PHP - Inserting Data From One Table Into Another With Different Values?
I want to take data from one table and insert it into another in the same database, the problem is the two tables have different values so it wouldn't be as simple as using an INSERT INTO script.
From table 1 I want to extract a row ID as well as a field called systems. I then want to insert that into the second table which is structured, Id (null) Name (games) Value (the data given from Systems in the other) ID2 (the ID from the other table) Category (news) Any ideas how I can go about this? Similar Tutorials
Table Issue - Multiple Location Values For User Pushes Values Out Of Row Instead Of Wrapping In Cell
Hello all Ok here is the problem... I want when a user inputs the requested data to the text fields , the script to insert those data in the prope table depending on the choise the user does by choosing one option from the drop down menu. Below is the php code (apparently not working) $editFormAction = $_SERVER['PHP_SELF']; if (isset($_SERVER['QUERY_STRING'])) { $editFormAction .= "?" . htmlentities($_SERVER['QUERY_STRING']); } $site_type = $_REQUEST['category_selection']; if ((isset($_POST["MM_insert"])) && ($_POST["MM_insert"] == "link_submission") && ($site_type = "Web_Sites")) { $insertSQL = sprintf("INSERT INTO partner_sites (url, url_title, anchor_text, `description`, webmaster_name, webmaster_email, category) VALUES (%s, %s, %s, %s, %s, %s, %s)", GetSQLValueString($_POST['url_field'], "text"), GetSQLValueString($_POST['title_field'], "text"), GetSQLValueString($_POST['anchor_field'], "text"), GetSQLValueString($_POST['description_field'], "text"), GetSQLValueString($_POST['webmaster_nane_field'], "text"), GetSQLValueString($_POST['webmaster_email_field'], "text"), GetSQLValueString($_POST['category_selection'], "text")); mysql_select_db($database_content_conn, $content_conn); $Result1 = mysql_query($insertSQL, $content_conn) or die(mysql_error()); } if ((isset($_POST["MM_insert"])) && ($_POST["MM_insert"] == "link_submission") && ($site_type = "Blogs")) { $insertSQL = sprintf("INSERT INTO partner_blogs (url, url_title, anchor_text, `description`, webmaster_name, webmaster_email, category) VALUES (%s, %s, %s, %s, %s, %s, %s)", GetSQLValueString($_POST['url_field'], "text"), GetSQLValueString($_POST['title_field'], "text"), GetSQLValueString($_POST['anchor_field'], "text"), GetSQLValueString($_POST['description_field'], "text"), GetSQLValueString($_POST['webmaster_nane_field'], "text"), GetSQLValueString($_POST['webmaster_email_field'], "text"), GetSQLValueString($_POST['category_selection'], "text")); mysql_select_db($database_content_conn, $content_conn); $Result1 = mysql_query($insertSQL, $content_conn) or die(mysql_error()); } if ((isset($_POST["MM_insert"])) && ($_POST["MM_insert"] == "link_submission") && ($site_type = "Directories")) { $insertSQL = sprintf("INSERT INTO partner_directories (url, url_title, anchor_text, `description`, webmaster_name, webmaster_email, category) VALUES (%s, %s, %s, %s, %s, %s, %s)", GetSQLValueString($_POST['url_field'], "text"), GetSQLValueString($_POST['title_field'], "text"), GetSQLValueString($_POST['anchor_field'], "text"), GetSQLValueString($_POST['description_field'], "text"), GetSQLValueString($_POST['webmaster_nane_field'], "text"), GetSQLValueString($_POST['webmaster_email_field'], "text"), GetSQLValueString($_POST['category_selection'], "text")); mysql_select_db($database_content_conn, $content_conn); $Result1 = mysql_query($insertSQL, $content_conn) or die(mysql_error()); } And the html form <form action="<?php echo $editFormAction; ?>" method="POST" enctype="multipart/form-data" name="link_submission" id="link_submission"> <table width="630" border="0" align="center" cellpadding="5" cellspacing="5"> <tr> <td width="76">URL:*</td> <td width="519"><label for="url_field"></label> <span id="sprytextfield1"> <label for="url_field"></label> <input name="url_field" type="text" id="url_field" size="50" /> <span class="textfieldRequiredMsg">A value is required.</span><span class="textfieldInvalidFormatMsg">Invalid format.</span></span></td> </tr> <tr> <td>Anchor Text:*</td> <td><label for="anchor_field"><span id="sprytextfield2"> <input type="text" name="anchor_field" id="anchor_field" /> <span class="textfieldRequiredMsg">A value is required.</span></span></label></td> </tr> <tr> <td>URL Title:*</td> <td><label for="title_field"><span id="sprytextfield3"> <input type="text" name="title_field" id="title_field" /> <span class="textfieldRequiredMsg">A value is required.</span></span></label></td> </tr> <tr> <td>Description:*</td> <td><span id="sprytextarea1"> <label for="description_field"></label> <textarea name="description_field" id="description_field" cols="45" rows="3"></textarea> <span id="countsprytextarea1"> </span><span class="textareaRequiredMsg">A value is required.</span><span class="textareaMaxCharsMsg">Exceeded maximum number of characters.</span></span></td> </tr> <tr> <td>Webmaster Name:*</td> <td><label for="textfield2"><span id="sprytextfield4"> <input type="text" name="webmaster_nane_field" id="webmaster_nane_field" /> <span class="textfieldRequiredMsg">A value is required.</span></span></label></td> </tr> <tr> <td>Webmaster E-mail:*</td> <td><label for="textfield3"><span id="sprytextfield5"> <input name="webmaster_email_field" type="text" id="webmaster_email_field" size="40" /> <span class="textfieldRequiredMsg">A value is required.</span><span class="textfieldInvalidFormatMsg">Invalid format.</span></span></label></td> </tr> <tr> <td>Category:*</td> <td><span id="spryselect1"> <label for="category_selection"></label> <select name="category_selection" id="category_selection"> <option>Select An Option</option> <option value="Web_Sites">Web Sites</option> <option value="Blogs">Blogs</option> <option value="Directories">Directories</option> </select> <span class="selectRequiredMsg">Please select an item.</span></span></td> </tr> <tr> <td> </td> <td><label for="select"></label> <input type="submit" name="button" id="button" value="Url Submission" /></td> </tr> </table> <input type="hidden" name="MM_insert" value="link_submission" /> </form> Im begging for your help..... i want insert data from text box in html form.there are many text boxes gave name using 2 loops..please tell how can insert data to table?please reply Stuck again on simple code. I am trying to insert some fields extracted from one table into another. I'm using code that worked elsewhere. The SQL statement flies, the script runs, the input array is printed back I get an echo back from the end of the script but nothing is added to the table. Even aded an echo print_r in the conditional and I know the data is getting to the execute command. The script follows with a sample of the input array. I have attached am image of the table I am trying to insert the data into. --Kenoli The script: <?php require '__classes/DB.php'; $sql = "SELECT name, table_id, image_name, description, medium FROM tbl_person_data "; $stmt = $pdo->query($sql); $array1 = $stmt->fetchall(PDO::FETCH_ASSOC); $stmt = $pdo->prepare("INSERT INTO Images (name, person_id, filename, description, medium) VALUES (?,?,?,?,?)"); //$pdo->beginTransaction(); foreach ($array1 as $row) { $stmt->execute($row); } echo "<pre>"; print_r ($row); echo "</pre>"; echo '<h4>Got to end of file</h4>'; ?> $array1: The input array [0] => Array ( [name] => Carol Lettko [table_id] => 21 [image_name] => Carol_Lettko-DSC_3022.jpg [description] => Baby Herons/Brickyard [medium] => photo ) [1] => Array ( [name] => [table_id] => 22 [image_name] => Carol_Lettko-DSC_0164.JPG [description] => Heron/Brickyard [medium] => photo ) [2] => Array ( [name] => [table_id] => 23 [image_name] => Carol_Lettko-IMG_5723.jpg [description] => Kayaker/Brickyard [medium] => photo )
Hello, I'm having trouble inserting data into a MySQL table. The user has a form which is HEIGHT and WIDTH and NUMBER_OF_OBSERVATIONS. All these values are stored in the same table. NUMBER_OF_OBSERVATIONS does what it needs to and inserts its calculated results into the database, as does DATE_TIME. I've been trying for a couple of days to get this done, and I am having no luck in getting it sorted. Any help is greatly appreciated! Generator.php Code: [Select] $WIDTH = $_POST['WIDTH']; $HEIGHT = $_POST['HEIGHT']; $NUMBER_OF_OBSERVATIONS = $_POST['NUMBER_OF_OBSERVATIONS']; $db1 = new Number_Information(); $db1->openDB(); $OBSERVATION_ID = $db1->insert_Observation(); echo "<br /><br />Success. ID: <strong>$OBSERVATION_ID<strong>"; $db1->closeDB(); Number_Information.php Code: [Select] function insert_Observation() { //$Date_Now = datetime(); $sql = "INSERT INTO Observations (DATE_TIME, HEIGHT, WIDTH) VALUES (NOW(), '{$esc_HEIGHT}','{$esc_WIDTH}' )"; $result = mysql_query($sql, $this->conn); if (!$result) { die("SQL Insertion error: " . mysql_error()); } else { return mysql_insert_id($this->conn); } The table name is Observations Again - Any help is greatly appreciated! Hello there! I've been banging my head on this for a while and I just can't seem to get it to work properly. I have a dropdown menu which selects information from table1 using a select statement (this table is called 'lid'). It selects the firstname, lastname and member id from this table and shows it in the dropdown menu. I'm glad I got that part working but the hard thing is inserting the data that the user selects into another table. So when you select the id member from this dropdown menu it only inserts a blank row into table2 (which is called 'teamlid'). Can you guys help me? How can I insert the id member into my table2? What am I doing wrong here? Thanks a million! This is my first post so if I'm doing anything wrong, let me know and I'll fix it asap! My code: <!DOCTYPE html> <html lang="en"> <head> <meta charset="UTF-8"> <title>Boast & Drive</title> <link rel="stylesheet" href="https://maxcdn.bootstrapcdn.com/bootstrap/3.3.7/css/bootstrap.css"> <style type="text/css"> .wrapper{ width: 650px; margin: 0 auto; } .page-header h2{ margin-top: 0; } table tr td:last-child a{ margin-right: 15px; } </style> </head> <body> <div class="container-fluid"> <div class="row"> <div class="col-md-12"> <div class="page-header clearfix"> <h2 class="pull-left">Teamleden</h2> <div class="btn-toolbar"> <a href="read.php" class="btn btn-primary btn-lg pull-right">Terug</a> </div> </div> <?php mysqli_report(MYSQLI_REPORT_ERROR | MYSQLI_REPORT_STRICT); error_reporting(E_ALL); //Verbinding maken met de database require_once "login.php"; $sql = "SELECT tl.teamnaam, tl.tl_ID, tl.lidnummer, l.voornaam, l.achternaam FROM teamlid tl JOIN lid l ON tl.lidnummer = l.lidnummer ORDER BY tl.teamnaam;"; if($result = mysqli_query($conn, $sql)) { if(mysqli_num_rows($result) > 0) { echo "<table class='table table-bordered table-striped'>"; echo "<thead>"; echo "<tr>"; echo "<th>Teamnaam</th>"; echo "<th>Tl_ID</th>"; echo "<th>Lidnummer</th>"; echo "<th>Voornaam</th>"; echo "<th>Achternaam</th>"; echo "</tr>"; echo "</thead>"; echo "<tbody>"; while($row = mysqli_fetch_array($result)){ echo "<tr>"; echo "<td>" . $row['teamnaam'] . "</td>"; echo "<td>" . $row['tl_ID'] . "</td>"; echo "<td>" . $row['lidnummer'] . "</td>"; echo "<td>" . $row['voornaam'] . "</td>"; echo "<td>" . $row['achternaam'] . "</td>"; echo "<td>"; echo "<a href='update.php?id=". $row['lidnummer'] ."' title='Gegevens wijzigen' data- toggle='tooltip'><span class='glyphicon glyphicon-pencil'></span></a>"; echo "<a href='delete.php?id=". $row['lidnummer'] ."' title='Lid verwijderen' data- toggle='tooltip'><span class='glyphicon glyphicon-trash'></span></a>"; echo "</td>"; echo "</tr>"; } echo "</tbody>"; echo "</table>"; mysqli_free_result($result); } else{ echo "<p class='lead'><em>Er zijn geen gegevens om weer te geven.</em></p>"; } } else{ echo "De volgende fout is gevonden: " . mysqli_error($conn); } ?> <form name="dropdown" method="post"> <div class="page-header clearfix"> <h2 class="pull-left">Teamlid toevoegen</h2> </div> <p>Selecteer hieronder met behulp van het dropdown menu een lid welke je aan bovenstaand team wilt toevoegen</p> <div class="container-fluid"> <div class="row"> <?php // Variabelen aanmaken en tonen met lege waardes $teamnaam = $lidnummer = ''; // Code voor dropdown. Selecteert voornaam, achternaam en lidnummer van tabel lid) $sql = "SELECT voornaam, achternaam, lidnummer FROM lid ORDER BY achternaam"; $result = mysqli_query($conn, $sql); echo "<select id='teamLid' name='teamLid'>"; echo "<option>--Selecteer Lid--</option>"; while ($row = mysqli_fetch_array($result)) { echo "<option value='" . $row['lid'] . "'>" . $row['voornaam'] . " " . $row['achternaam'] . " " . $row['lidnummer'] . "</option>"; } echo "</select>"; if (isset($_POST["id"]) && !empty($_POST["id"])) { $id = $_POST["teamLid"]; $stmt = $conn->prepare("INSERT INTO teamlid (teamnaam, lidnummer) VALUES (?,?)"); $stmt->bind_param('si', $param_teamnaam, $param_lidnummer); $param_teamnaam = $teamnaam; $param_lidnummer = $lidnummer; $stmt->execute(); } // Verbinding sluiten mysqli_close($conn); ?> <div> <input type="hidden" name="id" value="<?php echo $id; ?>" /> <input type="submit" name="submit" class="btn btn-primary" value="Toevoegen"> </div> </div> </div> </form> </div> </div> </body> </html>
Hi guys, I am building a website with basic e-commerce functionality, using php and using xampp to test it. I am having issues when attempting to submit a quantity (into table orders) using a form and validating it against an existing value (from table products), giving a response on whether there is sufficient quantity in the second table. I am then, in another page (same one performing the validations), attempting to then show a result based on the initial quantity entered, with a summary of the order details and calculation of the quantity * price to display a total as well. This has all been built from scratch, however I may have taken the wrong approach for these two pages... any assistance or insight as to where I am going wrong would be greatly appreciated. Here is the page I have placed the products, existing quantity and a text field they are able to enter their desired quantity: Code: [Select] <?php session_start(); require_once "../database/db.php"; require_once "../includes/functions.php"; $page_title = 'Product Catalogue'; include_once "header.php"; $conn = mysqli_connect ($dbhost, $dbuser, $dbpassword, $dbname); $query = "SELECT * from products"; $result = mysqli_query($conn, $query); if (!$result) { include_once "header.php"; die ("Error, could not query the database"); } else { $rows = mysqli_num_rows($result); if ($rows>0) { while ($row = mysqli_fetch_array($result)) { ?> <form> <br /> <br /> <br /> <table> <tr> <td style="width: 200px">Product Code:</td> <td><?php echo $row['ProductCode']; ?></td> </tr> <tr> <td>Product Name:</td> <td><?php echo $row['ProductName']; ?></td> </tr> <tr> <td>Product Description:</td> <td><?php echo $row['ProductDescription']; ?></td> </tr> <tr> <td>Product Colour:</td> <td><?php echo $row['ProductColour']; ?></td> </tr> <tr> <td>Product Price:</td> <td>$<?php echo number_format($row['ProductPrice'],2); ?></td> </tr> <tr> <td>Product Image:</td> <td><img src="<?php echo $row['ProductImagePath']?>"/></td> </tr> <tr> <td>Quantity in Stock:</td> <td><?php echo $row['ProductQuantity']; ?></td> </tr> </table> </form> <form method="post"action="processQuantity.php"> <table> <tr> <td style="width: 200px">Quantity:</td> <td><input type="number" name="Quantity" id="Quantity" value="<?php if (isset ($quantity)) echo $quantity; ?>"size = "20" /></td> <td><input type="submit" name="Purchase" value= "Purchase" /></td> </tr> </table> </form> <hr /> <?php } include "footer.html"; } } ?> Here is the page that I am using to validate the data as well as show a result based on the entered amount: Code: [Select] <?php session_start(); require_once "../includes/functions.php"; require_once "../database/db.php"; $quantity = $_POST['Quantity']; $productquantity = $_POST['ProductQuantity']; $orderid = $_POST['orderid']; $productcode = $_POST['productcode']; $productprice = $_POST['productprice']; $total = $quantity * $productprice; $error_message = ''; if ($error_message != '') { include_once "displayCatalogue-PlaceOrder.php"; exit(); $conn = mysqli_connect ($dbhost, $dbuser, $dbpassword, $dbname); if (!$conn) { echo "Error"; } else { //sanitise date $scustomerid = sanitiseMySQL($customerid); $sproductcode = sanitiseMySQL($productcode); $squantity = sanitiseMySQL($quantity); $sproductprice = sanitiseMySQL($productprice); $sorderdate = sanitiseMySQL($orderdate); $query = "select productquantity from products where productcode = '$sproductcode'"; $result = msqli_query ($conn, $query); $productquantity = mysqli_num_rows($result); if ($quantity < $productquantity) { $error_message = "You cannot order more than what is currently instock"; include_once "displayCatalogue-PlaceOrder.php"; exit (); } else { $row = mysqli_fetch_row($result); $query = "INSERT into orders (customerid, productcode, quantity, productprice, orderdate) values ('$scustomerid', $sproductcode', '$squantity', '$sproductprice', '$sorderdate')"; $result = mysqli_query($conn, $query); $row = mysqli_affected_rows($conn); if ($row > 0) { include "header.php";?> <h3>Order Confirmation</h3> <p>Thank you, your order is now being processed.</p> <table> <tr> <td style="width: 200px">Order Number:</td> <td><?php echo $orderid; ?></td> </tr> <tr> <td>Product Code:</td> <td><?php echo $productcode; ?></td> </tr><tr> <td>Quantity:</td> <td><?php echo $quantity; ?></td> </tr> <tr> <td>Price:</td> <td><?php echo $productPrice; ?></td> </tr> <tr> <td>Total Cost of Order:</td> <td><?php echo $total; ?></td> </tr> </table> <?php include "footer.html"; } else { $error_message ="Error placing your order, please try again"; include "displayCatalogue-PlaceOrder.php"; exit(); } } } } //this is used to validate the quantity entered against what is available in the database ?> Hey guys, I am kind of new to php but I am stuck on this question. I have a mySQL database and table set up called members. I have some data in the table and I want to be able to add certain things to a paticular row in the table based off the ID number of the row. One of the values of the table is an auto incremeted ID number. I want to add a text value called message to a specified ID number. How do I go about doing that. I have this code already but it doesn't seem to work. Code: [Select] $sql = "INSERT INTO members (message) VALUES ('$_POST[message]',(SELECT id FROM members WHERE id='$_POST[id]'))"; Any Ideas? Thanks Hi People i'm a newb at this so bare with me but i currently have a php file called Newkpi.php which has a select statement in. this selects data from a table called "StaffList". this then populates the page with a html table with 14 records (this will increase/decrease over time) i then have some extra text boxes to enter more detail into like service amaount service date and so on. when i click the submit button i want it to cycle through each row and insert the data into a separate table called "Services". however i cannot for the life of me get this to work and need some help with it. people find attached the code for Newkpi and see if you can help me with this. in total i want it to take the names from stafflist and populate Services with the names and the extra detail which is entered on the page Much Thanx in advance SLOWIE Is it possible to use for loop to insert values into database using for loop? Or what would be the another way to insert these values into the database if the number of values being entered differs from one time to another? Here is basically what I am trying to do: mysql_query("INSERT INTO MaxMillionsNum SET Day='$weekday', DrawDate='$CompleteDate', DateTime='$timestamp', for($i=1; $i<=$SetNumber; $i+=1){ for($j=0; $j<7; j+=1){ $NumberName="Number".$i.$v[$j];//Generating name of database field $$NumberName=$Match[0][$j];//Here I would store the $Match value into the fieldname name created above } } Tries='$RunCounter'"); Dear All Members here is my table data.. (4 Columns/1row in mysql table)
id order_no order_date miles How to split(miles) single column into (state, miles) two columns and output like following 5 columns /4rows in mysql using php code.
(5 Columns in mysql table) id order_no order_date state miles 310 001 02-15-2020 MI 108.53 310 001 02-15-2020 Oh 194.57 310 001 02-15-2020 PA 182.22
310 001 02-15-2020 WA 238.57 ------------------my php code -----------
<?php
if(isset($_POST["add"]))
$miles = explode("\r\n", $_POST["miles"]);
$query = $dbh->prepare($sql);
$lastInsertId = $dbh->lastInsertId(); if($query->execute()) {
$sql = "update tis_invoice set flag='1' where order_no=:order_no"; $query->execute();
} ----------------- my form code ------------------
<?php -- Can any one help how to correct my code..present nothing inserted on table
Thank You Edited February 8, 2020 by karthicbabuHello there,
I'm really new at PHP and I've been reading several beginner tutorials so please accept my apologies for any stupid questions I may ask along the way.
I've gotten as far as installing XAMPP, set up a database plus PHP form and I'm struggling to figure out how to insert values from an array into my database.
I've learnt the code in one particular way (see beginner tutorials) so I was wondering if you could help me keeping this in mind. I know there'll be a million better ways to do what I'm doing but I fear I will be bamboozled with different code or differently structured code.
Anyway the tutuorials I'm reading don't see to cover how I can insert an array of values into my database, just singular values.
In the attached file, I have 10 rows of 2x text inputs (20 text inputs total). Each row allows the user to enter a CarID and CarTitle. I've commented out the jQuery which validates the inputs so I can build a rudimentary version of this validation with PHP.
I thought that because the line $sql="INSERT INTO carids_cartitles (CarID, CarTitle) VALUES ($id, $title)"; is inside the foreach, means that for each pair of values from the form it'd insert to the database.
It doesn't do this. If I enter two or more CarIDs and CarTitles, only one pair of values gets saved to the database.
I'm sorry if I haven't explained this well enough, any questions please let me know.
Many thanks for your help in advance.
Attached Files
form.php 4.43KB
5 downloads So first of all, I have a confession, I used Dreamweaver to take care of all my database work. Pheww. Now that I got that of my chest, I am having problems, not only with my lack of experience working with databases, but with my script also. I need to insert multiple checkbox values into my database into the same cell. So I have searched around and I thought I had found a fairly good approach, but with Dw's hodgepodge of overcomplicated mess, I am finding problems integrating it. The error I am getting post submission is "Warning: mysql_real_escape_string() expects parameter 1 to be string, array given in C:\wamp\www\gov\ballot.php on line 10 Column 'involvement' cannot be null" So if you would, could you debug my script and give me some instruction along to way so that I can learn a little something too? Here is my script: <?php require_once('Connections/ballot.php'); ?> <?php if (!function_exists("GetSQLValueString")) { function GetSQLValueString($theValue, $theType, $theDefinedValue = "", $theNotDefinedValue = "") { if (PHP_VERSION < 6) { $theValue = get_magic_quotes_gpc() ? stripslashes($theValue) : $theValue; } $theValue = function_exists("mysql_real_escape_string") ? mysql_real_escape_string($theValue) : mysql_escape_string($theValue); switch ($theType) { case "text": $theValue = ($theValue != "") ? "'" . $theValue . "'" : "NULL"; break; case "long": case "int": $theValue = ($theValue != "") ? intval($theValue) : "NULL"; break; case "double": $theValue = ($theValue != "") ? doubleval($theValue) : "NULL"; break; case "date": $theValue = ($theValue != "") ? "'" . $theValue . "'" : "NULL"; break; case "defined": $theValue = ($theValue != "") ? $theDefinedValue : $theNotDefinedValue; break; } return $theValue; } } $editFormAction = $_SERVER['PHP_SELF']; if (isset($_SERVER['QUERY_STRING'])) { $editFormAction .= "?" . htmlentities($_SERVER['QUERY_STRING']); } if ((isset($_POST["MM_insert"])) && ($_POST["MM_insert"] == "Ballot")) { $insertSQL = sprintf("INSERT INTO votes (`first`, `last`, gender, grade, involvement, schedule, party, `time`) VALUES (%s, %s, %s, %s, %s, %s, %s, %s)", GetSQLValueString($_POST['first'], "text"), GetSQLValueString($_POST['last'], "text"), GetSQLValueString($_POST['gender'], "text"), GetSQLValueString($_POST['grade'], "text"), GetSQLValueString($_POST['involvement'], "text"), GetSQLValueString($_POST['schedule'], "text"), GetSQLValueString($_POST['party'], "text"), GetSQLValueString($_POST['time'], "text")); mysql_select_db($database_ballot, $ballot); $Result1 = mysql_query($insertSQL, $ballot) or die(mysql_error()); $insertGoTo = "thanks.php"; if (isset($_SERVER['QUERY_STRING'])) { $insertGoTo .= (strpos($insertGoTo, '?')) ? "&" : "?"; $insertGoTo .= $_SERVER['QUERY_STRING']; } header(sprintf("Location: %s", $insertGoTo)); } mysql_select_db($database_ballot, $ballot); $query_Recordset1 = "SELECT * FROM votes"; $Recordset1 = mysql_query($query_Recordset1, $ballot) or die(mysql_error()); $row_Recordset1 = mysql_fetch_assoc($Recordset1); $totalRows_Recordset1 = mysql_num_rows($Recordset1); ?> <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> <title>Please Place your Vote Below</title> </head> <body style="background-image:url(images/bg.jpg); background-repeat:repeat-x; background-color:#000000;"> <table align="center" bgcolor="#FFFFFF" cellpadding="0" cellspacing="0" border="0"> <tr><td> <div style="border:thin; border-color:000000; border-style:groove; width:700px; background-color:ffffff;"> <div align="center"><a href="index.php"><img src="images/header.jpg" alt="Mock Elections 2010" /></a></div> <div style="margin:10px; margin-top:30px;"> Before continuing to vote, in order to count your vote, we ask that you please ensure you are adhereing to the following guidelines: </div> <div style="margin:30px"> <p>- When putting your name, remember to put your full legal name. NO nicknames.<br /> - Be sure that all your information is valid otherwise your vote will not be counted. <br /> </p> </div> <div style="margin-left:150px; margin-right:150px; margin-top:50px;"> <form action="<?php echo $editFormAction; ?>" method="POST" name="Ballot"> First Name: <input type="text" name="first" /><br /> Last Name: <input type="text" name="last" /><br /> <div>Gender: <label> Male <input type="radio" value="Male" name="gender" /></label> <label>Female <input type="radio" value="Female" name="gender" /></label> </div> Grade: <select name="grade"> <option selected="selected"> </option> <option value="7">7</option> <option value="8">8</option> <option value="9">9</option> <option value="10">10</option> <option value="11">11</option> <option value="12">12</option> <option value="Teacher">Teacher</option> <option value="Staff">Staff</option> </select><br /> <div>Involvement: <label> <input type="checkbox" name="involvement[]" value="Athletics" id="involvement_0" /> Athletics</label> <label> <input type="checkbox" name="involvement[]" value="Co-Curricular" id="involvement_1" /> Co-Curricular</label> <label> <input type="checkbox" name="involvement[]" value="Clubs" id="involvement_2" /> Clubs</label> </div> <div>Schedule: <label><input type="radio" value="C4" name="schedule" />C4</label> <label><input type="radio" value="All Day" name="schedule" />All Day Hauser Student</label> </div> <div>Party: <label><input type="radio" value="PokePartay" name="party" />PokePartay</label> <label><input type="radio" value="Equilibrium" name="party" />Equilibrium Party</label> </div> <br /> <input type="Submit" value="Submit" /> <input type="hidden" value="<?php $tz = new DateTimeZone('America/Indianapolis'); $date = new DateTime('now', $tz); echo $date->format('m-d-Y h:i:s') . "\n"; ?>" name="time" /> <?php if (isset($_POST['submit'])) { $involvements = $_POST['involvement']; foreach($involvements as $involvement) { $query2 = "INSERT INTO votes (involvement) VALUES ('$involvement')"; $result2 = mysql_query($ballot, $query2) or die(mysql_error()); } } ?> <input type="hidden" name="MM_insert" value="Ballot" /> </form> </div> <br /> <br /> <br /> <br /> </div> </td> </tr> </table> </body> </html> <?php mysql_free_result($Recordset1); ?> Thanks, Philip Ulrich Hello, I am currently trying to learn php from a book called PHP for Absolute Beginners where it teaches you how to build a blog by "hand". All nice and good until i got to the submit an entry and save it to my database process. I'm using PDO with INSERT prepared statement like so, from a separate update.inc.php file: Code: [Select] $sql = "INSERT INTO entries (title, entry) VALUES (?,?)"; $stmt = $db->prepare($sql); $stmt -> execute(array($title, $entry)); $stmt ->closeCursor(); I have attached screenshots of my database in mysql. What could be the problem? Remeber I am an "ABSOLUTE BEGINNER" :p . Thank you $username = $_POST['uid']; $email = $_POST['mail']; $password = $_POST['pwd']; $passwordRepeat = $_POST['pwd-repeat']; $date = $_POST['date2']; $stream = $_POST['relationship']; $sql1 = "INSERT INTO users (uidUsers, emailUsers, pwdUsers, relationship) VALUES (?, ?, ?, ?);"; $sql2 = "INSERT INTO Family1 (username, application_filed, relationship) VALUES (?, ?, ?);"; $sql3 = "INSERT INTO Family2 (username, application_filed, relationship) VALUES (?, ?, ?);"; mysqli_query($sql1, $conn); mysqli_query($sql2, $conn); mysqli_query($sql3, $conn); $stmt = mysqli_stmt_init($conn); if (!mysqli_stmt_prepare($stmt, $sql2)) { header("Location: ../signup.php?error=sqlerror"); exit(); } else { mysqli_stmt_bind_param($stmt, "sss", $username, $date, $stream); $result = mysqli_stmt_get_result($stmt); if ($row = mysqli_fetch_assoc($result)) ($username==$_SESSION['uid'] and $stream =='nursing'); mysqli_stmt_execute($stmt); } if (!mysqli_stmt_prepare($stmt, $sql3)) { header("Location: ../signup.php?error=sqlerror"); exit(); } else { mysqli_stmt_bind_param($stmt, "sss", $username, $date, $stream); $result = mysqli_stmt_get_result($stmt); if ($row = mysqli_fetch_assoc($result)) ($username==$_SESSION['uid'] and $stream =='doctoral'); mysqli_stmt_execute($stmt); } if (!mysqli_stmt_prepare($stmt, $sql1)) { header("Location: ../signup.php?error=sqlerror"); exit(); } if (!mysqli_stmt_prepare($stmt, $sql1)) { header("Location: ../signup.php?error=sqlerror"); exit(); } else { $hashedPwd = password_hash($password, PASSWORD_DEFAULT); mysqli_stmt_bind_param($stmt, "ssss", $username, $email, $hashedPwd, $stream); mysqli_stmt_execute($stmt); header("Location: ../signup.php?signup=success"); exit(); I was wondering if someone could point me in the right direction. I have this code. They idea I had behind it is to insert values into different tables depending on variables being passed. So when user fills out a form and selects $stream="nursing" I want results to go to table 'users' and 'Family1', but not 'Family2' table. and if user selects $stream='doctoral' results should go to table 'users' and 'Family2', and not go to 'Family1' But with my query I get results go to both table and also users table. And there is no restriction to what users selects, variable $stream being passed no matter what it is. Is this the wrong way to go here? Did I completely mess up the logic? I have posted one set of values into my database and it worked fine but when i input another set they wont go inside unless i changes the value of the primary index colum. I want to be able to insert a new values regardless of the primary index value. Any idears...? Can someone please help me figure out how to insert "image" from table users, that contains the .jpg data associated with "screen_name", into table friends "friendimg" Here are the tables: friends: id, member, friendwith, friendimg users: id, screen_name, image $_GET["id"] only contains "screen_name" and"image" is not included add.php Code: [Select] <?php if(isset($_GET["id"])) { echo "<br/><a href=\"member?add=".$_GET["id"]."\">Add ".$_GET["id"]." to your list of friends</a>"; } ?>member.php Code: [Select] <?php if(isset($_GET["add"])) { $username = $_SESSION["screen_name"]; $friend = $_GET["add"]; $query = "SELECT * FROM friends WHERE member='$username' AND friendwith='$friend'"; $result = mysql_query($query); $exist = mysql_num_rows($result); if($exist=='0') { $query = "INSERT INTO friends(member,friendwith) VALUES('$username','$friend')"; mysql_query($query); echo "<br/>You are now friends with $friend"; } else { echo "<br/>$friend is already in your list of friends!"; } } ?> This UPDATE script works:
$query = $pdo->prepare("UPDATE posts SET headline = ? WHERE id = ?"); $query->bindValue("1", $_POST['headline']); $query->bindValue("2", "2"); $query->execute();Though, this INSERT script does not work: $query = $pdo->prepare("INSERT INTO posts (headline, post) VALUES (?, ?)"); $query->bindValue("1", $_POST['headline']); $query->bindValue("2", $_POST['post']); $query->execute();Nothing gets added, when executing this script. The connection: <?php $dsn = "mysql:dbname=phpblog;host=localhost"; $user = "root"; $password = ""; try{ $pdo = new PDO($dsn, $user, $password); }catch(PDOException $e){ echo "Connection failed: " . $e->getMessage(); } ?>Any suggestions why the INSERT script is not working? Edited by glassfish, 25 November 2014 - 09:26 AM. Hi, My company has 240+ locations and as such some users (general managers) cover multiple sites. When I run a query to pull user information, when the user has multiple sites to his or her name, its adds the second / third sites to the next columns, rather than wrapping it inside the same table cell. It also works the opposite way, if a piece of data is missing in the database and is blank, its pull the following columns in. Both cases mess up the table and formatting. I'm extremely new to any kind of programming and maybe this isn't the forum for this question but figured I'd give it a chance since I'm stuck. The HTML/PHP code is below: <table id="datatables-column-search-select-inputs" class="table table-striped" style="width:100%"> <thead> <tr> <th>ID</th> <th>FirstName</th> <th>LastName</th> <th>Username</th> <th>Phone #</th> <th>Location</th> <th>Title</th> <th>Role</th> <th>Actions</th> </tr> </thead> <tbody> <?php //QUERY TO SELECT ALL USERS FROM DATABASE $query = "SELECT * FROM users"; $select_users = mysqli_query($connection,$query);
// SET VARIABLE TO ARRAY FROM QUERY while($row = mysqli_fetch_assoc($select_users)) { $user_id = $row['user_id']; $user_firstname = $row['user_firstname']; $user_lastname = $row['user_lastname']; $username = $row['username']; $user_phone = $row['user_phone']; $user_image = $row['user_image']; $user_title_id = $row['user_title_id']; $user_role_id = $row['user_role_id'];
// POPULATES DATA INTO THE TABLE echo "<tr>"; echo "<td>{$user_id}</td>"; echo "<td>{$user_firstname}</td>"; echo "<td>{$user_lastname}</td>"; echo "<td>{$username}</td>"; echo "<td>{$user_phone}</td>";
//PULL SITE STATUS BASED ON SITE STATUS ID $query = "SELECT * FROM sites WHERE site_manager_id = {$user_id} "; $select_site = mysqli_query($connection, $query); while($row = mysqli_fetch_assoc($select_site)) { $site_name = $row['site_name']; echo "<td>{$site_name}</td>"; } echo "<td>{$user_title_id}</td>"; echo "<td>{$user_role_id}</td>"; echo "<td class='table-action'> <a href='#'><i class='align-middle' data-feather='edit-2'></i></a> <a href='#'><i class='align-middle' data-feather='trash'></i></a> </td>"; //echo "<td><a href='users.php?source=edit_user&p_id={$user_id}'>Edit</a></td>"; echo "</tr>"; } ?>
<tr> <td>ID</td> <td>FirstName</td> <td>LastName</td> <td>Username</td> <td>Phone #</td> <td>Location</td> <td>Title</td> <td>Role</td> <td class="table-action"> <a href="#"><i class="align-middle" data-feather="edit-2"></i></a> <a href="#"><i class="align-middle" data-feather="trash"></i></a> </td> </tr> </tbody> <tfoot> <tr> <th>ID</th> <th>FirstName</th> <th>LastName</th> <th>Username</th> <th>Phone #</th> <th>Location</th> <th>Title</th> <th>Role</th> </tr> </tfoot> </table>
Hello All, First, I'm new to php and I have spent a lot of time searching forums and google for the answer to my question with no luck, so if it's a topic already covered, PLEASE reply with a link or point me in the right direction. OK, I have a form that let's users upload multiple images. The upload portion works fine. What I can't figure out how to do is put the image name of each file that gets uploaded all into the same table record. I also need each file name to be put into it's own column in the table. For example, file1, file2 and file3 will get dumped into the same record and into it's respective column (uploaded_image1, uploaded_image2, uploaded_image3). I've included the working upload code and the code that inserts some of the information into the database (just not the image names). Code: [Select] echo "<textarea name=challenge rows=15 cols=60> </textarea><br/><br/>" echo "<textarea name=insight rows=15 cols=60> </textarea><br/><br/>" for($i=1; $i<=$max_no_img; $i++){ echo "Image $i <input type=file name='image[]' ><br/>"; } echo "<input type=submit value=Submit>"; Code: [Select] // Connect to DB $host = 'xxx'; $user = 'xxx'; $pass = 'xxx'; $db = 'xxx'; mysql_connect($host,$user,$pass) or die(mysql_error()); mysql_select_db($db) or die(mysql_error()); // Post Variables $challenge = $_POST['challenge']; $insight = $_POST['insight']; $filename=serialize($_POST['filename']); // Upload Images while(list($key,$value) = each($_FILES[image][name])) { if(!empty($value)) { $filename = $value; $add = "upimage/$filename"; copy($_FILES[image][tmp_name][$key], $add); chmod("$add",0777); } } // Insert into database $query = "INSERT INTO table ( challenge, insight, uploaded_image1, uploaded_image2, uploaded_image3,)". "values ( '$challenge', '$insight', '$filename' '$filename2' '$filename3')"; mysql_query($query) or die('Error, query failed : ' . mysql_error()); I know just enough about php that the reason the above wont work, is because $filename2 and $filename3 haven't been given a value. Unfortunately, I have no idea how to separate that information in the array. If anyone can point me in the right direction I'd be forever grateful! Thanks, Gary |