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PHP - Resolve My Php Problem
<?php
session_start(); if (!$_SESSION["user_name"]) { // User not logged in, redirect to login page Header("Location: login.php"); } // Member only content // ... $con = mysql_connect('localhost','root',''); if (!$con) { die('Could not connect: ' . mysql_error()); } mysql_select_db("login", $con); $result = mysql_query("select * from reference,users where reference.username=users.user_name AND reference.refid = '".$_POST['refid']."'"); while($row = mysql_fetch_array($result)) { echo $row['refid'];?><br><? echo $row['origin']; echo $row['dest']; echo $row['date']; echo $row['exdate']; echo $row['user_name']; } // ... // ... // Display Member information // echo "<p>User ID: " . $_SESSION["valid_id"]; //echo "<p>Username: " . $_SESSION["valid_user"]; //echo "<p>Logged in: " . date("m/d/Y", $_SESSION["valid_time"]); // Display logout link echo "<p><a href=\"logout.php\">Click here to logout!</a></p>"; ?> for the above code i got error Warning: mysql_fetch_array(): supplied argument is not a valid MySQL result resource in solve my problem Similar Tutorialsnow i am getting this error ( ! ) Warning: mysql_connect() [function.mysql-connect]: Access denied for user 'talos342c'@'localhost' (using password: YES) in C:\wamp\www\myNewweb\storescripts\connect_to_mysql.php on line 19 Call Stack # Time Memory Function Location 1 0.0008 380440 {main}( ) ..\index.php:0 2 0.0012 384880 include( 'C:\wamp\www\myNewweb\storescripts\connect_to_mysql.php' ) ..\index.php:11 3 0.0012 385528 mysql_connect ( ) ..\connect_to_mysql.php:19 Hello All,
I'm kinda new to PHP and web development and I seem to have a very wierd problem which is driving me nuts (for the last 2 days)...so I'd appreciate any and all help in getting it resolved.
Okay, so here's the problem:
In the code below, I used to have just the first statement below...which essentially accepted input as a textbox for a text field named qty_pkg (in the underlying MySQL table)...and that used to work just fine.
So then I decided to change the input type for that field to be a radio button, accepting one of two choices i.e. "UoM" or "Qty", and therefore I added the remainder of the code, whilst also commenting/remarking out the first statement.
What happens (when I added the radiobutton-related code) is that control no longer goes into the TRUE portion/logic of the "if ( !empty($_POST))" condition-check, but rather, it seems to go into the "ELSE/FALSE" portion of that conditional check. However, a record does get added to my table, even though I do not have an "INSERT INTO..." clause in the ELSE porition of that check. Also, what gets displayed on screen is as follows:
------------------------------------------------------------------------------------------------------------------------------------
Array()
There's something wrong somewhere!!!
Array()
------------------------------------------------------------------------------------------------------------------------------------
Now, if/when I comment/remark the radiobutton-related code, the "if ( !empty($_POST))" logic seems to work fine and the following is displayed on screen (which is what I expect):
------------------------------------------------------------------------------------------------------------------------------------
Array ( [datepicker] => 10/30/2014 [store_id] => 48 [new_store_name] => [item_id] => 5 [new_item_name] => [pkg_of] => 1 [price] => 1 [flyer_page] => 1 [limited_time_sale] => Array ( [0] => fri [1] => sat ) [nos_to_purchase] => 1 [create-and-add-more] => Create and Add More ) Notice: Undefined index: qty_pkg in /var/www/create.php on line 54 Array ( [0] => Array ( [item_id] => 5 [0] => 5 [item_name] => BD Cheese Strings [1] => BD Cheese Strings [section_id] => 7 [2] => 7 ) ) ------------------------------------------------------------------------------------------------------------------------------------ The other wierd thing is that if/when I now uncomment the first statement (which used to work just fine before) the "if ( !empty($_POST))" logic no longer seems to work the way it used to. Does/can someone see something wrong with my code somewhere?
<!-- <?php echo standardInputField('Qty / Pkg', 'qty_pkg', $qty_pkg, $errors); ?> -->
<div class="control-group">
<label class="control-label">Priced by:</label>
<div class="priced-by-radio-container">
<div class="pb-radiobuttons-container">
<label class="indent-to-the-left">
<input class='priced-by-radiobutton' type='radio' name='qty_pkg' value='UoM' $pb1>
<span class='no-highlight'>Unit of Measure</span>
</label>
<label>
<input class='priced-by-radiobutton' type='radio' name='qty_pkg' value='Qty' $pb2>
<span class='no-highlight'>Quantity</span>
</label>
</div>
</div>
</div>
<?php echo standardInputField('UoM Name/Pkg. Of:', 'pkg_of', $pkg_of, $errors); ?>
<?php echo standardInputField('Price:', 'price', $price, $errors); ?>
<?php echo standardInputField('Flyer Page #:', 'flyer_page', $flyer_page, $errors); ?>
print_r($_POST);
if ( !empty($_POST))
{
// keep track of $_POST(ed) values by storing the entered values to memory variables
$store_id = $_POST['store_id'];
$item_id = $_POST['item_id'];
$qty_pkg = $_POST['qty_pkg'];
$pkg_of = $_POST['pkg_of'];
...
...
$sql = "INSERT INTO shoplist (store_id,item_id,qty_pkg,pkg_of,price,flyer_page,limited_time_sale,flyer_date_start,nos_to_purchase,section_id,shopper1_buy_flag,shopper2_buy_flag,purchased_flag,purchase_later_flag,no_flag_set)
VALUES(?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?)";
$q = $pdo->prepare($sql);
$q->execute(array($store_id,$item_id,$qty_pkg,$pkg_of,$price,$flyer_page,$limited_time_sale,$flyerDateStart,$nos_to_purchase,$section_id,$initialize_flag_N,$initialize_flag_N,$initialize_flag_N,$initialize_flag_N,$initialize_flag_Y));
}
else
{
echo "<br />There's something wrong somewhere!!!<br />";
print_r ($_POST);
$qty_pkg = '';
$pkg_of = '';;
Thanks.
Haven't been here in a while but I have stumped myself at the moment or maybe I've looked at it too much LOL In the given code below I am getting this error Warning: mysql_fetch_array() expects parameter 1 to be resource, boolean given in C:\xampp\htdocs\samples\getcustomers.php on line 20 WHY? Code: [Select] <?php $value = $_GET["q"]; $con = mysql_connect('localhost', 'root', ''); //db_connect(); if (!$con) { die('Could not connect: ' . mysql_error()); } $db_selected = mysql_select_db("ajaxDb",$con); $sql = "SELECT * FROM 'cutomers' WHERE Name = '".$value."'"; // echo $sql; $result = mysql_query($sql); echo "<table border='1'> <tr> <th>Name</th> <th>Address</th> <th>Country</th> </tr>"; while($row = mysql_fetch_array($result)) { echo "<tr>"; echo "<td>" . $row['Name'] . "</td>"; echo "<td>" . $row['Address'] . "</td>"; echo "<td>" . $row['Country'] . "</td>"; echo "</tr>"; } echo "</table>"; mysql_close($con); ?> Thanks for reading this. I have just begun using php, and I cannot, for my life, figure out what I am doing wrong here. I want to submit a form for a person to register with my site. It's simple, just name, email and password. I keep getting an error that the connection failed, so I will just show you what I have up until that point. My form is Post method, and it looks like: Code: [Select] <form method="post" action="signup.php" enctype="multipart/form-data"> <input name="name" type="text" id="name"> <input name="email" type="text" id="email"> <input name="pass" type="password"> <input type="submit" name="Submit" value="Submit"> </form> And the connection script is like so: Code: [Select] <?php $username="db_username"; $password="db_password"; $database="db_name"; $dbc=mysql_connect ("localhost", "$username", "$password") or die ('I cannot connect to the database.'); mysql_select_db ("$database", "$dbc"); It's the 'I cannot connect to the database.' error that I keep getting. In case it helps, the rest of the thing looks like this: Code: [Select] <?php $name= $_POST['name']; $email= $_POST['email']; $pass= $_POST['pass']; $query = "INSERT INTO table (name, email, password) VALUES ('$name', '$email', '$pass')"; mysql_query($query); mysql_close(); I have deliberately left out the php opening and closing tags (<?php...?>). Thanks so much for any help. Adam MOD EDIT: [code] . . . [/code] BBCode tags added. This is how looks bug looks : Code echo "<div align='center' class='thread'>Forum</div>"; $forum_select = mysql_query("SELECT * FROM forum") or die (mysql_error()); while ($forum_show = mysql_fetch_array($forum_select)) { $forum_name = mysql_query("SELECT * FROM forum_group"); while($forum_group_name = mysql_fetch_array($forum_name)) { if ($forum_group_name['hosting_forum_group_id'] == $forum_show['hosting_forum_group_id']) { echo "<table width='900' border='1' align='center' cellpadding='0' cellspacing='0'>"; echo "<tr><td colspan='6' style='padding: 7px;color:red'>".$forum_group_name['hosting_forum_group_name']."</td></tr>"; echo "<tr><td style='white-space: nowrap;' align='center' width='1%'>".$forum_show['hosting_forum_icon']."</td>"; echo "<td>"."<a href='/?section=forumview&id=".$forum_show['hosting_forum_id']." '>".$forum_show['hosting_forum_title']."</a><br />".$forum_show['hosting_forum_description']."</td>"; echo "<td width='230'> </td></tr>"; echo "</table><br>"; } } } I Hope to resolve the problem maybe somebody can explain where is my mistake to fix it and resolve it ! I've followed every piece of advice (quotes, no quotes, $...) and nothing works. Here is the snippet of code that's generating the error. This woks fine in PHP 5, but I have to upgrade to 7. Warning if for line 71, which corresponds to where query3 starts.
if($numRows == 0) { Earlier in code, I define this: $numRows = mysql_num_rows($r); Thanks in advance for any help you can lend. Edited February 7 by PoetI need to find a way to resolve a relative path outside the document root, in a cross-platform friendly manner. My users have a settings page where they are able to set the path to a folder where files should be included. This path may not exist at the time of saving the setting. The given path is then retrieved from the database when files are being saved, the path is checked to see if a folder needs to be created, and the file is saved to the path. Two possible paths they may use a * files (This is the webpath: http://site.com/files or absolute path /home/user/public_html/files) * ../files (This is the absolute path: /home/user/files where the webroot is /home/user/public_html/) The first path is easy to deal with. However, I'm having a rough time resolving the second path into a usable system path (i.e. /home/user/files). This needs to be cross platform compatible (windows/'Nix). I've played around with realpath(), but I'm just not finding something that works for me. Any suggestions? Hi: I have few small issues with a Contact Us form I am putting together. 1 - When quotes or apostrophes are added to the input fields, they get turned into '\ (slashes). The "myCodeLib.php" file has a function to remove the slashes. I use it in the same way in the admin area and it works fine, so I don't see what I am missing: Code: [Select] <?php //STRIP SLASHES if(get_magic_quotes_gpc()) { $_POST = array_map('stripslashes',$_POST); $_GET = array_map('stripslashes',$_GET); $_COOKIE = array_map('stripslashes',$_COOKIE); } ?> 2 - A small issuse, but the Email validation doesn't seem to work entirely. It will accept a single character (like an "a") as valid, but it looks like it's suppose to check for a format like "a@a.com" 3 - How can I properly SPAN this code that write out the error: Code: [Select] echo $error; I want to do Code: [Select] <span class="textError">echo $error;</span> to make it red but I keep getting a snytax error This is the full code: Code: [Select] include('include/myConn.php'); include('include/myCodeLib.php'); <?php $error = NULL; $myDate = NULL; $FullName = NULL; $Address = NULL; $City = NULL; $State = NULL; $Zip = NULL; $Phone = NULL; $Email = NULL; $Website = NULL; $Comments = NULL; if(isset($_POST['submit'])) { $myDate = $_POST['myDate']; $FullName = $_POST['FullName']; $Address = $_POST['Address']; $City = $_POST['City']; $State = $_POST['State']; $Zip = $_POST['Zip']; $Phone = $_POST['Phone']; $Email = $_POST['Email']; $Website = $_POST['Website']; $Comments = $_POST['Comments']; if(empty($FullName)) { $error .= '-- Enter your Full Name. <br />'; } if(empty($Email) || preg_match('~^([0-9a-zA-Z]([-.\w]*[0-9a-zA-Z])*@([0-9a-zA-Z][-\w]*[0-9a-zA-Z]\.)+[a-zA-Z]{2,9})$~',$Email)) { //<- if email is empty, or doesn't follow the expression. $error .= '-- Enter your Email. <br />'; //<- this is the error message. } if($error == NULL) { $sql = sprintf("INSERT INTO myContactData(myDate,FullName,Address,City,State,Zip,Phone,Email,Website,Comments) VALUES ('%s','%s','%s','%s','%s','%s','%s','%s','%s')", //<-database structure must be right. mysql_real_escape_string($myDate), mysql_real_escape_string($FullName), mysql_real_escape_string($Address), mysql_real_escape_string($City), mysql_real_escape_string($State), mysql_real_escape_string($Zip), mysql_real_escape_string($Phone), mysql_real_escape_string($Email), mysql_real_escape_string($Website), mysql_real_escape_string($Comments)); if(mysql_query($sql)) { $error .= 'Thank you for your comment!'; } else { $error .= 'There was an error in our Database, please Try again!'; } } } echo $error; $myDate = $_REQUEST['myDate'] ; $FullName = $_REQUEST['FullName'] ; $Address = $_REQUEST['Address'] ; $City = $_REQUEST['City'] ; $State = $_REQUEST['State'] ; $Zip = $_REQUEST['Zip'] ; $Phone = $_REQUEST['Phone'] ; $Email = $_REQUEST['Email'] ; $Website = $_REQUEST['Website'] ; $Comments = $_REQUEST['Comments'] ; mail( "email@website.com", "Contact Request", "Date Sent: $myDate\nFull Name: $FullName\nAddress: $Address\n City: $City\n State: $State\n Zip: $Zip\n Phone: $Phone\n Email: $Email\n Website: $Website\n Comments: $Comments\n", "From: $Email" ); ?> <form name="myform" action="" method="post"> <input type="hidden" name="myDate" size="45" maxlength="50" value="<?php echo date("F j, Y"); ?>" /> <div id="tableFormDiv"> <fieldset><span class="floatLeftFormWidth"><span class="textErrorItalic">* - Required</span></span> <span class="floatFormLeft"> </span></fieldset> <fieldset><span class="floatLeftFormWidth"><span class="textErrorItalic">*</span> Full Name:</span> <span class="floatFormLeft"><input type="text" name="FullName" size="45" maxlength="50" value="<?php echo $FullName; ?>" /></span></fieldset> <fieldset><span class="floatLeftFormWidth">Address:</span> <span class="floatFormLeft"><input type="text" name="Address" size="45" maxlength="50" value="<?php echo $Address; ?>" /></span></fieldset> <fieldset><span class="floatLeftFormWidth">City:</span> <span class="floatFormLeft"><input type="text" name="City" size="45" maxlength="50" value="<?php echo $City; ?>" /></span></fieldset> <fieldset><span class="floatLeftFormWidth">State:</span> <span class="floatFormLeft"><input type="text" name="State" size="45" maxlength="50" value="<?php echo $State; ?>" /></span></fieldset> <fieldset><span class="floatLeftFormWidth">Zip:</span> <span class="floatFormLeft"><input type="text" name="Zip" size="45" maxlength="50" value="<?php echo $Zip; ?>" /></span></fieldset> <fieldset><span class="floatLeftFormWidth">Phone:</span> <span class="floatFormLeft"><input type="text" name="Phone" size="45" maxlength="50" value="<?php echo $Phone; ?>" /></span></fieldset> <fieldset><span class="floatLeftFormWidth"><span class="textErrorItalic">*</span> Email:</span> <span class="floatFormLeft"><input type="text" name="Email" size="45" maxlength="50" value="<?php echo $Email; ?>" /></span></fieldset> <fieldset><span class="floatLeftFormWidth">Website:</span> <span class="floatFormLeft"><input type="text" name="Website" size="45" maxlength="50" value="<?php echo $Website; ?>" /></span></fieldset> <fieldset><span class="floatLeftFormWidth">Comments:</span> <span class="floatFormLeft"><textarea name="Comments" cols="40" rows="10"><?php echo $Comments; ?></textarea></span></fieldset> </div> <input type="submit" name="submit" value="Submit" class="submitButton" /><br /> </form> </div> Can someone please help me with this... hello dear PHP-experts have set up a server at localhost with phpMyAdmin i get back the site " it works " if i type in localhost i get access to the phpMyAdmin if i type localhost/phpMyAdmin so far so good now i wanted to go ahead: i ve uploaded a file called php_info.php to the htdocs folder. i changed permissions accordingly. (see below) linux-c5sz:/srv/www/htdocs # ls -l insgesamt 28 -rwxrwxrwx 1 root root 302 13. Mär 2006 favicon.ico drwxrwxrwx 2 root root 4096 6. Nov 2013 gif -rwxrwxrwx 1 root root 45 11. Jun 2007 index.html -rwxrwxrwx 1 root root 2356 28. Sep 2013 info2html.css -rwxrwxrwx 1 martin users 188 3. Dez 19:07 php_info.php drwxrwxrwx 6 root root 4096 3. Nov 17:40 phpMyAdmin -rwxrwxrwx 1 root root 26 13. Okt 15:32 robots.txt linux-c5sz:/srv/www/htdocs #what makes me wonder is - i cannot see the content of the file of php_info.php - why is this so see below <?php // Zeigt alle Informationen (Standardwert ist INFO_ALL) phpinfo(); // Zeigt nur die Modul-Informationen. // phpinfo(8) führt zum gleichen Ergebnis. phpinfo(INFO_MODULES); ?>well i wonder why i cannt see any information in thebrowser is this a bug ? Hi, I found a very nice script for saving my TwitPic images in full size. I have tested this script for a couple of times yesterday and it seems that this way of saving images is now blocked by amazon or TwitPic. Using the API it's not possible to download the images as fas I can see, does anyone has an idea ? http://forrst.com/posts/TwitPic_Hack_Get_Full_TwitPic_Image_using_PHP-mFQ Code: [Select] <?php function imgResize($width, $height, $target) { if ($width > $height) { $percentage = ($target / $width); } else { $percentage = ($target / $height); } $width = round($width * $percentage); $height = round($height * $percentage); return "width=\"$width\" height=\"$height\""; } // full url of the TwitPic photo $url = "http://twitpic.com/1pfhfd"; // make the cURL request to TwitPic URL $curl2 = curl_init(); curl_setopt($curl2, CURLOPT_URL, $url); curl_setopt($curl2, CURLOPT_AUTOREFERER, true); curl_setopt($curl2, CURLOPT_RETURNTRANSFER,true); curl_setopt($curl2, CURLOPT_TIMEOUT, 10); $html = curl_exec($curl2); $HttpCode = curl_getinfo($curl2, CURLINFO_HTTP_CODE); $totalTime = curl_getinfo($curl2, CURLINFO_TOTAL_TIME); // if the HTTPCode is not 200 - you got issues if ($HttpCode != 200) { ?><p>Unable to connect to TwitPic. Please try again later.</p><? } else { // if you are not getting any HTML returned, you got another issue. if ($html == "") { ?><p>Yikes! TwitPic is experiencing heavy load. Please close this window and try again.</p><? } else { $dom = new DOMDocument(); @$dom->loadHTML($html); // grab all the on the page $xpath = new DOMXPath($dom); $hrefs = $xpath->evaluate("/html/body//img"); foreach( $hrefs as $href ) { $url = $href->getAttribute('id'); // for all the images on the page find the one with the ID of photo-display if ($url == "photo-display") { // get the SRC attribute of the element with the ID of photo-display $image = $href->getAttribute('src'); // get the image size $imagesize = getimagesize($image); ?> <a href="<? echo $url; ?>" target="_blank"><img class="twitpic" src="<? echo $image; ?>" "<? echo imgResize($imagesize[0], $imagesize[1], 450); ?>"></a> <? break; } } } } ?> Hi, WHAT: So I cannot for the life of me figure out why I'm getting this error. I'm trying to create a function that will display the user information from the database in a table but I have like a ton of these errors on the page and I don't know whats wrong. STEPS TO RESOLVE: So I've gone over my code a bunch of types to make sure that all the variables and what not were spelled correctly and as far as I can tell they are. I've also googled this issue to see if I can find a solution but none of them are very helpful. I honestly don't know whats wrong so kinda hard to find ways to resolve an issue, I don't even really know what this error means. THE CODE: This is where I put the function into action
<?php
display_table(
array(
"id" => "Id",
"emailaddress" => "Email",
"firstname" => "First Name",
"lastname" => "Last Name",
"salesperson" => "Salesperson",
"phonenumber" => "Phone Number",
"extension" => "Extension",
"type" => "Type"
)
);
?>
//This is the function
<?php
function display_table($fields, $data, $rows, $page){
if(isset($_GET['page'])){
$page = $_GET['page'];
} else {
$page = 1;
}
$firstRecord = ($page - 1) * ROWS_PER_PAGE;
$pageNumbers = ceil($rows / ROWS_PER_PAGE);
echo '<div class="table-responsive w-75 mx-auto py-3">
<table class="table table-dark table-bordered table-sm">
<thead>
<tr>';
foreach($fields as $key){
echo '<th class="py-2">' . $key . '</th>';
}
echo '</tr>
</thead>
</tbody>';
$keys = array_keys($fields);
for($record = $firstRecord; $record < $firstRecord + ROWS_PER_PAGE; $record++){
$row = $data[$record];
echo '<tr>';
for($recordCount = 0; $recordCount < count($keys); $recordCount++){
$column = $keys[$recordCount];
echo '<td class="py-2">' . $row[$column] . '</td>';
}
echo '</tr>';
}
echo '</tbody>
</table';
for($pages = 1; $pages <= $pageNumbers; $pages++){
echo '<a class="btn btn-dark mx-1" href=?page=' . $pages . '</a>';
}
}
?>
Any help/advice would be really appreciated My script IS working, but I can't get around a blank array error when no errors exist. Below is my code, and as you can see, I am being handed this: Notice: Undefined variable: error in C:\wamp\www\php\form_validation.php on line 19 as a result of my ... if (is_array($error)) { ... .. I could do if (@is_array($error)) { (note the @), but I hate using that thing... I've tried several things with no luck, so any ideas welcome at this point. <?php if (isset($_POST['set_test'])) { if (!preg_match("/^[A-Za-z' -]{1,50}$/", $_POST['first_name'])) { $error[] = "Please enter a valid First Name"; } if (!preg_match("/^[A-Za-z' -]{1,50}$/", $_POST['last_name'])) { $error[] = "Please enter a valid Last Name"; } if (is_array($error)) { foreach ($error as $err_message) { echo $err_message . "<br />"; } } } ?> Guys thanks for helping me solve the problem i had but now i have another problem and i am lost. i have included the code below for you to have overview.
This is the code:
<table style="width:100%; margin-left:auto; margin-right:auto"> i'm getting this erro "Warning: mysql_result() [function.mysql-result]: Unable to jump to row 0 on MySQL result index 3 in /***/***/*****.php on line 278 not an active session, starts new" this is the code: if ($phase = mysql_result(mysql_query("SELECT `phase` FROM `as_support` WHERE `mission` = '$var2'"),0,0)) { if ($phase=='5') { // mysql_query("DELETE FROM `as_support` WHERE `mission` = '$var2'"); // header("Location: https://www.**********/*******/*******.php"); } else { echo date('h:i:s') . ": PHASE is $phase<br />"; echo "\$var1=$var1,\$var2=$var2<br />"; } } else { echo "not an active session, starts new<br />"; echo "\$var1=$var1,\$var2=$var2<br />"; mysql_query("INSERT INTO `as_support` (`mission`, `phase`) VALUES ('$var2', '0')") OR DIE(mysql_error()); the first line is line no. 278 can someone please tell me what to do? tnx shirley You may see a lot of things wrong with the code below, but please bring it to my attention! I'm trying to advance my knowledge on OOP, but I'm trying my best to get the basics down. The below code, after selecting the two characters to fight, the page returns nothing, just blank. I'm pretty sure the error lyes within class_li.php, but I'm not exactly sure. Script is attached. I am trying to understand PHP OOP and I have some code that is not working. here is the error code. Code: [Select] Parse error: parse error, expecting `T_FUNCTION' in C:\wamp\www\testing\armor_lib.php on line 11 And here is the armor_lib.php file: <?php class armor { // Head public $head; public $torso; public $pants; public $gloves; public $boots; // new stuff here class head extends armor { function __construct($head){ $this->set_head($head); } } // Torso class torso extends armor { function __construct($torso){ $this->set_torso($torso); } } // Pants class pants extends armor { function __construct($pants){ $this->set_pants($pants); } } // Gloves class gloves extends armor { function __construct($gloves){ $this->set_gloves($gloves); } } // Boots class boots extends armor { function __construct($boots){ $this->set_boots($boots); } } } ?> And here is the php in the armor.php file I have: <?php $head = new armor("Leather Helm"); $torso = new armor("Leather Shirt"); $pants = new armor("Leather Pants"); $gloves = new armor("Chain Mail Gloves"); $boots = new armor("Leather Boots"); echo "You are wearing: " . $head->get_head() . "on your Head"; echo "<br />"; echo "You are wearing: " . $torso->get_torso() . "on your Torso"; echo "<br />"; echo "You are wearing: " . $pants->get_pants() . "on your Legs"; echo "<br />"; echo "You are wearing: " . $gloves->get_gloves() . "on your Hands"; echo "<br />"; echo "You are wearing: " . $boots->get_boots() . "on your Feet"; ?> Any Help in understanding this will be much appreciated. Thanks. Hi. I am from poland. I am 17 old age and like webmastering. I write my social network. I have new server 10 GB VPS and my script no runing In my server. in my server do can not login. No runing function Code: [Select] mb_strtolower();as delete function mb_strtolower() ; this login runing. In my server haven`t installing liberary GD and no runing upload avatars. my code upload is: elseif ($_GET['act'] == "upload") { echo <<< KONIEC <hr> <center> <p> <h2>Dodaj zdjęcie</h2> <ul class="gallery clearfix"> <li class="extra"> KONIEC; error_reporting(E_ALL); // we first include the upload class, as we will need it here to deal with the uploaded file include('include/class.upload.php'); // retrieve eventual CLI parameters $cli = (isset($argc) && $argc > 1); if ($cli) { if (isset($argv[1])) $_GET['file'] = $argv[1]; if (isset($argv[2])) $_GET['dir'] = $argv[2]; if (isset($argv[3])) $_GET['pics'] = $argv[3]; } // set variables $dir_dest = (isset($_GET['dir']) ? $_GET['dir'] : 'test'); $dir_pics = (isset($_GET['pics']) ? $_GET['pics'] : $dir_dest); if (!$cli) { } // we have three forms on the test page, so we redirect accordingly if ((isset($_POST['action']) ? $_POST['action'] : (isset($_GET['action']) ? $_GET['action'] : '')) == 'simple') { // ---------- SIMPLE UPLOAD ---------- // we create an instance of the class, giving as argument the PHP object // corresponding to the file field from the form // All the uploads are accessible from the PHP object $_FILES $handle = new Upload($_FILES['my_field']); // then we check if the file has been uploaded properly // in its *temporary* location in the server (often, it is /tmp) if ($handle->uploaded) { // yes, the file is on the server // now, we start the upload 'process'. That is, to copy the uploaded file // from its temporary location to the wanted location // It could be something like $handle->Process('/home/www/my_uploads/'); $handle->Process($dir_dest); function TestProcess(&$handle, $title = 'test', $details='') { global $dir_pics, $dir_dest; $unlink = 'test/'. $handle->file_dst_name; $myid = $_SESSION['id']; $opis = htmlspecialchars(stripslashes(strip_tags(trim($_POST["opis"]))), ENT_QUOTES); $handle->Process($dir_dest); if ($handle->processed) { unlink("$unlink"); $link = ''.$dir_pics.'/' . $handle->file_dst_name .''; $addphoto = mysql_query("INSERT INTO photo VALUES('', '$myid', '$link', '$opis')"); echo <<< KONIEC <br> <center> <img src="$link" > <br> <br /> </center> KONIEC; } else { echo '<fieldset class="classuploadphp">'; echo ' <legend>' . $title . '</legend>'; echo ' Error: ' . $handle->error . ''; if ($details) echo ' <pre class="code php">' . htmlentities($details) . '</pre>'; echo '</fieldset>'; } } if (!file_exists($dir_dest)) mkdir($dir_dest); // ----------- $handle->image_convert = 'jpg'; $handle->image_resize = true; $handle->image_ratio_y = true; $handle->image_x = 500; $handle->image_precrop = 15; $handle->image_watermark = "watermark_large.png"; $handle->image_watermark_x = 20; $handle->image_watermark_y = -20; TestProcess($handle, '15px pre-cropping (before resizing 800 wide), large watermark automatically reduced, position 20 -20', "\$foo->image_convert = 'jpg';\n\$foo->image_resize = true;\n\$foo->image_ratio_y = true;\n\$foo->image_x = 800;\n\$foo->image_precrop = 15;\n\$foo->image_watermark = 'watermark_large.png';\n\$foo->image_watermark_x = 20;\n\$foo->image_watermark_y = -20;"); } else { // one error occured echo '<fieldset>'; echo ' <legend>file not uploaded to the wanted location</legend>'; echo ' Error: ' . $handle->error . ''; echo '</fieldset>'; } // we copy the file a second time // we delete the temporary files $handle-> Clean(); } else { // if we are here, the local file failed for some reasons echo '<fieldset>'; echo ' <legend>local file error</legend>'; echo ' Error: ' . $handle->error . ''; echo '</fieldset>'; } echo <<< KONIEC <li> </ul> </p> </center> KONIEC; is it the only problem that isn`t installing GD as i have something off in php.ini ? Plise Help me I am trying to save this an an xml document but am getting this error when I try to open the xml file "feed.xml" - "XML Parsing Error: no element found" $xml = '<rss version="2.0"> <channel> <title> RSS Feed</title> <link></link> <description>the best industry-lead opinions</description> <language>en-us</language> </channel> </rss>"; $xml2 = new DOMDocument('1.0'); $xml2->Load($xml); $xml2->save("feed.xml"); Hi all. When I typed symbol ' in my textarea , after I submit it and view for what I typed , it will automatically add a slash in front of the ' . Such as the message is "I'm fine" , then it will turn out as "I\'m fine". Can I know what is the problem ? and how can I solve it? Thanks for every reply . |
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