PHP - Document Upload

I have code written for image uploading, but it doesn't allow multiple images on a single upload, and doesn't re-size.

Anyone willing to share a good upload script that will do the following?:
-Allow multiple image uploads (10+ per submission),
-Re-size images on upload, and
-Rename images.

Thanks
Brett

Hi everyone,

I have a page that i use to upload images to my website, i got a bit fed up of uploading one at a time so i decided to add multiple file fields to the form to upload multiple images at the same time.

Im having a few problems, iv read up he http://www.php.net/manual/en/features.file-upload.multiple.php and it seems all i have to do is add [] to the form names to turn them into arrays. However when i come to upload the images, i keep getting the "$error[] = "Incorrect format!...." error from the code below. I cant seem to figure out what the problem is.

Could anybody please point me in the right direction?


<?php 
session_start();

$id = $_SESSION['id'];

$connect = mysql_connect("localhost","leemp5_admin","p7031521");
mysql_select_db("leemp5_database");

$query = mysql_query("SELECT * FROM users WHERE id='$id'");
$row = mysql_fetch_assoc($query);

$username = $row['username'];

$submit = $_POST['submit'];

$type = $_FILES['image']['type'];
$size = $_FILES['image']['size'];
$max_size = "1000"; 
$width = "100"; 
$height = "100";
 
$error = array();

function make_thumb($image_name,$filename,$new_width,$new_height) 
{

$ext=getExtension($image_name); 

if(!strcmp("jpg",$ext) || !strcmp("jpeg",$ext)) 

$source_image=imagecreatefromjpeg($image_name);   

if(!strcmp("png",$ext)) 

$source_image=imagecreatefrompng($image_name);

if(!strcmp("gif",$ext)) 

$source_image=imagecreatefromgif($image_name); 

$old_x=imageSX($source_image);

$old_y=imageSY($source_image);   

$ratio1=$old_x/$new_width; 

$ratio2=$old_y/$new_height; 

if($ratio1>$ratio2)

{ 

$thumb_width=$new_width; 

$thumb_height=$old_y/$ratio1; 

} 

else 

{ 

$thumb_height=$new_height;

$thumb_width=$old_x/$ratio2; 

} 
  

$destination_image=ImageCreateTrueColor($thumb_width,$thumb_height);   

imagecopyresampled($destination_image,$source_image,0,0,0,0,$thumb_width,$thumb_height,$old_x,$old_y);   

if(!strcmp("jpg",$ext) || !strcmp("jpeg",$ext))

{

imagejpeg($destination_image,$filename); 

}

if(!strcmp("png",$ext)) 

{

imagepng($destination_image,$filename); 

}

if(!strcmp("gif",$ext)) 

{

imagegif($destination_image,$filename); 

}

imagedestroy($destination_image); 

imagedestroy($source_image); 
}   


function getExtension($str)
{ 

$i = strrpos($str,"."); 

if (!$i) { return ""; } 

$l = strlen($str) - $i; 

$ext = substr($str,$i+1,$l); 

return $ext; 
}   

if($submit) 
{ 

$image=$_FILES['image']['name']; 

if ($image) 

{ 

$filename = stripslashes($_FILES['image']['name']);   

$extension = getExtension($filename); 

$extension = strtolower($extension); 

if (($extension != "jpg") && ($extension != "jpeg") && ($extension != "png") && ($extension != "gif"))

{ 

$error[] = "Incorrect format! Please make sure your image is a .jpg, .jpeg, .png or .gif file.";

} 

else

{ 

$size=getimagesize($_FILES['image']['tmp_name']); 

$sizekb=filesize($_FILES['image']['tmp_name']); 
  

if ($sizekb > $max_size*1024) 

{ 

$error[] = "Your image is too big! The maximum upload size is 1MB.";

}   

else

{

$image_name=time().'.'.$extension; 
 

$newname="uploads/" . $username . "/images/".$image_name; $copied = copy($_FILES['image']['tmp_name'], $newname); 

if (!$copied) 

{ 

$error[] = "There was an error uploading your image. Please try again!";

} 

else 

{ 

$thumb_name='uploads/' . $username . '/images/thumbs/thumb_'.$image_name; 
 

$thumb=make_thumb($newname,$thumb_name,$width,$height); 

}

}

}

}

else

{

$error[] = "Please select an image to upload!";

}

if(empty($error))

{

echo "Upload Successfully!<br />"; 

echo '<img src="'.$thumb_name.'">';

mysql_query("INSERT INTO images VALUES ('','$username','$image_name','','','','','uploads/$username/images/$image_name','uploads/$username/images/thumbs/thumb_$image_name','$type','$size')");

}

else

{
    

echo implode($error);

}
}
?>
<form method="post" enctype="multipart/form-data" action="upload_images.php">
<input type="file" name="image[]" /><br />
<input type="file" name="image[]" /><br />
<input type="file" name="image[]" /><br />
<input type="file" name="image[]" /><br />
<input type="file" name="image[]" /><br />
<input type="file" name="image[]" /><br />
<input type="submit" name="submit" value="Upload">
</form>


Thanks

files that upload during insert/submit form was gone , only files upload during the update remain , is the way query for update multiple files is wrong ?

$targetDir1= "folder/pda-semakan/ic/";
if(isset($_FILES['ic'])){
     $fileName1 = $_FILES['ic']['name'];
 $targetFilePath1 = $targetDir1 . $fileName1;
 //$main_tmp2 = $_FILES['ic']['tmp_name'];
$move2 =move_uploaded_file($_FILES["ic"]["tmp_name"], $targetFilePath1);
}

$targetDir2= "folder/pda-semakan/sijil_lahir/";
if(isset($_FILES['sijilkelahiran'])){
     $fileName2 = $_FILES['sijilkelahiran']['name'];
 $targetFilePath2 = $targetDir2 . $fileName2;
$move3 =move_uploaded_file($_FILES["sijilkelahiran"]["tmp_name"], $targetFilePath2);
}

$targetDir3= "folder/pda-semakan/sijil_spm/";
if(isset($_FILES['sijilspm'])){
     $fileName3 = $_FILES['sijilspm']['name'];
 $targetFilePath3 = $targetDir3 . $fileName3;
$move4 =move_uploaded_file($_FILES["sijilspm"]["tmp_name"], $targetFilePath3);
}



$query1=("UPDATE semakan_dokumen set student_id='$noMatrik', email= '$stdEmail', surat_tawaran='$fileName', ic='$fileName1',sijil_lahir='$fileName2',sijil_spm= '$fileName3' where email= '$stdEmail'");

 

Ive tried
<?php
$file = file_get_contents('./time.php');
echo $file;
?>
This just outputs the php, how can I make it just the out php output value.
ty in advance.

im using dom to tidy up my html but i wondering is there a way to format my html like so

<dl>
     <dd>
            <label>Condition :</label>
            <select name="condition"><option value="New">New</option>
      </dd>
</dl>

insead of

<dl>
<dd>
<label>Condition :</label>
<select name="condition"><option value="New">New</option>
</dd>
</dl>

here is the php im using

$dom = new DOMDocument();
$dom->loadHTML($this->_body);
$dom->formatOutput = true;
echo $dom->saveHTML();

thank you

Hi Folks,


I am trying to scrape the price data from a webpage, but how to get the variable,

see here the target http://www.buergerstiftungen.de/cps/rde/xchg/SID-635E10F9-BFA1A4BF/buergerstiftungen/hs.xsl/db.htm

Code: [Select]
include 'simple_html_dom.php';
$html1 = file_get_html('http://www.buergerstiftungen.de/cps/rde/xchg/SID-635E10F9-BFA1A4BF/buergerstiftungen/hs.xsl/db.htm');

$info1 = $html1->find('b[class=[what to enter herer ]',0);

The variable then also contains data such as

<b class="info"> info </b>

Is there a way to trim the unwanted data out ? I just need all the infos out of the site. I am unsure if I do it during the find, or perhaps when i echo out the variable, then do I specify what I want ?
well how t o do it witout a regex but with DOM-Document!?

I'm using a here document for the html in my php page. In it I call a function to get the correct value to pass to the form and eventually to the next php page. I'm getting an error:Array to string conversion in. I'm not sure why, maybe I'm escaping the double quotes wrong? or do you need to do something special when the value being submitted is an array?   This line is where the error is, the second table data in the first table row

<td><input name="choice" type="radio" value=\"getCardValues($pyramid, 0,0)\" /></td>

in here

$output =<<< _HTML_
    
    <!DOCTYPE html>

    <html>
    <head>
        <title>Pyramid Solitaire</title>
    </head>
    
    <body>
        <div class="main">
        <h1>Rock Paper Scissors Game</h1>
        
        <form action="rps.php" method="post">
            <input type="text" name="name">
            <input type="hidden" name="past" value="0">
                
            <table width="20%">
                <tr>
                    <td><img src="./images/cards/getCardFile($pyramid, 0,0)" width="100" height="100" /></td>
                    <td><input name="choice" type="radio" value=\"getCardValues($pyramid, 0,0)\" /></td>
                </tr>
                
                for($i = 0; $i < 2; $i++)
                {
                    <tr>
                        <td><img src="./images/cards/getCardFile($pyramid, 1,$i)" width="100" height="100" /></td>
                        <td><input name="choice" type="radio" value="getCardValues($pyramid, 1,$i)" /></td>
                    </tr>
                }

and so on...   This is the function being called:

function getCardValues($array, $row, $col)
    {        
        $valuesHolder = array($array[$row][$col].getFace(), $array[$row][$col].getSuit());
        
        return $valuesHolder;
    }

Edited by 0rangeFish, 11 December 2014 - 01:25 AM.

Hey y'all.   I'll gladly admit that I'm not a server guy - I have the utmost respect for people comfortable enough with *nix to handle Apache setup and configuration in a production environment. I can noodle about in *nix typically without killing anything vitally important, but trust me when I say no-one wants me to be a server administrator. That having been said, I do have a development server behind my home network firewall running Ubuntu that I use to test and develop the sites that I create on my separate Windows box. So I try to keep up with the way a shared server would be set up in a real-world situation, to a degree. For instance, I haven't bothered setting up the mail server or FTP, but I do create virtual host files for each of my projects.   So, I've got a virtual host set up on the directory /var/www/myAwesomeSite.com/ with the .conf file containing the following configuration:

<VirtualHost *:80>
	ServerAdmin webmaster@localhost
	ServerName myAwesomeSite.com
	DocumentRoot /var/www/myAwesomeSite.com/www
	<Directory /var/www/myAwesomeSite.com/www>
		AllowOverride All
	</Directory>
        ErrorLog ${APACHE_LOG_DIR}/error.log
        CustomLog ${APACHE_LOG_DIR}/access.log combined
</VirtualHost>

Now, in my php scripts echoing out $_SERVER['DOCUMENT_ROOT'] gives me 'myAwesomeSite/www' as I would expect. And using $_SERVER['DOCUMENT_ROOT'] in any require() statements actually does include the requested file, so that part seems to be working fine. My question is this: when I use a leading slash ('/'), shouldn't that equate to the document root? I use it at work all the time and it works flawlessly, but on the dev server I have set up here, it's a no-go. Is there another config command that I need to issue to make it work, or am I crazy?   Basically, am I missing a setting somewhere that will make this:

require_once('/path/to/my/include.php');

work like this?

require_once($_SERVER['DOCUMENT_ROOT'].'/to/my/include.php');

*edit* I just realized that I used the wrong slash in the title of this post, but I don't see a way to change the topic title. crap.
Edited by maxxd, 23 November 2014 - 11:20 AM.

I would like to store weekly reports into documents.  I am familiar with storing data to a regular text document, but it does not keep bold text, tables and so forth.  Are there any other documents that would not be to hard to output to such as .pdf, .rtf, .doc, etc.?

I've attached the current format we are using in excel.  Now that I have things automated in php, I would like to output to a document with almost identical formatting.  And how can I keep it on 8 1/2" x 11" pages without it splitting data or tables between two pages?

Thanks,

Jake

This topic has been moved to Miscellaneous.

http://www.phpfreaks.com/forums/index.php?topic=354333.0

This upload form code works successfully, where a file is chosen, renamed and stored in the 'upload' folder,

I've been using php for a while now to create forms, up until now i've always transmitted the form data to a new php document that then processes them. I wanna take this to the next level and start trying to process the data within the same document. I know this has something to do with checking if the submit button is pressed and then processing the submitted data but thats about as far as my knowledge goes.

Can anyone help me out on  how i can achieve this type of thing. The reason is that i've found a way to execute php code within a joomla 1.6 environment without having to use the iframe option. I know the iframe option may be easier in a way of doing things but its out of the question. The final fase of the php will output code that will trigger a specific joomla plugin to do some specific action. If i pull a php document via an iframe the plugin doesnt trigger as it only gets triggered after the joomla "afterRender" (or something" has executed. If i use the iframe option then that rendering never gets used so the plugin doesnt get triggered.

So in a nutshell, i wanna create forms that submit data and that data gets processed in the same document (in this case joomla article). How do i go about doing this.

Hi all,

I can't get this code to work, if you can tel me what I am doing wrong I would be gratefull.

This is my XML file:

Code: [Select]
<?xml version="1.0" encoding="UTF-8"?>
<popis>
     <student>
          <prezime>Brkic</prezime>
          <ime>Ivica</ime>
          <index>D-142</index>
     </student>
     <student>
          <prezime>Cizek</prezime>
          <ime>Pero</ime>
          <index>D-143</index>
     </student>
</popis>
This is the form I wanna use to change nodes:

<form action="zamjena.php" method="post" enctype="multipart/form-data">
 <table>
   <tr>  
     <td colspan="2"class="labelcell"><label for="ime">Ime:</label></td>
     <td colspan="2"class="fieldcell"><input type="text" id="ime" name="ime"  tabindex="1"/></td>
   </tr>
      <tr>  
     <td colspan="2"class="labelcell"><label for="prezime">Prezime:</label></td>
     <td colspan="2"class="fieldcell"> <input type="text" id="prezime" name="prezime"  tabindex="2"/><br />
</td>
   </tr>
        <tr>  
     <td colspan="2"class="labelcell"><label for="index">Index:</label></td>
     <td colspan="2"class="fieldcell"> <input type="text" id="index" name="index"  tabindex="3"/> <br />
</td>
   </tr>
<tr>  
     <td colspan="2"class="labelcell"><label for="index">ID:</label></td>
     <td colspan="2"class="fieldcell"> <input type="text" id="id" name="id"  tabindex="4"/> <br />
</td>
   </tr>
   <td colspan="4"><input type="submit" name="upload" class="box" value="Zamjeni" tabindex="5" /></td>
  </table>
</form>


"id" is the mark which node to change

And this is code for changin nodes, I found it on: http://us.php.net/manual/en/domnode.replacechild.php :


<?php
// Create a new document fragment to hold the new <student> node
$student = new DomDocument;
$student_node = $student ->createElement('student');

// Add some children
$student_node->appendChild($student->createElement('ime', '$_POST['ime']'));
$student_node->appendChild($student->createElement('prezime', '$_POST['prezime']'));
$student_node->appendChild($student->createElement('index', '$_POST['index']'));


// Add the keywordset into the new document
// The $student variable now holds the new node as a document fragment
$student->appendChild($student_node);
?>

Next, we need to locate the old node:

<?php
// Load the XML
$dom = new DomDocument;
$dom->loadXML($xml);

// Locate the old student node
$xpath = new DOMXpath($dom);
$nodelist = $xpath->query('/popis/student');
$oldnode = $nodelist->item($_POST['id']);
?>

We then import and replace the new node:

<?php
// Load the $student document fragment into the current document
$newnode = $dom->importNode($student->documentElement, true);

// Replace
$oldnode->studentNode->replaceChild($newnode, $oldnode);

// Display
echo $dom->saveXML();
?>

thanks for help

Howdy,   So I am creating a website with SQLite and this time I decided to follow the rule of putting the SQLite DB outside of the document root. However, the admin would need to admin, basically, the DB, so I have two choices:   a) Put PhpLiteAdmin (The SQLite DB manager like PHPmyAdmin is for MySQL) in the document root while giving it a path to the actually DB that is outside of the document root;   b) Set a subdomain to a directory outside of the document root of course and put both PhpLiteAdmin and the SQLite DB there and the admin would access it like this - db.Awesome-Website.com;   Which one of those two options are safer?       Thank you very much!

I am running PHP 5 on a linux server.

I want to be able to open a .doc or .docx file with PHP (or any way possible, for that matter) in order to grab the contents from it. How can i do this? I know COM classes work with windows for this, but i have linux.

Any ideas are greatly appreciated.

Thanks.