'; } else if(mysql_num_rows($checkBanned)) { $thisError = 'Your account has been suspended by an Admin.'; } else { $password = md5($password); $checkAccount = mysql_query("SELECT account_id FROM customers WHERE email='$email' AND password='$password' LIMIT 1"); if(mysql_num_rows($checkAccount)) { $_SESSION['FM_user'] = $email; header('Location: members.php'); exit; } else { $thisError = 'Your e-mail address and/or password is incorrect.'; } } } include('includes/header.php'); ?> <body> <div class="headerBar"> <?php include('includes/navigation.php');?> </div> <?php headerText(); ?> <div class="content"> <div class="widthLimiter contentStyle"> <div class="formWrapper"> <?php if(isset($thisError)) { echo '<div class="errorDiv">',$thisError,'</div>'; } ?> <?php if(isset($thisSuccess)) { echo '<div class="successDiv">',$thisSuccess,'</div>'; } ?> <span class="subHeader">Initiate Password Reset</span> <?php // include("sendmail2010.php"); $securitycode = ($_GET['pwr']); //echo("53:security:".$securitycode.":<br>"); if ($securitycode != "") { $sql = "SELECT * FROM `customers` WHERE `changeofpasswordcode` = '".mysql_real_escape_string($securitycode)."' LIMIT 1"; //echo("54:sql:".$sql.":<br>"); $res = mysql_query($sql) or die(mysql_error()); //echo("57:<br>"); if (mysql_num_rows($res) != 0) { //echo("59:sql:".$sql.":<br>"); $customerName = mysql_result($res, 0 ,'fullname'); $email = mysql_result($res, 0 ,'email'); $yourpasswordtologin = CreateNewPassword(); $format = 'Y-m-d H:i:s'; $date = date( $format ); $sql = "UPDATE `customers` SET `password` = '" . md5($yourpasswordtologin) . "', `password2` = '" . mysql_real_escape_string($yourpasswordtologin) . "', `changeofpasswordcode` = '', `newpasswordrequestedon` = '" . $date . "' WHERE `changeofpasswordcode` = '" . mysql_real_escape_string($securitycode) . "' LIMIT 1"; //echo("65:sql:".$sql.":<br>"); $res = mysql_query($sql) or die(mysql_error()); $_SESSION['customerName'] = $customerName; $_SESSION['customerEmail'] = $email; $_SESSION['generatePass'] = $yourpasswordtologin; //echo("send email"); $sendemailnow = createEmailSend('newPassword', 'Your new password', 'customer'); //echo("email sent ".$sendemailnow); ?><div style="margin: 30px;">Thank you for completing your password reset process.<br><br>An email with a randomly generated password has been sent to your email address, please check your email account for this email as you will need this password to access your <?=$_SESSION['siteName'];?> account.<br><br><strong><em>Please check your 'spam folder' in case our emails are showing up there.</em></strong><br><br>You may now <a href="<?=$_SESSION['webAddress'];?>">sign in</a> to your account.</div><?php //echo("72:end of IF send email<br>"); } else { //echo("74 bad link<br>"); ?><div style="margin: 20px;">Sorry the link you clicked is and old password reset link or is not valid, please delete the email.<br><br>If you were trying to reset your password, please click the<br>'Member Login' link on our site and then click the 'Reset Password' link.</div><?php //echo("end of IF bad<br>"); } //echo("78:end of first IF<br>"); } ?> </div> </div> </div> <?php include('includes/footer.php');?> </body> </html> HI, I've upgraded from PHP version 5.2 to PHP version 5.4 and are not able to load / find mssql extension ? How do I use MSSQL in version 5.4 ?? Is MSSQL not supported in this version or am I (hopingly) missing something ??? Regards Dieter "I'm also running a forked version of php, that has many custom additions and modifications that I added to it, which helps keep everything running as fast as it does" what does saying u have a "forked" version of php and makes your site run super fast, wats this mean? What exactly can u edit in your php config to make it faster? I thought only php accelerators do that? lol This may sound like a really stupid question, but this is really bugging me.
If i code something in PHP 5.5.11 and upload it to a server that is running PHP 5.4, would the code work correctly? I didnt think there was a super amount of difference between the two versions. Perhaps im wrong.
The reason i asked is because someone has given me a project to help them with. Im running php 5.5.11. I coded it, tested in in xampp, working great. I upload it to his website, which he told me is currently running 5.4 (i tried phpinfo() but they have disabled it) and a majority of the functions i coded are no longer working. Things are not writing to the database, things collected from the database either dont show up on the website or they only show up when something gets posted after it, in which case the something posted after it doesnt show e.c.t.
Is the difference that much it can break code?
Thanks!
PHP Version : 5.3.28 is this outdated or what?
i run this on the server - which is configured and administered by a friend of me.
i run a wordpress-cms
and i have issues with the image upload.
all image uploads in the connections-plugin run in to a blank page
what can i do !?
i need your help and your ideas
love to hear from you
greetings
Hi I have used in the past search.php?sl=y on a link to the page, and in the page I would use
if($_GET[$sl]=='y'){
Show somw stuff here
}
This was good in php 5.6, but I'm in the process of upgrading my code to the newer version, and am looking for an updated way to acheive this. Help, pointers examples Thanks in advance.
Paul Can anyone tell me how I can find out which version of sqlsrv that I need to load to work with my IIS server and MSSQL server?
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