PHP - Question About Multiple Boxes
I want to create a calculator that allows you to type in how many pieces of data you have, or how many averages you have. Once that is done, the amount of boxes pop up correctly - and you can enter in your data. But how can I get all those pieces of data from EACH box using one form?
Current Example: http://novacms.vacau.com/ Code: <?php $boxes = $_POST['input']; if(!$boxes) { echo '<b>How many pieces of data do you have?</b> <form action="index.php" method="POST"><input type="text" name="input"><input type="submit"></form><br/><font size="2">Ex: 88.8,92.3,76.5 - That would be 3 pieces of data</font>'; } else { echo '<form action="index.php" method="POST">'; for($i = 0; $i <= $boxes; $i++) { echo '<input type="text"><br/>'; } echo '<input type="submit" value="Get average"></form>'; } ?> Similar TutorialsIs it possible to have multiple check boxes on a single form and a single submit button tp post the values into different rows of DB Kenny Hi I am trying to have the following as an example: Code: [Select] <select name="test[]" multiple="multiple">options here</select> <select name="test[]" multiple="multiple">options here</select> Then using $_POST['test'] to grab the boxes in the array. I want to then loop over each box so for example: Code: [Select] $boxes = $_POST['test']; foreach ( $boxes as $box ) // now here i would of expected $box to be an array of the options, } but it's not working like this, all the options from all submitted select boxes come in one array so I cannot distinguish which select box in the array they relate to, is there a way to do this?? Hi guys, I am struggling with a form containing multiple checkboxes with corresponding textboxes. Eg.: there are 5 checkboxes (XS, S, M, L, XL) and 5 textboxes (with values 3,4,5,6,8) that correspond to the checkboxes. I give all the checkboxes the name 'size[]' and the textboxes the name 'price[]'. The aim is to have my script set a boolean to true and update the corresponding price if the checkbox is selected. Unfortunately it does not work this way: checkboxes are only put in the array when they are selected, meaning that if I select only checkbox S and L, the array length is 2 only, but array length price is always 5, so size[1] does not correspond to price[1] necessarily. There probably is a better way to achieve what I need. Could anyone point me in the right direction? edit: BTW the number of items is dynamic: sometimes there will also be XXL or some items will be missing and I also need to set the price for items where the checkbox is not checked. I have a simple (1 table, 14 fields) database. I'm using 9 separate search boxes from my search page : http://www.cinemaposter.com/database.html There are currently 162 entries. Hitting "submit" throws them all out, same with valid input into any box, with the exception of "country" - example : entering "F" gives 20results; "PL" gives 34 results. Here's my code (to simplify, I only went down to the 4th box ('country' - the last and only one giving correct results). I'm one sorry newbie.... please help ! Here's the code : ------------------ <!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.0 Transitional//EN" "http://www.w3.org/TR/1998/REC-html40-19980424/loose.dtd"> <html> <head> <title>Search Results</title> <meta name="generator" content="BBEdit 6.5"> <style type="text/css"> td { color: #000000; font-family: arial; font-size: 10px; } </style> </head> <body> <?php $link = mysql_connect("xxxx", "xxxx", "xxxx") or die("Could not connect"); ///print "Connected successfully<BR>"; mysql_select_db("xxxx") or die("Could not select database"); { $Author = $_POST['Author']; $sql = "SELECT * FROM posters WHERE Author LIKE '%$Author%'"; } { $Title = $_POST['Title']; $sql = "SELECT * FROM posters WHERE Title LIKE '%$Title%'"; } { $Originaltitle =$_POST['Originalitle']; $sql="SELECT * FROM posters WHERE Originaltitle LIKE '%$Originaltitle%'"; } { $Country =$_POST['Country']; $sql="SELECT * FROM posters WHERE Country LIKE '%$Country%'"; } $result = mysql_query ($sql) or die("Query failed : " . mysql_error()); $numrs = mysql_num_rows($result); if ($numrs > 0){ if ($numrs==1){ print ("<p><font face=\"Arial\"><b>There is $numrs record in our database.</B> <BR><BR>"); }elseif($numrs>1){ print ("<p><font face=\"Arial\"><b>There are $numrs records in our database. </B><BR><BR>");//Apparently, he wan't to be able to search again...</b><form method \"POST\" action=\"$PHP_SELF\">Search Again:"); } echo("<a href='javascript:history.go(-1)'>Go Back</a></p>"); print("<P align=center>Click on the column heading links to sort the results.<br><br />"); print ("<TABLE CELLPADDING=\"1\" CELLSPACING=\"2\" BORDER=\"0\">\n"); PRINT ("<TR BGCOLOR=\"#FFFF77\"> <TD COLSPAN=2><P align=center>Author</td> <TD><P align=center>Title</TD> <TD><P align=center>Original Title</TD> <TD><P align=center>Country</TD> <TD><P align=center>Director</TD> <TD><P align=center>Cast</TD> <TD><P align=center>Year</TD> <TD><P align=center>Original Year</TD> <TD><P align=center>Photo</TD> <TD><P align=center>Producer</TD> <TD><P align=center>Circulation</TD> <TD><P align=center>Size</TD> <TD><P align=center>Print type</TD> <TD><P align=center>Remarks</TD></TR>"); $z=1; while ($line = mysql_fetch_array($result)) { $num=$z++; //Note here that I'm assigning the found objects new names (indicated by lowercase) to that php wont get confused..... $auth=$line['Author']; $title=$line['Title']; $originaltitle=$line['Originaltitle']; $country=$line['Country']; $director=$line['Director']; $cast=$line['Cast']; $year=$line['Year']; $originalyear=$line['Originalyear']; $producer=$line['Producer']; $circ=$line['Circulation']; $size=$line['Size']; $print=$line['Print']; $remarks=$line['Remarks']; $pict=$line['Picture']; //Set the formatting $bgcolor = ($i++ & 1) ? '#d3d3d3' : '#c0c0c0'; PRINT("<TR BGCOLOR=$bgcolor> <TD>$num.</TD> <TD>$auth</td> <TD>$title</TD> <TD>$originaltitle</TD> <TD><P align=center>$country</TD> <TD>$director</TD> <TD>$cast</TD> <TD><P align=center>$year</TD> <TD><P align=center>$originalyear</TD><TD>"); // This is the test to find do we have a picture if ($pict) { // If there is a picture, display it: print ("<P align=center><a href='zdjecie.php?zdj= $pict&autor=$auth&opis=$title&orig=$originaltitle&rok=$year' target='_blank'> <img src=$pict height=\"150\"></a>"); } else { // We don't have a picture, so we print some text instead: print ("<P align=center>no picture available"); } print ("</TD><TD>$producer</TD> <TD><P align=center>$circ</TD> <TD>$size</TD> <TD>$print</TD> <TD>$remarks</TD></TR>"); } PRINT("</TABLE><BR><font face=\"Arial\"><a href=\"javascript:history.go(-1);\">Search Again</a></font>"); }else { print ("<font face=\"Arial\">Sorry, there were no results for your search. <a href=\"javascript:history.go(-1);\">Please try again</a></font>"); } //mysql_close($link); ?> </body> </html> Hi, guys. I am a php newb and stuck (see title). I it will only send the value of 1 tick box over to the page "delete_message.php" This is what i have so far: Code: [Select] <?php // get messages $result = mysql_query("SELECT * FROM tbl_pvt_msg WHERE to_UID='$UID'"); if (!$result) die("Query to show fields from table failed"); while ($data=mysql_fetch_array($result)) { $_SESSION['from_UID']=$data['1']; UIDtoemail(); $from_email=$_SESSION['from_email']; $contents=$data['3']; $timesent=$data['4']; $msg_ID=$data['0']; echo "<form action='scripts/delete_message.php' method='POST' >"; echo "<tr><td>$from_email</td><td>$contents</td><td>$timesent</td><td><input type='checkbox' value='$msg_ID' name='msg_ID' /></td> </tr>"; } // turn uid into email function UIDtoemail(){ $from_UID=$_SESSION['from_UID']; $result = mysql_query("SELECT * FROM tbl_usr WHERE UID='$from_UID'"); if (!$result) die("Query to show fields from table failed"); $data=mysql_fetch_array($result); $_SESSION['from_email']=$data['7']; } ?> </table> <input type="submit" value="Delete" id="delete" /> </form> I am attempting to submit a form that includes multiple check boxes for one data field. I have set it up the implode the data and make it a comma delimited array. I am able to echo the results, yet I have not been able to post the information to the database. I believe that I have just one simple thig to do, yet I am not being successful. Here is my code I have attached the .txt file also: <?php require_once('Connections/rotarysantarosa.php'); ?> <?php if (isset($_POST['submit'])) { if (isset($_POST['currentClubPosition'])) { $strcurrentClubPosition = implode(",", $_POST['currentClubPosition']); } else { $strcurrentClubPosition = ""; } } ?> <?php if (!function_exists("GetSQLValueString")) { function GetSQLValueString($theValue, $theType, $theDefinedValue = "", $theNotDefinedValue = "") { if (PHP_VERSION < 6) { $theValue = get_magic_quotes_gpc() ? stripslashes($theValue) : $theValue; } $theValue = function_exists("mysql_real_escape_string") ? mysql_real_escape_string($theValue) : mysql_escape_string($theValue); switch ($theType) { case "text": $theValue = ($theValue != "") ? "'" . $theValue . "'" : "NULL"; break; case "long": case "int": $theValue = ($theValue != "") ? intval($theValue) : "NULL"; break; case "double": $theValue = ($theValue != "") ? doubleval($theValue) : "NULL"; break; case "date": $theValue = ($theValue != "") ? "'" . $theValue . "'" : "NULL"; break; case "defined": $theValue = ($theValue != "") ? $theDefinedValue : $theNotDefinedValue; break; } return $theValue; } } $editFormAction = $_SERVER['PHP_SELF']; if (isset($_SERVER['QUERY_STRING'])) { $editFormAction .= "?" . htmlentities($_SERVER['QUERY_STRING']); } if ((isset($_POST["MM_insert"])) && ($_POST["MM_insert"] == "frmMemberInsert")) { $insertSQL = sprintf("INSERT INTO members (firstName, lastName, photo, pastPresident, currentClubPosition, classification, workPosition, company, workAddress, workCity, workState, workZip, officePhone, fax, homePhone, cellPhone, email, website, homeAddress, homeCity, homeState, homeZip, birthdayMonth, birthdayDay, spouse, yearJoined) VALUES (%s, %s, %s, %s, %s, %s, %s, %s, %s, %s, %s, %s, %s, %s, %s, %s, %s, %s, %s, %s, %s, %s, %s, %s, %s, %s)", GetSQLValueString($_POST['firstName'], "text"), GetSQLValueString($_POST['lastName'], "text"), GetSQLValueString($_POST['photo'], "text"), GetSQLValueString($_POST['pastPresident'], "text"), GetSQLValueString($_POST['currentClubPosition'], "text"), GetSQLValueString($_POST['classification'], "text"), GetSQLValueString($_POST['workPosition'], "text"), GetSQLValueString($_POST['company'], "text"), GetSQLValueString($_POST['workAddress'], "text"), GetSQLValueString($_POST['workCity'], "text"), GetSQLValueString($_POST['workState'], "text"), GetSQLValueString($_POST['workZip'], "text"), GetSQLValueString($_POST['officePhone'], "text"), GetSQLValueString($_POST['fax'], "text"), GetSQLValueString($_POST['homePhone'], "text"), GetSQLValueString($_POST['cellPhone'], "text"), GetSQLValueString($_POST['email'], "text"), GetSQLValueString($_POST['website'], "text"), GetSQLValueString($_POST['homeAddress'], "text"), GetSQLValueString($_POST['homeCity'], "text"), GetSQLValueString($_POST['homeState'], "text"), GetSQLValueString($_POST['homeZip'], "text"), GetSQLValueString($_POST['birthdayMonth'], "text"), GetSQLValueString($_POST['birthdayDay'], "int"), GetSQLValueString($_POST['spouse'], "text"), GetSQLValueString($_POST['yearJoined'], "int")); mysql_select_db($database_rotarysantarosa, $rotarysantarosa); $Result1 = mysql_query($insertSQL, $rotarysantarosa) or die(mysql_error()); $insertGoTo = "members.php"; if (isset($_SERVER['QUERY_STRING'])) { $insertGoTo .= (strpos($insertGoTo, '?')) ? "&" : "?"; $insertGoTo .= $_SERVER['QUERY_STRING']; } header(sprintf("Location: %s", $insertGoTo)); } mysql_select_db($database_rotarysantarosa, $rotarysantarosa); $query_rsStates = "SELECT * FROM states ORDER BY stateName ASC"; $rsStates = mysql_query($query_rsStates, $rotarysantarosa) or die(mysql_error()); $row_rsStates = mysql_fetch_assoc($rsStates); $totalRows_rsStates = mysql_num_rows($rsStates); mysql_select_db($database_rotarysantarosa, $rotarysantarosa); $query_rsMemberInsert = "SELECT * FROM members ORDER BY lastName ASC"; $rsMemberInsert = mysql_query($query_rsMemberInsert, $rotarysantarosa) or die(mysql_error()); $row_rsMemberInsert = mysql_fetch_assoc($rsMemberInsert); $totalRows_rsMemberInsert = mysql_num_rows($rsMemberInsert); mysql_select_db($database_rotarysantarosa, $rotarysantarosa); $query_rsClubPosition = "SELECT * FROM clubpositions ORDER BY `Club Position` ASC"; $rsClubPosition = mysql_query($query_rsClubPosition, $rotarysantarosa) or die(mysql_error()); $row_rsClubPosition = mysql_fetch_assoc($rsClubPosition); $totalRows_rsClubPosition = mysql_num_rows($rsClubPosition); mysql_select_db($database_rotarysantarosa, $rotarysantarosa); $query_rsClassification = "SELECT * FROM classifications ORDER BY Classification ASC"; $rsClassification = mysql_query($query_rsClassification, $rotarysantarosa) or die(mysql_error()); $row_rsClassification = mysql_fetch_assoc($rsClassification); $totalRows_rsClassification = mysql_num_rows($rsClassification); mysql_select_db($database_rotarysantarosa, $rotarysantarosa); $query_rsBirthMonth = "SELECT * FROM birthdaymonth"; $rsBirthMonth = mysql_query($query_rsBirthMonth, $rotarysantarosa) or die(mysql_error()); $row_rsBirthMonth = mysql_fetch_assoc($rsBirthMonth); $totalRows_rsBirthMonth = mysql_num_rows($rsBirthMonth); mysql_select_db($database_rotarysantarosa, $rotarysantarosa); $query_rsBirthDay = "SELECT * FROM birthdayday ORDER BY birthdayday ASC"; $rsBirthDay = mysql_query($query_rsBirthDay, $rotarysantarosa) or die(mysql_error()); $row_rsBirthDay = mysql_fetch_assoc($rsBirthDay); $totalRows_rsBirthDay = mysql_num_rows($rsBirthDay); ?> I have a form that has a section where you can pick multiple check boxes and when the info is returned to me it has the word Array at the end of it. There are 2 check boxes on the form one fo Steve and one for Ben Below is the code I am using in my PHP file foreach($_POST['TestGroup'] as $val) { echo $val . "\n"; } The output from the PHP code is----Steve Ben Array.------ How do I keep Array from coming up? Hello, Iv written a small script in JS to add input boxes of the type file to the page.. My problem is when i use multiple of those input boxes and submit the form the $_FILES variable only reads 1 of those boxes.. This is the javascript im using: Code: [Select] function addImageBox() { var imageBoxes = document.getElementById("imageBoxes"); var tr = document.createElement("tr"); var td = document.createElement("td"); var td2 = document.createElement("td"); var inputFile = document.createElement("input"); inputFile.setAttribute("type", "file"); inputFile.setAttribute("name", "image[]"); inputFile.setAttribute("style", "width: 450px"); td.appendChild(document.createTextNode("Image")); td2.appendChild(inputFile); tr.appendChild(td); tr.appendChild(td2); imageBoxes.appendChild(tr); } When i add 2 boxes (making it 3 boxes on the page in total) and count the $_FILES var after submiting the form, the count method returns 1, and when i var_dump it only 1 array is in $_FILES. Any idea's? thanks! I need some help with the query for a form that selects values across multiple columns, and allow users to select multiple values in several columns. http://brinsterinc.com/tpa/tpasearch.php I assume you build the where clause for the sql by determining if there is an option value has been selected in the single-value select boxes. But how do I handle the multi-select list boxes? I'm desperate for help! Need to get somewhere with this over the weekend! TIA! hello. i have a question for you. say i have a group of tick boxes and i select a couple. would i put them in to the database as varchar ? like this: id varchar 1 1, 2, 3 or id varchar 1 '1', '2', '3' then my next question is how would i use them. i guess i would explode them or something. the thing is, i have some code that currently pull 1 item from the database (using varchar) and echos it fine but when i add more i get nothing back. thanks rick Hello, I had 8 select boxes(dropdowns) in a form. Its like a search kind of implementation in the website. I don't know what the user selects, he may choose different select boxes, any number of select boxes. So, based upon the user selection, I need to generate the data. The data fields to be generated would be almost same. So, How would I know what the user selection is and how many select boxes has been selected and how could I generate different data based upon selected boxes. I had to make a small note abt this, that the data generation fields may change for some of the user select combinations, but most of the result fields would be same. so, can you please help me out, how to do, how to make different combination data generations, because, i had 8 fields, i had to make 8! combinations, that would result in a big code. This may sound like a very stupid question, but I can't find a clear answer anywhere. I'm making my first dive in OOP and all the tutorials only really show basic usage. They define a class, and show how to use it in a file. My question is how does it work to use an object throughout a program? Is it available everywhere or do I store things in sessions and start a new object on each page? For example: logging in a user. If I created an instance after confirming the credentials, would that same instance be available for use in say index.php, or would I just pass a session over and create a new instance on each page? Again, sorry if this seems dumb to some people. This topic has been moved to MySQL Help. http://www.phpfreaks.com/forums/index.php?topic=351561.0 First, Happy X-Mas to all! I want to do a form for entering dog-show results. On first site of form the user is able to enter how many dogs for each class (there are youth and open class for example) he want to insert. So on second site there will be formfields for every dog in every class, created with php. User should be able to take dogname from jquery autocomplete - this works for multiple fields. But i need the according id to the dogname - and actual only one id is given - the first one is changing by choosing from autocomplete in next fields... Data came from a json array like 0: {dogidindatabase: "9892", value: "Excalibur Khali des Gardiens de la Cour ",…} dogidindatabase: "9892" label: "<img src='../main/img/female.png' height='20'>Excalibur Khali des Gardiens de la Cour " value: "Excalibur Khali des Gardiens de la Cour " 1: {dogidindatabase: "15942", value: "Excalibur from Bandit's World Kalli",…} dogidindatabase: "15942" label: "<img src='../main/img/male.png' height='20'>Excalibur from Bandit's World Kalli" value: "Excalibur from Bandit's World Kalli"all i need is inside ... the script in form is <script type='text/javascript'> //<![CDATA[ $(function() { $(".dog").autocomplete({ source: "xxx.php", minLength: 3, select: function(event, ui) { $('#dogidindatabase').val(ui.item.dogidindatabase); } }); $["ui"]["autocomplete"].prototype["_renderItem"] = function( ul, item) { return $( "<li></li>" ) .data( "item.autocomplete", item ) .append( $( "<a></a>" ).html( item.label ) ) .appendTo( ul ); }; }); //]]> </script>and the form looked like <input type='text' name='dog' class='dog' value='".strip_tags(${'dogname' .($countbabymale+1)})."' size='35' data-required='true' /><br> <input class='readonly' readonly='readonly' type='text' id='dogidindatabase' name='dogidindatabase' size='5' />I changed in script and form id='dogidindatabase' to class, but it doesn´t work. Testsite is under http://www.wolfdog-d...how.php?lang=de (only german at first) - Insert a number (higher than 1) under baby 3-6 (first box, the others are not working for testing); submit to get to page 2; you see all post-variables (for testing). Try to insert a dogname in first input-field (choose "exc") and insert first one - the id is under dogname. In second dogname inputfield you can choose second dog - the id for the first one changes to id of seond one .... How can i get both for every dog? Ok I'm trying to insert multiple rows by using a while loop but having problems. At the same time, need to open a new mysql connection while running the insert query, close it then open the previous mysql connection. I managed to insert multiple queries before using a loop, but for this time, the loop does not work? I think it is because I am opening another connection... yh that would make sense actually? Here is the code: $users = safe_query("SELECT * FROM ".PREFIX."user"); while($dp=mysql_fetch_array($users)) { $username = $dp['username']; $nickname = $dp['nickname']; $pwd1 = $dp['password']; $mail = $dp['email']; $ip_add = $dp['ip']; $wsID = $dp['userID']; $registerdate = $dp['registerdate']; $birthday = $dp['birthday']; $avatar = $dp['avatar']; $icq = $dp['icq']; $hp = $dp['homepage']; echo $username." = 1 username only? :("; // ----- Forum Bridge user insert ----- $result = safe_query("SELECT * FROM `".PREFIX."forum`"); $ds=mysql_fetch_array($result); $forum_prefix = $ds['prefix']; define(PREFIX_FORUM, $forum_prefix); define(FORUMREG_DEBUG, 0); $con = mysql_connect($ds['host'], $ds['user'], $ds['password']) or system_error('ERROR: Can not connect to MySQL-Server'); $condb = mysql_select_db($ds['db'], $con) or system_error('ERROR: Can not connect to database "'.$ds['db'].'"'); include('../_phpbb_func.php'); $phpbbpass = phpbb_hash($pwd1); $phpbbmailhash = phpbb_email_hash($mail); $phpbbsalt = unique_id(); safe_query("INSERT INTO `".PREFIX_FORUM."users` (`username`, `username_clean`, `user_password`, `user_pass_convert`, `user_email`, `user_email_hash`, `group_id`, `user_type`, `user_regdate`, `user_passchg`, `user_lastvisit`, `user_lastmark`, `user_new`, `user_options`, `user_form_salt`, `user_ip`, `wsID`, `user_birthday`, `user_avatar`, `user_icq`, `user_website`) VALUES ('$username', '$username', '$phpbbpass', '0', '$mail', '$phpbbmailhash', '2', '0', '$registerdate', '$registerdate', '$registerdate', '$registerdate', '1', '230271', '$phpbbsalt', '$ip_add', '$wsID', '$birthday', '$avatar', '$icq', '$hp')"); if (FORUMREG_DEBUG == '1') { echo "<p><b>-- DEBUG -- : User added: ".mysql_affected_rows($con)."<br />"; echo "<br />-- DEBUG -- : Query used: ".end($_mysql_querys)."</b></p><br />"; $result = safe_query("SELECT user_id from ".PREFIX_FORUM."users WHERE username = '$username'"); $phpbbid = mysql_fetch_row($result); safe_query("INSERT INTO `".PREFIX_FORUM."user_group` (`group_id`, `user_id`, `group_leader`, `user_pending`) VALUES ('2', '$phpbbid[0]', '0', '0')"); safe_query("INSERT INTO `".PREFIX_FORUM."user_group` (`group_id`, `user_id`, `group_leader`, `user_pending`) VALUES ('7', '$phpbbid[0]', '0', '0')"); mysql_close($con); } include('../_mysql.php'); mysql_connect($host, $user, $pwd) or system_error('ERROR: Can not connect to MySQL-Server'); mysql_select_db($db) or system_error('ERROR: Can not connect to database "'.$db.'"'); } So I need to be able to insert these rows using the while loop.. how can I do this? I really appreciate any help. Ok so i want to grab an id from the checkbox then grab the option drop down associated with that check box and update a mysql row here is my code so far any help is awesome help taaaanks guys <?php mysql_connect("localhost", "root", "root") or die(mysql_error()); mysql_select_db("db1") or die(mysql_error()); $query = "SELECT * FROM tickets ORDER BY id DESC"; $result = mysql_query($query) or die(mysql_error()); while($row = mysql_fetch_array($result)) { print "<input name='delete[]' value='{$row['id']}' type='checkbox'>"; mysql_connect("localhost", "root", "root") or die(mysql_error()); mysql_select_db("db1") or die(mysql_error()); $query2 = "SELECT * FROM admin"; $result2 = mysql_query($query2) or die(mysql_error()); print "<form name='namestoupdate' method='post' action='update.php'>\n"; print '<select>'; while($row2 = mysql_fetch_array($result2)) { if ($row2['priv']==prov){print '<option value="'.$row2['user'].'" name="prov['.$i++.']">'.$row2['user'].'</option>';} } print '</select>'; print "<input type='submit' value='submit' />"; print "</form>"; } ?> Visual aid This seems to be a bit of a challenge but I am creating a multiple page form and on one of the pages I have a select field. I would like the user to have the ability to select multiple options but I am using some functions to move the data in hidden fields from page to page. I don't think my functions are jiving with my my foreach loop cause I keep getting an invalid argument error. Thanks in advance for any help. Here is my function: function setSelected($fieldName, $fieldValue) { if(isset($_POST[$fieldName]) && $_POST[$fieldName] == $fieldValue) { echo 'selected="selected"'; } } And here is my loop: $selections = ""; if(isset($_POST["selections"])) { foreach ($_POST["selections"] as $selection) { $selections .= $selection . ", "; } } Hello all, I am trying to learn OOP in PHP so please forgive my ignorance. I seem to be having difficulty inserting data into my database from checkbox items. My database has a column for each each fruit. I would like for each column to be populated with either a one(1) for checked or a zero(0) for not checked. Currently, my attempts have failed. I can either get all checkboxes to insert all zeros or I can get the first column to insert a one(1) while the others as zeros. Is there anybody here that can help me figure out what I am doing wrong and help me to re-work my code so I can get this to work? If anybody can help me using OOP methods that would be fantastic. Thank you all in advance.
$preffruit->create_preffruit(array( 'fruit_apple' => escape(Input::get(['fruit_selection'][0]) ? 1 : 0), 'fruit_orange' => escape(Input::get(['fruit_selection'][1]) ? 1 : 0), 'fruit_banana' => escape(Input::get(['fruit_selection'][2]) ? 1 : 0), 'fruit_pear' => escape(Input::get(['fruit_selection'][3]) ? 1 : 0), 'fruit_kiwi' => escape(Input::get(['fruit_selection'][4]) ? 1 : 0) )); <input type="checkbox" name="fruit_selection[]" value="fruit_apple"> <input type="checkbox" name="fruit_selection[]" value="fruit_orange"> <input type="checkbox" name="fruit_selection[]" value="fruit_banana"> <input type="checkbox" name="fruit_selection[]" value="fruit_pear"> <input type="checkbox" name="fruit_selection[]" value="fruit_kiwi"> public function insert_preffruit($table, $fields = array()) { $keys = array_keys($fields); $values = ''; $x = 1; foreach($fields as $field) { $values .= '?'; if($x < count($fields)) { $values .= ', '; } $x++; } $sql = "INSERT INTO preffruit (`user_id`, `" . implode('`, `', $keys) . "`) VALUES (LAST_INSERT_ID(), {$values})"; if(!$this->query($sql, $fields)->error()) { return true; } return false; } Edited September 23, 2020 by ke-jo I am trying to export multiple csv files to download from 2 separate tables in my database. Some background: I have a web app that links to a phpmyadmin database. There are 2 tables in the database (entering and exiting). These tables hold the phone inventory information of employees currently entering or exiting the organization. The fields in my tables a location, firstname, lastname, username, extension, mac, type What I am trying to do is export the data in these 2 tables to CSV (which I have working now) but I need to have multiple CSVs for each. For example, for my exiting table, I need to have one CSV export all the fields in the table and I also need another CSV to export just the location and username field. I have a simple html form with a submit button which is currently working now: <form action="exportexiting.php" method="POST" style="width: 456px; height: 157px"> <div> <fieldset> <legend style="width: 102px; height: 25px"><strong>Entering CSV:</strong></legend> <input name="Export" type="submit" id="Export" value="Export"> </fieldset><br/> </div> </form> This links to my exportexiting.php file: <?php $host = 'localhost'; $user = 'root'; $pass = 'xxxx'; $db = 'PhoneInventory'; $table = 'exiting'; // Connect to the database $link = mysql_connect($host, $user, $pass); mysql_select_db($db); require 'exportcsv.inc.php'; exportMysqlToCsv($table); ?> Then to exportcsv.inc.php: <?php function exportMysqlToCsv($table,$filename = 'export.csv') { $csv_terminated = "\n"; $csv_separator = ","; $csv_enclosed = ''; $csv_escaped = "\\"; $sql_query = "select * from $table"; // Gets the data from the database $result = mysql_query($sql_query); $fields_cnt = mysql_num_fields($result); $schema_insert = ''; for ($i = 0; $i < $fields_cnt; $i++) { $l = $csv_enclosed . str_replace($csv_enclosed, $csv_escaped . $csv_enclosed, stripslashes(mysql_field_name($result, $i))) . $csv_enclosed; $schema_insert .= $l; $schema_insert .= $csv_separator; } // end for $out = trim(substr($schema_insert, 0, -1)); $out .= $csv_terminated; // Format the data while ($row = mysql_fetch_array($result)) { $schema_insert = ''; for ($j = 0; $j < $fields_cnt; $j++) { if ($row[$j] == '0' || $row[$j] != '') { if ($csv_enclosed == '') { $schema_insert .= $row[$j]; } else { $schema_insert .= $csv_enclosed . str_replace($csv_enclosed, $csv_escaped . $csv_enclosed, $row[$j]) . $csv_enclosed; } } else { $schema_insert .= ''; } if ($j < $fields_cnt - 1) { $schema_insert .= $csv_separator; } } // end for $out .= $schema_insert; $out .= $csv_terminated; } // end while header("Cache-Control: must-revalidate, post-check=0, pre-check=0"); header("Content-Length: " . strlen($out)); // Output to browser with appropriate mime type, you choose header("Content-type: text/x-csv"); //header("Content-type: text/csv"); //header("Content-type: application/csv"); header("Content-Disposition: attachment; filename=$filename"); echo $out; exit; } ?> Again, this is working perfectly for only exporting all the data from the exiting table into one CSV file. My question is, how can I make my one submit button export the 2 CSV files that I need? Thanks for the help... I have a search where I want to be able to search a string of words. The search is going to be looking in 2 different table joined by a left outer join. The tables are "quotes" and "categories". $sql="SELECT q.id, q.username, q.quote, q.by, q.voteup, q.votedown, q.servtime, c.quote_id, c.label FROM quotes q LEFT OUTER JOIN categories c ON q.id = c.quote_id WHERE ( q.username LIKE '$srch' OR q.quote LIKE '$srch' OR q.`by` LIKE '$srch' OR c.label LIKE '$srch')"; The above mysql statement works and returns values..BUT if say, I search "john" and "funny", and a quote is posted by the user "john", but has a category of "funny" it will output the same quote twice. I was wondering if there was a way to see if a quote has either 1 term or both terms, if so display that quote but only display it once. Below is what the query is outputting. [100] => Array ( [id] => 100 [username] => John [quote] => new test quote blah blah [by] => John [voteup] => 0 [votedown] => 0 [servtime] => 2010-12-02 @ 16:27:03 [label] => Array ( [0] => Historic [1] => Serious [2] => Funny ) ) Here is the code in full. //// $sword = explode(" ",$search); foreach($sword as $sterm){ $srch="%".$sterm."%"; echo"$srch<br />"; $sql="SELECT q.id, q.username, q.quote, q.by, q.voteup, q.votedown, q.servtime, c.quote_id, c.label FROM quotes q LEFT OUTER JOIN categories c ON q.id = c.quote_id WHERE ( q.username LIKE '$srch' OR q.quote LIKE '$srch' OR q.`by` LIKE '$srch' OR c.label LIKE '$srch')"; $result=mysql_query($sql); while($row=mysql_fetch_object($result)){ $quote[$row->id]['id'] = $row->id; $quote[$row->id]['username'] = $row->username; $quote[$row->id]['quote'] = $row->quote; $quote[$row->id]['by'] = $row->by; $quote[$row->id]['voteup'] = $row->voteup; $quote[$row->id]['votedown'] = $row->votedown; $quote[$row->id]['servtime'] = $row->servtime; $quote[$row->id]['label'][] = $row->label; } echo"<pre>"; print_r($quote); echo"</pre>"; I don't think this is the fastest way of doing this, as it loops for each item in the db, per each keyword that is search. Any help would be great!! -BaSk |