PHP - Parse Error: Syntax Error, Unexpected T_echo
Hi I am having problems with this script checked and checked but with no joy can you assist a php newb
Code: [Select] <?php # Product Entry $page_title = 'Product Entry'; if (isset($_POST['Submit'])) { $errors = array(); if (empty($_POST['SKU_ProductID'])) { $errors[] = 'Please enter Product ID.'; } else { $sid = trim($_POST['SKU_ProductID']); } if (empty($_POST['SKU_MerchSKUID'])) { $errors[] = 'Please enter Merchant SKU.'; } else { $mid = trim($_POST['SKU_MerchSKUID']); } if (empty($_POST['Game_Title'])) { $errors[] = 'Please enter Game Title.'; } else { $gt = trim($_POST['Game_Title']); } if (empty($_POST['Platform'])) { $errors[] = 'Please enter Platform.'; } else { $pl = trim($_POST['Platform']); } if (empty($_POST['Genre'])) { $errors[] = 'Please enter Genre.'; } else { $ge = trim($_POST['Genre']); } if (empty($_POST['Weight'])) { $errors[] = 'Please enter Weight.'; } else { $we = trim($_POST['Weight']); } if (empty($_POST['Supplier'])) { $errors[] = 'Please enter Supplier.'; } else { $sup = trim($_POST['Supplier']); } if (empty($_POST['Supplier_Price'])) { $errors[] = 'Please enter Supplier Price.'; } else { $sp = trim($_POST['Supplier_Price']); } if (empty($_POST['Cashback'])) { $errors[] = 'Please enter Cashback %.'; } else { $cb = trim($_POST['Cashback']); } if (empty($_POST['Cashback_Amount'])) { $errors[] = 'Please enter Cashback Amount.'; } else { $cba = trim($_POST['Cashback_Amount']); } if (empty($errors)) { require_once ('connect.php'); $q = "INSERT INTO Products (SKU_ProductID, SKU_MerchSKUID, Game_Title, Platform, Genre, Weight, Supplier, Supplier_Price, Cashback, Cashback_Amount) VALUES ('$sid' , '$mid' , '$gt' , '$pl' , '$ge' , '$we' , '$sup' , '$sp' , '$cb' , '$cba')"; $r = @mysql_query ($dbc, $q); if ($r) { echo '<H1>This game has been added to the database.</H1>'; } else { echo '<H1>Product Addition Error</H1> <p class="error">The game could not be added to the database.</p>'; echo '<p>' . mysqli_error($dbc) . '<br /><br />Query: ' . $q . '</p>'; } mysqli_close($dbc); exit (); } else { echo '<H1>Error!</H1> <p class="error">The Following error(s) occurred:<br />'; foreach ($errors as $msg { [b]echo " - $msg<br />\n";[/b] } echo '</p><p>Please try again.</p><p><br /></p>'; } [b]}[/b] ?> The errors regards syntax I see on dreamweaver are in bold. Thanks Paul Similar TutorialsI'm getting a syntax error in this code. Basically I'm printing out a form, and depending on the value of an option, I want "checked" to be printed out. I was getting a syntax error by using the non-shorthand version of an if statement too. Any ideas why? '<input type="radio" name="position" value="1" '.(get_option("shPosition") == 1 ? echo "checked" :).' /> Top <input type="radio" name="position" value="0" '.(get_option("shPosition") == 0 ? echo "checked" :).' /> Bottom' Parse error: syntax error, unexpected T_STRING in C:\xampp\htdocs\mywork\unique.php on line 15 <html> <head> <title> </title> </head> <body bgproperties="fixed"> <?php $dbhost = 'localhost'; $dbuser = 'root'; $dbpass = ''; $con = mysql_connect($dbhost, $dbuser, $dbpass) or die ('Error connecting to mysql'); $dbname = 'mywork'; mysql_select_db($dbname, $con); $sql=mysql_query(insert into users (regno,name,gender,date,month,year,emailid,cell,paddress,caddress,incometype,incomeamt,dad,fyes,dadocup,mom,myes,momocup,password) VALUES ('$_POST[regno]','$_POST[name]','$_POST[gender]','$_POST[date]','$_POST[month]','$_POST[year]','$_POST[emailid]','$_POST[cell]','$_POST[paddress]','$_POST[caddress]','$_POST[incometype]','$_POST[incomeamt]','$_POST[dad]','$_POST[fyes]','$_POST[dadocup]','$_POST[mom]','$_POST[myes]','$_POST[momocup]','$_POST[password]')"); $sql1=mysql_fetch_array($sql); $result = @mysql_query($SQl1); $result="SELECT * FROM users WHERE regno='$regno'"; while($row = mysql_fetch_array($result)) { //echo $row['regno']."regno<br>"; //echo $row['name']."name<br>"; //echo $row['gender']."gender<br>"; //echo $row['date']."date<br>"; //echo $row['month']."month<br>"; //echo $row['year']."year<br>"; //echo $row['emailid']."emailid<br>"; //echo $row['cell']."cell<br>"; //echo $row['paddress']."paddress<br>"; //echo $row['caddress']."caddress<br>"; //echo $row['incometype']."incometype<br>"; //echo $row['incomeamt']."incomeamt<br>"; //echo $row['dad']."dad<br>"; //echo $row['fyes']."fyes<br>"; //echo $row['dadocup']."dadocup<br>"; //echo $row['mom']."mom<br>"; //echo $row['myes']."myes<br>"; //echo $row['momocup']."momocup<br>"; //echo $row['password']."password<br>"; } echo "Thanks for Register!"; if (!mysql_query($sql,$con)) { die('Error: ' . mysql_error()); } echo "1 record added"; mysql_close($con); ?> <form name="security" action="index.php" method="post"> <input type="submit" value="click here to login"> </form> </body> </html> I have been trying to get my files to upload onto a computer and I receive this message: Parse error: syntax error, unexpected T_STRING in /home/content/19/6550319/html/listing.php on line 27. Line 27 is how the php logs into my SQL. The problem is that I was able to log in before. I just made changes to the form by adding a dropdown menu and price and now it says it doesnt parse. Can anyone figure this out. I will include the code without the login information because the forum is public but I did put the words left out for you to see where I took out the passcodes. Code: [Select] <?php //This is the directory where images will be saved $target = "potofiles/"; $target = $target . basename( $_FILES['photo']['name']); //This gets all the other information from the form $price=$_POST['price']; $gig=$_POST['giga']; $yesg=$_POST['yesg']; $pic=($_FILES['photo']['name']); $pic2=($_FILES['phototwo']['name']); $pic3=($_FILES['photothree']['name']); $pic4=($_FILES['photofour']['name']); $description=$_POST['iPadDescription']; $condition=$_POST['condition']; $fname=$_POST['firstName']; $lname=$_POST['lastName']; $email=$_POST['email'] // Connects to your Database mysql_connect ("left out", "left out", "left out") or die(mysql_error()) ; mysql_select_db("left out") or die(mysql_error()) ; //Writes the information to the database mysql_query("INSERT INTO listing (price,giga,yesg,photo,phototwo,photothree,photofour,iPadDescription,condition,firstName,lastName,email) VALUES ('$price', '$gig', '$yesg', '$pic', '$pic2', '$pic3', '$pic4', '$description', '$condition', '$fname', '$lname', '$email')") ; //Writes the photo to the server if(move_uploaded_file($_FILES['photo']['tmp_name'], $target)) { //Tells you if its all ok echo "The file ". basename( $_FILES['uploadedfile']['name']). " has been uploaded, and your information has been added to the directory"; } else { //Gives and error if its not echo "Sorry, there was a problem uploading your file."; } echo date("m/d/y : H:i:s", time()) ?> I just enabled error reporting and I am not that familiar with it. I know I have an error some where around line 33. I know I am missing a bracket or a comma or some other syntax error I just cannot find where the error is. Below is my script. Thanks for any help. Code: [Select] <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Strict//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-strict.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <title>Airline Survey</title> <meta http-equiv="content-type" content="text/html; charset=iso-8859-1" /> <meta name="author" content="Revised by abc1234"/> </head> <body> <?php $WaitTime = addslashes($_POST["wait_time"]); $Friendliness = addslashes($_POST["friendliness"]); $Space = addslashes($_POST["space"]); $Comfort = addslashes($_POST["comfort"]); $Cleanliness = addslashes($_POST["cleanliness"]); $Noise = addslashes($_POST["noise"]); if (empty($WaitTime) || empty($Friendliness) || empty($Space) || empty($Comfort) || empty($Cleanliness) || empty($Noise)) echo "<hr /><p>You must enter a value in each field. Click your browser's Back button to return to the form.</p><hr />"; else { $Entry = $WaitTime . "\n"; $Entry .= $Friendliness . "\n"; $Entry .= $Space . "\n"; $Entry .= $Comfort . "\n"; $Entry .= $Cleanliness . "\n"; $Entry .= $Noise . "\n"; $SurveyFile = fopen("survey.txt", "w") } if (flock($SurveyFile, LOCK_EX)) { if (fwrite($SurveyFile, $Entry) > 0) { echo "<p>The entry has been successfully added.</p>"; flock($SurveyFile, LOCK_UN; fclose($SurveyFile); else echo "<p>The entry could not be saved!</p>"; } else echo "<p>The entry could not be saved!</p>"; } ?d> <p><a href="AirlineSurvey.html">Return to Airline Survey</a></p> </body> </html> I don`t get it, waht is wrong?! Code: [Select] <?php require_once 'auth.php'; if (!isset($_SESSION['SESS_VERIFY'])) { header("location: access-denied.php"); exit(); } if ($_SESSION['lang'] == 'Ro') { // setare data romania date_default_timezone_set('Europe/Bucharest'); $today = getdate(); $zi = $today['mday']; $luna = $today['mon']; $lunastring = $today['month']; $an = $today['year']; $data = $zi.$luna.$an; $data = (string)$data; $ora = date('H:i:s'); $msg = array(); $err = array(); $luni = array ( 1=>'Ianuarie', 2=>'Februarie', 3=>'Martie', 4=>'Aprilie', 5=>'Mai', 6=>'Iunie', 7=>'Iulie', 8=>'August', 9=>'Septembrie', 10=>'Octobrie', 11=>'Noiembrie', 12=>'Decembrie'); // comun const SQL_ERR = 'SQL statement failed with error: '; const ADD_MODEL = 'ADAUGA UN MODEL NOU'; . .many constants.. . } elseif ($_SESSION['lang'] == 'It') {... Thank you! Hi folks, I am a complete n00b at php and mysql. I am teaching myself from books and the WWW, but alas I am stuck... the error I get is: Parse error: syntax error, unexpected T_STRING in X:\xampp\htdocs\search.php on line 7 here is the code: <?php mysql_connect ("localhost", "user", "password") or die (mysql_error()); mysql_select_db ("it_homehelp_test") or die (mysql_error()); $term = $_POST['term']; $sql = $mysql_query(select * from it_homehelp_test where ClientName1 like '%term%'); <<<------this is line 7 while ($row = mysql_fetch_array($sql)){ echo 'Client Name:' .$row['ClientName1']; echo 'Address:' .$row['Address1']; echo 'Phone:' .$row['Tel1']; } ?> Any help you can offer would be great. I can also post the ".html" file that creates the search bar if it is needed. Thanks
Hello everyone,
1 <?php
7 // Create connection
10 // Check connection
14 $firstname = $conn->real_escape_string($_REQUEST['firstname']); 25 $sql2 = "INSERT INTO countries VALUES ('$country')"; 27 $sql3 = "INSERT INTO Contacts (firstname, lastname, address, city, country, phone, email) VALUES ('$firstname', '$lastname', '$address', $city, $country, '$phone_number','$email')";
29 SELECT * FROM cities;
if($conn->query($sql2) === true){
if($conn->query($sql3) === true){ <?php require_once('nusoap.php'); $soap_server = 'http://www.domain.com/api/api.cfc?wsdl'; $client = new soapclient($soap_server); $client->call() $params = array('user' => 'username@domain.com', 'password' => 'PASSWORD'); $return_string = $client->call('getKey', $params); print_r($return_string); $subId = 'XXXXXX'; $params = array('keyStr' => $keyStr, 'subId' => $subId); $return_string = $client->call('getTodaySubIDStats', $params); print_r($return_string); unset($client); ?> spits out Parse error: syntax error, unexpected T_VARIABLE in /home/site82/public_html/stats.php on line 12 Line 12 is... $params = array('user' => 'username@domain.com', Code: [Select] <?php if (!isset($_POST['submit'])) { ?> <h2>Todays Special</h2> <p> <form action="<?php echo $_SERVER['PHP_SELF']; ?>" method="post"> <select name="day"> <option value="1">Monday/Wednesday <option value="2">Tuesday/Thursday <option value="3">Friday/Sunday <option value="4">Saturday </select> input type="submit" name="submit" value="Go"> </form> <?php // get form selection $day = $_POST['day']; // check value and select appropriate item switch ($day) { case 1: $special = 'Chicken in oyster sauce'; break; case 2: $special = 'French onion soup'; break; case 3: $special = 'Pork chops with mashed potatoes and green salad'; break; default: $special = 'Fish and chips'; break; } ?> I have been getting that error and I cannot figure out why it is happening Here is the error: Parse error: syntax error, unexpected T_ENDWHILE, expecting ',' or ';' in /home/scswc188/public_html/index.php on line 23 Here is my Code (Database Credentials removed for obvious reasons) <?PHP // Conect to the Mysql Server $connect = mysql_connect("IP","USER","PASS"); //connect to the database mysql_select_db("TABLE"); //query the database $query = mysql_query("SELECT * FROM users_online WHERE online = 1"); // fetch the results / convert into an array WHILE($rows = mysql_fetch_array($query)): $users = $rows['name']; echo "'<font color='black'>Online:<font color='green'>$users, </font></font>;" endwhile; ?> or here http://pastebin.com/ZYh4t2pD Thanks Edit: Found the php tag This topic has been moved to Third Party PHP Scripts. http://www.phpfreaks.com/forums/index.php?topic=315281.0 This topic has been moved to PHP Applications. http://www.phpfreaks.com/forums/index.php?topic=344105.0 I keep getting an error code when running my php, it states: Parse error: syntax error, unexpected $end in W:\www\blog\login.php on line 33 Line 33 is </html> Code: [Select] <?php mysql_connect ("localhost", "root", ""); mysql_select_db("blog"); ?> <html> <head> <title>Login</title> </head> <body> <?php if(isset($_POST['submit'])){ $name = $_POST['name']; $pass = $_POST['password']; $result = mysql_query("SELECT * FROM users WHERE name='$name' AND pass='$pass'"); $num = mysql_num_rows($result); if($num == 0){ echo "Bad login, go <a href='login.php'>back</a>"; }else{ session_start(); $SESSION ['name'] = $name; header("Location: admin.php"); } ?> <form action='login.php' method='post'> Username: <input type='text' name='name' /><br /> Password: <input type='password' name='password' /><br /> <input type='submit' name='sumbit' value='Login!' /> </form> </body> </html>Can any one advise me whats wrong? Hi all, Does anybody can help me with this error...? I am trying create a simple form which insert data into mysql table called 'sample' Here is my code... Code: [Select] <?php $connection = mysql_connect("localhost","root", "123"); if(!$connection) { die("db connection error" .mysql_error()); } $db_select = mysql_select_db("project", $connection); if(!$db_select) { die("db select error" .mysql_error()); } $sql = "INSERT INTO sample (id,firstname,lastname,bio,gender) VALUES ('$_POST['ID_']','$_POST['firstname']','$_POST['lastname']','$_POST['bio']','$_POST['gender']')"; if(!$sql) { die('Error: ' . mysql_error()); } echo "1 record added"; ?> And every time I am getting this annoying error Quote Parse error: syntax error, unexpected T_ENCAPSED_AND_WHITESPACE, expecting T_STRING or T_VARIABLE or T_NUM_STRING in C:\wamp\www\project\process.php on line 19 and Line 19 is Code: [Select] ('$_POST['ID_']','$_POST['firstname']','$_POST['lastname']','$_POST['bio']','$_POST['gender']')"; Thanks in advance..! :-) I just edited the tablerate.php in magento, and now I am getting this error, but I don't know what's wrong. Anybody here can help me?
The error message reads "Parse error: syntax error, unexpected '*', expecting function (T_FUNCTION) in /home/echoshom/public_html/app/code/core/Mage/Shipping/Model/Carrier/Tablerate.php on line 50"
Attached is tablerate.php
Attached Files
Tablerate.php 9.23KB
2 downloads i keep getting the above error.. help this is a class of the log entry <?php require_once "config.php"; abstract class DataObject { protected $data = array(); public function__construct( $data ) { foreach ( $data as $key => $value ) { if ( array_key_exists( $key, $this->data )) $this->data[$key] = $value; } } public function getValue( $field ) { if ( array_key_exists( $field, $this->data )) { return $this->data[$field]; } else { die( "field not found" ); } } public function getValueEncoded( $field ) { return htmlspecialchars( $this->getValue( $field )); } protected function connect() { try { $conn = new PDO(DB_DSN, DB_USERNAME, DB_PASSWORD ); $Conn->setAttribute( PDO::ATTR_PERSISTENT, true ); $conn->setAttribute( PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION ); } catch ( PDOException $e->getMessage() ); die( "connection failed: " . $e->getMessage() ); } return $conn; } protected function disconnect( $conn ) { $conn = ""; } } ?> |