PHP - Querry Mysql Database And Return Multiple Results - Please Please Help

Given the below 3 database tables I am trying to construct a SQL query that will give me the following result:

customer_favourites.cust_id
customer_favourites.prod_id OR product.id
product.code
product.product_name
product.hidden
product_ section.section_id (MUST BE ONLY THE ROW WITH THE LOWEST SECTION ID, I.E. ROW ID #44108)
product_ section.catpage (MUST BE ONLY THE ROW WITH THE LOWEST SECTION ID, I.E. ROW ID #44108)
product_ section.relative_order (MUST BE ONLY THE ROW WITH THE LOWEST SECTION ID, I.E. ROW ID #44108)

I currently have....

SELECT customer_favourites.cust_id, customer_favourites.prod_id, product.code, product.product_name, product.hidden, product_section.section_id, product_section.relative_order, product_section.catpage  
FROM customer _favourites  
INNER JOIN product ON customer_favourites.prod_id = product.id  
INNER JOIN product_section ON product_section.product_code = product.code  
WHERE `cust_id` = '17' AND `hidden` = '0' GROUP BY `code`  
ORDER BY `section_id` ASC, `relative_order` ASC, `catpage` ASC LIMIT 0,30

This gives me what I want but only sometimes, at other times it randomly selects any row from the product_section table.

I was hoping that by having the row I want as the last row (most recent added) in the product_section table then it would select that row by default but it is not consistent.

Somehow, I need to be able to specify which row to return in the product_section table, it needs to be the row with the lowest section_id value or it should by the last row (most recent).

Pulling my hair out so any help is gratefully received.  
customer_favourites

id     cust_id   prod_id
70    4            469
product

id        code           product_name    hidden
469    ABC123     My Product        0
product_section

id                  section_id      catpage    product_code    relative_order     recommended
44105         19                   232            ABC123             260                    1
44106          3                     125            ABC123              87                      1
44107          2                     98              ABC123             128                     1
44108          1                    156             ABC123             58                        0

 

Hi

I have got results being displayed after clicking the search button in a form on my home page but it brings up all the results which is ok but how do I get onlt the results a user searches for for example a location or property type etc as its for a property website

The coding is below for the results page

Also sorry how do I add a background image to the php page, I tried using css but wouldn't work

Code: [Select]
<style type="text/css">
body {background-image:url('images/greybgone.png');}
</style>

<?php
 
mysql_connect ("2up2downhomes.com.mysql", "2up2downhomes_c","mD8GsJKQ")  or die (mysql_error());
mysql_select_db ("2up2downhomes_c");

echo $_POST['term'];

$sql = mysql_query("select * from properties where typeProperty like '%$term%' or location like '%$term%'");

while ($row = mysql_fetch_array($sql)){
    echo 'Type of Property: '.$row['typeProperty'];
    echo '<br/> Number of Bedrooms: '.$row['bedrooms'];
    echo '<br/> Number of Bathrooms: '.$row['bathrooms'];
echo '<br/> Garden: '.$row['garden'];
echo '<br/> Description: '.$row['description'];
echo '<br/> Price: '.$row['price'];
echo '<br/> Location: '.$row['location'];
echo '<br/> Image: '.$row['image'];
    echo '<br/><br/>';
    }
 
?>

Hi,
This has been baffling me for a couple hours now and i cant seem to figure it out.
I have some code which creates an array and gets info from a mysql database and then displays in a list. This works great but after adding more and more rows to my database the list is now becoming quite large and doesnt look great on my site.
Is it possible to split the list into multiple columns of about 25 and if possible once 3 or 4 columns have been created start another column underneath.
To help explain i would be looking at a layout as follows:
Code: [Select]
line 1      line 1      line 1
line 2      line 2      line 2
...      ...      ...
line 25      line 25      line 25

line 1      line 1      line 1
line 2      line 2      line 2
...      ...      ...
line 25      line 25      line 25Im guessing there should be some sort of if statement to check how many items are being displayed and to create a new column if necessary. Is this correct?

Thanks,
Alex

I have a simple (1 table, 14 fields) database. I'm using 9 separate search boxes from my search page :
http://www.cinemaposter.com/database.html
There are currently 162 entries. Hitting "submit" throws them all out, same with valid input into any box, with the exception of "country" - example  : entering "F" gives 20results; "PL" gives 34 results.
Here's my code (to simplify, I only went down to the 4th box ('country' - the last and only one giving correct results).  I'm one sorry newbie.... please help !
Here's the code :
------------------

<!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.0 Transitional//EN"
"http://www.w3.org/TR/1998/REC-html40-19980424/loose.dtd">
<html>
<head>
   <title>Search Results</title>
   <meta name="generator" content="BBEdit 6.5">
   <style type="text/css">
td
{
   color: #000000;
   font-family: arial;
   font-size: 10px;
}
</style>
</head>
<body>
<?php
$link = mysql_connect("xxxx", "xxxx", "xxxx") or die("Could not connect");
///print "Connected successfully<BR>";
mysql_select_db("xxxx") or die("Could not select database");


{
$Author = $_POST['Author'];
$sql = "SELECT * FROM posters WHERE Author LIKE '%$Author%'";
}

{
$Title = $_POST['Title'];
$sql = "SELECT * FROM posters WHERE Title LIKE '%$Title%'";
}

{
$Originaltitle =$_POST['Originalitle'];
$sql="SELECT * FROM posters WHERE Originaltitle LIKE '%$Originaltitle%'";
}

{
$Country =$_POST['Country'];
$sql="SELECT * FROM posters WHERE Country LIKE '%$Country%'";
}


$result = mysql_query ($sql) or die("Query failed : " . mysql_error());
$numrs = mysql_num_rows($result);

if ($numrs > 0){

if ($numrs==1){
   print ("<p><font face=\"Arial\"><b>There is $numrs record in our database.</B> <BR><BR>");
   }elseif($numrs>1){
   print ("<p><font face=\"Arial\"><b>There are $numrs records in our database. </B><BR><BR>");//Apparently, he wan't to be able to search again...</b><form method \"POST\" action=\"$PHP_SELF\">Search Again:");
   }
   
   
   
   
  echo("<a href='javascript:history.go(-1)'>Go Back</a></p>");
  print("<P align=center>Click on the column heading links to sort the results.<br><br />");   
   
print ("<TABLE CELLPADDING=\"1\" CELLSPACING=\"2\" BORDER=\"0\">\n");
PRINT ("<TR BGCOLOR=\"#FFFF77\">
<TD COLSPAN=2><P align=center>Author</td>
<TD><P align=center>Title</TD>
<TD><P align=center>Original Title</TD>
<TD><P align=center>Country</TD>
<TD><P align=center>Director</TD>
<TD><P align=center>Cast</TD>
<TD><P align=center>Year</TD>
<TD><P align=center>Original Year</TD>
<TD><P align=center>Photo</TD>
<TD><P align=center>Producer</TD>
<TD><P align=center>Circulation</TD>
<TD><P align=center>Size</TD>
<TD><P align=center>Print type</TD>
<TD><P align=center>Remarks</TD></TR>");

$z=1;
      while ($line = mysql_fetch_array($result)) {
      
         $num=$z++;
         //Note here that I'm assigning the found objects new names (indicated by lowercase) to that php wont get confused.....
         $auth=$line['Author'];
         $title=$line['Title'];
         $originaltitle=$line['Originaltitle'];
         $country=$line['Country'];
         $director=$line['Director'];
         $cast=$line['Cast'];
         $year=$line['Year'];
         $originalyear=$line['Originalyear'];
         $producer=$line['Producer'];
         $circ=$line['Circulation'];
         $size=$line['Size'];
         $print=$line['Print'];
         $remarks=$line['Remarks'];
         $pict=$line['Picture'];


         //Set the formatting
         $bgcolor = ($i++ & 1) ? '#d3d3d3' : '#c0c0c0';
         
                           
      PRINT("<TR BGCOLOR=$bgcolor>
      <TD>$num.</TD>
      <TD>$auth</td>
      <TD>$title</TD>
      <TD>$originaltitle</TD>
      <TD><P align=center>$country</TD>
      <TD>$director</TD>
      <TD>$cast</TD>
      <TD><P align=center>$year</TD>
      <TD><P align=center>$originalyear</TD><TD>");
// This is the test to find do we have a picture
if ($pict) {
// If there is a picture, display it:
print ("<P align=center><a href='zdjecie.php?zdj= $pict&autor=$auth&opis=$title&orig=$originaltitle&rok=$year' target='_blank'>
<img src=$pict height=\"150\"></a>");
} else {

// We don't have a picture, so we print some text instead:
print ("<P align=center>no picture available");
}

print ("</TD><TD>$producer</TD>
<TD><P align=center>$circ</TD>
<TD>$size</TD>
<TD>$print</TD>
<TD>$remarks</TD></TR>");
            
         }
      PRINT("</TABLE><BR><font face=\"Arial\"><a href=\"javascript:history.go(-1);\">Search Again</a></font>");
   }else {
   print ("<font face=\"Arial\">Sorry, there were no results for your search. <a href=\"javascript:history.go(-1);\">Please try again</a></font>");
   }
//mysql_close($link);
?>                                                                     
</body>
</html>