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PHP - Preg_replace Not Working?
i want to remove any links which get pulled out in my general information query.
Code: [Select] $general_info = $row['general_info']; $general= preg_replace('/<a href="([^<]*)">([^<]*)<\/a>/', '', $general_info); echo '<h2>General Information : <img src="images/mag.png"></h2>'; echo '<div id="featurecontent">'; echo '<p>'. ucfirst($general).'</p>'; echo '</div>'; But the above code doesnt seem to be stripping out links. Can anyone see what i am doing wrong. Kind Regards Dean Similar TutorialsHi all. I'm having a bit of an issue with preg_replace and I'm not sure how to solve it. I'm having preg_replace find a "bus" (short for business) prefix in a file name and then print "Business Management" instead of "bus". I also have another prefix of "bus_it_requests". When preg_replace finds that prefix, it prints "Business Management It Requests" but I need it to print "Business It Requests". How do I have preg_replace make the distinction in the prefix matches? How come preg_replace won't traverse multiple lines?
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$str = ' Code: [Select] $str = preg_replace('/('.$word.')/i', '<em>\1</em>', $str); how come this doesn't work when $word = 'http://www.google.com', or any other URL? For all of you RegEx experts...here is my code: $str=preg_replace("/\[word=(.)(.*)\](.*)\[\/word\]/Usi", "<a href=\"http://www.accountingconcern.com/accounting-dictionary/".strtoupper('\\1')."/\\1\\2/ \">\\3</a>", $str); Basically it is taking [word=debit]Debit[/word] and making it link. The problem is, where I have the first \\1, I need that letter capitalized - not working. I'm not getting an error, it is just not capitalizing that letter. Any ideas? Thank you! im trying to do a complex(i think) prg replace but i keep getting the error: Code: [Select] Failed evaluating code: $lang->showing-1,1 the code i am trying to replace is: Code: [Select] <asf: lang[showing-<asf: var[num_report_alerts]>,<asf: var[num_report_alerts]>]> and the preg_replace is: Code: [Select] $content = preg_replace('|\<asf: lang\[(.*?)-(.*?)\]\>|e', '$lang->replace_vars($lang->//1, array(\\2))', $content); its supposed to take everything inside <asf: lang[]> and echo \\1 which would be "showing" and then add \\2 into an array which would be "array(1,1)". So the output would be showing 1 of 1. Anyone know where im going wrong? Hi there! I need to echo some text from a database table, this text should be linked to a url stored in the same database. I am trying to do this with preg_replace but I am terrible at it! I keep getting this error: Warning: Wrong parameter count for preg_replace() while($row = mysql_fetch_array( $result )) { $reg_exUrl = "/(http|https|ftp|ftps)\:\/\/[a-zA-Z0-9\-\.]+\.[a-zA-Z]{2,3}(\/\S*)?/"; echo preg_replace ($reg_exUrl, $row['title'); Any suggestion? Thanks Hello ppl, I have this website link http://www.somesite.com/anotherpage/yetotherpage.html what i want to make is using preg_replace that the final result will be www.somesite.com i have: $msg = ereg_replace("[^A-z0-9]"," ",$msg); $msg = ereg_replace(" "," ",$msg); $msg = ereg_replace(" "," ",$msg); how will i apply preg_replace please??? thank you After days of searching I found this thread http://www.phpfreaks.com/forums/index.php?topic=236954.0 that helped me do what I was trying to do. I've gotten the code to create and rename my html document but I can't figure out how to use the preg_replace part. This is my template with the 3 variables I want to replace with values from a form. Code: [Select] <html> <head> <link rel="stylesheet" type="text/css" href="style.css" /> </head> <body> <?php include_once('content.php') ?> </body> <SCRIPT language="JavaScript" SRC="javascript.js"></SCRIPT> <script type="text/javascript"> function nametitle(){ parent.iframe1.document.getElementById("div1").innerHTML = "VARIABLE1 <br>VARIABLE2"; parent.iframe1.document.getElementById("quotes").innerHTML = "VARIABLE3"; } </script> </html> I've spent hours reading and trying to understand how to make it work but it's a little over my head. Could someone help me with this? Thanks, I am trying to pull out the image HTML tag but its not working as expected. Here is what I am doing $removeimagetag='/<a href/'; $replacwith = "illegal"; $_POST['descr']=preg_replace($removeimagetag,$replacwith,$_POST['descr']); in the 'descr' there is a <a href="http://s635.photobucket.com...... When it post it does not strip out the <a href So the image is displayed. I tried a modified version to test to see if it work that looked like this. $removeimagetag='/goofy/'; $replacwith = "illegal"; $_POST['descr']=preg_replace($removeimagetag,$replacwith,$_POST['descr']); When the word goofy appears in the text then its replaced with the word illegal, Also I would like to make it so that it replaces the entire line from the <a href....... to the </a> with a phrase that says "this feature is not allowed" rather than just the part in the front...the <a href. Any help you can be will be greatly appreciated. Hi everyone, how do i add and ampersand symbol into preg_replace preg_replace("/[^a-zA-Z0-9\s\-\'\,\.\_]/" where do i place the symbol? & I'm trying to search a string for all occurences of a pattern, then append text after that pattern. The example is:
SUM("foo") as "bar"
and have it display as:
SUM("foo") over() as "bar"
The "SUM" could be any SQL aggregate and be case insensitive. So For bonus points, let's say the valid aggregates are array('SUM', 'MAX', 'MIN', 'AVG'). My plan right now is to figure it out for SUM, then loop it replacing the aggregate.
This is what I have so far... and it is not working.
$l= 'SUM("foo") as "bar"';
$l=preg_replace('/([^"]+")/','\0 over()',$l);
Thanks,
Ryan
Hi, I'm kind of new to PHP and very new to Regular Expressions and I was wondering if someone could help run through this code snippet from a callback function in a Joomla plugin called Affliates Feed. So far I have this is passed a pointer to variable item (I understand this is effectively the same as passing the variable but a lot less CPU intensive. Creates an array with keys and values Now the for loop I am stuck with, I understand the interation through the array. But what is preg_replace returning and why pass it back that way hasn't it already done its job? Can any one help? And please feel free to be as basic as possible :help: Thanks, Adam Code: [Select] function gardening(&$item) { #renaming categories, not the most efficient use for example strtolower first, and use only lowercase in the rename array $rename=array( ' Gardening?' => '', 'Climber Plants' => 'Climbing Plants', 'Seeds.*Bulbs' => 'Seeds Bulbs', 'Plant protection' => 'Horticultural goods', 'Garden structures' => 'Garden buildings',); foreach ( $rename as $k => $v ) { list($item['menu_1'],$item['menu_2'])=preg_replace("#$k#",$v,array($item['menu_1'],$item['menu_2'])); } $item['menu_1']=ucfirst(strtolower($item['menu_1'])); $item['menu_2']=ucfirst(strtolower($item['menu_2'])); $item['menu_3']=ucfirst(strtolower($item['menu_3'])); $item['menu_4']=ucfirst(strtolower($item['menu_4'])); } I currently have some custom tags, similar to BBCode, to be used for comments on my site. I'm trying to create a [nobr] tag (note: I know the no break tag will work in many major browsers, but it's deprecated, so I'm trying to be compliant). The idea is that if I encounter the [nobr] tag, I need to remove all line breaks. Here's the best I can do, but it's not working as I had hoped. Here's what I currently use to replace line breaks with a break tag. Code: [Select] $str=str_replace("\r\n","<br>",$str); Here's my attempt at introducing this new tag. Code: [Select] function BbToHtml($str) { $before=preg_replace("/(.+)\[nobr\](.+)\[\/nobr\](.+)/Usi","\\1",$str); $during=preg_replace("/(.+)\[nobr\](.+)\[\/nobr\](.+)/Usi","\\2",$str); $after=preg_replace("/(.+)\[nobr\](.+)\[\/nobr\](.+)/Usi","\\3",$str); $during=str_replace("\r\n","",$during); if($during != "") { // If the [nobr] tag was found, go with the new string. $str = $before.$during.$after; } else { // If the [nobr] tag was not found, go ahead like normal. $str=str_replace("\r\n","<br>",$str); } return $str; I can't get that working. Any ideas on how to fix that, or a completely alternate method of doing it? Thank you! This topic has been moved to PHP Regex. http://www.phpfreaks.com/forums/index.php?topic=332527.0 Quote Hi Guys, I have a small issue with doing a preg_replace on a string. Here is the string I wish to use preg_replace on Code: [Select] <?php $mystring = "This is my test string that has {['site_info']} and some more stuff {['taste']} then nothing" ?> Quote I want to do a preg_replace and replace {['site_info']} with $stuff['major']['site_info'] through the string Quote I want to replace the placeholder with real variables from the array Any help would be great Hello. Im working on a function: Code: [Select] function image_vote_img_replace($content) { preg_match_all('/<img[^>]+>/i',$content, $result, PREG_PATTERN_ORDER); foreach ($result[0] as $img_oryg) { $result = '<div class="test">'.$img_oryg.'</div>'; $content = preg_replace( $img_oryg, $result , $content ); } return $content; } It gets as input content from CMS. It supposed to add overlaping div to each <img src="xxxx" /> so it looks like: <div class="test"><img src="xxxx" /></div>. But instead i get: <<div class="test"><img src="xxxx" /></div>> with additional < and > at beginning and end. I thin ,that it might be first regexp problem, but in second hand - entire img is extracted properly... Thanks in advice. Martin. This topic has been moved to PHP Regex. http://www.phpfreaks.com/forums/index.php?topic=347057.0 im not sure how to do this: my code used the deprecated ereg_replace like this: $name = ereg_replace(" ", "", $name); i replaced it with this: $name = preg_replace(" ", "", $name); //this is line 65 but know get a warning: Warning: preg_replace(): Empty regular expression on line 65 what am i doing wrong please? thank you I have the following line of code in my program $html = preg_replace_callback(‘/\{DATE\s+(.*?)\}/’,create_function(‘$matches’, ‘return date($matches[1]);’),$html ); I am getting a warning about it being deprecated. I have tried the following two lines separately and get an error with both. $html = preg_replace_callback(‘/\{DATE\s+(.*?)\}/’, function($matches) { return date($matches[1]); },$html ); $html = preg_replace_callback(‘/\{DATE\s+(.*?)\}/’, function($matches) { return date($matches[1]); },$html ); Can anyone help me convert from preg_replace to preg_replace_callback. Edited March 2 by kwpreds |
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